An astronaut is floating in space. There is no rope connecting him to the ship. They have some tools and a
fire extinguisher.
Which action could propel the astronaut back to the ship? (Select two answers)
He could spray the fire extinguisher in the opposite direction of the ship
He could throw a tool in the opposite direction of the ship
He could throw a tool toward the ship
He could point the extinguisher towards the ship and spray it.

Answer:

all of the above I think??

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

How much time would it take for a 0.17 kg ice hockey puck to decrease its speed by 9.0 m/s if the coefficient of kinetic friction between the ice and the puck is 0.05

Time taken to decrease the speed

Equation :-

[tex]f {\tiny{k} }= u {\tiny{k}}.f \tiny{N}[/tex]

[tex]f {\tiny{N} }= mg = 0.17 \times 10 \\f {\tiny{N} }= 1.7 {N}[/tex]

[tex]u{ \tiny{N}} = 0.05[/tex]

[tex]mg = f {\tiny{k} }= u {\tiny{k}}.f {\tiny{N}} \\ 0.17a = 0.05 \times 1.7 \\ a = 0.05 \times \frac{ \cancel{1.7} {}^{ \: \: 10} }{ \cancel{0.17}} \\ a = 0.5m {s}^{ - 2} [/tex]

change in speed = 9 ms-1 (Given)

[tex]change \: in \: speed = at \\ 9 = 0.5 \times t \\ \frac{9 \times 10}{5} = t \\ \frac{9 \times \cancel{10} {}^{ \: \: 2} }{ \cancel{5}} = t \\ 18 \: sec = t \: [/tex]

Answer:

A. right before it hits the ground.

Explanation:

because all the way down, it is building kinetic energy.

Take the moment Allen sees the moose to be the origin.

First, convert his speed to m/s.

90 km/h = (90 km/h) • (1000 m/km) • (1/3600 h/s) = 25 m/s

(a) For the time it takes him to react (0.85 s), Allen is moving at a constant speed of 25 m/s, so that before he actually does anything, he covers a distance of

(25 m/s) • (0.85 s) = 21.25 m

(b) Once he presses the brakes, Allen's vehicle covers a distance x in time t of

x = 21.25 m + (25 m/s) t + 1/2 a t²

and has a speed v of

v = 25 m/s + a t

It takes him 3.5 s to come to a full stop. Use this to find the acceleration:

0 = 25 m/s + a (3.5 s)

a = - (25 m/s) / (3.5 s)

a ≈ - 7.1 m/s²

After 3.5 s, he will have traveled a total distance of

x = 21.25 m + (25 m/s) (3.5 s) + 1/2 (- 7.1 m/s²) (3.5 s)²

x = 152.5 m ≈ 150 m

(c) This one is worded a bit strangely, specifically "once he presses the brake" seems to suggest instantaneous acceleration, not average. Average acceleration is defined for some duration of time. You're probably expected to report the acceleration of the car as it comes to a stop, which we found earlier to be

a ≈ - 7.1 m/s²

Answer:

Since the ball is travelling 32 degrees above the horizontal, the value of Θ is 32

In the figure, v vector is the vertical component whereas h vector is the horizontal component

Using trigonometry:

CosΘ = h /24

Cos 32 = h/  24

0.85 = h / 24

h = 24*0.85

h = 20.4 m/s

Answer: 6 J

Explanation:

Total force applied = 47 N Assuming that direction of movement of pencil and applied force is same. Work done by force in moving the pencil W = Force × Distance through which force moves ⇒ W = 47 × 0.25 = 11.75 J .-.-.-.-.-.-.-.-. In case we are asked useful work done then we calculate net force used for pushing the pencil: Net force used for pushing the pencil = 47 − 23 = 24 N Assuming that direction of movement of pencil and net force is same. Useful Work done by force in moving the pencil W u = Force × Distance ⇒ W u = 24 × 0.25 = 6 J

The work done the pushing force is required.

The work done by the pushing force is [tex]6\ \text{J}[/tex]

[tex]F_1[/tex] = Pushing force = 47 N

[tex]F_2[/tex] = Opposing force = 23 N

m = Mass of object = 0.025 kg

s = Displacement = 0.25 m

Work done is given by

[tex]W=F_ns[/tex]

[tex]\Rightarrow W=(47-23)\times 0.25[/tex]

[tex]\Rightarrow W=6\ \text{J}[/tex]

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Answer:

i think its the top one

Explanation:

pls tell me if im wrong  

Answer:

the heat change to 10kg of ice to water 0

so quantity of heat required is answer: 5460 J.

hope its helps!

Answer:

Q=ml+mc∆+ml'

=10*80+10*1*(100-0)+10*540

=800+1000+5400

=7200cal.7.2kcel

L=heat of fusion of ice

L'=heat of vapourisation of water

Answer:

Water isn't wet by itself, but it makes other materials wet when it sticks to the surface of them.

Explanation:

Answer:

water is wet

it is a liquid

Explanation:

three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650

Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where  is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

[tex]\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s[/tex]

#2

[tex]\\ \rm\Rrightarrow v=2(0.4)=0.8m/s[/tex]

#Wavelength

#1

[tex]\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m[/tex]

#2

[tex]\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m[/tex]

#Frequency

[tex]\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz[/tex]

#2

[tex]\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz[/tex]

Answer:

Higher denisty

Explanation:

High pressure=high denisty

Answer:

V2 =  23 [m/s] to the left.

Explanation:

In order to solve this problem, we must use the definition of conservation of linear momentum. That is, the momentum is conserved before and after the collision. The values before the collision will be taken to the left of the equality, and the values after the collision will be taken to the right of the equality, in this way we have:

Σbefore = Σafter

ΣPbefore = ΣPafter

where:

P = m*v

The positive momentum will be taken to the right and the negative momentum is to the left in this way we formulate the following equation:

[tex](m_{1}*v_{1}) + (m_{2}*v_{2})=-(m_{1} +m_{2})*v_{3}\\[/tex]

where:

m1 = mass of the first object = 6 [kg]

v1 = velocity of the first object = 5 [m/s]

m2 = mass of the stick = 2 [kg]

v2 = velocity of the stick [m/s]

v3 = velocity of the composite object = - 2 [m/s]

(6*5) + (2*V2) = - (6 + 2)*2

30 + (8*2) = - 2*V2

46 = - 2*V2

V2 = - 23 [m/s]

Note: the negative sign means the stick moves to the left

Answer:

changes by 9.8 m/s each second.

Answer:

V2 = 15.53 [m/s]]

Explanation:

In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.

Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.

[tex]E_{1}=E_{2}\\ m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\ v_{2} =15.53[m/s][/tex]

The order of magnitude of the final velocity of an object that begins from rest and accelerates at a rate of 20m/s² for 5.0 seconds is 100m/s

​

The acceleration of a body is the change in velocity with respect to time as shown:

[tex]a=\frac{v-u}{t}[/tex]

Given the following parameters

a is the acceleration = 20m/s²

u is the initial velocity = 0m/s

t is the time taken = 5.0seconds

Required

Final velocity "v"

Substitute the given parameters into the formula:

[tex]20=\frac{v-0}{5} \\20 =\frac{v}{5}\\v = 20 \times 5\\v =100m/s[/tex]

Hence the order of magnitude of the final velocity of an object that begins from rest and accelerates at a rate of 20m/s² for 5.0 seconds is 100m/s

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Answer:

8.8 kN

Explanation:

V = 2 m³, W = 40 kN, SG = 1.59

Bouyant force N = 1.59 * 1000 kg/m³ * 9.81 N/kg * 2 m³ = 31.2 kN

So the weight becomes 40 - 31.2 = 8.8 kN

Explanation:

Glomar Challenger studies about the "age of rocks in various places in the ocean" in 1968. EXPLANATION: Glomar Challenger was a "deep sea research vessel" for marine geology and oceanography studies.

I hope this helps you :)

Answer:

c no cappp :)

Explanation:

R=A2+B2+2ABcosβ−−−−−−−−−−−−−−−−√R=A2+B2+2ABcosβ

A=4NA=4N , B=3NB=3N , β=90°β=90° , cosβ=0cosβ=0

R=A2+B2−−−−−−−√R=A2+B2

R=42+32−−−−−−√=25−−√=5NR=42+32=25=5N

tanα=Bsin90°A+Bcos90°=34tanα=Bsin90°A+Bcos90°=34

α=37°α=37°

Therefore the resultant of the two forces has a magnitude of 5N5N and is at an angle of 37°37° with respect to

Answer:

newton 's 3rd law which states that to every action there's equal but opposite reaction

Answer:

False

Explanation:

in my point of view the human race has adapted to being greedy in some ways we can save resources but its very rare

hope this helps! : )

Answer:

A.

Explanation:

The liquid with the higher density will be found at the bottom of the glass because is the heaviest of all. The liquids which have a lower density than the liquid at the bottom of the glass will be found at the top of the glass. We assume that the liquids are not soluble in each other because otherwise they will be mixed.

Answer:

  orbiting the Sun in an elliptical orbit

Explanation:

When orbits are circular, the center and the focus are the same point. For an elliptical orbit, the orbited object is at one focus of the ellipse. Kepler found planetary orbits to be elliptical with the sun at one focus.

__

As with a lot of scientific theories, it only explained some of the motion. As with a lot of scientific theories, explaining the discrepancies resulted in new discoveries.

Answer:

at one focus of the elliptical orbit of the planets.