Answer:
Amount Dan has = $17
Amount Ann has = $27
Amount Pablo has = $34
Step-by-step explanation:
Total amount they have = $78
Let
Amount Dan has = x
Amount Ann has = x + 10
Amount Pablo has = 2x
Total = Dan + Ann + Pablo
78 = x + (x + 10) + 2x
78 = x + x + 10 + 2x
78 = 4x + 10
78 - 10 = 4x
68 = 4x
x = 68/4
x = 17
Amount Dan has = x = $17
Amount Ann has = x + 10
= 17 + 10
= $27
Amount Pablo has = 2x
= 2(17)
= $34
In ΔCDE, the measure of ∠E=90°, ED = 28, CE = 45, and DC = 53. What ratio represents the tangent of ∠C?
Answer:
3/5
Step-by-step explanation:
prependicular / hypotenuse
sin C=ED/CD
=3/5
Plis help me it’s for today
Answer:
Following are the solution to the given points:
Step-by-step explanation:
For question 1:
[tex]\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789[/tex]
For question 2:
[tex]\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64[/tex]
For question 3:
[tex]\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633[/tex]
For question 4:
[tex]\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729[/tex]
For question 5:
[tex]\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225[/tex]
For question 6:
[tex]\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8[/tex]
For question 7:
[tex]\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000[/tex]
For question 8:
[tex]\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625[/tex]
For question 9:
[tex]\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5[/tex]
For question 10:
[tex]\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216[/tex]
a. 1.3
b. 9.6
c. 13
d. 1
Answer: I believe the answer would be 1.3
HOWEVER, if you do have to round to the nearest tenth then the answer would be 1
Step-by-step explanation:
2x+7 = 12x - 6
(subtract 2x from both sides)
7 = 10x - 6
(add 6 to both sides)
13 = 10x
(divide 13/10)
1.3 = x
The angle of elevation of a tree at a distance of 10m from the foot of the tree is 43°. Find the height of the tree
Answer:
9.32m is the height of. the tree from the ground.
© Find the quotient of 3/8 and ,4/9
Give your answer as a fraction in its simplest form.
[tex] \frac{3}{8} \div \frac{4}{9} \\ = \frac{3}{8} \times \frac{9}{4} \\ = \frac{27}{32} [/tex]
Hope it helps!!!
Thanks!!!
Instructions: Problem 2 ! Find the missing angle in the image below. Do not include spaces in your answers
Step-by-step explanation:
since angles in a triangle add up to 180
<vuw=180-(71+23)
=86°
since angles in a straight line add up to 180
<vuf=180-86
=94
Question 18 (5 points)
Determine the sum of the measures of the interior angles of a dodecagon (12-sided
polygon).
540°
1,800°
360°
2,160°
Answer:
its 540 bro
Step-by-step explanation:
pls help me in these questions
Answer:
1=85
2=10
3=108
Step-by-step explanation:
Number 1: Calculate each angle...and you know a straight line is 180°. N the interior sum of a quadrilateral is always 360°.
Number2: Use corresponding, alternate and interior angles method. It will help
Number 3: It's just about solving the interior sum of the pentagon
Answer:
2. 10 degrees
3. 108 degrees
Step-by-step explanation:
sorry I reposted it because the previous answer was deleted and plz mark me as a brainliest.
álgebra 1 solve -7 + 18(17h + 19)
Answer: =360h+335
Step-by-step explanation:
Answer:
306h + 281
Step-by-step explanation:
-7 + 18(17h + 19)
-7 + 306h + 288
306h + 281
All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High frequency EM is thought to be a cause of cancer; the lower frequencies associated with household current are generally assumed to be harmless. The following table summarizes the probability distribution for cancer sufferers and their wiring configuration in the Denver area.
Leukemia Lymphoma Other Cancers
High Frequency wiring 0.242 0.047 0.079
Low frequency wiring 0.391 0.098 ???
(a) What is the missing probability (labelled ???) in the above table?
(b) What is the probability of having high frequency wiring among cancer suffers in the Denver area?
(c) Is the event "Having Leukemia" independent of the event "Having high frequency frequency wiring"? Explain.
Answer:
[tex]x = 0.143[/tex]
[tex]P(High\ |\ Cancer) = 0.215[/tex]
Not independent
Step-by-step explanation:
Given
See attachment for proper table
Solving (a): The missing probability
First, we add up the given probabilities
[tex]Sum = 0.242+0.047+0.079+0.391+0.098[/tex]
[tex]Sum = 0.857[/tex]
The total probability must add up to 1.
If the missing probability is x, then:
[tex]x + 0.857 = 1[/tex]
Collect like terms
[tex]x = -0.857 + 1[/tex]
[tex]x = 0.143[/tex]
Solving (b): P(High | Cancer)
This is calculated as:
[tex]P(High\ |\ Cancer) = \frac{n(High\ n\ Cancer)}{n(Cancer)}[/tex]
So, we have:
[tex]P(High\ |\ Cancer) = \frac{0.079}{0.242+0.047+0.079}[/tex]
[tex]P(High\ |\ Cancer) = \frac{0.079}{0.368}[/tex]
[tex]P(High\ |\ Cancer) = 0.215[/tex]
Solving (c): P(Leukemia) independent of P(High Wiring)
From the attached table
[tex]P(Leukemia\ n\ High\ Wiring) = 0.242[/tex]
[tex]P(Leukemia) = 0.242 + 0.391 =0.633[/tex]
[tex]P(High\ Wiring) = 0.242+0.047+0.079=0.368[/tex]
If both events are independent, then:
[tex]P(Leukemia\ n\ High\ Wiring) = P(Leukemia) * P(High\ Wiring)[/tex]
[tex]0.242 = 0.633 * 0.368[/tex]
[tex]0.242 \ne 0.232[/tex]
Since the above is an inequality, then the events are not independent
I forgot to label the triangle below! I just know that the cos A = 0.48. Based on this information, which angle should be marked A?
Answer:
angle 1
Step-by-step explanation:
Using the trigonometric mnemonic SOH CAH TOA, we know that cos or cosine is the ratio between the adjacent side and hypotenuse side.
This means that if cos A = 0.48, A is the measure of the angle which it's relative adjacent side divided by the hypotenuse of the triangle will be around 0.48.
Let's try angle 2, cos (angle 2) = adjacent / hypotenuse = 7.8 / 8.9 = 0.876404494382 ≈ 0.87 ≠ 0.48. Since the proportions are not equal, this angle cannot be the one marked as A.
Since angle 3 is a right angle, the adjacent could be either side so it cannot be correct. Thus angle 1 is correct.
Find the measure of the missing angle using exterior angle sum theorm
Answer:
35
Step-by-step explanation:
The exterior sum theorem states the exterior angle is equal to the sum of the opposite interior angles
145 = ?+110
145 - 100 = ?
35 = ?
Solve The inequality
Answer:
D is the correct answer.
Please thank me
Step-by-step explanation:
You invest $4.000 in a savings account. The account pays 3% annual interest. How much money will be in the savings account after 9 years?
A) $4,938.29
B) $5,219.20
C) $5,124.33
D) $6,003.45
Answer:
4000*0.03*9=1080
4000+1080=5080
umm but like thats not one of the answers sorry
Hope This Helps!!!
Step-by-step explanation:
4000*3% = 120
120*9= 1080
1080+4000=5080
The a oranial price of a skate broad was reduced by 15 dollars .the new price is 49 dollars if p=the stakebroads oranail price in dollars what mathematical sentence expresses the information
a.49-p=15
b.15-p=49
c.15+p=49
d.p-15=49
Answer:
d. p - 15 = 49
Step-by-step explanation:
p = original price
The price was reduced by 15 dollars.
The new price is p - 15.
The new price is 49.
p - 15 = 49
Answer: d. p - 15 = 49
Two
1 1 sides of trapezium are bound 60 cm & 77cm
outer sides are 25cm. & 26cm Find the
area of trapezium
Answer:
area ABEC[tex]s =\frac{25 + 26 + 17}{2} = 34[/tex]
area ∆ BEC[tex] = \sqrt{34 \times 9 \times 8 \times 17} [/tex]
[tex]17 \times 3 \times 2 \times 2 = 204cm ^{2} [/tex]
area ∆ BEC
[tex] = \frac{1}{2} \times 17 \times h = 204[/tex]
[tex]h = \: \frac{204 \times 2}{17} = 24[/tex]
[tex]area \: trap \: \: abcd \\ = \frac{1}{2}(60 + 77) \times 24 \\ = 137 \times 12 = 1644cm ^{2} [/tex]
Step-by-step explanation:
❣️Jess bragoli❣️#keep learning!!
write the equation of the line that passes through the points (1,6) and (9,-8). put your answer in fully reduced slope form, unless it is a vertical or horizontal line.
Answer:
Y = - 7/4 X + 31/4
Step-by-step explanation:
M = 14/-8 = - 7/4
6 = - 7/4 + B
24 = -7 + 4B
31 = 4B
B = 31/4
I need help plz help
answer is C. 252 ft^2
split the figure into two pieces and first figure out the rectangle (shown in turquoise).
If you multiply the width and length (18*6) you should get 108.
Then figure out the trapezoid (in magenta). the formula is (a+b)/2*h where a and b are the bases and h is the height. the bases are given, 6 and 18. to find the height, subtract the entire figure's height by 6, which is 18-6 and gives us 12. so the formula converted to this problem is (6+18)/2*12. simplify parenthesis and get 24/2*12. 24/2=12, so multiply 12*12. The area of the trapezoid is 144. Add the areas of both figures together and get 252.
If and are the zeroes of the polynomial 2x^2+3x+5 then the value of 1/alpha + 1/beta
Pls answer fast..I’ll mark the brainlest
Answer:
-4/15
Step-by-step explanation:
Mathematically, we know that;
alpha= -b/a and beta = c/a
a refers to the coefficient of the x^2 which is 2
b is the coefficient of x which is 3
c is the last number which is 5
alpha = -b/a = -3/2
beta = c/a = 5/2
1/alpha = -2/3
1/beta = 2/5
so we have the sum as;
-2/3 + 2/5
= -5(2) + 3(2)/15 = (-10 + 6)/15 = -4/15
Find the area of the triangle whose vertices are (2, 3); (-1, 0); (2, -4)...
[Also show the steps of the solution]
Please answer correctly, it's really urgent!
Answer:
Area = 14.5
Step-by-step explanation:
Let's label the given coordinates A, B, C;
Thus;
A = (2, 3)
B = (-1, 0)
C = (2, -4)
From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;
Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2
Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2
Area = 29/2
Area = 14.5
Really struggling with these problems please help!
Solve.
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
Answer:
[tex]y_1 = -2[/tex] and [tex]y_2 = 4[/tex]
Step-by-step explanation:
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
Move the constant to the right-hand side and change their sign.
[tex] \sqrt{10y + 24} = y + 1 + 3 [/tex]
combine like terms
[tex] \sqrt{10y + 24} - 3 = y + 4[/tex]
Square both side to remove square brackets.
10y + 24 - 3 = y²+ 8y + 16
Move the expression to the left-hand side and change its sign.
10y + 24 - y² - 8y - 16 = 0
Combine like terms
10y - 8y + 24 - 16 - y² = 0
2y + 8 - y² = 0
Use commutative property to reorder the terms.
-y² + 2y + 8 = 0
Change the sign of expression.
y² -2y -8 = 0
split -2y
y² + 2y - 4y - 8 = 0
Factor out y from the first pair and -4 from the second equation.
y ( y + 2 ) - 4 ( y + 2 ) = 0
Factor out y+2 from the expression.
( y + 2 ) ( y - 4)
When the products and factors equals 0, at least one factor is 0.
y + 2 = 0
y - 4 = 0
Solve for y
y = -2
y = 4
When we plug the both solution as y we found that both is true solution of this equation.
This equation has two solutions which are -2 and 4.
Answer:
Solution given:
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
keep the constant term in one side
[tex] \sqrt{10y + 24} =y+1+3[/tex]
solve possible one
[tex]\sqrt{10y+24}=y+4[/tex]
now
squaring both side
[tex](\sqrt{10y+24})²=(y+4)²[/tex]
10y+24=y²+8y+16
taking all term on one side
10y+24-y²-8y-16=0
solve like terms
8+2y-y²=0
doing middle term factorisation
8+4y-2y-y²=0
4(2+y)-y(2+y)=0
(2+y)(4-y)=0
either
y=-2
or
y=4
y=-2,4
can someone answer plssss gives 100 pints i think bc I picked 100
[tex]1. \frac{20}{100} [/tex]
[tex]2. \frac{1}{5} [/tex]
Explanation:
There are a few ways to do this. One way is to notice that the jump from 5 to 100 is "times 20" (go from right to left across the bottom denominators).
So we must do the same "times 20" type of jump when going across the numerators. If x is the numerator for the right hand side, then we go from x to 20. That must mean x = 1
Put another way, we could have these steps
20/100 = x/5
20*5 = 100*x ... cross multiplication
100 = 100x
100x = 100
x = 100/100 .... dividing both sides by 100
x = 1
We see that the fraction 20/100 reduces fully to 1/5
To go from 1/5 to 20/100, we multiply both parts by 20 (divide both parts by 20 to go in reverse).
Solve simultaneously
4X + 3y= 19
2X +5y= 20
answer
4
2
Step-by-step explanation:
4x+3y=19
4x=19-3y
4x=16
x=16/4
x=4
2x+5y=20
5y=20/2x
5y= 10
y=10/5
y=2
please tel me answer of under root 3+4i
without calculatot with steps
Hello,
[tex]Let's\ say \\\\z=\sqrt{3+4*i} =a+b*i\\\\z^2=3+4*i=(a+b*i)^2=a^2-b^2+2i*a*b\\\\\\if \ a\neq 0\\\left\{\begin{array}{ccc}a^2+b^2&=&3\\2ab=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b=\dfrac{2}{a}\\a^2-(\dfrac{2}{a})^2=2\\\end{array}\right.\\\\\\a^4-4=3*a^2\\a^4-3a^2-4=0\\\\\Delta=(-3)^2-4*1*(-4)=25=5^2\\\\a^2=4\ or \ a^2=-1 (impossible)\\\\So:\\(a=2\ and\ b=1)\ or\ (a=-2\ and\ b=-1)\\[/tex]
Roots are thus 2+i and -2-i
There is an other using a geometrical formula (formule de Moivre)
Determine if the ordered pair (-1,-5) is a solution to the inequality y<_ -3/4x-1.
A.) No,because (-1,-5) is above the line
B.) Yes, because (-1,-5) is below the line
C.) No, because (-1,-5) is on the line
D.) Yes, because (-1,-5) is on the line
Answer:
the answer is B, comment if you need explanation
Step-by-step explanation:
If f(x) = 3x + 10 and g(x) = 2x - 4, find (f+g)(x).
O A. (f+g)(x) = -34 - 2x - 14
B. (f+ g)(x) = 3x - 2x + 14
O C. (f+ g)(x) = 5x + 6
D. (f+ g)(x) = 3x + 2x + 6
Help! I’m getting really confused which one it is
Answer:
O D
Step-by-step explanation:
f+g(x)
3x+10+2x-4
3x +2x+6
Can someone help me?
Answer:
C
Step-by-step explanation:
its asking for y, on the graph, the line is placed on point 4
Which best describes the vertex of the graph?
a (-3, -4)
b (-3, -4)
c (3, -4)
d (3, -4)
Answer: C
Step-by-step explanation:
8 Find the value of x a (22²)x is exponent of (22²) = 64
Given:
Consider the given equation is:
[tex](2\cdot 2^2)^x=64[/tex]
To find:
The value of x.
Solution:
We have,
[tex](2\cdot 2^2)^x=64[/tex]
It can be written as:
[tex](2\cdot 4)^x=8\times 8[/tex]
[tex]8^x=8^2[/tex]
On comparing the exponents of both sides, we get
[tex]x=2[/tex]
Therefore, the value of x is 2.
Which graph represents the solution of x2 + 9y2 ≤ 81 and y2 + 2 < x? On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded.
9514 1404 393
Answer:
C
Step-by-step explanation:
The ellipse y-intercepts are ±3, the x-intercepts are ±9, eliminating choices A and B. The parabola is shaded inside, eliminating choice D.
The correct choice is the third one.