This is because there's one space labeled "2" out of 38 spaces total.
This fraction is approximately equal to 1/38 = 0.0263 meaning there's roughly a 2.63% chance of landing on this space.
The probability is 0.0263 that the ball will land on 2 in a random spin of the wheel.
What is probability?The probability is defined as the possibility of an event is equal to the ratio of the number of outcomes and the total number of outcomes.
Assuming an unbiased wheel.
The probability of an event = number of favourable outcomes/ number of total outcomes.
The total number of outcomes is 38
The number of favourable outcomes is one because there's one space labeled "2" out of 38 spaces total.
The probability of an event = 1/38 = 0.0263
Hence, the probability is 0.0263 that the ball will land on 2 in a random spin of the wheel.
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PLEASE HELP I WILL GIVE BRIANLIEST
Answer:
T. Perimeter
Step-by-step explanation:
sub : 4x - 3y + 9z from 16x - 12y - 3z.
Answer:
12x−9y−12z
Step-by-step explanation:
1. 16x−12y−3z−4x−(−3y)−9z
2. Combine 16x and −4x to get: (12x−12y−3z+3y−9z)
3. Combine −12y and 3y to get: (12x−9y−3z−9z)
4. Combine −3z and −9z to get: (12x−9y−12z)
Answer: 12x−9y−12z Step-by-step
explanation: 1. 16x−12y−3z−4x−(−3y)−9z 2. Combine 16x and −4x to get: (12x−12y−3z+3y−9z)3. Combine −12y and 3y to get: (12x−9y−3z−9z) 4. Combine −3z and −9z to get: (12x−9y−12z)
What is the sum of 1/4 and 5/12 ?
Answer: 8/12
Step-by-step explanation:
1/4 times 3 will give you 3/12 and add 5/12
Evaluate the following limit, if it exists : limx→0 (12xe^x−12x) / (cos(5x)−1)
Answer:
[tex]\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}[/tex]
Step-by-step explanation:
Notice that [tex]\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=\frac{12(0)e^{0}-12(0)}{cos(5(0))-1}=\frac{0}{0}[/tex], which is in indeterminate form, so we must use L'Hôpital's rule which states that [tex]\lim_{x \to c} \frac{f(x)}{g(x)}=\lim_{x \to c} \frac{f'(x)}{g'(x)}[/tex]. Basically, we keep differentiating the numerator and denominator until we can plug the limit in without having any discontinuities:
[tex]\frac{12xe^x-12x}{cos(5x)-1}\\\\\frac{12xe^x+12e^x-12}{-5sin(5x)}\\ \\\frac{12xe^x+12e^x+12e^x}{-25cos(5x)}[/tex]
Now, plug in the limit and evaluate:
[tex]\frac{12(0)e^{0}+12e^{0}+12e^{0}}{-25cos(5(0))}\\ \\\frac{12+12}{-25cos(0)}\\ \\\frac{24}{-25}\\ \\-\frac{24}{25}[/tex]
Thus, [tex]\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}[/tex]
what is the awnser to 5+(5x20)x 30
Answer: 3005
Step-by-step explanation: multiply 5 by 20 and it will give 100 then times 30 Equals 3000 and plus gives 3005 . Please mark brainliest
Answer:3005
Step-by-step explanation :multiply 5 by 20 and it will give 100 then multiply by 30 that Equals 3000 and plus 5 that gives you 3005
what is the area of a 45 degree sector of a circle with a radius of 12 in.
given ,
a circle of radius 12 inches
and [tex]\theta[/tex] = 45°
now we know that ,
[tex]\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\ [/tex]
let's now plug in the values of radius and theta as 12 inches and 45° respectively ,
[tex]\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)[/tex]
hope helpful :D
Multiply 2+√10 by its conjugate and simplify.
[tex]\left(2+\sqrt{10} \right)\left(2-\sqrt{10} \right)\\\\=2^2-\left(\sqrt{10} \right)^2\\\\=4-10\\\\=-6[/tex]
please help answer by putting
"question ___ is option ___"
Answer:
B A C A B
Step-by-step explanation:
i took this test before
Working alone, Mr. Tough can grade the final exams in 12 hours. His assistant, Mrs. Nice, cam grade the same exams in 15 hours. What fraction of the exams can Mr.Tough and Mrs.Nice grade in 1 hour if they work together?
Answer:
9n/60
Step-by-step explanation:
add 1/12 + 1/15 which = 5/60 + 4/60.
= 9/60
YAY!!!!!!!
The fraction of the exams that Mr Tough and Mrs Nice grade in 1 hour if they work together is 3/20
What are fractions?In Maths, a fraction is used to represent the portion/part of the whole thing. A fraction has two parts, namely numerator and denominator. There are proper fractions, improper fractions and mixed fractions.
Example: 2/5, 1/4 etc.
How to solve Work and Time problems:We will this equation,
rate × time = work done
For this problem:
Mr Tough's rate:
Mr Tough's rate × 12 hours = final exam
Mr Tough's rate = 1/12
Mrs.Nice's' rate:
Mrs .Nice's' rate × 15 hours = final exam
Mrs .Nice's' rate = 1/15
To make this into a solvable equation, find the total time (T) needed for Mr Tough and Mrs.Nice to grade the final exam. This time is the sum of the rates of Mr Tough and Mrs.Nicea, or:
Total time:
T(1/12 hours + 1/15 hours) = final exam
T = final exam / (1/12 + 1/15)
Simplifying we get,
T = final exam / (0.15)
Now, to finish in 1 hour we will find what fraction of the final exam they can grade, so taking T = 1 hour,
1 hour = final exam / (0.15)
By further simplifying,
final exam = 1 × 0.15
= 0.15
= 15/ 100
= 3/20
Therefore, 3/20 fraction of the final exam they can grade if they work together for 1 hour.
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Solve by completing the square
Answer:
The answer is (-6 + √41), (-6 – √41)
Step-by-step explanation:
We are given an equation
x² + 12x = 5Subtract 5 from both side we get,
x² + 12x – 5 = 5 – 5
x² + 12x – 5 = 0
we get the equation in the form of
ax² + bx + c = 0Here, a = 1, b = 12, c = (-5)
Now, Add and subtract (b/2a)² we get,
x² + 12x + (12/2)² – (12/2)² – 5 = 0
x² + 12x + (6)² – (6)² – 5 = 0
(x + 6)² – 36 – 5 = 0
(x + 6)² – 41 = 0
Now, add 41 both side we get,
(x + 6)² – 41 + 41 = 0 + 41
(x + 6)² = 41
√(x + 6)² = √41
x + 6 = ±√41
x = -6 + √41, -6 – √41
Thus, The roots of the equation is
(-6 + √41) and (-6 – √41).
-TheUnknownScientist 72
Suppose that f(x)=6/x^7 find the following
F’(2)
F’(-1)
Answer:
f’(2) = -21/128
f’(-1) = -42
Step-by-step explanation:
We are given a function:
[tex]\displaystyle \large{f(x)=\frac{6}{x^7}}[/tex]
We want to evaluate f’(2) and f’(-1). Keep in mind that f’(x) denotes or means the derivative of f(x). So what we are going to do first is to find the derivative of given function.
Derive the function, there are two ways to derive it, either using power rules or quotient rules. For this, I’ll demonstrate two methods.
Power Rules
If [tex]\displaystyle \large{f(x)=x^n}[/tex] then [tex]\displaystyle \large{f\prime (x)=nx^{n-1}}[/tex] where n is any real numbers.
Since the function is written in a fraction form, we’ll have to convert it to the x^n form using law of exponent.
[tex]\displaystyle \large{f(x)=\frac{6}{x^7} \to f(x)=6\cdot \frac{1}{x^7}}[/tex]
Law of Exponent I
[tex]\displaystyle \large{\frac{1}{a^n} = a^{-n}}[/tex]
Therefore:
[tex]\displaystyle \large{f(x)=6x^{-7}}[/tex]
Then derive the function using power rules:
Property of Differentiation I
[tex]\displaystyle \large{y=kf(x) \to y\prime = kf\prime (x)}[/tex] where k is a constant.
[tex]\displaystyle \large{f\prime (x)=6\cdot -7x^{-7-1}}\\\displaystyle \large{f\prime (x)=6\cdot -7x^{-8}}\\\displaystyle \large{f\prime (x)=-42x^{-8}}[/tex]
Quotient Rules
[tex]\displaystyle \large{y=\frac{f(x)}{g(x)} \to y\prime = \frac{f\prime (x)g(x)-f(x)g\prime (x)}{[g(x)]^2}}[/tex]
If f(x) = k or a constant then:
Property of Differentiation II
[tex]\displaystyle \large{y=k \to y\prime = 0}[/tex] for k is a constant.
[tex]\displaystyle \large{y=\frac{k}{g(x)} \to y\prime = \frac{0\cdot g(x)-kg\prime (x)}{[g(x)]^2}}\\\displaystyle \large{y\prime = \frac{-kg\prime (x)}{[g(x)]^2}}[/tex]
Therefore:
[tex]\displaystyle \large{f\prime (x)=\frac{-6\cdot 7x^{7-1}}{[x^7]^2}}\\\displaystyle \large{f\prime (x)=\frac{-42x^6}{x^{14}}}\\\displaystyle \large{f\prime (x)=-42x^{6-14}}\\\displaystyle \large{f\prime (x)=-42x^{-8}}[/tex]
Laws of Exponent used above:
[tex]\displaystyle \large{(a^n)^m = a^{nm}}\\\displaystyle \large{\frac{a^n}{a^m} = a^{n-m}}[/tex]
Therefore the derivative of function is:
[tex]\displaystyle \large{f\prime (x) = -42x^{-8}}[/tex] or [tex]\displaystyle \large{f\prime (x)=-\frac{42}{x^8}}[/tex]
Next is to substitute x = 2 and x = -1 in the derivative.
[tex]\displaystyle \large{f\prime (2)=-\frac{42}{2^8}}\\\displaystyle \large{f\prime (2) = -\frac{42}{256}}\\\displaystyle \large{f\prime (2)= -\frac{21}{128}}[/tex]
And:
[tex]\displaystyle \large{f\prime (-1)=-\frac{42}{(-1)^8}}\\\displaystyle \large{f\prime (-1) = -\frac{42}{1}}\\\displaystyle \large{f \prime (-1) = -42}[/tex]
Therefore, f’(2) = -21/128 and f’(-1) = -42.
If total assets increased $150,000 during the year and total liabilities decreased $60,000, what is the amount of owner’s equity at the end of the year?
Answer:
$710,000
Step-by-step explanation:
The computation of the owner’s equity at the end of the year is given below:
We know that
The accounting equation equals to
Total assets = Total liabilities + owners equity
where,
Total assets = $800,000 + $150,000 = $950,000
And, the total liabilities = $300,000 - $60,000 = $240,000
So, the owners equity at the end of the year would be
= $950,000 - $240,000
= $710,000
What is the product?
48+ 2 K-2
24 2+1
4
O2k+1
2
K-2
2
2641
2
R+2
Answer:
[tex]\frac{2}{k+2}[/tex]
Step-by-step explanation:
Simplify the expression and you will get this.
hope this helps
11 18 The diagram shows an equilateral triangle. All measurements are in cm. NOT TO SCALE 2x+2 3x+4 3 OLTY а The perimeter of the triangle is 57 cm. Find the length of a.
Answer:
a = 7
Step-by-step explanation:
3x + 4 = 57 ÷ 3
3x + 4 = 19
3x = 15
x = 5
2x + 2 = 2(5) + 2 = 10 + 2 = 12
19 - 12 = 7
a = 7
hope this helps!! p.s. i really need brainliest :)
what is 2(9p-1/2) equil to?
Answer:
Step-by-step explanation:
Use distributive property: a*(b - c) = (a*b) -(a*c).
Here, a = 2 ; b = 9p & c = 1/2
[tex]2*(9p - \dfrac{1}{2})=2*9p-2*\dfrac{1}{2}\\\\\\ = 18p - 1[/tex]
A cone has a circular base of radius 8m. Given that the total surface area of the cone is 350m^2, find the slant height
Radius of Circular Base Of Cone= 8m
Total Surface Area= 350m²
Considering Slant Height as l
SolvingWe know,
Total Surface Area= Curved Surface Area of Cone+ Area of circular Base
i.e.,
[tex]350 { \text{m}}^{2} = \pi \times r \times l + \pi \times {r}^{2} [/tex]
[tex]350 = \pi \times r(l \times r) \\ \\ \implies 350 = 3.142 \times 8(l + 8) \\ \\ \implies \frac{350}{3.142 \times 8} = l + 8 \\ \\ \implies 13.924 = l + 8 \\ \\ \implies l = 13.924 - 8 \\ \\ \therefore l = 5.924 \: \text{cm}[/tex]
So, Slant Height= 5.924 cm
Hope This Helpsthe length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
Answer:
Width = 12in, Length = 17in
Step-by-step explanation:
We can create two expressions from the given statements:
1) L (length) = 5 + W (width)
and
2) 58 = 2L + 2W (the equation for rectangular perimeter)
Substituting L from the first equation into the second equation yields:
58 = 2(5+W) + 2W
Distributing the 2 and solving for W yields:
12in = W
Plug this back into the first expression,
L = 5 + 12
L = 17in
Answer:
width = 12 in
length = 17 in
Step-by-step explanation:
Let width of rectangle = x
⇒ length of rectangle = x + 5
Given:
Perimeter = 58 inPerimeter = 2 × width + 2 × length
⇒ 58 = 2x + 2(x + 5)
⇒ 58 = 2x + 2x + 10
⇒ 58 = 4x + 10
⇒ 48 = 4x
⇒ x = 12
Therefore,
width = x = 12 in
length = x + 5 = 12 + 5 = 17 in
At a sale, a desk is being sold for 29% of the regular price. The sale price is $272.60.
What is the regular price?
Answer:$940
Step-by-step explanation:
29%=$272.60
100%=
100%*$272.60/29%=$940
$940
Sam has a small paper delivery business. His parents require him to to save $1 every $5 he earns. If he made $200, how much would he need to save
i need helps pls
The net of a square pyramid and its dimensions are shown in the diagram. What is the total surface area in square feet?
5,760 ft²
976 ft²
1,120 ft²
1,040 ft²
The net square pyramid and its given dimension as shown has a total surface area of 1040 ft².
How to calculate surface area of a square pyramidSurface area of a square pyramid = A + 1 / 2 ps
where
A = area of the basep = perimeter of bases = slant heightTherefore,
A = l²
where
l = length = 20 ftA = 20² = 400 ft²
p = 4l = 4 × 20 = 80 ft
s = 16 ft
Therefore,
Surface area = 400 + 1 / 2 × 80 × 16
Surface area = 400 + 1280 / 2
Surface area = 400 + 640
Surface area = 1040 ft²
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3. Avery records her rock-climbing progress and finds that her altitude, in kilometers above sea
level, can be represented by a linear model, A = 7+ 1.3t, where t is the number of hours since
Avery started climbing.
Based on this model, how many kilometers above sea level was Avery's altitude before she started
climbing?
km
Using the given linear function, it is found that Avery was 7 kilometers above sea level before she started climbing.
What is a linear function?A linear function is modeled by:
[tex]y = mx + b[/tex]
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can be interpreted as the initial value.In this problem, her altitude in kilometers after t hours is modeled by:
A(t) = 7 + 1.3t.
The y-intercept is of b = 7, which means that Avery was 7 kilometers above sea level before she started climbing.
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A rectangle has a perimeter of 20 cm. What will the perimeter be if the rectangle tripled in size?
ITS A VOLUME QUESTION
Answer:
Step-by-step explanation:
Holding the perimeter fixed, the shape with greatest area is square ( all sides of the same) length) For your name example a square with a perimeter of 20 cm has sides of 5 cm and area of 5 times 4=20 cm) ^3 hope this helps
The average number of potholes per 10 miles of paved U.S. roads is 130. Assume this variable is approximately normally distributed and has a standard deviation of 5. Find the probability that a randomly selected road has more than 142 potholes per 10 miles
Answer:
54.03% probability that a randomly selected road has between 128 and 136 potholes per 10 miles.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the probability that a randomly selected road has between 128 and 136 potholes per 10 miles.
This probability is the pvalue of Z when X = 136 subtracted by the pvalue of Z when X = 128. So
X = 136
has a pvalue of 0.8849.
X = 128
has a pvalue of 0.3446.
0.8849 - 0.3446 = 0.5403
54.03% probability that a randomly selected road has between 128 and 136 potholes per 10 miles.
for each of the figures, write an absolute value equation that has the following solution set 3 and 7
The solution set 3 and 7 are the true values of the absolute value equation
The absolute value equation that has a solution set of 3 and 7 is [tex]|x - 5| = 2[/tex]
How to determine the absolute value equation?The solution sets of the absolute value equation are given as:
x = {3, 7}
Calculate the mean of the solutions
[tex]x_1 = \frac{7 +3}{2}[/tex]
[tex]x_1 = 5[/tex]
Calculate the difference of the solutions divided by 2
[tex]x_2 = \frac{7 - 3}{2}[/tex]
[tex]x_2 = 2[/tex]
The absolute value equation is the represented as:
[tex]|x - x_1| - x_2 = 0[/tex]
Substitute known values
[tex]|x - 5| - 2 = 0[/tex]
Add 2 to both sides
[tex]|x - 5| = 2[/tex]
Hence, the absolute value equation that has the a solution set of 3 and 7 is [tex]|x - 5| = 2[/tex]
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A chocolatier makes chocolate covered cherries in the form of spheres. Amelia
measures the outer diameter of these chocolates to be 2.8 cm. If she measures the
thickness of the chocolate to be 0.5 cm, how much chocolate is used in one of the
chocolate covered cherries? Round your answer to the nearest hundredth if
necessary. (Note: diagram is not drawn to scale.)
The volume of the chocolate is the amount of choclate used in the cherries
The amount of chocolate used is 17.24 cubic centimeters
How to determine the amoumt of chocolate?Start by calculating the volume of the cherries using:
V = 4/3 π(D/2)^3
The diameter of the cherry is 2.8 cm.
So, we have:
V = 4/3π(2.8/2)^3
Evaluate
V = 11.49
Next, calculate the volume of the cherry and the chocolate.
V = 4/3π(0.5+2.8/2)^3
V = 28.73
Calculate the difference (d) between both volumes
d = 28.73 - 11.49
d = 17.24
Hence, the amount of chocolate used is 17.24 cubic centimeters
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Choose the best answer that represents the property used to rewrite the expression.
log6 20 - log6 x = log6 20/x
Answer:
㏒₆ (18) - ㏒₆ (6) = ㏒₆ (3)Here subtraction of logarithm given. So we have to use the property of logarithm of quotient.The property says that㏒ₐ (M) - ㏒ₐ (N) = ㏒ₐ (M/N)So for subtraction we have to divide them. That is logarithm of difference becomes the quotient.So we can write,㏒₆ (18) - ㏒₆ (6) = ㏒₆ (18/6) If we divide 18 by 6 we will get 3.So, ㏒₆ (18) - ㏒₆ (6) = ㏒₆ (3)
Step-by-step explanation:
Answer:Quotient Property
Step-by-step explanation:The property used to rewrite the expression is the quotient rule of logarithms, which states that log_b(x/y) = log_b(x) - log_b(y).
x^3-125=0
what’s the nth root
Peyton's family took a road trip to the Grand Canyon. Peyton fell asleep 77% of the way through the trip. If the total length of the trip was 1000 miles, how many miles had they travelled when Peyton fell asleep?
The miles Peyton's family had travelled when he fell asleep is 770 miles
How many miles had they travelled when Peyton fell asleep?Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred. The sign used to represent percentages is %.
Miles when Peyton fell asleep = 77% x 1000 = 770 miles
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In your own words, name the two operations used for converting weight measurements, and describe when to use each.
What are the 2 operations that you use to convert weight? I'm confused.
Is it multiplying and dividing?
Answer:
In physics the standard unit of weight is Newton, and the standard unit of mass is the kilogram. On Earth, a 1 kg object weighs 9.8 N, so to find the weight of an object in N simply multiply the mass by 9.8 N. Or, to find the mass in kg, divide the weight by 9.8 N.Divide the object's weight by the acceleration of gravity to find the mass.
Step-by-step explanation:
this is what i think
What is the answer for this 4² × 4²
Answer:
4squared is 16 so 16×16=256
hope it help
Answer:
4^2=16 multiplyin 16 by 16 gets you 256
Step-by-step explanation: