An acute angles measure is
A. Between 0 and 90
B. Between 90 and 180
C. Exactly 90

Answer:

36

Step-by-step explanation:

63/(7/4) 63 divided by 7/4

63* 4/7 63 multiplied by 4/7

=36 answer is 36

Answer:

Step-by-step explanation:

Given functions are,

f(x) = [tex]\sqrt{x} +3[/tex]

g(x) = 4 - [tex]\sqrt{x}[/tex]

22). (f - g)(x) = f(x) - g(x)

                    = [tex]\sqrt{x}+3-(4 - \sqrt{x} )[/tex]

                    = [tex]\sqrt{x} +3-4+\sqrt{x}[/tex]

                    = [tex]2\sqrt{x}-1[/tex]

     Domain of the function will be [0, ∞).

23). (f . g)(x) = f(x) × g(x)

                   = [tex](\sqrt{x}+3)(4-\sqrt{x} )[/tex]

                   = [tex]4(\sqrt{x}+3)-\sqrt{x}(\sqrt{x}+3)[/tex]

                   = [tex]4\sqrt{x} +12-x-3\sqrt{x}[/tex]

                   = [tex]-x+\sqrt{x}+12[/tex]

      Domain of the function will be [0, ∞).

Answer:

+2633 ft

Step-by-step explanation:

The city is above sea level meaning it is a positive number.

Answer:

1.5(B)

Step-by-step explanation:

This is a geometric sequence where each number is 1/2 times the last. So 3/2 is 1.5.

Answer:

0.1

Step-by-step explanation:

r = y/x

r = 1.4 / 14 = 0.1

Answer:

Step-by-step explanation:

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that [tex]a[/tex] raised to the power [tex]b[/tex] can be written as [tex]a^b[/tex].

Any non zero number raised to the power 0 is always 1. It means,

[tex]a^0=1[/tex], where [tex]a\neq 0[/tex].

-3 raised to the power 0 [tex]=(-3)^0[/tex]

                                         [tex]=1[/tex]

Therefore, the value of the given statement is 1.

Answer:

y= ¼x +1

Step-by-step explanation:

Rewriting the equation into the slope-intercept form (y= mx +c, where m is the gradient and c is the y- intercept):

4y -x= -20

4y= x -20 (+x on both sides)

y= ¼x -5 (÷4 throughout)

Thus, slope of given line is ¼.

Parallel lines have the same gradient.

Gradient of line= ¼

y= ¼x +c

To find the value of c, substitute a pair of coordinates into the equation.

When x= 8, y= 3,

3= ¼(8) +c

3= 2 +c

c= 3 -2

c= 1

Hence the equation of the line is y= ¼x +1.

Answer:

6 x 2 = 8 + 11 = 19 x 3 = 57

Step-by-step explanation:

Answer:

The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.

Step-by-step explanation:

Here's why each one did or didn't work:

First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.

Second answer- since you added the numerator separately and then did the basic division, this worked.

Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.

Answer:

[tex](2 \ sin 60)(3\ cos 60) +3\ tan 30\ =\ \frac{5\sqrt3}{2}[/tex]

Step-by-step explanation:

[tex](2 \ sin 60)(3 \ cos 60) + 3\ tan 30\\\\= (2 \times \frac {\sqrt3}{2}) (3 \times \frac{1}{2})+ (3 \times \frac{1}{\sqrt3})\\\\=(\sqrt{3}\ \times \frac{3}{2})+ \frac{3}{\sqrt3}\\\\=\frac{3\sqrt3}{2}+\frac{3}{\sqrt3}\\\\=(\frac{3\sqrt3}{2} \times \frac{\sqrt3}{\sqrt3})+(\frac{3}{\sqrt3} \times \frac{2}{2})\\\\=\frac{3\times (\sqrt3)^2}{2\sqrt3}\ + \ \frac{6}{2 \sqrt3}\\\\=\frac{3 \times 3}{2 \sqrt3} +\frac{6}{2 \sqrt3}\\\\=\frac{9+6}{2\sqrt3}\\\\=\frac{15}{2\sqrt3} \times \frac{\sqrt3}{\sqrt3}\\\\[/tex]

[tex]=\frac{15 \sqrt3}{2 \times (\sqrt{3})^2}\\\\=\frac{15 \sqrt 3}{2 \times 3}\\\\=\frac{5\sqrt3}{2}[/tex]

Answer:

120 in^2

Hope it helps

Answer: -5  < x < -2 or (-5, -2)

Step-by-step explanation:

Graph- (-5, -2)

Inequality- -5  < x < -2

k<28

Step 1: Simplify both sides of the inequality.

−k+28>0

Step 2: Subtract 28 from both sides.

−k+28−28>0−28

−k>−28

Step 3: Divide both sides by -1.

−k /−1  >  −28 /−1

k<28

Answer:

k < 28

Step-by-step explanation:

Given inequality :-

Last Option is correct .

Answer:

See explanation

Step-by-step explanation:

The given options are not properly formatted; so, I will give a general explanation instead

An equation is said to be radical if its variable is in a radicand sign.

For instance, the following equation is a radical;

[tex]\sqrt x + 2 = 4[/tex]

In the above equation, x is the variable, and it is in [tex]\sqrt[/tex] sign

However, the following equation is not a radical equation

[tex]x + \sqrt 4 = 2[/tex]

Because the variable is not in a radicand

i dont know

hi hi hi hi hi ih ih ih ihi ih i h

Answer:

D

Step-by-step explanation:

The answer is D because if you flip those circles down and wrap the rectangle around it will create a cylinder

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

inside the circle

Step-by-step explanation:

we want to verify whether (-4,2) lies inside or outside or on the circle to do so recall that,

step-1: define h,k and r

the equation of circle given by

[tex] \displaystyle {(x - h)}^{2} + (y - k) ^2= {r}^{2} [/tex]

therefore from the question we obtain:

step-2: verify

In this case we can consider the second formula

the given points (-4,2) means that x is -4 and y is 2 and we have already figured out h,k and r² therefore just substitute the value of x,y,h,k and r² to the second formula

[tex] \displaystyle {( - 4 - 0)}^{2} + (2 - 0 {)}^{2} \stackrel {?}{ < } 25[/tex]

simplify parentheses:

[tex] \displaystyle {( - 4 )}^{2} + (2 {)}^{2} \stackrel {?}{ < } 25[/tex]

simplify square:

[tex] \displaystyle 16 + 4\stackrel {?}{ < } 25[/tex]

simplify addition:

[tex] \displaystyle 20\stackrel { \checkmark}{ < } 25[/tex]

hence,

the point (-4, 2) lies inside the circle

Answer:

V=1/3(pi)*r^2*h

Step-by-step explanation:

Think about a cylinder. If you combine 3 cones, you get a cylinder. Find the volume of a cylinder

Answer:

Step-by-step explanation:

V = 1/3 r^2 * π * h

3V = r^2 *π * h

3V/π = r^2 * h

h = 3V/(r^2 * π)

Answer:

4

Step-by-step explanation:

3*10=10+5s

30 = 10 + 5s

30-10 = 5s

or, 20/5= s

or, 4 =s

therefore the value of s is 4.

thank you

Answer:

The equation of line which is parallel to the given line is y =  3 x + k.

Step-by-step explanation:

The equation of the line is

y = 3 x - 8

Compare with the standard equation

y = mx + c

The slope of line is

m = 3

So, the line parallel to the given line is

y = 3 x + k

where, k is any real number.

Answer:

length divided by breadth divided by  height

pls add me as brainliest

Solution:

20 - 1 1 = 9 cm

We can divide figure in 2 parts

rectangle = 14 cmx 11 cm

square = 9 cm x 9  cm

Area of rectangle = 14 * 11 = 154 cm²

Area of square = 9 * 9 = 81 cm²

Total area = 154 + 81

= 235 cm²

Answer:

15/12

Step-by-step explanation:

[tex]x = \frac{31}{12} - \frac{8}{6} = \frac{15}{12} [/tex]

and it says don't reduce otherwise u could also say 5/4

Answer:

parallel

Step-by-step explanation:

Let's rewrite each equation into the slope-intercept form so that we can easily identify the slope of each line.

slope-intercept form: y= mx +c, where m is the gradient and c is the y-intercept.

9x +3y= 12

3x +y= 4 (÷3 throughout)

y= -3x +4 -----(1)

24x +8y= 35

8y= -24x +35 (-24x on both sides)

[tex]y = - 3x+ 4 \frac{3}{8} [/tex] -----(2)

Thus, the slopes of the lines are both -3. Since both lines have the same gradient, they are parallel to each other.

Notes:

• parallel lines have the same gradient

• the product of the gradients of two perpendicular lines is -1

• gradient and slope has the same meaning and can thus be used interchangeably

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

[tex]\implies 360m^2 = 360 \times 10^4 \ cm^2 [/tex]

And , the number of tiles required will be ,

[tex]\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}[/tex]

Hence the required answer is 1500 .

Answer:

[tex] \displaystyle\rm 15000[/tex]

Step-by-step explanation:

we given the area of rectangular floor and tile we want to find the number of tiles needed to tile the floor

notice that the area of the rectangular floor is in meter and the tile in cm so we need to convert cm to meter in order to figure out the number of tiles needed to tile the floor

therefore,

[tex] \rm 1m \implies 100 c m\\ \rm{1m}^{2} \implies10000 {cm}^{2} [/tex]

remember that,

[tex] \displaystyle\rm \: N _{ \rm tile} = \frac{A _{ \rm floor} }{A _{ \rm tile} } [/tex]

Thus substitute:

[tex] \displaystyle\rm \: N _{ \rm tile} = \frac{360 \times 10000 {cm}^{2} }{ {240cm}^{2} } [/tex]

simplify which yields:

[tex] \displaystyle\rm \: N _{ \rm tile} = 15000[/tex]

hence,

15000 of tiles needed to tile the floor

Answer:

35/40

Step-by-step explanation:

To compare, both denominator should be same.

[tex]\frac{15}{20}=\frac{15*2}{20*2}=\frac{30}{40}\\\\\\\frac{30}{40} \ < \ \frac{35}{40}\\\\\\\frac{15}{20} \ < \ \frac{35}{40}[/tex]

[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]

[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]

⠀⠀⠀⠀

[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]

we have to find the greater number between 15/20 and 35/40

To do this,

we have to compare the denominator same.

According to the question,

we have to find the greatest one

[tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]

⠀⠀

[tex]\therefore\mathrm{\dfrac{35}{40} > \dfrac{15}{20} }[/tex]

⠀⠀