Answer:
D-Enhancing memory
Explanation:
How much force is needed to move a 12 kg mass 10 m/s?? FEMA
Answer:
F=ma
=12×10
120 N.........
Answer:
F = 120 N [Newtons]
Explanation:
F = 120N
If the speed is 10m/s² [an acceleration], and the mass is 12 kg [kilograms].
F [Force] = ma [mass × acceleration].
F = 10 × 12 = 120.
It cannot be a velocity because time is not given.
Momentum would be the velocity times mass. p = mv.
Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change in potential energy of a 3.0 kg backpack carried up the stairs. (b) Determine the change in potential energy of a person with weight 650 N that descends the stairs.
Answer:
a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Explanation:
Let consider the bottom of the first floor in a building as the zero reference ([tex]z = 0\,m[/tex]). The change in potential energy experimented by a particle ([tex]\Delta U_{g}[/tex]), measured in joules, is:
[tex]\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o})[/tex] (1)
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Initial and final height with respect to zero reference, measured in meters.
Please notice that [tex]m\cdot g[/tex] is the weight of the particle, measured in newtons.
a) If we know that [tex]m = 3\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex] and [tex]z_{f} = 4.1\,m[/tex], then the change in potential energy is:
[tex]\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)[/tex]
[tex]\Delta U_{g} = 120.626\,J[/tex]
The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) If we know that [tex]m\cdot g = 650\,N[/tex], [tex]z_{o} = 4.1\,m[/tex] and [tex]z_{f} = 0\,m[/tex], then the change in potential energy is:
[tex]\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)[/tex]
[tex]\Delta U_{g} = -2665\,J[/tex]
The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Three liters (3000 cm3) of oil is spilled onto a smooth lake. If the oil spreads out uniformly until it makes a circular oil slick just one molecule thick, with adjacent molecules just touching, estimate the diameter of the oil slick. Assume the oil molecules are round with a diameter of 2 x 10-10 m.
Answer:
4.38 km
Explanation:
Volume of oil slick, V = Area of oil slick, A × thickness of 1 molecule, d'
Since the oil slick spreads out in a circular area, it has the area of a circle.
So, V = πd²/4 × d'
d² = 4V/πd'
d = 2√(V/πd') where d = diameter of oil slick.
Since V = 3000 cm³ = 3000 × 10⁻⁶ m³ = 3 × 10⁻³ m³ and d' = 2 × 10⁻¹⁰ m
So, d = 2√(3 × 10⁻³ m³/(π × 2 × 10⁻¹⁰ m))
= 2√(3 × 10⁻³ m³/(6.283 × 10⁻¹⁰ m))
= 2√(0.477 × 10⁷ m²) = 2√(4.775 × 10⁶ m²)
= 2 × 2.19 × 10³ m
= 4.38 × 10³ m
= 4.38 km
a 500g model rocket with a weight of 4.90 N is launched straight up. The small rocket burns for 5s and has a steady thrust of 20N. What maximum altitude does the rocket reach
Answer:
The maximum height reached by the rocket at the given time is 377.5 m.
Explanation:
Given;
mass of the rocket, m = 500 g = 0.5 kg
weight of the rocket, W = 4.9 N
Applied force or thrust of the rocket, F = 20 N
time of the rocket motion, t = 5 s
Apply Newton's second law of motion;
Applied force = Weight of the rock + Upward force of the rocket
F = W + ma
where;
a is the upward acceleration of the rock
[tex]a = \frac{F-W}{m} \\\\a = \frac{20 - 4.9}{0.5} \\\\a = 30.2 \ m/s^2[/tex]
The maximum height reached by the rock during the given time is calculated as;
h = ut + ¹/₂at²
h = 0 + ¹/₂at²
h = ¹/₂at²
h = ¹/₂ (30.2)(5)²
h = 377.5 m
Therefore, the maximum height reached by the rocket at the given time is 377.5 m.
As positively charged sodium ions enter the axon, _______ flow(s) out to repolarize part of the axon
a. potassium ions
b. a neural impulse
c. the action potential
d. glial cells
As positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
At the beginning of an action potential of cell membrane, the sodium ion gates open and sodium ions flows into the cell. This process is called depolarization. Due to rapid influx of sodium ion, the channel is eventually closed.
The potassium channels are then activated in a process called repolarization. This process occurs when the potassium channels open and allow potassium ions to flow out of the cell.
To maintain the cell membrane potential, cells are kept at low concentration of sodium ions and high concentration of potassium ions.
Thus, as positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
Learn more here: https://brainly.com/question/7778945
You yell into a canyon. You hear the echo in 3 seconds. How long did the sound of your voice travel before bouncing off a cliff?
Answer:
The sound travelled 516 meters before bouncing off a cliff.
Explanation:
The sound is an example of mechanical wave, which means that it needs a medium to propagate itself at constant speed. The time needed to hear the echo is equal to twice the height of the canyon divided by the velocity of sound. In addition, the speed of sound through the air at a temperature of 20 ºC is approximately 344 meters per second. Then, the height of the canyon can be derived from the following kinematic formula:
[tex]2\cdot h = v\cdot t[/tex] (1)
Where:
[tex]h[/tex] - Height, measured in meters.
[tex]v[/tex] - Velocity of sound, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]v = 344\,\frac{m}{s}[/tex] and [tex]t = 3\,s[/tex], then the height of the canyon is:
[tex]h = \frac{v\cdot t}{2}[/tex]
[tex]h = \frac{\left(344\,\frac{m}{s} \right)\cdot (3\,s)}{2}[/tex]
[tex]h = 516\,m[/tex]
The sound travelled 516 meters before bouncing off a cliff.
An automobile has a mass of 1500 kg. What is the minimum uncertainty in the velocity (in miles per hour) when its center of mass is located with an uncertainty no greater than 1 cm
Answer:
[tex]\triangle v=1.57*10^-^3^5miles/hour[/tex]
Explanation:
From the question we are told that
Mass of of automobile M= 1500 kg
Generally the equation of the uncertainty principle is given by
[tex]\triangle p=\frac{h}{ \triangle x}[/tex]
[tex]\triangle p=\frac{1.054*10^-^3^4}{ 10^-^2}[/tex]
[tex]\triangle p=1.054*10^-^3^2[/tex]
Generally the uncertainty in velocity is mathematically given by
[tex]\triangle v=\frac{\traingle p}{m}[/tex]
[tex]\triangle v=\frac{1.054*10^-^3^2}{1500}[/tex]
[tex]\triangle v=7*10^-^3^6m/s[/tex]
Therefore the minimum uncertainty in the velocity (in miles per hour)
[tex]\triangle v=7*10^-^3^6*\frac{3600}{1609.3}[/tex]
[tex]\triangle v=1.57*10^-^3^5miles/hour[/tex]
A capacitor is connected to an AC generator. As the generator's frequency is increased, what happens to the current in the capacitor
Answer:
The current increases.
Explanation:
A capacitor can be defined as an electronic component used in electrical circuits to store charge temporarily.
A capacitor is connected to an AC generator. As the generator's frequency is increased, the current in the capacitor increases as well.
This ultimately implies that, when a capacitor is connected to an AC generator, the frequency of the circuit is directly proportional to the amount of current flowing through it.
A 5 kg ball was hit with 1523 J of energy how fast is it going?
a. 304.6 m/s
ь. 39 m/s
C 609.2 m/s
d. 1.218.4 m/s
Answer:
the answer is a 304.6m/s
Explanation:
1,523 / 5 equals 304.6
What kind of injury would most likely come from an unfortunate slide into home in a baseball game?
erosion
macule
crust
bullae
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb
Answer:
585lb
Explanation:
Given the formula for calculating the magnitude of the resultant force as;
[tex]F_R = F_1 + F_2[/tex]
Given
[tex]F_1 = 235 lb \ and \ F_2 = 350 lb\\F_R = 235lb + 350lb\\F_R = 585lb\\[/tex]
Hence the magnitude of the resultant force is 585lb
Which of the following is Not One of the four Assumptions of kinetic theory?
A. All matter is composed of tiny particles
B. These particles are in constant random motions
C. The particles move in a choreograph path and do not collide
D. The amount of energy that the particles this on this collision is negligible
Answer:
I Believe it is
Option C (The particles move in a choreograph path and do not collide)
Explanation:
Hope this Helps! :)
Who invented gravity
Answer: joe
Explanation:
Answer:
Sir Isaac Newton
Explanation:
Sir Isaac Newton was an English mathematician and mathematician and physicist who lived from 1642-1727. The legend is that Newton discovered Gravity when he saw a falling apple while thinking about the forces of nature.
A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing in a northwesterly direction (45 degrees west of North). Considering the initial velocity of the ball and the velocity of wind, what will be the resultant velocity (m/s) and the resultant direction of the golf ball assuming no other forces are acting on the ball
Answer:
[tex]c=71.4m/s[/tex]
[tex]\theta=8.54\textdegree[/tex]
Explanation:
From the question we are told that
Initial velocity of 60 m/s
Wind speed [tex]V_w= 15 m/s \angle 45 \textdegree[/tex]
Generally Resolving vector mathematically
[tex]sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6[/tex]
Generally the equation Pythagoras theorem is given mathematically by
[tex]c^2=a^2+b^2[/tex]
[tex]c^2=10.6^2 +(10.6+60)^2[/tex]
[tex]c=\sqrt{10.6^2 +(10.6+60)^2}[/tex]
Therefore Resultant velocity (m/s)
[tex]c=71.4m/s[/tex]
b)Resultant direction
Generally the equation for solving Resultant direction
[tex]\theta=tan^-1(\frac{y}{x})[/tex]
Therefore
[tex]\theta=tan^-1(\frac{10.6}{70.6})[/tex]
[tex]\theta=8.54\textdegree[/tex]
An energy source forces a constant current of 2A to flow through a light bulbfilament for twenty seconds. If 4.6 kJ is given off in the form of light and heatenergy, calculate the voltage drop across the bulb.
Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
[tex]V=\frac{\Delta W}{\Delta q}[/tex]
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
[tex]I=\frac{\Delta q}{\Delta t}[/tex]
Where:
I is the current (2 A)
Δt is the time (20 s)
[tex]2=\frac{\Delta q}{20}[/tex]
[tex]q=40 C[/tex]
Then, we can put this value of charge in the voltage equation.
[tex]V=\frac{4600}{40}=115 V[/tex]
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!
If an object was observed to orbit the Sun once every half of a year, what would be this object's average distance from the Sun according to Kepler's third law?
A. 0.63 au
B. 0.25 au
C. 0.79 au
D. 0.71 au
Which process is defined as breaking down rocks into smaller pieces without changing the rocks' compositions
Answer:
mechanical weathering
Explanation:
Answer:
Mechanical weathering is responsible for the composition of a rock
Explanation:
The answer is (D)
Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collides with and sticks to cart Y, which is initially at rest. Draw the graphs that best shows the velocity of cart X before and after the collision?
Answer:
Explanation:
Using the law of conservation of momentum;
[tex]m_1 u_1+m_2u_2 = m_1v_1+m_2v_2[/tex]
here;
There is a need for conservation of the total momentum that occurred before and after the collision.
So;
[tex]m_1[/tex] = mass of cart X
[tex]m_2[/tex] = mas 9f cart Y
[tex]u_1[/tex] = velocity of cart X (before collision)
[tex]u_2[/tex] = velocity of cart Y (before collision)
[tex]v_1[/tex] = velocity of cart X (after collision)
[tex]v_2[/tex] = velocity of cart Y (after collision)
So;
[tex]m(u_1+0) =(m_1v+m_2)v[/tex]
because the mass is identical and v represents the velocity of both carts.
Now;
[tex]u_1[/tex] = 2 m/s
[tex]u_2[/tex] = 0 ( at rest)
∴
m(2) = (2m)v
v = 1 m/s
Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.
2. A gas with a constant pressure of 270 kPa does 36,000 J of work as it expands.
What was the change in volume of the gas?
a) 0.13 meters cubed
b) 0.24 meters cubed
c) 0.33 meters cubed
d) 0.46 meters cubed
If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardless of the order in which each object was plotted. True
Answer:
This is false
Explanation:
This is why the answer to this question is false. If these types of objects (2 points connected) should pass through same sets of 3 points, irrespective of the order that each object was plotted, we will not get identical shapes created.
The shape that is going to be created will be dependent on the pattern/order that was involved in the plotting. If it was identical, then we will have identical shapes. But if the order during plotting is different then we will have different shapes created.
Thank you!
why is red light used in photographic dark rooms
Photographic paper reacts to light to produce the image taken by a camera and stored on film. Darkrooms used red lighting to allow photographers to control light carefully, so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.
Answer:
Photographic paper reacts to light to produce the image taken by a camera and stored on film.
Explanation:
Darkrooms used red lighting to allow photographers to control light carefully so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.
Interesting fact about the rib
Answer:
YOU CAN SNEEZE YOUR WAY TO A RIB FRACTURE.
Explanation:
Sarah is a forensic what is her job to do
Answer:
She takes pictures and analyzes DNA samples
what relationship must exist between an applied force and the velocity of a moving obkect if uniform circular motion is to result
Answer:
See explanation
Explanation:
The centripetal force keeps an object moving in a circular orbit at constant velocity. The velocity of an object undergoing uniform motion is always tangential to the circle while the centripetal force is directed towards the center of the circle.
This now implies that the direction of the force acting on a body undergoing circular motion at constant velocity is perpendicular to the direction in which the object is being displaced.
A piece of putty and a tennis ball with the same mass are thrown against a wall with the same velocity. Which object experiences a greater force from the wall or are the forces equal
Answer:
Explanation:
Firstly, we have to define momentum.
Momentum is define as the product of mass and velocity.
That is P = mass×velocity
Also considering the third law of motion which states that: For every action, there is equal and opposite reaction.
Moreso, considering the 2nd law of motion which states that the rate of change in the momentum of a body is equal to the applied force and takes place in the direction of the applied force.
Now, applying P = mass×velocity
They both have same mass and velocity definitely, they will both experience same momentum.
Also from the question, the both share same velocity hence, the will both hit the wall with same velocity meaning the will both feel the same impact from the wall as well. Hence the third law of motion proves this right.
Allen and Jason are chucking a speaker around. On one particular throw, Allen throws the speaker, which is playing a pure tone of frequency f, at a speed of 10 m/s directly towards Jason, but his aim is a bit off. As a result, Jason runs forward towards the speaker at a speed of 6 m/s before catching it. Then, the frequency that Jason hears while running can be written as (m/n)f Hz, where m and n are relatively prime positive integers. Compute m n.
Answer:
Explanation:
We shall apply Doppler's effect of sound .
speaker is the source , Jason is the observer . Source is moving at 10 m /s , observer is moving at 6 m/s .
apparent frequency = [tex]f_o\times\frac{V+v_o}{ V-v_s}[/tex]
V is velocity of sound , v₀ is velocity of observer and v_s is velocity of source and f_o is real frequency of source .
Here V = 340 m/s , v₀ is 6 m/s , v_s is 10 m/s . f_o = f
apparent frequency = [tex]f\times \frac{340+6}{340-10}[/tex]
= [tex]f\times \frac{346}{330}[/tex]
So m = 346 , n = 330 .
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of gravity, in ft/s2, at that elevation
Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
Convert 41.3 kilocalories into joules.
Answer:172799.2
Explanation:
If it took you 5 seconds to move a rock 15 meters using a force of 150 Newtons, how much power did you need to use?
500 joules/sec
45 joules/sec
4,500 joules
450 joules/sec
Answer:
Given that:
Time taken = 5 seconds
Distance = 15 meters
Force = 150 Newtons
Power = ?
Recall that power is the rate of work done per unit time
i.e Power = work / time
(since work is a product of force and distance, then
power = (force x distance)/ time
Power = (150 Newtons x 15 m) / 5 s
Power = 2250 / 5
Power = 450 joules per second
Answer:
450 joules/sec
Explanation:
150 x 15 = 2,250
2,250 / 5 = 450
= 450 joules/sec
what is phase voltage of star connected three phase system in balanced loa is 240 the line voltage
Answer:
Explanation: the Star Connection, the similar ends (either start or finish) of the three windings are connected to a common point called star or neutral point. The three-line conductors run from the remaining three free terminals called line conductor