Answer:ruedas (con las masas concentradas en las llantas). La rueda izquierda tiene una masa de 2 kg y un radio de 23,1 cm. La rueda derecha tiene una masa de 2,1 kg y un radio de 30,77 cm. La masa colgante de la izquierda es de 2 kg y la de la derecha de 1,69 kg.
Explanation:
Which type of spectrum can we use to determine the chemical composition of
interstellar gas clouds?
In the electromagnetic spectrum, EM radiation includes radio waves, visible light, and gamma rays.
What is a spectrum?
The characteristic wavelengths of electromagnetic radiation (or a subset thereof) emitted or absorbed by a material, atom, or molecule are called spectra. A spectrum is a state that can vary continuously along a continuum and is not limited to a set of values. After passing through a prism, visible light takes on a rainbow of colors, as the term was originally used scientifically in optics.
We study the electromagnetic radiation, or EM radiation, that interstellar clouds emit and receive from them. The range of this EM radiation includes radio waves, visible light and gamma rays in the electromagnetic spectrum.
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What is a trench? Where would trenches typically be located?
Answer:
The deepest part of earth or oceans. They are most commonly found in oceans however
Explanation:
determine the magnitude and location of the resultant of the distributed load. (you must provide an answer before moving to the next part.)
The magnitude of the resultant would be 40 N, the location of the resultant is 0 m.
What is resultant?Resultant is a term used to refer to the combined effect of two or more forces acting on an object. It is the vector sum of the individual forces acting on the object, and can be determined by adding the individual vectors of the forces together.
The magnitude of the resultant of the distributed load can be calculated by summing the forces at each point and then resolving them into components. The location of the resultant can then be determined by calculating the moment of the distributed load.
For example, if the load is distributed over a distance of 4 m and has a magnitude of 10 N/m,
the magnitude of the resultant would be 40 N.
This can be calculated by summing the forces at the start and end points (40 N = 10 N + 10 N + 10 N + 10 N).
The location of the resultant can then be determined by calculating the moment of the distributed load.
This is done by finding the sum of the moments at each point and then dividing by the total force (location = moment / force).
In this case, the moment at each point is 0 Nm, so the location of the resultant is 0 m.
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Complete Question is attached Below:
An airplane with an airspeed of 140 km/h lands on a runway where the wind speed is 40 km/h . What is the landing speed of the plane if the wind is head on? as well as If the wind is a tailwind, coming from behind the airplane? and lastly What would be the landing speed of the 140- km/h plane landing in a headwind of 140 km/h ?
When we use the concept of the resultant speed to obtain the landing speed we have it as 146 m/s.
What is the landing speed?We would need to resort to talking about the resultant speed in this context. We know that the speed that the airplane would use to land is what we call the resultant speed of the air plane as we have it here.
We can now say that;
Resultant speed =√ (140)^2 + (40)^2
= 146 m/s
Thus we see that the speed of the airplane when the airplane is found to be landing is about 146 m/s.
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A swimmer swims north across a river that flows at 0.20m/s from west to east. If the speed of the swimmer is 0.15m/s relative to still water, what is the swimmer's velocity relative to the river bank?
Answer:
The swimmer's velocity relative to the river bank is 0.35 m/s east.
Explanation:
This can be determined by adding the velocities together in the direction of the current. The velocity of the swimmer relative to still water (0.15m/s) and the velocity of the river (0.20m/s) must be added together in the eastward direction, resulting in a total velocity of 0.35m/s east.
An electron initially at rest accelerates through a potential difference of 1 V, gaining kinetic energy KEe, whereas a proton, also initially at rest, accelerates through a potential difference of - 1 V, gaining kinetic energy KEp. Which of the following relationships holds?
The electron gains more kinetic energy than the proton when accelerated through a potential difference of 1 V.
The relationship between the kinetic energies of the electron and proton can be determined using the formula for the kinetic energy of a particle:
[tex]KE = (1/2)mv^2[/tex]
[tex]V = (q/m)d[/tex]
where V is the potential difference, q is the charge, m is its mass, and d is the distance .
For the electron, [tex]V = 1 V[/tex]and[tex]q/m = -1.6 x 10^-19 C/kg[/tex], so its final velocity is:
[tex]v_e = sqrt((2qV)/m) = sqrt((2*(-1.6 x 10^-19)*1)/9.11 x 10^-31) = 5.93 x 10^6 m/s[/tex]
For the proton, [tex]V = -1 V and q/m = 1.6 x 10^-19 C/kg,[/tex] so its final velocity is:
[tex]v_p = sqrt((2qV)/m) = sqrt((2*(1.6 x 10^-19)*(-1))/1.67 x 10^-27) = 7.16 x 10^5 m/s[/tex]
Substituting these values into the formula for kinetic energy, we get:
[tex]KE_e = (1/2)9.11 x 10^-31(5.93 x 10^6)^2 = 1.63 x 10^-17 J[/tex][tex]KE_p = (1/2)1.67 x 10^-27(7.16 x 10^5)^2 = 0.84 x 10^-17 J[/tex]
Therefore, we have:
[tex]KE_e > KE_p[/tex] , This is because the electron has a much smaller mass than the proton, so it experiences a much larger acceleration and gains more velocity and kinetic energy.
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find the center of mass of a right-circular cone with a base radius r, height h, and a non- uniform mass density varies as the square of the distance from apex (tip of the cone).
The center of mass of a right-circular cone with a base radius r, height h, and a non-uniform mass density varies as the square of the distance from apex (tip of the cone) is:
ρ(x, y, z) = k * (√(x^2 + y^2 + z^2))^2
where k is a constant of proportionality.
Find Center of Mass ConeTo find the center of mass of a right-circular cone with a base radius "r" and height "h", and a non-uniform mass density that varies as the square of the distance from the apex, we need to use the following formula:
Let "m" be the total mass of the cone, then the center of mass can be found using the following formulas for the x, y, and z-coordinates:
x-coordinate:
x_cm = (1/m) * ∫∫∫_V x * ρ(x, y, z) * dV
y-coordinate:
y_cm = (1/m) * ∫∫∫_V y * ρ(x, y, z) * dV
z-coordinate:
z_cm = (1/m) * ∫∫∫_V z * ρ(x, y, z) * dV
where V is the volume of the cone, ρ(x, y, z) is the mass density function, and the integration is performed over the entire volume of the cone.
Since the mass density varies as the square of the distance from the apex, we have:
ρ(x, y, z) = k * (√(x^2 + y^2 + z^2))^2
where k is a constant of proportionality.
Substituting this into the above equations, we can find the center of mass of the cone.
The final result will depend on the specific values of r, h, and k, and the integration may be challenging to perform analytically. But numerical integration methods can be used to approximate the center of mass with good accuracy.
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Calculate the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV.
The de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV will be 1.242 nm.
de Broglie wavelength is λ
λ = hC/eV₀ [V₀ = 1 kV]
λ = (hC/e) (1/V₀) [hC/e = 12.42 × 10⁻⁷]
λ = (12.42 × 10⁻⁷) (1/10³)
λ = 1.242 × 10⁻⁹ m
λ = 1.242 nm
Therefore, the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV will be 1.242 nm.
de Broglie wavelength is an essential concept while exploring quantum mechanics. The wavelength (λ) that is associated with an object in reference to its momentum and mass is learned as the de Broglie wavelength. A particle's de Broglie wavelength is inversely proportional to its force.
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A long, straight wire carries a current of 8.00A. At one point, a proton, 7.00mm from the wire travels at 4.00×
[tex] {10}^{8} [/tex]
ms parallel to the same direction as the current Find the magnetic force that is acting on the proton because of the magnetic field produced by the wire.
Answer:
Explanation:
jajs poza
A ball is in motion. At some point in its motion, its instantaneous acceleration vector is perpendicular to its velocity vector. At this point in its motion, which statement is true?
The ball changes direction without changing its speed
At that point in its motion, the ball changes direction without changing its speed, is the a true statement.
What is instantaneous acceleration?Instantaneous acceleration refers to the rate of change of an object's velocity at a specific point in time. It measures the change in an object's velocity over an infinitesimal amount of time and is the derivative of velocity with respect to time.
This statement is true because when the acceleration vector is perpendicular to the velocity vector, it means the ball is changing direction without changing its speed. The direction of the acceleration vector determines the change in direction, and the magnitude of the acceleration vector determines the rate of change in speed. If the acceleration vector is perpendicular to the velocity vector, it means that the direction is changing, but the speed is not changing.
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a subway train starts from rest at a station and accelerates at a rate of 1.60m/s2 1.60 m / s 2 for 14.0 s s . it runs at constant speed for 70.0 s s and slows down at a rate of 3.50m/s2 3.50 m / s 2 until it stops at the next station. Find the total distance covered.
The total distance covered by the subway train is 1796.5 m. The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. The equations apply in horizontal dimension are
v₁ = v₀ + at
v₁² = v₀² + 2ax
x = v₀t + ½ at²
Where
v₀ = initial velocityv₁ = final velocitya = accelerationt = timex = distanceA subway train starts from rest at a station.
It accelerates at a rate of 1.60 m/s² for 14.0 s. It runs at constant speed for 70.0 s.It slows down at a rate of 3.50 m/s² until it stops at the next station.Find the total distance covered!
When it accelerates, the distance is
x₁ = v₀t + ½ a₁t₁²
x₁ = 0 + ½ (1.60)(14.0)²
x₁ = 0 + 0.8(196)
x₁ = 156.8 m
The final speed after 14 s is
v₁ = v₀ + at
v₁ = 0 + (1.6)(14.0)
v₁ = 22.4 m/s
The speed later will be constant for t₂ = 70.0 s.
When it moves with a constant speed (22.4 m/s), the distance is
x₂ = v₁t₂
x₂ = 22.4(70)
x₂ = 1568 m
When it slows down until it stops (v₂ = 0), the distance is
v₂² = v₁² - 2a₂x₃
0 = 22.4² - 2(3.5)x₃
22.4² = 2(3.5)x₃
501.76 = 7x₃
x₃ = 71.68 m
The total distance covered will be
x = x₁ + x₂ + x₃
x = 156.8 m + 1568 m + 71.68 m
x = 1796.48
x = 1796.5 m
Hence, the subway train traveled for a total distance of 1796.5 m.
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refrigerant migration into the compressor crankcase will not usually occur if the temperature where the compressor is located is kept well above the
Refrigerant migration into the compressor crankcase will not usually occur if the temperature where the compressor is located is kept well above the refrigerant's saturation temperature.
Refrigerant migration occurs when the refrigerant vapor in the system condenses into a liquid and migrates into the compressor crankcase oil. If the temperature around the compressor is kept well above the saturation temperature, the refrigerant remains in a vapor state and does not condense, thereby reducing the likelihood of refrigerant migration into the compressor crankcase.
It is important to maintain the proper temperature in the compressor area to prevent refrigerant migration as it can cause several issues such as decreased compressor efficiency, reduced system performance, and increased oil degradation.
Additionally, the presence of refrigerant in the oil can cause oil degradation and system contamination, which can ultimately lead to compressor failure. Therefore, it is important to keep the temperature in the compressor area well above the refrigerant's saturation temperature to prevent refrigerant migration and ensure the longevity and proper operation of the refrigeration system.
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Suppose you have two conductors of different sizes and different initial charges. You connect them with a wire. What one measurement will then be equal for both of them?
The charge of the two capacitors will be equal when they are connected. Similarly their electrical potential will be equal. The charge distribution to attain equilibrium is making them equally charged.
What is capacitance?The capacitance of a device is its ability to store charge. Such devices are called capacitors. The capacitance of a capacitor is dependent on the electrical potential and charge as well as their size and shape.
According to the law of conservation of electrical charges, the charge lost by one body is equal to the charge gained by the other body. Hence, when two differently charged capacitors when connected each other, the start charge transfer until they attain equal charges.
Therefore, the measurement that is equal for the capacitors here connected by the wire is charge.
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Charge will be equal on both conductors after connecting with wire.
Electric charge is the physical property of matter that causes that matter to experience a force when placed in an electromagnetic field. Electric charge can be positive or negative.
Given,
Two conductors of different sizes and different initial charges are connected with a wire,
Connecting with a wire will start flow of charge until charges on both conductors become equal.
Hence, charge will then be equal for both conductors.
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what happens to the momenta of a system of two dynamics carts that start out at rest and then explode?
The momenta of the two dynamic carts that start out at rest and then explode would be altered drastically.
What is dynamic carts?Dynamic carts are shopping carts that are programmed to track data about customer purchases and preferences. This data is used to provide personalized product recommendations and discounts to customers. Dynamic carts are powered by advanced algorithms that analyze customer purchasing behavior and analyze it in real-time.
When the carts explode, the energy released from the explosion will create an equal and opposite reaction, pushing each cart in the opposite direction. This means that the momentum of each cart will be altered depending on the amount of energy released from the explosion. The total momentum of the system will remain the same, since the momentum of the first cart will be equal and opposite to that of the second cart.
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A 10 kg object dropped from a certain window strikes the ground in 2.0 s. Neglecting air resistance, a 5 kg object dropped from the same window strikes the ground in?
A 10 kg object dropped from a certain window strikes the ground in 2.0 s. Neglecting air resistance, a 5 kg object dropped from the same window strikes the ground in 1.41 seconds.
The time it takes an object to fall to the ground is determined by its initial velocity, which is zero, and its acceleration due to gravity, which is constant at 9.8 m/s² on the surface of the Earth.
The distance fallen can be calculated using the equation:
d = 1/2 × a × t²,
where d is the distance, a is acceleration and t is time.
We can assume that the height from which both the 10 kg and 5 kg objects were dropped is the same, so the distance fallen is the same for both. We can rearrange this equation to solve for time:
t = √(2d/a)
t = √(2 × d / 9.8)
t = √(2 × 2.0² / 9.8)
t = √(8 / 9.8)
t = 1.41 s
Therefore the 5 kg object strikes the ground in 1.41 seconds.
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A lead weight falls from a height of 6 m onto a muddy surface. It comes to rest after penetrating 0.4 cm into the surface. What was the magnitude of the average acceleration during the impact? How long did it take to stop?
The duration of motion is 1.11 seconds, and the average acceleration during impact is 9.8 m/s2.
Average lead weight acceleration during impact:
The gravitational pull of 9.8 m/s2 will cause the lead weight to descend.
Lead weight's time of motion is given by t = 2h/g.
where:
The entire height of the fall is given by h, which is equal to 6 metres plus 0.4 centimetres, or 6.004 metres per second.
t = 1.11 s
As a result, the period of motion is 1.11 s, and the average acceleration during impact is 9.8 m/s2.
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A parallel plate capacitor with plates of area (A) and plate separation (d) is charged so that the potential difference between its plates is (V). While the capacitor is still connected to the power source and its plate separation is decreased to d/4, which statement is correct? The charge on the plates is decreased to one-fourth its original value. The capacitance is unchanged. The voltage between the plates is decreased to one-fourth its original value. The charge on the plates is increased four times its original value. The voltage between the plates is increased four times its original value. The charge on the plates is unchanged.
The correct statement is (d) The charge on the plates is increased four times its original value.
What is parallel plate capacitor?
A parallel plate capacitor is a type of capacitor that consists of two parallel conductive plates separated by a dielectric material. It is a type of capacitor used in electrical circuits to store electrical energy. The plates are usually made of metal and the dielectric material is usually a thin non-conductive material like paper or plastic. The size of the capacitor is determined by the distance between the plates and the dielectric material.
This is because the charge on the capacitor plates is proportional to the voltage across the plates and the capacitance, which is given by the formula C = ε_0 * A / d, where ε_0 is the electric constant and A is the area of the plates.
When the plate separation is decreased to d/4, the capacitance of the capacitor becomes C' = ε_0 * A / (d/4) = 4 * ε_0 * A / d, and thus the charge on the plates becomes Q' = C' * V = 4 * Q.
Therefore, The charge on the plates is increased four times its original value is the correct answer.
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A solid nonconducting sphere is inside a solid nonconducting spherical shell, as shown in the figure. A total charge +Q is evenly distributed throughout the sphere and is also evenly distributed throughout the shell. Which of the following statements is a correct claim about the electric field at point X between the sphere and shell and has a valid supporting statement? (A) The electric field points to the left, because the electric field from sphere is zero and the electric field from the shell is directed to the left (B) The electric field points to the left, because a Gaussian sphere concentric with the sphere X on its surface only encloses the charge on the inner sphere. c) The electric field points to the right, because the electric field from the shell has a larger magnitude that the electric field from the sphere d) The electric field is zero, because a Gaussian sphere concentric with the sphere with X on its surface encloses zero net charge. (E) The electric field is zero, because point X is inside a nonconducting shell.
The electric field is zero, because a Gaussian sphere concentric with the sphere with X on its surface encloses zero net charge. The correct claim is (D).
The electric field at point X is the vector sum of the electric fields from the sphere and the shell. However, since the total charge on both the sphere and the shell is evenly distributed, the electric field from the sphere will be exactly canceled by the electric field from the shell at any point inside the sphere. Therefore, the net electric field at point X will be zero.
This can be proven by using a Gaussian surface, which is a hypothetical sphere drawn around point X. Since the electric field is spherically symmetric, we can choose the Gaussian surface to be a spherical shell centered at X.
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Two 17cm -long thin glass rods uniformly charged to +16nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1, E2, and E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?
The required electric field strengths are calculated to be E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
Length of the two glass rods is given as, L = 17 cm = 0.17 m
Charge on them = 16 nc = 16 × 10⁻⁹ C
Distance between the rods is given as 4 cm = 0.04 m.
Electric charge due to a single glass rod can be given by,
E = Q/ (2π ε₀ r L) ----(1)
(1) can be used to determine E₁, E₂, E₃ because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced.
E₁ = Q/ (2π ε₀ r L) × [1/0.01 - 1/0.03]
⇒ (16 × 10⁻⁹)/(2× 3.14× 8.85 × 10⁻¹² × 0.17) × (66.67)
⇒ (16× 66.67 × 10³)/(9.45) = 112.88 × 10³ N/C
Let us find E₂,
E₂ = Q/ (2π ε₀ r L) × [1/0.02 - 1/0.02] = 0
And E₁ = E₃.
Thus, E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
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a dog lifts a 1.5 kg bone straight up through a distance of 0.2 m. How much work was done by the dog?
Answer:
see below
Explanation:
we have ,
mass = 1.5kg height = 0.2 mWe know,
Work = mgh
Work = 1.5kg * 10m/s² * 0.2m
Work= 3J
and we are done!
When striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.2 m/s in 0.14 s . a. What is the acceleration of the pike during this strike? Express your answer in meters per second squared. b. How far does the pike move during this strike? Express your answer in meters.
The pike's acceleration during the strike is 30m/s² and the pike moves 0.049 meters.
What is acceleration?An object's rate of change in velocity (speed and direction) over a predetermined amount of time is known as acceleration.
How do you determine it?a. The following acceleration formula can be used to determine the pike's rate of acceleration during the strike:
a = Δv / Δt
where v denotes the velocity change and t the time change.
When we enter the values provided, we get:
acceleration = (4.2 m/s - 0 m/s) / 0.14 s = 30m/s²
The pike's acceleration during the hit is 30m/s².
b. The formula for distance based on initial velocity, final velocity, acceleration, and time can be used to calculate the distance the pike travels during the strike:
Distance = (1/2) * Acceleration * Time * Initial Velocity * Time
Given that the pike's initial speed is 0 m/s, the distance can be computed as follows:
Distance = 0 m/s * 0.14 s + (1/2) * 30 m/s * 0.14 s
=0.049 m.
Due to this hit, the pike moves 0.049 meters.
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if the spring db has an unstretched length of 2 m, determine the stiffness of the spring to hold the 40-kg crate in the position shown.
Spring force P on the cable if the spring is compressed 0.025 m when the mechanism is in the position shown is 0.198 kN.
When the mechanism is in the position indicated, the force P on the cable is 0.198 kN if the spring is compressed 0.025 m in 40 kg
When a spring mechanism is adjusted by a length away from its balance length, it exerts a force on items fastened to its end that is continuously coordinated towards its harmonic position. F = - kx. The term "spring steady" refers to the proportional constant k. It is a percentage of the solidity of the spring. The following power is negative (moving towards the left) if x is positive (uprooting to the right), and vice versa. As a result, the spring force often works to restore mass to its harmonious position. The force P on the cable is therefore 0.198 kN. when, the mechanism is in the position shown.
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8. using the information given in chapters 2 and 3, describe the conditions that induce brittle fracture in an otherwise ductile piece of metal.
Rapid deformation rates, cooler temperatures, the existence of a high stress concentration degree of stress, radiation damage, and corrosion can all result in brittle fracture (including hydrogen embrittlement).
What degree of temperature is considered?When temperatures exceed 90 degrees, you are in "hot" terrain from just a strictly thermometric perspective.
Is 37 temperature hot or cold?The average body temperature is between 36 and 37 degrees Celsius, however this varies based on age, exercise levels, time of day, and measuring method. Colds, the flu, and COVID-19 are examples of viral respiratory illnesses that can raise a person's temperature.
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Electric toothbrushes can be effective in removing dental plaque. One model consists of a head 1.10 cm in diameter that rotates back and forth through a 70.0 degrees angle 7600 times per minute. The rim of the head contains a thin row of bristles.Part A: What is the average angular speed in each direction of the rotating head, in rad/s?Part B: What is the average linear speed in each direction of the bristles against the teeth? (to two sig. figures)Part C: Using your own observations, what is the approximate speed of the bristles against your teeth when you brush by hand with an ordinary toothbrush? (Estimate that the toothbrush turns back and forth through 45 degrees five times per second) (in cm/s, two sig. figures).
The average angular speed in each direction of the rotating head is 9.42 rad/s.
The average linear speed in each direction of the bristles against the teeth is 5.09 cm/s.
The approximate speed of the bristles against the teeth when brushing by hand with an ordinary toothbrush is 1.26 cm/s.
Part A: The formula ω = Δθ/Δt can be used to determine the rotating head's average angular speed in each direction.
Where Δθ denotes the angular displacement, Δt denotes the rotational time, and ω denotes the angular speed.
In this instance,
Δt = 1/(7600/2) s/rotation, and Δθ= 70.0 degrees = 70.0 x (π/180) radians.
Thus, ω = (70.0 x (π/180)) / (1/(7600/2)) = 9.42 rad/s is the average angular speed in each direction.
Part B: The following equation can be used to determine the average linear speed of the bristles against the teeth:
v = rω
where r is the head's radius (0.55 cm), v is the linear speed, and ω is the angular speed.
The average linear speed is therefore v = 0.55 x 9.42 = 5.09 cm/s in each direction (rounded to two significant figures)
Part C: Although it is challenging to measure precisely, it is possible to estimate the speed of the bristles against the teeth when brushing by hand with a regular toothbrush. The average linear speed can be estimated using the formula v = rΔθ/Δt if we suppose that the bristles rotate through an average displacement of 45 degrees five times each second.
Where Δθ = 45 degrees, Δt = 1/5 s, and r = the radius of the bristles (estimated as 0.2 cm).
So, the average linear speed is approximately:
v = 0.2 x (45 x (π/180)) / (1/5) = 1.26 cm/s (rounded to two significant figures).
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A student throws a 0.140-kg ball straight upwards to a height of 3.10 m. How much work did the student do?
Answer:
The student did 4.54 joules of work. This can be determined by using the formula W = mgh, where W is the work done, m is the mass of the ball, g is the acceleration due to gravity, and h is the height to which the ball is thrown. In this case, m = 0.140 kg and h = 3.10 m, so W = 0.140 x 9.8 x 3.10 = 4.54 joules.
You are designing a diving bell to withstand the pressure of seawater at a depth of 25.0 m.
a. What is the gauge pressure at this depth? (You can ignore changes in the density of the water
with depth) (2 marks)
b.
At this depth, what is the net force due to the water outside and the air inside the bell on a
circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the
pressure at the surface of the water? (You can ignore the small variation of pressure over
the surface of the window.) (3 marks)
Psw 1.03x10³ kgm³
Psw
=
-3
1.03 x 10³kgm ³
p=pgh
F = PA
a. The gauge pressure at this depth is 250 kPa.
b. The net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter is 7.5 kN.
What do you mean by pressure?
Pressure is a measure of the force applied over a given area and is usually expressed in units such as pascals (Pa) or pounds per square inch (psi). It is a fundamental physical quantity found in all areas of physics, including fluid dynamics, thermodynamics, and mechanics.
a. The pressure at a certain depth in a body of water is given by the equation P = ρgh, where ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water. In this case, the gauge pressure at a depth of 150 m is equal to 250 kPa.
b. The net force on the glass window can be calculated by using the formula F = Pπr2, where P is the pressure, π is the mathematical constant, and r is the radius of the window. In this case, the net force on the window is 7.5 kN, which can be calculated as 7.5kN = 250kPa × (0.15m)2 × 3.14.
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Suppose a particle is accelerated through space by a 10-N force. Suddenly the particle encounters a second force of 10 N in the opposite direction of the first force. The particle is: a) *brought to a rapid halt b) decelerates gradually to a halt c) continues at the speed it had when it encountered the second force d) theoretically tends to accelerate toward the speed of light e) none of these
The particle cannot accelerate toward the speed of light if no acceleration is applied. The correct answer is e) none of these.
The particle encounters a force of 10 N in the opposite direction of the initial force, creating an unbalanced force. This means that the particle experiences an acceleration of 10 N in the opposite direction, decelerating from its initial velocity.
However, since the acceleration caused by the second force is equal to the acceleration caused by the first force, the particle does not come to a rapid halt, but rather its velocity gradually decreases until it comes to a stop. This means that the correct answer to the question is b) decelerates gradually to a halt.
In order for the particle to theoretically tend to the speed of light, it must experience a constant acceleration in any direction.
Since the two forces are in opposite directions and of equal magnitude, the resultant force is zero, meaning that the particle experiences no acceleration and therefore its speed remains the same.
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Suppose a 0.3-kg mass on a spring that has been compressed 0.10 m has elastic potential energy of 1 J. What is the spring constant?
a. 10 N/m
b. 20 N/m
c. 200 N/m
d. 300 N/m
The spring constant of the spring is 200 N/m.
option C.
What is the spring constant of the spring?The spring constant of the spring is calculated by applying the following formula as shown below;
.
Mathematically, the formula for energy stored in a spring is given as;
U = ¹/₂kx²
where;
k is the spring constantx is the extension of the springk = ( 2U ) / ( x² )
k = ( 2 x 1 J ) / ( 0.1 m )²
k = 200 N/m
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A solid rectangular block measures
[tex]1m \times 0.8m \times 0.6m[/tex]
and floats freely in a liquid of density 1354.6kg/m3.if the depth of the liquid 150.45m up the blocks side , find the density of the block
The block has a density of 16309.2 kg/m3.
Why is density important?The density of a material is an indicator of how heavy it is in relation to its size. If an object is submerged in water, it will float if its density is lower than that of the water, and sink if it has a higher density. A differentiating characteristic that is unrelated to a substance's volume is its density.
We must apply Archimedes' principle, which states that the weight of the fluid that is displaced by an object when it is immersed in a fluid equals the buoyant force acting on the item.
Let's start by determining the block's weight:
mass = density * volume
= density_block * length * width * height
weight_block = mass * g
= density_block * length * width * height * g
where g is the acceleration due to gravity (9.81 m/s²).
Next, let's find the weight of the displaced fluid:
volume_submerged = length * width * depth_submerged
weight_fluid = density_fluid * volume_submerged * g
Since the block is floating freely, the weight of the displaced fluid must be equal to the weight of the block:
density_block = density_fluid * volume_submerged / (length * width * height)
Plugging in the given values, we get:
density_block = 1354.6 kg/m³ * (0.8 m * 0.6 m * 150.45 m) / (1 m * 0.8 m * 0.6 m)
= 16309.2 kg/m³.
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Object x is dropped from a height of 65m at the same instant object y is thrown vertically upwards with a velocity of 5m^-1. Calculate the distance at which the two objects pass each other
The path travelled by a projectile is known as its trajectory. The distance at which the two objects pass each other is 16.9 m.
What is a projectile?Any object which is thrown into space and the only force acting on it is the force of gravity. The motion of a projectile is known as the projectile motion.
The height covered by the projectile from ground is:
h = ut - 1/2 gt²
h = 5t - 1/2 × 9.8 × t²
h = 5t - 4.9t² (1)
When projectile is thrown downward, u = 0
65 - h = 1/2 gt²
65 - (5t - 4.9t² ) = 4.9t²
65 = 5t
t = 65/5 = 13 s
h = 65t - 4.9t²
= 65 × 13 - 4.9 × 169
= 16.9 m
Thus the distance at which the two objects pass each other is 16.9 m.
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