alicia rides her bike 4 miles due north and 3 miles due west to a playground. What is the shortest distance to alicias home from the playground

Answer:

It depends on the measure of the angle you are talking about

Answer:

y = 28

Step-by-step explanation:

Firstly, we will set y to be a constant. That is y= constant,j. The question directed us to "Find an equation of the plane that is parallel to the xz-plane and is located 28 units to the right of the xz-plane in standard perspective."

Recall that the value of y is equal to zero[0] for the xz plane. Therefore, as the question stated that the plane is located twenty-eight[28] units to the right, the required equation for the plane is equal to y = 28 which is the solution or answer to the problem.

the corresponding amount in a 13% increase is: (59 * 13): 100 = $ 7.67

so the current stock price is: 59 + 7.67 = $ 66.67

Answer:

Only B

Step-by-step explanation:

Did this in Khan Academy.

=> Also, there are 2 '-' symbols in the question.

In Option A, there is only 1 "-' symbol.

In Option B, there are 2 '-' symbols.

Option C says none of the above.

Since, Option B has 2 '-' symbols, it is the correct.

Answer:

Step-by-step explanation:

Answer:

190 = 13.78

290 =17.02

390 = 19.74

545 = 23.34

Step-by-step explanation:

if you need simplest ratical let me know

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

Answer:

Step-by-step explanation: you want to divide the price of eatch to the pacets???

Answer:

Step-by-step explanation:

[tex] \sf{7h + 2 + 4}[/tex]

Add the numbers

⇒[tex] \sf{7h + 6}[/tex]

Hope I helped!

Best regards!

Answer:

7h+6

Step-by-step explanation:

We are given the expression:

7h + 2 + 4

and asked to simplify.

In order to simplify an expression, we must combine like terms. In this expression, we have 2 constants, or terms without variables. The 2 constants and 2 and 4. Add 2 and 4.

7h + (2+4)

7h+6

There are no more like terms, so this expression is simplified.

The expression 7h+2+4 simplified is 7h +6

Answer:

[tex] \frac{3}{5} [/tex]

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

[tex] \frac{9}{25} = (\frac{x}{y})^2 [/tex] (area of similar polygons theorem)

The scale factor of their sides would be [tex] \frac{x}{y} [/tex]. Which is:

[tex] \sqrt{\frac{9}{25}} = \frac{x}{y} [/tex]

[tex] \frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y} [/tex]

[tex] \frac{3}{5} = \frac{x}{y} [/tex]

Scale factor of their sides = [tex] \frac{3}{5} [/tex]

Answer:

3:5

Step-by-step explanation:

Answer:

We conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

Step-by-step explanation:

We are given that using traditional methods it takes 98 hours to receive an advanced flying license. A researcher believes the new technique may reduce training time and decides to perform a hypothesis test.

After performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance.

Let [tex]\mu[/tex] = mean time to receive an advanced flying license.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 98 hours

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 98 hours

Here, the null hypothesis states that it takes 98 hours to receive an advanced flying license.

On the other hand, the alternate hypothesis states the new technique may reduce training time that it takes less than 98 hours to receive an advanced flying license.

Now, it is stated that after performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance. This means we don't have sufficient evidence to support the null hypothesis as our test statistics will fall in the rejection region.

Therefore, we conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

Answer:

The left over wood in foot is 2.34  foot

or 2 foot 4 inch

Step-by-step explanation:

This problem desires to test our unit conversion skills

Step one:  let us work with foot and convert inches to foot.

The total wood is 8 foot, and we are expected to subtract 5 foot 8 inches from it.

converting 8 inches to foot we have

1 inch -----0.0833333 foot

8 inch-----x foot

cross multiplying we have

x= 8*0.0833333

x= 0.66 foot

Hence the total number of wood to be subtracted in foot is 5.66 foot

i.e 8-5.66= 2.34  foot

The left over wood in foot is 2.34  foot

or 2 foot 4 inch

Answer:

P' (2, -4)

Q' (3, -1)

R' (4, -4)

Step-by-step explanation:

Reflection in the y axis

(x, y) → (-x, y)

P(⁻²₋₄ ) → P'(²₋₄ ) ∴ P'(2, -4)

Q(⁻³₋₁ ) → Q'(³₋₁ ) ∴ Q'(3, -1)

R(⁻⁴₋₄ ) → R'(⁴₋₄ ) ∴ R'(4, -4)

Answer:

see below (I hope this helps!)

Step-by-step explanation:

41. √20 = √4 * 5 = √4 * √5 = 2√5

43. The sum of interior angles in a triangle is 180°, therefore, x = 180 - (75 + 64) = 41°.

45. 15 + 5(2x - 3) = 15 + 5(2x) + 5(-3) = 15 + 10x - 15 = 10x

47. Complementary angles have a sum of 90°, therefore, x = 90 - 48 = 42°.

Answer:

i dont what it is can u tell me

Step-by-step explanation:

The length side is not a integer. Therefore, The answer is irrational.

The area of a square is given by the formula

A = side x side

In this problem we have

A = 150 square feet.

Now, substitute in the formula

150 = side^2

Now, take the square root both sides

side = √150

Then simplify

side = 5√6 feet

Remember that; A Rational Number is a number that can be made by dividing two integers. soThe length side is not a integer

Therefore, The answer is irrational.

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Step-by-step explanation:

Hey there!!

Let angle 2 be x then,

measure of angle 1 is three less than twice of angle 2 = 2x-3.

Now, we have.

Measure of supplementary angle is 180°.

Angle 1 + angle 2 = 180°

x+(2x - 3)= 180°

3x -3=180°

3x= 180°+3°

[tex]x = \frac{183}{3} [/tex]

Therefore, x = 61°.

Now, angle 2 = 61°

angle 1 = (61×2-3)= 119°.

check (119°+61°=180°).

Hope it helps...

Answer:

Step-by-step explanation:

Hello, please consider the following.

[tex]3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)[/tex]

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

[tex]4^n+17[/tex] is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so [tex]4^k+17[/tex] is divisible by 3

and we check what happens for k+1

[tex]4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17[/tex]

[tex]3\cdot 4^k[/tex] is divisible by 3 and

[tex]4^k+17[/tex] is divisible by 3, by induction hypothesis

So, the sum is divisible by 3.

Step 3 - Conclusion

We just prove that [tex]4^n+17[/tex] is divisible by 3 for all positive integers n.

Thanks

Answer:

78.7

Step-by-step explanation:

2 m = 78.7402

Rounded to nearest tenth-

78.7

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

verified

B.

Answer:

Give him or her brainlist

Step-by-step explanation:

^

|

|

Answer:

[tex]2.5[/tex]    [tex]-1.25[/tex]      [tex]\sqrt{16}[/tex]        [tex]0.6[/tex]

Step-by-step explanation:

Required

Which of the given parameters can be represented as fraction of integers

Taking them one at a time;

1.  2.5

This can be rewritten as

[tex]2.5 = \frac{2.5}{1}[/tex]

Multiply numerator and denominator by 2

[tex]2.5 = \frac{2.5 * 2}{1 * 2}[/tex]

[tex]2.5 = \frac{5}{2}[/tex]

Hence, 2.5 can be represented as fraction of integers

2.  √14

This can be rewritten as

[tex]\sqrt{14} = 3.74165738677...[/tex]

The ... implies that the decimal continues and this cannot be represented as a fraction

3.  -1.25

This can be rewritten as

[tex]-1.25 = \frac{-1.25}{1}[/tex]

Multiply numerator and denominator by 4

[tex]-1.25 = \frac{-1.25 * 4}{1 * 4}[/tex]

[tex]-1.25 = \frac{-5}{4}[/tex]

Hence, -1.25 can be represented as fraction of integers

4.  5.33333.....

The ... implies that the decimal continues and this cannot be represented as a fraction

5.  √16

[tex]\sqrt{16} = \±4[/tex]

This can be rewritten as

[tex]\sqrt{16} = \±\frac{4}{1}[/tex]

Multiply numerator and denominator by 2

[tex]\sqrt{16} = \±\frac{4 * 2}{1 * 2}[/tex]

[tex]\sqrt{16} = \±\frac{8}{2}[/tex]

Hence, √16 can be represented as fraction of integers

6.  0.6

This can be rewritten as

[tex]0.6 = \frac{0.6}{1}[/tex]

Multiply numerator and denominator by 10

[tex]0.6 = \frac{0.6 * 10}{1 * 10}[/tex]

[tex]0.6 = \frac{6}{10}[/tex]

Hence, 0.6 can be represented as fraction of integers

Answer:

P=6x+8

A=2x^2+11x-21

Step-by-step explanation:

Perimeter:

P=2(x+7)+2(2x-3)

P=6x+8

Area:

A=(x+7)(2x-3)

A=2x^2+11x-21

Answer: 24 m

Step-by-step explanation:

Given: area of the circle is 144 π m² .

Area of a circle = [tex]\pi r^2[/tex], where r= radius of the circle.

Then, [tex]144\pi = \pi r^2[/tex]

Cancelling π from both sides , we get

[tex]144 = r^2[/tex]

Taking square root on both sides , we get'

[tex]12= r[/tex]

i.e. radius = 12 m

Then diameter = 2 (radius ) = 2 (12)= 24 m

Hence, the diameter of the circle is 24 m.

The diameter of the circle is 13.54cm

The formula for calculating the area of the circle is expressed as:

A = πd²/4

d is the diameter of the circle

GIven the following

A = 144m²

Substitute the area into the circle

144 = πd²/4

πd² = 144 * 4

πd² = 576

d² = 576/3.14

d² =183.44

d = 13.54cm

Hence the diameter of the circle is 13.54cm

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Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = the blood platelet counts of a group of women

So, X ~ Normal([tex]\mu=257.62, \sigma^{2} =62.1^{2}[/tex])

Now, the empirical rule states that;

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                   =  [tex]\frac{443.9-257.62}{62.1}[/tex]  = 3

       z-score of 71.3 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                =  [tex]\frac{71.3-257.62}{62.1}[/tex]  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Answer:

7/40

Step-by-step explanation:

Simplify the following:

-1/5 + 3/8

Hint: | Put the fractions in -1/5 + 3/8 over a common denominator.

Put -1/5 + 3/8 over the common denominator 40. -1/5 + 3/8 = (-8)/40 + (5×3)/40:

(-8)/40 + (5×3)/40

Hint: | Multiply 5 and 3 together.

5×3 = 15:

(-8)/40 + 15/40

Hint: | Subtract the fractions over a common denominator to a single fraction.

-8/40 + 15/40 = (-8 + 15)/40:

(-8 + 15)/40

Hint: | Subtract 8 from 15.

-8 + 15 = 7:

Answer:  7/40

Complete questions:

A deposit of $200 is made in an account at the beginning of each month at an annual interest rate of 3% compounded monthly. The balance in the account after n months is An = 200(401)(1.0025^n - 1).(Round your answers to two decimal places.)

Answer:

Kindly check explanation

Step-by-step explanation:

Given the amount of balance in an account after. 'n' months using the eqation:

An = 200(401)(1.0025^n - 1)

(a) Compute the first six terms of the sequence {An}.

A1 = 200(401)(0.0025) = $200.50

A2 = 200(401)(1.0025^2 - 1) = $401.50

A3 = 200(401)(1.0025^3 - 1) = $603.00

A4 = 200(401)(1.0025^4 - 1) = $805.01

A5 = 200(401)(1.0025^5 - 1) = $1007.53

A6 = 200(401)(1.0025^6 - 1) = $10210.54

B) balance 5 years after n = 5 * 12 = 60

A60 = 200(401)(1.0025^60 - 1) = $12,961.67

C.) balance 15 years after ; n = 15 * 12 = 180

A180 = 200(401)(1.0025^180 - 1) = $45,508.02

Answer:

17

Step-by-step explanation:

What we have to realize is that RS + ST = RT. Since we know the value of all, let's substitute inside the equation.

[tex]23 - 2x + 9x - 5 = 39[/tex]

Now let's try and solve for x by isolating the variable on one side.

Combine like terms:

[tex]7x + 18 = 39[/tex]

Subtract 18 from both sides:

[tex]7x = 21[/tex]

Divide both sides by 7:

[tex]x = 3[/tex]

Now that we know the value of x, we can substitute it back into the equation for RS, [tex]23-2x[/tex].

[tex]23-2(3)\\\\23-6\\17[/tex]

Hope this helped!

Answer:

$12 up to $15

Step-by-step explanation:

Given

Hourly Earning: $6 - $9 || $9 - $12 || $12 - $15

Frequency:          16        ||         4      ||   10

Required

Determine the limits of the least frequency;

First, we have to determine the lowest frequency;

From the table. the lowest frequency is:

[tex]Lowest = 10[/tex]

Next is to determine the corresponding class limits

The corresponding class limit is $12 up to $15

Step-by-step explanation:

and go outside take fresh air you breathe you get answers constrate answer

I hope this helps you

false

cause two negative numbers multiple must be positive

(-1).(-49)

+49

The statement is false.

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14, . 09, and 5,643.1.

RULE 1: The product of a positive integer and a negative integer is negative.

RULE 2: The product of two positive integers is positive.

RULE 3: The product of two negative integers is positive.

Given:

−(−49) = −49

Is we use the properties of integer

(+).(+)= (+)

(-).(-)=(+)

(-).(+)=(-)

(+).(-)= (-)

So, the statement −(−49) = −49 is false because (-).(-)= (+)

Then, −(−49) = +49

Learn more about integers here:

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