An object has a constant acceleration a = 4 m/s². Its velocity is 1 m/s at t = 0, when it is at x = 7 m. How fast is it moving when it is at x = 8m? At what time is this?
​

The condition for the photodynamic effect to occur is that the pigment must have the absorption spectrum is the same as the absorption spectrum of the substrate.

In order to induce cell death  (phototoxicity), photodynamic treatment (PDT), a type of phototherapy, uses light, a photosensitizing agent, and molecular oxygen.

PDT is frequently used to treat acne. It is clinically used to treat a variety of medical problems, such as wet age-related macular degeneration, psoriasis, and atherosclerosis. It has also showed some promise in the treatment of viral diseases like herpes. Malignant malignancies of the head and neck, bladder, lung, and specific skin types are also treated by it.

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Answer:

20Ω

Explanation:

we are here given that,

From Ohm's law ,

[tex]\implies V = iR \\[/tex]

where,

on substituting the respective values, we have,

[tex]\implies 8V = 0.4A \times R\\[/tex]

[tex]\implies R =\dfrac{8V}{0.4A} \\[/tex]

[tex]\implies \underline{\underline{ R = 20\Omega}}\\[/tex]

and we are done!

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

If we add a new residence in the circuit in parallel to the bulb of same resistance, the resultant resistance will get half the value of initial resistance [ when only bulb was connected in the circuit ], the current will increase as resultant resistance is half the original. and same current will flow in both the parallel wires.

So, by above information :

A.) Current would increase ? [ Yes ], As by ohms law, V = IR

and, if R is halfed, to maintain the same potential difference, current in the circuit will increase.

B.) Total voltage will decrease ? [ No ]... voltage will remain constant

C.) The current would stay the same ? [ yes ], it would increase...

D.) Total resistance would remain same ? [ No ], it will decrease...

The magnitude of acceleration of the car during the entire test is 4.83 m/s^2.

To calculate the magnitude of acceleration of the car before the collision, we can use the formula for uniform acceleration:

a = (v_f - v_i) / t

where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time.

v_i = 0 (the car is initially at rest), v_f = 145 km/h = 40 m/s, t = 8.28 s

a = (40 - 0) / 8.28 = 4.83 m/s^2

To calculate the magnitude of acceleration of the car during the collision, we can use the formula for average acceleration:

a = (v_f - v_i) / (2t)

where v_f is the final velocity after the collision (82 km/h = 22.8 m/s), v_i is the initial velocity before the collision (145 km/h = 40 m/s), and t is the time of the collision (0.815 s).

a = (22.8 - 40) / (2 * 0.815) = -19.86 m/s^2

Finally, to find the magnitude of acceleration of the car during the entire test, we have to integrate the acceleration over the time interval from t = 0 to t = 8.28 s. The area under the acceleration versus time graph represents the velocity of the car. By finding the velocity at t = 8.28 s, we can find the acceleration required to get from rest to that velocity.

v = a * t = 4.83 * 8.28 = 40 m/s

a = v / t = 40 / 8.28 = 4.83 m/s^2

So the magnitude of acceleration of the car during the entire test is 4.83 m/s^2.

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Answer:

A) 3.0 ohms

Explanation:

R=V/I=12V/4.0A=3.0 ohms

The correct answer is (a): satellite 1's acceleration is half as much as satellite 2's.

This is due to the fact that the acceleration of two satellites in a circular orbit depends on their masses and orbital periods. Satellite 2 accelerates more quickly because it has twice as much mass as satellite 1. As a result, satellite 1 accelerates at a rate that is half that of satellite 2.

This results in a divergence in the orbits of the two spacecraft since satellite 1's speed will rise more slowly than satellite 2's. Over time, this difference will become more obvious, with satellite 1's orbit straying from a circular form more so than satellite 2's.

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The distance ratio r2/r1 is approximately 0.605. 

The point charge is given by

E = k*q/r^2

where E is the electric field, k is the Coulomb constant ([tex]k = 8.99 * 10^9 Nm^2/C^2[/tex]), q is the charge of the point charge, and r is the distance between the point charge and the location. The electric field is measured.

Using this equation, we can find the distance ratio r2/r1.

[tex]E1 = k*q/r1^2\\E2 = k*q/r2^2[/tex]

Dividing these equations gives:

[tex]E2/E1 = (kq/r2^2) / (kq/r1^2)\\E2/E1 = (r1/r2)^2[/tex]

Solving for r2/r1 gives:

r2/r1 = √(E2/E1)

Inserting the given value will result in:

r2/r1 = √(145n/C ÷ 397n/C)

r2/r1 = √(0.365)

r2/r1 = 0.605

Therefore, the distance ratio r2/r1 is approximately 0.605. 

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Answer:produces red and white blood cells

Explanation: the bone marrow helps with the blood but cannot produce red and white blood cells

Answer:

"prevents movement of limbs and digits" is NOT a function of the skeletal system.

The arrow pointing downward is gravitational force, F(g), The left arrow is the applied force, F(t), The right arrow is frictional force, F(f) and the arrow pointing upward is the net force, F(n).

A force is a push or pull upon an object resulting from the object's interaction with another object. Forces can cause an object to accelerate or change its direction of motion.

Forces can be described by their magnitude and direction. In physics, forces can be caused by many interactions, including gravity, electromagnetic forces, and the strong and weak nuclear forces.

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Monkey Mo is in a static equilibrium because of the balance of all these forces acting on him.

The interaction between two things or the pressure applied to alter an object's motion is described by the physical quantity known as force. An object can change direction, accelerate, decelerate, or continue in motion as a result of force.

The forces at work on Monkey Mo when he is hung at rest while grasping a rope in one hand and the side of his cage in the other are as follows:

Gravitational force, which is vertically downward operating force of attraction between Monkey Mo and the Earth.

The tension force, which acts upward along the length of the rope, is the force the rope applies to Monkey Mo.

Normal force, which force balances the gravitational pull by operating perpendicular to the surface of the cage and being applied to Monkey Mo by the side of the cage.

Frictional force prevents Monkey Mo from falling out of the cage by acting between his hand and the side of the cage.

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As the object is raised, the gravitational potential energy of the system grows. When you drop something, the potential energy of the object is transformed into kinetic energy, which is the energy of the moving object, when it strikes the ground.

What is kinetic and potential energy?

Potential energy is the energy stored in an object or system due to its position or arrangement of elements. It is unaffected by the environment outside the installation or system, such as air or altitude. Conversely, kinetic energy refers to the energy of moving particles in a system or object.

An object's kinetic energy, unlike potential energy, relates to other stationary and moving objects in its immediate vicinity. Thus, the lifted object is in kinetic motion when released.

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The correct option for the problem is option D. they reach the bottom together. Their gravitational potential energy is converted to kinetic energy, total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.

Here sphere and cylinder both have equal mass and equal radius and it is given that both are simultaneously released also.

When two objects with equal mass and equal radius like these two, the time taken for them to roll down and reach the bottom will be their gravitational potential energy.

Here what happens is that their gravitational potential energy is converted to kinetic-energy and both of them rolling down the incline.

Total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.

Inertia and rotational energy are also there in this context for their motion but they do not take part any role for the time taken to slide down.

Instead, they affect the stability and trajectory of the objects as they roll down the incline.

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The change in the velocity of the planet is 18.55 m/s.

The gravitational force between the star and the planet, is calculated by applying Newton's third law of motion.

F = Gm₁m₂ /r²

where;

The distance between the start and the planet is calculated as;

r = √ ( 8 x 10¹² - 5 x 10¹² )² + ( 5 x 10¹² - 8 x 10¹² )²

r = 4.24 x 10¹² m

F = ( 6.67 x 10⁻¹¹ x 5 x 10³⁰ x 6 x 10²⁴ ) / ( 4.24 x 10¹² )²

F = 1.11 x 10²⁰ N

The acceleration of the planet is calculated as;

a = F / m₂

a = ( 1.11 x 10²⁰ N ) / ( 6 x 10²⁴ kg )

a = 1.85 x 10⁻⁵ m/s²

The change in the velocity of the planet;

Δv = at

Δv = ( 1.85 x 10⁻⁵ x 1 x 10⁶ s )

Δv = 18.55 m/s

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If a constant force of 85 lb is used to pull a cart a distance of 220 ft. Then the work done W is 18700 ft-lb.

Work is the amount of energy transferred when a force is applied over a distance. In this case, a constant force of 85 lb is used to pull a cart a distance of 220 ft. To find the work done, we can use the formula W = Fd, where F is the force and d is the distance. Plugging in the values, we get W = 85 x 220 = 18700 ft-lb. This is the amount of work done by the force to move the cart a distance of 220 ft.

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For part 4 after solving the equation the the rotation rate is 0.74 rev/s.

What is rotation rate?

Rotation rate is the angular velocity of a body or object in a circular motion. It is typically measured in rotations per minute (RPM) and is the number of times a full rotation is completed in one minute.

Part 1 of 4 - Conceptualize: Look carefully at the figure and imagine you are the astronaut sitting in the seat at the far right. As the centrifuge rotates, you are experiencing an acceleration toward the center of the device.

The faster the centrifuge spins, the larger is that acceleration. The problem is asking for a rotation rate, measured in revolutions per second. Because the period of circular motion is the number of seconds per revolution, we see that the rotation rate will be the inverse of the period.

Part 2 of 4 - Calculate: To calculate the rotation rate, we need to find the period of the motion. The period of circular motion is given by:

T = 2π√(L/2a)

Where L is the length of the centrifuge and a is the centripetal acceleration.

Part 3 of 4 - Calculate: In this problem, L = 59.0 ft, and a = 20.0g. Since gravitational acceleration is equal to 9.8 m/s2, we need to convert the acceleration from g to m/s2. We can do this by multiplying the acceleration by 9.8. Thus, a = 20.0g × 9.8 m/s2 = 196.0 m/s2. Substituting the numerical values into the equation, we get:

T = 2π√(59.0 ft/2 × 196.0 m/s2) = 2π√(29.5 ft × 9.8 m/s2) = 2π√(291.1 m2/s2) = 2π√(291.1) s = 5.15 s

Part 4 of 4 - Calculate: Since the period of circular motion is the number of seconds per revolution, the rotation rate is equal to the inverse of the period. Thus, the rotation rate is:

Rotation rate = 1/T = 1/5.15 s = 0.74 rev/s

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a. The mass is doubled = 4 s

b. The string length is doubled= 5.66 s

c. The string length is halved=2.83 s

d.The amplitude is doubled= 4 s

(a) The period of the pendulum is independent of the mass, therefore, the period when the mass is doubled is

T= To =4.00s

(b) Let I be the new length of the pendulum and Lo be the original length of the pendulum. The period of the pendulum if the string length is doubled is found by substituting 2Lo for L in Equation (*):

2π=√2Lo/g

√2=(2π(√Lo/g)

where the term in parenthesis is the original period of the pendulum To:

T=√√2To

T=√2.(4seconds)

T=5.66 s

c) The period of the pendulum if the string length is halved is found by substituting Lo/2 for L in Equation (*):

T=2π(√Lo/2 :g)

T= 1/√2 (2π√(Lo/g)

where the term in parenthesis is the original period of the pendulum To:

T =To /√2

T=4.00s/√2

T=2.83 s

d.) The period of the pendulum is independent of the amplitude, therefore, the period when the amplitude is halved is

T= To 4.00s

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Answer:

9.22 m=s

Explanation:

m=s×v

jskkdkdjdhbdnkksksijsj

jdjkdo

The first and third statements for the positive charge which moves in the electric field are correct.

When placed in an electric field, the positive charge typically flows in the direction of the electric field. The work done by the electric field in this situation is positive because both the electric field vector and the displacement vector point in the same direction and there is no angle between them.

The potential will also decrease in the direction of the electric field. This is because the work done in the order of the electric field is called the potential. electric potential is the amount of work required to move a unit charge from a reference point against an electric field to a particular point 

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A) Motion 1: The car starts at rest at the stop sign, at x=0, and then accelerates in the east (positive x) direction.

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. Acceleration is usually measured in meters per second squared (m/s2). It is a fundamental concept in physics, and is used to describe the motion of objects in a variety of contexts, from astronomy to everyday life. Acceleration can result from a force, from a change in direction, or from a change in speed.

The correct position vs time graph for this motion is a line with a positive slope, starting at the origin and going up to the right. This shows that the car is accelerating in the positive x direction and is increasing its position over time.

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0.0018 moles of air must be pumped into the tire to increase its pressure to 272 kPa.

We can use the ideal gas law to find the number of moles of air in the tire.

The ideal gas law states that PV = nRT,

where

P is pressure,

V is volume,

n is the number of moles of gas,

R is the ideal gas constant, and

T is temperature.

The initial number of moles of air in the tire:

n1 = (P1 * V) / (R * T)

= (217 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)

= 0.00625 moles

Next, we can find the final number of moles of air in the tire, assuming the temperature and volume remain constant:

n2 = (P2 * V) / (R * T)

= (272 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)

= 0.00805 moles

Finally, we can find the difference between the final and initial number of moles, which represents the number of moles of air that must be pumped into the tire:

n2 - n1 = 0.00805 moles - 0.00625 moles = 0.0018 moles.

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The gravitational force put by the planet earth on a unit mass at a distance from the center of the planet is "the strength of the gravitational field at that location".

It is directly proportional to the mass of the planet and inversely proportional to the square of the distance between the unit mass and the center of the planet. The formula for gravitational force is

      F = G * (m1 * m2) / r^2,

where

The strength of the gravitational field decreases with increasing distance from the planet.

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The definition of horsepower is . A. the amount of force used to cover the length of an English associated activities track B. the practical benefit of utilizing a standard horse

Who developed the horsepower?

James Watt, an engineer, is credited with creating the term horsepower. According to legend, Watt wanted to find a method to describe the power that one of those animals could produce while he was dealing with ponies in a coal mine. An engine is connected to a dynamometer in order to determine its horsepower.

What is the power of a horse?

The most prevalent unit of power is horsepower , which measures how quickly work is completed. According to the British Imperial Units, a horsepower is equivalent to 33,000 walking of work per minute, or the force required to elevate a mass of 3 million pounds one foot in a minute.

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The net gravitational force is terms of L and h and is equal to[tex]f_{net} = G m_3*(m_2 / ((L - 1)^2 + h^2) + m_1 / (L^2 + h^2))[/tex]

(a) The gravitational force on the Moon due to the Earth can be calculated using the equation:

f_gravity = G * (m2 * m3) / d^2

where d is the distance between the Earth and the Moon. The distance between the Earth and the Moon can be calculated using the Pythagorean theorem:

d = sqrt((L - 1)^2 + h^2)

Plugging in the values, we get:

[tex]f_{gravity} = G * (m_{Earth} * m_{Moon}) / d^2 = G * (m_{2} * m_{3}) / d^2 \\\\= G * (m_{2} * m_{3}) / (sqrt((L - 1)^2 + h^2))^2[/tex]

(b) The gravitational force on the Moon due to the Sun can be calculated using the same equation as above:

f_gravity = G * (m1 * m3) / d^2

where d is the distance between the Sun and the Moon. The distance between the Sun and the Moon can be calculated using the Pythagorean theorem:

d = sqrt(L^2 + h^2)

Plugging in the values, we get:

[tex]f_{gravity} = G * (m_{Sun} * m_{Moon}) / d^2 \\= G * (m_{1} * m_{3}) / d^2 = G * (m_{1} * m_{3}) / (sqrt(L^2 + h^2))^2[/tex]

(c) The net gravitational force on the Moon is the sum of the gravitational forces due to the Earth and the Sun:

f_net = f_gravity_Earth + f_gravity_Sun

Substituting the values of f_gravity_Earth and f_gravity_Sun, we get:

[tex]f_{net} = G * (m_2 * m_3) / (sqrt((L - 1)^2 + h^2))^2 + G * (m_1 * m_3) / (sqrt(L^2 + h^2))^2[/tex]

[tex]f_{net} = G * (m_2 * m_3) / ((L - 1)^2 + h^2) + G * (m_1 * m_3) / (L^2 + h^2)[/tex]

[tex]f_{net} = G m_3*(m_2 / ((L - 1)^2 + h^2) + m_1 / (L^2 + h^2))[/tex]

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It is discovered that the object, which weighs 60g and has a volume of 50cm³, has a density of 1.2 g/cm³.

Under pressure, a liquid becomes denser. In other words, as an excessive force is given to a liquid, volume decreases and density increases, and as molecules get closer to one another, interparticle spacing decreases.

A substance or object's mass is a measure of how much matter it contains. Volume (the amount of space an object or substance occupies) to mass (the amount of material present) ratio is known as density (its mass).

According to the given information:

Mass= 60g

Volume = 50cm³

Density = mass / volume

        => 60/50 =>1.2 g/cm³

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The answer is (E) I, II, and III. When a satellite of mass m moves in a circular orbit of radius r at a constant speed v, all three statements are true.

i. The net force on the satellite is equal to mv^2 / r and is directed toward the center of the orbit. This force is known as the centripetal force, and it keeps the satellite moving in a circular path.

ii. The net work done on the satellite by gravity in one revolution is zero. Work is defined as the dot product of force and displacement, and the displacement of the satellite in a circular path is zero, so the net work done on it is also zero.

iii. The angular momentum of the satellite is a constant. Angular momentum is a measure of an object's rotational motion and is conserved if there are no external torques acting on the system. In this case, the satellite is in a stable orbit and there are no external torques acting on it, so its angular momentum is conserved and remains constant.

Therefore, all three statements (I, II, and III) must be true.

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Answer:

The soccer ball would keep traveling until it hit something else.

Explanation:

Friction acts as a force that opposes motion and slows objects down. When friction is absent, there is no force slowing the soccer ball down. So, without friction, the soccer ball would continue to move in a straight line at a constant velocity (assuming no other forces are acting on the ball) until it encounters an obstacle such as a wall or the ground, at which point it would stop.

The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.

Electromagnetic radiation is a form of energy that consists of waves of electric and magnetic fields, travelling through the air or other substances at the speed of light. These waves are created when an electric charge is accelerated and can be generated from a variety of sources, such as a light bulb, the sun, a microwave oven, or a radio transmitter.

The frequency (f) of electromagnetic radiation is calculated using the equation:
f = c/λ
where c is the speed of light (3.00 x 10⁸ m/s) and λ is the wavelength of the radiation (536.0 nm).
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (536.0 nm)
First, we need to convert the wavelength from nanometers (nm) to meters (m). We can do this by dividing 536.0 nm by 1,000,000 to get 0.000536 m.
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (0.000536 m)
f = 5.6 x 10¹¹ Hz
The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.

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the girl's velocity after they push off is 0.816 m/s.

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

The momentum of the boy after he pushes off is given by m_boy * v_boy = -747 N * 0.540 m/s = -405.08 N * m/s.

The momentum of the girl after she pushes off is denoted as   m_girl * v_girl, where m_girl is the mass of the girl and v_girl is her velocity.

The principle of conservation of momentum requires that the total momentum of the two-person system before and after the push off must be the same, hence we have:

m_boy * v_boy + m_girl * v_girl = 0

Substituting in the values for m_boy and v_boy, we find:

-405.08 N * m/s + m_girl * v_girl = 0

Solving for v_girl, we find:

v_girl = 405.08 N * m/s / m_girl = 405.08 N * m/s / 497 N = 0.816 m/s.

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The Earth's motion is unrelated to your motion, so the wall doesn't slam into you at 30 km/s.

Motion is the change in an object's location with regard to its surroundings over a specific amount of time.

While the earth moves relative to the sun at a speed of around 30 km/s, this velocity has no bearing on how things move on the surface of the planet. Because the motion of things on the surface of the earth is governed by the gravity of the earth rather than its velocity relative to the sun, when you jump upward in front of a wall, the wall does not slam into you at a speed of 30 km/s.

The uniform gravitational field produced by the earth's gravity causes things on its surface to accelerate steadily in the direction of the planet's center. Your muscles generate an upward push that causes you to jump upward, leaving the ground.

Similar gravitational effects are also felt by the wall, which maintains its equilibrium with respect to the surface of the earth. Since no outside force is acting on the wall to cause it to shift position when you jump upward, the wall does not move towards you.

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