an atom includes 8 electrons, 8 protons, and 8 neutrons. what is the mass of the atom?

The volume occupied by 0.108 mol of helium gas at a pressure of 0.92 atm and a temperature of 313 K is 2.3 L.

The gas laws involve the relationship between the pressure, volume, and temperature of a gas. The ideal gas law can be used to determine the volume of gas that a certain amount of substance occupies at a particular pressure and temperature. The ideal gas law equation is:

PV = nRT

where, P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin (K).

To determine the volume of helium gas that is occupying 0.108 moles at 0.92 atm and 313 K, we need to rearrange the ideal gas law equation to solve for V:

V = (nRT)/P

Substituting the values given, we have:

V = (0.108 mol)(0.08206 L atm/mol K)(313 K)/(0.92 atm)

V = 2.28 L

The volume of gas to two significant figures, the volume is 2.3 L.

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DNA polymerase differs from RNA polymerase being that the former synthesizes a double stranded DNA while the latter synthesizes a single stranded RNA.

Polymerase is generally any of various enzymes that catalyze the formation of polymers of DNA or RNA using an existing strand of RNA or DNA respectively as a template.

DNA and RNA polymerase are enzymes responsible for the process of DNA and RNA replication i.e. copy of two identical DNA/RNA molecules from a single strand.

Both DNA polymerase and RNA polymerase share the same end goal i.e. synthesizing nucleic acid in the cell. However, DNA polymerase produces double stranded DNA, whereas RNA polymerase produces single stranded RNA.

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2.32 g of  CO2 will dissolve if the pressure is raised to 1. 35 atm and the temperature will remain the same.

The given data is:

Pressure = 1 atm

Temperature = 20 degrees =  293 K

CO2 weight = 1.72g

Water weight = 1L

Henry's law is used which defines that the amount of gas dissolved in a fluid is proportional to the partial pressure of the gas beyond the liquid.

Mathematically,

C = kH * P

C is the concentration of the gas given.

1.72 g CO2 / 44.01 g/mol = 0.039 mol CO2

C = 0.039 mol/L

kH = C/P

kH = 0.039 mol/L / 1 atm = 0.039 mol/(L*atm)

CO2 when the pressure is raised to 1.35 atm:

P' = 1.35 atm

C' = kH * P'

C' = (0.039 mol/(L*atm)) * 1.35 atm

C' = 0.0527 mol/L

The amount of CO2 dissolved in the water is

m = C' * M * V

m = 0.0527 mol/L * 44.01 g/mol * 1 L

m = 2.32 g

Therefore, a pressure of 1.35 atm is required and at a temperature of 20°C,  makes 2.32g of CO2 will dissolve.

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b. The temperature of the equilibrium mixture is increased at constant volume. The number of moles of CO (g) in the container will increase when the temperature is increased. The equation given is an exothermic reaction, so increasing the temperature favors the reaction to the right, releasing heat energy and producing more moles of CO (g).

The given equilibrium equation is CO (g) + H2(g) <--> C(s) + H2O (g) ∆H˚ = -131 kJ. The question asked to determine whether the number of moles of CO (g) in the container will increase, decrease or stay the same for different disturbances.

b. The temperature of the equilibrium mixture is increased at constant volume. When the temperature is increased at constant volume, the equilibrium will shift towards the product side in order to counteract the increase in temperature. Since CO (g) is a reactant, the number of moles of CO (g) will decrease after the disturbance is applied, so the correct answer is "decrease."

c. The volume of the container is decreased at constant temperature.

When the volume of the container is decreased at constant temperature, the pressure inside the container will increase, which will cause the equilibrium to shift towards the side with fewer gas moles to counteract the increase in pressure. CO (g) has one gas mole, and H2O (g) and H2 (g) have two gas moles. Therefore, the equilibrium will shift towards the side with fewer gas moles, which is the product side. This means that the number of moles of CO (g) will decrease, so the correct answer is "decrease."

d. The graphite pellets are pulverized. When the graphite pellets are pulverized, the surface area of C(s) will increase. This will increase the rate of reaction from the reactant side to the product side. The reaction will continue until the equilibrium is reestablished, but the number of moles of CO (g) will not change, so the correct answer is "stay the same." Therefore, the correct answer is b. The temperature of the equilibrium mixture is increased at constant volume.

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a) an acid that produces one hydrogen atom. Monoprotic acid refers to an acid that donates only one hydrogen ion (H+) in an aqueous solution.

An acid that can only donate one hydrogen ion (H+) in an aqueous solution is referred described as being "monoprotic." This indicates that just one hydrogen ion may be emitted for each acid molecule. In contrast, polyprotic acids are able to contribute a number of hydrogen ions in solution.

Titration of a monoprotic acid solution with NaOH causes the NaOH to react with the acid's H+ ions to produce water and salt. The concentration of the acid may be calculated from the quantity of NaOH needed to fully neutralize the H+ ions in the acid solution.

Acetic acid and hydrochloric acid (HCl) are examples of monoprotic acids (CH3COOH).

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The average mass of chemistrium (Ch) in amu is: 12.5 amu.

Chemistrium is an element with the atomic number 106. It is a transactinide synthetic element with an atomic weight of 268 u. Until 2009, this element was known as unnilhexium (Unh). It was named chemistrium in honor of the chemistry in recognition of the Moscow-based Joint Institute for Nuclear Research's contributions to the synthesis of new elements.

If a sample of the element chemistrium (Ch) contains 100 atoms of Ch-12 and 10 atoms of Ch-13 (for a total of 110 atoms in the sample), the average mass of chemistrium in amu can be calculated as follows:

Average mass of Ch = [(number of atoms of Ch-12 x atomic weight of Ch-12) + (number of atoms of Ch-13 x atomic weight of Ch-13)] / Total number of atoms of Ch= [(100 x 12.000000) + (10 x 13.003355)] / 110= [1200.0000 + 130.03355] / 110= 1330.03355 / 110= 12.18212318 amu, which is rounded off to 12.5 amu.

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Menthol, like methanol, occurs naturally and has several isomers. One structural characteristic of menthol that is responsible for it having enantiomers is that it has a chiral center.

Chiral centers are atoms with four different substituents attached to them, and they are a type of stereocenter. Menthol has a chiral center, which means it has two possible enantiomers.

Enantiomers are molecules that are mirror images of each other and cannot be superimposed on one another.

The two enantiomers of menthol are (1R,2S,5R)-(−)-menthol and (1S,2R,5S)-(+)-menthol. They have identical physical and chemical properties, except for their interaction with polarized light. This is due to the fact that they rotate plane-polarized light in opposite directions.

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The equations that relate the partial derivatives of pressure, volume, temperature, and entropy of a simple compressible system are called Maxwell relations.

Maxwell's relations or thermodynamic equations of state are the set of equations in thermodynamics that relate partial derivatives of properties of a thermodynamic system to each other. The Maxwell relations arise from the fundamental relations between thermodynamic potentials.The Maxwell relations relate the partial derivatives of thermodynamic properties such as pressure, volume, temperature, and entropy. They are a consequence of the symmetry of the second derivative of the thermodynamic potential.

The four thermodynamic potentials are internal energy, enthalpy, Helmholtz free energy, and Gibbs free energy. The relations are named after James Clerk Maxwell, who presented them as part of his 1871 textbook "Theory of Heat."The Maxwell relations are named after James Clerk Maxwell, a Scottish physicist who first published them in 1871 in his book Theory of Heat. They are applied in thermodynamics to help connect and calculate various thermodynamic properties of a system.

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The value of the atomic mass of the metal calculated would be too high if the hot metal sample cooled off before it was transferred to the water in the calorimeter.

The atomic mass of an element is defined as the mass of an atom of an element in atomic mass units (amu). One atomic mass unit is defined as 1/12th of the mass of an atom of carbon-12.

The atomic mass of an element can be calculated using the following formula:

Atomic mass = (mass of isotope 1 × % abundance of isotope 1) + (mass of isotope 2 × % abundance of isotope 2) + (mass of isotope 3 × % abundance of isotope 3) + ...

If the hot metal sample cooled off before it was transferred to the water in the calorimeter, the temperature of the sample would have decreased. The decrease in temperature would result in a decrease in the thermal energy of the sample. Consequently, the amount of heat absorbed by the water in the calorimeter would decrease, leading to a lower value of the heat capacity of the metal.

Since the heat capacity is directly proportional to the mass of the sample, a lower value of the heat capacity would lead to a higher value of the atomic mass of the metal calculated. Therefore, the value of the atomic mass of the metal calculated would be too high if the hot metal sample cooled off before it was transferred to the water in the calorimeter.

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17.264 g of 2KI (potassium iodide) is necessary to completely react with 17.3 g of Pb(NO3)2 in a precipitation reaction.

To calculate the mass of the first reactant required, we will use the mole concept.

Let's first write the balanced chemical equation.

A 2KI(aq) + Pb(NO₃)₂ (aq) → PbI₂(s) + 2KNO₃(aq)

We need to find the number of moles of Pb(NO₃)₂.

To do that, we will use the given mass of Pb(NO₃)₂ and its molar mass.

Molar mass of Pb(NO₃)₂ = 207.2 + 3(14.01) + 6(16) = 331.2 g/mol

Number of moles of Pb(NO₃)₂ = mass / molar mass = 17.3 / 331.2 = 0.052 moles

From the balanced chemical equation, we see that 1 mole of Pb(NO₃)₂ reacts with 2 moles of KI.

Therefore, the number of moles of KI required would be twice the number of moles of Pb(NO₃)₂.

The number of moles of KI required = 2 x 0.052 = 0.104 moles

To calculate the mass of KI required, we will use its molar mass.

The molar mass of KI = 39.10 + 126.90 = 166.0 g/mol

Mass of KI required = a number of moles x molar mass = 0.104 x 166.0 = 17.264 g

Therefore, 17.264 g of KI is required to completely react with 17.3 g of Pb(NO₃)₂.

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The electronic configuration for an atom of oxygen is:

1s2 2s2 2p2

The correct options is:

C. This specific electron configuration has one unpaired electron.

Electron configuration can be defined as the specific arrangement of negatively charged electrons in different energy levels around atomic nuclei.

The correct statements about this electron configuration are:

A. The atom of oxygen represented by this configuration will have a charge: This statement is incorrect. The electron configuration provided is for a neutral oxygen atom, which means it has no charge.

B. This specific electron configuration has three unpaired electrons: This statement is incorrect. The 2p subshell contains a total of 4 electrons, which are arranged in 2 orbitals with opposite spins. This means that there are 2 paired electrons and 2 unpaired electrons, not 3.

C. This specific electron configuration has one unpaired electron: This statement is correct. The 2p subshell contains 2 orbitals, each of which can hold a maximum of 2 electrons. Since the 2p subshell contains 4 electrons, there are 2 paired electrons and 2 unpaired electrons, with one unpaired electron in each of the two 2p orbitals.

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The equation that allows you to calculate the mass of sodium in 1.5 grams of sodium chloride correctly is

Mol NaCI / 58.44 g NaCI X mol Na / NaCI X 22.99 g Na / mol Na =.

The mass of the sodium can be calculated with the aid of a mole ratio from the sodium chloride (NaCl). We will need to apply stoichiometric mole ratios to convert between the number of atoms, ions, or molecules in a reaction and the mass or volume of the reactants and goods.

To calculate the mass of sodium in 1.5 grams of sodium chloride, we need to use the following formula:

Mol NaCI / 58.44 g NaCI X mol Na / NaCI X 22.99 g Na / mol Na =

As we can see from the equation, the mass of sodium is determined by multiplying a mol ratio by the number of grams of sodium chloride used.

Answer: A. Mol NaCI / 58.44 g NaCI X mol Na / NaCI X 22.99 g Na / mol Na

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Option A is the correct statement for the process was exothermic that a large amount of heat is released when sodium metal is exposed to chlorine gas.

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Therefore, the constancy in color intensity can be an indicator of a dynamic equilibrium, where the rates of the forward and reverse reactions are equal and the concentrations of reactants and products remain constant over time.

Chemical equilibrium occurs when a reversible reaction takes place, where the reactants can form products and the products can also react to form reactants. At the beginning of the reaction, the reactants are transformed into products, and as the reaction progresses, the concentration of the reactants decreases while the concentration of the products increases. Eventually, a point is reached where the rate of the forward reaction is equal to the rate of the reverse reaction, and the concentrations of the reactants and products remain constant. This state is called chemical equilibrium.

Here,

The constancy in color intensity can indicate the dynamic nature of equilibrium in certain cases. In a chemical equilibrium, the forward and reverse reactions are occurring simultaneously, but at equal rates, resulting in a constant concentration of reactants and products. Many chemical reactions involve colored species, and changes in the intensity of the color can indicate a change in the concentration of the species involved. For example, consider the reaction between iodine and starch:

I2 + starch ⇌ I2-starch complex

In this reaction, the iodine-starch complex is a blue-purple color, while the reactants (iodine and starch) are colorless. As the reaction proceeds, the concentration of the complex increases, leading to an increase in color intensity. However, if the reaction reaches equilibrium, the forward and reverse reactions will be occurring at equal rates, and the concentration of the complex will remain constant. This will result in a constant color intensity, indicating the dynamic nature of the equilibrium.

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When 27 g of iron reacts with oxygen, a total of 8 electrons are transferred.

The balanced equation for this reaction is:  
4Fe + 3O2 → 2Fe2O3

This equation tells us that 4 moles of iron (Fe) react with 3 moles of oxygen (O2) to form 2 moles of iron oxide (Fe2O3).

Molar mass of iron = 55.85 g/mol.

The number of moles: 27 g Fe × (1 mol Fe/55.85 g Fe) = 0.483 mol Fe

Therefore, 27 g of iron is equivalent to 0.483 moles of iron.

0.483 mol Fe × 4 electrons/mol Fe = 1.932 electrons

To convert this value to the number of electrons per 27 g of iron. To do this, we can use Avogadro's number, which tells us the number of particles (including electrons) in one mole of a substance:

1.932 electrons/mol × 6.022 × 10^23 electrons/mol = 1.162 × 10^24 electrons ≈ 8

Therefore, the number of electrons transferred when 27 g of iron reacts is approximately 8.

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Answer:

Explanation: Use the formula density = mass divided by volume

so to get the answer multiply the density by the volume

Answer: 1.63 x (0.25x1000)

we multiply 0.25 by 1000 because we need to use volume in ml instead of L.

Food fats and oils decay through a process known as rancidity, which affects the taste, texture, and flavour of the meal as well as the odour and smell. Unsaturated fatty acid oxidation is what triggers this process.

Rancidity is known to be influenced by time, temperature, light, air, exposed surface, moisture, nitrogenous organic material, and traces of metals.

Unsaturated fatty acids that contain double bonds in their molecules are peroxidation-prone. Lipids can undergo this peroxidation, often known as "oxidative degradation," in one of two ways. Autoxidation is one method, and it's by far the most significant one. A less significant alternative is an enzymatic oxidation. A fatty acid molecule undergoes oxidation when an oxygen ion replaces a hydrogen ion, and the likelihood of autoxidation rises as the number of double bonds increases inside the fatty acid.

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Answer:

   Fatty acids

   Steroids

   Glycolipids

   Triacylglycerols

   Sphingolipids

   Phospholipids

0.566 moles of hydrogen iodide will be formed upon the complete reaction of 0.283 moles of hydrogen gas with excess iodine.

To determine how many moles of hydrogen iodide will be formed, we need to use stoichiometry.

The balanced chemical equation for the given reaction is:-

H₂ (g) + I₂ (s) → 2HI (g)

From the balanced chemical equation, we know that 1 mole of hydrogen reacts with 1 mole of iodine to produce 2 moles of hydrogen iodide.

Since the number of moles of hydrogen is given as 0.283 moles, therefore, the number of moles of iodine required is also 0.283 moles.

Therefore, the number of moles of hydrogen iodide formed = 2 x 0.283 mol= 0.566 mol.

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Answer:

Gravity helps move water into the ground.

A 3.6102 M HI solution has a pH of 1.44. A 9.23102 M HClO4 solution has a pH of 0.036. The mass-based solution with 1.01% HCl has a pH of 2.09 in water.

The concentration of hydrogen ions (H+) in a solution determines the pH, which is a measurement of the solution's acidity or basicity. The pH values of various solutions are measured in the examples provided. Strong acids, HI and HClO4, are present in the first two solutions. Due to its lower pH, HI is a stronger acid than HClO4. The third solution, which comprises a combination of HClO4 and HCl and is weaker than the previous two because of its higher pH level, contains HCl. The pH of the final solution, which contains 1.01% HCl by mass, is 2.09, showing that it is a weak acid.

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The electron transport chain (ETC) is an essential part of cellular respiration, which is a series of molecules that transfer electrons from one molecule to another used by cells to convert nutrients into energy.

This starts with the oxidation of molecules such as glucose, which releases electrons that are then transferred to a series of electron carriers in the ETC. The electron carriers are molecules that hold the electrons and can transfer them to other molecules which is known as redox reactions. As the electrons move through the ETC, they release energy which is used to form a proton gradient that is then used to drive the synthesis of ATP, the energy currency of the cell. The ETC is an essential part of cellular respiration as it is the process responsible for generating the energy necessary for cells to function.

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The appropriate unit for a third-order rate constant is  The L² mol-² s-¹. A third-order reaction is a type of chemical reaction where the concentration of each molecular responding determines how quickly the reaction proceeds.

A reaction rate constant, or reaction rate coefficient, k, quantifies the rate and direction of a chemical reaction in chemical kinetics. The rate constant, also known as the specific rate constant, is the proportionality constant in the equation expressing the relationship between the rate of a chemical reaction and the concentrations of the reactants.

A third-order reaction is a type of chemical reaction where the concentration of each molecular responding determines how quickly the reaction proceeds. Typically, the variation of three concentration factors in this reaction determines the rate.

There may be various cases involved when dealing with a third-order reaction. It might be;

(i) The concentrations of the three reactants are equal.

(ii) Two reactants are present in an equal amount, but one is present in a different amount.

(iii) The concentrations of the three reactants vary or are uneven.

Use formula,

(mol/L)¹⁻ⁿ s⁻¹

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Components that are typically included when citing a journal article are, volume or issue number, author(s), name of journal, page number(s), year of publication are typically included when citing a journal article. The correct choices are a, b, c, d, e.

The abstract, comments, and conclusions may or may not be included depending on the citation style and the specific requirements of the report. When citing a journal article in a laboratory report, it is important to include certain components to provide enough information for the reader to locate the article.

The name of the journal in which the article was published should be included, as well as the volume and issue number (if applicable) and the page numbers of the article within the journal. This information helps to identify the specific article within the publication. The author or authors of the article should also be included, typically in the format of last name followed by initials. The year of publication is also important information to include.

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The precipitate that will form when a solution of aluminum chloride is mixed with a solution of potassium phosphate is aluminum phosphate (AlPO4).

When aluminum chloride and potassium phosphate are mixed together, the cations and anions form different combinations of ion pairs. This causes the precipitation of a solid phase (AlPO4) from the solution. The chemical reaction that occurs can be represented as follows:

3K3PO4 + 2AlCl3 → 6KCl + AlPO4

The aluminum ion (Al3+) in the aluminum chloride solution and the phosphate ion (PO43−) in the potassium phosphate solution combine to form a precipitate of aluminum phosphate (AlPO4). The resulting solid aluminum phosphate (AlPO4) will appear as a white or slightly yellowish powder. The solubility of AlPO4 in water is relatively low, with a solubility of about 0.06 grams per liter of water at room temperature (25°C).

Therefore, it will readily settle out of the solution as a solid mass, rather than remaining dissolved.

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The reaction demonstrates that energy is needed to dissociate the hydrogen atoms from one another, and as a result energy is consumed.

When a chemical bond is broken, energy is required to break the bond, and thus energy is absorbed. The equation that represents energy being absorbed as a bond is broken is option D, which is:

H2 + energy → 2H

In this equation, the energy is shown as a reactant on the left-hand side of the arrow, indicating that it is required for the reaction to proceed. The H2 molecule on the left-hand side represents a molecule with a covalent bond between two hydrogen atoms. When energy is added to the molecule, the bond between the two hydrogen atoms is broken, and the atoms become separated. This results in the formation of two hydrogen atoms on the right-hand side of the arrow, each with one unpaired electron.

Overall, the reaction shows that energy is required to break the bond between the hydrogen atoms, and thus energy is absorbed during the process.

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The given figure is shown below:

Given figure from which shaft A is made of AISI 1020 hot-rolled steel, is welded to a fixed support and is subjected to loading by equal and opposite forces F via shaft B.

A theoretical stress-concentration factor Kts of 1.6 is induced by the 1/8" fillet. The length of shaft A from the fixed support to the connection at shaft B is 2 ft. The load F cycles from 150 t0 500 lbf. To find:

Factor of safety for infinite life using the modified Goodman fatigue failure criterion using the von Mises combined stress approach for shaft A.

Solution: The factor of safety for infinite life can be given by the following formula:

Factor of safety for infinite life= σ′ut1.5σ′a + σm

Here, σm = (σ1+σ2)/2= (800+400)/2= 600 psi

σa = (σ1-σ2)/2= (800-400)/2= 200 psi

σ′ut = σut/Kf= 64000/1.5 = 42666.67 psi

The alternating stress (σa) can be obtained as follows:

The force F can be given as,F= 150 + 350sin(πn/60) …(i)Where n is the rotational speed in rpm. For the given data, n= 1800 rpm.

Substituting the values, we get,

F= 150 + 350sin(π×1800/60)= 500 lb

Substituting the values of force and cross-sectional area of shaft A, we get,

σa= 4F/πd²= 4×500/π×0.25²= 4080 psi

Thus, substituting the above values in the formula of factor of safety, we get,

Factor of safety for infinite life= σ′ut1.5

σ′a + σm= 42666.67/1.5×4080 + 600= 4.23

Hence, the factor of safety for infinite life using the modified Goodman fatigue failure criterion using the von Mises combined stress approach for shaft A is 4.23.

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The molecule with the highest boiling point is 1,4-butanediol. This is because of the presence of intermolecular hydrogen bonding. Thus, the correct option is C.

A hydrogen bond is an intermolecular force that exists between a hydrogen atom bonded to a highly electronegative atom (like N, O, or F) and another highly electronegative atom in another molecule. Hydrogen bonding is a type of dipole-dipole interaction that occurs between molecules that have a permanent dipole.

The four molecules, 3-methoxy-1-propanol, 1,2-dimethoxyethane, 1,4-butanediol, and 2-methoxy-1-propanol, all have oxygen atoms that are capable of forming hydrogen bonds. In order to form a hydrogen bond, a hydrogen atom in one molecule must be bonded to an electronegative atom like oxygen or nitrogen, and another electronegative atom in a neighboring molecule must be present.

In this case, 1,4-butanediol has two -OH groups on the ends of the carbon chain that are capable of forming hydrogen bonds with neighboring molecules, resulting in a higher boiling point. Because of the presence of intermolecular hydrogen bonding, the molecules have stronger intermolecular forces that require more energy to break, resulting in a higher boiling point.

Therefore, the correct option is C.

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In order to calculate the theoretical yield of sulfuric acid, we need to know the balanced chemical equation for the reaction between sulfur and oxygen to form sulfur trioxide, and then the reaction between sulfur trioxide and water to form sulfuric acid. The balanced chemical equation for these reactions are:

2S (s) + 3O2 (g) → 2SO3 (g)

SO3 (g) + H2O (l) → H2SO4 (aq)

From the equation, we can see that 3 moles of O2 are required to react with 2 moles of sulfur to produce 2 moles of SO3, and 1 mole of SO3 reacts with 1 mole of water to produce 1 mole of H2SO4.

Since the limiting reagent is 134.4 L of O2, we need to convert this volume to moles. To do this, we need to know the pressure, temperature, and the number of moles of O2 present. Assuming standard temperature and pressure (STP) of 0°C and 1 atm, the number of moles of O2 can be calculated using the ideal gas law:

PV = nRT

where P = 1 atm, V = 134.4 L, n = ?, R = 0.08206 L atm/mol K, and T = 273 K.

Solving for n, we get:

n = PV/RT = (1 atm)(134.4 L)/(0.08206 L atm/mol K)(273 K) = 5.29 mol O2

Since 3 moles of O2 are required to react with 2 moles of sulfur to produce 2 moles of SO3, the number of moles of SO3 produced is:

(2/3) × 5.29 mol = 3.53 mol

Since 1 mole of SO3 reacts with 1 mole of water to produce 1 mole of H2SO4, the number of moles of H2SO4 produced is:

3.53 mol H2SO4

Finally, we can convert the number of moles of H2SO4 to grams using the molar mass of H2SO4:

molar mass of H2SO4 = 2(1.008 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.08 g/mol

The theoretical yield of sulfuric acid is therefore:

3.53 mol H2SO4 × 98.08 g/mol = 345.7 g H2SO4

Therefore, the theoretical yield of sulfuric acid if the limiting reagent is 134.4 L of O2 is 345.7 g.

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The answer that comes closest to the result is the letter b. However, the exact number is 9.86 x 10²⁶  CaCl₂ formula units applied per mile.

To solve this, we need to calculate how much CaCl₂ (calcium chloride) is being applied.

To do this, we can use the conversion factor 1 lb = 453.6 g. We are given that 400 lb of CaCl₂ is applied per mile of highway. This is equal to 400 x 453.6 g = 181,440 gCaCl₂ applied per mile.

We also know that the molar mass of CaCl₂ is 110.98 g/mol. This means that 181,440 g CaCl₂ = (181,440 g)/ (110.98 g/mol) = 1,640 mol CaCl₂ applied per mile.

Finally, we can calculate the number of formula units of CaCl₂ applied. This is equal to the number of moles of CaCl₂ applied multiplied by Avogadro's number (6.02 x 10²³). Therefore, 1,640 molCaCl₂ applied per mile is equal to 1,640 x 6.02 x 10²³ = 9.86 x 10²⁶  CaCl₂ formula units applied per mile.

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