An archer's bow is drawn at its midpoint until the tension in the string is 0.842 times the force exerted by the archer. What is the angle between the two halves of the string

Answer:

C. Velocity and Position

Explanation:

The quantities that are increasing for the object represented by line B are velocity and position. The correct option is b.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

The graph is given which represents the velocity and time with terms A, B, and C. As opposed to the position-time graph, which describes an object's motion over time, the velocity-time graph reveals an object's speed.

Therefore, the correct option is b. velocity and position.

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The question is incomplete. Your most probably complete question is given below:

Velocity and acceleration

velocity and position

velocity only

velocity, position, and acceleration

The magnitude of the magnetic field inside the solenoid is [tex]6.46 \times 10^{-3} \ T[/tex].

The given parameters;

The magnitude of the magnetic field inside the solenoid is calculated as;

[tex]B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\[/tex]

where;

[tex]\mu_o[/tex] is the permeability of frees space = 4π x 10⁻⁷ T.m/A

[tex]B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T[/tex]

Thus, the magnitude of the magnetic field inside the solenoid is [tex]6.46 \times 10^{-3} \ T[/tex].

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The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

The increase in temperature of the metal hammer is calculated as follows;

[tex]Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}[/tex]

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

[tex]\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C[/tex]

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

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Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

Answer:

friction force

Explanation:

force of friction is opposite to the force applied it resist the motion

Answer:

215mph

Explanation:

multiply 112milws by 2 and multiple that by seven, then divide it by two

Este problema describe el funcionamiento de una tobera adiabática (sin flujo de calor), la cual tiene una corriente de entrada que difiere de la de salida espacial y energéticamente, pero que conservan el mismo flujo másico de 250 kg/h. De este modo, usamos un balance de energía con el fin the determinar la velocidad a la que sale el fluido, según es requerido en el problema:

[tex]mu_1+mP_1v_1+mgh_1+\frac{1}{2} mv_1^2=mu_2+mP_2v_2+mgh_2+\frac{1}{2} mv_2^2[/tex]

En la que se tiene que la incógnita es la velocidad de salida, [tex]v_2[/tex], y es posible simplificar el flujo másico, [tex]m[/tex], al estar como factor común en ambos lados y despreciar la energía potencial (mgh), ya que no hay diferencia de altura significativa entre la entrada y salida de la tobera.

De este modo, es posible reemplazar los valores dados para obtener la siguiente expresión:

[tex]2510\frac{kJ}{kg} +1378kPa*0.147\frac{m^3}{kg} +\frac{1}{2} (5\frac{m}{s} )^2=2263\frac{kJ}{kg}+138.7kPa*1.099\frac{m^3}{kg} +\frac{1}{2} v_2^2[/tex]

Y así, hallar la velocidad de salida como sigue:

[tex]2725.066\frac{kJ}{kg}=2415.431\frac{kJ}{kg} +\frac{1}{2} v_2^2\\\\v_2=\sqrt{2(2725.066\frac{kJ}{kg}-2415.431\frac{kJ}{kg} )} \\\\v_2=24.9\frac{m}{s}[/tex]

Para revisar:

Answer:

both the stone will meet at a distance of 80 m from the top of tower.

Explanation:

let "t" = time after which both stones meet

"S" = distance travelled by the stone dropped from the top of tower

(100-S) = distance travelled by the projected stone.

◆ i) For stone dropped from the top of tower

-S = 0 + 1/2 (-10) t²

or, S = 5t²

◆ ii) For stone projected upward

(100 - S) = 25t + 1/2 (-10) t²

= 25t - 5t²

Adding i) and ii) , We get

100 = 25t

or t = 4 s

Therefore, Two stones will meet after 4 s.

◆ ¡¡¡) Put value of t = 4 s in Equation i) , we get

S = 5 × 16

= 80 m.

Thus , both the stone will meet at a distance of 80 m from the top of tower.

(Hope this helps can I pls have brainlist (crown)☺️)

The magnetic field in the gap is [tex]\mathbf{B = \dfrac{\mu_oI s}{2 \pi a^2}}[/tex]

In a circuit, a magnetic flux is circulated or followed via a confined environment or passage called a magnetic field gap. The narrow air gap is a non-magnetic component of a magnetic circuit that is normally connected to the remainder of the circuit magnetically in series. This enables a significant amount of magnetic flux to pass via the gap.

The magnetic field in the gap at a distance s < a can be computed by using the formula:

[tex]\mathbf{ \oint Bdl = \mu_oI_{enclosed}}[/tex]

where;

[tex]\mathbf{B( 2 \pi d) = \mu _o \oint _s J_d da }[/tex]

where;

[tex]\mathbf{B( 2 \pi d) = \mu _o J_d \oint _sda }[/tex]

[tex]\mathbf{B( 2 \pi d) = \mu _o J_d (\pi d^2) }[/tex]

Making the magnetic flux density the subject, we have:

[tex]\mathbf{B =\dfrac{ \mu _o J_d (\pi d^2) }{( 2 \pi d)}}[/tex]

[tex]\mathbf{B =\dfrac{ \mu _o J_dd}{ 2 }}[/tex]

Recall that, the drift current density [tex]\mathbf{J_d = \dfrac{I}{\pi a^2}}[/tex]

[tex]\mathbf{B = \dfrac{\mu_o d}{2}(\dfrac{I}{\pi a^2})}[/tex]

Recall that distance in question is said to be (s);

∴

[tex]\mathbf{B = \dfrac{\mu_oI s}{2 \pi a^2}}[/tex]

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Answer:

Capacitor is a device which used to store energy .

Capacitance is the ratio of the change in an electric charge in a system to the corresponding change in its electric potential.

Explanation:

Answer:

0.25

Explanation:

That is the right answer.

The fraction of the initial kinetic energy is lost in the collision is 35.3%.

The given parameters:

The initial kinetic energy of the system collision is calculated as follows;

[tex]K.E_i = \frac{1}{2} mv_1_i^2 + \frac{1}{2} mv_2_i^2\\\\K.E_i = \frac{1}{2} (m)(8.3)^2 + \frac{1}{2} (m) (0)^2\\\\K.E_i = 34.445 m[/tex]

The final velocity of ball A after collision is calculated as follows;

[tex]u_1 + v_1 = u_2 + v_2\\\\8.3 + v_1 = 0 + 6.4\\\\v_1 = 6.4 - 8.3\\\\v_1 = -1.9 \ m/s[/tex]

The final kinetic energy of the system after collision is calculated as follows;

[tex]K.E_f = \frac{1}{2} m(-1.9)^2 + \frac{1}{2} m(6.4)^2\\\\K.E_f = 22.285 \ m \[/tex]

The fraction of the initial kinetic energy is lost in the collision is calculated as follows;

[tex]= \frac{K_i - K_f}{K_i} \\\\= \frac{34.445 - 22.285}{34.445} \\\\= 0.353\\\\= 35.3\%[/tex]

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Answer:

15-45/2 = -7.5 downwards

Explanation:

cos(60) x 45 = z

z = 45/2

sin (30) x 70 = y

y = 15

15-45/ 2 = -7.5 downwards

Answer:

25.0 cm3

Explanation:

The volume is 25.0 cm3 .

Explanation:

I think this is it, give it a try

Answer:

Decline in soil health is a serious worldwide problem that decreases complexity and stability of agricultural ecosystems, commonly making them more prone to outbreaks of herbivorous insect pests. Potato (Solanum tuberosum L., Solanaceae) and onion (Allium cepa L., Amaryllidaceae) production is currently characterized by high soil disturbance and heavy reliance on synthetic inputs, including insecticides. Evidence suggests that adopting soil conservation techniques often (but not always) increases mortality and decreases reproductive output for the major insect pests of these important vegetable crops. Known mechanisms responsible for such an effect include increases in density and activity of natural enemy populations, enhanced plant defenses, and modified physical characteristics of respective agricultural habitats. However, most research efforts focused on mulches and organic soil amendments, with additional research needed on elucidating effects and their mechanisms for conservation tillage, cover crops, and arbuscular mycorrhizae.

Introduction

Soil erosion is a serious problem worldwide (Amundson et al., 2015). Although it is often overshadowed in public discourse by other concerns, such as climate change and invasive species, soil deterioration receives considerable attention from the scientific community (Montgomery, 2007; Borrelli et al., 2017; Berhe et al., 2018). In addition to the loss of agricultural productivity, soil erosion has been linked to increased emissions of greenhouse gases and reduced water quality (Amundson et al., 2015; Berhe et al., 2018). Global soil erosion is forecasted to increase in the near future because of cropland expansion, especially in the least economically developed areas (Borrelli et al., 2017).

Answer:

Gravitational potential energy

kinetic energy

Answer: Plenty

Explanation:

some words are Hi, Banana, Dude and many more

Answer:

[tex]E=mgh[/tex]

[tex]m=3kg[/tex]

[tex]h=4m[/tex]

[tex]g=9.8m/s^{2}[/tex]

[tex]E= 3*4*9.8=117.6J[/tex]

Explanation:

Only substitute amounts to formula.

Hope this helps ;)

Cheers :D

Answer: a, c, d

Explanation: a is true because the object will continue to move even without any force because of inertia (so yh thats why a is true). c is true because an object can accelerate if a single force acts on it. to accelerate (not move), it needs a force to act on it

Would appreciate brainly <3

Explanation:

inertia ...

you push or throw something, and you apply some force to it at that moment, but then it moves and keeps moving even long after you have no more connection to it, and no more force is applied to it.

please consider : we are only talking about moving. not about acceleration.

so, yes, (a) is true.

(c) is true.

(d) is true.

Answer:

B) a pinch of sugar mixed with cup of water

Answer:

A pinch of sugar mixed with a cup of water

Explanation:

A homogeneous mixtures have a uniform appearance where the parts are pretty evenly spaced out throughout the mixture. Picking out the individual pieces should be hard, ,which is why sugar in water is the best choice.  

Answer:

Newton's second law states that .

Formulically

F=Force

m=mass

a=acceleration

The best example is hitting a tennis ball.

Hello!

We can use the following angular kinematic equation to solve:

α = Δω/Δt, or (ωf-ωi)/t

Plug in the given values:

α = (25 - 10)/5 = 15/5 = 3 rad/sec²

Answer:

100kg x 4 x 10 = 4000J

Explanation:

Answer:

Explanation:

What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.

horizontal velocity component

vx = 55.0/2.50 = 22 m/s

vertical initial velocity component

(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²

vy₀ = 13.0625 m/s

θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°

Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

Reasons:

The energy given  to the block by the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = [tex]0.5 \cdot k \cdot x^2[/tex] = kinetic energy of

block = [tex]0.5 \cdot m \cdot v^2[/tex]

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

The energy given to the block = [tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta)[/tex] = The kinetic energy of block as it leaves the spring = [tex]\mathbf{0.5 \cdot m \cdot v^2}[/tex]

Which gives;

[tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta) = 0.5 \cdot m \cdot v^2[/tex]

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and c are constants

The graph of the equation a·x² + c·v² = b  is an ellipse

Therefore;

Please find attached a drawing related to the question obtained from a similar question online

The possible question options are;

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Answer:

First aid refers to the emergency or immediate care you should provide when a person is injured or ill until full medical treatment is available.

Explanation:

Answer:

......the answer is 496.4

Answer:

3.6 miles at 56.3 degrees north of east.

Explanation:

If you draw a diagram to calculate Jimmy's displacement, you end up with a triangle.

To solve for the magnitude of Jimmy's displacement with respect to his original position, we need to use the Pythagorean Theorem formula.

Pythagorean Theorem Formula = a^2 + b^2 = c^2

Step by Step to solve for the magnitude of Jimmy's displacement:

1) a^2 + b^2 = c^2

2) 2.0^2 + 3^2 = c^2

3) 4 + 9 = c^2

4) 13 = c^2

5) To find what "c" equals to we need to find the square root of 13.

6) √13 = 3.6 | c = 3.6 miles

To solve for the direction of Jimmy's displacement with respect to his original position, we need to use the following formula:

tan^-1 ∅ (3/2)

tan^-1 ∅ (1.5)

∅ = 56.309° north of east

Therefore, your answer is 3.6 miles at 56.3 degrees north of east.