All of the following choices are examples of commonly used assessment methods for body
composition EXCEPT

A. waist to hip ratio
B. bioelectrical impedance analysis
C. the spongy bob technique
D. skinfold measurements this is PE please help mee

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

Answer: about 1,100,000,000 to 1,500,000,000 Joules/second

Explanation:

1 MW (megawatt) = 1,000,000.00 J/s (joules per second)

1100(1,000,000) = 1,100,000,000

1500(1,000,000) = 1,500,000,000

Answer:

2 Mg + O2 = 2MgO

Type: Synthesis

Answer:

I have know idea what that means lol.

Thanks for the free points. Hope you have a fantastic rest of your life!

Answer: I put the importance of the lab in the topic is to find how dense an object is and if it can sink or float and it's important to answer the question so you can also find mass and volume.

Explanation: I dunno haha...

Answer:

the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position  x= l/3

Explanation:

The forces in this system are given by Coulomb's law

           F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]

As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .

Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge

Let's find the location of charge 3 so that it is in balance

               ∑ F = F₁₃ - F₂₃ = 0

               F₁₃ = F₂₃

we seek every force

              F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]

              F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]

the distances are

              x₁₃ = x-0 = x

              x₂₃ = l -x

we substitute

              k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}

we solve

             (l-x)² = [tex]\frac{q_2}{q_1}[/tex]   x²

              l² - 2lx + x² = \frac{4q}{q} x²

              3x² + 2l x - l² = 0

we solve the quadratic equation

              x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)

              x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6

              x₁ = -l

              x₂ = l / 3

as charge 3 must be between the two charges the correct answer is

              x = l / 3

with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.

now let's analyze the force on the other charges

charge 1 so that it is in balance

           ∑F = F₁₃ - F₁₂ = 0

           F₁₃ = F₁₂

          [tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]

           l² q₃ = q₂ (l/3)²

           q₃ = q₂ / 9

            q₃ = 4q / 9

            q₃ = [tex]\frac{4}{9} q[/tex]

in summary the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q

in the position  x= l/3

Answer:

Trough

Explanation:

cuz physics you see

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

The speed of the truck is 21.2 m /s

Momentum is the product of the mass of the object and the velocity of the object. Therefore,

p = mv

where

m  = mass

v = velocity

m = 3000 kg

p = 6.36 x 104 kg·m/s.

lets find the velocity

6.36 x 10⁴  = 3000 × v

v = 6.36 x 10⁴ / 3000

v = 21.2 m / s

The speed of the truck is 21.2 m /s

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Answer:

c

Explanation:

Answer:

the mass of object is 2000

Answer:

0.2 A

Explanation:

V= IR

3 = I × 15

I = 3/15

= 1/5 = 0.2 A

The flow of current in a battery will be "0.2 A". To understand the calculation, check below.

According to the question,

Voltage, V = 3 V

Resistance, R = 15 ohm

We know the relation,

→ Voltage (V) = Current (I) × Resistance (R)

or,

→ Current, I = [tex]\frac{V}{R}[/tex]

By substituting the values,

                    = [tex]\frac{3}{15}[/tex]

                    = 0.2 A

Thus the above answer is correct.  

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Answer:

Period = 6 seconds.

Explanation:

Given the following data;

Number of oscillation, n = 10

Time = 1 minute to seconds = 60 seconds

To find the period;

A period is the number of revolutions in a minute.

[tex] Period = \frac {time}{number \; of \; oscillations}[/tex]

Substituting into the equation, we have;

[tex] Period = \frac {60}{10}[/tex]

Period = 6 seconds.

Answer:

the final temperature of the gas is 785.18 K

Explanation:

The computation of the final temperature of the gas is shown below:

Here we apply the gas law

= PV ÷ T

Given that

P1 = 1.9 atm

V1 = 24.6 L

T1 = 335 K  

P2 = 3.5 atm

V2 = 31.3 L  

T2 = ?

Now

P1V1 ÷ T1 = P2V2 ÷ T2

(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2

T2 = 785.18 K

hence, the final temperature of the gas is 785.18 K

Answer: D

Explanation: edge

Answer:

The correct option is (d). "3x stronger".

Explanation:

The force between two charged particle is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

If one charge is tripled, [tex]q_1'=3q[/tex]

New force will be :

[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]

It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.

Answ

Explanation:

HOPE IT HELPS..

The image formed by the location of object is beyond 2F the image by convex lenses is between F and 2F and is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real.

A convex lens is a type of lens that is projected outwards and shows the real image of an object.  Whereas a concave lens is curved inwards and shows virtual image of objects.

The image formed at by the location of convex lenses beyond 2F is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real. If the lens is placed between F and 2F the image formed is beyond 2F and it will be inverted, enlarged and real.

If the object is at F , no image will be formed. If it at between F and the lens, then the image forms beyond 2 F which is upright, enlarged and virtual.

The object be at any position with respect to the focal length of lens, the image formed by a concave lens is between F and the lens and upright, small and virtual.

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Answer:

the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Explanation:

Given;

applied force, F = 5000 N

cross sectional area of the steel wire, A = 0.2 m²

The tensile stress of the steel wire, is calculated as;

[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]

Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Answer:

9.8N

Explanation:

Given the following data;

Mass = 1kg

We know that acceleration due to gravity is equal to 9.8m/s²

To find the force:

Force = mass * acceleration

Substituting into the equation, we have:

Force = 1 * 9.8

Force = 9.8N

Answer:

the density of the wooden cube is 204.1 kg/m³

Explanation:

Given;

applied force, F = 54 N

length of each side of the solid wooden cube, L = 30 cm = 0.3 m

mass of the wooden cube is calculated as;

F = mg

m = F/g

m = 54/9.8

m = 5.51 kg

The volume of the wooden cube is calculated as;

V = L³

V = (0.3)³

V = 0.027 m³

The density of the wooden cube is calculated as;

ρ = m/V

ρ = (5.51 kg) / (0.027 m³)

ρ = 204.1 kg/m³

Therefore, the density of the wooden cube is 204.1 kg/m³

Answer: I believe the answer is C

Explanation:

Cars are composed of hundreds of simple machines

Answer:

4

Explanation:

Waves that are squished have higher frequency. It has short wavelength.

Answer:

4

Explanation:

frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).

Answer:

The momentum of an object varies directly with the speed of the object.

Explanation:

Two objects of different mass are moving at the same speed; the more massive object will have the greatest momentum. A less massive object can never have more momentum than a more massive object.

Answer:

En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.  

Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.

Answer: 20m/s.

Explanation:

Remember the second Newton's law:

F = a*m

This is:

The net force acting on an object is equal to the mass of the object times the acceleration of the object.

In this case, we have a force of 5N pushing the object to the right.

We also have a force of 5N pushing the object to the left.

These forces act on opposite directions.

Then the net force will be equal to the difference of these forces, this is:

F = 5N - 5N = 0N

Then the net force is 0N, then we have:

0N = m*a

0N/m = 0m/s^2 = a

This means that the acceleration of the object is 0, then the velocity of the object does not change.

This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)

Answer:

It's very simple- 8 valence electrons

Answer:

it's 8

Explanation:

that the answer for the question

Yes. Many people either know the answer, or can figure it out using the information in the picture.

Answer:

a) At 0.20 m, the magnitude of the field is 675.0 kV

The direction of the field is acting outwards from the center of the charged spheres

b) At 0.10 m, the magnitude of the field is 135 kV

The direction is acting outwards from the center of the charged spheres

c) At 0.025 m

The magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres

Explanation:

The charged spherical shell parameters are;

The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C

The radius of the inner shell, R₁ = 0.050 m

The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C

The radius of the outer shell, R₂ = 0.15 m

Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;

When r < R₁ < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < r < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < R₂ < r,

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

a) When r = 0.20 m, we have;

R₁ < R₂ < r, therefore

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} + 4.50\times 10^{-6} }{0.20^2} \right ) = 675.0 \ kV[/tex]

Therefore, the magnitude of the field, V = 675.0 kV

The direction of the field is outwards

b) When r = 0.10 m, we have;

When R₁ < r < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.10} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = 135 \ kV[/tex]

Therefore, the magnitude of the field, V = 135 kV

The direction of the field is outwards from the center

c) When r = 0.025 m, we have;

When r < R₁ < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.05} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = -270 \ kV[/tex]

Therefore, the magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres.

Answer:

12 g i think

Explanation:

brainliest pls

Answer:0.060

Explanation:

The mass of the tennis ball is equal to 0.23 Kg.

According to the law of conservation of linear momentum, the sum of the momentum of the bodies which are collided with each other must be equal before and after the collision.

m₁ .u₁ + m₂.u₂ = m₁ .v₁ + m₂.v₂

where m₁ and m₂ is the masses, u₁ and u₂ are initial speed while v₁ & v₂ is their final speed of the collieded objects.

Linear momentum can be defined as the product of the mass times the velocity of that object.

Given, the initial velocity of the baseball is u₁ = 15 m/s

The initial velocity of the tennis ball u₂ = 22 m/s.

The mass of baseball, m₁ =0.15 Kg

From the law of conservation of momentum, find the  mass of the tennis ball:

m₁ u₁ + m₂ u₂ = m₁.v₁ + m₂.v₂

0.15 × 15 + m ×22 = 0.15 × 1.2 + m × 13

2.25 + 22 m = 0.18 + 13 m

9 m = 2.25

m = 0.23 Kg

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