Aiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two subatomic particles. Do you agree with her? Why or why not?

The question is incomplete. The complete question is  :

The pressure difference, Δp, ac[tex]K_u[/tex]ross a partial blockage in an artery (called a stenosis) is approximated by the equation :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the  artery diameter, [tex]A_0[/tex] the area of the unobstructed artery, and A1 the area of the stenosis.  Determine the dimensions of the constants [tex]K_v[/tex] and [tex]K_u[/tex]. Would this equation be valid in any  system of units?

Solution :

From the dimension homogeneity, we require :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Here, x means dimension of x. i.e.

[tex]$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$[/tex]

                    [tex]$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$[/tex]

So, [tex]$[K_u]=[K_v]=[1 ]=$[/tex] dimensionless

So, [tex]K_u[/tex] and [tex]K_v[/tex]  are dimensionless constants.

This equation will be working in any system of units. The constants [tex]K_u[/tex] and [tex]K_v[/tex] will be different for different system of units.

Answer:

To protect control circuits or small devices with insufficient cutting power

Explanation:

Answer:

Explanation:

what do u need help with

Answer:

that's for frequency other answers are coming soon

Answer:

Efficiency can be increase by using rollers in conjunction with the inclined plane. Wedge. The wedge is an adaptation of the inclined plane. It can be used to raise a heavy load over a short distance or to split a log.

Explanation:

Hope it helps

Answer:

Dynamo

Explanation:

As we all know, there are dynamos in bicycles. When we paddle the cycle, the wheels of the cycle rotates by generating kinetic energy. When the wheels rotate, the dynamo starts to rotate. This makes the motor inside the dynamo rotates and generate electrical energy.

Explanation:

→ Force = Mass × Acceleration

→ F = (1.12 × 1.11) N

→ F = 1.2432 N

Answer:

i dont know guy sorry ha babu

Answer:

Velocidad promedio = 5.29 m/s

Explanation:

Dados los siguientes datos;

Distancia = 900 m

Tiempo = 170 segundos

Para encontrar la velocidad media;

La velocidad se puede definir como la distancia recorrida por unidad de tiempo. La velocidad es una cantidad escalar y, como tal, tiene magnitud pero no dirección.

Matemáticamente, la velocidad viene dada por la fórmula;

[tex] Velocidad = \frac{distancia}{tiempo}[/tex]

Sustituyendo en la fórmula anterior;

[tex] Velocidad = \frac{900}{170}[/tex]

Velocidad = 5.29 m/s

Por lo tanto, la velocidad promedio del automóvil es 5.29 metros por segundo.

Answer:

Just as wavelength and frequency are related to light, they are also related to energy. The shorter the wavelengths and higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy. The energy equation is E = hν.

Explanation:

Answer:

Explanation

The most famous and common example is Christmas tree lights. You can't tell easily by looking at them whether they are in series or parallel. But you sure know the difference when one of them burns out. When that happens, the whole string goes dead. No matter what you do (other than find out which bulb burned out) will not fix the problem.

Another example is anything that is temperature controlled. For example a furnace is controlled by a thermostat. When the room temperature reaches a certain point, the thermostat is constructed in a certain way so that it forms an open circuit and no current can flow through it. The furnace motor turns off and the furnace stops pumping hot air into a room.

Answer:

a sidereal day is the time it takes for the earth to rotate about it axis so that the distant star appears In the same position in the sky while a solar day is the time it takes for the earth to rotate about it axis so that the sun appears in the same position in the sky

Answer:

The energy will be increased by a factor 16

Explanation:

Mathematically, we have it that the energy carried by the sound wave is directly proportional to the square of the amplitude

So we have it that;

E = k * A^2

where E is the wave energy

K is the constant value

A is the amplitude value

So;

If E1 = k * (A1)^2

E2 = k * (A2)^2

But A2 = 4A1

E2 = k * (4A1)^2

E2 = k * 16(A1)^2

Divide E2 by E1

E2/E1 = k/k * 16(A1)^2/(A1)^2

E2/E1 = 16

E2 = 16 * E1

so simply, the energy will be increased by a factor of 16

Answer:

C, A and E

Explanation:

In theory you always assume that the prostive is going to the negtive and since C, A and E are in series they all will turn off will turn off

Answer:

All of the above

Explanation:

To ensure the ball go to where we expected it go

Answer:

The ball exerts a force of 400 N on the bat.

Explanation:

Given that,

A baseball player hits a ball with 400 N of force.

We need to find the force the ball exert on the bat.

We know that,

According to Newton's third law, when object 1 exerts a force on an object 2, then object 2 will exert a force on object 1 but in opposite direction.

So, the ball exerts a force of 400 N on the bat.

Answer:

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Answer:

PE = mgh

Explanation:

PE is potential energy

m is mass

g is gravitational field strength

h is height

Answer:

h2 PRD algo trata gevbjjgcvnkoytewxc.

Answer:

12.5kg

Explanation:

The process is explained in the paper

Answer:

an o point i think

Explanation:

Answer:

1. A hiking

2. C

3. B

4. D

5. E

Explanation:

The relation between the speed of sound and the temperature is direct. As the temperature increases, the speed of sound also increases. If the substance is heated up, its molecules moves faster. As a result they collide faster and hence the speed increases. There is a relation between the speed of sound and the temperature i.e.

[tex]v=331+0.61T[/tex]

Hence, this is the required solution.

Answer:

0.00005 second =

50 microseconds

Time

0.00005

Second

50

Microsecond

Answer:

Family

1. Definition of a family

A family is a group of people living together in a home related by blood, marriage or adoption.

2. Two function of the family are;

3. Two types of family are;

4. Two roles and responsibilities of the parents and children in the home are;

Accident in the Home

1. Definition of accident in the home

accidents in the home are common to persons of all ages, therefore home accidents occurs in one's home that may cause an result an injury of a person

2. Two types of accident in the home

3. The two uses of cereals in cooking

Cereals in cooking are used as thickened agents.

4. complete table

1. minor cuts and wounds

2. Poisoning

Care labels

1. definition of care label

care labels can be defined as a permanent label or we can say a tag, which contains regular instructions that is attached at the back of a cloth.

3. two classification of carbohydrates

Answer:

Período del tambor: [tex]T = 0.25\,s[/tex], fuerza sobre la prenda: [tex]F \approx 80.852\,N[/tex], velocidad lineal del tambor: [tex]v \approx 10.053\,\frac{m}{s}[/tex], velocidad angular del tambor: [tex]\omega \approx 25.133\,\frac{rad}{s}[/tex].

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante ([tex]\omega[/tex]), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga ([tex]a[/tex]), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor ([tex]T[/tex]), en segundos:

[tex]T = \frac{1}{f}[/tex] (1)

Donde [tex]f[/tex] es la frecuencia, en hertz.

([tex]f = 4\,hz[/tex])

[tex]T = \frac{1}{4\,hz}[/tex]

[tex]T = 0.25\,s[/tex]

Ahora determinamos la fuerza aplicada sobre la prenda ([tex]F[/tex]), en newtons:

[tex]F = m\cdot a[/tex] (2)

[tex]F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}[/tex] (2b)

Donde:

[tex]m[/tex] - Masa de la prenda, en kilogramos.

[tex]r[/tex] - Radio interior del tambor, en metros.

([tex]m = 0.32\,kg[/tex], [tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])

[tex]F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}[/tex]

[tex]F \approx 80.852\,N[/tex]

La velocidad lineal de la lavadora es:

[tex]v = \frac{2\pi\cdot r}{T}[/tex] (3)

([tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])

[tex]v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}[/tex]

[tex]v \approx 10.053\,\frac{m}{s}[/tex]

Y la velocidad angular del tambor de la lavadora:

[tex]\omega = \frac{2\pi}{T}[/tex]

([tex]T = 0.25\,s[/tex])

[tex]\omega = \frac{2\pi}{0.25\,s}[/tex]

[tex]\omega \approx 25.133\,\frac{rad}{s}[/tex]

Answer:

Yes

Explanation:

The friction is bigger than the mechanical energy so it kind off takes over the mechanical energy. but if the friction decreases mechanical energy can work on the object again

Answer:

Forces that the rider applies to the pedals, saddle and handlebars during speeding, hill climbing and starting are estimated from cine film records using elementary mechanics. The results are compared with force measurements obtained from an instrumented pedal. Pedal forces of up to three times bodyweight were recorded during starting. Handlebar loads were always significantly large.

Answer:the voltmeter measures the potential difference of the circuit,. Voltmeter is a device used to measure potential difference.

Explanation:

Answer:

I am not sure if this is the answer

acceleration: 2.2m/s

Explanation:

here

initial velocity(u): 11m/s

Final velocity(v): 33m/s

time taken(t): 10 s

now

a:v-u/t

or

acceleration:final velocity-initial velocity/time taken

or

a: 33-11/10

or

a:22/10, divide it

: a=2.2m/s#

Answer:

The magnitude of the force acting on the sled is 60.5 newtons.

Explanation:

The Work-Energy Theorem states that the work done by the external force applied on the sled ([tex]W[/tex]), in joules, is equal to the change of its translational kinetic energy ([tex]\Delta K[/tex]), in joules:

[tex]W = \Delta K[/tex] (1)

By definitions of work and translational kinetic energy we expand the equation above:

[tex]F\cdot s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex] (1b)

Where:

[tex]F[/tex] - External force applied on the sled, in newtons.

[tex]s[/tex] - Travelled distance, in meters.

[tex]v_{1}, v_{2}[/tex] - Initial and final velocities, in meters per second.

If we know that [tex]m = 11\,kg[/tex], [tex]v_{1} = 4\,\frac{m}{s}[/tex], [tex]v_{2} = 7\,\frac{m}{s}[/tex] and [tex]s = 3\,m[/tex], then the external force applied on the sled is:

[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot s}[/tex]

[tex]F = \frac{(11\,kg)\cdot \left[\left(7\,\frac{m}{s} \right)^{2}-\left(4\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3\,m)}[/tex]

[tex]F = 60.5\,N[/tex]

The magnitude of the force acting on the sled is 60.5 newtons.