Answer:
[tex]3.029\ \text{m/s}[/tex]
Explanation:
m = Mass of pendulum = 1 kg
L = Length of pendulum = 2 m
g = Acceleration due to gravity = [tex]9.8\ \text{m/s}^2[/tex]
h = Height of the pendulum = 0.468 m
[tex]\theta[/tex] = Angle of deflection = [tex]-40^{\circ}[/tex]
[tex]\cos\theta=\dfrac{L-h}{L}\\\Rightarrow h=L-L\cos\theta\\\Rightarrow h=L(1-\cos\theta)\\\Rightarrow h=2(1-\cos(-40))=0.468\ \text{m}[/tex]
The energy balance of the pendulum is as follows
[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.8\times 0.468}\\\Rightarrow v=3.029\ \text{m/s}[/tex]
The maximum velocity of this pendulum is [tex]3.029\ \text{m/s}[/tex].
Answer:
Max velocity = 3.03 m/s
Explanation:
Mgh = ½ mv2
(1 kg)(9.8 m/s2)(0.468 m) = ½ (1 kg) v2
2 x 4.5864 = ½ v2 x 2
√V2 = √9.1728
V = 3.03 m/s
I hope this helps!
Helppp Convert 240 seconds into minutes.
Answer:
240/60 .minute
plz make me brainliest
Which chemical equation models the law of conservation of mass?
A. 3KOH + H3PO4 - K3PO4 + 3H20
B. 2KOH + H3PO4 - K3PO4 + 2H20
C. 3KOH + 2H3PO4 - 2K3PO4 + 3H20
D. KOH + H3PO4 - K3PO4.
The Law of conservation of mass states the creation and destruction of mass to be impossible. The reaction between 3 moles of Potassium hydroxide and Phosphoric acid is conserved.
What is conservational mass?The law of mass of conservation states that the mass of the reactants and the products of the reaction cannot be added or removed.
In the first reaction, the mass of the atoms in the reaction is balanced, while in the second reaction the mass of potassium and hydrogen is not balanced.
In the third and fourth reactions, the mass of the elements is not balanced and not conserved hence not following the law.
Therefore, option A. [tex]\rm 3KOH + H_{3}PO_{4} \rightarrow K_{3}PO_{4} + 3H_{2}O[/tex] follows the law of conservation of mass.
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Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon monoxide and hydrogen: (g)(g)(g)(g) In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide: (g)(g)(g)(g) Write the net chemical equation for the production of hydrogen from propane and water. Be sure your equation is balanced.
Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Find odd one out.
H2SO4 , HCL, NaOH, HNO3
Answer:NaOH
Explanation:all are acids except NaOH
Answer:
it is NaOH
Explanation:
Because NaOH is base, while the others are acid
A hypothetical AX type of ceramic material is known to have a density of 3.15 g/cm3 and a unit cell of cubic symmetry with a cell edge length of 0.41 nm. The atomic weights of the A and X elements are 90.5 and 37.3 g/mol, respectively. On the basis of this information, which one of the following crystal structures is possible for this material?
a. Sodium chloride
b. Cesium chloride
c. Zinc blende
Answer:
b.
Explanation:
From the given information:
[tex]p = \dfrac{zM}{N_oa^3}[/tex]
where;
a = 0.41 nm = [tex]4.1 \times 10^{-8} \ cm[/tex]
M = 90.5 + 37.3 = 127.8 g/mol
[tex]N_o = 6.023 \times 10 ^{23}[/tex]
p = 3.15 g/cm³
∴
[tex]3.15 = \dfrac{z \times 127.8}{(6.02 \times 10^{23}) \times (4.1 \times 10^{-8} )^3}[/tex]
Z = 1
Thus, the ceramic material has a simple cubic crystal system and the crystal structure is possible to be Cesium chloride.
5. Calcium carbide (CaC2) reacts with water, producing acetylene (C2H2): CaC2 + 2H2O -> Ca(OH)2 + C2H2
Production of 13g of C2H2 requires __________ g of H2O. a. 4.5 b. 9.0
c. 18 d. 4.8 x 102 e. 4.8 x 10-2
Answer: c
Explanation:
18
Answer:
17.99 g H2O
Explanation:
13 g C2H2(1 mol C2H2/26.04 g C2H2)(2 mol H2O/1 mol C2H2)(18.02 g H2O/1 mol H2O) = 17.99 g H2O used up
When a liquid is at its boiling point, the vapor pressure of the liquid
is less than the external pressure on the liquid.
is equal to the external pressure on the liquid.
is greater than the external pressure on the liquid.
can be either less or greater than the external pressure on the liquid.
Answer:
=external pressure on liquid
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
Answer:
The pH of the buffer is 3.90
Explanation:
The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:
pH = pKa + log [A-] / [HA]
Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.
To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:
CH3COO- + HCl → CH3COOH + Cl-
The moles of CH3COO- are its initial moles - the moles of HCl added
And moles of CH3COOH are its initial moles + moles HCl added
Moles CH3COO-:
Initial moles = 0.100L * (0.010mol / L) = 0.00100moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.000500 moles
Moles CH3COOH:
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.003500 moles
pH is:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
The pH of the buffer is 3.90
The pH of the buffer after addition of 10.0 mL of 50.0mM HCl is 3.90
What is the Henderson-Hasselbach equation?The Henderson-Hasselbach equation is given as:
pH = pKa + log [A-] / [HA]where
pKa of acetic acid (4.75), [A-] is moles of the conjugate base[HA] the moles of thw weak acid.How to determine the moles of CH3COO- and CH3COOHThe formula for calculating number of moles is:
Moles = concentration × volumeThe equation of the reaction is given below:
CH3COO- + HCl → CH3COOH + Cl-
moles of CH3COO- = initial moles - moles of HCl added
moles of CH3COOH = initial moles + moles HCl added
Moles CH3COO-
Molarity = 0.010 M
volume = 100 mL = 0.100 L
Initial moles = 0.100 L * 0.010 M = 0.001 moles
Moles HCl = 0.010L * 0.050 M= 0.0005 moles
Moles CH3COO- = 0.001 - 0.0005 moles
Moles of CH3COO- = 0.000500 moles
Moles CH3COOH:
Molarity = 0.040 M
volume = 100 mL = 0.100 L
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.004 - 0.0005 moles
Moles CH3COO- = 0.003500 moles
Substituting the calculated values:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
Therefore, the pH of the buffer after addition of the 10.0 mL 50.0mmHg HCL is 3.90
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What is the percent oxygen in Rb2Cr2O7
Answer:
28.9452
Explanation:
Answer:
28.9452%
Explanation:
Rb-44.1781
Cr-26.8767
O-28.9452
If one DNA strand reads CCGTAATGCAT, what will be the sequence of the complementary
strand?
Si una hebra de ADN lee CCGTAATGCAT, ¿cuál será la secuencia de la hebra
complementaria?
Write your answer here:
Escriba su respuesta aquí:
a) CCGTAATGCAT
b) GGCATTACGTA
c) CCGATTAGCTA
d) GGCTAATCGAT
If one DNA strand reads CCGTAATGCAT, the sequence of the complementary strand will be - b) GGCATTACGTA
Complementary base pairingThe nucleic acid sequence of bases can form a double-stranded structure by matching base pairs.Adenine matches with thymine (uracil in RNA) and vice versaGuanine matches with cytosine and vice versaFor example, the complementary sequence to C-A-T-G (where each letter stands for one of the bases in DNA) is G-T-A-C.So, DNA strand - C-C-G-T-A-A-T-G-C-A-T
Complementary DNA strand - G-G-C-A-T-T-A-C-G-T-A
Thus, If one DNA strand reads CCGTAATGCAT, the sequence of the complementary strand will be - b) GGCATTACGTA
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The bond enthalpy of the Br–Cl bond is equal to ΔH°rxn for the following reaction. BrCl(g) → Br(g) + Cl(g) Using the following data, what is the bond enthalpy of the Br–Cl bond?
a. Br2(l) → Br2(g) ΔH°rxn = 30.91 kJ/mol
b. Br2(g) → 2Br(g) ΔH°rxn = 192.9 kJ/mol
c. Cl2(g) → 2Cl(g) ΔH°rxn = 243.4 kJ/mol
d. Br2(l) + Cl2(g) → 2BrCl(g) ΔH°rxn = 29.2 kJ/mol
Answer:
a. Br2 (l) → Br2(g) ΔH°rxn = 30.91 kJ/mol
Explanation:
Bond enthalpy is the energy which is required to break 1 mol of of bonds in gaseous covalent molecules. Bond breaking process can be endothermic or exothermic depending on the molecules association. The process needs to be performed in chemical laboratory under standard conditions.
For each of the following substituents, indicate whether it withdraws electrons inductively, donates electrons by hyperconjugation, withdraws electrons by resonance, or donates electrons by resonance. (Effects should be compared with that of a hydrogen; remember that many substituents can be characterized in more than one way).
A. Br
1. Withdraws electrons inductively.
2. Donates electrons by hyperconjugation.
3. Withdraws electrons by resonance.
4. Donates electrons by resonance.
B. CH2CH3
1. Withdraws electrons inductively.
2. Donates electrons by hyperconjugation.
3. Withdraws electrons by resonance.
4. Donates electrons by resonance.
C. NHCH31. Withdraws electrons inductively.2. Donates electrons by hyperconjugation.3. Withdraws electrons by resonance.4. Donates electrons by resonance.D. OCH31. Withdraws electrons inductively.2. Donates electrons by hyperconjugation.3. Withdraws electrons by resonance.4. Donates electrons by resonance.E. +N(CH3)31. Withdraws electrons inductively.2. Donates electrons by hyperconjugation.3. Withdraws electrons by resonance.4. Donates electrons by resonance.
Answer:
Br- Withdraws electrons inductively
Donates electrons by resonance
CH2CH3 - Donates electrons by hyperconjugation
NHCH3- Withdraws electrons inductively
Donates electrons by resonance
OCH3 - Withdraws electrons inductively
Donates electrons by resonance
+N(CH3)3 - Withdraws electrons inductively
Explanation:
A chemical moiety may withdraw or donate electrons by resonance or inductive effect.
Halogens are electronegative elements hence they withdraw electrons by inductive effect. However, they also contain lone pairs so the can donate electrons by resonance.
Alkyl groups donate electrons by hyperconjugation involving hydrogen atoms.
-NHCH3 and contain species that have lone pair of electrons which can be donated by resonance. Also, the nitrogen and oxygen atoms are very electron withdrawing making the carbon atom to have a -I inductive effect.
+N(CH3)3 have no lone pair and is strongly electron withdrawing by inductive effects.
Unit cells provide the simplest repeating structures of a crystal. This means a unit cell must contain an integer multiple of the empirical formula.
a. True
b. False
Answer:
True
Explanation:
The unit cell is the smallest group of atoms which has the overall symmetry of a crystal, and from which the entire lattice can be built up by repetition in three dimensions (Oxford dictionary).
The number of atoms in a unit cell of a crystal structure must be equal to or a multiple of the number of atoms in the empirical formula of the compound. In other words, the unit cell should contain the formula unit of the compound.
What three biotechnologies do you think are the most important???
Answer:
Vaccines. Vaccines are chemicals that stimulate the body's immune system to better fight pathogens when they attack the body. ...
Antibiotics. ...
Pest Resistant Crops. ...
Plant and Animal Breeding. ...
Biocatalysts. ...
Fermentation. ...
Microorganisms. ...
Bioremediation.
Explanation:
If a country has a large amount of children born, but most do not live past 5, the population
pyramid would be described as:
Expansive
Constrictive
Stationary
Answer:
Constrictive,
Explanation:
Constrictive population pyramid displays lower percentages of younger people
A geochemist in the field takes a 25.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 26.° C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 350. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.00 g.1) Using only the information above, can you calculate the solubility of X in water at 26 degrees Celsius.? Yes or No2) If yes than calculate the solubility of X. Round your answer to 3 significant digits
Answer:
Yes we can calculate the solubility
The solubility of the mineral is 120 g/L
Explanation:
We have the information that the sample taken originally from the rock pool is 25.0 mL
So,
25.0 mL of the sample contained 3.000 g of the sample
10000mL of the sample now contains 1000 * 3.000/25 = 120 g
This means that 120 g of the sample dissolves in 1000mL or 1L of solution.
Therefore, the solubility of the mineral is 120 g/L
Draw a mechanism for the reaction of water with formic acid. In the box to the left, draw any necessary curved arrows. Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, indicate which side of the reaction is favored at equilibrium.
Answer:
See explanation
Explanation:
When water reacts with formic acid, The following equilibrium is set up;
HCOOH(aq) + H20(l) ⇄ HCOO-(aq) + H30+(aq)
This is because, the water abstracts a proton from formic acid to form its conjugate base, formate ion.
At equilibrium, the forward is favored.
If given 12 moles of Cl2, how many moles of HCl can form?
CH4+ 4Cl2——CCI4 + 4HCI
A. 4 moles HCl
B. 12 moles HCI
C. 1 mole HCI
D. 3 moles HCI
Answer:
B
Explanation:
4moles of Cl2 produces 4moles of HCl therefore 12moles of Cl2 will produce 12moles of HCl
What does the pH of a solution represent?
A. The pH indicates how acidic or basíc a solution is,
B. The pH represents the partial pressure of hydrogen gas.
O.C. The pH tells how quickly a reaction reaches equilibrium
D. The pH is an indicator of the salt content of a solution
Answer:
a
Explanation:
how much heat is required to convert 29g of ice at -4.0c to water vapor at 105
Answer:
45 degrees at 29 so 105 is lower than 45 and 105 wants to be 32 so 45 can be higher. so then the water vapor will be 35 because 105 is too much of water gallon
When the temperature of a reaction is raised from 278 K to 300 K, the reaction rate increases by a factor of 17. Determine the activation energy, Ea, of the reaction. R = 8.314 J/mol.K
Answer: The activation energy, Ea, of the reaction is 89195 Joules
Explanation:
The effect of temperature on rate constant is given by Arrhenius equation:
[tex]ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}][/tex]
where
[tex]k_2[/tex] = rate constant at temperature [tex]T_2[/tex]
[tex]k_1[/tex] = rate constant at temperature [tex]T_1[/tex]
[tex]E_a[/tex]= activation energy
R= gas constant
[tex]T[/tex] = temperature
[tex]ln \frac{17k_1}{k_{1}} = \frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}][/tex]
[tex]2.83=\frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}][/tex]
[tex]E_a=89195J[/tex]
The activation energy, Ea, of the reaction is 89195 Joules
la densidad de un aceite liviano para vehiculo es 0.87g/cm3 calcules su volumen especifico y peso especifico
Answer:
Pe = 8700 N/m³
Vesp = 1,15 cm³/g
Explanation:
Ya que conocemos el valor de la densidad de este aceite, es muy sencillo calcular tanto volumen como peso específico.
En el caso de volumen específico, esta se refiere al cociente del volumen de un líquido con su masa respectiva. En otras palabras, es el inverso de la densidad, por tanto usamos la siguiente expresión para el volumen específico:
Vesp = 1/d
Vesp = 1 / 0,87
Vesp = 1,15 cm³/gPara el caso del peso específico, se calcula como el cociente de la masa del líquido y su volumen que ocupa. Sin embargo no conocemos ninguno de esos dos datos, por lo que para calcular el peso específico solo basta multiplicar este valor por la aceleración de gravedad, que vamos a asumir para este problema que es 10 m/s². Y ademas cambiaremos las unidades de densidad de g/cm³ a kg/m³. Esto es porque las unidades de peso específico son N/m³ y los newton (N) son kg m/s².
d = 0,87 g/cm³ * (1 kg/1000g) * (100 cm/1m)³ = 870 kg/m³
Pe = 870 kg/m³ * 10 m/s²
Pe = 8700 N/m³ESpero te sirva.
which element has 51 protons in its nucleus?
Answer:
Antimony
Explanation:
Protons-51
Neutrons-71
Electrons-51
The standard heat of combustion is shown in the following chemical equation CgH 20 (g) + 140 2(g) 9CO 2(g) + 10H 2 o (1) delta
The given question is incomplete. The complete question is:
The standard heat of combustion is shown in the following chemical equation [tex]C_9H_{20}(g)+14O_2(g)\rightarrow 9CO_2(g)+10H_2O[/tex][tex]\Delta H_{rxn}=-6125.21kJ/mol[/tex]. If 130 g of nonane combusts , how much heat is released?
Answer: 6211.21 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of nonane = 6125.21 kJ
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of nonane [tex](C_9H_{20})[/tex] weighs = 128.2 g
Thus we can say:
128.2 g of nonane on combustion releases = 6125.21 kJ
Thus 130 g of [tex]C_4H_{10}[/tex] on combustion releases =[tex]\frac{6125.21}{128.2}\times 130=6211.21kJ[/tex]
Thus the heat of combustion of 130 g of nonane is 6211.21 kJ
What kind of thermal energy transfer is illustrated in the diagram?
Answer:
I think radiaction
Explanation:
How many moles are there in 6.33x10^23 molecules of NH3?
WILL GIVE BRAINLIEST how do you make a potion of fire resistance
A. Blaze powder, water bottle and nether wart
B. water bottle, nether wart, and magma cream
C. wither skull, water bottle and netherrack
D. water bottle, golden carrot and god apple
Answer:
B is the answer
Please give brainliest
Explanation:
I play Minecraft and Dream made it once
Carbon dioxide is an example of a molecular compound.
O True
O False
Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 0.365 g of hydrochloric acid is mixed with 0.18 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 2 significant digits.
Answer:
0.26g of NaCl is the maximum mass that could be produced
Explanation:
Based on the reaction:
HCl + NaOH → NaCl + H₂O
Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl
To solve this question we need to find limiting reactant. The moles of limiting reactant = Moles of NaCl produced:
Moles HCl -Molar mass: 36.46g/mol-:
0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl
Moles NaOH -Molar mass: 40g/mol-:
0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH
As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.
The mass of NaCl is:
Mass NaCl -Molar mass: 58.44g/mol-:
0.0045 moles * (58.44g/mol) =
0.26g of NaCl is the maximum mass that could be producedAlso what happens if you decrease NOCL
Answer:
el que paso del one jhaulio
Explanation: