angle2 cong angle5 so A|| B

Angle2 Cong Angle5 So A|| B

Answers

Answer 1

Answer:

False

Step-by-step explanation:

If angle 2 and angle 5 are equal in length, then what we have is that the two lines are not parallel

For the two lines to be parallel, these two angles should be supplementary

what this mean is that these two angles should add up to give 180 degrees


Related Questions

What's the area of the entire shape?

Answers

Answer:

30

Step-by-step explanation:

you need to multiply its length by its with

If f(x) is discontinuous, determine the reason.

f of x equals the quantity x squared plus 4 for x less than or equal to 1 and equals x plus 4 for x greater than 1 (5 points)
A. f(x) is continuous for all real numbers
B. The limit as x approaches 1 does not exist
C. f(1) does not equal the limit as x approaches 1
D. f(1) is not defined

Answers

Answer:  Choice A

f(x) is continuous for all real numbers

=============================================================

Explanation:

The piecewise function given to us basically breaks down into these two cases:

If x = 1 or smaller, then f(x) = x^2+4If x > 1, then f(x) = x+4

So if we plug in x = 1, then we go for the top line and say

f(x) = x^2+4

f(1) = 1^2+4

f(1) = 5

Showing that f(1) is indeed defined. We rule out choice D because of this.

----------------

Let's see what happens when we plug x = 1 into the bottom equation

f(x) = x+4

f(1) = 1+4

f(1) = 5

Both pieces produce the same output. This tells us that as x approaches 1 from either the left or right sides, the y value approaches y = 5. Therefore, the limit at x = 1 exists. We rule out choice B because of this.

We rule out choice C as well because f(1) does equal the limiting value mentioned earlier.

----------------

The answer is choice A because no matter what x value we plug in, it's not only defined but also it's connected to the rest of the function curve as shown below.

Answer: A; f(x) is continuous for all real numbers

Can someone help me solve this? I will need the x and y and will also need to solve for angles 1, 2, 3, and 4.

Answers

Answer:

x = 20,

y = 15

m<1 = 75°

m<2 = 75°

m<3 = 75°

m<4 = 105°

Step-by-step explanation:

m<1 = 3x + 15

m<2 = 4x - 5

m<3 = 5y

✔️m<1 = m<2 (corresponding angles are congruent)

3x + 15 = 4x - 5 (substitution)

Collect like terms

3x - 4x = -15 - 5

-x = -20

Divide both sides by -1

x = 20

✔️m<3 = m<2 (corresponding angles are congruent)

5y = 4x - 5 (substitution)

Plug in the value of x and solve for y

5y = 4(20) - 5

5y = 80 - 5

5y = 75

5y/5 = 75/5

y = 15

✔️Find the measure of each labelled angle:

x = 20, y = 15

Thus:

m<1 = 3x + 15 = 3(20) + 15

m<1 = 75°

m<2 = 4x - 5 = 4(20) - 5

m<2 = 75°

m<3 = 5y = 5(15)

m<3 = 75°

m<4 + m<3 = 180° (same side interior angles are supplementary)

m<4 + 75° = 180° (substitution)

m<4 = 180° - 75° (subtraction property of equality)

m<4 = 105°

Help please!!!!!!!!!!!!!!!!!!!!

Answers

9514 1404 393

Answer:

  (c) The solution -6 is an extraneous solution

Step-by-step explanation:

If you solve the equation graphically, you can avoid extraneous solutions. The true solution is x = -1.

You can tell from the equation that the domain will be restricted to values of x that make the radical non-negative:

  x+4 ≥ 0   ⇒   x ≥ -4

Then x=-6 must be an extraneous solution. It arises when the negative square root is used.

__

The conventional solution method has you square both sides and solve the resulting quadratic.

  (x +4)² = x +10

  x² +7x +6 = 0

  (x +6)(x +1) = 0   ⇒   x = -6 or -1

The solution x=-6 is not in the domain, so is extraneous.

__

Additional comment

Graphical solution is often easier if the equation is in the form f(x) = 0. That form can be had by subtracting one side of the equation from both sides. In the attached, we subtracted √(x+10) from both sides. (We added the negative branch of the square root function to show where the extraneous root comes from.)

find the value of x and y​

Answers

X=58

58-14= 44
44+58= 102
180-102= 78
78/2=39

Y=39

Answer:

x = 58

y = 39

Step-by-step explanation:

x = 58 (Vertically opposite angles)

x + 2y + (x-14) = 180 (Angles in a straight line)

=> x + 2y + x - 14 = 180

=> 2x + 2y = 180 + 14

=> 2(58) + 2y = 194

=> 116 + 2y = 194

=> 2y = 194 - 116

=> 2y = 78

=> y = 78/2

=> y = 39

(2-3 t)^2 QUICK PLEASEEEEEEEEEEEEEEEE

Answers

Answer:

The answer is = 4 - 12t + 9t^2

Step-by-step explanation:

(2-3t)^2

= 2^2 - 2*2*3t + (3t)^2

= 4 - 12t + 9t^2

Use the three steps to solve the problem.

Betty has 10 more dimes than quarters. If she has $3.45, how many quarters and dimes does she have?

Answers

Answer:

17

Step-by-step explanation:

Let d be dimes

q represent quarters

d = q + 10

10d + 25q = 345 cents

Substitute for "d" and solve for "q";

10(q+10) + 25q = 345

35q + 100 = 345

35q = 245

q = 7

Since d = q+10, d = 17

The ages of five children in a family are 6, 1, 3, 10, and 17. Which statement is true for this group of data?

mode>mean
median>mean
median=mode
mean>median

Answers

Answer:D - mean>median

Step-by-step explanation:

There are no repeating variables to have a mode so median and mean are the only options. The mean of this data set is 7.4 and the median is 6. Therefore mean greater than median

Can someone help I don’t understand the question

Answers

Answer:

36x

Step-by-step explanation:

OF= 6x (given radius of circle)

OB=OF+FB

= 6x +6x(given OF=FB)

= 12x

Angle D= angle B and angle O= 60°( given arc EF is 60°)

D + B + O= 180° ( sum of angles in a triangle)

x + x + 60= 180° ( let the value of remaining angles be x and D= B)

2x= 180 -60

x = 120/2

x= 60°

now, triangle DOB is a equilateral triangle because all angles are equal.

so, OB=DB=OD= 12x ( all sides are equal in equilateral triangle)

so,

perimeter of DOB= OB+DB+OD

= 12x+12x+12x

= 36x

follow me if this was helpful

Có 10 bạn mua cùng một loại vở hết tất ả 60 000 tính giá tiền của mỗi quyển vở biết rằng mỗi bạn mua 2 quyển vở

Answers

Answer:

Giá một cuốn sách là $ 1000

Step-by-step explanation:

Được

Tổng chi phí sách = 60000

Tổng số bạn bè = 10

Sách do mỗi người bạn mua = 2

Như vậy, tổng số sách mua của cả 10 bạn = 10 * 2 = 20

Giá của một cuốn sách = Tổng giá / tổng số sách đã mua

Giá một cuốn sách = 20000/20 = 1000

Giá một cuốn sách là $ 1000

Using the net below, find the surface area of the pyramid. 6 cm 7 cm Surface Area - [?] cm2​

Answers

Answer:

120 cm²

Step-by-step explanation:

Surface area of the pyramid = area of the 4 triangles + area of the square

✔️Area of the 4 triangles = 4(½*b*h)

b = 6 cm

h = 7 cm

Area = 4(½*6*7)

= 4(3*7)

= 4(21)

= 84 cm²

✔️Area of the square = s²

s = 6 cm

Area = 6² = 36 cm²

✅Surface area of the pyramid = 84 + 36 = 120 cm²

Trong mặt phẳng tọa độ Oxy , cho vectơ a = ( -3;4) . Độ dài vectơ a bằng bao nhiêu

Answers

Answer:

Step-by-step explanation:

Độ dài vecto a= căn bậc hai của (-3)*(-3)+4*4=5

Answer:

5

Step-by-step explanation:

If the cos of an angle is .75, what is the csc?
A. 1/√(5)
B. 9/√(6)
C. 6/√(2)
D. 3/√(9)
E. 4/√(7)
F. 2/√(3)

Answers

Answer: Choice E. 4/sqrt(7)

This is the same as writing [tex]\frac{4}{\sqrt{7}}[/tex]

=================================================

Explanation:

0.75 = 3/4

Recall that cosine is the ratio of adjacent over hypotenuse.

That means if cos(theta) = 3/4, then the adjacent is 3 units and the hypotenuse is 4 units.

Through the pythagorean theorem, we would then find that

a^2+b^2 = c^2

a = sqrt(c^2 - b^2)

a = sqrt(4^2 - 3^2)

a = sqrt(7)

This is the opposite side of reference angle theta.

From here, we can say

csc(angle) = hypotenuse/opposite

csc(theta) = 4/sqrt(7)

which points to choice E as the final answer.

what is the vertex of x^2

Answers

Answer:

The vertex is (0,0)

Step-by-step explanation:

To find the x coordinate of the vertex

x = -b/2a  where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)

Find the odd one out, and explain why
26..325..226..49..50
a) 325
b) 226
c) 50
d) 49

Answers

Answer:

B.226

Step-by-step explanation:

I HOPE ITS HELP PO

3a+5b+2c=?
a+b=15
b+c=14
5b=3b,2b

Answers

Step-by-step explanation:

please check you typing 5b = 3b, 2b

?????

Answer:

73

Step-by-step explanation:

3a + 5b + 2c = ?

Given:

a + b = 15

b + c = 14

now express in terms of b

a = 15 - b    equation (i)

c = 14 - b     equation (ii)

3a + 5b + 2c

substitute the values

3(15 - b) + 5b + 2(14 - b)

45 - 3b + 5b + 28 - 2b

add or subtract like terms

73 + 5b - 5b

plus 5b and minus 5b gets cancel

73

By writing each number correct to 1 significant figure, estimate the value of
37.8 x 13.2
28,5 + 22.1
You must show all your working.​

Answers

Answer:

37.8 x 13.2 =4988.6

28,5 + 22.1 = 50.6

In the diagram below, ΔPQR ≅ ΔSTR. Complete the statement ∠Q ≅ ___

Answers

Answer:  Choice A.  [tex]\angle T[/tex]

Explanation:

Notice how letters Q and T are in the middle of the sequences of PQR and STR respectively. This means the angles correspond.

Because the triangles are congruent, this means the corresponding pieces are congruent. Therefore, angle Q and angle T are the same measure.

As you can see, the order matters when it comes to forming congruence statements. Something like [tex]\triangle PQR \cong \triangle STR[/tex] is slightly different from [tex]\triangle PQR \cong \triangle SRT[/tex]

Congruent triangles have all corresponding measurements like angles and side lengths congruent. The completed statement would be ∠Q ≅ ∠T (Option A: ∠T)

What are congruent triangles?

Suppose it is given that two triangles ΔABC  ≅ ΔDEF

Then that means ΔABC  and  ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.

The order in which the congruency is written matters.

For ΔABC  ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.

Thus, we get:

[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D[/tex] (small m shows we're taking about measurement) (both the statements are equivalent)[tex]\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E[/tex][tex]\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F[/tex][tex]\rm |AB| = |DE| \: \: or \: \: AB \cong DE[/tex][tex]\rm |AC| = |DF| \: \: or \: \: AC \cong DF[/tex][tex]\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]

(|AB| denotes length of line segment AB, and so on for others).

For this case, we have:  ΔPQR ≅ ΔSTR

Thus, we have:

[tex]\angle Q = \angle T[/tex]

Thus, the completed statement would be ∠Q ≅ ∠T. (Option A: ∠T)

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Write an equation of a line that passes through (3, -1) and is perpendicular to y = 6x - 4. Show work.

I NEED THIS FAST

Answers

Answer:

y = -1/6x - 1/2

Step-by-step explanation:

y = -1/6x + b

-1 = -1/6(3) + b

-1 = -1/2 + b

-1/2 = b

What am I doing wrong? I've tried every conceivable answer, I thought I knew this type of math well, but this program keeps telling me I'm wrong.

Answers

Answer:

15.0 units

Step-by-step explanation:

Here, we want to get the distance between the two points as follows;

CD = √(x2-x1)^2 + (y2-y1)^2

So we have;

CD = √(7+8)^2 + (-5+4)^2

CD = √225+ 1 =

CD = √(226

CD = 15.0 units


Anyone know the answer to this question ?

Answers

Answer:

4.35

Step-by-step explanation:

(1 * 0.35) + (2 * 0.2) + (5 * 0.1) + (8 * 0.2) + (10 * 0.15) = 4.35

2020 people formed a line. In one move, you are allowed to exchange the positions of two people, separated by one other person. Can you always sort the people form tallest to shortest using these moves?

Answers

Answer:

yes you CAN you can use the descending to ascending formular but on people in which they might be a mixup of tallest and shortest

No, it is not always possible to sort the people from tallest to shortest using these moves.

Suppose there are four people in the line with heights A, B, C, and D, where A is the tallest and D is the shortest.

The initial order is A-B-C-D.

In each move, we can only exchange the positions of two people separated by one other person.

However, no matter how many moves we make, we cannot change the relative order of A and D since they are separated by two other people.

Thus, it is not possible to sort the people from tallest to shortest using these moves.

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if cos A= 9\13 find csc A

Answers

Answer:

13[tex]\sqrt{22}[/tex] / 44

Step-by-step explanation:

cos A = 9/13

here adjacent = 9 and hypotenuse = 13  opposite = ?

using pythagoras theorem to find opposite

a^2 + b^2 = c^2

9^2 + b^2 = 13^2

81 + b^2 = 169

b^2 = 169 - 81

b^2 = 88

b = [tex]\sqrt{88}[/tex]

b =  [tex]2\sqrt{22}[/tex]

therefore opposite =  [tex]2\sqrt{22}[/tex]

cosec A = hypotenuse/opposite

= 13/[tex]2\sqrt{22}[/tex]

rationalizing the denominator

=13/ [tex]2\sqrt{22}[/tex]  *  [tex]2\sqrt{22}[/tex] /  [tex]2\sqrt{22}[/tex]

=13 *[tex]2\sqrt{22}[/tex] /( [tex]2\sqrt{22}[/tex] )^2

=26 [tex]\sqrt{22}[/tex] / 4*22

=26 [tex]\sqrt{22}[/tex] / 88

=13[tex]\sqrt{22}[/tex] / 44

Answer:

[tex]cosec A = \frac{13}{\sqrt{88}}[/tex]

   OR

[tex]cosec A = \frac{13 \sqrt{22}}{44}[/tex]

Step-by-step explanation:

Formulas used:

[tex]cos^2 A = 1 - sin^2 A\\\\cosec A = \frac{1}{sin A}[/tex]

Given :

  [tex]cos A = \frac{9}{13}[/tex]

Find cosec A

   [tex]sin ^2 A = 1 - cos^2 A[/tex]

              [tex]= 1 - (\frac{9}{13})^2\\\\= 1 - \frac{81}{169}\\\\=\frac{169 - 81}{169}\\\\=\frac{88}{169}[/tex]

 [tex]sin A = \sqrt{\frac{88}{169}} = \frac{\sqrt{88}}{13}[/tex]

Therefore,

         [tex]cosec A = \frac{1}{sin A} = \frac{1}{ \frac{\sqrt{88}}{13}} = \frac{13}{ \sqrt{88}}[/tex]

OR In a simplified form :

[tex]cosec A = \frac{13}{\sqrt{88}} \times \frac{\sqrt{88}}{\sqrt{88}} = \frac {13 \times \sqrt{4 \times 22}}{88} = \frac{13 \times 2 \sqrt{22}} {88} = \frac{13 \sqrt{22}}{44}[/tex]        

Q.No.1: A subset of {2, b} is:

Answers

Answer:

{2}

or

{b}

a subset is a part of the whole set.

Answer:

hope it helps...

In Byron's class, there are 2 boys for every 3 girls. Today 7 new boys were added making the number of boys and girls the same. How many boys and girls were there originally?​

Answers

Answer:

12

Step-by-step explanation:

2+3=5+7=12

can someone help me I don't understand ​

Answers

Answer:

(a) 165 m/min

(b) 107.14m/min

Step-by-step explanation:

The slope of the distance time graph gives speed.

Here, the speed of the segment A is

[tex]v_A= \frac{900-0}{4-0}=225 m/min[/tex]

The speed of segment B is

[tex]v_B= \frac{1500- 900}{14-4}= 60 m/min[/tex]

(a) The change in speed is

= 225 - 60 = 165 m/min

(b) The average speed is defined as the ratio of total distance to the total time.

So, the average speed is

[tex]= \frac{1500}{14}= 107.14 m/min[/tex]

For the given functions f(x) and g(x), find (f + g)(x) or (f – g)(x) as
indicated.
f(x) = 8x – 7,8(x) = 6x – 4
Find (f + g) (x)

Answers

Answer:

(f + g) (x) = 14x-11

Step-by-step explanation:

From the question, what we have to do is to add the two given polynomials

We have this as;

(8x-7) + (6x-4) = 8x + 6x -7-4 = 14x -11

Find the value of x in the triangle .Please show work

Answers

Answer:

x=4

Step-by-step explanation:

So basically first we see the angles of this triangle, and we learn that all the angles are congruent. Only a equilateral triangle can have all angles congruent, so this must be equilateral triangle. In equilateral triangles all the sides are congruent. So we just put 5x-12=3x-4. We then solve for x and get 4.

Escribe un número de tres cifras digamos a1b1c1, en el cual a1 sea distinto de c1; ahora invierte los dígitos a1 y c1, (obtendrás el número c1b1a1 ); resta el número menor al número mayor, es decir a1b1c1 - c1b1a1 o bien c1b1a1 - a1b1c1, obtendrás como resultado un número de tres cifras, digamos a2b2c2 (es posible que a_2=0 ); invierte los dígitos a_2 y c_2. Finalmente suma los números a2b2c2 y c2b2a2 . ¿Qué número obtuviste?

Answers

Answer:

El número obtenido es:

1089.

Step-by-step explanation:

Vamos a escoger tres números sencillos para cada variable como:

a1 = 1b1 = 2c1 = 3

Por lo tanto, nuestro número de tres cifras es:

123 (la única pauta es que a1 sea diferente a c1 y con este número la cumplimos)

Ahora, nos dice que invirtamos los números a1 y c1, por lo tanto, nuestro nuevo número de tres cifras sería:

321

A continuación, nos menciona que restemos el menor del mayor, en este caso, nuestro número menor es 123 y el mayor es 321, por lo tanto:

321 - 123 = 198 (Este resultado será el mismo sin importar cuáles números elijas para el ejercicio)

Como obtuvimos el número 198, se podría decir que:

a2 = 1b2 = 9c2 = 8

Ahora nos piden que invirtamos a2 y c2, por lo tanto nuestro nuevo número sería:

891

Y por último, nos solicita que sumemos los dos últimos números obtenidos, entonces tenemos:

891 + 198 = 1089

Por lo tanto, el número obtenido al final es 1089, el cual obtendrás sin importar qué número de tres cifras elijas al inicio, siempre y cuando no se repitan el primero y el tercer dígito.

Question 7 of 27
Which of the following is an element in the sample space for first rolling a
number cube and then tossing a coin?

Answers

Answer:

TH is an element on the sample space for first rolling a die and then tossing a coin. A coin has both heads and tails.

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

The elements can be any of the elements in the sample space.

What is sample space?

It is the total number of possible outcomes from a given set.

We have,

The sample space for rolling a number cube and then tossing a coin consists of all possible outcomes from rolling the number cube and tossing the coin.

Each outcome is a pair consisting of a number from 1 to 6 (the possible outcome from rolling the number cube) and a head or tail (the possible outcome from tossing the coin).

Therefore, an element in the sample space can be represented as an ordered pair (n, h/t), where n is the number rolled on the number cube and h/t is the outcome of the coin toss (either head or tail).

So,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

For example, (3, H), (6, T), (1, H), and (4, T) are all elements in the sample space.

Thus,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

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