Arnez Company’s annual accounting period ends on December 31. The following information concerns the adjusting entries to be recorded as of that date. The Office Supplies account started the year with a $3,850 balance. During the year, the company purchased supplies for $15,901, which was added to the Office Supplies account. The inventory of supplies available at December 31 totaled $3,388. The Prepaid Insurance account had a $27,744 debit balance at December 31 before adjusting for the costs of any expired coverage for the year. An analysis of prepaid insurance shows that $20,004 of unexpired insurance coverage remains at year-end. The company has 15 employees, who earn a total of $1,800 in salaries each working day. They are paid each Monday for their work in the five-day workweek ending on the previous Friday. Assume that December 31 is a Tuesday, and all 15 employees worked the first two days of that week. Because New Year’s Day is a paid holiday, they will be paid salaries for five full days on Monday, January 6 of next year. The company purchased a building at the beginning of this year. It cost $725,000 and is expected to have a $45,000 salvage value at the end of its predicted 25-year life. Annual depreciation is $27,200. Since the company is not large enough to occupy the entire building it owns, it rented space to a tenant at $3,400 per month, starting on November 1. The rent was paid on time on November 1, and the amount received was credited to Rent Revenue. However, the tenant has not paid the December rent. The company has worked out an agreement with the tenant, who has promised to pay both December and January rent in full on January 31. On November 1, the company rented space to another tenant for $3,080 per month. The tenant paid five months' rent in advance on that date. The payment was recorded with a credit to the Unearned Revenue account. Assume no other adjusting entries are made during the year. Required: 1. Use the information to prepare adjusting entries as of December 31. 2. Prepare journal entries to record the first subsequent cash transaction in January of the next year for parts c and e.

The catcher must throw the ball in a distance of 127.2 feet to force a runner out at second base.

From the figure we understands that it is a right angled triangle.

The hypotenuse of a right triangle is formed by the line from home plate to second base. The triangle's two sides are each 90 feet.

We can calculate the length of the hypotenuse using the Pythagorean theorem:

90² + 90² = c²

= 8100 + 8100 = c²

= 16200 = c²

c = √16200

c = 127.2

c = 127 feet

As a result, the distance that the catcher must throw the ball to get a runner out at second base is 127 feet.

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The enclosed area between the 2 equations, x = 7y² and x = 4 + 6y² is 32/3 sq units

Here equation 1 is x = 7y²

and equation 2 is x = 4 + 6y²

To find the area enclosed between the region, we need to first find the points where these two lines meet.

This implies,

eq 1 = eq 2

or, 7y² = 4 + 6y²

or, y² = 4

or, y = ±2

Now if we see the graph with respect to y, the area between the y-axis and eq 2 is greater than that of the y-axis and equation 1.

Now area is enclosed between 2 lines with respect to x. Hence it will be

= ∫eq 2 dy - ∫eq 1 dy with limts of 2 and -2

= ∫4 + 6y²dy - ∫7y²dy with limits 2 and -2

= [4y + 2y³ - 7/3 y³] with limits 2 and -2

= 8 + 16 - 56/3 + 8 + 16 - 56/3 sq. units

= 48  - 112/3

= 32/3 sq units

Hence the enclosed area is 32/3 sq units

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The final statement is: A rigid creates figure that are congruent.

A rigid motion is when an object is moved from one location to another and the size and shape of the object have not changed. Two figures are congruent if and only if there exists a rigid motion that sets up a correspondence of one figure as the image of the other.

Given here: A rigid motion

Rigid Motion and Congruence-Two figures are congruent if and only if there exists one, or more, rigid motions which will map one figure onto the other. (thus maintaining the conditions for the figures to be congruent)

Hence, The right option is A.Congruent.

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Yes , watching TV helps you live longer  by using correlation coefficient.

How to interpret a correlation coefficient?

The statistical measure of how well changes in the value of one variable predict changes in the value of another is called a correlation coefficient. The value rises or falls together when the variables are positively linked.

The r represents the correlation coefficient which has a value 0.89 for the given case.

we can say that there is a positive association between the life expectancy of citizen and the average number of TVs in households.

the r value is close to +1 which means that the association is close to linear relation .

 so we put it like

               R² = 0.89² = 0.7921

now  0.7921 signifies that almost 79% variation in life.

So we can say that  watching TV helps you live longer.

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y=2x²+4x+4 and y=3x²+6x+9 are two instances for the provided standard form, y=ax²+bx+c.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A condition on a variable (or variables) such that two expressions in the variable (variables) have equal value is referred to as an equation. • The solution or root of the equation is the value of the variable for which the equation is fulfilled.

Here,

given standard form,

y=ax²+bx+c

examples of this,

y=2x²+4x+4

y=3x²+6x+9

The 2 examples for given standard form, y=ax²+bx+c is y=2x²+4x+4 and y=3x²+6x+9.

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The number of cups of milk that she will need would be = 20 cups.

A ratio is defined as the expression that shows the relationship between two numbers of the same unit.

The ratio used by Aunt Janelle to make hot chocolate is as follows;

The quantity of milk to cocoa = 5 cups : 2 cups respectively.

Therefore the cups of milk to 8 cups would be = X

That is, 5 cup of milk = 2 cups of cocoa

X cup of milk = 8 cups of cocoa

make X the subject of formula;

X = 5 × 8/2

X= 40/2

X = 20

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3: 4=6: 8 We discovered an analogous ratio by multiplying both terms by 2, as the ratio was already in lowest terms.

The proportion between two or more items in terms of number, amount, or size. When the second number in the ordered pair, b, is not equal to 0, the ratio is expressed as a/b. An equation in which two ratios are made equal is known as a percentage. As an illustration, you could express the ratio as 1: 3 if there is 1 guy and 3 girls (for every one boy there are 3 girls) 40% are girls, and 14% are boys.

Comparing two numbers by dividing them is how ratios work. Your formula would be A/B if you were contrasting one data point (A) with another data point (B). By doing so, you are multiplying information A by information B.

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Answer:

-----------------------------

Slope-intercept form:

Use two points on the line:

The first point is the y-intercept:

Find the slope:

The line is:

Domain of the relation will be {-3,-4,1,0} and

Range of the relation will be {1,-4,-3,8}.

What is range and domain of a function?

Domain

The set of all possible values which qualify as inputs to a function is known as the domain of the function, or it can also be defined as the entire set of values possible for independent variables. The domain can be found in – the denominator of the fraction is not equal to zero and the digit under the square root bracket is positive. (In the case of a function with fraction values).

Range

The set of all the outputs of a function is known as the range of the function or after substituting the domain, the entire set of all values possible as outcomes of the dependent variable.

Now,

As inputs in the given relation are  {-3,-4,1,0}

and outputs are {1,-4,-3,8}.

Hence,

          Domain of the relation will be {-3,-4,1,0} and

          Range of the relation will be {1,-4,-3,8}

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Answer:

$81.19

Step-by-step explanation:

8.25% x 75 = 8.19

75 + 8.19 = $81.19

Answer:

5, 9, 13, 17, 21, 25, 29, 33, 37, 41

Step-by-step explanation:

every time you go up one number, there is a 4 matchstick difference

the ninth figure therefore would be using 37 matchstick squares (:

hope this helped have a good day!

The value of percent in 1 decimal point is, 52.7%.

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Given that;

There 19 out of 36 in a class are girls.

Hence, The percentage of girls is,

⇒ 19 / 36 × 100 %

⇒ 1900/36 %

⇒ 52.7%

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Using simultaneous equations, the price of one adult ticket is $4 and one student ticket is $7.

Simultaneous equations are two or more equations solved concurrently.

Sales of Tickets:

                                            Adult     Student   Sales Revenue

First day of ticket sales         1               8               $60

Second day of ticket sales   5              4               $48

Let the price per adult ticket = a and students ticket = s

Equation 1: a + 8s = 60

Equation 2: 5a + 4s = 48

Multiply equation 1 by 5:

Equation 3: 5a + 40s = 300

Subtract equation 2 from equation 3:

5a + 40s = 300

-

5a + 4s = 48

36s = 252

s = 7

= $7

In equation 1, substitute s = 7:

a + 8s = 60

a + 8(7) = 60

a + 56 = 60

a = 4

= $4

Thus, the price of one adult ticket is $4 while the price of one student ticket at Kali's school is $7.

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In this question, we use the theory of LCM (Least Common Multiple) for finding the numbers which are divisible by 2,5 and 10. As we know, in arithmetic, the LCM is the smallest or least positive integer that is divisible by both a and b. So, in this question we need to calculate the LCM of 2,5

step 1

Solution

LCM of 2,5,10 is 10

So, if a number is divisible by 10 then it will be divisible by 2,5,10

Like 60,100,120,450,600

step-by-step answer:

For example, let us take two positive integers 4 and 6. Multiples of 4 are: 4,8,12,16,20,24… Multiples of 6 are: 6,12,18,24…. The common multiples for 4 and 6 are 12,24,36,48…and so on.

2, 5 and 10 (LCM by Division Method).

LCM of 2, 5 and 10 = 2X5

                                 = 10

we get LCM of 2, 5 and 10 is 10.

So, if a number is divisible by 10

Then it will be divisible by 2,5,10.

Therefore, any number which is multiple of 10 or which is divisible by 10. We say it will be divisible by 2,5,10.

Like- 10, 20, 30, 40, 50, 60, 70, 80 etc.

Thus, 10, 20, 30, 40, 50 are 5 numbers which are divisible by 2,5 and 10.

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The inequality for the expression is x≥83

inequality, In mathematics is a statement of an order relationship. The signs in inequality includes: greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

greater than( >)

less than (<)

less than or equal to ≤

greater than or equal to ≥

Kami needs to score at least 83 on her quiz, this means that kami need to score a mark greater than or equal to 83 in her quiz.

If we represent the score of kami by x, this means the expression can be represented as:

x ≥ 83

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Answer:

The answer should be 7 [tex]cm^{2}[/tex]

Step-by-step explanation:

If I make a 4 by 4 rectangle around the figure, I will have a 4 by 4 square.

The area will be 16.  Now subtract out the triangle on the bottom left and top right.

The triangles have a length and a height of 3.

a = 1/2 (lxh)

1/2(3x3) + 1/2(3x3) = 9

Subtract 9 from 16

16-9 = 7

Answer:

x+9

Step-by-step explanation:

for example x is 18 , add 9 to it will become 18+9=27

general equation of the tangent line, expressed through the x-coordinate of the point, at which it touches the function.

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Answer:

[tex]\textrm {D. The derivative is }\dfrac{x^{3}\cdot(\boldsymbol{9x^{8}})-x^{9}\cdot(\boldsymbol{3x^{2}})}{x^{6}}[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \dfrac{u(x)}{v(x)}[/tex]

the derivative of f(x) wrt x is

[tex]f'(x) = \dfrac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2}[/tex]

[tex]u(x) =x^9 \;so \; u'(x) = 9x^8[/tex]

[tex]v(x) = x^3 , v'(x) = 3x^2\\\\\[v(x)\]^2 = [x^3]^2 = x^6[/tex]

Putting all these together we get

[tex]f'(x)=y'=\dfrac{x^{3}\cdot(\boldsymbol{9x^{8}})-x^{9}\cdot(\boldsymbol{3x^{2}})}{x^{6}}[/tex]

Missing entries are in bold

The function that increases at a faster rate on 0 to infinity is g(x) = 2ˣ

An average rate measure of how much the function changed per unit, on average, over that interval. It is derived from the slope of the straight line connecting the interval's endpoints on the function's graph.

The functions are given as:

f(x) = x² --- quadratic

g(x) = 2ˣ --- exponential

The exponential function has the same base as the power of the quadratic function.

This means that the exponential function would increase faster from the point where f(x) = g(x)

This is illustrated using the following table

x      0   1   2   3   4    5

f(x)  0    1   4   9   16   25

g(x)  1   2    4   8   16   3

Hence, the function that increases at a faster rate on 0 to infinity is g(x) = 2ˣ

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The required probability is 0.8

Probability is a measure of the likelihood of an event occurring. The probability formula is defined as the possibility of an event happening is equal to the ratio of the number of favorable outcomes and the total number of outcomes. Probability of event to happen P(E) = Number of favorable outcomes/Total Number of outcomes.

Given here: Twenty percent of a town’s voters favor letting a major discount store move into their neighborhood, 63% are against it, and 17% are indifferent.

Thus total percentage of voters that are either against or be indifferent is equal to P( against or indifferent)=80%

                                                       =0.8

The probability is not equal to one because there is also percentage of voters that are in favour which accounts for 20%

Hence, The required probability is 0.8

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Madison should multiply the price on the tag by (1-0.15) = 0.85 to find the price she would have to pay

Discount Formulas can be used to solve Discount problems in mathematics. It aids in boosting sales. Where M.P. (Marked Price) denotes the item's full retail cost without any discounts. The selling price, or S.P., is what consumers pay for the item. A percentage of the marked price is the discount.

The loyalty card gives a 15% discount so Madison should multiply the price on the tag by (1-0.15) = 0.85 to find the price she would have to pay, before tax, in one step.

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The polygons with the specified vertices and their graphs are as follows;

2. The polygon is a rectangle

Please find attached the graph of polygon 2, a rectangle, created with MS Excel

3. The polygon is an irregular octagon

Please find attached the graph of the polygon, an octagon, created with MS Excel

A polygon is a closed plane figure with three or more linear sides and interior angles.

2. The vertices of the polygon are; (-3, 8), (5, 8), (-3, -5), (5, -5)

The number of vertex points indicates that the polygon is a quadrilateral.

The vertices indicates that the vertical lines x = -5, and x = 8, are lines that form the sides of the quadrilateral

Similarly, the horizontal lines y = -3, and y = 5 are boundaries of the quadrilateral

The distance between the vertical lines = 8 - (-5) = 13

The distance between the horizontal lines = 5 - (-3) = 8

The quadrilateral is therefore a rectangle

The graph of the rectangle, created with MS Excel is attached

3. The vertices of the polygon are; (4, 3), (3, 3), (2, 2), (2, 1), (3, 0), (4, 0), (5, 1), and (5, 2)

The number of vertex points are 8 indicating that the polygon is an octagon.

The length of the sides are;

(4 - 3) = 1

√((3 - 2)² + (3 - 2)²) = √2

(2 - 1) = 1

√((3 - 2)² + (0  - 1)²) = √2

4 - 3 = 1

√((5 - 4)² + (1 - 0)²) = √2

2 - 1 = 1

The lengths of the sides of the octagon are alternating therefore, the figure is an irregular octagon.

Please find attached the graph of the octagon, created with MS Excel

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The Taylor series up to the degree 4 terms is:

e^8 + (x - 8)e^8 + (x - 8)^2/2! e^8 + (x - 8)^3/3! e^8 + (x - 8)^4/4! e^8

The Taylor series of a function f(x) at point a is an infinite sum of terms that approximates the value of the function near point a. The general form of the Taylor series of f(x) at a is:

f(x) = f(a) + (x - a)f'(a) + (x - a)^2/2! f''(a) + (x - a)^3/3! f'''(a) + ...

Where,

In the case of e^x, the function is infinitely differentiable, so all its derivatives are equal to itself. Hence the Taylor series at a=8 is:

e^8 + (x-8)e^8 + (x-8)^2/2! e^8 + (x-8)^3/3! e^8 + (x-8)^4/4! e^8 + ....

by taking the degree 4 terms we can find the Taylor series of e^x at a = 8 up to the degree 4 terms, which is

e^8 + (x-8)e^8 + (x-8)^2/2! e^8 + (x-8)^3/3! e^8 + (x-8)^4/4! e^8

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Vertex (3, -4) with x-intercepts (1, 0), (5, 0), and (0, 5) and an axis of symmetry of 3. As a result, choice B is the right response.

The characteristics of the quadratic function graphed in the figure must be identified.

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The expression for each values of {a} and {c} are calculated below..

Given are the expressions as -

3a + 6 + 5a - 2

5c - 4c + c - 3

For the expression -

3a + 6 + 5a - 2

8a + 4

For {a} = 2, we can write -

8 x 2 + 4

20

for {a} = 5, we can write -

8 x 5 + 4

44

for {a} = -3, we can write -

8 x -3 + 4

-20

For the expression -

5c - 4c + c - 3c

- c

For {a} = 2, we can write -

- 2

for {a} = 5, we can write -

- 5

for {a} = -3, we can write -

3

Therefore, the expression for each values of {a} and {c} are calculated above.

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The solutions to the exponential equation [tex]12^{x^2 + 5x - 4} = 12^{2x + 6}[/tex] are given as follows:

x = 2 and x = -5.

The exponential equation for this problem is defined as follows:

[tex]12^{x^2 + 5x - 4} = 12^{2x + 6}[/tex]

The n^x function is an injective function, which means that if they are equal, and have the same base, than their exponents are equal.

Thus the equation can be simplified as follows:

x² + 5x - 4 = 2x + 6.

x² + 3x - 10 = 0.

The coefficients of the quadratic function are given as follows:

a = 1, b = 3, c = -10.

Hence the discriminant is given as follows:

D = 3² - 4(1)(-10)

D = 49.

The first solution is given as follows:

x = (-3 + 7)/2 = 2.

The second solution is given as follows:

x = (-3 - 7)/2 = -5.

Meaning that the third option is the correct option in the context of this problem.

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Answer:

c

Step-by-step explanation:

Answer:

im sorry but i need the points

If pentagon ABCDE is rotated 180° around the origin to create pentagon A′B′C′D′E′, the ordered pair of point A′ is equal to (2, -4).

In Geometry, the rotation of a point 180° about the origin in a clockwise or counterclockwise direction would produce a point that has these coordinates (-x, -y).

By applying a rotation of 180° to the ordered pair of point A in pentagon ABCDE, the coordinates of its image (pentagon A′B′C′D′E′) can be calculated as follows:

(x, y)                                                   →               (-x, -y)

Ordered pair of points A = (-2, 4)    →     Ordered pair of points A' = (-(-2), -(4)) = (2, -4).

Therefore, the coordinates of points A' is equal to (2, -4).

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Answer:

The answer is  A) (2, −4)

Step-by-step explanation:

The rotation rule for 180° is (x, y) → (−x, −y) so wll use this rule to find the ordered pair of A′.

A = (-2,4)

(x, y) → (−x, −y)  → (−(-2), −(4)) Change the sign of both coordinates (2, −4)

so, the answer is (2, −4)