(i ) The velocity of the car at the bottom of the hill is 31.3 m/s.
(ii) The height at which it will have half the speed is 12.5 m.
What is the velocity of the car at the bottom?
The velocity of the car at the bottom of the hill is calculated by applying the principle of conservation of energy as follows;
¹/₂mv² = mgh
v = √ (2 gh )
where;
h is the height of the hillg is gravityv = √ (2 x 9.8 x 50 )
v = 31.3 m/s
The height at which it will have half the speed is calculated as;
¹/₂v = ¹/₂ ( 31.3 m/s ) = 15.65 m/s
h = v² / 2g
h = ( 15.65² ) / ( 2 x 9.8 )
h = 12.5 m
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A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of 39.1 cm . The room is slightly warm, so the speed of sound is 344 m/s.
If the string's linear density is 0.690 g/m and the tension is 160 N , how long is the vibrating section of the violin string?
The length of the vibrating section of the violin string is approximately 16 cm.
The length of the vibrating section of the violin string can be calculated using the formula for the wavelength of a wave on a string:
λ = 2L / n
where λ is the wavelength, L is the length of the vibrating section of the string, and n is the number of nodes in the vibration.
Next, we can use the formula for the frequency of a wave on a string:
[tex]f = (1 / 2L) * (T / μ)^0.5[/tex]
where f is the frequency, T is the tension in the string, and μ is the linear density of the string.
Combining these two equations and solving for L, we get:
[tex]L = (μ / T) * (f^2 / n^2)[/tex]
Substituting the given values, we get:
[tex]L = (0.690 g/m / 160 N) * [(344 m/s / (2 * 39.1 cm))^2 / (1 / 2)^2][/tex]
Converting the units, we get:
[tex]L = (0.690 g/m / 160 N) * [(344 m/s / (2 * 0.391 m))^2 / (1 / 2)^2][/tex]
Calculating the value, we get:
L = 0.016 m
So, the length of the vibrating section of the violin string is approximately 16 cm.
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one little of water at 100c is added to four litres of water at 30c.what will be the final temperature of the water?
Answer:
o calculate the final temperature of the water, we can use the formula for heat transfer:
Q = mcΔT
where Q is the heat transfer, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature.
For the one liter of water at 100°C, the heat transfer is:
Q1 = (1 kg) * (4.18 J/g°C) * (100°C - 30°C) = 4180 J
For the four liters of water at 30°C, the heat transfer is:
Q2 = (4 kg) * (4.18 J/g°C) * (100°C - 30°C) = 16680 J
Since heat is conserved, the total heat transfer must remain constant:
Q1 + Q2 = Qfinal
Therefore, the final temperature of the water can be calculated as:
Qfinal = (5 kg) * (4.18 J/g°C) * ΔTfinal
Solving for ΔTfinal, we get:
ΔTfinal = Qfinal / (5 kg) * (4.18 J/g°C) = (Q1 + Q2) / (5 kg) * (4.18 J/g°C) = (4180 J + 16680 J) / (5 kg) * (4.18 J/g°C) = (20860 J) / (5 kg) * (4.18 J/g°C) = 40°C
Therefore, the final temperature of the water will be 40°C.
Explanation:
Answer:
The final temperature of the water will be approximately 46.25°C.
Explanation:
Let's call the initial temperature of the first liter of water T1 = 100°C and the initial temperature of the four liters of water T2 = 30°C.
The total mass of the water is 1 + 4 = 5 liters.
Using the equation of Heat Transfer: Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity of water, and ΔT is the change in temperature, we can calculate the heat transfer from the first liter of water to the four liters of water.
Q = (1 kg) * (4.18 J/g°C) * (100°C - T3)
Q = (4 kg) * (4.18 J/g°C) * (T3 - 30°C)
Solving for T3, we get:
T3 = 46.25°C
So, the final temperature of the water will be approximately 46.25°C.
two charges, each of magnitude 4.02 c, are placed at the ends of a meter stick. find the electric potential (relative to infinity) at the 39.7 cm mark of the meter stick.
At the 39.7 cm mark on the meter stick, the electric potential (relative to infinity) is -140.74 x 106 V.
What does "electric potential" mean?Electric potential is the effort required to transport an units charge from one place to another in the presence of an electric field. Earth is typically chosen as the reference point, but any location outside the range of the applied electric charge can be used. potential electricity.
Let the negative charge be located at the left end of the meter stick and the positive charge at the right end. E = kq / x2, where k is the Coulomb constant (8.99 x 109 Nm2/C2) and q seems to be the charge at the left end of the meter stick, can be used to calculate the electric field at a location x cm from the left end of the meter stick (4.02 C).
The following equation can be applied to compute the electrical potential difference seen between left end of the meter stick & infinity:
ΔV left = -kq / d = -kq / 100 cm = -kq / 0.01 m = -8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = -359.57 x 10^6 V
Similarly, the electric potential difference between the right end of the meter stick and infinity can be calculated as:
ΔV right = kq / d = kq / 100 cm = kq / 0.01 m = 8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = 359.57 x 10^6 V
The total electric potential difference between the 39.7 cm mark and infinity can then be calculated as:
ΔV_total = ΔV_left + ΔV_right * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 359.57 x 10^6 V * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 218.83 x 10^6 V = -140.74 x 10^6 V
Therefore, the electric potential (V) at the 39.7 cm mark relative to infinity can be calculated as:
V = ΔV_total = -140.74 x 10^6 V
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Two blocks of masses 3 kg and 5 kg
approach each other with initial velocities 4 m/s and -6 m/s respectively.
The two blocks collide in a totally inelastic collision. What is their common
final velocity after the inelastic collision?
The common final velocity of the two blocks after the inelastic collision is -2.25 m/s.
In a totally inelastic collision, the two objects stick together and move as a single object with a common velocity after the collision. The final velocity of this combined object can be determined using the law of conservation of momentum.
The law of conservation of momentum states that the total momentum of an isolated system remains constant if no external forces act on it. This means that the total momentum of the two blocks before the collision must equal their total momentum after the collision.
The momentum of each block before the collision can be calculated as follows:
m1 * v1 = 3 kg * 4 m/s = 12 kg m/s
m2 * v2 = 5 kg * -6 m/s = -30 kg m/s
The total momentum before the collision is the sum of the individual momenta:
[tex]p_initial = m1 * v1 + m2 * v2 = 12 kg m/s + (-30 kg m/s) = -18 kg m/s[/tex]
After the collision, the two blocks have combined into a single object of mass m1 + m2 = 3 kg + 5 kg = 8 kg. The velocity of this combined object is equal to the final velocity of the collision, which we will call v_final.
The total momentum after the collision is equal to the momentum of the combined object:
[tex]p_final = (m1 + m2) * v_final = 8 kg * v_final[/tex]
Setting p_initial equal to p_final and solving for v_final:
[tex]-18 kg m/s = 8 kg * v_finalv_final = -18 kg m/s / 8 kg = -2.25 m/s[/tex]
So the common final velocity of the two blocks after the inelastic collision is -2.25 m/s.
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carl is on vacation from school and he went to the beach for the day. he laid his towel out and got his sunblock out. he noticed a warning on the back of the aerosol can of sunblock -- it says: contents under pressure; do not heat. why does the warning advise against heating the can?
The warning advises against heating the can because if the can is heated, the pressure inside it can increase, causing it to burst and potentially causing injury.
Heating the can cause the pressure inside it to increase, leading to a dangerous and potentially explosive situation. This is because the aerosol can contains a mixture of ingredients that are pressurized, including a volatile propellant, the sunblock product, and possibly other chemicals.
When the can is heated, the pressure inside it can rise to a level that exceeds the strength of the can, causing it to burst. This can release the contents of the can rapidly and forcefully, posing a risk of injury to anyone nearby. Therefore, it's important to avoid heating the can and to handle it with care, following the manufacturer's instructions and warnings.
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a plastic balloon that has been rubbed with wool will stick to a wall. can you conclude that the wall is charged? if so, where does the charge come from? if not, why does the balloon stick?
No, it doesn't always imply that the wall is charged because the ball can cling to a non-charged wall.
The effect is caused by static electricity where we have plastic balloons. Static electricity refers to the buildup of electric charge in an item. Static electricity is significant because it may cause items to cling to one another.
This happens when two items with opposing charges, positive and negative, attract one other. Wool is a conductive substance, which means it quickly absorbs electrons as we discuss our dilemma. As a result, pressing a balloon against a wall causes electrons to move from the wool to the balloon's surface.
The rubbed area of the balloon is now negatively charged. Rubber things, such as the balloon, are electrical insulators, which means they hinder the flow of electrical charge through them.
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A 25 kg box is lifted to a height of 6 m. If the lift required 400 watts of power, what distance was the box lifted?
Group of answer choices
2.8 m
4.5 m
4.2 m
3.7 m
Explanation:
many greetings to your teacher : the question and answer options are wrong.
let's repeat the basic definitions :
Force = mass × acceleration
for a lift the acceleration is going against Earth's gravity : 9.81m/s²
so, we have
F = 25kg × 9.81m/s² = 245.25 N
Work = force × distance
so, we have
W = 245.25 N × 6 m = 1,471.5 J
Power = work / time
so, we have
400 watts = 1,471.5 J / time
time = 1,471.5 J / 400 watts = 3.67875 ≈ 3.7 seconds
so, as you can see, the question has to be "how long did the lift take, when it required 400 watts of power ?"
and the answer is "about 3.7 seconds".
NOT about the distance. that was already defined in the first sentence : 6 m.
without knowing the time duration, no distance can be calculated out of the given data. if we cannot trust the given 6m, then we have one equation with 2 variables (distance and time). that has infinitely many solutions.
Which object has the most momentum? (I don’t need work just the answer)
Answer: I don't know sorry
Explanation:
yeah
Answer:
Z
Explanation:
Momentum = mass * velocity
Z has the highest mass * velocity = 15 * 3 = 45 kg m/s
through which of the gaussian surfaces is the total electric flux zero?
The Gaussian surface through which the total electric flux is zero is the one that does not enclose any net charge.
According to Gauss's Law, the total electric flux passing through a closed surface is proportional to the charge enclosed by that surface. If there is no charge enclosed by the surface, then the total electric flux passing through that surface is zero.
Therefore, if there is no charge enclosed by a Gaussian surface, the total electric flux passing through that surface is zero.
However, if there is a charge enclosed by a Gaussian surface, the total electric flux passing through that surface is not necessarily zero. In that case, the total electric flux passing through the surface is proportional to the charge enclosed by the surface.
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how does the temperature dependence of resistance explain the trends you see on the v -i plot for your light bulb? (you do not need to calculate anything here, but give a qualitative answer based on the shape of your v -i plot.)
The resistance decreases with the increasing temperature. The lower the current, the higher the resistance.
What is resistance?Electrical resistance, or resistance to electricity, is a force that opposes the passage of current. In this way, it indicates how difficult the process is for the current to flow. The resistance is measured in ohms.
When there is an electron difference between the two terminals, electricity flows from high to low. That flow is countered by resistance. The lower the current, the higher the resistance. The stronger the current, the lower the resistance. The resistance decreases with the increasing temperature.
Therefore, the resistance decreases with the increasing temperature.
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what is the frequency of the sound wave that a bicyclist hears if she is approaching the bagpiper at 10.0 m/s ?
As a result, the sound wave's frequency and wavelength are 440 Hz and 5.4 m, respectively, for a bike traveling at either 10.0 m/s toward the bagpiper or away from him.
How does frequency mean?The quantity of waves passing a fixed place in a unit of time is known as the frequency in physics. A body undergoing periodic motion undergoes how many cycles or vibrations in one unit of time, according to this definition.
Does frequency equate to energy?They have a relationship between frequency and amplitude and the quantity of energy they transport. Energy is inversely correlated with frequency and amplitude, increasing with higher frequency.
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suppose that one such plate has an average speed of 3.4 cm/yr, assuming the plate maintains the given speed for 1.0 s, how far, in meters, does it move?
Complete Question: Large sections of the Earth's crust called tectonic plates move slowly. How long, in meters, does one of these plates go if its average speed is 3.4 cm/year and it keeps moving at that rate for 1.0 second?
The distance moved by the plate in this case would be [tex]1.08 * 10^-10 m/s * 1.0 s = 1.08 * 10^-10 m.[/tex]
The speed of tectonic plates is measured in centimeters per year (cm/yr), but to find the distance moved in meters, we need to convert the speed to meters per second (m/s). To do this, we first convert the speed to meters per year (m/yr) and then divide by the number of seconds in a year (31,536,000 s/yr).
The average speed of the tectonic plate is 3.4 cm/yr, so the equivalent speed in meters per year is 3.4 cm/yr * 0.01 m/cm = 0.034 m/yr. The speed in meters per second is then 0.034 m/yr / (31,536,000 s/yr) = 1.08 x 10^-10 m/s.
If the plate maintains this speed for 1.0 s, the distance it moves can be calculated using the formula distance = speed x time. The distance moved by the plate in this case would be [tex]1.08 * 10^-10 m/s * 1.0 s = 1.08 * 10^-10 m.[/tex]
This distance may seem small, but it is important to remember that tectonic plates move slowly over long periods of time.
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Explain how your core sample differs from an actual core sample from the earth. It is in a jar and has colored sand to represent the core.
A obtained experimental is indeed a long, narrow chunk of stone that is extracted by drilling a hole through a rock with such a unique tool and lifting out an undamaged piece of the rock.
Is lifting considered work in physics?Work is being done on the thing as you lift it. The equation W = Fd describes the work W performed on an item by a constant force. It is determined by multiplying the force's intensity by how far the object is moved by the force.
Are you lifting something?Surface and body are no longer in contact when the body is lifted, eliminating any frictional forces. For the simple reason that friction opposes any relative motion between a surface and a substance (both are in contact).
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what is the classical momentum pclass(t) for this classical particle? find an expression for ! such that
In classical physics, an object's momentum is calculated by multiplying its mass by its speed.
How do classical and relativistic momentum differ from one another?
Relativistic momentum is the same as classical momentum at slow speeds. As u moves closer to c, relativistic momentum grows infinitely large. This suggests that a mass-containing item cannot travel at the speed of light. As with classical momentum, relativistic momentum is conserved.
The two types of momentum are linear momentum and angular momentum. The three different types of inertia are inertia at rest, inertia in motion, and inertia in direction. Mass and speed are factors in momentum. An object moving with a velocity has linear momentum, but a spinning object has angular momentum.
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2.81 A certain volcano on earth can eject rocks vertically to a maximum height H. (a) How high (in terms of H) would these rocks go if a volcano on Mars ejected them with the same initial velocity? The acceleration due to gravity on Mars is 3.71 m/s², and you can neglect air resistance on both planets. (b) If the rocks are in the air for a time T on earth, for how long (in terms of 7) will they be in the air on Mars?
The height of a volcano can reach a maximum of 0.3 times that of Earth, and boulders will float in the air for 0.38 times as long as they did on Earth.
a) When rocks are ejected from a volcano, their initial velocity (V) and the acceleration due to gravity (G) dictate how high they may go (g).
The equation for the greatest height (h) is given by h = V2/. (2g). Gravitational acceleration is 9.8 m/s2 on Earth and 3.71 m/s2 on Mars.
With the same beginning velocity as on Earth, boulders blasted from a volcano on Mars would reach a height of h = V2/(2 * 3.71) = (V2/7.42) m.
On Earth, the maximum height would be 1/7.32 times 1/2.72 times 0.37 times H.
(b) The equation T M = 2V/g may be used to calculate how long the pebbles will remain in the air on Mars (T M).
The equation is T E = 2V/9.8 on Earth and T M = 2V/3.71 on Mars. T M/T E = (2V/3.71) / (2V/9.8) = 3.71/9.8 = 0.38 gives the ratio of the time in the air on Mars to that on Earth.
In other words, the rocks will remain in the air for around 0.38 times as long as they were on earth.
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Which object has potential energy?(1 point)
Responses
unlit lightbulb
unlit lightbulb
rock on the ground
rock on the ground
stereo speaker
stereo speaker
can of gasoline
The object that has potential energy is the can of gasoline.
What is potential energy?Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
The forms of potential energy includes:
Elastic Potential Energy.Electrical (Electromagnetic) Potential Energy.Gravitational Potential Energy.Nuclear Potential Energy.Potential energy is described as the energy a system has due to position, shape, or configuration.
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do you see any evidence that the coefficient of restitution depends on the intial velocity of the cart?
Newton's law of restitution is expressed in this formula. The restitution coefficient always fulfills 0e1. The balls continue to be in contact after the impact when e=0.
What is the height equivalent of the coefficient of restitution formula?The equation yields the coefficient of restitution. Speed increase/decrease is the Coefficient of Restitution. We had to use the average height that we measured and enter it into the calculation in order to calculate speed. v = √(2gh) (2gh) where v = speed, g = 9.8 m/s2, and h = measured average height.
What is the collision's coefficient of restitution?The coefficient of restitution is a value that ranges from 0 to 1. The difference between the velocity of two objects following a collision in a perfectly inelastic collision is zero because they things cling to one another.
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Television broadcasts utilize _________ waves. Select one: magnetic gamma radio ultraviolet
Television broadcasts utilize radio waves to transmit signals from the broadcaster to the television set.
The signals contain data, including audio and video, which is decoded and shown on the screen. The electromagnetic spectrum, which also contains visible light and X-rays, includes radio waves. These waves can move across a variety of media, including air, water, and even space, and have varying frequencies.
Since the early 20th century, radio waves have been used to broadcast television, becoming a standard in homes all over the world. Over time, technological advancements have improved picture and sound quality and increased the number of available channels. In the worlds of communication and entertainment, television transmissions and radio waves have, in short, had a long and significant association.
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explain how a converging lens could be used to ignite a piece of carbon paper
A converging lens, also known as a positive lens, is a type of lens that has the ability to focus light rays to a single point, known as the focal point. This property can be utilized to ignite a piece of carbon paper.
When using a converging lens to burn carbon paper, care must be taken to position the lens such that sunlight (or another light source) is focused on the paper. As the light is focused, its intensity rises until it eventually reaches a temperature high enough to burn the carbon paper. The lens serves as a magnifying glass in this process, focusing the light beams onto a pinpoint area of the carbon paper and creating heat that eventually ignites the paper.
The size and temperature of the point of ignition will depend on the lens's distance from the paper, its size, and the angle at which the light rays are directed. The "fire by reflection" or "camera obscura" principle refers to this phenomenon. The principle of refraction, which asserts that light changes direction as it passes through various media with differing refractive indices, can be demonstrated in this way.
It is feasible to create a concentrated point of heat hot enough to ignite the carbon paper by employing a converging lens to focus the light.
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What type of friction is the force between two moving surfaces
It is known as a force that acts between moving surfaces as kinetic friction. The movement of a body on the surface is opposed by a force that is perceived.
What causes two moving surfaces to friction?There may still be friction between the surfaces even when they are moving past one another; this sliding friction is known as a kinetic frictional force.
Between two surfaces, what force exists?Friction is a force that exists between two surfaces that are sliding or attempting to slide over one another. As an illustration, friction makes it difficult to push a book over the floor. An object is always moved by friction in the opposite direction from where it is moving or trying to move.
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what is the sensitivity of the analytical balance; that is, what is the smallest amount of mass that it can detect?
Laboratory equipment with a high level of sensitivity, analytical balances are used to precisely measure mass. Their readability ranges from 0.01 mg to 0.10 mg.
What is the analytical balance's sensitivity to top loading?
Top-loading balances are less expensive than analytical balances but are less precise because they can only weigh things up to 200 g. With a readability of up to three decimal places to the right of the decimal point, they are regarded as semi-analytical balances (up to . 001 g). The readability of precision balances is 0.01 g.
The weighing chamber or draft shield on analytical scales protects the incredibly small samples from being impacted by air currents. The "magnetic force restoration" theory underlies the operation of analytical balance. It is an electromagnetic balance that calculates an object's mass using an electromagnet.
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How do you think population variables would affect the economic impact of an environmental hazard?
Effects of Population Growth on The Economy Population growth may have a positive effect on the economy.
How does population affect the economy?Human population growth bounces the Earth's system in a variety of ways, involving Increasing the extraction of resources from the environment. Rapid population growth built it more difficult for low-income and lower-middle-income countries to supply the increase in public expenditures. Population growth, along with increasing use, of the economy tends to increase emissions of climate-changing greenhouse gases.
On a facile level, the relationship between growth in population and growth in per capita income is clear. After all, per capita income equals total income divided by population. The growth rate of per capita income forcefully equals the difference joining the growth rate of income and the growth rate of population.
So we can conclude that Population size, growth, age structure, and geographic issues influence economies.
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A spaceship hovering over the surface of Venus drops an object from a height of 24 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases. [The acceleration due to gravity on Venus is 90.7% of that on Earth,
gVenus = (0.907)g.]
The time taken is 2.3s for a spaceship hovering over the surface of Venus to drop an object from a height of 24m, and 2.21s for the same spaceship hovering over the surface of Earth to drop an object from the same height.
What is the time taken?To solve this problem, we will use the motion equation to calculate the time of flight of an object on the surface of Venus and the Earth. The height is related by the following equation of motion:
h = v₀t + gt²/2
Because the object's initial velocity before dropping is zero, we can simplify the equation to:
h = gt²/2
We know the height h of the spaceship hovering, and Venus's gravity is g = 9.07m/s². Substituting the following values into the equation:
24m = (9.07 m/s²t²)/2
To calculate the time it takes an object dropped by a spaceship hovering from a height of 24m to reach the surface of Venus, we must remove t from the equation above, yielding:
t = [tex]\sqrt{2(24m)/9.07m/s^{2} }[/tex]
= [tex]\sqrt{48m/9.07m/s^{2} }[/tex]
= 2.3s
Similarly, to calculate the time it takes an object dropped from a height of 24m to reach the Earth's surface, and the gravity of the Earth is g = 9.81m/s² .
t = [tex]\sqrt{2(24m)/9.81m/s^{2} }[/tex]
= [tex]\sqrt{48/9.81m/s^{2} }[/tex]
= 2.21s
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a spring requires a force of 3 n to stretch to 20 cm beyond its original length. the amount of work required to stretch the spring to 40 cm beyond its original length is
The amount of work required to stretch the spring to 40 cm beyond its original length is 5333 J.
Spring is defined as an elastic object which gets deformed from its original shape when an external force is applied to it and again reverts back to its original shape when the external force is removed. When a force is placed on a material, the material stretches or compresses in response to the force. The length of the extension is directly proportional to the amount of force applied to it. Hence more the extension more the force is applied. Force and stretch are proportional to one another such that if you double the force applied, the amount of stretching of the spring will also be double. F 1 =kx 1, 3=k×20. This spring constant k= 20/3 N/m. Now, W= ½ k x^2 =1/2×20/3×40×40= 5333 J.
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the distance from the sun is 93,000,000 miles and is called 1 au. what is the distance in miles to a star that is
The distance from star A to star B is about 3.999 billion miles.
AU stands for "astronomical unit". It is a unit of measurement used in astronomy and represents the average distance from the Earth to the Sun, which is about 93 million miles (or 149.6 million kilometers).
If the average distance from star A to star B is 43 AU, then we can find the distance in miles by multiplying 43 by the distance of 1 AU from the sun, which is about 93 million miles:
Distance from star A to star B = 43 x 93,000,000 miles
Distance from star A to star B = 3,999,000,000 miles
Therefore, the distance from star A to star B is about 3.999 billion miles (or 3.999 x 10^9 miles).
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--The complete question is, The distance from Earth to the sun is defined as 1 astronomical unit, or AU. It is about 93 million miles, The average distance from star A to star B is 43AUs.
Find this distance in miles.--
a car traveling on a uphill grade has a grade resistance of lb. determine the weight of the car to the nearest hundred pounds.
To the nearest hundred pounds, the weight of the car is 4,000 pounds.
The force of grade resistance can be related to the weight of the car using the equation:
F_grade = (W_car × sinθ) / g
where F_grade is the force of grade resistance, W_car is the weight of the car, θ is the slope angle (1.6°), and g is the acceleration due to gravity (32.2 ft/s²).
Rearranging the equation to solve for W_car, we have:
W_car = (F_grade × g) / sin θ = (114 lb × 32.2 ft/s²) / sin(1.6°)
Using a calculator, the weight of the car can be found to be approximately 4,000 pounds. To the nearest hundred pounds, the weight of the car is 4,000 pounds.
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A car traveling on a 1.6° uphill grade has a grade resistance of 114 lb. determine the weight of the car to the nearest hundred pounds.
an elevator suspended by a cable is descending at constant velocity.part ahow many force vectors would be shown on a free-body diagram?how many force vectors would be shown on a free-body diagram?012345
Two force vectors would be shown on a free-body diagram for an elevator descending at a constant velocity: the gravitational force and the tension force in the cable.
What are the forces of the free body diagram?In a free-body diagram, the forces acting on an object are represented as vectors pointing in the direction that the force is acting. When an elevator is suspended by a cable and is descending at a constant velocity, there are two main forces acting on the elevator:
gravity and tension.Gravity is a force that acts downward on all objects and is equal to the mass of the object times the acceleration due to gravity (g). The force of gravity on an elevator can be represented as a downward-pointing vector.
The tension in the cable is the force exerted by the cable on the elevator that opposes the force of gravity. This force can be represented as an upward-pointing vector.
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what is the force exerted by a catchers glove on a .15 kg baseball moving at 35 m/s that is stopped in .02 s
Answer:
Explanation:
v=u+at
Final velocity v=0 , u=35m.s, a=-a , t=0.02
a=u/t = 35/0.02 = 1750 m/s2
force = mass * acceleration = 0.15 * 1750 = 262.5N
A 1 m spring requires 10 J to stretch the spring to 1. 1 m. How much work would it take to stretch the spring from 1 m to 1. 2 m
It would take 8 J of work to stretch the spring from 1 m to 1.2 m.
The work required to stretch a spring is given by the formula:
[tex]W = (1/2)kx^2,[/tex] where W is the work done, k is the spring constant, and x is the distance the spring is stretched or compressed.
Given that the spring requires 10 J of work to stretch from 1 m to 1.1 m, we can calculate the spring constant as follows:
[tex]10 J = (1/2)k(0.1 m)^2[/tex]
[tex]k = 200 J/m[/tex]
Using this spring constant, we can calculate the work required to stretch the spring from 1 m to 1.2 m:
[tex]W = (1/2)(200 J/m)(0.2 m)^2[/tex]
[tex]W = 8 J[/tex]
Therefore, it would take 8 J of work to stretch the spring from 1 m to 1.2 m.
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determine the maximum mass of the lamp that the cord system can support so that no single cord develops a tension exceeding 400 n.
In order to determine the maximum lamp mass, we therefore convert the maximum tension cable value to 400N, and the cord type DE is discovered.Therefore, 20.387 kg is the maximal mass of the lamp at F.
How do you establish the upper limit?Reason: To locate the maximum, you must identify the point at which the graph turns from growing to decreasing.We check at the derivative and see when the changing the ways from positive to negative to determine the rate at which the graph goes from increasing to decreasing.
What is the mass mass equation?For a body, mass is constant.Mass can be calculated using the formula: mass = volume density.A mass's weight is a measurement of a gravitational force at work on it.The kilogram is indeed the SI mass unit.
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