Answer:
The value of g is [tex]g =76.2 m/s^2[/tex]
Explanation:
From the question we are told that
The mass of the weight is [tex]m = 1.30 kg[/tex]
The spring constant [tex]k = 1.73 g/m = 1.73 *10^{-3} \ kg/m[/tex]
The second harmonic frequency is [tex]f = 100 \ Hz[/tex]
The number of oscillation is [tex]N = 200[/tex]
The time taken is [tex]t = 315 \ s[/tex]
Generally the frequency is mathematically represented as
[tex]f = \frac{v}{\lambda}[/tex]
At second harmonic frequency the length of the string vibrating is equal to the wavelength of the wave generated
[tex]l = \lambda[/tex]
Noe from the question the vibrating string is just half of the length of the main string so
Let assume the length of the main string is [tex]L[/tex]
So [tex]l = \frac{L}{2}[/tex]
The velocity of the vibrating string is mathematically represented as
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
Where T is the tension on the string which can be mathematically represented as
[tex]T = mg[/tex]
So
[tex]v = \sqrt{\frac{mg}{k} }[/tex]
Then
[tex]f = \frac{v}{\frac{L}{2} }[/tex]
=> [tex]v = \frac{fL }{2}[/tex]
=> [tex]\sqrt{\frac{mg}{k} } = \frac{fL}{2}[/tex]
=> [tex]g = \frac{f^2 L^2 \mu}{4m}[/tex]
substituting values
[tex]g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2[/tex]
[tex]g = 3.326 m^{-1} s^{-2} L^2[/tex]
Generally the period of oscillation is mathematically represented as
[tex]T_p = 2 \pi \sqrt{\frac{L}{g} }[/tex]
=> [tex]L = \frac{T^2 g}{4 \pi ^2}[/tex]
The period can be mathematically evaluated as
[tex]T_p = \frac{t}{N}[/tex]
substituting values
[tex]T_p = \frac{315}{200}[/tex]
[tex]T_p = 1.575 \ s[/tex]
Therefore
[tex]L = \frac{1.575^2 * g }{4 \pi ^2}[/tex]
[tex]L = 0.0628 ^2 g[/tex]
so
[tex]g = 3.326 m^{-1} s^{-2} L^2[/tex]
substituting for L
[tex]g = 3.326 ((0.0628) g)^2[/tex]
=> [tex]g = \frac{1}{(3.326)* (0.0628)^2}[/tex]
[tex]g =76.2 m/s^2[/tex]
who is the first person created light bulb
Answer:
Thomas Alva EdisonExplanation:
he created the bulb first. He was an American. He was an inventor and also a businessman. Moreover he invented the phonograph, and the motion picture camera, as well as improving the telegraph and telephone.
hope this helps
brainliest appreciated
good luck! have a nice day!
each
A boy of mass 10kg
climbs up to Steps
of height
0.2m in 20 seconds calculate the
Power of the body.
So the right answer is 0.98 watt.
look at the attached picture
Hope it will help you
A team of landscapers pull an unplanted tree across the lawn. What forces are used?
Answer:
Explanation:
When an unplanted tree is pulled across the lawn then a variety of forces will be acting on the tree i.e.
1.There will be gravity force
2.Friction force to oppose the motion
3.Applied force which is pulling the tree
4. Normal force in response to the gravity force.
The solubility of solid in a liquid __________________ with the increase in temperature.
g Only something with no mass (such as light) can move at the speed of light. b. Theoretically, a particle with mass can only move faster than the speed of light if given infinite energy. c. When in a medium (such as water) light will move less than c, and observers in different inertial frames can observe that light moving at different speeds. d. Theoretically, a particle with mass can only reach the speed of light if given infinite energy. e. Choices a), c), d) are correct.
Answer:
true a and c
Explanation:
The theory of special relativity is formulated under two postulates
* that the laws of physics are the same in all inertial systems
* that the speed of light in the vacuum is constant for all systems
with these postulates the energy of a particular is
E = K + m c²
where the last term is called energy at rest
a) True. only when m = 0 the energy of the particle is scientific energy
be False. Nothing can go faster than light
c) Right. In a material medium the speed of light depends on the measurement reference frame
d) False For a particle of finite mass the energy must be greater than the energy at rest
The invisible line that passes through the North Pole and the South
Pole is called Earth's what
Answer:
The Prime Meridian
The invisible line that passes through the North Pole and the South
Pole is called Earth's axis.
What is axis of earth?The imaginary line connecting the North and South poles is known as the Earth's axis. Its orbital plane and it are at an angle of 66 (1/2) degrees.
What is north pole and south pole?The Earth rotates on a 22 1/2-degree axis rather than vertically. A compass's arrow always points north when being used. The South Pole is located at the southernmost point on Earth, whereas the North Pole is located at its northernmost point. The region near the North and South Poles is extremely cold, whereas the region around the equator is extremely warm.
Learn more about Earth here:
https://brainly.com/question/12041467
#SPJ2
URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally insulated chamber. For water L = 3.33 x 105 J/kg. The specific heat of ice is 2090 J/(kg°C) and of water 4186 J/(kg°C). How much does the ice heat up in order to bring the water down to 0°C?
A. 0.04°C
B. 0.4°C
C. 4°C
D. 10°C
E. 20°C
Answer:
Explanation:
heat lost by water will be used to increase the temperature of ice
heat gained by ice
= mass x specific heat x rise in temperature
1 x 2090 x t
heat lost by water in cooling to 0° C
= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .
= 1 x 2 x 4186
8372
heat lost = heat gained
1 x 2090 x t = 8372
t = 4°C
There will be a rise of 4 degree in the temperature of ice.
The increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
The given parameters;
mass of the ice, m₁ = 1 kgtemperature of the ice, t₁ = -20°Cmass of the water, m₂ = 1 kgtemperature of the water, t₂ = 2 °CApply the principle of conservation of energy to determine the increase in the temperature of the ice to bring the water to 0 °C.
Heat absorbed by the ice = Heat lost by water
[tex]Q_{ice} = Q_{w}\\\\mc\Delta t_{ice} = mc \Delta t_{w}\\\\1 \times 2090 \times \Delta t = 1 \times 4186 \times (2-0)\\\\2090\Delta t = 8372\\\\\Delta t = \frac{8372}{2090} \\\\\Delta t = 4 \ ^0C[/tex]
Thus, the increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
Learn more here:https://brainly.com/question/14854725
For an advanced lab project you decide to look at the red line in the Balmer series. According to the Bohr Theory, this is a single line. However, when you examine it at high resolution, you find that it is a closely-spaced doublet. From your research, you determine that this line is the 3s to 2p transition in the hydrogen spectrum. When an electron is in the 2p subshell, its orbital motion creates a magnetic field and as a result, the atom's energy is slightly different depending on whether the electron is spin-up or spin-down in this field. The difference in energy between these two states is ΔE = 2μBB, where μB is the Bohr magneton and B is the magnetic field created by the orbiting electron. The figure below shows your conclusion regarding the energy levels and your measured values for the two wavelengths in the doublet are λa = 6.544550 ✕ 10−7 m and λb = 6.544750 ✕ 10−7 m. (Let h = 6.626069 ✕ 10−34 J · s, c = 2.997925 ✕ 108 m/s, and μB = 9.274009 ✕ 10−24 J/T.) Determine the magnitude of the internal magnetic field (in T) experienced by the electron. When doing calculations, express all quantities in scientific notation, when possible keep six places beyond the decimal, and round your answer off to at least three significant figures at the end.
Answer:
1.000153 T
Explanation:
The energy change ΔE = hc(1/λb - 1/λa)
= 6.626069 ✕ 10⁻³⁴ J · s 2.997925 × 10⁸ m/s(1/6.544750 × 10⁻⁷ m - 1/6.544550 × 10⁻⁷ m)
= 19.864457907 × 10⁻²⁶(1527942.2438 - 1527988.9374) = 19.864457907 × 10⁻²⁶(-46.6936)
= 927.543052 × 10⁻²⁶
= -9.275431× 10⁻²⁴ J.
This energy change ΔE = 2μBB. So the magnetic field, B is
B = ΔE/2μB where μB = 9.274009 ✕ 10⁻²⁴ J/T
B = -9.275431× 10⁻²⁴ J/9.274009 ✕ 10⁻²⁴ J/T = -1.000153 T
The magnitude of the magnetic field B = 1.000153 T
Calculate the percentage of an iceberg submerged beneath the surface of the ocean given that the density of ice is 916.3kg/m3 and the salt water has a density of 1021.9 kg/m3
Answer:
The percentage of an iceberg submerged beneath the surface of the ocean = 89.67%
Explanation:
Let V be the total volume of the iceberg
Let x be the volume of iceberg submerged
According to Archimedes principle,
weight of the iceberg = weight of the water displaced (that is, weight of x volume of water)
Weight of the iceberg = mg= ρ(iceberg) × V × g
Weight of water displaced = ρ(fluid) × x × g
We then have
ρ(iceberg) × V × g = ρ(fluid) × x × g
(x/V) = ρ(iceberg) ÷ ρ(fluid) = 916.3 ÷ 1021.9 = 0.8967 = 89.67%
Hope this Helps!!!!
What is a neutral subatomic particle that has almost no mass and is released
from a radioactive nucleus during by fission and fusion reactions. These particles
can usually pass through matter undetected.
Answer:
Alpha particle
Explanation:
Alpha particles emitted by radioactive nuclei consist of 2 protons and 2 neutrons bound together which makes it neutral and are able to pass through ordinary matter almost undisturbed
A 385-g tile hangs from one end of a string that goes over a pulley with a moment of inertia of 0.0125 kg ⋅ m2 and a radius of 15.0 cm. A mass of 710 g hangs from the other end of the string. When the tiles are released, the larger one accelerates downward while the lighter one accelerates upward. The pulley has no friction in its axle and turns without the string slipping. What is the tension in the string on the side of the 710-g tile?
Answer:
the tension in the string is 5.59 N
Explanation:
Here ,
m_1 = 0.385 Kg
m_2 = 0.710 Kg
Using second law of motion ,
a = F_net / effective mass
a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)
a = 1.93 m/s^2
Now , let tension be T ,
then,
mg-T=ma
0.710×g - T = 0.710×1.93
T = 5.59 N
the tension in the string is 5.59 N
in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of the ball?
Answer:
R = 73.25 m
Explanation:
We have,
Initial speed of the ball is 27 m/s
It is projected at an angle of 40 degrees
The maximum range of the ball is given by :
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Plugging all the values we get :
[tex]R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m[/tex]
So, the maximum range of the ball is 73.25 m
Which best describes the direction of heat?
ellus
Three horizontal forces are pulling on a
ring, at rest. F1 is 12.0 N at a 0° angle, and
F2 is 18.0 N at a 90° direction. What is the
x-component of F3?
Answer:
Explanation:
Three forces are in equilibrium .
Let us represent forces in vector form ie in the form of i and j .
F₁ is acting along positive x axis ( at a 0° angle )
F₁ = 12 i
F₂ is acting along positive y axis ( at a 90° direction)
F₂ = 18 j
Suppose F₃ is represented by X i + Y j
Total of three forces is zero .
F₁ + F₂ + F₃ = 0
12 i + 18 j + F₃ = 0
F₃ = - 12i - 18 j
So x - component of F₃ = - 12 i
X - component of F₃ is equal to 12 N in magnitude and is acting in negative x direction ie at 180° direction .
similarly y - component is 18 N acting in negative y direction.
Answer:
x-component: -12
y-component- -18
Explanation:
2. Water at the Antarctica usually exits as ice, making it very difficult to use the water or conduct experiment requiring the water to be in liquid state. A coffee addicted physicist stationed at a research base requires about 0.8 kg of ice for his coffee on the hour.
a. How much heat is required to convert 0.8 kg of ice at —35 °C into steam at 100°C?
Answer:
662480 J
Explanation:
The heat required to convert 0.8Kg of ice at -35°c to steam at 100°c is the sum of the heat required to raise the temperature of the ice from -35°c to 0°C, the latent heat of fusion of ice and the heat required to raise the temperature of the ice from 0°c to 100°c.
Latent heat of fusion for ice= 3.36× 10^5 J Kg-1
Specific heat capacity of ice= 2060 J kg−1K−1
Specific heat capacity of water= 4200 JKg-1K-1
Heat required to raise the temperature of the ice to fusion point
H= 0.8 × 2060 × [0-(-35)]
H= 57680 J
Latent heat of fusion of ice;
H= mL
H= 0.8 ×3.36× 10^5
H= 2.688×10^5 J
Heat required to raise the temperature of the water to 100°C
Since mass is conserved, the mass of ice that has melted has been turned into an equivalent mass of water.
Therefore mass of water formed= 0.8Kg
H= 0.8× 4200 × 100
H= 336000J
Therefore total heat required;
H= 57680 + 2.688×10^5 + 336000
H= 662480 J
Answer:
2468,080j
Explanation:
Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wavelengths Radiation through the same region
Answer:
Unequal Wavelengths
Explanation:
Got it right on the exam
Unequal wavelengths limit interference between waves because the waves will have different frequencies and will not be able to form a stable interference pattern. When waves of different wavelengths interact, they will interfere constructively and destructively at different points, creating an unpredictable pattern.
Answer:
Unequal wavelengths
Explanation:
Got it correct on the quiz.
Why do astronauts' weights differ in space?
There is a less gravitational force in space.
Their mass changes in space.
Space is colder than Earth.
There is less oxygen in space.
Answer:
There is less gravitational force in space.
Explanation:
Gravity doesn't exist as it does on Earth. Earth's gravity is as 6 times stronger as it is on the moon.
name 3 things in the solar system
Answer:
mercury ,venus, earth
Answer
sunplanets moonscometshope this helps
brainliest appreciated
good luck! have a nice day!
through which material does the light travel the fastest?
Give reasons for the following:
a. Knives and swords are supposed to have extremely thin blades.
b. Lorries and trucks carrying heavy loads have 8 tires instead of four, and the
tires are broader.
c. Camels can walk easily in desserts but humans cannot.
d. In a flight, the human ear pain during take-off and landing.
e. A suction cup does not stick on a rough surface.
Answer:
a. lower surface area, less resistence
b. more surface area, the load is split so no single tire overstrained
c. more surface area, more resistance against the sand. human steps sink down in the sand.
d. rapid change in air pressure on eardrums lead to somewhat-painful tension
e. air would always find its way in so no pressure difference can be achieved
(would indeed appreciate the brainliest if you appreciate the work)
A train is 240 meters long and travels 20 m/s. How long does
it take to cross a 360-meter long bridge?
S
Answer:
=18 sec
Explanation:
240m=20m/s, find 360m
360×20÷240=30m/s
time=distance÷speed
240÷20=12sec
if 240=12sec,find 360
360×12÷240
=18 sec
A block is given an initial speed of 3m/s up a 25° incline coefficient of friction= 0.12
A) how far up the plane will it go?
B) how much time elapses before it returns to it's starting point?.
Answer:
a) y = 0.459 m , b) t = 13 s
Explanation:
a) For this exercise we use Newton's second law to find the acceleration of the block
we fix a reference system with the x axis parallel to the plane and the y axis perpendicular to it
X axis
-Wₓ - fr = m a (1)
Axis y
N - [tex]W_{y}[/tex] = 0
N = W_{y}
the friction force has the formula
fr = μ N
let's use trigonometry to find the components of the weight
sin 25 = Wₓ / W
Wₓ = W sin 25
cos 25 = W_{y} / W
W_{y} = W cos 25
we substitute in 1
- W sin 25 - μ W cos 25 = m a
- g (sin 25 - μ cos 25) = a
let's calculate
a = - 9.8 (sin 25 - 0.12 cos 25)
a - 0.25 m / s
this is the acceleration on the plane, so we can use the kinematic relations in one dimension
the highest point where the block rises the speed is zero (va = 0)
v² = v₀² - 2 a y
y = v₀² / 2g
y = 3 2 / (2 9.8)
y = 0.459 m
this is the distance the cantes block travels to stop
b) the time of the entire journey is
y = v₀ t - ½ a t²
the point where the body recesses is y = 0
0 = (vo - ½ a t) t
whose solutions are
t = 0
0 = vo - ½ a t
t = 2vo / a
t = 2 3 / 0.459
t = 13 s
how does the force of gravity affects an objects acceleration
Answer:
When objects fall to the ground, gravity causes them to accelerate.
Explanation:
Gravity causes an object to fall toward the ground at a faster and faster velocity the longer the object falls.
a student stands several meters in front of a smooth reflecting wall, holding a board on which a wire is fixed at each end. the wire, vibrating in its third harmonic, is 75.0cm long, has a mass of 2.25g, and is under a tension of 400 N. a second student, moving towards the wall, hears 8.30 beats per second. what is the speed of the student approaching the wall? (solve without calculus)
Answer:
Explanation:
From the question we are told that
The length of the wire is [tex]L = 75.0cm = \frac{75}{100} = 0.75 \ m[/tex]
The mass of the wire is [tex]m = 2.25 \ g = \frac{2.25}{1000} = 0.00225 \ kg[/tex]
The tension is [tex]T = 400 \ N[/tex]
The frequency of the beat heard by the second student is
[tex]f_b = 8.30\ beat/second[/tex]
The speed of the wave generated by the vibration of the wire is mathematically represented as
[tex]v = \sqrt{\frac{TL}{m}}[/tex]
substituting values
[tex]v = \sqrt{\frac{400 *0.75}{0.00225}}[/tex]
[tex]v = 365.15 m/s[/tex]
The wire is vibrating in its third harmonics so the wavelength is
[tex]\lambda = \frac{2L}{3}[/tex]
substituting values
[tex]\lambda = \frac{2*0.75}{3}[/tex]
[tex]\lambda = 0.5 \ m[/tex]
The frequency of this vibration is mathematically represented as
[tex]f = \frac{v}{\lambda }[/tex]
substituting values
[tex]f = \frac{365.15}{0.5 }[/tex]
[tex]f = 730.3 Hz[/tex]
The speed of the second student (Observer) is mathematically represented as
[tex]v_o = [\frac{f_b}{2f} ] * v[/tex]
substituting values
[tex]v_o = [\frac{8.30}{2* 730.3} ] * 365.15[/tex]
[tex]v_o = 2.08 \ m/s[/tex]
The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? 20W 200W 400W 800W 8000W 16000W 32000W\
Answer:
400 W
Explanation:
Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.
This means that power input = 400 W = power output
What is clear cutting?
Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much torque must Ned produce to turn the bolt?
Answer:
[tex]T = 6.75\,N\cdot m[/tex]
Explanation:
Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:
[tex]T = F\cdot r \cdot \sin \theta[/tex]
[tex]T = F_{\bot} \cdot r[/tex]
Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:
[tex]T = (15\,N)\cdot (0.45\,m)[/tex]
[tex]T = 6.75\,N\cdot m[/tex]
A very tall building has a height H0 on a cool spring day when the temperature is T0. You decide to use the building as a sort of giant thermometer on a hot summer day by carefully measuring its height. Suppose you do this and discover that the building is a length h taller than it was on the cool spring day where h is much much less than H0. Assume the entire frame of the building is made of steel, which has a coefficient of linear expansion αsteel.
Required:
What is the temperature, assuming that the building is in thermal equilibrium with the air and that its entire frame is made of steel?
Answer:
The temperature is [tex]T = \frac{h}{H_O \alpha_{steel} } + T_O[/tex]
Explanation:
From the question we are told that
The height on a cool spring day is [tex]H_O[/tex]
The temperature on a cool spring day is [tex]T_O[/tex]
The difference in height between a cool spring day and a summer day is h
The coefficient of static friction is [tex]\alpha _{steel}[/tex]
The mathematical relation for the linear expansion of the steel buiding is represented as
[tex]h = H_o \alpha_{steel} [T-T_O][/tex]
Where T is the temperature of the steel during summer
Now making T the subject we have
[tex]T = \frac{h}{H_O \alpha_{steel} } + T_O[/tex]
In one experiment, you measured the potential difference across a resistor as a capacitor discharged through it. You then plotted the natural logarithm of the voltage vs time (in seconds), and from the equation of the best fit line you measured the time constant of the RC circuit. If the equation of that line is ln open vertical bar V close vertical bar equals negative 0.027 t plus 2.5 , what is the time constant of the circuit?
Answer:
Explanation:
For discharge of capacitor in RC circuit , the relation is as follows
[tex]V=V_0e^\frac{-t}{\lambda}[/tex]
V is voltage across the capacitor , V₀ is maximum voltage across capacitor , λ is time constant and t is the time after which the voltage is recorded. During discharge this will also be voltage across resistance .
Taking log on both sides
lnV = lnV₀ - [tex]\frac{t}{\lambda}[/tex]
Given equation
[lnV] = - .027 t + 2.5
Comparing these equation
[tex]\frac{1}{\lambda} = .027[/tex]
λ = 37 s
time constant = 37 sec.
A bullet of mass m and speed v passes completely through a pendulum bob of mass M. The bullet emerges with a speed of v/2. The pendulum bob is suspended by a stiff rod of length script l and negligible mass. What is the minimum value of v such that the pendulum bob will barely swing through a complete vertical circle? (Use any variable or symbol stated above along with the following as necessary: g. Be sure to use script l from physPad.)
v =
Answer:
[tex]v = \sqrt{16\cdot g \cdot L}[/tex]
Explanation:
The physical phenomenon is described by the Principles of Momentum Conservation and Energy Conservation:
Momentum
[tex]m \cdot v = M\cdot \frac{v}{2} + m \cdot v'[/tex]
Energy
[tex]\frac{1}{2}\cdot m \cdot v^{2} = \frac{1}{8}\cdot M \cdot v^{2} + \frac{1}{2}\cdot m \cdot v'^{2}[/tex]
[tex]\frac{1}{8}\cdot M\cdot v^{2} = 2\cdot M\cdot g \cdot L[/tex]
The minimum speed of the pendulum bob so that it could barely swing through a complete vertical cycle is:
[tex]\frac{1}{8}\cdot v^{2} = 2\cdot g\cdot L[/tex]
[tex]v^{2} = 16\cdot g\cdot L[/tex]
[tex]v = \sqrt{16\cdot g \cdot L}[/tex]