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Answer:

  MCl₂

Explanation:

The formula for boiling point elevation can be used to find x. The "complete dissociation" means there will be an ion of M and x ions of Cl in the solution. The number of moles of solute will be 30.2 grams divided by the molecular weight of MClx, where x is the variable we're trying to find.

  [tex]\Delta T=imK_b\qquad\text{where i=ions/mole, m=molality, $K_b\approx 0.512$}\\\\376.81-373.15=(x+1)\dfrac{\text{moles}}{\text{kg solvent}}(0.512)\\\\\dfrac{3.66}{0.512}=(x+1)\dfrac{\dfrac{30.2}{56+35.45x}}{0.1}=\dfrac{302(x+1)}{56+35.45x}\\\\\dfrac{3.66}{0.512\cdot 302}(56+35.45x)=x+1\\\\\dfrac{3.66\cdot 56}{0.512\cdot 302}-1=x\left(1-\dfrac{3.66\cdot 35.45}{0.512\cdot 302}\right)\\\\x=\dfrac{50.336}{24.877}\approx 2.023[/tex]

Then the formula for the salt is MCl₂.

Answer:

Cu2+ (aq) + e- -------->Cu+ (aq)​E° = 0.15 V anode

Br2 (l) + 2e- -------------> 2Br- (aq) ​E° = 1.08 V cathode

Explanation:

The half equation having a more positive reduction potential indicates the reduction half equation while the half equation having the less positive reduction potential indicates the oxidation half equation.

The overall redox reaction equation is;

2Cu^+(aq) + Br2(g) ----> 2Cu^2+(aq) + 2Br^-(aq)

E°cell= E°cathode -E°anode

E°cathode= 1.08 V

E°anode= 0.15 V

E°cell= 1.08V-0.15V

E°cell= 0.93V

From;

∆G=-nFE°cell

n= 2

F=96500C

E°cell= 0.93V

∆G= -(2×96500×0.93)

∆G= - 179.49 J

From ∆G= -RTlnK

∆G= - 179.49 J

R=8.314Jmol-K-1

T= 25° +273= 298K

K= ???

lnK= ∆G/-RT

lnK=-( - 179.49/(8.314×298))

lnK= 0.0724

K= e^0.0724

Kc= 1.075

Answer: 7.505

×

10

22

atoms. (rounded to third place of decimal)

Explanation:

Answer:

4.83% of acetic acid in the vinegar

Explanation:

The neutralization reaction of acetic acid (CH₃COOH) with sodium hydroxide (NaOH) is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

Assuming the sodium hydroxide solution has a concentration of 0.500M, moles used in the neutralization reaction are:

0.0185L × (0.500mol / L) = 0.00925 moles of NaOH = 0.00925 moles CH₃COOH

Because 1 mole of acid reacts per mole of NaOH

Using molar mass of acetic acid (60g/mol):

0.00925moles CH₃COOH ₓ (60g / mol) = 0.555g of CH₃COOH

As mass of vinegar sample is 11.5g (d = 1g/mL), percentage of acetic acid by mass is:

0.555g CH₃COOH / 11.5g vinegar × 100 = 4.83% of acetic acid in the vinegar

Answer:

1.23 g/mL

-18.2%

Explanation:

We need to find the average, which is just the sum of the numbers divided by the number of numbers. Here, the sum will be 1.24 + 1.21 + 1.23 = 3.68 g/mL. There are 3 numbers, so divide 3.68 by 3: 3.68 / 3 ≈ 1.2266...

However, we need to round this and take into account significant figures. Each trial gave a number with 3 significant figures, so we round our number off to three: 1.22666... ≈ 1.23. So, circle the first number under the X column.

We now need to find the percent error, which is RE (%). To calculate this, we take the measured value (1.23 in this case) and subtract the exact value (1.50 here) from it, and then divide that by the exact value:

(1.23 - 1.50) / 1.50 ≈ -0.1822...

Again, we need to round to 3 significant figures, which would make it:

-0.1822... ≈ -0.182

Thus, circle the last number under the RE (%) column.

Answer:

CₙH₂ₙ

Explanation:

Answer:

[tex]\huge \boxed{\mathrm{C_nH_{2n}}}[/tex]

Explanation:

The general molecular formula for cycloalkanes is [tex]\mathrm{C_nH_{2n}}[/tex].

Answer:

Animal cells don't have a dividing cell wall like plant cells do

Explanation:

Plants cells use photosynthesis from the sun, which requires them to have chloroplast filled with chlorophyll to complete this function; animal cells do not have chloroplasts

Answer:

13.3 atm(assuming the temperature given is in Celsius)

Explanation:

First, the moles of each gas must be found. .25 mol He, .50 mol CO, .33 mol NO. Next, each set of mols must be plugged into the ideal gas law, PV=nRT, for each gas. Move it around so you get the pressure P=nRT/V. When you calculate everything, you should get 3.08atm He, 6.15atm CO, and 4.06atm NO. Add these together and you get the pressure of the container.

Answer:

0.25 mol

Explanation:

Moles= No.of molecules / Avogadros number

Answer:

0.25

Explanation:

Answer:

1. C+ ---- O-

2. O+ ---- Cl-

3. O+ ----- F-

4. C+ ----- N-

5. Cl- ----- C+

6. S- ----- H+

7. S+ ----- Cl -

Explanation:

Electronegativity determines the polarity . There may be two atoms in a bond with high electronegativity, in such cases the positive charge is given to atom with comparatively lower electronegativity. Electronegativity determines the easiness with which an atom attract electrons in a chemical bond. A polar bond is formed when the difference in the electronegativity of two combining atoms is between 0.4 and 1.7. The correct direction is

1. C+ ---- O-

2. O+ ---- Cl-

3. O+ ----- F-

4. C+ ----- N-

5. Cl- ----- C+

6. S- ----- H+

7. S+ ----- Cl -

The  mass of solid BaSO4 formed - 7.64 grams. and the pH of the mixed solution - 13.13

We can calculate the mass of the Ba(OH)2 by calculating the moles each solution contains

n(Ba(OH)2) = 1.00M x 0.05L

= 0.05 moles

0.494M x 0.0864L

= 0.04268 moles

According to balanced reaction 1 mole Ba(OH)2 react with 1 mole H2SO4 molar ratio between Ba(OH)2 to H2SO4 is 1:1 therefore to react with 0.05 mole Ba(OH)2 required H2SO4 = 0.05 mole but H2SO4 therefore H2SO4 is limiting reactant

Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O  

0.04268<--- 0.04268  

= 0.0172 mole

0.0172:(0.05 + 0.0664)

= 0.1478 M

Ba(OH)2 is strong base therefore dissociate completely and 1 mole of Ba(OH)2 form to mole of OH- ion therefore concentration of OH- is double than Ba(OH)2

14 - -log[0.1478]

= 14 - 0.83

= 13.13 pH

0.0328 x ( 137 + 32 + 16 x 4 )

= 7.64 grams.

Thus, The  mass of solid BaSO4 formed - 7.64 grams. and the pH of the mixed solution - 13.13

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Answer:

a) Sulphur + Oxygen → Sulphur dioxide

b) Carbon + Oxygen → Carbon dioxide

c) Sulphur + Iron → Iron sulphide

Answer:

.

Explanation:

.

Answer:first one: 3.0g second one: 10g H2O(I)

Explanation:

Answer:

First blank: 3.0 g Pb

Second Blank: 10g [tex]H_{2} O[/tex](l)

Explanation:

Edge '21

Answer:

Chemical rocket engines use a fuel (something to burn) and an oxidiser (something to react with the fuel). ... As the propellant reacts inside a combustion chamber, the chemical reaction produces hot gases. It is the ejection of these rapidly expanding hot gases at high speed from the rocket nozzle that

( I found this on a website called Science Learning. Full credit to them and their work. Check it out for more information)

Answer:

The percentage is   k  [tex]= 20.8[/tex]%

Explanation:

From the question we are told that

    The mass of the stibnite is  [tex]m_s = 5.86 \ g[/tex]

   The volume of   KBrO3(aq) is  [tex]V = 26.6 mL = 26.6 *10^{-3} \ L[/tex]

     The concentration  of   KBrO3(aq) is  [tex]C = 0.125 M[/tex]

Now the balanced ionic  equation for this reaction is

        [tex]BrO_3 ^{-}+ 3Sb^{3+} + 6H^{+} \to Br^{1-} + 3Sb^{5+} + 3H_2O[/tex]

The number of moles of   [tex]BrO_3 ^{-}[/tex] is  

     [tex]n = C *V[/tex]

substituting values

     [tex]n = 26.6*10^{-3} * 0.125[/tex]

     [tex]n = 0.003325 \ mols[/tex]

from the reaction we see that 1 mole of [tex]BrO_3 ^{-}[/tex]  reacts with 3 moles of  [tex]Sb^{3+}[/tex]

so 0.003325 moles will react with x moles of  [tex]Sb^{3+}[/tex]

Therefore

               [tex]x = \frac{0.003325 * 3}{1}[/tex]

              [tex]x = 0.009975 \ mols[/tex]

Now the molar mass of [tex]Sb^{3+}[/tex] is a constant with a values of  [tex]Z = 121.76 \ g/mol[/tex]

Generally the mass of  [tex]Sb^{3+}[/tex] is mathematically represented as

        [tex]m = x * Z[/tex]

substituting values

        [tex]m = 1.215 \ g[/tex]

The percentage of  Sb(antimony) in the overall mass of the stibnite is mathematically evaluated as

            k  [tex]= \frac{1.215}{5.85 } * 100[/tex]

           k  [tex]= 20.8[/tex]%

Answer:

Explanation:

Step 1: Data given

Mass of stibnite (Sb2S3) = 5.85 grams

The Sb3+(aq) is completely oxidized by 26.6 mL of a  0.125 M aqueous solution of KBrO3(aq).

Step 2: The balanced equation

BrO3-(aq)+ 3Sb^3+(aq) + 6 H+ → Br-(aq) + 3Sb^5+(aq) + 3H2O (l)

Step 3: Calculate moles KBrO3

Moles KBrO3 = molarity * volume

Moles KBrO3 = 0.125 M *0.0266 L

Moles KBrO3 = 0.003325 moles

Step 4: Calculate moles Bro3-

in 1 mol KBrO3 we have 1 mol K+ and 1 mol BrO3-

In 0.003325 moles KBrO3 we have 0.003325 moles BrO3-

Step 5: Calculate moles Sb

For 1 mol BrO3- we need 3 mol Sb^3+ to produce 1 mol Br- and 3 mol Sb^5+

For 0.029085 moles BrO3- we need 3*0.003325 = 0.009975 moles Sb

Step 6: Calculate mass Sb

Mass Sb = moles Sb * molar mass Sb

Mass Sb = 0.009975 moles * 121.76 g/mol

Mass Sb = 1.21 grams

Step 7: Calculate the percentage of Sb in the ore

% Sb = (mass Sb / total mass) * 100%

% Sb = (1.21 grams / 5.85 grams) * 100 %

% Sb = 20.76 %

Answer:

A general instrument, which is used to determine the concentration of hydrogen ion within the aqueous solution is known as a pH meter. The meter helps in determining the alkalinity or acidity, which is articulated in the form of pH. It is also called a potentiometric pH meter as it helps in finding the variation in electrical potential between a reference electrode and a pH electrode. This electrical potential variation is associated with the pH of the solution.  

The potentiometric pH meter comprises a pair of electrodes and a basic electronic amplifier, some may even comprise a combination electrode and some sort of display that demonstrates pH units. The potentiometric pH meter generally exhibits a reference electrode or a combination electrode, and a glass electrode. The probes or electrodes are administered within a solution whose pH values are needed to be determined.  

Answer:

True if by rifting you mean continental rift. If not idk.

Answer:

A. Enthalpy of hydration of CaCl2 = -2293 KJ/mol

Enthalpy of hydration of CaI2 = -2163 KJ/mol

B. Chloride ions

Explanation:

Enthalpy of hydration is the energy required to convert one mole of gaseous ions to aqueousions.

Enthalpy of hydration = Enthalpy of solution - lattice energy

For CaCl2;

Enthalpy of hydration = -46 - 2247 = -2293 KJ/mol

For CaI2;

Enthalpy of hydration = -104 - 2059 = -2163 KJ/mol

B. Since the enthalpy of hydration of CaCl2 is more negative than that of CaI2, it means that chloride ions are more easily attracted to water molecules. This we conclude because the difference in enthalpy values are due to the negative ions as the two compounds share a common positive calcium ion.

The enthalpy for hydration of calcium chloride is -2293 kJ/mol. The enthalpy for the hydration of calcium iodide is -2163 kJ/mol. The chloride ion Cl^- is more strongly attracted to water than iodide.

The enthalpy of hydration also the enthalpy of solvation is the quantity of energy released when 1 mole of gaseous ion is diluted.

It can be expressed by using the formula:

[tex]\mathbf{\Delta H_{hyd} = \Delta H_{solution} + \Delta H_{LE}}[/tex]

The enthalpy for hydration of calcium chloride can be expressed as:

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = \Delta H_{solution(caci_2)} + \Delta H_{LE(caci_2)}}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = -46 \ kJ/mol +-2247 \ kJ/mol}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} =-2293 \ kJ/mol}[/tex]

The enthalpy for the hydration of calcium iodide can be expressed as:

[tex]\mathbf{\Delta H_{hyd(cal_2)} = \Delta H_{solution(caI_2)} + \Delta H_{LE(caI_2)}}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = -104 \ kJ/mol +-2059 \ kJ/mol}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} =-2163 \ kJ/mol}[/tex]

From the above calculation, we can see that the enthalpy of hydration of calcium chloride is greater than that of calcium iodide,

Therefore, we can conclude that the chloride ion Cl^- is more strongly attracted to water than iodide.

Learn more about enthalpy of hydration here:

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Answer:

A. 4Ni(s) + 3O2(g) —> 2Ni2O3(s)

B. Synthesis reaction.

C. 18.31g of O2

Explanation:

A. The equation for the reaction.

Ni(s) + O2(g) —> Ni2O3(s)

The above equation can be balance as follow:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front Ni2O3 and 3 in front of O2 as shown below:

Ni(s) + 3O2(g) —> 2Ni2O3(s)

There are 4 atoms of Ni on the right side and 1 atom on the left it can be balance by putting 4 in front of Ni as shown below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Now the equation is balanced

B. From the equation, we can see that two reactants combined to form a single product. Therefore, the reaction is termed synthesis reaction.

C. We'll begin by calculating the mass of Ni and O2 that reacted from the balanced equation. This is illustrated below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Molar mass of Ni = 59g/mol

Mass of Ni from the balanced equation = 4 x 59 = 236g

Molar mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Summary:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Now, we can obtain the mass of O2 needed to react with 45g of Ni as follow:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Therefore, 45g of Ni will react with = (45 x 96)/236 = 18.31g of O2.

Therefore, 18.31g of O2 is needed to react with 45g of Ni

Answer:

0.209M

Explanation:

M1V1=M2V2

(28.5 mL)(0.183M)=(25.0mL)(M)

M2= 0.209M

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

Answer:

H2O / H+

Explanation:

In alkene hydration, water, being a very weak acid, with insufficient proton concentration, does not have the capacity to initiate the electrophilic addition reaction. An acid must be added to the medium for the reaction to take place.

The mechanism proceeds with the formation of a carbocation after adding the proton to the double bond. Alkene hydration is Markovnikov, that is, the proton is added to the less substituted carbon of the alkene.

Answer:

P4 + 5O2 → P4O10

Explanation:

White Phosphorus - P4

Dioxygen - O2

Tetraphosphorus Decaoxide - P4O10

Explanation:

[tex]CH_2O[/tex] is an energy rich molecule, which when reacts with oxygen produces carbon dioxide and energy. In aerobic reaction oxygen is consumed. IN this biochemical reaction oxygen is consumed and CO2 + CH4 is produced. Thus the reaction is aerobic one.

Answer:

C is the answer.

Explanation:

They are both people of color who were the first to do something in their fields

Answer:

increases

Explanation:because it cant decrease

Answer:

remains the same

Explanation:

Answer:

Br2 (l) + 2e- ---------> 2Br- (aq) E° = 1.08 V cathode

Cu2+ (aq) + e- --------->Cu+ (aq) E° = 0.15 V anode

Explanation:

We have to first state the fact that the reaction having the most positive reduction potential occurs at the cathode in any spontaneous electrochemical cell. The half reaction with the less positive electrode potential usually occurs at the anode.

The overall reaction equation is;

2Cu2+ (aq) + Br2 (l) ----->2Cu+ (aq) + 2Br- (aq)

E°cell= E°cathode - E°anode

E°cathode= 1.08 V

E°anode= 0.15V

E°cell = 1.08-0.15 = 0.93 V

But

∆G°= -nFE°cell

n= 2, F=96500C, E°cell= 0.93V

∆G° = -(2× 96500× 0.93)

∆G= -179490 J

But;

∆G = -RTlnK

R=8.314 JK-1

T= 25+273= 298K

Kc= the unknown

∆G° = -179490 J

Substituting values and making lnK the subject of the formula

lnK= ∆G/-RT

lnK= -( -179490/8.314 × 298)

lnK= 72.45

K= e^72.45

K= 2.91×10^31

During respiration, the inhalation of Oxygen (O) using the energy from Glucose (C6H12O6) is the first chain reaction.

Products formed during respiration are: Carbon Dioxide (CO2) and Water (H2O)

Answer:

8.3ml of 12M HCl contains 3.646 grams HCl

Explanation:

moles HCl = Molarity X Volume => Volume (Liters) = moles HCl/Molarity

Vol(L) = (3.646g/36.46g/mole)/12M = 0.0083Liter x 1000ml/L = 8.3ml

Answer:

less than 4.62 g

Explanation:

Sodium chloride contains 39% sodium by mass. Hence, 1 g of sodium chloride will contain:

39/100 x 1 = 0.39 g of sodium.

If 1 g of sodium chloride contains 0.39 g of sodium, then how many g of sodium chloride will contain the 1.8 g required sodium per day?

1 g sodium chloride = 0.39 g sodium

x g sodium chloride = 1.8 g sodium

x = 1.8 x 1/0.39 = 4.62 g of sodium chloride

Since the adult is supposed to consume less than 1.8 g of sodium per day, the mass of sodium that should be consume per day and still be within the FDA guidelines will be less than 4.62 g of sodium chloride.