An electron is moving at a constant speed of 83 m/s on a circle of radius 3.7 m. Part (a) Express the circumference of the circle C in terms of its radius R. Expression C= Select from the variables below to write your expression. Note that all variables may not be required. a. B. At, 2. 0. C. d. g, h, m, P. Q, R, t. Part (b) Express the time interval At for the electron to finish one circle in terms of the circumference and speed v. Expression 41 = Select from the variables below to write your expression. Note that all variables may not be required. a,B,A,2, 0. C. d.g,h,m, P, Q, R, L, V Part (e) Express the current on the circle through the charge e and time interval 41. Expression: Select from the variables below to write your expression. Note that all variables may not be required. a, b, At,, 0,C,d,e, g, h, k, m, n, P. Part (d) Calculate the numerical value of 7 in A. Numeric : A numeric value is expected and not an expression. I=

(1) If this were the case, 1000g of this would consist of 965.5 grams of water and 34.5 grams of salt.

(2) Increase in either salinity or temperature leads to an increase in the density of seawater and vice versa.

The salinity of seawater is typically measured in "parts per thousand" (ppt), which means that for every 1000 parts (by weight) of seawater, 34.5 parts are salt.

So it implies that  in 1000g of seawater with a salinity of 34.5 ppt, there would be 34.5g of salt and 965.5g of water.

Salinity has a direct effect on the density of seawater because the dissolved salts in seawater increase its mass, which in turn increases its density.

Temperature also affects the density of seawater because as the temperature increases, the water molecules move faster and the spaces between them increase, leading to a decrease in the density of the water.

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Answer:

sorry I'm not smart

Explanation:

Answer: A bear

Explanation:

I think it is a bear because in the North pole it swims to get food and walks in land to hide.

half I think that's just a guess though

At a height of 8.0 cm from the bulb's center, the radiation pressure caused by a 75-w bulb is calculated as current=watts divided by voltage=75/120=0.625 amperes.

The mechanical stress that is applied to any surface as a result of the electrical waves and the object exchanging momentum is known as radiation pressure. When photons hit the object's surface in this instance, momentum is transferred.

The development of cometary tail, in which dust particles ejected by cometary nuclei are driven by solar radiation into distinctive trailing patterns, is another visually striking example of radiation pressure. With the development of, it became possible to apply radiation pressure to terrestrial environments.

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Let's call the speed of the current "c". Then, the speed of the boat relative to the water when it is going upstream is 24 - c mph, and the speed of the boat relative to the water when it is going downstream is 24 + c mph.

Using the time it takes to travel the given distances, we can set up the following equation:

(54) / (24 - c) = (90) / (24 + c)

Expanding and solving for c, we find that:

c = 4 mph

So the speed of the current is 4 mph.

Answer: Upstream: 24 - 6 = 18  --->   54 = 18 x?  --->  ? = 54/18 = 3 hours

   (24 - 6)x 3 = 18 x 3 = 54 miles

   (24 + 6) x 3 = 30 x 3 = 90 miles

The speed of the current is 6 mph.

Time is 3 hours

The charge on each identical bead is calculated to be q = √[4πε/√3× (R² m g)].

The mass of the two identical beads is given as m.

The charge on each bead is q.

The radius of the hemispherical bowl is R.

The beads are said to be in equilibrium.

For the charges to balance at a point, the force of electric repulsion along the tangent should balance the force of gravitation along the tangent.

1/4πε q²/R² cos 30° = m g cos 60°

1/4πε q²/R² (√3/2) = m g (1/2)

√3/4πε q²/R² = m g

q² = (4πε)/√3 × (R² m g)

q = √[4πε/√3× (R² m g)]

Thus, the charge on each bead is calculated to be √[4πε/√3× (R² m g)].

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1. As the Tsunami wave approaches the beach, water levels will start to rise, and the ocean may appear to recede away from the shoreline.

2. The ocean may become very calm, and the surface may appear glassy.

3. Strong currents may be felt, and debris such as seaweed, branches, and shells may be seen rushing away from the shoreline.

4. Animals such as birds may be seen fleeing from the shoreline, and a loud roar may be heard as the wave approaches.

5. The wave will eventually reach the beach, and the water levels will quickly rise to a high level. The wave will then crash into the shore, causing destruction and flooding.

A  Tsunami is a powerful series of ocean waves caused by an underwater disturbance, such as an earthquake, volcano, or landslide. These waves travel across the ocean at high speeds and can reach up to hundreds of feet in height when they reach coastlines, causing severe flooding and destruction. Tsunamis are also known as seismic sea waves, and they can occur anywhere in the world.As the wave energy travels, it causes the sea level to rise and creates a “wave” that can travel up to 500 miles per hour. Tsunamis can reach heights of up to 100 feet and can cause extensive damage to coastal areas. The strength of the wave depends on the intensity of the earthquake or eruption that caused it.

Tsunamis usually arrive onshore suddenly and without warning, leaving little time for people to evacuate to safety and are often accompanied by strong currents and large amounts of debris, making them even more destructive.

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Answer:

Fc=mv2/r v=√(Fcr/m) v=√[(3.6 N)(0.38 m)/(0.0012kg)] v=33.76388603 m/s v=38 m/s

Explanation:

The resulting amplitude of the two waves is 1.25 m

When two waves of different amplitudes interfere, the resulting wave pattern is determined by the relative phase and amplitude of the two waves. If the two waves are in phase, meaning that their peaks and troughs line up, they will reinforce each other and produce a wave with a larger amplitude. This is known as constructive interference.

In this case the amplitude of the resulting wave would be a combination of two amplitudes of the waves and that would be 1.25 m

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A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.

When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,

where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:

|C|min = |A| - |B| = 1 m - 10 m = 9 m.

The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:

|C|max = |A| + |B| = 1 m + 10 m = 11 m.

Therefore, the magnitude of C is between 1m and 10m, and it can be determined.

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correct question

Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)

A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.

Answer:

Explanation:

The Root Mean Square (RMS) pressure of a waveform can be defined as the square root of the average of the square of the pressure values over one period of the wave. The RMS pressure provides a measure of the effective pressure of a waveform and is often used to compare the strength of different waveforms.

For a square wave, the RMS pressure can be found as follows

P_RMS = sqrt((1/T) * ∫_0^T (P_square(t))^2 dt)

Where T is the period of the waveform and P_square(t) is the pressure value of the square wave at time t. The integral is taken over one period of the waveform.

For a triangular wave, the RMS pressure can be found as follows:

P_RMS = sqrt((1/T) * ∫_0^T (P_triangular(t))^2 dt)

Where T is the period of the waveform and P_triangular(t) is the pressure value of the triangular wave at time t. The integral is taken over one period of the waveform.

The RMS pressure of a sinusoidal wave is given by the equation:

P_RMS = (A/sqrt(2))

Where A is the amplitude of the waveform.

Comparing the RMS pressures of the three waveforms, it can be seen that the RMS pressure of a sinusoidal wave is (A/sqrt(2)) which is smaller than the RMS pressure of a square wave or a triangular wave. This is because the square wave and triangular wave have sharper transitions from positive to negative values compared to the sinusoidal wave, which results in higher peak pressure values and hence a higher RMS pressure.

It is worth noting that while the RMS pressures of the three waveforms are different, they provide a measure of the effective pressure of the waveforms and can be used to compare their strengths.

Here is a definition of each variable used in the equation:

P_RMS: The Root Mean Square (RMS) pressure of the waveform. It is a measure of the effective pressure of the waveform.

T: The period of the waveform. It is the time it takes for the waveform to repeat itself.

P_square(t): The pressure value of the square wave at time t.

P_triangular(t): The pressure value of the triangular wave at time t.

∫_0^T: The integral symbol. It represents the sum of the pressure values over one period of the waveform, from time t = 0 to time t = T.

A: The amplitude of the waveform. It is the maximum positive or negative deviation from the zero line of the waveform.

sqrt: The square root symbol. It is used to find the square root of a value.

(A/sqrt(2)): The RMS pressure of a sinusoidal wave. It is calculated as the amplitude divided by the square root of 2.

The angular momentum of the system is  225,540 kg [tex]m^{2} /s[/tex] and the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

(a) The angular momentum of the system is given by L = Iω.

The moment of inertia of an equilateral triangle of mass M and side length a is I = (1/6)M[tex]a^{2}[/tex]

The mass of each capsule is 100 people × 75.0 kg/person = 7,500 kg.

Therefore, the total mass of the system is M = 3 × 7,500 kg = 22,500 kg.

The radius of the circle is half the side length of the equilateral triangle, so r = 41.0 m.

Therefore, the angular velocity of rotation is given by ω = (g/2)/r = 0.120 rad/s.

Using these values, the angular momentum of the system is L = (1/6)M[tex]a^{2}[/tex]ω = (1/6) × 22,500 kg × (82.0 [tex]m^{2}[/tex]) × 0.120 rad/s = 225,540 kg[tex]m^{2} /s[/tex]

(b) If the modules are pulled closer together, the moment of inertia of the system will decrease, because the mass of the system will be closer to the axis of rotation. According to the conservation of angular momentum, if the moment of inertia decreases, the angular velocity of rotation must increase in order to keep the angular momentum constant. Therefore, pulling the modules closer together would increase the rotational rate of the space station.

(c) The effective acceleration of gravity is given by g_eff = (g/2) + ([tex]v^{2}[/tex]/r), where v is the linear velocity of the space station. At the current rotational rate, the linear velocity of the space station is v = rω = 41.0 m × 0.120 rad/s = 4.92 m/s.

g.eff = (g/2) + ([tex]v^{2}[/tex]/r) = g

([tex]v^{2}[/tex]/r) = (g/2)

r = (2[tex]v^{2}[/tex])/g

Substituting the values for v and g, we get:

r = (2 × [tex]4.92m/s ^{2}[/tex])/9.81 [tex]m/s^{2}[/tex] = 24.8 m

Therefore, the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

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Answer:

  2.32 m/s

Explanation:

If an 8.90 kg block of ice slides down a 1.15 m frictionless ramp to reach a speed of 2.87 m/s, you want to know its final speed if there were friction opposing the motion with a force of 11.0 N.

The kinetic energy at the bottom of the frictionless ramp is ...

  KE = 1/2mv²

  KE = 1/2(8.90 kg)(2.87 m/s)² = 36.654205 J

When friction is introduced, the work done to oppose the friction is ...

  W = Fd

  W = (11 N)(1.15 m) = 12.65 J

Hence the remaining energy of the block at the bottom of the ramp with friction is ...

  KE' = 36.654205 -12.65 J = 24.004205 J

This corresponds to a speed of ...

  v = √(2·KE/m) = √(2·24.004205/8.9) ≈ 2.32 . . . . m/s

The speed at the bottom of the ramp with friction is about 2.32 m/s.

__

Additional comment

We can find the slope of the ramp by equating the ending kinetic energy to the beginning potential energy. As you can see, that is not relevant to the problem, since the opposing force is parallel to the ramp.

part a.

the work done by gravity is approximately 1690 J.

part b.

the work done by the normal force is 0.

part c.

the work done by friction is approximately -671 J

part d.

the total work done is approximately 1019 J

work done is described  as the multiplication of magnitude of displacement d and the component of the force that is in the direction of displacement.

For part a, the work done by gravity can be found using the formula:

W_gravity = mgh

h = dsin(37°) = 8sin(37°) = 4.83 m

W_gravity = (35 kg) * (9.81 m/s^2) * (4.83 m) ≈= 1690 J

In conclusion, the same pattern can be followed to calculate for b, c and d.

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Answer: Most of them need water to help reproduce & Most of them live in shady, moist, or humid areas.

Explanation:

Bryophytes are non-vascular plants, meaning they do not have specialized tissue for transporting water and nutrients throughout their bodies. Instead, they absorb nutrients and water from the environment. Bryophytes are usually short-lived and don't grow tall, and they prefer to live in shady, moist, or humid areas because they require water to help them reproduce.

The east would be the location of the Sun's rising and setting are the changes would you anticipate seeing.

Annual motion, which is a direct result of the Earth's rotation around the sun, is the visible yearly move of the stars as seen from Earth. The ecliptic is a line on the surface of a sphere around which the revolves around the sun 360 degrees each year.

We, the watchers on Earth, whirl past this foreground of far-off stars as the planet rotates on its axis. The stars seem to travel throughout our darkness of space from east to west as Earth spins for the same reason.

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a. Upthrust on the solid:

[tex]Upthrust = volume of solid * density of fluid * g = 1000 kg/m^3 * volume of solid * 10 m/s^2[/tex]

b. Volume of the solid:

[tex]volume = mass/density = 1.3 kg / (1000 kg/m^3) = 1.3 x 10^-3 m^3[/tex]

c. Density of the solid:

So,[tex]density = mass/volume = 1.3 kg / (1.3 x 10^-3 m^3) = 1000 kg/m^3[/tex]

Upthrust is the upward force exerted on an object immersed in a fluid. It is equal to the weight of the fluid displaced by the object and acts in the opposite direction to gravity. Upthrust helps to counteract the weight of the object and keep it afloat.

a. The upthrust on an object immersed in a fluid is equal to the weight of fluid displaced by the object. The weight of fluid displaced can be calculated using the formula:

Weight of fluid = volume of fluid * density of fluid * g

Since the solid is completely immersed in water, the volume of the fluid displaced is equal to the volume of the solid. The density of water is given as 1000 kg/m^3, and the acceleration due to gravity is given as[tex]10 m/s^2.[/tex]

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 (c) n=3,1=2,m=1,s=+1/2 this set of quantum number represents the highest energy of atom

Correct option is C)

The sets of the quantum numbers and the corresponding orbitals are as shown below.

a)n=3,l=0 means 3s− orbital

b)n=3,l=1 means 3p− orbital

c)n=4,l=2 means 4d− orbital

d)n=4,l=0 means 4s− orbital

Increasing order of energy among three orbitals is 3s<3p<4s<4d

∴4d has highest energy.

Hence, the set c of quantum numbers (n=4,l=2,m=1,s=+1/2)  represents the highest energy of an atom.

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It will take the car 3.2 seconds to hit the ground.

Using the kinematic equation,

y = yo + vot + 1/2a*t^2

where y is the displacement (in this case, y = -58 m), yo is the initial displacement (yo = 0), vo is the initial velocity (vo = 0), a is the acceleration due to gravity (a = -9.81 m/s^2), and t is the time we want to find.

We can solve for t by rearranging the equation:

t = sqrt(2*y/a)

t = sqrt(2*(-58)/(-9.81))

t = 3.2 seconds (to two significant figures)

Time taken is 3.2 seconds.

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(1) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal.(2)  Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed.

a) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal. Since Sphere 1 has a positive charge, electrons will flow from Sphere 2 to Sphere 1 until their potentials are equal. This means that Sphere 1 will end up with a lower potential than its initial potential and Sphere 2 will end up with a higher potential than its initial potential. Therefore, Vi is smaller than V2.

b) Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed. Therefore, the final charge on Sphere 2, Q2, will be equal to the initial charge on Sphere 1. Hence, Qi is equal to Q2.

c) The electric field strength at the surface of a charged conductor is proportional to the surface charge density. Since Sphere 1 has a larger radius than Sphere 2, it has a larger surface area and therefore a lower surface charge density. This means that E1 will be smaller than E2. Additionally, as charges move from Sphere 1 to Sphere 2, the surface charge density on Sphere 1 decreases, leading to a decrease in E1. Therefore, E1 will be smaller than E2 after the switch is closed.

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The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

Gravity is a fundamental force of nature that exists between all objects that have mass or energy. It is the force that pulls two objects towards each other, and it is what keeps objects like planets, stars, and galaxies in their orbits.

The force of gravity is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This means that the greater the mass of the objects and the closer they are to each other, the greater the force of gravity between them.

Gravity is responsible for many phenomena that we observe in our daily lives, such as keeping us and other objects on the surface of the Earth, causing tides in the ocean, and making objects fall to the ground when we drop them. It is also a key concept in the fields of astronomy and astrophysics, as it is what allows us to understand the motion and behavior of celestial objects in the universe.

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Answer:

The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N

Explanation:

Answer:

Average force of gravitation between Mercury and the Sun is approximately 3.54 x 10^20 N.

Explanation:

The following equation determines the gravitational force between two objects:

F = G * (m1 * m2) / d^2

In this equation, F is the gravitational force, G is the gravitational constant (G = 6.67 x 10-11 Nm2/kg2), m1 and m2 are the objects' masses, and d is the space between their centres.

We need the masses of Mercury and the Sun as well as their typical separation in order to compute the average gravitational force between them.

The Sun's mass is roughly 1.989 x 1030 kg, while Mercury's mass is roughly 3.285 x 1023 kg. Mercury and the Sun are typically separated by around 57.9 million kilometres (0.39 astronomical units).

With these values entered into the formula, we obtain:

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F = 3.54 x 10^20 N

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By supplying the distance travelled and the quantity of gasoline spent as inputs, Shubham may write a Python function to get the current mileage of his automobile. The statement is true.

Shubham can create a function in Python to calculate the current mileage of his car by passing the distance traveled and the amount of petrol consumed as parameters. He can define the function to take two arguments: distance and petrol, and then calculate the mileage by dividing the distance by petrol.

If the function is written correctly, it will return the current mileage of his car in km/l. By passing the appropriate values to this function, he can easily calculate the mileage of his car at any time, which can help him keep track of his car's fuel efficiency and plan his journeys accordingly.

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The estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

Since the human body is mostly made of water, we can assume that the total amount of positive charge is equal to the total amount of sodium ions (Na+) and other positively charged ions in the body.

The concentration of sodium ions in the human body is approximately 140 milliequivalents per liter (mEq/L), which is equivalent to 0.140 moles per liter (mol/L).

Assuming that the total volume of water in a 70 kg person is approximately 42 liters, we can estimate the total amount of sodium ions in the body as follows:

Total amount of sodium ions = concentration x volume of water
Total amount of sodium ions = 0.140 mol/L x 42 L
Total amount of sodium ions = 5.88 mol

Since each sodium ion has a charge of +1, the total amount of positive charge in a 70 kg person is also 5.88 C.

Therefore, the estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

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The maximum length of runway needed and tension in the towrope will be 175.05 m and 5999N.

For solving this question we will use the laws of Kinematics as well as the Newton's Laws of Motion. According to the third law of Kinematics

v² = u² + 2aS ; where v is the final velocity, u is the initial velocity, a is the acceleration and S is the displacement.

According to Newton's Laws of Motion we know that the net force is equal to product of mass and acceleration that is

F = ma ; where F is net force, m is mass of the body and a is the acceleration.

Now, form the free body diagram of the gliders, we balance the forces by Newton's law of motion as:

For glider 1 the forces in x axis will be:

T₁ - T₂ - f = ma                                                    ......(1)

where T₁ and T₂ are tensions on glider 1 and 2 respectively and f is the frictional force.

In y axis the forces will be:

N₁ - W = 0 ; where N₁ is the normal on first glider and W is the weight due to gravity.

For glider 2 the forces in x axis will be:

T₂ - f = ma                                                           ......(2)

where T₂ is tensions on glider 2 and f is the frictional force.

In y axis the forces will be:

N₂ - W = 0 ; where N₂ is the normal on second glider and W is the weight due to gravity.

From equation (1) and (2) we get

T₁ - 2f = 2ma

a = T₁ - 2f/2m

a = 12000 - 2(2800)/2(700)

a = 6400/1400

a = 4.57 m/s²

Now from laws of Kinematics we have

v² = u² + 2aS; here the initial velocity is zero so u = 0 and v = 40 m/s

(40)² = 0 + 2 × 4.57 × S

S = 1600/9.14

S = 175.05 m

Now for the tension in the second rope of glider we use equation (2) that is

T₂ - f = ma

T₂ = ma + f

T₂ = 700 × 4.57 + 2800

T₂ = 3199 + 2800

T₂ = 5999 N

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The magnitude of the acceleration of each block is given by the absolute value of a

In a system with a massless string and pulley, the forces acting on each block must be taken into account in order to calculate the amount of each block's acceleration.

Assume that the mass of block 1 is m1, the mass of block 2 is m2, and the string's tension is T.

Block 1 is being pulled up and down by the tension in the string (T) and its weight (m1g), respectively.

Block 2 is being pulled up and down by the tension in the string (T) and its weight (m2g), respectively.

The tension in the string remains constant throughout due to the masslessness of the string and the pulley as well as the absence of friction, which causes the blocks to accelerate in opposing directions at the same rate (a).

As a result, we may express the two blocks' motion equations as follows:

m1g - T = m1a for block 1.

T - m2g = m2a for block 2.

These equations for T and a can be resolved:

T = (m1 + m2)g / 2

m1 + m2 / (m2 - m1)g = a

The absolute value of a, which is as follows, determines the extent of each block's acceleration:

A is equal to (m1 + m2)g / (m2 - m1)g.

This formula indicates that the acceleration of each block is a function of both the total and difference of their masses.

A negative acceleration means that block 1 is travelling downhill and block 2 is moving upward if m1 is bigger than m2.

A positive acceleration means that block 1 is going upward and block 2 is falling downward if m2 is larger than m1.

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This statement refers to the value of the function f(t) at t = 6, which represents the amount of rainfall that has fallen since midnight up to 6 AM.

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