Answer:
1, 2, 3 and 6.
Step-by-step explanation:
Factors of 6 are 1, 2, 3 and 6.
The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes. Find the probability that a call a. lasts between 5 and 10 minutes. b. lasts more than 7 minutes. c. lasts less than 4 minutes.
Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e. [tex]\mu = 6.3[/tex] minutes
[tex]\sigma=2.2[/tex] minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-
[tex]P(5<X<10)=P(\dfrac{5-6.3}{2.2}<\dfrac{X-\mu}{\sigma}>\dfrac{10-6.3}{2.2})\\\\=P(-0.59<Z<1.68)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=P(z<1.68)-(1-P(z<0.59))\\\\=0.9535-(1-0.7224)\ \ \ \ [\text{by z-table}]\\\\=0.6759[/tex]
b. The probability that a call lasts more than 7 minutes. :
[tex]P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.318)\\\\=1-0.6248\ \ \ \ [\text{by z-table}]\\\\=0.3752[/tex]
c. The probability that a call lasts more than 4 minutes. :
[tex]P(X<4)=P(\dfrac{X-\mu}{\sigma}<\dfrac{4-6.3}{2.2})\\\\=P(Z<-1.045)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<1.045)\\\\=1-0.8520 \ \ \ [\text{by z-table}]\\\\=0.1480[/tex]
Find the value of x.
Step-by-step explanation:
3x-12 + 6 = 14
3x-12 = 14 - 6
3x = 8 + 12
x= 20 ÷ 3
x = 6.7
Internal Angle Bisector Theoram:
Interior Angle Bisector Theorem : The angle bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
[tex] \Large{ \boxed{ \bf{ \color{limegreen}{Solution:}}}}[/tex]
Here, We can see that angle bisector of an angle is dividing the opposite side.
And,
From here, we can say that the ratio of side being divided is same as the ratio of sides containing this angle.
So, we can write it as,
➝ 14 : 21 = 6 : 3x - 12
Prdouct of means = Product of extremes
➝ 21 × 6 = 14(3x -12)
➝ 126 = 14(3x - 12)
➝ 9 = 3x - 12
Flipping it,
➝ 3x - 12 = 9
➝ 3x = 21
➝ x = 7
☘️ So, Value of x is [tex]\boxed{\sf{x = 7}}[/tex]
━━━━━━━━━━━━━━━━━━━━
If a 1000-count bottle of omeprazole 40 mg capsules costs the pharmacy $42.88, what is the estimated cost per capsule, rounded
to the nearest penny?
Answer:
Estimated cost per capsule = 4.288 (penny)
Step-by-step explanation:
Given:
Cost of 1000 capsule = $42.88
Number of capsules = 1000
Find:
Estimated cost per capsule
Computation:
1 dollar = 100 penny
So,
$42.88 = 4288 penny
Estimated cost per capsule = 4288 / 1000
Estimated cost per capsule = 4.288 (penny)
851-473 is the same as (_)-378...
What is working to get the answer in the parentheses?
Answer:
851- 473 = 373
(751)-378 = 373
4.72x10^10 Please I need help fast
Answer:
The answer is 47200000000
Use Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
Hence the approximate value of x₂ is 7.9156
Write the decimal as a fraction or a mixed number. Write your answer in simplest form. 0.2
Answer:
[tex] \frac{1}{5} [/tex]
Step-by-step explanation:
[tex]0.2 \times \frac{10}{10} = \frac{2}{10} = \frac{1}{5} [/tex]
This number can't be written as a mixed number since it is proper fraction.
It's numerator is less than it's denominator.
Hope this helps ;) ❤❤❤
What's the answer to this question I need help I don't understand it
Greetings from Brasil...
Making the division
(X⁵ + 2X⁴ - 7X² - 19X + 15) ÷ (X² + 2X + 5)
we get
X³ - 5X + 3Answer:
x³ − 5x + 3
Step-by-step explanation:
To solve with long division:
Start by dividing the highest terms:
x⁵ / x² = x³
This becomes the first term of the quotient. Multiply by the divisor:
x³ (x² + 2x + 5) = x⁵ + 2x⁴ + 5x³
Subtract from the first three terms of dividend:
(x⁵ + 2x⁴ + 0x³) − (x⁵ + 2x⁴ + 5x³) = -5x³
Drop down the next two terms and repeat the process.
To use the "box" method:
Each square in the box is the product of the term at the top of the column and the term at the end of the row. Also, squares diagonal of each other must add up to the term outside the box.
Look at the first diagonal. There is only one square, so that must be x⁵. Knowing this, we can say that x³ must be at the top of the column. We can fill in the rest of the column (2x⁴ and 5x³).
Repeat this process until all squares are filled in.
a jogger runs at an average speed of six miles per hour. At that rate, how far will the jogger travel in one and one half hours?
Answer:
9 miles
Step-by-step explanation:
Hour = 6 miles
Half an hour = 3
6 + 3 = 9
16y — 13= —157 solve for y
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation
PV^1.4=C
where C is a constant. Suppose that at a certain instant the volume is 610 cubic centimeters and the pressure is 89 kPa and is decreasing at a rate of 10 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?
Answer:
48.96 cm³/min
Step-by-step explanation:
We are given;
Relationship between pressure P and volume V; PV^(1.4) = C
Volume;V = 610 m³
Pressure; P = 89 KPa
Rate of decreasing pressure; dP/dt = -10 kPa/minute.
We want to find the rate at which the volume is increasing at that instance, thus, its means we need to find dV/dt
So, we will differentiate the relationship equation of P and V given.
Thus, we have;
[V^(1.4)(dP/dt)] + d(V^(1.4))/dt = dC/dt
Differentiating this gives us;
[(dP/dt) × (V^(1.4))] + [1.4 × P × V^(0.4) × (dV/dt)] = 0
Plugging in the relevant values, we have;
(-10 × 610^(1.4)) + (1.4 × 89 × 610^(0.4) × (dV/dt)) = 0
This gives;
-79334.44155 + 1620.5035(dV/dt) = 0
Rearranging, we have;
1620.5035(dV/dt) = 79334.44155
Divide both sides by 1620.5035 to give;
dV/dt = 79334.44155/1620.5035
dV/dt = 48.96 cm³/min
The sum of two numbers, x and y, is 12. The difference of four times the larger number and two
times the smaller number is 18. Whích system of equations should you use to find the two
numbers?
O
A X-y=12
4x - 2y = 18
O B x + y = 12
X-y= 18
C x+y=12
2x - 4y = 18
D x + y = 12
4% - 2y = 18
Answer:
D
Step-by-step explanation:
"Sum" indicates that we add the two variables so we can eliminate option A because that has x - y = 12 not x + y = 12. We can eliminate option B because the second equation should be 4x - 2y = 18, not x - y = 18. For that same reason, we can eliminate C because the coefficients are swapped. I will assume that in option D, the second equation is 4x - 2y = 18. Since we have eliminated everything else, the answer is D.
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Answer: Absolute minimum: f(-1) = -2[tex]\sqrt{6}[/tex]
Absolute maximum: f([tex]\sqrt{12.5}[/tex]) = 12.5
Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:
f(t) = [tex]t\sqrt{25-t^{2}}[/tex]
f'(t) = [tex]1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)[/tex]
f'(t) = [tex]\sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }[/tex]
f'(t) = [tex]\frac{25-2t^{2}}{\sqrt{25-t^{2}} }[/tex] = 0
For this function to be zero, only denominator must be zero:
[tex]25-2t^{2} = 0[/tex]
t = ±[tex]\sqrt{2.5}[/tex]
[tex]\sqrt{25-t^{2}}[/tex] ≠ 0
t = ± 5
Now, evaluate critical points in the given interval.
t = [tex]-\sqrt{2.5}[/tex] and t = - 5 don't exist in the given interval, so their f(x) don't count.
f(t) = [tex]t\sqrt{25-t^{2}}[/tex]
f(-1) = [tex]-1\sqrt{25-(-1)^{2}}[/tex]
f(-1) = [tex]-\sqrt{24}[/tex]
f(-1) = [tex]-2\sqrt{6}[/tex]
f([tex]\sqrt{12.5}[/tex]) = [tex]\sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}[/tex]
f([tex]\sqrt{12.5}[/tex]) = 12.5
f(5) = [tex]5\sqrt{25-5^{2}}[/tex]
f(5) = 0
Therefore, absolute maximum is f([tex]\sqrt{12.5}[/tex]) = 12.5 and absolute minimum is
f(-1) = [tex]-2\sqrt{6}[/tex].
Solve the system algebraically.
3x - 2y - 1 = 0 y = 5x + 4
What is the solution?
A:{(-9/7,-17/7)}
B:{(9/7.17/7)}
C:{(9/7,-17-7)}
Answer:
A:{(-9/7,-17/7)}
Step-by-step explanation:
3x - 2y - 1 = 0 ⇒ 3x - 2y = 1
y = 5x + 4
then:
3x - 2(5x+4) = 1
3x - 2*5x - 2*4 = 1
3x - 10x - 8 = 1
-7x = 1 + 8
7x = 9
x = -9/7
y = 5x + 4
y = 5(-9/7) + 4
y = -45/7 + 4
y = -45/7 + 28/7
y = -17/7
Answer:
A:{(-9/7, -17/7)}
Identify the type of conic section given by the polar equation below. Also give the equation of its directrix (in rectangular coordinates is fine.)
r = 8/4+ cos θ.
Answer:
x = ±8
Step-by-step explanation:
A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:
[tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]
From the question, the polar equation of the circle is:
[tex]r=\frac{8}{4+cos\theta}[/tex]
We have to make the equation to be in the form of [tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]. Therefore:
[tex]r=\frac{8}{4+cos\theta}\\\\Multiply \ through\ numerator\ and\ denminator\ by\ \frac{1}{4}\\\\ r=\frac{8*\frac{1}{4} }{(4+cos\theta)*\frac{1}{4} }\\\\r=\frac{2}{4*\frac{1}{4} +cos\theta*\frac{1}{4}}\\ \\r=\frac{\frac{1}{4}*8}{1+\frac{1}{4}cos\theta}[/tex]
This means that the eccentricity (e) = 1/4 and the equation of the directrix is x = ±8
Use technology and a t-test to test the claim about the population mean at the given level of significance using the given sample statistics. Assume the population is normally distributed. Claim: ; Sample statistics: , s, n What are the null and alternative hypotheses? Choose the correct answer below. A. H0: HA: B. H0: HA: C. H0: HA: D. H0: HA:
Complete question is;
Use technology and a t-test to test the claim about the population mean μ at the given level of significance α using the given sample statistics. Assume the population is normally distributed.
Claim: μ > 71; α = 0.05
Sample statistics:
¯x = 73.9, s = 3.7, n = 25
A) What are the null and alternative hypotheses?
Choose the correct answer below.
A. H0:μ = 71 ; HA:μ ≠ 71
B. H0:μ ≤ 71; HA:μ > 71
C. H0: μ ≥ 71; HA: μ < 71
D. H0: μ ≠ 71; HA: μ = 71
B) What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)
C) What is the P-value of the test statistic? P-value = Round to three decimal places as needed.)
D) Decide whether to reject or fail to reject the null hypothesis.
Answer:
A) Option B - Alternative hypothesis: HA: μ > 71
Null hypothesis: H0: μ ≤ 71
B) t = -7.54
C) p-value = 0.000
D) we reject the null hypothesis
Step-by-step explanation:
A) We are told that the claim is: μ > 71. Thus, due to the sign, the alternative hypothesis would be the claim. So;
Alternative hypothesis: HA: μ > 71
Null hypothesis: H0: μ ≤ 71
B)Formula for standardized test statistic with a t-test is;
t = (¯x - μ)/√(s/n)
Plugging in the relevant values, we have;
t = (71 - 73.9)/√(3.7/25)
t = -7.54
C) From online p-value from t-score calculator attached using t = -7.54, n = 25, significance level = 0.05, DF = 25 - 1 = 24 and a one - tailed test, we have;
p-value = 0.00001 ≈ 0.000
D) The p-value of 0.000 is less than the significance value of 0.05,thus we will reject the null hypothesis
Solve the equation V2 + 4 + 12 = 3-
a.
330
-733
d. 753
b. -776
Please select the best answer from the choices provided
Answer:
d
Step-by-step explanation:
trust
Answer:
x = -733
Step-by-step explanation:
[tex]\sqrt[3]{x+4}[/tex] + 12 = 3
[tex]\sqrt[3]{x+4}[/tex] = -9 (cube both sides)
x + 4 = -729
x = -733
HURRY! QUICK! SHOW WORK THANKS Write the simplified polynomials that represent the perimeter and area for the rectangle.
Length: (x-5) ft
Width: (3x-10) ft
Perimeter =
Area =
Answer:
Perimeter = (8x-30)
Area=(X-5)(3x-10)
Step-by-step explanation:
Perimeter equation for solving is this
2(X-5+3x-10)=p
it is length plus width twice which will equal the perimeter
solving this out
2(4x-15)=p
8x-30=p
area equation for solving this is
(x-5)(3x-10)=a
I don’t know how to solve this one out but i hope the setup helps!
A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.100.10 level to substantiate the publisher's claim?
Complete Question
A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?
State the null and alternative hypotheses for the above scenario.
Answer:
The null hypothesis is [tex]H_o : p \le 0.41[/tex]
The alternative hypothesis [tex]H_1 : p> 0.41[/tex]
Step-by-step explanation:
From the question we are told that
The population proportion is [tex]p = 0.41[/tex]
The level of significance is [tex]\alpha = 0.10[/tex]
The null hypothesis is [tex]H_o : p \le 0.41[/tex]
The alternative hypothesis [tex]H_1 : p> 0.41[/tex]
In a recent year, 32.3% of all registered doctors were female. If there were 46,300 female registered doctors that year, what was the total number of
registered doctors?
Round your answer to the nearest whole number.
Answer:
143,344
Step-by-step explanation:
Let d represent the total number of registered doctors. The given relation is ...
0.323d = 46,300
Dividing by the coefficient of d, we get ...
d = 46,300/0.323 ≈ 143,343.7
The total number of registered doctors was about 143,344.
How to translate the number of people increased by 13 into an algebraic expression
Answer:
x +13.
where
x is number of people
Step-by-step explanation:
Let the number of people be x
given that number of people increased by 13
increased by 13 means that we whatever is the initial number of people, new number of people is 13 more than that.
thus, new number of people = x +13
to translate the number of people increased by 13 into an algebraic expression
we add 13 to number of people which can be represented by x +13.
PLEASE HURRY add n to the product of 7 and 5
Answer:
[See Below]
Step-by-step explanation:
Multiply 7 by 5.
*35
Now add n to it.
*35 + n
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle.
2x + y2 = 48, x = y
Find the area of the region.
Answer: A = 58
Step-by-step explanation: The sketched region enclosed by the curves and the approximating rectangle are shown in the attachment.
From the sketches, the area will be integrated with respect to y.
To calculate the integral, first determine the limits, which will be the points where both curves meet.
In respect to y:
[tex]2x+y^{2} = 48[/tex]
[tex]2x= 48- y^{2}[/tex]
[tex]x= 24 - \frac{y^{2}}{2}[/tex]
Finding limits:
[tex]y= 24 - \frac{y^{2}}{2}[/tex]
[tex]24 - \frac{y^{2}}{2}-y=0[/tex]
Multiply by 2 to facilitate calculations:
[tex]48 - y^{2}-2y=0[/tex]
Resolving quadratic equation:
[tex]y=\frac{-2+\sqrt{2^{2}+192} }{2}[/tex]
y = 6 and y = -8
Then, integral to calculate area will be with limits -8<y<6:
[tex]A = \int {24-\frac{y^{2}}{2}-y } \, dy[/tex]
[tex]A = 24y - \frac{y^{3}}{6}-\frac{y^{2}}{2}[/tex]
[tex]A = 24.6 - \frac{6^{3}}{6}-\frac{6^{2}}{2}-[24.(-8) - \frac{(-8)^{3}}{6}-\frac{(-8)^{2}}{2}][/tex]
A = 58
The area of the enclosed region is 58 square units.
What is the slope of the line in the graph?
Answer:
i believe it is 1
Step-by-step explanation:
Answer:
the slope is 1
Step-by-step explanation:
rise/run
1/1 = 1
Eddie treated his sister to lunch while visiting her in Manchester, Their lunch cost $20, and the
sales tax in Manchester is 15%, If Eddie left a 15% tip on the $20, how much in total did he pay?
Sul
Answer:
Eddie spent $26 total
Step-by-step explanation:
15% of 20 is 3
He paid 15% tax which is $3
He also tipped 15% of the $20 which he paid for lunch so another $3
3+3+20= $26
Find the mode. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The mode(s) is(are) nothing. (Type an integer or a decimal. Do not round. Use a comma to separate answers as needed.) B. There is no mode.
Answer:
The question is not complete, but I found a possible match:
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us?
86 4 85 83 9 51 24 34 28 43
Find the mode. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The mode(s) is(are) nothing. (Type an integer or a decimal. Do not round. Use a comma to separate answers as needed.)
B. There is no mode.
Answer:
The correct answer is:
There is no mode (B.)
Step-by-step explanation:
b. The mode of data is the number that repeats the most number of times. The number that occurs most frequently. on the list of the distribution, 86 4 8 5 83 9 51 24 34 28 43, every number occurs just once, hence, there is no mode for the distribution.
a. To calculate the Mean
[tex]Mean: \frac{Sum\ of\ terms}{number\ of\ players}\\ Mean = \frac{86\ +\ 4\ +\ 8\ +\ 5\ +\ 83\ +\ 9\ +\ 51\ +\ 24\ +\ 34\ +\ 28\ +\ 43}{11}\\Mean= 34.09[/tex]
c. To calculate the median:
Median is the mid-way term of the distribution, but first, we have to arrange the terms in ascending order (descending order can also be used)
4, 5, 8, 9, 24, 28, 34, 43, 51, 63, 86
To find the median, count the numbers equally from the left- and right-hand sides to the middle, the remaining number becomes the median. In this case, the median = 28
d. Midrange:
The midrange is the number mid-way between the greatest and smallest number in a data set. To find the midrange, we will add the smallest (4) and largest number (86), and divide by 2:
Midrange = (4 + 86) ÷ 2
Midrange = 90 ÷ 2 = 45
e. what do the results tell us:
Since only 11 of the jersey numbers were in the sample, the statistics cannot give any meaningful results
Celine's book club read 42 books over 14 months. How many total months will it take them to read 57 books? Solve using unit rates.
Answer:
Step-by-step explanation:
42/14 = 57/x
42x = 57*14
42x = 798
x = 19 months
Answer: Actually its 18 months they calculated wrong
Choose two statements that are true for this expression.
4x^3 – 7x^2 – 30/y + 15
A. There are four terms.
B. There are three terms. 30
C. The term is a ratio.
D. The entire expression is a difference.
Answer:
A. There are four terms.
C. The term [tex]\frac{30}{y}[/tex] is a ratio.
Step-by-step explanation:
The expression given is the sum of four components: a third order monomial ([tex]4\cdot x^{3}[/tex]), a second order monomial ([tex]-7\cdot x^{2}[/tex]), a zero order monomial ([tex]15[/tex]) and a ratio ([tex]\frac{30}{y}[/tex]). There are a sum and two differences. Hence, the correct answers are:
A. There are four terms.
C. The term [tex]\frac{30}{y}[/tex] is a ratio.
Answer:
there are 4 terms
the term 30/y is a ratio
Step-by-step explanation:
got it right on my quiz
Given A = {a, b, c, d} and B = {1, 2, 3, 4} , sets A and B can be defined as? Question 2 options: equal sets equivalent sets equal and equivalent sets neither equal or equivalent sets
Answer:
equal and equivalent sets
Step-by-step explanation:
Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each
Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each of the following.
(i) 3 to 4
(ii) 3 to 3.5
(iii) 3 to 3.1
(b) Find the instantaneous rate of change when r = 3. A'(3)
Area of a circle A(r)= πr²
The average rate of change of the area of a circle with respect to its radius
ΔA(r)/Δr = πr₂²-πr₁²/r₂-r₁
ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁
i) If the radius changes from 3 to 4
ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁
ΔA(r)/Δr = π(4²-3²)/4-3
ΔA(r)/Δr = π(16-9)/1
ΔA(r)/Δr = 7π
Hence, average rate of the area of a circle when the radius changes from 3 to 4 is 7π
ii) If the radius changes from 3 to 3.1
ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁
ΔA(r)/Δr = π(3.5²-3²)/3.5-3
ΔA(r)/Δr = π(12.25-9)/0.5
ΔA(r)/Δr = 3.25π/0.5
ΔA(r)/Δr = 6.5π
Hence, average rate of the area of a circle when the radius changes from 3 to 3.5 is 6.5π
iii) If the radius changes from 3 to 3.1
ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁
ΔA(r)/Δr = π(3.1²-3²)/3.1-3
ΔA(r)/Δr = π(9.61-9)/0.1
ΔA(r)/Δr = 0.61π/0.1
ΔA(r)/Δr = 6.1π
Hence, average rate of the area of a circle when the radius changes from 3 to 3.1 is 6.1π
iv) Instantaneous rate of change A'(r) = 2πr
When r = 3;
A'(3) = 2π(3)
A'(3) = 6π
Hence, the instantaneous rate of change when r = 3 is 6π
Answer:A number decreased by 4 is the same as 12.5
Step-by-step explanation: