ABCD is a quadrilateral.
a) Calculate the value of x.

b) When ABCD is drawn to scale, would the lines AD and BC be parallel or not? A You must justify your answer without using a scale drawing.​

Multiply the rate per quarter hour by quarter hours: 250g. This then gets added to the starting temperature of 2300

The answer would be : A. T = 250g + 2300

Answer:

[tex] \large{ \tt{❃ \: TAKING \: \angle \: \: A \: AS \: A \: ANGLE \: OF \: REFERENCE : }}[/tex]

[tex] \large{ \tt{❁ \: sin \: 60 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{➝ \: \frac{ \sqrt{3} }{2} = \frac{6}{y} }}[/tex]

[tex] \large{ \tt{➝ \sqrt{3}y = 6 \times 2 }}[/tex]

[tex] \large{ \tt{➝ \: \sqrt{3} \: y = 12 }}[/tex]

[tex] \large{ \tt{➝ \: y= \frac{12}{ \sqrt{ 3} } }}[/tex]

[tex] \boxed{ \large{ \tt{➝ y = \: 4 \sqrt{3} }}}[/tex]

[tex] \large{ \tt{❇ \: TAKING \: \angle \: B \: AS \: THE \: ANGLE \: OF \: REFERENCE}} : [/tex]

[tex] \large{ \tt{❊ \: sin \: 30 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{⟶ \: \frac{1}{2} = \frac{x}{4 \sqrt{3} } }}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 4 \sqrt{3} }}[/tex]

[tex] \large{ \tt{⟶ \: x = \frac{4 \sqrt{3} }{2} }}[/tex]

[tex] \boxed{\large{ \tt{⟶ \: x = 2 \sqrt{3} }}}[/tex]

[tex] \boxed{ \large{ \tt{❈ \: OUR \: FINAL \: ANSWER : \boxed{ \tt \: x = 2 \sqrt{3} \: \: y = 4 \sqrt{3} }✓}}}[/tex]

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Answer:

A. Definition of angle bisector

Step-by-step explanation:

Given that ΔABC is an isosceles triangle where AB = BC, and that BD bisects ∠ABC, then by the definition of angle bisection of ∠ABC, we have;

m∠ABD = m∠CBD

The correct option is option A. Definition of angle bisector

Also, given that ΔABC is an isosceles triangle and BD is the angle bisector of ∠ABC, we get;

AD = CD and BD = BD

We can therefore, also find that ΔABD ≅ ΔCBD by Side Side Side (SSS) rule of congruency

Answer:

the answer is C, comment if you need explanation

Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer:

50

Step-by-step explanation:

Arc AT the center = angle at the center = 50

Answer:

{0,-3,-9,5,7}

Step-by-step explanation:

range = all y values

function =(x,y)

so all the second values are ranges

Answer:

1

Step-by-step explanation:

Place value can be defined as the numerical value representing a digit owing to its position in a number. Some examples of the various place values used in representing each digit are tenths, hundredths, thousandths, unit, tens, hundreds, thousands etc.

Given the following digit;

3,536.655

Starting from the right (after the decimal), we would determine the place value of each number.

* These are the values that are required for this calculation.

Thus, 6 = 1 * 6

In 3,536.655, the value of the digit in the tenths place is equal to one (1) times the value of the digit in the ones place.

Answer:

1

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (4, - 1 ) and r = 3 , then

(x - 4)² + (y - (- 1) )² = 3² , that is

(x - 4)² + (y + 1)² = 9 → C

Answer:

1441.08 in^3

Step-by-step explanation:

Volume of rectangular prism = 15 * 9 * 9 = 1215 in^3

radius = 3 in

Volume of the cylinder = 3^2 * 3,14 * 8 = 226.08 in^3

Total volume = 1215 + 226.08 = 1441.08 in^3

Answer:

HJHJGHJHG

Step-by-step explanation:

JGHU45565677689789

The three angles of a triangle equal 180

Third angle = 180 - 31.8 - 89.8 = 58.4

Answer: 58.4

Answer:

The first one: 0=-3x-5+x²

Step-by-step explanation:

You have to rearrange the equation to identify the coffecients on the quadratic.

Answer:

First one.

Step-by-step explanation:

Put in standard form. Highest exponent to lowest to constant.

[tex]x^{2}[/tex] - 3x - 5 = 0

a[tex]x^{2}[/tex] - bx - c = 0

Step-by-step explanation:

this is the correct answer you wanted to know

please mark brainliest

Answer:

0.036

Step-by-step explanation:

See image below:)

the area is 32 and the length is 888

you use the formula w= a/l

so a= 32 and l= 888

The width is 0.036mm.

Area of a rectangle (A) is the product of its length (l) and width (w).

A= l. w

Here, given that,

the area is 32 and the length is 888

We use the formula w= A/l

so, A= 32 and l= 888

Then, width= w= 32/888

                         =0.036 mm.

Hence, width is 0.036mm

To learn more on Area click:

https://brainly.com/question/20693059

#SPJ2

Answer:

[tex]1.5[/tex]

Step-by-step explanation:

[tex](6 \: \: \: \: \: 4)(4 \: \: \: \: \: 1) \\ m = \frac{y1 - y2}{x1 - x2} \\ = \frac{4 - 1}{6 - 2} \\ = \frac{3}{2} \\ = 1.5[/tex]

hope this helps you.

Answer:

You already post your answer!

Step-by-step explanation:

Maybe you should get two points in order to find midpoint and endpoint!

or you should give other information!

Answer:

x⁷ – 8x⁵ – 3x⁴ + 15x³ + 20x² + 10x – 75

Step-by-step explanation:

(x⁵ – 3x³ – 3x² – 10x + 15) ˣ (x² – 5) = x⁷ – 8x⁵ – 3x⁴ + 15x³ + 20x² + 10x – 75

Answer:

Zach chose C as the correct answer

Answer:

64

Step-by-step explanation:

-1.5 = (X - 82)12

-18 = X-82

X = 64

Given:

The vertices of a triangle are D(1,5), O(7,-1) and G(3,-1).

To find:

The perpendicular bisector of line segment DO.

Solution:

Midpoint formula:

[tex]Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]

The midpoint of DO is:

[tex]Midpoint=\left(\dfrac{1+7}{2},\dfrac{5+(-1)}{2}\right)[/tex]

[tex]Midpoint=\left(\dfrac{8}{2},\dfrac{4}{2}\right)[/tex]

[tex]Midpoint=\left(4,2\right)[/tex]

Therefore, the midpoint of DO is (4,2).

Slope formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Slope of DO is:

[tex]m=\dfrac{-1-5}{7-1}[/tex]

[tex]m=\dfrac{-6}{6}[/tex]

[tex]m=-1[/tex]

Therefore, the slope of DO is -1.

We know that the product of slopes of two perpendicular line is -1.

[tex]m_1\times m_2=-1[/tex]

[tex]m_1\times (-1)=-1[/tex]

[tex]m_1=1[/tex]

The slope of perpendicular bisector is 1 and it passes through the point (4,2). So, the equation of the perpendicular bisector of DO is:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-2=1(x-4)[/tex]

[tex]y-2+2=x-4+2[/tex]

[tex]y=x-2[/tex]

Therefore, the equation of the perpendicular bisector of DO is [tex]y=x-2[/tex].

Answer:

You didn't send a picture from that question so we don't know what to do with it.

Answer:

x=(-1/10) is the answer of given algebra

Answer:

The sphere

[tex]v=\frac{4}{3} \pi r^{3}=\frac{4}{3}*3.14 *2^{3}=\frac{4*3.14*8}{3}=\frac{100.48}{3}=33.493[/tex]

The cylinder

[tex]v=\pi r^{2} h=3.14*(\frac{4}{2} )^{2}*3=3.14*2^{2}*3=9.42*4=37.68[/tex]

Add those two volumes together:

[tex]33.493 + 37.68 = 71.173 in^{3}[/tex]

Answer:

it will be 50°

Step-by-step explanation:

I'll give you some of the other answers to see if you get it:

m <1 : 180-50 =130

m <5: 180

m <4: 180

m<7: 50

Step-by-step explanation:

I'm not good at geometry but I was trying to explain that you need to follow all your rules at geometry so that you canget your answer right

hello what I can say to you is that you need to follow the rules whereby they say the corresponding angles to the exterior angles then make sure that you follow all the rules that straight line add up into 180 degrees say for example a is equal to b

Answer:

11 weeks

Step-by-step explanation:

350=X*20+130

220=X*20

11=x

Answer:

B

Step-by-step explanation:

It is shifted 15 units up. Think of how you're solving for y, and by adding 15 to the equation, y increases by 15. If y increases by 15 the graph shifts up by 15. Hope that helps.

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 [tex]mm^3[/tex]

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 [tex]mm^3[/tex]

We know the volume of a cylinder is given by V = [tex]$\pi r^2 h$[/tex]

where, r is the radius of the cylinder

            h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = [tex]$\frac{6}{4}$[/tex]

                                          [tex]$=\frac{3}{2}$[/tex]

Area scale factor [tex]$=\left(\frac{3}{2}\right)^2$[/tex]

                           [tex]$=\frac{9}{4}$[/tex]

∴ Volume scale factor [tex]$=\left(\frac{3}{2}\right)^3$[/tex]

                                     [tex]$=\frac{27}{8}$[/tex]

Therefore, the volume of cylinder B is [tex]$=20 \times \frac{27}{8}$[/tex]

                                                               = 67.5 [tex]mm^3[/tex]

Answer:

[tex]{ \boxed{ \tt{m \angle1 = m \angle5}}} \\ { \tt{m \angle1 = 180 \degree - m \angle6}} \\ { \tt{m \angle1 = 180 \degree - 123.5 \degree}} \\ { \bf{m \angle1 = 56.5 \degree}}[/tex]

When a pair of parallel lines is intersected by a transversal, then

Corresponding angles are equal.

∠2 and ∠6 are corresponding angles.

So, m∠2 = m∠6

=> m∠2 = 123.5°

We know that linear pair of angles are supplementary (180°).

∠1 and ∠2 are linear pair of angles.

So, m∠1 + m∠2 = 180°

=> m∠1 + 123.5° = 180°

=> m∠1 = 180° - 123.5°

=> m∠1 = 56.5°