American League baseball teams play their games with the designated hitter rule, meaning that pitchers do not bat. The league believes that replacing the pitcher, traditionally a weak hitter, with another player in the batting order produces more runs and generates more interest among fans. Below are the average numbers of runs score in American League and National League stadiums for the first half of the 2001 season. **American:** 11.1, 10.8, 10.8, 10.3, 10.3, 10.1,10.0, 9.5, 9.4, 9.3, 9.2, 9.2, 9.0, 8.3 **National:** 14.0, 11.6, 10.4, 10.3, 10.2, 9.5, 9.5, 9.5, 9.5, 9.1, 8.8, 8.4, 8.3, 8.2, 8.1, 7.9 (a) Create two box plots to display this data and comment on what you see. (b) Estimate the mean number of runs scored in American League games with a 95% CI. What concerns do you have about making a similar CI for National League games

Answer:

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

14 account majors from a set of 29 students.

Then, 6 history majors from a set of 29 - 1 = 28 students.

So

[tex]p = \frac{14}{29}*\frac{6}{28} = \frac{14*6}{29*28} = 0.1034[/tex]

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major

Answer:

618

Step-by-step explanation:

They are added

Answer:

240 + 378 = 618

Step-by-step explanation:

an easy way to add big numbers s to break it up into smaller pieces.

Example:   240+378 = (200 + 300 = 500) + (40 + 70 = 110) + (0 + 8 = 8) = 618

Answer:

It's 15.

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Plug in m = 3 & n = 2 into the equation.

7(3) - 3(2)

21 - 6

15

Hope this helps & have a great rest of your day!

Answer:

0.5

Step-by-step explanation:

Answer:

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units

Step-by-step explanation:

Given - A particle moves along a horizontal line so that its position at time t,

t ≥ 0, is given by  s(t) = 40 + te^−t/20.

To find - Find the minimum velocity of the particle for 0 ≤ t ≤ 100.

Proof -

Velocity, v(t)  = [tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex]

Now,

[tex]\frac{d}{dt}(40 + te^{-\frac{t}{20} } )[/tex] =  [tex]\frac{d}{dt}(40 ) + \frac{d}{dt}(te^{-\frac{t}{20} } )[/tex]

                       = 0 + [tex]t\frac{d}{dt}(e^{-\frac{t}{20} } ) + e^{-\frac{t}{20} }\frac{d}{dt}(t )[/tex]

                       = [tex]t(-\frac{1}{20} )e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

⇒v(t) = [tex]-\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} }[/tex]

Now,

For minimum velocity, Put [tex]\frac{d}{dt}(v(t)) = 0[/tex]

Now,

[tex]\frac{d}{dt}[v(t)] = \frac{d}{dt} [ -\frac{t}{20}e^{-\frac{t}{20} } + e^{-\frac{t}{20} } ][/tex]

           = [tex]-\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }[/tex]

Now,

Put [tex]\frac{d}{dt}(v(t)) = 0[/tex], we get

[tex]-\frac{2}{20} = - \frac{t}{400}[/tex]

⇒t = 40

Now,

Check that the point is minimum or maximum

Calculate  [tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]

Now,

[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex] = [tex]\frac{d}{dt} [ -\frac{2}{20} e^{-\frac{t}{20} } + \frac{t}{400} e^{-\frac{t}{20} }][/tex]

            = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]

⇒[tex]\frac{d^{2} }{dt^{2} } [v(t)][/tex]  = [tex]\frac{1}{400}e^{- \frac{t}{20} } [ 3 - \frac{t}{20}][/tex]  > 0

∴ we get

t = 40 is point of minimum

So,

The minimum velocity be

v(40) = [tex]-\frac{40}{20}e^{-\frac{40}{20} } + e^{-\frac{40}{20} }[/tex]

      = [tex]-2e^{-2 } + e^{-2 }[/tex]

      = [tex]-e^{-2 }[/tex]

⇒v(40) = [tex]-e^{-2 }[/tex] units

∴ we get

The minimum velocity of the particle  = [tex]-e^{-2 }[/tex] units

Answer:25

Step-by-step explanation:

Answer:

comparing both equations

-2x-1=3x+4

or, -1-4 =3x+2x

or, -5=5x

or, X= -1

Y= -2x-1

or, Y= -2(-1)-1

or, Y=1

hence, ( -1,1)

Answer:

$7700

Step-by-step explanation:

amount invested + interest = total

amount invested + 700 = 8400

Subtract 700 from both sides.

amount invested = 7700

Answer: $7700

9514 1404 393

Answer:

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

Answer:

73373773737477374747373738

Answer:

h = -25

Step-by-step explanation:

h - 5 = - 30

   +5     +5

h = -25

☁️ Answer ☁️

Inequality Form:

b < −2

❤️

Interval Notation:

(− ∞, −2)

Hope it helps.

Explanation: Have a nice day!~ ￣▽￣

Answer:

b < -2

Step-by-step explanation:

-3 (4b + 7) > 3

-12b -21 > 3

-12b > 3 + 21

-12b > 24

b < 24/-12

b < -2

Answer:

You are correct

Step-by-step explanation:

Answer: yes, you are correct :)

Step-by-step explanation:

Answer:

2.28% of players are under 86kg

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weights of the players were distributed normally with a mean of 98kg and a standard deviation of 6kg.

This means that [tex]\mu = 98, \sigma = 6[/tex]

What percentage of players are under 86kg?

The proportion is the pvalue of Z when X = 86. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{86 - 98}{6}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.0228*100% = 2.28%

2.28% of players are under 86kg

Answer:

Its A

Step-by-step explanation:

ez

Answer:

A

Step-by-step explanation:

y= -3x + 7

Answer:

hey there

The answer is 7/10

this is true because we have two green marbles and five blue

2+5=7

Step-by-step explanation:

Answer:

20% or 2/10

Step-by-step explanation:

10 marbles in total. We want to find the probability of not picking a green marble. 10marbles-3red-5blue=2marbles left.

So the probability of picking a green marble is 2/10 or 20%

Answer:

Step-by-step explanation:

Midpoint formula:

(x1 + x2)/2, (y1 + y2)/2

Substitute needed values.

4 + -8 = -4

-4/2 = -2

Now for the y's

-1 + 3 = 2

2/2 = 1

MIDPOINT: (-2,1)

Answer:

a) 10

b) 3

c) 16

Step-by-step explanation:

Count the squares and the half ones match them with each other to get a full square... so so sorry if im wrong i did this a while ago! Currently Yr 9 x

Answer:

y=-16

Step-by-step explanation:

Answer:

y = -16

Step-by-step explanation:

−10y+4(3y−8)=−64

Step 1: Simplify both sides of the equation.

−10y+4(3y−8)=−64

−10y+(4)(3y)+(4)(−8)=−64(Distribute)

−10y+12y+−32=−64

(−10y+12y)+(−32)=−64(Combine Like Terms)

2y+−32=−64

2y−32=−64

Step 2: Add 32 to both sides.

2y−32+32=−64+32

2y=−32

Step 3: Divide both sides by 2.

2y

2

=

−32

2

y=−16

Answer:

y=−16

Answer:

7881.75

Step-by-step explanation:

10,170x0.775

Answer:

7881.75

Step-by-step explanation:

Answer:

∠QRT = 42°

Step-by-step explanation:

arc QT + 2(∠QPT = 2(42°) = 84°

arc QT = arc TQ

arc TQ = 2(∠QRT)

84° = 2(∠QRT)

∠QRT = 42°

Answer:

Option A, Left by 4 units

Step-by-step explanation:

Step 1:  Convert g(x) to a function square

We currently have g(x) in this order:  [tex]ax^2 + bx + c[/tex]

However, we want g(x) to be in this order:  [tex](ax + c)^{2}[/tex]

The first thing we have to do is to factor it out:

[tex]g(x)=x^{2}+8x+16[/tex]

[tex]g(x) = (x + 4)(x + 4)[/tex]

[tex]g(x) = (x+4)^{2}[/tex]

Step 2:  Now we can see which way we need to move it

The original form is:  [tex]f(x) = (ax - b)^{2}[/tex]

Since the - has changed to a +, that means that we moved -4 spaces down the x-axis.  This means that we move left by 4 units.

Answer:  Option A, Left by 4 units

Look at the graphs below to make sure:

Answer:

A.) Left By 4 Units

Step-by-step explanation:

Functions f(x) and g(x) are shown below: f(x) = x2 g(x) = x2 + 8x + 16

The direction in which and by how many units the f(x) should be shifted to obtain the g(x) is given by as follows.

Given,

f(x) = x²

g(x) = x² + 8x + 16

we have to consider, the dependent term while selecting the direction.

Therefore, except x², only x term is dependent term.

In g(x), the x term is given by 8.

Therefore, we need to shift the f(x) left by 4 units.

Therefore, option A is correct.

Answer:

D

D. license, permits, and stamp requirements

The type of information that determine the hunting regulations publication is option D.

The following information should be considered:

Learn more: brainly.com/question/16911495

Answer:

C.

Step-by-step explanation:

Given

[tex]A =(x_1,y_1)[/tex]

[tex]B =(x_2,y_2)[/tex]

[tex]C =(x_3,y_3)[/tex]

[tex]D =(x_4,y_4)[/tex]

Required:

Which condition proves that AB is perpendicular to CD

First, calculate the slopes of both.

For AB

[tex]m_1 = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

For CD

[tex]m_2 = \frac{y_4 -y_3}{x_4 - x_2}[/tex]

The condition of perpendicularity is:

[tex]m_1 * m_2 = -1[/tex]

Substitute values for m1 and m2

[tex]\frac{y_2 -y_1}{x_2 - x_1} * \frac{y_4 -y_3}{x_4 - x_2} = -1[/tex]

Option (c) is correct

Answer: -1/3

Step-by-step explanation: slope is the difference in the y values over the difference in the x values

Answer:

D. Triangles A and C

Step-by-step explanation:

We can see whether the figures are congruent or not by checking out the similarity ratio

For triangle A and C the side lengths and angle measures are proportional so we can say that these two angles are congruent.

Answer:

[tex]1-8x-2x^2[/tex]

Step-by-step explanation:

(-4x^3-14x^2+10x-1)÷(2x-1)

Factor the expressions that are not already factored.

[tex]\frac{(2x-1)(2x^2-8x+1)}{2x-1}[/tex]

Cancel out 2x−1 in both numerator and denominator.

[tex]2x^2-8x+1[/tex]

Swap terms to the left side.

[tex]1-8x-2x^2[/tex]

Graph if needed: