An automobile tire has a volume of 0.0185 m 3 3 . At a temperature of 294 K the pressure in the tire is 212 kPa. How many moles of air must be pumped into the tire to increase its pressure to 252 kPa, given that the temperature and volume of the tire remain constant?

Answers

Answer 1

The number of moles of the air will be 1.6.

What is an ideal gas equation?

The equation of state for a fictitious ideal gas is known as the ideal gas law, also known as the general gas equation. Although it has some restrictions, it is a good approximation of the behaviour of many gases under various circumstances.

Given that an automobile tire has a volume of 0.0185 m ³. At a temperature of 294 K, the pressure in the tire is 212 kPa.

Calculate the volume at pressure P₂,

P₁V₁ = P₂V₂

V₂ = ( P₁V₁ ) / P₂

V₂ = ( 212 x 0.0185 ) / 252

V₂ = 0.0155 m³

The number of the moles will be calculated as:-

PV = nRT

n = ( P₂V₂ / RT)

n = ( 252 x 0.0155 x 1000 ) / ( 8.3145 x 294 )

n = 1.6 moles

Therefore, there will be 1.6 moles in the air.

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Related Questions

there is a single electron at a distance from the point charge. on which of the following quantities does the force on the electron depend?

Answers

The force acting on the electron is dependent upon the distance seen between positive charge and indeed the electron, the charges on the electron, and indeed the charge of something like the positive charge.

Why is there a positive charge?

A material that has more protons than electrons is said to have a positive charge. We are aware that electrons seem to be positively charged and protons become positively charged. Consequently, positively charged objects have more protons than electrons.

The positive charge is absent:

The positive charge on the protons and neutrons (red) results from an imbalance between protons and electrons, more particularly, when there are more protons than electrons. Protons can be added to an atom or other substance with both a neutral charge to produce a positive charge.

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The electric field points away from positive charges and toward negative charges. A distribution of charges creates an electric field that can be found by taking the vector sum of the fields created by individual point charges. Note that if a charge is placed in an electric field created by q', q will not significantly affect the electric field if it is small compared to q'.

Imagine an isolated positive point charge with a charge Q (many times larger than the charge on a single electron).

There is a single electron at a distance from the point charge. On which of the following quantities does the force on the electron depend?

Check all that apply.

A the distance between the positive charge and the electron

B the charge on the electron

C the mass of the electron

D the charge of the positive charge

E the mass of the positive charge

F the radius of the positive charge

G the radius of the electron

I got A, B, and D for this part of the problem and was correct. However,

For the same situation as in Part A, on which of the following quantities does the electric field at the electron's position depend?

Check all that apply.

A the distance between the positive charge and the electron

B the charge on the electron

C the mass of the electron

D the charge of the positive charge

E the mass of the positive charge

F the radius of the positive charge

G the radius of the electron

the acceleration of the system shown above is? please answer ASAP​

Answers

Answer:

3.92 m/s²

Explanation:

It's hard to read your sketch, but it looks like m2 = 30 kg?  If so, here's the answer:

m1 = 20 kg

m2 = 30 kg

a = (m2·g) - (m1·g·sin∅) / (m1 + m2)   you can see how this equation is derived from Newton's 2nd Law in any physics textbook or website

a = ((30 kg)(9.8 m/s²) - (20 kg)(9.8 m/s²)(sin30)) / (20 kg + 30 kg)

a = (294 kg·m/s² - 98 kg·m/s²) / (50 kg) = 3.92 m/s²

two tennis balls fall through the air from a tall building. one of them is filled with lead pellets. the ball to reach the ground first is the

Answers

From a towering building, 2 tennis balls fall into the air. Lead pellets are contained within one of them. The lead-filled ball becomes the first to touch the ground.

What do you call air?

The invisible atmospheric mixture that envelops Earth is called air. Most organisms depend on vital elements like oxygen and nitrogen to thrive, which are found in air. Of course, a member of this species is human people (Homo sapiens). In some cases, "atmosphere" is substituted in place of "air."

What purpose does air serve?

Respiration is a procedure that includes breathing. A living organism breathes by taking intake oxygen from the environment and exhaling carbon dioxide. This process provides the energy necessary for plants and animals to absorb, grow, and sustain life.

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explain three examples of a workshop

Answers

The required three examples of a workshop are given as 1) Woodworking Workshop, 2) Photography Workshop, and 3) a Writing Workshop.

What are workshops?

Workshops are the places where production operations take place.

Woodworking Workshop: A workshop that teaches the skills and techniques involved in woodworking such as using tools, working with different types of wood, and constructing wooden objects such as furniture, toys, and crafts.

Photography Workshop: A workshop that focuses on teaching the fundamentals of photography such as composition, lighting, and editing techniques. Participants learn how to use a camera and develop their own style through practical exercises and group discussions.

Writing Workshop: A workshop that provides a supportive environment for writers to develop their craft and receive feedback from peers and a writing instructor. Topics covered in a writing workshop may include character development, plot structure, dialogue, and revision techniques.

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During a football match, the ball kicked at 45° angle of elevation went just over the goal post, height 2.4m. Assuming the goal post height is the greatest, calculate: The speed at which the ball was projected, The time taken to reach the greatest height
the horizontal distance between the point of kick and foot of the goal post bar (neglect the thickness of the bar)​

Answers

Answer:

see below

Explanation:

We are here given that ,

maximum height of projectile= 2.4m (h)angle at which it is kicked = 45° speed of projection= ? (u)

As we know that,

[tex]\implies h =\dfrac{u^2\sin^2\theta}{2g} \\[/tex]

substitute the respective values,

[tex]\implies 2.4 m =\dfrac{u^2\sin^245^\circ}{2\times 10} \\[/tex]

[tex]\implies 2.4m =\dfrac{u^2\times \bigg(\dfrac{1}{\sqrt2}\bigg)^2}{20}\\[/tex]

[tex]\implies u^2 = 40 \times 2.4 = 96 \\[/tex]

[tex]\implies u^2 =\sqrt{96}\\[/tex]

[tex]\implies \underline{\underline{ u \approx 9.79 \ m/s }}\\[/tex]

secondly we know that,

[tex]\implies t = \dfrac{u\sin\theta}{g}\\[/tex]

[tex]\implies t =\dfrac{9.79\times \sin45^\circ}{10} \\[/tex]

[tex]\implies t =\dfrac{9.79\times \dfrac{1}{\sqrt2}}{10} \\[/tex]

[tex]\implies \underline{\underline{ t \approx 0.69 \ s }}\\[/tex]

and we are done!

A Jogger runs 2.0km due east, then 10km at 45° north of east and finally 0.5km due north- Determine the displacement using graphical method Using Scale of 5ocm =2 km​

Answers

Answer:

Explanation:

To determine the displacement of the jogger using a graphical method, we can create a vector diagram to represent the individual components of the jogger's motion. We can then find the resulting displacement by adding the vectors end to end.

Assuming that "50cm = 2km" is the scale, we can convert the distances to represent them on the diagram:

2.0 km due east = 100 cm

10 km at 45° north of east = 70.71 cm (using Pythagorean theorem)

0.5 km due north = 25 cm

Next, we can plot the vectors on a coordinate grid, with east as the x-axis and north as the y-axis.

The jogger's first move, 2 km due east, can be represented by a vector starting from the origin and extending 100 cm to the right.

The second move, 10 km at 45° north of east, can be represented by a vector starting from the end of the first vector and extending 70.71 cm up and to the right.

The third move, 0.5 km due north, can be represented by a vector starting from the end of the second vector and extending 25 cm straight up.

Finally, to find the displacement, we add the vectors end to end. The displacement is the vector that starts at the origin and extends to the endpoint of the final vector. The magnitude of the displacement can be found using the Pythagorean theorem.

Using this method, we can determine the displacement of the jogger using a graphical method and the given scale.

A 67 kg high jumper leaves the ground with a
vertical velocity of 6.4 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s².
Answer in units of m. Answer in units of m.

Answers

The height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

What is Kinetic and Potential energy?

Potential energy is defined as the energy stored in an object or system by virtue of its position or arrangement of parts while kinetic energy is defined as the energy of the moving particles of an object or system.

Potential energy is represented as :

P.E.= mgh

Kinetic energy  is represented as :

[tex]K.E.= 1/2mv^2[/tex]

where, m = mass of the object

h= height

v= velocity

g= acceleration due to gravity which is [tex]9.8m/s^2[/tex]

For above given example,

m= 67kg, v= 6.4m/s

we first find out Kinetic energy,

K.E.=[tex]\frac{1}{2} 67* (6.4)^2[/tex]= 2744.32/2= 1372.16 J

As we know, K.E.= P.E.

So, P.E.= 1372.16J = mgh

1372.16= 67* 9.8* h

height= 2.089 m

Thus, the height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

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Help me please physics worksheet

Answers

Kinetic friction has a coefficient of 0.52 while static friction has a coefficient of 0.67.

What is friction?

A force called friction prevents motion from occurring when two surfaces come into contact. Based on the characteristics of the two surfaces, their roughness, and the pressure used to press them together, it moves the objects in the opposite direction from the motion or planned motion.

How do you determine it?

a. The formula friction = force of friction / normal force is used to calculate the coefficient of static friction.

The frictional force needed to move the chair is 165 N, and the normal force equals the chair's weight (25 kg * 9.8 m/s2 = 245 N).

The static friction coefficient is therefore equal to 165 N / 245 N = 0.67.

b. The formula friction = force of friction / normal force is used to determine the coefficient of kinetic friction.

The frictional force needed to maintain the chair's motion at a constant speed is 127 N, whereas the normal force remains 245 N.

Therefore, the kinetic friction coefficient is equal to 0.52 for 127 N/245 N.

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A cart rolls with low friction on a track. A fan is mounted on the cart, and when the fan is turned on, there is a constant force acting on the cart. Three different experiments are performed: Fan off: The cart is originally at rest. You give it a brief push, and it coasts a long distance along the track in the +x direction, slowly coming to a stop. Fan forward: The fan is turned on, and you hold the cart stationary. You then take your hand away, and the cart moves forward, in the +x direction. After traveling a long distance along the track, you quickly stop and hold the cart. Fan backward: The fan is turned on facing the "wrong" way, and you hold the cart stationary. You give it a brief push, and the cart moves forward, in the +x direction, slowing down and then turning around, returning to the starting position, where you quickly stop and hold the cart. The figure displays graphs of x, position along the track, vs. time. The graphs start when the cart is at rest, and end when the cart is again at rest. Match the experiment with the correct graph.

Answers

Experiment A (Fan Off) corresponds to graph C, as it shows the cart starting from rest and slowing down until it comes to a stop. Experiment B (Fan Forward) corresponds to graph A, as it shows the cart starting from rest, accelerating, and then coming to a stop. Experiment C (Fan Backward) corresponds to graph B, as it shows the cart starting from rest, accelerating, slowing down, and then turning around and returning to the starting position before coming to a stop.

Friction is the force that resists the motion of one object against another. It is a force that acts in the opposite direction of the motion. Friction occurs when two objects rub against each other, resulting in a force that resists their relative motion. This force can be caused by a variety of factors, including the surface roughness of the objects, the material they are made of, the weight of the objects, and the environment they are in.

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2.) For an atom of helium, it takes 40.8 electron-volts of energy to move an electron from the first energy level to the second, it takes 48.4 electron-volts to move an electron from the first energy level to the third, and it takes 51.0 electron-volts of energy to move an electron from the first energy level to the fourth.

If I were to shine a light made of photons with 51.0 electron-volts of energy, which transition(s)

will I observe? Explain your answer.

Answers

Answer:

You will observe the transition from the first energy level to the fourth energy level. This is because the energy of the photons is equal to the amount needed to move the electron from the first energy level to the fourth energy level. Any energy higher than 51.0 electron-volts would not be observed because the electron would not be able to transition to a higher energy level.

What makes types of light different?

Answers

Answer:

Their wavelength

Explanation:

Light is a form of energy that travels as waves. Their length — or wavelength — determines many of light's properties. For instance, wavelength accounts for light's colour and how it interacts with matter. The range of wavelengths, from super short to very long, is known as the light spectrum.. Please mark this answer the brainliest. I need it. thanks.

Hope this helps!

A hot-air balloon is ascending at the rate of 11 m/s and is 59 m above the ground when a package is dropped over the side. (a) How long does the package take to reach the ground? (b) With what speed does it hit the ground?

Answers

The speed of the package just before hitting the ground is 46.942 m/s.

How to calculate the speed?

We can solve this problem using the kinematic equations of motion. Let's assume that the positive direction is upwards and take the acceleration due to gravity to be -9.8 m/s².

(a) To find how long the package takes to reach the ground, we can use the equation:

y = y0 + v0t + (1/2)at²

Plugging in the values, we get:

0 = 59 m + (11 m/s)t + (1/2)(-9.8 m/s^2)t²

Simplifying and solving for t, we get:

t = 4.79 seconds

Therefore, the package takes approximately 4.79 seconds to reach the ground.

(b) To find the speed at which the package hits the ground, we can use the equation:

v = v0 + at

Plugging in the values, we get:

v = 11 m/s + (-9.8 m/s²)(4.79 s)

= -46.942 m/s (the negative sign indicates that the package is moving downwards)

The speed of the package just before hitting the ground is 46.942 m/s.

What really is speed in physics, and what is its unit?

The pace at which distance changes over time is referred to as speed. It has a dimension of time and distance. As a result, the fundamental unit of length as well as the basic unit if duration are combined to form the High silica content of speed. As a result, the Si derived unit for speed is the meter per second.

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___ tubing is commonly used in hydraulic systems. Carbon Steel. _____ fittings are typically used in hydraulic equipment when attaching tubing to a hose.

Answers

Flared tubing is commonly used in hydraulic systems. Carbon Steel fittings are typically used in hydraulic equipment when attaching tubing to a hose.

Liquid fluid power is used by hydraulic machines to do operations. Heavy-duty construction vehicles are a typical illustration. Hydraulic fluid is pumped to numerous hydraulic motors and hydraulic cylinders located all around the machine in this sort of machine and is pressured in accordance with the resistance present. Control valves direct or automate the distribution of the fluid through hoses, tubes, or pipes.

Pascal's law, which asserts that any pressure applied to a fluid inside a closed system would transmit that pressure equally everywhere and in all directions, is the foundation of hydraulic systems, just like pneumatic systems. An incompressible liquid, as opposed to a compressible gas, serves as the fluid in a hydraulic system.

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Do the following factors increase or decrease as one moves to higher magnifications with the microscope?a. resolutionb. amount of light neededc. working distanced. depth of field

Answers

The following factors change as one moves to higher magnifications with a microscope:

What is magnification?

Magnification is a measure of how much an image is enlarged or increased in size compared to the original object. It is commonly used in optics, such as microscopes and telescopes, to describe the level of enlargement achieved by the instrument. The magnification is usually expressed as a ratio or a multiple of the original size.

a. Resolution: Resolution refers to the ability of a microscope to distinguish two separate points as separate entities. As one moves to higher magnifications, the resolution of the microscope increases, meaning that smaller and finer details can be seen.

b. Amount of light needed: As magnification increases, the amount of light needed to illuminate the specimen also increases. This is because the increased magnification reduces the amount of light that reaches the specimen and the observer.

c. Working distance: Working distance refers to the space between the lens and the specimen. As one moves to higher magnifications, the working distance decreases, meaning that the lens must be positioned closer to the specimen.

d. Depth of field: Depth of field refers to the range of distances from the lens that are in focus at any given time. As one moves to higher magnifications, the depth of field decreases, meaning that only a very small portion of the specimen will be in focus at any given time.

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what is the value of gravity on moon?

Answers

Answer:

The gravitational force on the moon is approximately 1/6th of the gravitational force on Earth. This means that the value of gravity on the moon is 1.62 m/s2.

Answer:

on earth the value of gravity on moon is 1.625 m/s2

Explanation:

1.625 m/s2

Which of the following is likely to happen when a glass of cold water is warmed to room temperature?Select the correct answer below:A. The water will absorb air as the solubility of its dissolved air increases.B. Small air bubbles will form as the solubility of its dissolved air decreases.C. The water will neither absorb nor release air because the solubility of its dissolved air does not change.D. We need more information to predict what will happen to the water.

Answers

Small air bubbles will form as the solubility of its dissolved air decreases when a glass of cold water is warmed to room temperature. Option B. is correct.

It's not as easy as it seems to pour water into a glass. Gases have been dissolved in them.

Furthermore, before we warm a glass of ice-cold water to room temperature, we must understand what we are doing. In essence, we are raising the water's temperature.

We now need to think about how rising temperatures will affect how soluble gases in the water.

By raising the temperature, we are supplying thermal energy in the form of heat to the gaseous molecules. The mobility and propensity to escape from the solution both increase as the thermal energy of the dissolved gaseous molecules rises. Because of this, the solubility of gases decreases as temperature rises.

As a result, when water is heated, gaseous molecules that have been dissolved begin to rise up from the water.

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a new laptop was delivered to your home and left on the porch while you were at work. it is very cold outside, and you don't know how long it has been there. you unpack the laptop. you would like to know if it is working properly. which of the following is the best action to take?

Answers

The optimal course of action is to allow the laptop to warm up to room temperature before turning it on.

The room atmosphere and the outside temperature of the laptop are very different in terms of temperature.

When the user was at work and the laptop was discovered on the deck, it was delivered to his house. He is unable to recall how long it has been really chilly outside. The user opens his laptop and checks to see if everything is working correctly. Instead, turn on the machine at room temperature and let it preheat up.

When a computer is still in a frigid environment, it must warm up to room temperature for roughly 6 to 24 hours before being turned on. Otherwise, the heat the components produce might cause the laptop to become moist with water. The system's components might then be harmed by that water.

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What is a wave function?

Answers

a function that satisfies a wave equation and describes the properties of a wave.

a pulley system has a mechanical advantage of 3, and an object weighing 9 newtons must be lifted 15 meters. how much force must be applied to lift the object? use the following equation to find the answer: ma=fo/fi

Answers

To lift the object, you must apply a force of 27 Newtons (9 Newtons divided by 3, the mechanical advantage).

The equation you can use to find the answer is MA = F0/Fi, where MA is the mechanical advantage, F0 is the input force and Fi is the output force.

MA is the mechanical advantage of a machine and is the ratio of output force to input force. For example, if an object needs to be lifted but the force required to lift it is too great, a machine such as a pulley system can be used to reduce the force needed. A pulley system has a mechanical advantage of 3, meaning that the output force is three times greater than the input force.

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Can someone please help me label this right

Answers

The tension at the top of the horizontal circle is T = m (v²/r - g ).

The tension at the bottom of the horizontal circle is m (v²/r + g ).

What is the tension at the bottom and top of the rope?

The tension at the bottom and top of he rope is calculated by applying the following formula as shown below;

The tension at the top of the horizontal circle is calculated as;

T = ma - mg

T = mv²/r - mg

T = m (v²/r - g )

where;

v is the speedr is the radius of the circleg is acceleration due to gravity

The tension at the bottom of the horizontal circle is calculated as;

T = ma + mg

T = mv²/r + mg

T = m (v²/r + g )

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The complete question is below:

Find the expression for the tension at the bottom and top of the circle

Four small spheres, each charged to +15 nC, form a square 2.0 cm on each side. From far away, a proton is shot toward the square along a line perpendicular to the square and passing through its center. What minimum initial speed does the proton need to pass through the square of charges

Answers

The speed of the charged particles or proton or electron will be 2.75 × 10⁵ m/s.

What is Kinetic energy?

The kinetic energy of an object is the energy which it possesses due to its motion. Kinetic energy is defined as the work needed to accelerate an object of a given mass from the state of rest to its stated velocity.

At the center of the square, all the kinetic energy of the proton is converted to potential energy of the proton. Therefore, far away the kinetic energy of proton must be equal to the potential energy of the person at the center.

Speed of the electron far away from the square, v = 2.75 × 10⁵ m/s

Given, that the charge, q = 15 × 10⁻⁹C

Each side of square, l = 0.02m

Distance of center of square from any charge r = √2l/2 = r= √2 × 0.02/ 2

r = 0.014m

q = 15nC

q = 15nC

I = 0.02m

q = 15nC

q = 15nC

Electric potential at the center of the square is given by:

Vc = 4 × (kq/r)

Electric potential at point far away is V∞ = 0

Potential Energy difference between the two point is

ΔV = Ve - V∞

ΔV = 4×(kq/r)

For the proton to pass through the center of square the proton must have kinetic energy equal to the potential energy at the center of the square.

The kinetic energy of the proton K = mv²

The potential energy of the proton U = eΔV

For the proton to pass through

K(at ∞) = U(Center)

1/2 mv² = 4kqe/ r

v = [tex]\sqrt{(8kq)/(mr)}[/tex]

v = √(8 × 9 × 10⁹ × 15 × 10⁻⁹ × 1.6 × 10⁻¹⁹)/ (1.67 × 10⁻²⁷ × 0.014) m/s

v = 2.75 × 10⁵ m/s

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PLS HELP WILL MARK AS BRAINLIEST
100PTS
1. if a ball of 60kg falls from a height of 20m to the ground calculate the potential energy (g=10mls²)
2. A girl whose weight is 30N run up a flight of stairs 5m high in 6 seconds. what is her average power.​

Answers

1.) The potential energy of an object can be calculated using the equation: PE = mgh

Where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

So, the potential energy of a 60 kg ball falling from a height of 20 m would be:

PE = 60 kg * 10 m/s² * 20 m = 12000 J (joules)

2.) The average power can be calculated using the equation: P = W / t

Where W is the work done and t is the time taken.

In this case, the work done can be calculated as W = mgh, where m is the mass of the girl (30 N), g is the acceleration due to gravity (10 m/s²), and h is the height of the stairs (5 m).

So, W = 30 N * 10 m/s² * 5 m = 1500 J

And the average power can be calculated as:

P = 1500 J / 6 s = 250 W (watts)

Answer:

Answer is in attached photo.

Explanation:

Solution

The solution is in the attached photo, do take note to solve these questions, multiple formulas are needed:

Q1) Potential Energy = Mass x Gravitational Accceleration x Height

= m x g x h (SI Unit: J)

Q2) Work Done = Force x Distance

= F x d (SI Unit: J)

Average Power = [tex]\frac{Total \ Work \ Done}{Total \ Time}[/tex] (SI Unit: W)


A 66 kg student traveling in a car with a constant velocity has a kinetic energy of 1.1 104 J. What is the speedometer reading of the car in km/h?

Answers

Answer:

The speedometer reading of the car in km/h is 100.1 km/h. This can be calculated by using the formula K = 0.5mv2, where K is the kinetic energy, m is the mass, and v is the velocity. Rearranging this equation to solve for v yields v = √(2K/m). In this case, m = 66 kg and K = 1.1 x 104 J, so v = √(2 x 1.1 x 104 J/ 66 kg) = 100.1 km/h.

the block has a weight of 20 lb and is being hoisted at uniform velocity. determine the angle u for equilibrium and the force in cord ab.

Answers

The force in the cord ab is 37.6 lb when being lifted at a constant speed, and the angle u for balance.

Describe uniform velocity using an illustration.

The rotation of the earth is an example of a body that is moving with uniform velocity when its speed is increasing throughout an interval of time.

The sum of the forces in each direction must be zero in order to lift the block at a steady speed.

XFx = 0 : F sin θ − T sin 20° = 0

XFy = 0 : T cos 20° − F cos θ − 20 = 0

The tension in cord CAD stays constant throughout because there is no friction on the pulley: F = 20 lb.

20 sin θ − T sin 20° = 0......... (1)

T cos 20° − 20 cos θ − 20 = 0 ........(2)

Solve equation (1) for T

T = 20 sin θ/sin 20

and substitute it into equation (2).

(20 sin θ/sin 20°)cos 20° − 20 cos θ − 20 = 0

cot 20°sin θ − cos θ − 1 = 0

cot 20°sin θ − 1 = cos θ

cot 20°sin θ − 1 = √1 − sin2θ

cot²20°sin²θ − 2 cot 20°sin θ + 1 = 1 − sin²θ

(cot²20° + 1) sin²θ − 2 cot 20°sin θ = 0

csc²20°sin²θ − 2 cot 20°sin θ = 0

(csc²20°sin θ − 2 cot 20°) sin θ = 0

csc²20°sin θ − 2 cot 20° = 0 or sin θ = 0

sin θ = 2 cot 20°/csc² 20°

= 2 cos 20°sin 20° = sin 40° or sin θ = 0

θ = 40° or θ ≠ 0°.

Substitute this nonzero value for θ into the formula for T.

T =20 sin θ/sin 20°

≈ 37.6 lb

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The probability that a baseball player hits a home run is greater than the probability that he gets a successful hit. (Select all that apply.) A.) A home run is the only type of successful hit, so the probabilities of each must be equal. B.)The probability that he hits a home run and the probability that he gets a successful hit must add up to 1. C.)The probability that he gets a successful hit must be 1, since a successful hit is always possible, and therefore the probability that he hits a home run cannot be greater. D.)A home run by definition is a successful hit, so the probability that he gets a successful hit must be greater than, or at least equal to, the probability that he hits a home run. E.)These probabilities cannot be calculated, so it is impossible to say which one is greater.

Answers

A and D are correct. A home run is the only type of successful hit, so the probabilities of each must be equal.

Additionally, a home run by definition is a successful hit, so the probability that he gets a successful hit must be greater than, or at least equal to, the probability that he hits a home run. B, C and E are incorrect since these probabilities can be calculated and it is possible to say which one is greater.

The probability is a measure of how likely an event is to occur. It is a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain. The probability of an event can be calculated by dividing the number of favorable outcomes by the total number of potential outcomes. For example, if the probability of flipping a coin and getting heads is 0.5, it means that there is a 50% chance of getting heads when flipping the coin.

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3. A stopped roller coaster cart (velocity = 0 m/s) with a mass of 12,000 kg starts from the top of
the track at a height of 35 meters. It begins to roll down to the bottom (where height will be 0
meters).

(a.)What is the kinetic energy of the roller coaster cart at the bottom? KE PE

(b.)What is the velocity of the cart at the bottom?
bottom
top

Answers

A stopped roller coaster cart (velocity = 0 m/s) with a mass of 12,000 kg starts from the top of

the track at a height of 35 meters. It begins to roll down to the bottom (where height will be 0 meters).

KE = PE = mgh

KE = (12,000)(9.8)(35)

= 4,116,000

What is height?

Despite the fact that height is typically measured in relation to a plane of reference, most height measurements in the real world are based on sea level, which is a zero surface. The position of a point above mean sea level is typically used to define altitude and elevation, two synonyms for height. The sea-level surface beneath the continents can be extended; naively, one might picture a large number of little canals running through the continents. In reality, gravity measurements must be used to calculate the sea level beneath a continent; various computing techniques are available; see Geodesy, heights.

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a golf ball is suit from a ship which is at a height 46 m above water surface the horizontal distance covered by Golf is​

Answers

The horizontal distance travelled by the golf is 7.75 m.

What is the height of fall of the golf?

The time taken for the golf to fall from the given height is calculated by applying the following equation.

t = √ ( 2h / g )

where;

h is the height of fall of the golfg is acceleration due to gravity

t = √ ( 2 x 46 / 9.8 )

t = 3.1 seconds

The horizontal distance travelled by the golf is calculated as follows;

d = vt

where;

v is the horizontal velocity

d = 2.5 m/s x 3.1 s

d = 7.75 m

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The complete question is below:

a golf ball is suit from a ship which is at a height 46 m above water surface the horizontal distance covered by Golf is​ if the horizontal velocity is 2.5 m/s.

how matter is identified.

Answers

Answer:

Explanation:

Matter is identified based on its physical and chemical properties.

Physical properties, such as color, texture, density, melting point, and boiling point, can be used to identify matter without changing its composition. For example, a solid object with a high density and a high melting point is likely to be a metal, while a lighter, less dense material with a low melting point is likely to be a plastic.

Chemical properties, such as reactivity, flammability, and acidity, are also used to identify matter. For example, the reaction of a substance with a strong acid or base can provide information about its chemical composition.

In addition to physical and chemical properties, matter can also be identified based on its molecular structure and composition. This can be done using techniques such as X-ray diffraction, spectroscopy, and microscopy, which allow scientists to examine the atomic and molecular structure of matter.

Finally, the chemical formula of a substance can also be used to identify it. The chemical formula specifies the types and numbers of atoms present in the substance, which can be used to determine its chemical properties and behavior.

Matter can be identified by its characteristic inertial and gravitational mass and the space that it occupies. Matter is typically commonly found in three different states: solid, liquid, and gas.

after you size up the scene, the following are steps involved with performing a primary assessment for a child. place them in order in which they should occur.

Answers

The correct order of steps involved in performing a primary assessment for a child is check the patient for responsiveness, summon more advanced medical personnel, check for breathing and a pulse, and quickly scan for severe bleeding. The correct order is 2, 1, 4, and 3.

The first step in performing a primary assessment is to check the patient for responsiveness, if the child is responsive or not. This involves calling out their name, tapping their shoulder, or gently shaking them to see if they respond.

The next step is to summon more advanced medical personnel. If the child is not responsive or if you suspect a serious injury, it's important to call for more advanced medical personnel such as paramedics or emergency medical technicians (EMTs) as soon as possible.

Next, check for breathing and a pulse by checking if the child's airway, breathing, and pulse to make sure they're getting enough oxygen. If the child isn't breathing, begin cardiopulmonary resuscitation (CPR) immediately.

Then, quickly scan for severe bleeding. Look for any severe bleeding, such as from a major wound or a deep cut. If the child is bleeding severely, apply pressure to the wound to stop the bleeding.

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Your question seems incomplete, but I suppose the question was:

"After you size- up the scene, the following are steps involved with performing a primary assessment for a child. Place them in the order in which they should occur.

1. summon more advanced medical personnel

2. check the patient for responsiveness

3. quickly scan for severe bleeding

4. check for breathing and a pulse."

The radius of the Earth is 6370 km. If a satellite orbits 150 km above the Earth's surface, what is the velocity of the orbit? The Earth's mass is 5.97 × 1024 kg. Give your answer in m-s¹, to three significant figures and do not include units.​

Answers

Answer:

Approximately [tex]7.61 \times 10^{3}\; {\rm m\cdot s^{-1}}[/tex].

Explanation:

Add the radius of the Earth to the altitude of the satellite to find the radius of the orbit:

[tex]\begin{aligned}r &= (6370 + 150)\; {\rm km} \\ &= 6880\; {\rm km} \\ &= 6.88\times 10^{6}\; {\rm m}\end{aligned}[/tex].

Look up the gravitational constant:

[tex]G \approx 6.6743\times 10^{-11}\; {\rm m^{3}\, kg^{-1}\, s^{-2}[/tex].

Let [tex]m[/tex] denote the mass of the satellite. At an orbital velocity of [tex]v[/tex], the (centripetal) net force on the satellite would be:

[tex]\displaystyle (\text{net force}) = \frac{m\, v^{2}}{r}[/tex].

Let [tex]M[/tex] denote the mass of planet Earth. At a distance of [tex]r[/tex] from the center of the Earth, the gravitational attraction on the satellite would be:

[tex]\displaystyle (\text{gravitational attraction}) = \frac{G\, M\, m}{r^{2}}[/tex].

When the satellite is at the correct orbital velocity, the net force on the satellite would be equal to the gravitational attraction from the Earth. In other words:

[tex]\displaystyle (\text{net force}) = (\text{gravitational attraction})[/tex].

[tex]\displaystyle \frac{m\, v^{2}}{r} = \frac{G\, M\, m}{r^{2}}[/tex].

Rearrange the equation and solve for orbital velocity [tex]v[/tex]:

[tex]\begin{aligned}v^{2} &= \frac{G\, M}{r}\end{aligned}[/tex].

[tex]\begin{aligned}v &= \sqrt{\frac{G\, M}{r}} \\ &\approx \sqrt{\frac{(6.6743 \times 10^{-11})\, (5.97 \times 10^{24})}{6.88 \times 10^{6}}}\; {\rm m\cdot s^{-1}} \\ &\approx 7.61 \times 10^{3}\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

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