Amphoteric oxides exhibit both acidic and basic properties. True. False.

0.723 is the [H ] (molarity) before any base is added.

the balanced equation for the acid-base reaction is

KOH + HClO₄ ---> KClO₄ + H₂O

stoichiometry of KOH to HClO₄ is 1:1

The number of HClO₄ moles - 0.723 M / 1000 mL/L x 25.0 mL = 0.0181 mol

Number of KOH moles - 0.27 M/ 1000 mL/L x 80.0 mL = 0.0216 mol

KOH is a strong acid and HClO₄ is a strong base therefore complete dissociation takes place.

the acid reacts with base in a 1:1 molar ratio, there's excess base remaining.

excess OH⁻ ions - 0.0216 - 0.0181 = 0.0035 mol

concentration is calculated as the number of moles/volume

volume of solution - 25.0 + 80.0 = 105.0 mL

[OH⁻] = 0.0035 mol / 0.105 L = 0.033 M

pOH = -log [OH⁻]

pOH = -log(0.033 M)

pOH = 1.48

pH can be calculated by knowing the pOH

pH + pOH = 14

pH = 14 - 1.48 = 12.52

pH = -log [H₃O⁺]

[H₃O⁺] = antilog(-12.52)

[H₃O⁺]  = 3.0 x 10⁻¹³ M

0.723 is the [H ] (molarity) before any base is added.

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Answer:

» Chlorine (Cl) is the oxidizing agent because it gains an electron.

Explanation:

Oxidization is the process of losing electrons during an ionic reaction.

In the reaction above, aqueous chlorine captures the electrons of bromide ion hence becoming oxidized. In this sense, since aqueous chlorine is the one gaining electrons, it oxidizes bromide to bromine

[tex]{ \rm{Cl _{2(aq)}+ 2Br {}^{ - } _{(aq)} \dashrightarrow 2Cl {}^{ - } _{(aq)} + Br _{2( aq)}}}[/tex]

Answer:

c

Explanation:

edge 2022

You picked up a dirty test tube with a sticky substance on the outside. You get some of this substance on your hand. The first thing that I should do is wash my hand and then tell the teacher.

A test tube often referred to as a culture tube or sample tube, is a typical item of lab glassware that is made up of a finger-like length of clear plastic or glass tubing that is open at the top and closed at the bottom. Usually, test tubes are stored on dedicated racks.

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The type of cleaning agent that should be used to clean a laminar flow hood is 70% Isopropyl Alcohol.

Isopropyl alcohol is mixed with water for use as a rubbing-alcohol antiseptic. It is also utilized in aftershave creams, hand lotions, and other cosmetics. In enterprise, it is used as a less expensive solvent for cosmetics, drugs, shellacs, and gums, in addition to denaturing ethanol (ethyl alcohol).

Isopropyl alcohol is a colorless, flammable chemical compound with a robust alcoholic smell. As an isopropyl institution related to a hydroxyl group, it's far the handiest example of a secondary alcohol, wherein the alcohol carbon atom is connected to 2 other carbon atoms.

Isopropyl alcohol is pure alcohol and is a colorless liquid with a musty, sharp odor. There are no other components in a bottle of isopropyl alcohol. through assessment, rubbing alcohol consists of isopropyl alcohol among different components, including water. maximum rubbing alcohol manufacturers incorporate 70% isopropyl alcohol.

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Answer:

1120 mm Hg

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Based on the type of experiment that is being conducted:

This is the term that is used to refer to the variable that is used to arrive at conclusions about the dependent variable.

The experiment is trying to tell us that the temperature of a material is the function of the heat applied to it and the type of material.

This is the term that is used to refer to the variable of interest. It is what is being tested in the experiment.

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The products will be [tex]ZnCl_2(s) + H_2(g)[/tex]

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: [tex]Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)[/tex]

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

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Answer:

6.21 moles O

Explanation:

To find the moles of oxygen, you need to (1) convert grams Mn(ClO₄)₄ to moles Mn(ClO₄)₄ (via molar mass) and then (2) convert moles Mn(ClO₄)₄ to moles O (via mole-to-mole ratio from formula subscripts). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.

Molar Mass (Mn(ClO₄)₄): 452.74 g/mol

1 Mn(ClO₄)₄ = 1 Mn and 4 Cl and 16 O

175.7 g Mn(ClO₄)₄           1 mole                   16 moles O
---------------------------  x  -------------------  x  ---------------------------  =  6.21 moles O
                                       452.74 g            1 mole Mn(ClO₄)₄

Part of the investigation must be measuring the pressure inside the lighter fuel tank.

The pressure of gas measures how compact the gas molecules are. We know that the more compacted the gas molecules are, the more likely the gas will exist in the liquid state.

Hence, part of the investigation must be measuring the pressure inside the lighter  fuel tank.

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Derivatization means adding fluorescent labels or combining the analyte with chiral reagents or other chemicals to increase detectability.

Some analytes must be derivatized to increase their column retention or detectability.

Retention time can be referred to as the amount of time a solute spends in the stationary and mobile phases of a column.

Detectability is the ability of an analyte to get detected in the mobile phase of chromatography.

The refractometer, fluorescence detector, and UV detector are the three most popular liquid chromatography detectors. These detectors increase the detectability.

For derivatization, the fluorescence detector are used.

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18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).

The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.

When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.

1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.

Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])

3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].

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To make a solution of lemonade, lemon juice and sugar are dissolved in water. the water is the Solvent in this example.

Solvent Examples. Common examples of solvents consist of water, ethanol, methanol, and acetone. The term 'solvent' may be defined as a substance that has the ability to dissolve a given solute to form a solution with it.

Solvents are substances that are used to dissolve the solutes used in the formulation. These solutes can be solids, liquids, or gaseous in nature. Thus solvents are used to get a solution upon interacting the solute with a suitable solvent.

Solvents are usually, however not usually, liquids. They can also be gases or solids. The material dissolved in the solvent is referred to as the solute. collectively, the solvent and solute comprise the solution.

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The number of atoms in one unit cell with one atom at each corner, one atom on 8 of the edges, and one atom on 6 of the faces are 4.6atoms.

There is one atom at each corner and there are 8 corners in a unit cell, so there is one atom in each of the eight corners.

Therefore, the number of atom from corners = 1 x 1/8 = 1atom

There are 12 edges, since there are one atom on 8 of the edges the number of atom = 1 x 8/12 = 0.6atom

There is one atom at each face and there are 6 faces in a unit cell, each atom shares two face.

Therefore, the number of atoms on face = 2 x 1/6 = 3

Total number of atoms in one unit cell = 1 + 0.6 + 3 = 4.6atoms

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Fractional distillation is used for the refining of crude petroleum.

Fractional distillation is the procedure used to separate crude oil's numerous constituents.

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Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

H₂ + F₂ → 2HF

An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.

It is expressed as:

PV = nRT

where,

P = Pressure

V = Volume

n = number of moles

R = Ideal gas constant

T = temperature

Here,

P = 1 atm   [At STP]

V = 110 ml = 0.11 L

T = 273 K   [At STP]

R = 0.0821   [Ideal gas constant]

Now put the values in above expression

PV = nRT

1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K

[tex]n = \frac{1\ \text{atm} \times 0.11\ L}{0.0821\ \text{L. atm/ K. mol} \times 273\ K}[/tex]

n = 0.0049 mol

To calculate the concentration of resulting solution use the expression

[tex]C = \frac{n}{V}[/tex]

   [tex]= \frac{0.0049}{0.15}[/tex]  

   = 0.032 M

Thus from the above conclusion we can say that Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

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Answer:

Mn₁O₂

Explanation:

To find the empirical formula, you need to (1) determine how many grams of each element are within the compound, then (2) convert grams to moles (via the atomic masses of each element), and then (3) determine the mole-to-mole ratio of each element.

(Step 1)

Because the percents add to equal 100%, we can say that each percent is the mass of each element.

63% Mn ----> 63 grams Mn

37% O ----> 37 grams O

(Step 2)

We need to convert each mass to moles using the atomic masses. The atomic masses are a ratio comparing the mass of each element per every 1 mole.

Atomic Mass (Mn): 54.983 g/mol

Atomic Mass (O): 15.998 g/mol

63 grams Mn                 1 mole
----------------------  x  -------------------------  =  1.15 moles Mn
                                 54.983 grams

37 grams O                1 mole
--------------------  x  ------------------------  =  2.31 moles O
                               15.998 grams

(Step 3)

You can find the mole-to-mole ratio of each element in the compound by dividing the calculated mole values by the smallest mole value. In this case, since 1.15 moles was the smallest value calculated, it should be the divisor. The resulting amounts are the subscripts within the empirical formula.

1.15 moles Mn / 1.15 moles  =  1 moles Mn

2.31 moles O / 1.15 moles  =  2 moles O

Ratio of MnO = 1:2

This make the empirical formula: Mn₁O₂

Considering the definition of empirical formula, the empirical formula is C₃H₈.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

In this case, in first place you know the percent composition:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

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A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

According to Stoichiometry

[tex]7\ \text{mol C} \times \frac{1\ \text{mol O}}{1\ \text{mol C}}[/tex]

= 7 mol O

Thus from the above conclusion we can say that A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: This is the chemical formula for Nickel Tetracarbonyl (a powerfully poisonous liquid used in Nickel Refining).

Ni(CO)₄

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample ?

There is nearly 1000 times more uranium diffused in our oceans as compared to mine on land.

The world ocean contain more than 4 billion metric tons of dissolved uranium . Uranium is removed from ocean by diffusion across the sediment-water interface of organic-rich sediments.

Uranium ore is deposits are economically recovered within earth crust. The uranium elements is common elements present in earth crust as it found 40 times more as compare to silver and 500 times more as compare to gold. It can found in everywhere in the rock , soil, river, and ocean.

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Empirical formula mass

[tex]\\ \tt{:}\dashrightarrow 12+2+16[/tex]

[tex]\\ \tt{:}\dashrightarrow 30g/mol[/tex]

n:-

[tex]\\ \tt{:}\dashrightarrow \dfrac{Molecular\:mass}{Empirical\:mass}[/tex]

[tex]\\ \tt{:}\dashrightarrow \dfrac{90}{30}[/tex]

[tex]\\ \tt{:}\dashrightarrow 3[/tex]

Molecular formula

[tex]\\ \tt{:}\dashrightarrow n\times Empirical\: formula [/tex]

[tex]\\ \tt{:}\dashrightarrow 3(CH_2O)[/tex]

[tex]\\ \tt{:}\dashrightarrow C_3H_6O_3[/tex]

Answer: 2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Explanation: The quantities of aluminum and copper sulfate used as reactants will be such that the copper sulfate will be in excess. Thus, the aluminum will be the limiting factor in determining the number of moles (gram-atoms) of products that will be formed.

Answer:

Explanation:  The reaction between hydrazine and hydrogen peroxide yields nitrogen and water. The balanced chemical reaction is:

N2H4 + 2H2O2  N2 + 4H2O

which means that the mole ratio between hydrazine and hydrogen peroxide is 1:2 and the mole ratio between hydrazine and water is 1:4.

Answer:

1.) 2 Mg + H₂ ------> 2 MgH

2.) 2 K + O₂ -----> 2 KO

3.) K + S -----> KS

4.) 2 Ba + Br₂ -----> 2 BaBr

5.) 2 Ca + N₂ ------> 2 CaN

Explanation:

An equation is balanced when there is an equal amount of each element on both sides of a reaction. If there is an unequal amount, they can be altered by adding coefficients which modify the amount of an element/molecule. It is important that the coefficients are as small as possible while staying as whole numbers.

1.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Mg + H₂ -----> MgH

Reactants: 1 magnesium, 2 hydrogen

Products: 1 magnesium, 1 hydrogen

The balanced equation:

2 Mg + H₂ ------> 2 MgH

Reactants: 2 magnesium, 2 hydrogen

Products: 2 magnesium, 2 hydrogen

2.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

K + O₂ -----> KO

Reactants: 1 potassium, 2 oxygen

Products: 1 potassium, 1 oxygen

The balanced equation:

2 K + O₂ -----> 2 KO

Reactants: 2 potassium, 2 oxygen

Products: 2 potassium, 2 oxygen

3.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

K + S -----> KS

Reactants: 1 potassium, 1 sulfur

Products: 1 potassium, 1 sulfur

This equation is already balanced with all the elements/compounds having coefficients of 1.

4.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Ba + Br₂ -----> BaBr

Reactants: 1 barium, 2 bromine

Products: 1 barium, 1 bromine

The balanced equation:

2 Ba + Br₂ -----> 2 BaBr

Reactants: 2 barium, 2 bromine

Products: 2 barium, 2 bromine

5.) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Ca + N₂ ------> CaN

Reactants: 1 calcium, 2 nitrogen

Products: 1 calcium, 1 nitrogen

The balanced equation:

2 Ca + N₂ ------> 2 CaN

Reactants: 2 calcium, 2 nitrogen

Products: 2 calcium, 2 nitrogen

Hydrocarbons (typically petroleum products), which separate in water and have a Specific Gravity of less than one, represent a significant hazard to firefighters. Why?

Any member of the class of organic chemical compounds known as hydrocarbons only includes the atoms carbon (C) and hydrogen (H). The hydrogen atoms bond to the carbon atoms in a variety of ways to create the compound's structural framework.

Although there could be thousands of different hydrocarbon molecules in a given crude oil, these descriptions only focus on the type of hydrocarbon that predominates in the combination. Typically, each sort of molecule can be found in all naturally occurring crude oils.

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Answer:

C. Parasympathetic

Explanation:

A solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL. Details about weights per volume can be found below.

Weights per volume is a unit for measuring density of a substance. It can be converted to g/mL using the following expression:

w/v% = g/100mL

According to this question, a solution contains 7.8% W/V ethanol. The equivalent of this in g/mL is as follows:

7.8% W/V = 7.8g/100mL

= 0.078g/mL

Therefore, a solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL.

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Answer:

3 Electron shell/orbit

Explanation:

the number of shell an element has is what determines the period of that element.

One way in which God showed precision in his creation was his mighty love on the he has on his creation

The book of John made us to know that: For God do love the world that he gave his only begotten son that whosoever believeth in him shall not perish but have everlasting life.

Creations is the art of producing or making something out of something

So therefore, one way in which God showed precision in his creation was his mighty love on the he has on his creation

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Metal which produces hydrogen gas:

Aluminum metal produces hydrogen gas with dilute hydrochloric acid as well as sodium hydroxide.

What are amphoteric oxides?

Amphoteric oxides are the metal oxides which reacts with both acids and bases.

Some metals are also amphoteric, ie. on reaction with acid or base, the product will be salt and Hydrogen gas.

Amphoteric metal + acid/base →  salt + hydrogen gas

Few metals of the periodic table are amphoteric in nature. Like Aluminum, Zinc etc.

Reactions:

Reaction with dilute NaOH:

2Al + 2NaOH + 2[tex]H_{2}[/tex]O → 2NaAl[tex]O_{2}[/tex] + [tex]H_{2}[/tex]

Reaction with dilute HCl:

2Al + 6HCl(aq) → 2Al[tex]Cl_{3}[/tex] + 3[tex]H_{2}[/tex]

Dilute and Aqueous (aq) means mixed with water ([tex]H_2O[/tex])

These reaction are balanced in order to follow the Law of conservation of mass.

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Answer:

FeCO₃,  Fe(IO₃)₂,  Pb(CO₃)₂,  Pb(IO₃)₄

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) FeCO₃

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

2.) Fe(IO₃)₂

-----> Fe²⁺ and IO₃⁻

-----> +2 + (-1) + (-1) = 0

3.) Pb(CO₃)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 + (-2) + (-2) = 0

4.) Pb(IO₃)₄

-----> Pb⁴⁺ and IO₃⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

[tex]\rm FeCO_3, Fe(IO_3)_2, Pb(CO_3)_2, Pb(IO_3)_4[/tex] are the empirical formula for at least four ionic compounds that could be formed from the given ions.

Ions, which are atoms or molecules with one or more lost or acquired electrons and an electric charge, are bonded together to create ionic compounds, a particular class of chemical complex. A metal cation (a positively charged ion) and a non-metal anion (a negatively charged ion) typically make up these compounds. Ionic bonding is a process that leads to the synthesis of ionic compounds. A non-metal atom becomes a negatively charged anion when it gets one or more electrons, while a metal atom becomes a positively charged cation when it loses one or more electrons.

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