At 20°C the vapor pressure of benzene (C6H6) is 75 torr, and that of toluene (C7H8) is 22 torr. Assume that benzene and toluene form an ideal solution. What is the composition in mole fractions of a solution that has a vapor pressure of 40. torr at 20°C?

Answers

Answer 1

Answer: The mole fraction of benzene will be 0.34 and mole fraction of toluene is 0.66

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

[tex]p_1=x_1p_1^0[/tex] and [tex]p_2=x_2P_2^0[/tex]

where, x = mole fraction in solution

[tex]p^0[/tex] = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_1+p_2\\[/tex][tex]p_{total}=x_{benzene}p_{benzene}^0+x_{toluene}P_{toluene}^0[/tex]

[tex]x_{benzene}=x[/tex],

[tex]x_{toluene}=1-x_{benzene}=1-x[/tex],

[tex]p_{benzene}^0=75torr[/tex]

[tex]p_{toluene}^0=22torr[/tex]

[tex]p_{total}=40torr[/tex]

[tex]40=x\times 75+(1-x)\times 22[/tex]

[tex]x=0.34[/tex]

Thus (1-x0 = (1-0.34)=0.66

Thus the mole fraction of benzene will be 0.34 and that of toluene is 0.66


Related Questions

How do you solve this ??

Answers

Answer:

Option D. 400 mmHg

Explanation:

The following data were obtained from the question:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total pressure = 10³ mmHg

Partial pressure of He =.?

Next, we shall determine the total number of mole in the reaction vessel.

This can be obtained as follow:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total mole =?

Total mole = nHe + nNe

Total mole = 0.04 + 0.06

Total mole = 0.1

Next, we shall determine the mole fraction of He.

This can be obtained as follow:

Mole fraction = mole of gas /total mole

Mole of He (nHe) = 0.04 mole

Total mole = 0.1

Mole fraction of He =.?

Mole fraction of He = nHe/total mole

Mole fraction of He = 0.04/0.1

Mole fraction of He = 0.4

Finally, we shall determine the partial pressure of He as follow:

Partial pressure = mole fraction x total pressure

Mole fraction of He = 0.4

Total pressure = 10³ mmHg

Partial pressure of He =.?

Partial pressure of He = 0.4 x 10³

Partial pressure of He = 400 mmHg.

Therefore, the partial pressure of He is 400 mmHg.

A constant current of 1.30 amps is passed through an electrolytic cell containing OsO2. How many hours will it take to produce 45.0 grams of osmium metal from this process

Answers

Answer:

9.8 h

Explanation:

From the question,

Os²⁻ - 2e⁻ = Os

From the equation above,

2 F of electron is needed to liberate 1 mole of osmium.

45 g of osmium contains 45/190 mole of osmium = 0.237 mole.

2 F ⇒ 1 mole.

2(0.237) F ⇒ 0.237 mole

0.474 F. will produce 45 g of osmium.

If         1 F = 96500 C ,

Then,  0.474 F = 45741 C,

But,

Q = it

t = Q/i....................... Equation 1

Given: Q = 45741 C, i = 1.30 A

Substitute into equation 1

t = 45741/1.3

t = 9.8 h.

Reactants that are_____will appear in the rate law as the concentration of the reactant squared.
a. zero order.
b. first order.
c. second order.
d. fourth order.

Answers

Answer:

The correct answer is c. second order

Explanation:

In a rate law, second order means that the chemical rate is related with the reactant concentration raised to 2. For example, if the chemical equation is:

A ⇒ B

A is the reactant and it is a second order reaction, so the rate law will be:

r = [A]²

We explored the copper cycle. In the first step, copper was oxidized by nitric acid to make a green solution. Water was then added to the solution and the color changed from green to blue. Is this result supported by the spectrochemical series?

Answers

Answer:

Yes, the reaction is supported by spectrochemical series.

Explanation:

When copper oxidizes with concentrated nitric acid, it produces copper ions; and the nitric acid is then reduced to nitrogen dioxide, a very poisonous gas which is brown in color and with an irritating odor.

[tex]$ Cu + 4HNO_{3} \rightarrow Cu(NO_{3})_{2} + 2NO_2+2H_2O$[/tex]

The copper ions ([tex]$Cu^{2+} $[/tex]) product which is initially coordinated to form nitrate ions from nitric acid and thus first gives the solution a green color.

Now when the solution is further diluted with water, the water molecules then displaces the nitrate ions  around the copper ions and causes the solution to change its color to blue. The reaction is -

[tex]$ 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2+ 2NO + 4H_2O $[/tex]

Yes, the results are supported by spectrochemical series.

PLEASE NEED URGENT HELP WILL VOTE BRAINLIEST!!!!!
Why does bromine (Br) have a smaller atomic radius than scandium (Sc)?
A. Scandium (Sc) has more energy shells than bromine (Br), making its atoms bigger.
B. Bromine (Br) has less neutrons than scandium (Sc), so it does not have as much mass.
C. Bromine (Br) has more electrons, which makes its energy sublevels more negative, which pulls them closer to the positively charged nucleus.
D. Electrons are added from right to left across the periodic table, so bromine (Br) does not have as many as scandium (Sc).

Answers

Answer:

Option (C) Bromine (Br) has more electrons, which makes its energy sublevels more negative, which pulls them closer to the positively charged nucleus.

Atomic radius is the size of the atom that measures from the center to the outermost electron.  Bromine has a smaller atomic radius because of more number of electrons. Thus, option C is correct.

What is the periodic trend of radii?

The elements are placed in the periods and groups in the periodic table based on the atomic number. Bromine belongs to group 17, period 4 in the periodic table, and scandium (Sc) to group 3, period 4.

In the periodic trend, the atomic radii of the element in the period decrease when moving from left-right. Here bromine and scandium both belong to the same period but differ in the group.

The number of electrons in bromine is more than the scandium element that in turn increases the force of attraction towards the nucleus making them have smaller radii.

Therefore, bromine has smaller radii.

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Using VSEPR model, how is the molecular arrangement about the central atom (molecular geometry) for XeF4?

Answers

Answer:

Square planar.

Explanation:

Hello,

In this case, it can be demonstrated that the central atom Xenon in XeF₄ has a sp³d² hybridization which means that its geometry is likely to be octahedral.  Nevertheless Applying by applying the valence shell electron pair repulsion (VSEPR) model to in order to minimize the repulsion among lone pairs, bond pairs and lone pair-bond pairs, we we realize repulsion is actually minimized when lone pairs are anti to one another and the fluorine atoms are in equatorial position, for that reason, the corrected and properly exhibited geometry or molecular arrangement of the compound turns out square planar. You can verify it on the attached picture.

Regards.

Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of H2SO4 and KOH are mixed.

a. H+(aq) + OH -(aq) → H2O(l)
b. 2K+(aq) + SO42-(aq) → K2SO4(s)
c. H+(aq) + OH-(aq) + 2K+(aq) + SO42-(aq) → H2O(l) + K2SO4(s)
d. H2^2+(aq) + OH-(aq) → H2(OH)2
e. No reaction occurs.

Answers

Answer:

a. H⁺(aq)+ OH⁻(aq) →  H₂O(l)

Explanation:

First, we will write the molecular equation for the reaction between H₂SO₄ and KOH.

H₂SO₄(aq) + 2 KOH(aq) →  K₂SO₄(aq) + 2 H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

2 H⁺(aq) + SO₄²⁻(aq) + 2 K⁺(aq) + 2 OH⁻(aq) →  2 K⁺(aq) + SO₄²⁻(aq) + 2 H₂O(l)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

H⁺(aq)+ OH⁻(aq) →  H₂O(l)

How does a lone pair distort the molecular shape?
O A. The lone pair forces bonding atoms farther from the nucleus.
B. The lone pair makes new bonds, changing the molecule's shape.
O C. The lone pair pushes bonding atoms closer to the nucleus.
O D. The lone pair forces bonding atoms away from itself.
SUBMIT

Answers

Answer:

D. The lone pair forces bonding atoms away from itself.

Explanation:

The lone pairs are found in the outermost shell thereby making sharing of electrons easier. Lone pairs which are found in a covalent bond creates a bond angle which makes it a determinant of the bond angle.

The lone pairs which are negatively charged repulses the bond pairs thereby creating a distortion in the shape of the molecule.

The lone pairs creates the distortion by forcing bonding atoms away from itself.

When titrating 50.0 mL of 0.10 M H2SO4 with 0.10 M NaOH, how many mL of NaOH will you have added to reach the 1st equivalence point?

Answers

Answer:

50.0mL 0.10M NaOH

Explanation:

The chemical equation of H₂SO₄ with NaOH to reach the first equivalence point is:

H₂SO₄ + NaOH → HSO₄⁻ + Na⁺ + H₂O

Where 1 mole of the H₂SO₄ reacts per mole of NaOH

The initial moles of H₂SO₄ are:

50.0mL = 0.0500L × (0.10 mol / L) = 0.0050 moles of H₂SO₄

As 1 mole of the acid reacts per mole of NaOH, to reach the first equivalence point we need to add 0.0050 moles of NaOH. As molarity of NaOH is 0.10M, the volume that we need to add to reach 1st equivalence point is:

0.0050 moles NaOH ₓ (1L / 0.10 moles NaOH) = 0.050L NaOH 0.10M =

50.0mL 0.10M NaOH

The potential of a voltaic cell (Ecell) is calculated based on several variables. Identify from the list below the values you would need to determine the cell potential.
a. number of electrons, n
b. density of metal, rho
c. coefficients from balanced redox equation (various)
d. temperature, T
e. Gibbs free energy change, ΔG
f. enthalpy change, ΔH
g. reduction potential, Ered

Answers

Answer:

number of electrons, n

Gibbs free energy change, ΔG

temperature, T

coefficients from balanced redox equation (various)

Explanation:

The standard electrode potential of a cell can be obtained from;

∆G°= -nFE°cell

Also;

E°cell= RTlnK/nF

Where;

∆G°= standard free energy of the cell

n= number of electrons transferred

F= Faraday constant

E°cell= standard cell potential

R= universal gas constant

T= temperature

K= equilibrium constant

Which of the following statements is true? A. The process of meiosis forms daughter cells which are genetically identical to their parent cells. B. Mitosis results in the formation of two haploid gametes which can then combine to form a diploid daughter cell. C. During the process of meiosis, haploid cells are formed. After fertilization, the diploid number of chromosomes is restored. D. The daughter cells formed during mitosis are genetically similar to, though not identical to, their parent cell.

Answers

Answer:

Mitosis results in the formation of two haploid gametes which can then combine to form a diploid daughter cell

Explanation:

Meiosis creates different cells

Answer:

During the process of meiosis, haploid cells are formed. After fertilization, the diploid number of chromosomes is restored.

Explanation:

Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
H2(g) + C2H4(g)--------C2H6(g)

Answers

Answer:

[tex]\Delta _rH=-136.27kJ/mol[/tex]

Explanation:

Hello,

In this case, for the given reaction, the enthalpy of reaction is computed in terms of the enthalpies of formation as:

[tex]\Delta _rH=\Delta _fH_{C_2H_6}-\Delta _fH_{C_2H_4}-\Delta _fH_{H_2}[/tex]

Whereas hydrogen, ethene and ethane enthalpies of formation are 0 kJ/mol, 52.47 kJ/mol and -83.8kJ/mol respectively. Therefore, we compute:

[tex]\Delta _rH=-83.8kJ/mol-52.47kJ/mol-0kJ/mol\\\\\Delta _rH=-136.27kJ/mol[/tex]

Best regards.

Suppose a balloon was released from the ground and rose to such a height that both the atmospheric pressure. Which statement is true?
A) The temperature change acts to decrease the balloon's volume and the pressure change acts to increase the balloon’s volume.
B) The temperature change acts to increase the balloon's volume and the pressure change acts to decrease the balloon’s volume.
C) Both the temperature and pressure changes act to increase the balloon's volume.
D) Both the temperature and pressure changes act to decrease the balloon's volume.

Answers

Answer:

The correct answer is option E) "none of the above".

Explanation:

This question is missing the following information "both the atmospheric pressure and temperature decreased"; as well as the last option, which is the correct one "none of the above". In this hypothetical scenario, a ballon has reach a height were the atmospheric pressure and the the temperature decreased. However, the change in the atmospheric pressure and the temperature would have no effect on the balloon's volume. The internal balloon's temperature and pressure tends to stabilize with the external conditions, therefore, the volume its not affected by the changes described in the question.

The molecule below, 2-acetyl-1-pyrroline (2-AP), is associated with the aroma and flavor of white bread and basmati rice. In higher concentrations, it gives cooked popcorn its characteristic buttery aroma and flavor. Its odor is very intense: We can detect 2-AP in water at concentrations below one nanogram/liter. The buttery aspect derives from a hydrolysis reaction. Identify the functional group sensitive to hydrolysis, write out a hydrolysis mechanism under acidic conditions, and give the structure of the product.

Answers

Answer:

OLA  IQESOXPJMXXXXOX{OADUOOAOOOOOSCDCSXWAXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

Explanation:

A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does. Classify the descriptions by whether they apply to the X or Y electrode.

a. Anode
b. Cathode
c. Loses mass
d. Electrons in the wire flow away from it
e. Anions from the salt bridge flow toward it
f. Cations from the salt bridge flow toward it
g. Gains mass
f. Electrons in the wire flow toward it

Answers

Answer:

X

Anode

Loses mass

Electrons in the wire flow away from it

Anions from the salt bridge flow toward it

Y

Cathode

Gains mass

Electrons in the wire flow toward it

Cations from the salt bridge flow toward it

Explanation:

A galvanic cell consists of an anode, a cathode and a salt bridge. The cathode is the negative electrode. The cathode increases in mass due to mass deposition. The cathode becomes increasingly negative as the cell reaction progresses, hence cations from the salt bridge flow towards it.

The anode is the positive electrode. It becomes more positive as the cell reaction progresses hence anions from the salt bridge flow towards it. The anode is the electrode where oxidation reaction occurs hence electrons are lost here and flow towards the cathode. The anode looses mass as the cell reaction progresses due to oxidation.

Select the correct answer. What affects the efficiency of a heat engine? A. high friction between hot and cold reservoirs B. the heat difference between hot and cold reservoirs C. low friction between hot and cold reservoirs D. the temperature difference between hot and cold reservoirs

Answers

Explanation:

Efficiency of a Carnot heat engine depends on :

(D) The temperature difference between hot and cold reservoirs

Which of the following is not a
trigonal planar molecule?
Select one:
a. AICI:
b. NH3
c. BF3
d. AlH3
Question 17​

Answers

Answer would be B
It’s the only one that does not have a +3 not a -3

An unknown compound’s semicarbazone melts at 162-165 degree Celsius. The compound does not give a silver mirror in the Tollens’ test. On reaction with KI/I2, NaOH/H2O no straw yellow precipitate forms. Identify the unknown. Explain your reasoning.

Answers

Answer:

Benzophenone

Explanation:

Given that:

an unknown compound’s semicarbazone melts at 162° -165°

The compound does not give a silver mirror in the Tollens’ test.

On reaction with KI/I2, NaOH/H2O no straw yellow precipitate forms.

The objective is to identify the unknown compound.

Since the unknown compound result to a semicarbazone, we can deduce that the unknown compound is a carbonyl compound. A carbonyl compound is either an aldehyde or ketone in nature. Also, the absence of  silver mirror in the Tollens’ test carried out in the reaction confirms that the compound is a ketone because  ketones will  never give a silver mirror in Tollens’ test.

Similarly, on reaction with KI/I2, NaOH/H2O no straw yellow precipitate forms,  that is an iodoform test. That implies that a keto-methyl group is absent in the unknown compound.

Finally, since the unknown compound melting point is between 162° -165° and Benzophenone semicarbazone  melting point is 164°.

We can conclude that the unknown  compound is Benzophenone semicarbazone  

What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?

Answers

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

Consider the following reaction at equilibrium. What effect will increasing the pressure of the reaction mixture have on the system?
CuS(s) + O2(g) ? Cu(s) + SO2(g)
Consider the following reaction at equilibrium. What effect will increasing the pressure of the reaction mixture have on the system?
CuS(s) + O2(g) ? Cu(s) + SO2(g)
a) The equilibrium constant will increase.
b) The reaction will shift to the left in the direction of reactants.
c) The reaction will shift to the right in the direction of products.
d) No effect will be observed.
e) The equilibrium constant will decrease.

Answers

Answer:

Choice d. No effect will be observed as long as other factors (temperature, in particular) are unchanged.

Explanation:

The equilibrium constant of a reaction does not depend on the pressure. For this particular reaction, the equilibrium quotient is:

[tex]Q = \displaystyle \frac{[\mathrm{SO_2\, (g)}]}{[\mathrm{O_2\, (g)}]}[/tex].

Note that the two sides of this balanced equation contain an equal number of gaseous particles. Indeed, both [tex][\mathrm{SO_2\, (g)}][/tex] and [tex][\mathrm{O_2\, (g)}][/tex] will increase if the pressure is increased through compression. However, because [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex] have the same coefficients in the equation, their concentrations are raised to the same power in the equilibrium quotient [tex]Q[/tex].

As a result, the increase in pressure will have no impact on the value of [tex]Q\![/tex]. If the system was already at equilibrium, it will continue to be at an equilibrium even after the change to its pressure. Therefore, no overall effect on the equilibrium position should be visible.

Express 450 x 10-9 m (wavelength of blue light) in decimal notation (i.e., express
the number without using scientific notation).

Answers

Answer:

0.00000045 m  is the wavelength of blue light in decimal

0.00000045 m  is the wavelength of blue light in decimal without using scientific notation.

What is scientific notation?

Scientific notation is defined as a way of expressing numbers which are too large or too small so that they can be easily written in decimal form. It can be referred to the scientific form or the scientific index form or even the standard form.

Base ten notation is used by scientists, engineers as it helps in simplification of arithmetic operations. It contains the significant figures which include all non-zero numbers , the zeroes between significant digits and zeroes which are needed to be significant.

In scientific notation, the base should always be ten. The exponent should be a non-zero integer and it can be either positive or negative.

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How much heat will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°C to 67.0°C?

Answers

A 50.3 g piece of aluminum (specific heat = 0.930 J/g・°C) will change its temperature from 23.0°C to 67.0°C while absorbing 2.06 × 10³ J of heat.

When a material absorbs heat, its temperature increases. We can calculate the amount of heat (Q) absorbed using the following expression.

[tex]Q = c \times m \times \Delta T[/tex]

where,

c: specific heatm: massΔT: change in the temperature

[tex]Q = c \times m \times \Delta T\\Q = \frac{0.930J}{g. \° C } \times 50.3 g \times (67.0 \° C - 23.0 \° C) = 2.06 \times 10^{3} J[/tex]

A 50.3 g piece of aluminum (specific heat = 0.930 J/g・°C) will change its temperature from 23.0°C to 67.0°C while absorbing 2.06 × 10³ J of heat.

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What is the optimum pH to separate a mixture of lysine, arginine, and cysteine using electrophoresis

Answers

Answer:

9.5

Explanation:

Electrophoresis is a separation technique which involves the passage and the use of electric current in separating amino acid mixtures. The positively charged protein moves to the negative electrode while the negatively charged protein moves to the positive electrode which is in accordance to the law of attraction.

Proteins however perform optimally at the right temperature and pH. Studies shows that the optimum pH to separate a mixture of lysine, arginine, and cysteine using the electrophoresis method of separation is around 9.5

When the pH of the solution equals the pKa of an indicator, the solution will have an intermediate color. Estimate the pKa of bromocresol green, the indicator that made the transition in the acidic region of the titration.

Answers

Answer:

pKa bromocresol green is ≅4.5

Explanation:

The bromocresol green is a chemical indicator used in titrations with equivalence point at pH's between 3 and 5.

Is an indicator that, in acidic region is yellow, and in basicic region is blue. The intermediate color is green (at pH≅ 4.5).

As at the intermediate color of the indicator pKa = pH,

pKa bromocresol green is ≅4.5

What is the procedure for heating a metal to an exact but measured temperature?

Answers

Answer:

An unknown metal between 10-30 g is transferred to a test tube, place the tube in water that is boiling for ten minutes until it reaches a thermal equilibrium.

Explanation:

convert 0.237 μL to ml

Answers

Answer:

0.000237mL

Explanation:

0.237 x 10^-6L = 0.000000237L = mL

0.000237mL

A 100.0 mL sample of 0.18 M HCl is titrated with 0.27 M KOH at 25°C. Determine the pH of the solution after the addition of 66.67 mL of the KOH titrant.

Answers

Answer:

pH = 7.0

Explanation:

The HCl reaction with KOH as follows:

HCl + KOH → H₂O + KCl

To find pH first we need to know how many moles of each reactant reacts as follows:

HCl = 0.1000L * (0.18 mol / L) = 0.018 moles HCl

KOH = 0.06667L * (0.27mol / L) = 0.018 moles KOH

That means all HCl reacts with all KOH and you will have in solution just water. The equilibrium of water is:

H₂O(l) ⇆ H⁺(aq) + OH⁻(aq)

K = 1x10⁻¹⁴ = [H⁺] [OH⁻]

As the amount of H⁺ = OH⁻:

1x10⁻¹⁴ = [H⁺]²

[H⁺] = 1x10⁻⁷M

as pH = -log [H⁺]

pH = 7.0

You wish to set up an electrochemical cell that has a copper anode and an
Eºcell value > 1.00 V. What should your cathode and cathode solution be?

Answers

i think cathode should be silver or gold
you can use silver nitrate solution or mercury nitrate solution

Write the net ionic equation for the precipitation of silver phosphate from aqueous solution:________
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)

Answers

Answer: 3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)

Explanation:

The question requires us to write down the net ionic equation for the precipitation of silver phosphate from aqueous solution:________

Note that we we told to:

(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)

Answer:

From the solubility rule,

Phosphate (PO₄³⁻) and Carbonates are insoluble except for NH₄⁺ and Group1A compounds.

According to the solubility rule, the precipitation of silver phosphates and that of the net ionic equations is given thus;

3AgNO³ (aq) + K₃PO₄ (aq) → Ag₃PO₄ (s) + 3KNO₃ (aq)

while the Net ionic equation is given;

3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)

cheers i hope this helped !!

2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average molarity of the NaOH solution. 4. Label the volumetric flask containing the NaOH solution with the average molarity.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete as the actual values are not provided however you can solve the question yourself if you have the actual value using the formulas below.

The formula for Molarity is

Molarity = number of moles (n) ÷ volume (in dm³ or Litre)

If number of moles is not given, to calculate for number of moles

number of moles (n) = given mass of NaOH ÷ molar mass of NaOH

Please NOTE that the volume MUST be converted to dm³ (or litre) if not provided in dm³.

The unit for Molarity is mol/dm³ or mol/L or M (molar concentration).

Average molarity = (Trial 1 + Trial 2 + Trial 3)/ 3

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The method of accounting for long-term investments in equity securities that most closely fits the requirements of accrual accounting is the If youre storing some personal information like Debit/Credit card numbers or Passwords etc, on different sites for running youre E-business. Do you think that cookies are stored and maintain such information on the server-side and hackers can''t steal user''s information from these cookies easily? Do you agree with the above statement? Please give short comments in favor of or against the statement. How did Spanish contact with the New World drive the development of capitalism in Europe? (Supporting Details: Encomienda System, Incas) What are reasons to vote ? What are reasons not to vote? Que es la proporcionalidad inversa? What is the term for a short statement about history that has not yet beenproved?A. ThemeB. ClaimC. ConclusionD. Point of view What is 0/7 Simplified A. 7 B. 70 C. 0 D. Undefined In the story Romeo and Juliet, how did Juliet Capulet die? Appropriate, carefully timed prompts by the listener might includeO "Who do you think you are?"O "What happened then?"O "Are you sure?"O "What would make you do that?" Trish has bought a new computer that she plans to start working on after a week. Since Trish has not used computers in the past, she has asked her friends to suggest any preventive measures that she can take to avoid hardware failures. Which of the following suggestions should her friends give her? Why did businesses hire children Balance the following equations: i) KClO3 KCl + O2 ii) HNO3 + NaHCO3 NaNO3 + H2O + CO2 iii) Na + H2O NaOH + H2 Can someone please help me with this exercise? I'm having problems with point B. Which is the best example of vivid imagery?O A. The room had nice colors on the walls.B. The walls of the room glowed a soft red.C. The room had four walls and a door.O D. The walls of the room were painted. Maddie spent about $12 on 3.8 pounds of one type of fruit which types of fruit could Maddie have bought difference of squares factoring ( please show work) :)p2 - r2 = 0 India's first great civilization wasAryans.Harappa.Gupta.Mauryans. Parent Co. owns 90% of the 10,000 outstanding shares of Subsidiary Co.'s common stock on December 31, year 1. On that date, the stockholders' equity of Subsidiary was $150,000, consisting of $100,000 of no-par common stock and $50,000 of retained earnings. On January 2, year 2, Subsidiary issued 2,000 previously unissued shares for $24,000 to various outside investors. As a consequence of this transaction, Parent's ownership share was reduced to 75%. Which of the following correctly reports this transaction?a. Parent's investment in Subsidiary is reduced by $4,500.b. Parent's investment in Subsidiary is increased by $3,000.c. The consolidated income statement reports a loss of $7,500.d. The consolidated income statement reports a gain of $4,000. _____________ are usually described as being interactional, contextual, episodic, and improvisational. Identify the comma rule that the following sentence breaks: In the early morning hours everything is silent and peaceful. a) Use a comma to separate three or more items in a series. b) Use a comma and a conjunction to separate two complete thoughts. c) Use a comma to set off a phrase or clause at the beginning of a sentence. d)Use a comma to separate coordinate adjectives.