The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory. T/F?
The given statement about “The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory.” is true, because in his famous experiment, alpha particles were seen to scatter away from a gold foil in the reverse direction.
In the Rutherford model, the atom is described as having a small, dense, positively charged core known as a nucleus, in which nearly all of the mass is concentrated, and around which the light, negative constituents known as electrons circulate at some distance, similar to how planets revolve around the sun at a certain distance. Under the guidance of Rutherford and German physicist Hans Geiger in 1909, Ernest Marsden, conducted a series of experiments that revealed the scattering of alpha particles from thin gold foil. This resulted in the hypothesis that the nucleus was small and dense.
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A 11-kg cannonball is fired with a velocity of 19m / s from 28 m above the ground . It hits a target that is 11 m above the ground . With what velocity does it hit, in m / s ? (Round your answer to one decimal place if necessary .)
The required cannonball hits the target with a velocity of 26.25 m/s.
What is the law of conservation of energy?The law of conservation of energy states that sum, when the object is in motion the sum of the initial energy, is equal to the sum of the final energy.
The velocity of the cannonball just before it hits the target can be determined using the law of conservation of energy, which states that the total energy of a system is constant.
The initial potential energy of the cannonball is given by:
PE(i) = mgh
PE(i) = 11 kg * 9.8 m/s^2 * 28 m
PE(i) = 3018.4 J
The final potential energy of the cannonball is given by:
PE(f) = mgh
PE(f) = 11 kg * 9.8 m/s^2 * 11 m
PE(f) = 1185.8J
The initial kinetic energy of the cannonball is given by:
KE(i) = 0.5 * m * v^2
KE(i) = 0.5 * 11 kg * 19 m/s^2
KE(i) = 1985.5 J
Since the total energy of the system is conserved, we have:
PE(i)l + KE(i) = PE_(f) + KE_(f)
3018.4 J + 1985.5 J = 1185.8 J + KE(f)
KE(f) = 3791.1 J
Finally, the velocity of the cannonball just before it hits the target can be calculated from its kinetic energy:
v^2 = 2 * KE / m
v^2 = 2 * 3791.1J / 11 kg
v = √(2 * 3791.1 J / 11 kg)
v = 26.25 m/s
So the cannonball hits the target with a velocity of 26.25 m/s.
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a ball thrown upward reaches its maximum height and then falls back. if air resistance is negligible, its acceleration is
A ball sent upward reaches its highest point before falling backward. If aerodynamics is minimal, the motion's acceleration is constant throughout.
Describe acceleration.In physics, acceleration is the rate at which the movement of an object changes in relation to time. According to Newton's Second Law, the sum of all force applied on an item results in its acceleration. The axis of motion is altering, therefore an object moving at a steady speed on a circular path is still moving forward.
What are the three types of acceleration?The three forms of increasing motions are often classified as uniform acceleration, non-uniform acceleration, and average acceleration. Uniform acceleration describes a motion that occurs when a object follows an uniform path while accelerating gradually over time.
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At depth of 12. 5m of chemicals solvent the pressure at bottom of storage tank due solvent was 306kpa calculatr the density of solvent take g=10m\s2
The density of solvent is 2448 kg/m³.
What is pressure?Per unit area across which a force is spread, pressure is the force delivered perpendicularly to an object's surface. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.
Pressure is expressed using a variety of units. Some of them come from dividing a force unit by an area unit; for example, the SI pressure unit, the pascal, is derived from this (Pa).
According to the question:
ρ × 10 × 12.5 = 306 × 10³
ρ = 2448 kg/m³
Hence, the density of solvent is 2448 kg/m³.
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Find the magnitude of the electric field, in newtons per coulomb, at the location of q a in the figure, given that q b = q c = q d = 4.9 nC , q = - 0.25 nC , and the square is 12 cm on a side
At the location of q a in the figure, given that q b = q c = q d = 4.9 nC , q = - 0.25 nC , and the square is 12 cm on a side. The magnitude of the electric field at the location of qa is 2.16 x [tex]10^{7}[/tex] N/C.
The electric field at a point due to a point charge is given by the formula:
E = k . q / r^2
where,
k = Coulomb's constant (8.99 x 10^9 Nm^2/C^2),
q = the charge producing the field,
r = the distance from the charge.
Let's call the side length of the square L. The charges qb, qc, and qd are located at the corners of the square, and are equidistant from the point where we want to calculate the electric field, so we can calculate the field due to each of them separately and then add them up.
The distance between the charges and the point of interest is L/√2. The electric field due to each charge can be calculated as:
E = k * 4.9 x 10^-9 C / (L/√2)^2 = k * 4.9 x 10^-9 C / (12/√2)^2 = k * 4.9 x 10^-9 C / (12/1.4142)^2
Adding the contributions from the three charges, the total electric field due to qb, qc, and qd is:
E = 3 * k * 4.9 x 10^-9 C / (12/1.4142)^2
Next, we need to calculate the contribution from the charge q. The electric field due to q can be calculated in the same way, but since q is negative, the direction of the field will be opposite to that due to the other charges:
Eq = - k * -0.25 x 10^-9 C / (L/√2)^2 = k * 0.25 x 10^-9 C / (12/√2)^2
Finally, the total electric field at the point is the sum of the contributions from all the charges:
Etotal = E + Eq = 3 * k * 4.9 x 10^-9 C / (12/1.4142)^2 + k * 0.25 x 10^-9 C / (12/√2)^2
So, the magnitude of the electric field at the location of qa is:
Etotal = √(Ex^2 + Ey^2) = √((3 * k * 4.9 x 10^-9 C / (12/1.4142)^2)^2 + (k * 0.25 x 10^-9 C / (12/√2)^2)^2)Etotal = √((3 * 8.99 x 10^9 Nm^2/C^2 * 4.9 x 10^-9 C / (12/1.4142)^2)^2 + (8.99 x 10^9 Nm^2/C^2 * 0.25 x 10^-9 C / (12/√2)^2)^2) = √((3 * 8.99 x 10^9 Nm^2/C^2 * 4.9 x 10^-9 C / (12/1.4142)^2)^2 + (8.99 x 10^9 Nm^2/C^2 * 0.25 x 10^-9 C / (12/√2)^2)^2) = 2.16 x 10^7 N/CSo the magnitude of the electric field at the location of qa is 2.16 x [tex]10^{7}[/tex] N/C.
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A point charge is placed in an electric field which varies with location. No force is exerted on this charge: at locations where the electric field is zero at locations where the electric field strength is 1/(1.6 times 10^-19) N/C if the charge is moving along an electric field line if the charge is moving perpendicular to an electric field line if the electric field is produced by an equal amount of positive and negative
A point charge placed in an electric field does experience a force due to the interaction of the electric field with the charge. At locations where the electric field is zero, the force on the point charge would be zero as well, as it would not experience any interaction with the field.
If the electric field strength is 1/(1.6 times 10^-19) N/C, the force on the point charge would be equal to the product of the electric field strength and the magnitude of the charge.
The direction of the force would depend on the sign of the charge - if it is positive, it would experience a force in the direction of the electric field, and if it is negative, it would experience a force in the opposite direction.
If the charge is moving along an electric field line, it would experience a force in the direction of the field.If the charge is moving perpendicular to an electric field line, it would experience no net force in the direction perpendicular to the field. However, it would still experience a force in the direction of the field due to the interaction of the field with the charge.If the electric field is produced by an equal amount of positive and negative charges, the net force on a point charge would be zero, as the field would cancel out. However, the charge would still experience a force due to the interaction of the electric field with the charge.Here you can learn more about the electric field
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FILL IN THE BLANK. when you increase your vehicle's speed, you must also increase your __ to compensate for limitations.
When you increase your vehicle's speed, you must also increase your following interval to compensate for limitations.
What is speed?
When an object travels an identical distance in a same amount of time, this is referred to as having uniform speed.The uniform speed determined by the ratio of the whole distance travelled by an object to the total amount of time it took to travel that distance is known as the average speed.Instantaneous speed: When an object is travelling at a variable pace, it refers to the speed of that object at any given moment in time.To know more about speed, click the link given below:
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what is a dielectric constant
Answer: The dielectric constant is the ratio of the capacitance formed by two plates with material between them to the capacitance of the same plates with air as the dielectric. For low megahertz, frequencies are less than are equal to 1,000 MHz.
Explanation:
Your roommate is working on his bicycle and has the bike upside down. He spins the 70.0 cm -diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second. Express your answer with the appropriate units.
Part A: What is the pebble's speed?
Part B: What is the pebble's acceleration?
The wheel's circumference is C = d = (0.7 m) = 2.2 m. The pebble travels 3C = 6.6 m in one second since it passes by three times every second. Hence, the stone moves at 6.6 m/s when v = d/t. Part B: The formula = /t, where is the change in angular speed and t is the time it takes for the change to occur, can be used to calculate the angular acceleration of the wheel.
What is an example of inertia?
Upon being battered, the mat releases dust. falling forward when abrupt breaks are applied in transit. When the tree is shaken violently, the leaves fall off. Artificial satellites continue to orbit in a circular motion due to inertia.
What is a SI unit of inertia?
An object's inability to change its position or the configuration of a particular body is known as inertia. Kilo Gram is the SI unit of inertia since mass is a measure of inertia. If you require a unit of inertial moment, it is Kg m2.
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Now we replace the resistor in the circuit of problem 1 with a diode-connected PMOS device asshown.A. What W/L ratio is needed for M6 in order to set IREF = 25 mA?B. If M6 is implemented as a diode-connected nFET instead of pFET, what W/L ratio would berequired?C. Which implementation, pFET or nFET would take up the most area?
The circuit of an electric bell consists of an electromagnet, a switch, and a source of power. When the switch is activated, the electromagnet is energized, creating a magnetic field. This magnetic field attracts a metal hammer, which strikes a bell and produces a ringing sound. When the switch is released, the circuit is broken, de-energizing the electromagnet and allowing the hammer to return to its original position. This process repeats each time the switch is activated.
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define a function using python ewma(data, alpha) for the exponential weighted moving average calculation, where alpha is the degree of weighting decrease coefficient. use the function to generate the results for alpha
Sure, here's an example implementation of the ewma function in Python:
import numpy as np
def ewma(data, alpha):
"""
Calculate the exponential weighted moving average of a given data array.
Args:
- data: a 1D numpy array containing the data points to be averaged.
- alpha: a float between 0 and 1 representing the degree of weighting decrease.
A higher value of alpha gives more weight to recent data points.
Returns:
- ewma: a 1D numpy array containing the exponentially weighted moving average of the input data.
"""
# Initialize variables
ewma = np.zeros_like(data)
ewma[0] = data[0]
for i in range(1, len(data)):
ewma[i] = alpha * data[i] + (1 - alpha) * ewma[i-1]
return ewma
To use this function, you can call it with your data array and the desired alpha value, like so:
data = np.array([1, 2, 3, 4, 5])
alpha = 0.5
result = ewma(data, alpha)
print(result)
This will output the exponential weighted moving average of the data array with the specified alpha value. You can change the value of alpha and the input data to generate different results.
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A tourist purchases a car in England and ships it home to the United States. The car stickers advertised that the car's fuel consumption was the rate of 40 miles per gallon on the open road.
The tourist does not realize that the U.K. gallon differs from the U.S. gallon:
1 U.K. gallon =4.546 090 0 litres
1 U.S. gallon =3.785 411.8 litres
For a trip of 750 miles (in the United states), how many gallons of fuel does the mistaken tourist believe she needs ?
The actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.
What is fuel ?Fuel is a material that is burned or used to produce energy. It can come in many forms, including gasoline, diesel, propane, wood, coal, natural gas, and oil. Fuel can be used to power engines to move vehicles, generate electricity, and heat homes and buildings. It is a necessity of modern life, as it is required to power many of the machines, appliances, and systems that make our lives easier. Without fuel, transportation, communication, and many other essential services would be impossible. Fuel is often divided into two categories, renewable and non-renewable.
The tourist mistakenly believes that she needs 18.75 gallons of fuel for a trip of 750 miles. This is calculated as follows:
750 miles/40 miles per gallon = 18.75 gallons
However, since the tourist is using a U.K. gallon, which is larger than a U.S. gallon, the actual amount of fuel needed is less. To do the conversion, we need to convert the 18.75 gallons to litres and then back to U.S. gallons:
18.75 U.K. gallons x 4.546090 litres/U.K. gallon = 85.22 litres
85.22 litres/3.785411.8 litres/U.S. gallon = 22.54 U.S. gallons
Therefore, the actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.
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An object has a constant acceleration a = 4 m/s². Its velocity is 1 m/s at t = 0, when it is at x = 7 m. How fast is it moving when it is at x = 8m? At what time is this?
The object is moving at a velocity of 5 m/s when it is at x = 8 m.
How to calculate?The velocity of an object with constant acceleration can be found using the equation:
v = v0 + at
where v0 is the initial velocity, a is the acceleration, and t is the time elapsed.
Given that the object has an acceleration of a = 4 m/s²
initial velocity of v0 = 1 m/s,
we can calculate the velocity at x = 8 m by solving for t and then substituting into the velocity equation:
x = x0 + v0t + 0.5at^2
x = 7 m + 1 m/s * t + 0.5 * 4 m/s² * t^2
x = 8 m
Expanding and solving for t, we find:
t = (8 - 7 - 1 * t) / (0.5 * 4 * t^2)
t = 1 s
So the object has been moving for 1 second, and its velocity at x = 8 m is given by:
v = v0 + at
v = 1 m/s + 4 m/s² * 1 s
v = 5 m/s
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A telecommunications tower is supported by three cables affixed to its top and ground. We can find the vertical force induced in the tower by the cables by a) considering the product to pairs of vectors and projecting a resultant force from the tower. b) Cartesian vector analysis to the coplanar forces, finding the resultant and direction cosine, and then resolving the resultant into its parallel and perpendicular components.c) applying Newton's second law of motion and the Pythagorean Theorem to the analysis. d) force resolution, the determination of force components to find the resultant vertical force on the tower. e) all of the above
The vertical force induced in the tower by the cables by:
e) all of the above. All of the methods listed (a, b, c, and d) can be used to find the vertical force induced in the tower by the cables, and each method provides a different approach to finding the solution. The choice of method will depend on the complexity of the problem and the level of mathematical sophistication required for the solution.
Vertical force inducedThe various methods listed (a, b, c, and d) all involve mathematical and physical principles that can be used to find the vertical force induced in the tower by the cables.
a) Product to pairs of vectors and projecting a resultant force from the tower: This method involves using vector dot products or cross products to find the projection of one vector onto another, which can then be used to find the magnitude and direction of the vertical force.
b) Cartesian vector analysis to the coplanar forces: This method involves finding the components of each cable force in a two-dimensional coordinate system, adding the components to find the resultant force, and then finding the direction cosine to determine the direction of the resultant force.
c) Applying Newton's second law of motion and the Pythagorean Theorem: This method involves using Newton's second law of motion (F = ma) to find the net force acting on the tower and then using the Pythagorean Theorem to find the magnitude and direction of the vertical force.
d) Force resolution: This method involves breaking down the cables' forces into their individual components, finding the net force in each direction, and then using vector addition to find the magnitude and direction of the vertical force.
Each method has its own advantages and disadvantages, and the choice of method will depend on the complexity of the problem, the level of mathematical sophistication required for the solution, and the desired level of accuracy.
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when a firm has transcended a production or selling orientation, and attempts to discover and satisfy its customer's needs and wants, the firm is blank .
When a firm has transcended a production or selling orientation, and attempts to discover and satisfy its customer's needs and wants, the firm is customer-oriented.
A customer-oriented firm places the needs and wants of its customers at the forefront of all its decision-making processes. This approach goes beyond merely producing and selling products, as it takes into account the entire customer experience.
The focus is not just on meeting customer needs, but on anticipating and exceeding them. This involves collecting and analyzing customer data, regularly gathering feedback, and continuously improving the customer experience.
A customer-oriented culture also permeates all levels of the organization, from top management to front-line employees. The result is increased customer loyalty, higher sales and profits, and a stronger brand reputation. Ultimately, a customer-oriented approach helps a firm to establish a long-term, sustainable competitive advantage.
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We once thought that the crisis facing the United States was simply a capitalist economic crisis.weakening national governance capacity internally and draining national soft power externally.
The thought is a significant issue facing by united states. In the capitalist economy, all the sectors are changing to private mode and labors facing competing issues.
What is capitalist economic crisis in US ?In capitalist democracies, there are impossibly high hurdles that prevent the government from opposing capitalism. Although the concept of "one person, one vote" gives the impression that everyone has an equal voice, the state is actually a system of institutions that we may influence by casting the proper votes.
Instead, it is wanted to demonstrate that capitalists wield excessive political power through both the market and the state, and that this power comes mainly from the productive assets they own.
The wealth of the wealthy, however, has been financialized during the past 40 years. Due to this, they now have more access to money markets to leave political areas. Even if this gives capitalists more leverage to evade expropriation demands, I'll conclude on a positive note.
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Answer the following questions using the Velocity vs Time graph.
1. What is the car doing a position
2. What is the car doing a position
3. What is the car doing a position
According to the Velocity vs Time graph:
at A: car is moving with increased velocity with time
at B: the car is stationary or at uniform velocity
at E: the car is slowing down or its velocity decreases with time.
What is velocity, exactly?
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
When an item is moving, its velocity is the rate at which it is changing position as seen from a certain point of view and as measured by a specific unit of time.
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Rocket observations show that dust particles in Earth's upper atmosphere are often electrically charged.a) Find the distance separating two dust particles if each has a charge of +e and the Coulomb force between them has magnitude 1.00x10−14−14N.b) Calculate the mass of one of the dust particles if this Coulomb force would accelerate it at 4.50x1088m/s22. (In the upper atmosphere, effects from other nearby charges typically result in a small net force and acceleration.)
a. The distance separating two dust particles if each has a charge of +e and the Coulomb force is 2.5 × 10⁻³ m
b. The mass of one of the dust particles if this Coulomb force would accelerate it is 2.22 x 10⁻²³ kg.
What is force?
Force is a physical quantity that represents the interaction between two objects that cause changes in motion of the objects. Force can be defined as the push or pull effect on an object. It is a vector quantity, which means it has both magnitude and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
a) The force between two charged particles can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:
F = k × q1 × q2 / r²
where k is the Coulomb constant (8.99 x 10⁹ N m²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
Given that the force between the two particles is 1.00 x 10⁻¹⁴ N and each particle has a charge of +e, we can rearrange the equation to solve for r:
r = [tex]$ \sqrt{\frac{k \times q_1 \times q_2 }{ F} }[/tex]
= [tex]$ \mathrm{ \sqrt{\frac{8.99 \times 10^2 N m^2/C^2 \times 2e^2 }{ 1.00 \times 10^{-14} N} } }[/tex]
= 2.5 × 10⁻³ m
b) To calculate the mass of one of the dust particles, we can use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
F = m × a
where F is the force, m is the mass, and a is the acceleration. Given that the acceleration of the particle is 4.50 x 10⁸ m/s², we can rearrange the equation to solve for m:
m = F / a
[tex]$ \mathrm{= \frac{1.00 \times 10^{-14} N}{ 4.50 \times 10^8 m/s^2} }[/tex]
= 2.22 x 10⁻²³ kg
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Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct? (Please answer quickly, it's due in 5 hours)
No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.
No, the force applied to the bowling ball should be a strong force.
Yes, the force applied to the bowling ball affects the motion of the ball.
Yes, the ball will travel a longer distance when a weak force is applied.
particle a of charge 3.24 x 10-4 c is at the origin, particle b of charge -5.64 x 10-4 c is at (4.00 m, 0), and particle c of charge 1.01 x 10-4 c is at (0, 3.00 m). we wish to find the net electric force on c.(a) What is the x component of the electric force exerted by A on C?(b) What is the y component of the force exerted by A on C?(c) Find the magnitude of the force exerted by B on C.(d) Calculate the x component of the force exerted by B on C.(e) Calculate the y component of the force exerted by B on C.(f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C.(g) Similarly, find the y component of the resultant force vector acting on C.(h) Find the magnitu
(a) The x component of the electric force exerted by A on C is 2.29 x 10⁻⁷ N.
(b) The y component of the force exerted by A on C is 1.72 x 10⁻⁷ N.
(c) The magnitude of the force exerted by B on C is -3.96 x 10⁻⁷ N.
(d) The x component of the force exerted by B on C is -3.17 x 10⁻⁷ N.
(e) The y component of the force exerted by B on C is -2.38 x 10⁻⁷ N.
(f) The sum of two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C is -0.88 x 10⁻⁷ N.
(g) The y component of the resultant force vector acting on C is -0.66 x 10⁻⁷ N.
(h) The magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.
Net Electric ForceThe electric force exerted by a particle on another particle can be calculated using Coulomb's Law, which states that the force between two point charges is given by:
F = k * q1 * q2 / r²
where k is the Coulomb constant (8.99 x 10⁹ Nm²/C²), q1 and q2 are the magnitudes of the charges, and r is the distance between the two particles.
(a) The x component of the electric force exerted by particle A on C can be found by considering the x direction only. The distance between A and C can be found using the Pythagorean theorem:
r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m
The electric force in the x direction can then be found as follows:
F_x = k * q1 * q3 / r² * cos(θ)
where q1 is the charge of particle A (3.24 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:
θ = arctan(3.00 m / 4.00 m) = 0.93 radians
cos(θ) = cos(0.93) = 0.80
F_x = k * q1 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.80 = 2.29 x 10⁻⁷ N
(b) The y component of the force exerted by A on C can be found in a similar manner:
F_y = k * q1 * q3 / r² * sin(θ)
sin(θ) = sin(0.93) = 0.60
F_y = k * q1 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = 1.72 x 10⁻⁷ N
(c) The magnitude of the force exerted by B on C can be found using Coulomb's Law:
F = k * q2 * q3 / r²
where q2 is the charge of particle B (-5.64 x 10⁻⁴ C) and r is the distance between the two particles:
r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m
F = k * q2 * q3 / r² = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)²= -3.96 x 10⁻⁷ N
(d) The x component of the force exerted by B on C can be found by considering the x direction only:
F_x = k * q2 * q3 / r² * cos(θ)
where q2 is the charge of particle B (-5.64 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:
θ = arctan(3.00 m / 4.00 m) = 0.93 radians
cos(θ) = cos(0.93) = 0.80
F_x = k * q2 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴C) / (5.00 m)² * 0.80 = -3.17 x 10⁻⁷ N
(e) The y component of the force exerted by B on C can be found in a similar manner:
F_y = k * q2 * q3 / r² * sin(θ)
sin(θ) = sin(0.93) = 0.60
F_y = k * q2 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = -2.38 x 10⁻⁷ N
(f) The x component of the resultant force can be found by summing the x components from parts (a) and (d):
F_x_resultant = F_x(A on C) + F_x(B on C) = 2.29 x 10⁻⁷ N + (-3.17 x 10⁻⁷ N) = -0.88 x 10⁻⁷ N
(g) The y component of the resultant force can be found by summing the y components from parts (b) and (e):
F_y_resultant = F_y(A on C) + F_y(B on C) = 1.72 x 10⁻⁷ N + (-2.38 x 10⁻⁷ N) = -0.66 x 10⁻⁷ N
(h) The magnitude of the resultant force can be found using the Pythagorean theorem:
F_resultant = sqrt(F_x_resultant² + F_y_resultant²) = sqrt((-0.88 x 10⁻⁷ N)² + (-0.66 x 10⁻⁷ N)²) = 1.01 x 10⁻⁷ N
So the magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.
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aball of mass 2kg has a diameter of 50cm falls in the pool. calculate its buoyant force and volume of water displaced
Answer:
Answer: Buoyant force = 19.6N. Water displaced = 0.065m³
Explanation:
The question says:
A ball of mass 2kg had a diameter of 50cm falls into a pool.
Calculate its buoyant force and volume of the water displaced.
According to Archimedes' principle, When a body is immersed fully or partially in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it.
Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
The football Felipe throws to Lilah will go at a speed of 23 km/h.
What is the relative velocity?The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's close location changes in reference to another object over time.
Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
Then the velocity of the ball is given as,
v = 15 + 8
v = 23 km/h
The velocity of the ball will be 23 km / h.
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A 5.2 "kilo" bag of sugar is on a counter. How much work is required to put the bag on a shelf a distance of 0.37 m above the counter?
Answer: approximately 18.854 Joules of work is required to put the bag of sugar on the shelf. where Force is the weight of the bag of sugar and Distance is the vertical distance lifted.
Explanation:
Calculate the wavelength and the energy in joules associated with an NMR signal at 250 MHz. The wavelength of the signal is 1.2m and the energy is 1.67 x 10-25J?
The wavelength of an NMR signal at 250 MHz is 1.2m and its energy is 1.67 x 10⁻²⁵ J.
Nuclear Magnetic Resonance (NMR) spectroscopy is a widely used technique in physics and chemistry for determining the chemical and physical properties of substances. The frequency of an NMR signal is related to the magnetic field strength and the magnetic properties of the nuclei being studied.
The wavelength of an NMR signal can be calculated using the equation:
λ = c/v
where c is the speed of light (3 x 10⁸ m/s) and v is the frequency of the signal (250 MHz).
λ = c / v
λ = 3 x 10⁸ m/s / (250 x 10⁶ Hz)
λ = 1.2 m
The energy of an NMR signal can be calculated using the equation:
E = hv
where h is Planck's constant (6.63 x 10⁻³⁴ J s) and v is the frequency of the signal.
E = h × v
E = 6.63 x 10⁻³⁴ J s × (250 x 10⁶ Hz)
E = 1.67 x 10⁻²⁵ J
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a body of mass 10kg on a smooth inclined plane is connected over a smooth pulley to a mass of 15kg . the acceleration of the system is? please help ASAP will give branliest
The acceleration of the system is (m₁g sinθ + m₂g) / (m₁ + m₂) / (m₁ + m₂)
What is the acceleration of the system?
The acceleration of the system can be calculated using the equation of motion and considering the forces acting on each mass.
The equation of motion for the 10 kg mass is:
W₁ - T = m₁a
The equation of motion for the 15 kg mass is:
W₂ + T = m₂ a
Where;
m₁ and m₂ are the masses of the 10 kg and 15 kg masses respectivelya is the acceleration of the system.Solving for the tension T and substituting the values for W₁ and W₂, we get:
T = (m₁g sinθ + m₂g) / (m₁ + m₂)
And substituting T back into either equation, we get:
a = (m₁g sinθ + m₂g) / (m₁ + m₂) / (m₁ + m₂)
where;
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determine the direction of the resultant force, measured counterclockwise from the positive x axis. express your answer using three significant figures.
Resultant force direction = 11.08 degrees counter-clockwise from the positive x-axis.
In order to address this issue, we must first divide these forces into their corresponding x and y components, which we must then combine to determine the final force.
Given the magnitude of force (F1) = 32kN
The angle of direction (θ1) = 30°
F1x = -32k x cos(30°) = -27.7kN
F1y = -32 x sin(30°) = -16kN
Given a triangle, let cos(θ) = 5/13 = 0.99 then θ = 67.3°
The magnitude of force F2 = 26kN
The angle of direction (θ2) = 0.99°
F2x = -26 x cos(67.3°) = 10.03kN
F2y = 26 x sin(67.3°) = 23.9kN
Frx = F1x + F2x = -37.73kN
Fry = F1y + F2y = 7.9kN
Let the resultant force = Fr then,
Fr^2 = Frx^2 + Fry^2
Fr^2 = (-37.73)^2 + (7.9)^2
Fr = √1423.55+62.41 = √1485.96 = 38.5kN
Hence the resultant force = 38.5kN
θ = tan^-1(Fry/Frx) = tan^-1(7.9/-37.73) = -11.08°
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what will happen when O2 increases in the atmosphere
Answer:
Explanation:
when o2 increases, the co2 percentage drops. plants will die. because they needed CO2 for respiration. specially carbon cycle fell into verge.
A 5.7 diameter horizontal pipe gradually narrows to 3.6 cm. The the water flows through this pipe at certain rate, the gauge pressure in these two sections is 32.5 kPa and 24.0 kPa, respectively. What is the volume of rate of flow?
The volume rate of flow is approximately 102.3 cm if a 5.7 diameter horizontal pipe gradually narrows to 3.6 cm.
To determine the volume rate of flow in a pipe, we can use the equation for the continuity of fluid flow:
[tex]A1 * v1 = A2 * v2[/tex]
where A1 and A2 are the cross-sectional areas of the two sections of the pipe and v1 and v2 are the velocities of the fluid in each section.
We can first convert the diameter measurements to cross-sectional areas:
[tex]A1 = (π / 4) * (5.7 cm)^2 = 40.2 cm^2A2 = (π / 4) * (3.6 cm)^2 = 10.1 cm^2[/tex]
Next, we can use the formula for the velocity of a fluid in a pipe:
[tex]v = (2 * ΔP / ρ)^0.5[/tex]
where ΔP is the pressure difference across the pipe, and ρ is the density of the fluid.
Using this formula, we can find the velocities in each section of the pipe:
[tex]v1 = (2 * (32.5 kPa - 0) / 1000 kg/m^3)^0.5 = 2.53 m/sv2 = (2 * (24.0 kPa - 0) / 1000 kg/m^3)^0.5 = 1.94 m/s[/tex]
Finally, using the continuity equation, we can find the volume rate of flow:
[tex]V = A1 * v1 = A2 * v2V = 40.2 cm^2 * 2.53 m/s = 10.1 cm^2 * 1.94 m/sV = 102.3 cm^3/s[/tex]
So, the volume rate of flow is approximately 102.3 cm
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while standing at the edge of a building's roof, chad throws an egg upward with an initial speed of 8.00 m/s. the egg subsequently smashes on the ground, 12.0 m beneath the height from which chad threw it. ignore the effects of air resistance.At what speed does the egg pass the point from which it was thrown?v= _____m/sHow much time t does the egg spend in the air? t=___sWhat total distance d does the egg travel? d=___m
The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. The equations apply in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = heightWhile standing at the edge of a building's roof, Chad throws an egg upward.
Initial speed, v₀ = 8.00 m/sIt finally falls 12.0 beneath the height at which Chad threw it. No air resistance.Find
The speed of the egg when passes the point which it was thrown!The time spent by the egg in the air!The total distance the egg travels!See the illustration picture in the attachment!
The distance between the egg when it was thrown and the highest point it could reach is
v₁² = v₀² - 2gh₁
0 = 8² - 2(10)h₁
64 = 20h₁
h₁ = 3.2 m
The egg then moves downward. The speed when it passes the initial point is
v₂² = v₁² + 2gh₁
v₂² = 0 + 2(10)(3.2)
v₂² = 64
v₂ = 8 m/s
The speed is the same with the initial speed.
The time spent by the egg from initial point to the highest point is
v₁ = v₀ - gt₁
0 = 8 - 10t₁
8 = 10t₁
t₁ = 0.8 s
The time spent from the highest point to the ground is
h = v₀t + ½ gt²
(3.2 + 12) = 0 + ½ (10)t₂²
15.2 = 5t₂²
t₂² = 3.04
t₂ = 1.74 s
The total time spent in the air will be
t = t₁ + t₂
t = 0.8 + 1.74
t = 2.54 s
The total distance traveled by the egg is
= 2(3.2) + 12
= 6.4 + 12
= 18.4 m
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A worker pushes horizontally on a large crate with a force of 235 N, and the crate is moved 3.3 m. How much work was done?
Answer:
Explanation:
The work done by a force on an object is equal to the product of the magnitude of the force, the distance moved by the object in the direction of the force, and the cosine of the angle between the force and the direction of motion.
In this case, the worker pushes the crate horizontally, so the force and the direction of motion are in the same direction. Therefore, the angle between them is 0 degrees, and the cosine of the angle is 1.
The work done by the worker on the crate is then:
work = force x distance x cos(angle)
= 235 N x 3.3 m x cos(0)
= 773.5 J
So the work done by the worker is 773.5 Joules (J).
Hello,
Answer:
The work done by a force on an object is given by:
Work = Force x Distance x cos(theta)
where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and displacement vectors. Since the worker is pushing horizontally on the crate, the angle between the force and displacement vectors is zero degrees, and cos(0) = 1.
So, the work done by the worker is:
Work = Force x Distance x cos(theta)
Work = 235 N x 3.3 m x cos(0)
Work = 773.5 J
Therefore, the work done by the worker on the crate is 773.5 J.
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