Ana vive a 3 km del instituto y María en la misma carretera, 500 m. Más lejos. Todas las mañanas, a las ocho y cuarto, cogen la bici para ir a clase. Ana pedalea a 6 m/s y María a 8 m/s. A) ¿Cuándo y dónde se encuentran? B) A que velocidad tendría que pedalear Ana como mínimo para que María no la alcanzase antes de llegar al instituto

Answers

Answer 1

Answer:

A) Ana y María e encuentran a las 8 hs 19 minutos 10 segundos (250 segundos después).

María y Ana  se encuentran cuando aún faltan 1500 metros para llega al instituto.

B) Ana tendría que pedalear como mínimo para que María no la alcanzase antes de llegar al instituto a una velocidad de 6.857 [tex]\frac{m}{s}[/tex].

Explanation:

A) Un movimiento es rectilíneo cuando un objeto describe una trayectoria recta, y es uniforme cuando su velocidad es constante en el tiempo. En otras palabras, el Movimiento Rectilíneo Uniforme es una trayectoria recta, su velocidad es constante y su aceleración es nula.

Para una posición inicial x0 y una velocidad v que tiene el cuerpo a lo largo del movimiento,  la posición para cualquier tiempo está dada por:

x(t)= x0 + v*t

Estableciendo el origen de referencia en el instituto, se tienen los siguientes valores:

x0ana= 3 km= 3000 mx0maria= 3500 m

Por otro lado, Ana pedalea a 6 m/s y María a 8 m/s.

Entonces, como Ana y María se acercan al origen de referencia, la escuela, se la ecuación del movimiento para cada una de ellas es:

xana= 3000 - 6*txmaria= 3500 - 8*t

Ambas se encuentra cuando la posición de ellas sea la misma, esto es xana=xmaria. Entonces:

3000 -6*t= 3500 - 8*t

Resolviendo:

-6*t + 8*t= 3500 - 3000

2*t= 500

t= 500÷2

t=250 s= 4 minutos 10 segundos

Ana y María se encuentran a las 8 hs 19 minutos 10 segundos (250 segundos después).

Para conocer la posición en la que se encuentran debes sustituir el tiempo en la ecuación del movimiento de alguna de ellas:

xana=3000 - 6*250

xana= 1500 m

Es decir, María y Ana  se encuentran cuando aún faltan 1500 metros para llega al instituto.

B) Para que esto ocurra Ana y María deben llegar al instituto al mismo tiempo. Entonces, el tiempo que tarda María en llegar a al origen de referencia, la escuela, es:

0= 3500 - 8*t

Resolviendo:

3500=8*t

3500÷8= t

437.5 segundos= t

Así que, si Ana 437.5 segundos o menos, María no la alcanzaría. Siendo la velocidad la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello, entonces la velocidad de Ana se calcula como:

[tex]velocidad=\frac{distancia}{tiempo}[/tex]

[tex]velocidad=\frac{3000 metros}{437.5 segundos}[/tex]

velocidad= 6.857 [tex]\frac{m}{s}[/tex]

Ana tendría que pedalear como mínimo para que María no la alcanzase antes de llegar al instituto a una velocidad de 6.857 [tex]\frac{m}{s}[/tex].


Related Questions

What is the average speed of the Earth after one orbit if it travels 585.6 million miles in 12 months?

Answers

Answer:

Forty-eight million eight hundred thousand

Explanation:

You divide 585.6/12. I really hope this helps!!

3. Why does any bonding occur (this includes ionic bonding and covalent bonding)?

A.to avoid nuclear decay

B.to decrease stability

C.to increase nuclear decay
.
D.to increase stability

Answers

Answer:im not sure but hope this helps

Explanation:

Covalent bonds are formed because of sharing electrons whereas ionic bonds formation occurs because of transferring of electrons. Molecules are the particles in covalent bonds all through compound formation whereas in ionic bonds these are positively charged and negatively charged ions.

Between which two atoms of water are hydrogen bonds are formed?

A. between the hydrogen atom of one water molecule and the oxygen atom of another

B. between the hydrogen atoms of two water molecules

C. between the oxygen atoms of two water molecules​

Answers

I hope you find the answer :)

A wheel with radius r rotates freely about its axle with initial angular speed ωi. A point on the wheel's rim moves at linear speed v.

Suddenly, the wheel accelerates so the point moves at linear speed 3v. The final angular speed is ωf.

How does the angular speed of the wheel change?

Answers

Answer:

[tex]\dfrac{2\omega_i}{t}[/tex]

Explanation:

r = Radius of wheel

v = Initial linear speed

3v = Final linear speed

Initial angular speed is given by

[tex]\omega_i=\dfrac{v}{r}[/tex]

Final angular speed after time [tex]t[/tex] is given by

[tex]\omega_f=\dfrac{3v}{r}\\\Rightarrow \omega_f=3\dfrac{v}{r}=3\omega_i[/tex]

The angular acceleration of the wheel will give us how the angular speed of the wheel changes.

From the equations of rotational motion we have

[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow 3\omega_i=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{3\omega_i-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{2\omega_i}{t}[/tex]

The acceleration wheel is [tex]\dfrac{2\omega_i}{t}[/tex].

Answer:increases by a factor of 3

Explanation: just trust me bro

5. You require a high-current battery to start a large tractor. While shopping
for this battery, should you be more concerned with the battery's rating
of volts or amps? Explain.

Answers

Answer:

I have no clue sorry I wish I could help

what are some of the uses of ultra-sound​

Answers

Answer:

Ultrasou­nd has been used in a variety of clinical settings, including obstetrics and gynecology, cardiology and cancer detection. The main advantage of ultrasound is that certain structures can be observed without using radiation. Ultrasound can also be done much faster than X-rays or other radiographic techniques

Answer:

Ultrasound can be used for various purposes like diagnosing conditions, including those in the heart, blood vessels, liver and more. Yet most commonly to monitor growth and development of a fetus. A echocardiogram is a ultrasound of the heart.

Explanation:

1. Isotopes have a different nubmer of neutrons in the nucleus. These atoms would have different
as a result. *
A) identities
B) charges
C) atomic numbers
D) atomic masses

Answers

Answer:

i believe atomic mass

Explanation:

The answer is atomic mass

A rock is dropped from a height of 3.4 m. How much time does it take to hit
the ground?
O .83 s
O 1.17 s
O 0.59 s
O 33.32 s

Answers

Answer: 33.32 s

Explanation: gravity =9.8m/s2 which means that 3.4mx9.8m/s2=33.32s

I hope this helped ! Sorry if it’s wrong :)

A 5.00 kg firecracker explodes into two parts: one part has a
mass of 3.00 kg and moves at a velocity of 25.0 m/s towards
the west. The other part has a mass of 2.00 kg. What is the
velocity of the second piece as a result of the explosion?
a -28.7 m/s
b 15.8 m/s
C-37.5 m/s
d 43.2 m/s

Answers

Answer:-37.5 m/s

Explanation:

Answer:

-37.5

Explanation:

Brian and Emily are testing different paper airplane designs to see which will allow a plane to travel the farthest distance. Emily folds her plane and attaches a paperclip to the front of it. After she throws the plane, it travels about fifty feet and then falls to the ground. Why does the plane eventually fall to the ground?

Halp meh pleaase

Answers

Answer:

The answer is "The gravity force is stronger than for the powers in the air".

Explanation:

Gravity is the fundamental attraction force which acts among all material. On Earth, each organ does have a weight, and decreasing force of gravity, it relative towards its weight imposed by the earth's mass. Force is measured mostly by acceleration it gives to artifacts that can drop, that's why the plane eventually falls to the ground.

Rolling Balls LAB - ANSWER SHEET (45 pts)

QUESTIONS:
1. What is the formula for calculating speed? (1 pt)


2. If you were trying to determine if cars in your neighborhood were traveling at or below the posted speed limit, how would you do it? (2 pts)


3. Create a hypothesis as an if-then statement. (2 pts)


4-15. Fill in the Data Table for Balls #1 and #2 (2 pts per blank)
Ball #1 (Describe the ball) - ____________________________________________________
Trial Time to travel 2 meters (seconds)
1
2
3
Average Time




Using the formula s = d/t, calculate the average speed of Ball #1: _____________________

Ball #2 (Describe the ball) - ____________________________________________________
Trial Time to travel 2 meters (seconds)
1
2
3
Average Time




Using the formula s = d/t, calculate the average speed of Ball #2: _____________________

16. Based on your data, which ball was the fastest? (1 pt)
17. Why do you think it was the fastest? (2 pts)
18. Was your hypothesis correct? (1 pt)
19. Do you think size of the ball had anything to do with the speed of the ball? (2 pts)
20. Why or why not? (2 pts)
21. Name 2 factors that could determine the speed at which a ball rolls. (2 pts)

22. A car travels 3 kilometers and it takes 2 minutes to cover that distance What is the speed of the car? (2 pts)
23. A train is traveling at 60 km/hr. It travels for 2 hours. How far will it travel? (2 pts)
24. A girl is riding her bicycle at 10 miles/hour. At the end of the ride she has traveled 35 miles. How long did it take her to cover that distance? (2 pts)

Answers

Answer:

1. s = d/t

22. d = 3km = 3000m

t = 2m = 60s

s = 3000/60

= 300/6

= 50m/s

Therefore, the speed of the car is 50 m/s.

23. s = 60km/hr

t = 2hrs

d = s × t

d = 60 × 2

d = 120km

The car travels for 120km.

24. s = 10mile/hr

d = 35km

t = d/s

t = 35/10

t = 3.5hrs

The girl takes 3.5 hours to cover the distance

For which optical devices does d¡ always have a negative value?
A. A and B
B. A and D
C. Band D
D. B and C

Answers

Answer:

Explanation:

A i think

this is my physical science homework on chemical equations please if you can answer them in order thank you!

Answers

Do you still need help or did you do them?

50 POINT PHYSICS QUESTION! PLEASE HELP!

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. If the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?
Remember to identify all your data, write the equation, and show your work.

Answers

Answer: I solved it and got 30.65 meters.

Explanation: Pic Attached. Hope this helps.

Answer:

30.65

Explanation:

becuase i read the othe part

What type of modulation is typically used by broadcasting stations to transmit pictures on television screens?
O amplitude
O frequency
O phase
O pulse

Answers

Answer:

The correct option is;

Amplitude

Explanation:

When transmitting picture signals over the air by broadcasting stations, the signals are shifted into high frequency channels of Very High Frequency (VHF) or Ultra High Frequency (UHF) carrier currents and imposing the the television signal by changing the amplitude of the high frequency carrier current to match the transmitted television signal waveform shape

A soccer ball was kicked off the roof of a building going
20m/s. It took 5 s for the soccer ball to hit the ground?
Find the vertical final velocity, the distance the ball
traveled horizontally, and the height the ball fell.

Answers

Answer:

Final vertical velocity = -29m/s

Horizontal distance = 100m

Height = 20.41m

Explanation:

1. The vertical final velocity can be calculated thus: vy = vyo - gt

Where;

vy = vertical velocity (m/s)

vyo = vertical initial velocity (20m/s)

g = acceleration due to gravity (9.8m/s²)

t = time (5s)

Hence, vy = vyo - gt

vy = 20 - (9.8 × 5)

vy = 20 - 49

vy = -29m/s

2. x = V0 x t

Where;

x = horizontal distance (m)

Vo = initial velocity

t = time (s)

x = 20 × 5

x = 100m

3. Maximum height = (voy)²/2g

= 20²/ 2 × 9.8

= 400/19.6

= 20.41m

If the velocity of a moving object decreases from 60 m/s to 30 m/s, what happens to its momentum? (2 points) Group of answer choices It is reduced by half It doubles It stays the same It quadruples

Answers

Answer:

it is decreased by 1/2

Explanation:

The velocity of the moving object is reduced by half decreasing speed is also decreasing the momentum of a certain object.

Answer:

-1/2

Explanation:

A man exerts a force on a large couch by pushing on it. Which of the following must be a true statement about the couch after he begins pushing?

A. The couch will maintain a constant acceleration due to the man's push.
B. The couch will remain at rest.
C. The couch will remain at rest if the push does not overcome the force of friction.
D. The couch will accelerate and then remain at a constant velocity.

Answers

Answer: the answer is c

Explanation:

A 2.0 kg box is pulled along a frictionless, horizontal surface by a force that makes an angle of 30 degrees with the ground. If the box is pulled a distance of 4.0 meters and changes speed from 1.0 m/s to 3 m/s, what was the magnitude of the force on the box?

Answers

Answer:

2 N

Explanation:

v = Final velocity = 3 m/s

u = Initial velocity = 1 m/s

s = Displacement = 4 m

m = Mass of box = 2 kg

Acceleration of the box is

[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{3^2-1^2}{2\times 4}\\\Rightarrow a=1\ \text{m/s}^2[/tex]

Force is given by

[tex]F=ma\\\Rightarrow F=2\times 1\\\Rightarrow F=2\ \text{N}[/tex]

The force on the box is 2 N.

A cheetah and a gazelle are grazing in the savannah. The gazelle is 275 meters away from the gazelle safe zone and the cheetah is 455 meters away. If the gazelle can run at 25 m/s and the cheetah can run at 65 m/s will the gazelle get to safety? If not how fast does the gazelle need to run to beat the cheetah by 2 seconds? I​

Answers

Answer:

1) Yes, the gazelle gets to safety

2) The speed with which the gazelle needs to run, to beat the cheater by 2 seconds is approximately 29.79 m/s

Explanation:

1) The distance of the gazelle, from the gazelle safe zone = 275 m

The distance of the cheetah from the gazelle = 455 m

The speed of the gazelle = 25 m/s

The speed of the cheetah = 65 m/s

Therefore, we have;

Let the time the gazelle reaches the safe zone = t, which gives;

t = 275 m/(25 m/s) = 11

t = 11 seconds

Let the time the cheetah reaches the gazelle = t₁, we have;

455 + 25 × t₁ = 65 × t₁

t₁ = 455/40 = 11.375

t₁ = 11.375 seconds

The gazelle reaches the gazelle safe zone before the cheetah reaches the gazelle

Therefore, the gazelle gets to safety

2) In order for the gazelle to beat the gazelle by 2 seconds, we have;

The time for the cheetah to reach the safe zone = (275 + 455)/65 = 11.23 seconds

Therefore, we have;

In order for the gazelle to beat the gazelle by 2 seconds the time the cheetah reaches the safe zone = 11.23 - 2 = 9.23 s

The speed of the gazelle is then 275/9.23 ≈ 29.79 m/s

Answer: d = r · t d + 300cheertah = 18t gazelle = 16t the running times are equal!   (d + 300) / 18 = d / 16   Solve ford then determine time.

sorry if its confusing

Determine the gravitational energy of your 2 kg physics binder if it is sitting on the ground (height= 0
meters)

Answers

Answer:

0J

Explanation:

The gravitational potential energy of the body is 0J because the height is at 0m.

Gravitational potential energy is a form of energy which is highly dependent on the position of a body. The relative position of a body in space accounts for the amount of gravitational potential energy they posses.

A body at height 0m has no gravitational potential energy:

 Gravitational potential energy  = mgh

       m is the mass of the body

       g is the acceleration due to gravity

       h is the height

 So, if h = 0, Gravitational potential energy will become 0.

The energy that is stored in
chemical composition of matter is....
a. Potential Energy
b. Elastic Enersy
c. Chemical Energy
d Mechaneal Energy

Answers

Answer:

C

Explanation:

Chemical energy is energy stored in the bonds of chemical compounds, like atoms and molecules. This energy is released when a chemical reaction takes place.

a. potential energy. chemical energy is the form of potential energy in which energy is stored in chemical bonds. when those bonds are formed, chemical energy is invested, and when they break, chemical energy is released.

After a wave passes through a medium, particles in the medium

Answers

Answer:

If a particle is affected by a wave, then the particles are displaced. They move along the direction of the wave. Hence, After a wave passes through a medium, particles in the medium are moved along with the wave.

Explanation:

hope this helps you

Why does the comet have tails

Answers

Answer:

Comets leave long beautiful tails when they come close to the sun. ... But when it approaches the sun, the heat evaporates the comet's gases, causing it to emit dust and microparticles (electrons and ions). These materials form a tail whose flow is affected by the sun's radiation pressure.

Explanation: I just searched it up on the internet lol.

Answer:

when it approaches the sun, the heat evaporates the comet's gases, causing it to emit dust and micro particles

Explanation:

:)

A skater increases her velocity from 2.0 m/sec to 10.0 m/sec in 3.0 sec. what is the acceleration of the skater

Answers

Final speed 10.0 rn/s Change in time = 3 seconds The acceleration of the skater is 2.7 meters per second Relationship per second. 3.

1. The same amount of work can be done when applying a small force over a long distance or applying a large force over a short distance, since work equals blank times blank​

Answers

Answer:

work done = force × displacement

Over 75 seconds a truck traveled at a constant velocity of 25 meters per second to the west. Find the trucks displacement

Answers

Answer:

1875 m west

Explanation:

Take east to be the positive direction.  Given:

v₀ = -25 m/s

a = 0 m/s² (constant velocity)

t = 75 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (-25 m/s) (75 s) + ½ (0 m/s²) (75 s)²

Δx = -1875 m

Matching vocabulary terms

Answers

Answer:

.

Explanation:

26 = Terminal Velocity

27 = Force

34 = Momentum

33 = Laws of Conversation of Momentum (I think)

Which of the following is NOT a type of electromagnetic wave?

Answers

Answer:

Sound waves

Explanation:

You should let someone else answer too though because I'm not 100% sure that's the correct answer.

Which of the following materials is a mixture? A. water B. table salt C. seawater D.iron filings

Answers

Answer:

eu acho que ê a B

uma bela noite abençoada

Answer:

The answer is "B" table salt

Good look

Explanation:

     

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