An elements had three isotopes, determine the average atomic mass and
element.
1x - percent abundance = 80%, mass = 127
2x - percent abundance = 17%, mass = 126
3x - percent abundance = 3% , mass = 128

Answer: Ions are formed by the addition of electrons to, or the removal of electrons from,

Explanation:

Answer:What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution? 903 mL What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

Explanation:

Answer:

Deposition

Explanation:

Deposition is the phase transition in which gas transforms into solid without passing through the liquid phase. Deposition is a thermodynamic process. The reverse of deposition is sublimation and hence sometimes deposition is called desublimation.

Answer:

B. water displacement is used "graduated cylinder is filled with water (100 mL) and the object is then put inside. ... If the new water level is (120 mL) we now know that the object has a volume of 20 mL."

Explanation:

Answer:

I think it would be b.water displacement

Answer:

the answer in simplest form is A) N2H

Answer: A. The s orbital is lower in energy than the p orbital

Explanation: Just did test

The S-Orbital fill before the p-orbital Because, The s-orbital is lower in energy than the p-orbital. Hence, Option (A) is correct.

The aufbau principle, from the German Aufbauprinzip, also called the aufbau rule, states that in the ground state of an atom or ion, electrons fill subshells of the lowest available energy, then they fill subshells of higher energy.

For example, the S subshell is filled before the P subshell is occupied.

Therefore, The S-Orbital fill before the p-orbital Because, The s-orbital is lower in energy than the p-orbital. Hence, Option (A) is correct.

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Answer:

hydrochloride acid

Explanation:

hope this helps :D

Answer:

214.77 g/mol

Explanation:

Tin(II) sulfate

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Tin(II) sulfate

Tin(II) sulfate crystallizes in an heavily distorted barium sulfrate structure.

Unit cell of tin(II) sulfate.

Names

Other names

Stannous sulfate

Identifiers

CAS Number  

7488-55-3 ☑

3D model (JSmol)  

Interactive image

ChemSpider  

21106484 ☑

ECHA InfoCard 100.028.457 Edit this at Wikidata

EC Number  

231-302-2

PubChem CID  

62643

UNII  

0MFE10J96E ☑

CompTox Dashboard (EPA)  

DTXSID20884389 Edit this at Wikidata

InChI[show]

SMILES[show]

Properties

Chemical formula SnSO4

Molar mass 214.773 g/mol

Appearance white-yellowish crystalline solid

deliquescent

Density 5.15 g/cm3

Melting point 378 °C (712 °F; 651 K)

Boiling point decomposes to SnO2 and SO2

Solubility in water 33 g/100 mL (25 °C)

Structure[1]

Crystal structure Primitive orthorhombic

Space group Pnma, No. 62

Lattice constant  

a = 8.80 Å, b = 5.32 Å, c = 7.12 Å[2]

Hazards

NFPA 704 (fire diamond)  

NFPA 704 four-colored diamond

010

Flash point Non-flammable

Lethal dose or concentration (LD, LC):

LD50 (median dose) 2207 mg/kg (oral, rat)

2152 mg/kg (oral, mouse)[3]

Related compounds

Other anions Tin(II) chloride, tin(II) bromide, tin(II) iodide

Other cations Lead(II) sulfate

Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Tin(II) sulfate (SnSO4) is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence. It can be prepared by a displacement reaction between metallic tin and copper(II) sulfate:[4]

Sn (s) + CuSO4 (aq) → Cu (s) + SnSO4 (aq)

Tin(II) sulfate is a convenient source of tin(II) ions uncontaminated by tin(IV) species.

Answer:

It occurs when a gas passes through a tiny hole.

Explanation:

Effusion is a term used to describe when a gaseous molecule in a container passes or escapes through a tiny/small hole. Effusion and diffusion are two properties of gases that are often used interchangeably, however, they differ.

Effusion differs from diffusion in the sense that the gas passes through a TINY HOLE that is smaller than the normal path. This is contrary to when gas disperses throughout a container as in diffusion.

The correct answer is:

A) It occurs when a gas passes through a tiny hole.

Answer:

Explanation:

Start with the number of grams of each element, given in the problem.

Convert the mass of each element to moles using the molar mass from the periodic table.

Divide each mole value by the smallest number of moles calculated.

Round to the nearest whole number. This is the mole ratio of the elements and is.

Answer:

Frame of Reference

The fixed background surrounding an object, assumed to be at rest and in a fixed position.

Answer:

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V

1

T

1

=

V

2

T

2

V

1

is the initial volume,

T

1

is initial temperature,

V

2

is final volume,

T

2

is final temperature.

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:

2.75

291

=

V

2

318

By cross multiplying, we have...

291

V

2

= 874.5

Dividing both sides by 291 to isolate

V

2

, we get...

V

2

= 3.005...

In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.

Therefore,

V

2

= 3.01 L

Explanation:

please mark me as the brainliest answer and please follow me

Answer:

6L im not completly sure but i wouldnt risk it

Explanation:

Answer:

Cobalt (III) Iodide

General Formulas and Concepts:

Chemistry - Compounds

Explanation:

Step 1: Define

CoI₃

Step 2: Identify

Co is a Transition Metal, has either a charge of 2+ or 3+

I is a Halogen, has a charge of 1-

Step 3: Write name

We need to balance the charges, and in order to do that, we must have a Co³⁺

Cobalt (III) Iodide

Answer:

The second choice and the fourth choice are both based on science fact. The others are examples of pseudoscience.

Answer:

c elevation

Explanation:

C is the answer for your question

Answer:

3.077 × 10¹⁴ Hz

Explanation:

f = ?

wavelength = 9.75 × 10-⁷m

using the formula,

c = wavelength × frequency

f = c/wavelength

but c(speed of light) = 3×10⁸m/s

f = 3 × 10⁸/9.75 × 10-⁷

f = 3.077 × 10¹⁴ s-¹

Answer:

0.282 M

General Formulas and Concepts:

Chemistry - Solutions

Explanation:

Step 1: Define

5.85 g KI

0.125 L

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

Step 3: Convert

[tex]5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} )[/tex] = 0.035241 mol KI

Step 4: Find Molarity

M = 0.035241 mol KI / 0.125 L

M = 0.281928

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.281928 M ≈ 0.282 M

Answer:

0.972mol

Explanation:

Given parameters:

Volume of Solution of KCl = 0.486L

Molarity = 2.0M

Unknown:

Number of moles of KCl in solution = ?

Solution:

To find the number of moles of KCl in this solution, use the expression below;

  Number of moles  = molarity x volume

Insert the parameters and solve;

  Number of moles  = 0.486 x 2  = 0.972mol

Answer:

Porque las moléculas de glucosa son salvajes

Explanation:

Answer:

Glucose cannot move across a cell membrane via simple diffusion because it is simple large and is directly rejected by the hydrophobic tails. Instead it passes across via facilitated diffusion which involves molecules moving through the membrane by passing through channel proteins.

Explanation:

Volume of Ba(OH)₂ : 0.363 L

Balanced equation :

H₂(g)+S(s)+2OH⁻(aq)⇒ S²⁻(aq)+2H₂O(l) (eq 1)

Ba(OH)₂⇒Ba²⁺+2OH⁻ (eq 2)

mol S :

[tex]\tt \dfrac{3~g}{32~g/mol}=0.09375[/tex]

mol OH from eq 1 : (mol S : mol OH = 1 : 2)

[tex]\tt \dfrac{2}{1}\times 0.09375=0.1875[/tex]

mol Ba(OH)₂ from eq 2 : (mol Ba(OH)₂ : mol OH⁻=1 : 2)

[tex]\tt \dfrac{1}{2}\times 0.1875=0.09375[/tex]

volume of Ba(OH)₂ :

[tex]\tt Volume =\dfrac{mol}{M}=\dfrac{0.09375}{0.258}=0.363 L[/tex]

Answer:

.......................................................

Explanation:

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hydrogen is a chemical and is found in the sun and most of the stars, and the planet Jupiter is composed mostly of hydrogen. On Earth, hydrogen is found in the greatest quantities as water.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I hope this helps! /~\

Answer:

Im a 100% sure it is B. average molecular speed of ethane is greater than the average molecular speed of propanol.

Explanation:

Sry I didnt' get the explaination from my teacher.

According to the Kinetic theory of gases, the average speed of all gases at the same temperature will be in the same range. Hence, option C is correct.

Kinetic theory of gases states the properties and composition of gases at a temperature and pressure. According to this theory, gaseous substances are made of tiny particles which are free to move and collide to each other.

The kinetic energy of the particles is directly proportional to the temperature. Hence, as the temperature increases, the kinetic energy increases and their average molecular speed increases.

At the same temperature, all the gases have equal range of average molecular speed irrespective of their molecular weight. Hence, at 400 K the average molecular speed of ethane and propanol will be the same.

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Answer:

Yes

Explanation:

It is heating up both

Answer: the correct answer is D

Explanation: I just got the quiz finished

The products of the reaction has been potassium sulfate ([tex]\rm K_2SO_4[/tex]), and water ([tex]\rm H_2O[/tex]). Thus, option D is correct.

The chemical equation has been the representation of the reactants and the products formed. The reaction of KOH and sulfuric acid has been the neutralization reaction.

The products formed by the neutralization reaction has been salt and water.

The reaction of KOH and sulfuric acid has been:

[tex]\rm 2\;KOH\;+\;H_2SO_4\;\rightarrow\;K_2SO_4\;+\;2\;H_2O[/tex]

The products of the reaction has been potassium sulfate ([tex]\rm K_2SO_4[/tex]), and water ([tex]\rm H_2O[/tex]). Thus, option D is correct.

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Answer:

10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.

Explanation:

Hello!

In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.

Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.

Best regards!

Answer:

x and y

Explanation:

Answer:

wx

Explanation:

Because the w is going toward the x

Answer:

1.1 mol H₂O

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

6.8 × 10²³ molecules H₂O

Step 2: Convert

[tex]6.8 \cdot 10^{23} \ mc \ H_2O(\frac{1 \ mol \ H_2O}{6.022 \cdot 10^{23} \ mc \ H_2O} )[/tex] = 1.12919 mol H₂O

Step 3: Check

We are given 2 sig figs. Follow sig fig rules.

1.12919 mol H₂O ≈ 1.1 mol H₂O

Answer:

Our final conversion is 1.1 moles of water.

Explanation:

When we want to find the amount of moles in a substance, we can use dimensional analysis or conversion factors in order to convert it from molecules, grams, atoms, formula units, or virtually any other unit.

We are given that we want to convert 6.8 x 10²³ molecules of water to moles. We can set up a dimensional analysis table to solve this.

In dimensional analysis, we multiply across the top and then divide the results by the multiplied value on the bottom.

[tex]\begin{tabular}{c|c}6.8 \times 10^{23} \ \text{molec. of water} & \text{1 mol H}_2 \text{O} \\ \cline{1-2} 1 & 6.022 \times 10^{23} \ \text{molec. of water} & \end{tabular}[/tex]

Now, we will perform our calculations and find our final answer.

[tex](6.8 \times 10^{23}) \times (1) = 6.8 \times 10^{23}[/tex]

[tex](1) \times (6.022 \times 10^{23}) = 6.022 \times 10^{23}[/tex]

[tex]\huge\frac{6.8 \times 10^{23}}{6.022 \times 10^{23}} = 1.129192959[/tex]

[tex]\text{Round to significant figures} \rightarrow 1.129192959 \approx 1.1[/tex]

Therefore, using our table, we have determined that our final answer is 1.1 moles of water.

[tex]\begin{tabular}{c|c}6.8 \times 10^{23} \ \text{molec. of water} & \text{1 mol H}_2 \text{O} \\ \cline{1-2} 1 & 6.022 \times 10^{23} \ \text{molec. of water} & \end{tabular} = 1.1 \text{moles of water}[/tex]