When the concentration of CO2 increases, the concentration of H+ ion increases. This is according to the Bohr's effect.
Bohr's effect can be explained as the observation that increases in the carbon dioxide partial pressure of blood or decreases in blood pH result in a lower affinity of hemoglobin for oxygen. This shifts right ward shift in the Oxygen Hemoglobin Dissociation Curve. The Bohr Effect allows for enhanced unloading of oxygen in metabolically active peripheral tissues. It causes the muscles and tissues to release more oxygen when CO2 levels rise. It helps in deliver oxygen to metabolizing tissue such as skeletal muscle where it is needed most. The decrease in carbon dioxide will increase hemoglobin's affinity for oxygen. It means hemoglobin is less likely to release oxygen.
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The complete question is,
According to the Bohr's effect, as the concentration of co2 increases, the concentration of [tex]H^{+}[/tex] ion increases or decreases?
A sample of oxygen gas initially at 0.760 atm is cooled from 27°C to −93°C at constant volume.
What is its final pressure (in atm)?
Answer:
0.38 atm
Explanation:
Gay-Lussac's Law states:
[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]
p = pressure
T = temperature
Change temps from Celcus to Kelvin:
27+273 = 360
-93+273 = 180
plugging the information in we have:
[tex]\frac{0.760 atm}{360K} = \frac{x}{180K}[/tex]
Cross multiply:
136.8 = 360x
divide 136.8 by 360 = .38 atm
Note that the freezing-point-depression constant for any solvent can be calculated as long as the heat of fusion and the freezing point of the solvent is known. Calculate the freezing-point-depression constant (in SI units) for carbon tetrachloride (CCl4), given that its heat of fusion is 2.5 kJ/mol and its freezing point is 250.3 K.
The freezing-point depression constant for [tex]CCl_4[/tex] is [tex]397 K/mol[/tex].
What is freezing-point depression constant?
The freezing-point depression constant ([tex]Kf[/tex]) is a measure of the decrease in the freezing point of a solvent due to the addition of a solute. It is defined as the change in the freezing point of a solvent per unit of molality of solute particles.
it is a colligative property, meaning it depends on the concentration of solute particles in the solvent, but not on their chemical identity. This makes the freezing-point depression constant a useful tool for determining the molality of a solute in a solution, by measuring the change in the freezing point of the solvent.
Calculation of freezing point depression constant
The freezing-point depression constant ([tex]Kf[/tex]) can be calculated using the equation:
[tex]Kf = ΔHf / (mass of solute per unit volume\times i)[/tex]
where, [tex]ΔHf[/tex] is the heat of fusion, "i" is the number of particles of solute dissolved in the solvent and the mass of solute per unit volume can be calculated as the molar mass of the solute divided by the molar volume of the solvent at its freezing point.
For [tex]CCl4,[/tex] its molar mass is [tex]153.82 g/mol[/tex] and its molar volume at its freezing point can be calculated as the molar volume of an ideal gas at that temperature, which is approximately [tex]24.45 cm3/mol.[/tex]
The mass of solute per unit volume can be calculated as:
mass of solute per unit volume = molar mass of solute / molar volume of solvent at freezing point
[tex]= 153.82 g/mol / (24.45 cm3/mol) = 6.29 × 10^-4 g/cm3[/tex]
And the number of particles of solute (i) can be assumed to be 1, since [tex]CCl_4[/tex] is a non-electrolyte and does not dissociate into ions in solution.
The freezing-point depression constant can be calculated as:
[tex]Kf = ΔHf / (mass of solute per unit volume \times i)[/tex]
[tex]= 2.5 kJ/mol / (6.29 \times 10^-4 g/cm3 \times 1) = 397 K/mol[/tex]
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Which of the following statements about subatomic particles are correct? (select all that apply)
A. Neutrons and protons are the only charges subatomic particles
B. The charge on a proton is equal in magnitude and opposite in sign to that of an electron
C. The mass of a proton is similar to that of a neutron
D. The mass of a neutron is slightly greater than that of an electron
The following statements about subatomic particles are correct:
B. The charge on a proton is equal in magnitude and opposite in sign to that of an electron
C. The mass of a proton is similar to that of a neutron
D. The mass of a neutron is slightly greater than that of an electron.
Subatomic particles refer to the basic building blocks of matter that make up atoms. The main subatomic particles are:
Protons: Positively charge particles found in the nucleus of an atom. The number of protons in an atom determines the atomic number, and thus the identity, of the element.
Neutrons: Neutral particles found in the nucleus of an atom. The number of neutrons in an atom can vary, resulting in isotopes of the same element.
Electrons: Negatively charged particles that orbit the nucleus of an atom. The number of electrons in an atom determines its chemical properties and reactivity.
These subatomic particles interact with each other through electromagnetic forces to form the atoms and molecules that make up matter. Understanding the behavior and interactions of subatomic particles is key to understanding the properties and behavior of matter on a macroscopic scale.
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How much volume of the above stock solution you will need to prepare the riboflavin solutions of following concentrations: (a) 0.059 mM in 25 ml (b) 14 uM in 25 ml
0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
To prepare a 0.059 mM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water.
First, we need to convert the concentration from mM to μM:
0.059 mM × 1000 μM/1 mM = 59 μM
Next, we need to calculate the amount of riboflavin required to prepare a 25 ml solution with a concentration of 59 μM:
59 μM × 25 ml = 1475 μmol
Finally, we need to convert μmol to milligrams:
1475 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.055 g
So, 0.055 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 0.059 mM solution.
To prepare a 14 μM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water:
14 μM × 25 ml = 350 μmol
Finally, we need to convert μmol to milligrams:
350 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.013 g
So, 0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
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within atoms, there is an ongoing relationship between the nucleus and the electrons. categorize the characteristics by whether they describe the nucleus or electrons.
Within atoms, there is an ongoing relationship between the nucleus and the electrons. Characteristics describe the nucleus are:
Positively chargedAttracts the negatively charged particles into the space surrounding itCharacteristic describe electrons :
Negatively chargedCan gain or lose energyCan move from one atom to anotherCan bond two atoms into a molecule when shared between two atomsOn the basis of the 1909 Geiger-Marsden gold foil experiment, Ernest Rutherford identified the atomic nucleus in 1911, which is the compact, dense region made up of protons and neutrons at the heart of an atom. Positively charged nucleus draws negatively charged particles into the area around it.
The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically regarded to be elementary particles.
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Red sphere represent oxygen atoms and yellow spheres represent sulfur atom and all the molecules are gases
Write a chemical equation.
The reaction equation is; S + O2 --->SO2
What is a chemical reaction?We know that when we have a chemical reaction, we have the combination of the reactants so as to have the products of the reaction. In this case we have that the reactants that were combined as oxygen and sulfur.
We must note that in the chemical reaction that the number of the oxygen and the sulfur atoms on the right hand side of the reaction equation must be the same as the number of the oxygen and the sulfur atoms on the left hand side of the reaction equation.
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Why is it advisable to run a mixed melting point determination on samples of two different compositions before concluding that the two compounds are identical?
It is advisable to perform a mixed melting point determination to accurately identify an unknown compound.
If the two compounds have different melting points, then it is likely that they are not the same compound. However, if the two compounds have nearly identical melting points, then it is possible that they are the same compound but with different levels of impurities.
A mixed melting point determination involves testing a sample of each compound together, and if the melting point of the mixture is identical to the melting point of either of the two compounds, then it can be concluded that the two compounds are the same.
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Organic chemists often purify organic compounds by a method known as fractional crystallization. An experimenter wanted to prepare and purify 4.85 g of aniline. Ten 4.85-gram specimens of aniline were prepared and purified to produce acetanilide. The following dry yields were obtained: 3.85, 3.88, 3.90, 3.62, 3.72, 3.80, 3.85, 3.36, 4.01, 3.82. Construct a 95 percent confidence interval for the mean number of grams of acetanilide that can be recovered from 4.85 grams of aniline.
To construct a 95 percent confidence interval for the mean number of grams of acetanilide that can be recovered from 4.85 grams of aniline, we need to first find the mean, standard deviation, and sample size of the data.
Given the dry yields of 10 specimens, the mean can be calculated as (3.85 + 3.88 + 3.90 + 3.62 + 3.72 + 3.80 + 3.85 + 3.36 + 4.01 + 3.82) / 10 = 3.79 grams. The standard deviation can be calculated using the formula: sqrt(sum of squares of deviations from the mean / (n - 1)), where n is the sample size.
Once we have the mean and standard deviation, we can use the t-distribution to find the 95 percent confidence interval. The t-value can be looked up in a t-table given the degrees of freedom, which is n - 1. The confidence interval is then calculated as mean ± t-value × standard deviation / sqrt(n).
This interval gives us an estimate of the mean yield of acetanilide that we can expect to obtain with a 95 percent confidence. It also gives us an idea of the precision of our estimate, as the width of the interval gives us an idea of the variability in the data.
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how to calculate 100 ton/h to kmol/h
You just need to calculate the following to go from kg/hour to kmol/s: For instance, 1 kmol/h should represent 36 kg with 1 kg/s should equal 1/36 kmol/h if there was 3 kmol in 1 kilogram and 12 seconds in 1 hour.
Is mol the same as KMOL?1000 moles make up one kilomole. 1 Mole: Denotes the quantity of a chemical compound that has the same number of atoms as there are in Twelve grams of natural carbon-12. 103 moles are equivalent to one kilogram, or one kilomole, in the SI system of measurement (metrology).
A Kmol contains how many mmol?mmol↔kmol 1000000 mmol make up 1 kmol.
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which of the following elements (p, na, o, n) is most likely to form a compound involving an expanded valence shell of electrons? explain.
The element most likely to form a compound involving an expanded valence shell of electrons is oxygen (O).
Oxygen has a valence shell of 6 electrons and it is able to form a variety of compounds with other elements by sharing its electrons with them. This gives oxygen the ability to form compounds with expanded valence shell, and is one of the reasons why it is such a versatile element.Oxygen is an essential element in the air that humans and other animals need to survive. It is the most abundant element on Earth and makes up 21% of the atmosphere. Oxygen is a colorless, odorless gas that is essential for the respiration of living organisms. It is also used in a variety of industrial processes, such as the production of steel, plastics
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S + 6 HNO3 --> H₂SO4 + 6 NO2 + 2H₂O
In the above equation how many grams of water can be made when 6 grams of HNO3 are
consumed?
Taking into account the reaction stoichiometry,50.57 grams of H₂O are formed when 6 grams of HNO₃ are consumed.
Reaction stoichiometryThe balanced reaction is:
S + 6 HNO₃ → H₂SO₄ + 6 NO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
S: 1 moleHNO₃: 6 molesH₂SO₄: 1 moleNO₂: 6 molesH₂O: 2 molesThe molar mass of the compounds is:
S: 32 g/moleHNO₃: 63 g/moleH₂SO₄: 98 g/moleNO₂: 46 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
S: 1 mole ×32 g/mole= 32 gramsHNO₃: 6 moles ×63 g/mole= 378 gramsH₂SO₄: 1 mole ×98 g/mole= 98 gramsNO₂: 6 moles ×46 g/mole= 276 gramsH₂O: 2 moles× 18 g/mole= 36 gramsMass of H₂O formedThe following rule of three can be applied: if by reaction stoichiometry 378 grams of HNO₃ form 36 grams of H₂O, 6 grams of HNO₃ form how much mass of H₂O?
mass of H₂O= (6 grams of HNO₃×36 grams of H₂O)÷378 grams of HNO₃
mass of H₂O= 0.57 grams
Finally, 50.57 grams of H₂O are made.
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which of the following are ways carbon is transferred between the surface and deep ocean? select all that apply.
Carbon is transferred between the surface and deep ocean through a variety of processes, including vertical mixing and diffusion, upwelling, and biological processes such as photosynthesis, respiration, and excretion.
Vertical mixing and diffusion occur when currents and waves mix the surface and deep water layers, allowing carbon to be transferred from one layer to the other. Upwelling is the process of deep ocean water rising to the surface, bringing with it dissolved carbon from the deep ocean. Finally, biological processes such as photosynthesis, respiration, and excretion also move carbon from the surface to the deep ocean.
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Which of the following are ways carbon is transferred between the surface and deep ocean? select all that apply.
diffusionupwellingadvectionphotosynthesisrespiration.Which of the following is an example of an extensive property of a substance?
A. mass
B. temperature
C. length
D. volume
how many grams of aluminim will react fully with 1.25 moles Cl2
2Al+3Cl2->2AlCl3
The number of grams of aluminum that will react fully with chlorine gas is 22.5grams.
How to calculate moles using stoichiometry?Stoichiometry refers to the quantitative relationship between the reactants and products of a specific reaction or equation.
According to this question, aluminium reacts with chlorine gas as follows:
2Al + 3Cl₂ → 2AlCl₃
Based on the above reaction, 2 moles of aluminium reacts with 3 moles of chlorine gas.
1.25 moles of chlorine gas will react with 1.25 × ⅔ = 0.83 moles of aluminum.
mass of aluminum = 0.83 × 27 = 22.5grams of aluminum
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Describe the situations when Greek prefixes are used:
a) To specify the number of hydrogen atoms in the formula of simple nonmetal hydrogen compounds.
b) To specify the number of water molecules in a hydrate.
c) To specify the number of atoms of each element in molecular compounds.
d) To specify the charge of elements in the names of polyatomic compounds.
e) To specify the number of atoms of each element in ionic
compounds.
**YOU CAN CHOOSE MULTIPLE
The situations when Greek prefixes are used to specify the charge of elements in the names of polyatomic compounds. Therefore, option D is correct.
When and why are prefixes used when naming compounds?Because molecular compounds can form compounds with different element ratios, prefixes are used to specify the number of atoms of each element in a compound molecule. SF₆, sulfur hexafluoride, and N₂O₄, dinitrogen tetroxide are two examples.
Greek prefixes are used to indicate the number of atoms of each nonmetal element in the compound's chemical formula. The prefix "mono-" is not used if the compound contains only one atom of the element listed first in the name.
Thus, option D is correct.
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The magnitude of the electric force between two particles depends on which
factors?
OA. Mass and charge
OB. Charge and distance
OC. Charge and density
D. Mass and distance
Answer:
The magnitude of the electric force between two particles depends on the product of their charges and the inverse of the square of their separation distance.
So, the correct answer is:
OB. Charge and distance.
Answer:
The magnitude of the electrostatic force F between two point charges q1 and q2 is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.
Write the chemical symbols for three different atoms or atomic anions with 17 electrons
Three different atoms or atomic anions with 17 electrons are:
Chlorine (Cl)Fluorine (F)Bromine (Br)What is an atomic anions?An atomic anion is an ion that consists of a single atom with a negative charge. The charge results from the atom gaining one or more electrons, which gives it a surplus of electrons and a net negative charge. Atomic anions are commonly found in ionic compounds, where they bond with positive ions (cations) to form a neutral compound.
Therefore, the chemical symbols for three different atoms or atomic anions with 17 electrons are CI, F, and Br.
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Answer: Cl, S-, P2-
Explanation:
Begin by thinking of an atom which is uncharged or neutral. In this case, the number of protons in the atom must equal the number of electrons. That would give the atom 17 protons and make it an atom of element 17.
A neutral atom of sulfur has 16 protons and 16 electrons. That's one less electron than you want. However, a sulfur anion with a charge of -1 has 16 protons and electrons. So this is a second possible answer.
Similarly, an atom of phosphorus with a charge of -2 would have 15 protons and 17 electrons.
1.Calculate the boiling point (in degrees C) of a solution made by dissolving 6.60 g of naphthalene {C10H8} in 47.1 g of CCl4. The Kbp of the solvent is 4.95 K/m and the normal boiling point is 76.5 degrees C. Enter your answer to 2 decimal places.
The boiling point ( in degree Celsius) of solution
of a solution made by dissolving 6.60 g of naphthalene {C₁₀H₈} in 47.1 g of CCl₄ is equals to the 81.91°C.
The naphthalene compound is dissolved in carbon tetrachloride, CCl₄. When naphthalene added to the carbon tetrachloride it will result in higher boiling point compared to the boiling point of a pure carbon tetrachloride (solvent). This is known as the boiling point elevation The equation for the boiling point elevation is:
ΔT= Kb × m
where: ΔT is the change in temperature
Kb is the boiling point elevation constant m is molality of the solutionFirst we calculate the molality of the solution
Moles of naphthalene = 6.60 g / 128.17 g per mol = 0.0515 mol
Mass of solvent = 47.1 g ×1 kg / 1000 g = 0.0471kg
Molality = moles / kg solvent
= 0.0515mol / 0.0471 kg
= 1.093 m
∆ Tb = kb ×m
= 4.95 °C per m × 1.093m
= 5.410°C
So the boiling point of the solution is = bp of pure CCl₄ + ∆Tb
= 76.5°C + 5.41°C
= 81.91°C
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Photoelectron spectroscopy typically measures the binding energy of electrons in units of
MJ/mol
. Use the value for the energy of an electron in a hydrogen atom in the ground state that you just calculated using the Bohr model to predict the binding energy for the electron in hydrogen in units of
MJ/mol
. Note: If you are not sure where to start to answer this question, click on the "Extra Info" button. Binding energy for the electron in hydrogen predicted by the Bohr model
=
MJ/mol
Check your calculated value. To answer this question, remember that
E binding =−E e−
​ . It can also be helpful to think of the units for the energy of the electron as J/electron, while the units for the binding energy are
MJ/mol
of electrons. You will need Avogadro's number and conversion factor for the prefix mega (M).
Previous question
The predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
Using the value for the energy of an electron in a hydrogen atom in the ground state calculated using the Bohr model, we have:
E_binding = -E_electron = -(13.6 eV) = -2.18 × 10²-18 J/electron
To convert from J/electron to MJ/mol, we can use the following conversions:
1 J/electron * (1 mol/6.022 x 10²23 electrons) = 1.66 x 10²-24 J/mol
1 MJ = 10²6 J
So, putting it all together:
E_binding = (-2.18 x 10²-18 J/electron) * (1 mol/6.022 x 10²23 electrons) * (10²-6 MJ/1 J) = -13.6 MJ/mol
Therefore, the predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
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How many ATOMS of boron are present in 5.44 grams of boron tribromide, BBr3?
Answer:
Explanation:
To calculate the number of atoms of boron present in 5.44 grams of boron tribromide (BBr3), we need to use Avogadro's number and the molar mass of BBr3.
The molar mass of BBr3 can be calculated by adding the atomic masses of boron and three bromine atoms:
BBr3 molar mass = 1 x atomic mass of B + 3 x atomic mass of Br
BBr3 molar mass = 1 x 10.81 g/mol + 3 x 79.90 g/mol
BBr3 molar mass = 295.41 g/mol
Next, we can calculate the number of moles of BBr3 in 5.44 grams:
moles of BBr3 = mass of BBr3 / molar mass of BBr3
moles of BBr3 = 5.44 g / 295.41 g/mol
moles of BBr3 = 0.0184 mol
Since there is one boron atom in each molecule of BBr3, the number of atoms of boron is the same as the number of molecules of BBr3. We can calculate the number of molecules of BBr3 using Avogadro's number:
number of molecules of BBr3 = moles of BBr3 x Avogadro's number
number of molecules of BBr3 = 0.0184 mol x 6.022 x 10^23/mol
number of molecules of BBr3 = 1.11 x 10^22
Therefore, there are 1.11 x 10^22 atoms of boron in 5.44 grams of BBr3.
Which of the following options describe situations in which hydrogen bonding will be observed between the solute and solvent? Select all that apply.
A. Solvent contains OH or NH groups, solute contains N, O, or F atoms.
B. Solvent contains N, O, or F; solute contains OH or NH groups.
C. Solvent and solute both contain OH or NH groups.
D. As long as the solvent can form hydrogen bonds, hydrogen bonding is observed between solute and solvent.
E. Solvent and solute both contain O, N, or F.
The following options describe situations in which hydrogen bonding will be observed between the solute and solvent is Solvent contains OH or NH groups, solute contains N, O, or F atoms. The Solvent and solute both contain OH or NH groups in the process.
It contains the maximum amount of solute that will dissolve in that solvent at that temperature.
Solution= solute+ solvent
The solubility of a solute depends on temperature. A solution containing just the right (maximum) amount of solute that can normally dissolve at a given temperature is said to be saturated. Solvent contains N, O, or F; solute contains OH or NH groups in general.
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how do we open a business that is cheaper
Answer:dont sell as much stuff and name it something like the doller treestore LOL
Explanation:
Na S=0 N H N H2N Sulfadiazine pk, 6.3 Given the pka of sulfadiazine is 6.3, then what would be the ratio of sulfadiazine's (A-)[HA) in blood plasma with a pH = 7.4? Be sure to show your calculations. Edit View Insert Format Tools Table 12pt v Paragraph BIU A & Tv :
The ratio of A- to HA in blood plasma with a pH of 7.4 would be approximately 2.5119 : 1.
The dissociation reaction of sulfadiazine can be represented as follows:
HA ⇌ H+ + A-
Where HA represents the protonated form of sulfadiazine and A- represents the deprotonated form.
The pKa of sulfadiazine is given as 6.3. This means that at pH values below 6.3, sulfadiazine will predominantly exist in its protonated form (HA), while at pH values above 6.3, it will exist mostly in its deprotonated form (A-).
In blood plasma with a pH of 7.4, the ratio of A- to HA can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
Rearranging this equation, we get:
[A-]/[HA] = 10^(pH - pKa)
Substituting the values given:
[A-]/[HA] = 10^(7.4 - 6.3) = 2.5119
Therefore, the ratio of A- to HA in blood plasma with a pH of 7.4 would be approximately 2.5119 : 1.
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What happens when solid goes to liquid?
When solid goes to liquid, it is called melting. Think of a solid ice cube being melted into liquid water.
Now for particles, for solids, particles are arranged in regular, repeating patterns. For liquid, the molecules lose the arrangement and is now random, but close toward each other. The particles move freely and take the shape of the container.
At 27c and 750 mm hg a sample of hydrogen occupies 5.00l how much space will it occupy at stp
Considering the ideal gas law, the gas will ocuppy a volume of 0.0299 L at STP.
Definition of ideal gas lawAn ideal gas is a gas made up of certain particles that, despite having a random displacement, do not interact with each other, having perfect elastic collisions without suffering attraction or repulsion. These gases are known as ideal because they have only been described theoretically, although they are useful for the analysis of real gases.
An ideal gas can be fully described by the ideal gas equation:
P×V = n×R×T
Where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas.Definition of STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Volume at STPIn first place, you know:
P= 750 mmHg= 0.00657895 atm (760 mmHg= 1 atm)V= 5 Ln= ?R= 0.082 (atmL)/(molK)T= 27 C= 300 K (being 0 C= 273 K)Replacing in the ideal gas law:
0.00657895 atm× 5 L = n× 0.082 (atmL)/(molK)× 300 K
Solving:
(0.00657895 atm× 5 L)÷ (0.082 (atmL)/(molK)× 300 K)= n
1.337×10⁻³ moles= n
This number of moles will be the same although you change the pressure and temperature. For STP, you know:
P= 1 atmV= ?n= 1.337×10⁻³ molesR= 0.082 (atmL)/(molK)T= 0 C= 273 KReplacing in the ideal gas law:
1 atm× V= 1.337×10⁻³ moles× 0.082 (atmL)/(molK)× 273 K
Solving:
V= (1.337×10⁻³ moles× 0.082 (atmL)/(molK)× 273 K)÷ (1 atm)
V= 0.0299 L
Finally, the volume will be 0.0299 L.
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Suppose that when you plot the masses of several samples of an unknown substance against the corresponding volumes of water displaced by the samples, the slope of the resulting straight line is 2.7 g/mL. What is the substance's density and probable identity?
Suppose that when you plot the masses of several samples. The density of the object is 2.7 g/mL and it is aluminum.
What is density?It is important to keep in mind that the material's density is the ratio of the object's mass to its volume. By plotting the masses of several samples of an unknown substance against the volumes of water displaced by the samples, the case's density was experimentally determined.
Why is the substance's density so high?The relationship between a substance's mass and the amount of space it occupies (volume) is its density. The density of a substance is determined by the mass, size, and arrangement of its atoms. Density is equal to the material's mass divided by its volume; D = m/v.
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8. A cashier at Whole Foods measures the weight (mass) of fruit with an electronic scale at the register.
If the cashier accidentally leaves a pen on the scale for each measurement, would this contribute to
random error or systematic error? Explain.
Leaving a pen on the scale for each measurement would contribute to systematic error.
The term "systematic error" describes a predictable and repeatable deviation in measurement results that takes place in the same direction every time the measurement is taken. In this instance, each measurement is consistently and repeatedly deviated by the pen on the scale, systematically elevating all of the readings above the actual weight of the fruit.
What is a systematic error with an example?
A systematic error is one that consistently changes in the same manner. For instance, if something consistently or frequently raised the blood pressure right before the measurements, this might happen when taking blood pressure.
What is the random error?
Each measurement varies slightly from the next because of random error. Unexpected outcomes of an experiment are where it comes from.
What are 3 systematic errors?
Environmental Errors.
Observational Errors.
Instrumental Errors.
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If a particular solution process is endothermic, then it will be accompanied by ___ in the disorder of the system.
If a particular solution process is endothermic, then it will be accompanied by temperature changes in the disorder of the system.
What is endothermic?An endothermic reaction is a chemical reaction in which the reactants have a low enthalpy, but produce products with a high enthalpy. Because the enthalpies of the reactants are low, the system requires additional energy to release bonds so that heat absorption occurs from the surrounding environment to the system. This causes a decrease in temperature in an endothermic reaction.
So if there is a solution that has endothermic properties it will be accompanied by a disturbance of the temperature changes system.
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Which of the following would not be helpful in separation a mixture of sand and salt? Select one: O Filter paper and funnel O Water O Glass cup O Magnet
The technique that would not be helpful in the separation of a mixture of sand and salt is O Magnet.
The combination of salt and sand may be separated via way of means of filtration observed via way of means of an evaporation process. Filtration can separate sand from a aggregate of sand and salt solution (salt dissolved in water). Sand remains at the clear out out paper as a residue after filtering. By boiling the filtrate, not unusualplace salt might also additionally now be produced. Probably the perfect approach to split the 2 materials is to dissolve salt in water, pour the liquid far from the sand, after which evaporate the water to get better the salt.
Thus, the correct option is magnet.
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sma membranes in which the concentration of unsaturated (cis) fatty acid chains is high will be more
SMA membranes with a high concentration of unsaturated (cis) fatty acid chains will be more fluid and dynamic than those with a low concentration of unsaturated fatty acid chains.
This is because the cis configuration of the fatty acid chains creates a bent shape which has a greater effect on the fluidity of the membrane than the straight configuration of saturated fatty acid chains.
Additionally, the increased mobility of the cis fatty acid chains can reduce the rigidity of the membrane, making it more dynamic.
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