An athlete runs some distance before taking a long jump. Why ?​

Answers

Answer 1
An athlete run some distance before taking a jump to increase his speed, therefore it is their inertia of motion which helps him to jump a longer distance
Answer 2

An athlete runs before taking a long jump because they need to gather the strength to jump its like a person brain storming before they write an essay


Related Questions

To expel hot air out of the kitchen, A has an exhaust fan fitted on the window of her kitchen and B has a similar exhaust fan fitted on the wall near the ceiling of the kitchen. Which one of the exhaust fan will expel the hot air more effectively? Explain why.

Answers

Answer:

Kitchen B

Explanation:

This all boils Down to the phenomenon of convection current of àir where warmer air rises up and is replaced by cooler air, the fan is placed higher up in B and because hot air rises higher up it will remove more hot air here

Which of these item(s) are NOT mentioned in Stuff Matters? Leather Shoes Microphones Candles Jet Engine Teacup

Answers

Answer:

Leather Shoes, Microphones, Candles

Explanation:

Surprisingly, leather Shoes, Microphones, Candles were not mentioned in Stuff Matters a book written by Mark Miodownik which according to him explored "the marvelous things that shape our man-made world."

the maximum speed limit on interstate 10 is 75 miles per hour. how many meters per second is this

Answers

Answer:

33.53m/s

Explanation:

Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.

Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds

75 miles perhour = 75miles/1 hour

75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *

= 75 *1609.34m* 1 /1 * 1 * 3600s

= 120,700.5m/3600s

= 33.53m/s

Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s

I can raise a bucket of cement mix of mass 12kg through a vertical height of 8m in 10 seconds.Calculate the average power used in raising the bucket against the gravitational force?

Answers

Explanation:

Power = work / time

Power = force × distance / time

P = (12 kg × 10 m/s²) (8 m) / (10 s)

P = 96 Watts

The average power used in raising the bucket against the gravitational force is equal to 94.08 W.

What is power?

Power can be defined as the rate of doing work in unit time. The S.I. unit that is used to measure power is Watt (W) or Joule per second. Power can be described as the rate at which work is done.

Power = Work /time

Given, the mass of the bucket, m = 12 kg

The distance traveled by the bucket, d = 8 m

The work is done by the bucket, W = F.d

W = mg.d

W = 12 × 9.8 ×8

W = 940.8 J

Given, the time is taken by the bucket, t = 10 s

The power used in raising the bucket against the gravitational force:

P = W/t

P = 940.8/10

P = 94.08 W

Therefore, the average power is equal to 94.08 W.

Learn more about power, here:

brainly.com/question/14070854

#SPJ2

Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?

Answers

Answer:

The observer will say that galaxy 2 is moving away from galaxy 3 where he stands.

Explanation:

Since the galaxies are expanding, each one would move away from the others. Observers on all three galaxies have their frame of reference fixed on their own galaxies. Judging from their own galaxies, each observer will perceive the other galaxies moving away from his/or galaxy.

The observer at galaxy 3 will talk about galaxy 2 by doing is; he will say that galaxy 2 is moving far from him.

We are told that the universe is expanding and as such, the galaxies would be expanding and moving away from each other.

Since the galaxies are expanding, it means that they will be moving away from each other.

From time dilation principle, an observer at galaxy 3 will say that galaxy 2 is moving far from him.

Read more about galaxies at; https://brainly.com/question/21413373

Part B – Scientific Method
READ THIS STORY AND ANSWER THE QUESTIONS:
Joe baked a cake for his mother's birthday. When he removed the cake from the oven, Joe noticed that the cake had not risen. Joe guessed that the baking powder he had used was too old. He designed the following experiment to test his idea.
Joe prepared two cakes – one using the same ingredients as his first cake and one using fresh baking powder. After preheating the oven to 350°F, he placed both cakes in the oven for 30 minutes. After 30 minutes, he removed both cakes and noticed that neither one had risen. He decided that the baking powder wasn’t the cause of his problem.
What is Joe's hypothesis?



What is Joe's conclusion?



What did Joe’s observe?



What was the independent variable in Joe’s experiment?


What was the dependent variable in Joe’s experiment?



What was the control in Joe’s experiment?



What were the constants in Joe’s experiment (assuming he did it correctly)?






8. Based on his conclusion, what should Joe do next?

Answers

Answer:

1) Joe's hypothesis was that the baking powder he used was too old and that was why the cake did not rise

2) Joe concluded that the baking powder was not the cause of the cake not rising

3) Joe observed that the cake he made for his mother's birthday did not rise

4) The independent variable was the baking powder

5) The dependent variable was the rising cake

6) Joe's control in the experiment was the extra cake made using the same ingredient as the first

7) The constants were the heat and time to bake both cakes

8) He should recheck all the variables and constants (recipes and procedures) are correct as can be found in baking books

Explanation:

Answer: Please find the answers in the explanation

Explanation:

From the given description, when Joe noticed that the cake had not risen,  he guessed that the baking powder he had used was too old.

Hypothesis is one of the scientific methods which means guessing.

What is Joe's hypothesis?

Joe's hypothesis is that the baking power used was not effective to make the cake rise believing that it was too old.

After Joe prepared two cakes, one using the same ingredients as his first cake and one using fresh baking powder. After preheating the oven to 350°F, he placed both cakes in the oven for 30 minutes. After 30 minutes, he removed both cakes and noticed that neither one had risen. He decided that the baking powder wasn’t the cause of his problem.

What is Joe's conclusion?

The conclusion is that the inability for the cake to rise wasn't as a result of ineffectiveness of the baking powder used.

What did Joe’s observe?

Joe observed that the cake had not risen.

What was the independent variable in Joe’s experiment?

The independent variable determines the dependent variable.

The independent variable is therefore, the different types of baking powder used.

What was the dependent variable in Joe’s experiment?

The dependent variable is the volume of the cakes.

What was the control in Joe’s experiment?

Joe was able to control the time and the temperature.

What were the constants in Joe’s experiment (assuming he did it correctly)?

The constant were the quantities of the cake ingredient, time used, and the temperature

8. Based on his conclusion, what should Joe do next?

Joe can try another ingredient like yeast or reconsider the ratio of the baking powder to the flour.

 

Simple Harmonic Motion: A simple harmonic oscillator oscillates with frequency f when its amplitude is A. If the amplitude is now doubled to 2A, what is the new frequency

Answers

Answer:

The frequency will still remain F

Explanation:

Firstly, we should remember that the frequency of a simple harmonic oscillator doesn't depend on the amplitude. Rather, it depends on the spring constant, k, and the mass of the attached weight, m. This means that the change in amplitude will not lead to a corresponding change in frequency.

the frequency is represented by the formula

f = 1/2π * √(k/m),

where

f = frequency of the oscillator

k = spring constant and

m = mass attached to the spring

From the formula above, we can state that the frequency doesn't depend on the amplitude at all, and as such, the amplitude changing from A to 2A, will effect no change in the frequency F.

7. Una locomotora de 80.000 kilogramos de masa, parte del reposo y a los 10 segundos lleva una velocidad de 36Km/h. Halla: A. La aceleración del movimiento. B. La fuerza que causa el movimiento.

Answers

Answer:

a) La aceleración del movimiento es 1 metros por segundo al cuadrado, b) La fuerza que causa el movimiento es 80.000 newtons.

Explanation:

a) Supóngase que la locomotora acelera uniformemente, la aceleración se está descrita por la siguiente ecuación cinemática:

[tex]v = v_{o}+a\cdot t[/tex]

Donde:

[tex]v_{o}[/tex] - Rapidez inicial, medida en metros por segundo.

[tex]v[/tex] - Rapidez final, medida en metros por segundo.

[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.

[tex]t[/tex] - Tiempo, medido en segundos.

Se despeja la aceleración:

[tex]a = \frac{v-v_{o}}{t}[/tex]

Si [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 10\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], la aceleración del movimiento es:

[tex]a = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{10\,s}[/tex]

[tex]a = 1\,\frac{m}{s^{2}}[/tex]

La aceleración del movimiento es 1 metros por segundo al cuadrado.

b) Dado que una locomotora es un sistema de masa constante, la fuerza ([tex]F[/tex]) que genera el movimiento es igual a:

[tex]F = m\cdot a[/tex]

Donde:

[tex]m[/tex] - Masa, medida en kilogramos.

[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.

Dados que [tex]m = 80.000\,kg[/tex] y [tex]a = 1\,\frac{m}{s^{2}}[/tex], la fuerza que causa el movimiento es:

[tex]F = (80.000\,kg)\cdot \left(1\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 80.000\,N[/tex]

La fuerza que causa el movimiento es 80.000 newtons.

A baseball player up to bat gets hit by a fast ball. What is the predominant type of force generated by the ball on the player? Explain your reasoning.

Answers

Answer:

Reaction force

Explanation:

According to Newton's third law of motion, for every action, there is an equal opposite reaction.

Hence the reaction force is often equal in magnitude to the applied force but acts in a direction opposite to the direction of the applied force.

Hence, when a baseball player, gets a hit, the ball exerts a reaction force on the player which is equal in magnitude to the force with which the player hits the ball but opposite in direction.

Which statement best describes the similarities between fundamental forces? a Electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom. b Gravitational and magnetic forces are the most alike because they are both types of charges that occur in nature. c Nuclear and magnetic forces are the most alike because they are both related to mass and weight. d Strong nuclear force is most like electrical force because they are both related to distance.

Answers

Answer:

a

Explanation:

............

..............option A

Answer:

A is the answer as electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom the only difference being their intensity! Hope this helps :) and if you dont mind, mark me brainliest so i can get to the next rank :(

compare distance and mass

Answers

Answer:

The amount of gravity affecting an object depends on two things: the masses of the objects being attracted and the distance between the objects. Mass is the measure of the amount of matter in an object. With distance, we see that the strength of gravity decreases if the distance between two objects increases.

Hope this helps!

An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?

Answers

Answer:

The maximum speed of the oscillating object doubles as well.

Explanation:

The oscillatory motion of the object on the spring can be modelled using this equation below:

[tex]Vmax= A\omega[/tex]

Where

Vmax = the maximum speed of the oscillating object.

A = Amplitude of the oscillating object.

[tex]\omega[/tex] = angular velocity of the oscillating object.

If the amplitude, A becomes doubled, the new amplitude will be = 2A.

As a result,  [tex]Vmax = 2 A \omega[/tex]

This shows that the maximum speed has doubled in its value

give an example of unbalanced force

Answers

Your question has been heard loud and clear.

Well , basically anything that moves in a certain direction is an example of unbalanced forces.

When we kick the football , the force given by our leg is greater than the frictional force by the ball and therefore the ball moves in the direction of the greater force , which is the force given by our leg.

Thank you

Answer:

friction

Explanation:

an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image​

Answers

Answer:

[tex]\boxed{\sf Position \ of \ the \ image = 6 \ cm}[/tex]

[tex]\boxed{\sf Nature \ of \ the \ image = Virtual \ and \ Erect}[/tex]

Given:

Object distance (u) = -10 cm

Focal length (f) = 15 cm

To Find:

Image distance (v) and nature of the image

Explanation:

Mirror Formula:

[tex]\boxed{\bold{\sf \frac{1}{v} + \frac{1}{u} = \frac{1}{f}}}[/tex]

Substituting values of u and f in the equation:

[tex]\sf \implies \frac{1}{v} -\frac{1}{10} =\frac{1}{15}[/tex]

[tex]\sf \implies \frac{1}{v}=\frac{1}{15} +\frac{1}{10}[/tex]

[tex]\sf \implies \frac{1}{v}=\frac{2}{30}+\frac{3}{30}[/tex]

[tex]\sf \implies \frac{1}{v}=\frac{2+3}{30}[/tex]

[tex]\sf \implies \frac{1}{v}=\frac{5}{30}[/tex]

[tex]\sf \implies v=\frac{30}{5}[/tex]

[tex]\sf \implies v=6 \ cm[/tex]

[tex]\therefore[/tex]

Image distance (v) = 6 cm

Nature of the image = Virtual and Erect

Which one of the two potential differences emf or terminal voltage will be greater in magnitude?Why?​

Answers

Answer:

True, yes terminal voltage of a battery can never be greater than the emf of the battery. Because due to internal resistance of the current terminal

when object goes under acceleration
a).a force always acys on it
b).its speed always increase
c).its velocity always increases

Answers

when object goes under acceleration

c).its velocity always increases

Additional information:-

★ Acceleration: Rate of increase in velocity.

★ Velocity: Distance travelled by a body per unit time in given direction is called velocity .

Answer: velocity always increase

Explanation: Really dont need any explanation

Se lanza una bala con una velocidad inicial de 200 m/s y con un ángulo de inclinación de 30º respecto a la horizontal. Si se considera g=10 m/s2. ¿Cuál es el alcance de la bala?

Answers

Answer:

El alcance de la bala es 3464,1 m.

Explanation:

El alcance de la bala se puede calcular como sigue:

[tex]y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}[/tex]

En donde:

y: es la altura final = 0

[tex]y_{0}[/tex]: es la altura inicial = 0

x: es el alcance

θ: es el angulo respecto a la horizontal = 30°

[tex]v_{0}[/tex]: es la velocidad inicial = 200 m/s

g: es la gravedad = 10 m/s²

Entonces, tenemos:

[tex] y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}} [/tex]

[tex] x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(30)*(200 m/s*cos(30))^{2}}{10 m/s^{2}} = 3464,1 m [/tex]

Por lo tanto, el alcance de la bala es 3464,1 m.

Espero que se te sea de utilidad!


1. It takes 10 seconds for you to go to the cafeteria from the classroom and to
come back. Cafeteria is 20m away East to the classroom. What is your average
velocity?

Answers

Answer:

4 m/s East.

Explanation:

Velocity: This cam be defined as the rate of change of displacement. The unit of velocity is m/s.

From the question,

v = d/t...................... Equation 1

Where v = velocity, d = displacement, t = time.

Given: d = 20 m East, t = 5 seconds.

substitute into equation 1

v = 20/5

v = 4 m/s East.

Hence the average velocity = 4 m/s East.

a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receive? (b) what is its change in momentum?

Answers

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

[tex]J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m[/tex]

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

What is the net force on an object that is experiencing a force of 25 N north, a force of 25 N
south, a force of 50 N to the east and a force of 45 N to the west?

Answers

Answer:

net 5N of force will act in east direction.

Explanation:

force acting in North and South direction will cancel each other.

force in east direction - force in west direction = 5N

Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effort distance? (Ans 80cm)

Answers

Answer:

Solution

Load(L)=400

Effort(E)=100

Load distance (Ld)=20cm

Effort distance(Ed)=?

Now,from the principle of equilibrium

L×Ld=E×Ed

or,Ed=L×Ld/E

or,Ed=400×20/100

:.Ed=80cm and

Therefore,the effort distance will be 80cm

Answer:

80cm

Explanation:

load l = 400

Effort e = 100

load distance Ld = 20

Effort distance Ed = ?

L×ld= E×Ed

Ed=L×Ld \ E

Ed=400×20/100

Ed=80cm Ans

What is the standard unit for time

Answers

standerd unit of time is second

Answer:

The standard unit for time is second (s).

Kangaroos have been clocked at speeds of 18 m/s. How far can a kangaroo hop in 192 sec at this speed?

Answers

[tex] \bf \underline{ \underline{given : }}[/tex]

Speed of kangaroo = 18 m/s

Time taken by a kangaroo = 192 sec

[tex]\bf \underline{ \underline{to \: be \: calculated : }}[/tex]

Calculate the distance covered by a kangaroo.

[tex]\bf \underline{ \underline{formula \: applied : }}[/tex]

[tex] \boxed{ \bf{Speed = \frac{Distance}{Time} }}[/tex]

[tex]\bf \underline{ \underline{Solution : }}[/tex]

We know that,

Speed = Distance/Time

=> Distance = Speed × Time

Substituting the values in the above formula,we get;

=> Distance = 18 × 192

=> Distance = 3456 m

Thus,the distance covered by a kangaroo is 3456 meters.

places of hot climate it is advised that outer walls of houses be painted white. Why?​

Answers

Answer: In places of hot climate it is advised that the outer wall of houses be painted white because white color reflects heat and the houses do not heat up too much.

The radius of a small ball is around 2.8436 cm. The radius of a basketball is about 4.22 times larger. What is the ratio of the surface areas of the small ball and a basketball? Part 2 What is the ratio of their volumes?
help please

Answers

Answer:

Explanation:

Both small ball and a basketball are in form of a sphere. Total surface area of a sphere is gotten using the formula;

surface area of a sphere S = 4πr²

If the radius of a small ball is around 2.8436 cm, its total surface area will be:

S = 4π(2.8436)²

S =4π(8.086)

S = 101.61 cm²

If the radius of a basketball is about 4.22 times larger, the radius will be 4 times larger as well. The radius of the basket ball = 4.22*2.8436

radius of thr basketball = 11.99cm

Surface area of the basketball S2 =  4π(11.99)²

S2 =4π(143.76)

S2 =1806.54cm²

The ratio of the surface areas of the small ball and a basketball S:S2

S:S2 = 101.61 cm² : 1806.54cm²

S:S2 = 0.0562

Hence, the ratio of the surface areas of the small ball and a basketball is approximately 0.0562.

2) The volume of a sphere = 4/3πr³

Volume of the small ball = 4/3π(2.8436)³

Volume of the small ball = 4/3 π  * 22.994

Volume of the small ball= 96.315cm³

Similarly;

Volume of the basketball = 4/3π(11.99)³

Volume of the small ball = 4/3 π  * 1723.68

Volume of the small ball= 7220.14cm³

The ratio of the volume of the small ball and a basketball V:V2

V:V2 = 96.315  : 7220.14

V:V2 = 0.01333

Hence, the ratio of the volumes of the small ball and a basketball is approximately 0.01333

1. How many inches are in 6 meters?

Answers

Answer:

236.22 inches

Explanation:

There are 39.3701 inches in 1 meter.  So to find 6 meters, multiply 6 times 39.3701.

6·39.3701=236.22

Answer:

236.22

Explanation:

just because itit's common sense

o
Question 4
1 pts
You jog around 180m track 4 times in 30 minutes. What is your average speed in
m/s? (Hint: Convert min to seconds first)
O 0.4 m/s
O 6 m/s
O 24 m/s
O O m/s

Answers

Well first you would multiply 180m x 4 for the total distance of 720m. Next you would convert 30 minutes or half an hour into seconds which would be a total of 1,800 seconds. Finally, you would divide 1,800 seconds by the 720 meters ran for an average speed of 0.4 m/s.

Answer:

0.4m/s

Explanation:

It is given speed so it is scalar.

distance covered in 1 round = 180m

therefore, distance covered in 4 rounds = 180*4 = 720m

time = 30 mins = 30*60 = 1800 seconds

average speed = total distance/total time taken

= 720/1800

= 0.4m/s

What are the balanced forces for someone in a parachute? A. Gravity and Earth B. Gravity and air resistance C. Gravity and centripetal D. Centripetal and air resistance

Answers

Answer:

B. Gravity and air resistance

Explanation:

Experimentation has proven that :

When the parachute opens, air resistance becomes much greater than gravity. The forces are no longer balanced and this changes the

speed

Answer:

[tex]\large \boxed{\mathrm{B. \ Gravity \ and \ air \ resistance}}[/tex]

Explanation:

Gravity and air resistance are the forces that get balanced out during a free fall. This is also known as terminal velocity, when gravity = air resistance.

Find the density of a substance that has a volume of 754 cm3 and a mass of 7,917 grams. Don't forget your units!

Answers

Answer:

[tex] \boxed{\sf Density \ of \ the \ substance = 10.5 \ g/cm^3} [/tex]

Given:

Mass (M) = 7917 grams

Volume (V)= 754 cm³

To Find:

Density of the substance

Explanation:

[tex] \boxed{ \bold{\sf Density \ (\rho) = \frac{Mass \: (M)}{Volume \: (V)}}}[/tex]

Substituting values of M & V in the equation:

[tex] \sf \implies \rho = \frac{7917}{754} [/tex]

[tex]\sf \implies \rho = 10.5 \: g/ {cm}^{3} [/tex]

I don't know how to solve this, can I get a little help?

Answers

Explanation:

Acceleration is the change in velocity over change in time.

a = Δv / Δt

So it is the slope of the line of a velocity vs. time graph.

a = (10 m/s − 40 m/s) / (12 s − 0 s)

a = -2.5 m/s²

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