A=(2,4,6,8,10)
B=(3,6,9,12,15,18)
R=(A x B: /Y=3x)

Answer:

C is the answer

Step-by-step explanation:

The equation that justifies why[tex]27^{(1/3)}[/tex] is equivalent to the cube root of 27 is:[tex]27^{(1/3)} = (27^{1)^{(1/3)}} = 27^{(1/3)}[/tex]

The cube root symbol is represented by the number "3". In the square root case, only the root symbol—also known as a radical—was employed. Therefore, the cube root of different numbers can be symbolically represented as follows: 5 divided by its cube = 3. 11 has a cube root of 311 and so on.

The cube root of three is the same as the number 1.442224957031. The cube root of three has the radical representations 33 and 31/3. " denotes the square root.

The cube root formula aids in computing the cube root of any given number that is represented by the symbol in radical form. It can be determined by first determining the number's prime factorization and then using the cube root formula. Assume that x is any number such that it equals y, y, and y.

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Step-by-step explanation:

Expanding and simplifying 2(x + 7) + 3(x + 1):

2(x + 7) = 2x + 14

3(x + 1) = 3x + 3

Adding the two expressions:

2x + 14 + 3x + 3 = 5x + 17

So 2(x + 7) + 3(x + 1) = 5x + 17.

[tex] \sf2(x + 7) + 3(x + 1) \\ \sf2x + 14 + 3x + 3 \\ \sf5x + 17[/tex]

De Morgan's laws state: (A∪B)^c = A^c∩B^c and (A∩B)^c = A^c∪B^c.

What is Venn diagram ?

A Venn diagram is a widely used diagram style that shows the logical relation between sets, popularized by John Venn in the 1880s. The diagrams are used to teach elementary set theory.

The first law states that the complement of the union of two sets is equal to the intersection of their complements:

(A ∪ B)’ = A’ ∩ B’

This law can be illustrated with a Venn diagram, where the complement of a set is represented by shading the region outside the set. In this diagram, the shaded region outside the union of A and B is equal to the overlap of the shaded regions outside of A and B individually.

The second law states that the complement of the intersection of two sets is equal to the union of their complements:

(A ∩ B)’ = A’ ∪ B’

De Morgan's laws state: (A∪B)^c = A^c∩B^c and (A∩B)^c = A^c∪B^c.

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The first three terms of the sequence are -4 , -1, 4. The 10th term of the sequence is given as 95

The general form of the nth term of a sequence can be represented as an expression involving n, such as n^2 - 5.

The first three terms of the sequence are:

n = 1, term = 1^2 - 5 = -4

n = 2, term = 2^2 - 5 = -1

n = 3, term = 3^2 - 5 = 4

The tenth term of the sequence is:

n = 10, term = 10^2 - 5 = 95

So, the first three terms are -4, -1, 4, and the tenth term is 95.

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

[tex](\stackrel{x_1}{-5}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{5}-\underset{x_1}{(-5)}}} \implies \cfrac{-12}{5 +5} \implies \cfrac{ -12 }{ 10 } \implies - \cfrac{ 6 }{ 5 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{ 6 }{ 5 }}(x-\stackrel{x_1}{(-5)}) \implies y -4 = - \cfrac{ 6 }{ 5 } ( x +5) \\\\\\ y-4=- \cfrac{ 6 }{ 5 }x-6\implies {\Large \begin{array}{llll} y=- \cfrac{ 6 }{ 5 }x-2 \end{array}}[/tex]

Answer:

Step-by-step explanation:

I hope this helps you

The equation which represents total pay P and number of copies sold N is P =1800 + 70N and the total pay for 28 copies sells will be $3760.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

From the question, we were given the following parameters

P = total pay

N = copies sold

P = 1800 +70N

replace N with 28

P=1800 + 70(28)

P=1800 + 1960

P= 3760 is her total pay selling 28 copies

Hence The equation which represents total pay P and a number of copies sold N is P =1800 + 70N and the total pay for 28 copies sells will be $3760

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The Answer is 2.557 when 17.9 is divided by 7

1. f(-1) = 9

2. the domain of the function f(x) = (x+3)/(x-1) is: x ∈ R {1} or x ∈ R {- 1}

3. y = 3x + 2

4. y = 2/3x + 1

The formula for a straight line, written as y = mx + b, where m denotes the line's slope and b its y-intercept. When the slope of the line being studied is known, and the provided point is also the y-intercept, the slope-intercept formula, y = mx + b, is utilized (0, b). b  stands in for the y value of the y-intercept point in the formula.

1.

Given f(x) = 4x² - 3x + 2

f(-1) = 4(-1)² - 3(-1) + 2

f(-1) = 4 + 3 + 2

f(-1) = 9

2.

f(x) = x + 3/ x - 1

x - 1 ≠ 0

x ≠ 1

therefore, x ∈ R {1} or x ∈ R {- 1}

3.

Two points (1, 1) and (2, 4)

(x₁, y₁) = (1,1)

(x₂, y₂) = (2, 4)

Two points form an equation:

y - y₁ = {(y₂ - y₁) / (x₂ - x₁)} (x - x₁)

y - 1 = {(4 - 1) / (2 - 1)} (x - 1)

3x - y = 2

x/ (2/3) + y / (-2) = 1

intercept form: x/a + y/b = 1

y = 3x + 2

this is slope intercept form.

4.

given slope (m) = 2/3

y - intercept (c) = 1

y = mx + c

y = 2/3x + 1

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Answer:(2,6)

Step-by-step explanation: 4/1 is going rise/run. your rise would be 4 and your run would be 1. 4/1 is up 4 to the right 1. another point would be (0,-2). you are still gonne do the same thing as rise over run just go negavtive. -4/1 which is down 4 to the left 1.

160 ounces or 10 pounds of cheese is $ 15 and 84 cents.

The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value.

Direct Variation

When there is a direct variation, an increase or decrease in one quantity will result in an equivalent rise or fall in the other. For instance, a rise in the quantity of commodities will result in higher costs.

Indirect Variation

A change in one quantity will directly affect a change in another, known as a direct variation. A rise in the quantity of goods, for instance, will result in higher costs.

We can say 1 pound = 16 ounces

10 pounds = 10 * 16 = 160 ounces

10 ounces of cheese is 99 cents

1 ounce of chess is 99/10 cents

160 ounces of cheese is 99*160/10 = 1584 cents = $ 15 and 84 cents.

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The image coordinates for A, B, C are:

A' = (1, -7)

B' = (-7, 5)

C' = (-11, -4)

A translation refers to a transformation in which an object is moved a certain distance in a certain direction without changing its size or orientation. The effect of a translation is to shift the position of the object, while leaving its shape unchanged.

Since the translation rule is (x, y) => (x-1, y-3). This means you will subtract 1 from x and subtract 3 from y to get the image coordinates for A, B, C. That is:

A = (2, -4) => A' =  (2-1, -4-3) = (1, -7)

B = (-6, 8) => B' =  (-6-1, 8-3) = (-7, 5)

C = (-10, -1) => C' =  (-10-1, -1-3) = (-11, -4)

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The length of BD is approximately 8.62 cm and the length of CD is approximately 4.30 cm.

AB = 10 cm and BC = 18 cm and angle ADB = 56 degrees.

A: Length of BD:

Using the law of sines, BD can be calculated as:

BD = 10 * sin(56) = 8.62 cm (approx)

B: Length of CD:

Using the Pythagorean theorem, AD can be calculated as:

AD = sqrt(BD^2 + AB^2 - 2 * BD * AB * cos(56)) = 12.92 cm (approx)

And then, CD can be calculated as:

CD = AD - BD = 12.92 cm - 8.62 cm = 4.30 cm (approx)

So, the length of BD is approximately 8.62 cm and the length of CD is approximately 4.30 cm.

"

Complete question

ABCD is a trapezium AD and BC are parallel

where AB = 10cm and BC = 18cm and angle ADB = 56degree

Find

A: work out the length of BD

B:  work out the length of CD

"

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The answer to this question requires the use of the Poisson distribution and the cumulative distribution function.

(a) We are asked to find the probability that the fourth person weighed is the first person to be overweight. Since 63% of Americans are overweight, this means that the probability of a randomly selected American being overweight is 0.63. The probability of the first overweight person being the fourth person weighed is given by P(X=3) where X is the number of overweight people in the first 4 people weighed. Using the binomial distribution formula, we have:

[tex]P(X=3) = (4 choose 3) * (0.63)^3 * (0.37)^1\\\\ = 4 * (0.63)^3 * (0.37)[/tex]

(b) We are asked to find the probability that it takes more than 4 people to observe the first overweight person. This is equivalent to finding the probability that none of the first 4 people weighed are overweight. Using the complement rule, we have:

[tex]P(X=0) = 1 - P(X > 0)\\\\ = 1 - [P(X=1) + P(X=2) + P(X=3) + P(X=4)]\\\\ = 1 - [ (4 choose 1) * (0.63)^1 * (0.37)^3 + (4 choose 2) * (0.63)^2 * (0.37)^2 + P(X=3) ][/tex]

(c)  The expected value (mean) of a binomial distribution is given by μ = np, where n is the number of trials and p is the probability of success in each trial. In this case, n=4 and p=0.63. Thus, the mean number of overweight people in 4 trials is 4 * 0.63 = 2.52. The variance of a binomial distribution is given by σ^2 = np(1-p), so in this case the variance is 4 * 0.63 * 0.37 = 1.41. The standard deviation is the square root of the variance, so the standard deviation is approximately [tex]\sqrt{(1.41) } = 1.19[/tex]. This means that the number of overweight people in 4 trials is expected to be around 2.52, with a standard deviation of 1.19.

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The roots of a polynomial are values that make the polynomial equal zero.

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[tex]\huge\begin{array}{ccc}f(-3)=-33\to\boxed{A.}\end{array}[/tex]

We have the function:

[tex]f(x)=2x-3x^2[/tex]

We need

[tex]f(-3)=?[/tex]

Substitute [tex]x=-3[/tex] to [tex]f(x)[/tex]:

[tex]f(-3)=2\cdot(-3)-3\cdot(-3)^2=-6-3\cdot9=-6-27=-33\to\boxed{A.}[/tex]

Answer:

x = 48

Step-by-step explanation:

x/12 = 4

Multiply both sides by 12:

[x = 48]

Answer:

12

Beth has read 12 books.

Step-by-step explanation:

2/3 of 18 is

2/3 × 18

= 2/3 × 18/1

= 36/3

= 12

or "cancel" the 3 and 18 so the work looks more like:

2/3 × 18

= 2/1 × 6

= 12

Or skip the fraction math and logic it out. 18 in three parts is 6books, 6books and 6books.

Beth has read 2 parts:

6books and 6books

She read 12 books.

The coordinates of point P along the directed line segment AB is (10, 13).

The midpoint of a line segment is given as,

x = (a + c)/2

y = (b + d) / 2

Where (x, y) is the midpoint and (a, b) and (c, d) are the two endpoints.

We have,

The line AB.

P is the point between the line AB.

Now,

A = (4, 10) = (a, b) and B = (14, 15) = (c, d)

m : n = 3 : 2

So,

P = (x, y)

The coordinates is given by:

x = (mc + na) / (m + n)

y = (md + nb) / (m + n)

So,

x = (42 + 8) / 5

x = 10

y = (45 + 20) / 5

y = 13

Now,

P = (10, 13)

Thus,

The coordinates of point P is (10, 13).

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Answer:

1 + 1 = 2.

Step-by-step explanation:

Answer NOBODY KNOWS THAT

Step-by-step explanation: MATHMATIONS HAVE BEEN TRYING TO FIND THAT OUT FOR YEARS  AND YOU THINK YOU'LL FIND IT ON BRAINLY THE EQUATION IS FAR TO COMPLEX FOR HUMAN MINDS THE ONLY WAY YOU'LL GET THE ANSWER IS IF YOU ASKED GOD HIMSELF: but i think 1 + 1 = 2

If the medium drink cost $1. 50, the inequality that represents the cost of a popcorn is x ≤ 3.5. Hence, the most he can pay for each popcorn is $3.5.

To translate a word problem into an inequality:

In this problem, let:

x = the cost of 1 popcorn

Three popcorns means = 3x

The cost of a medium drink = 1.5

The amount he need to pay for a medium drink and 3 popcorn:

amount = 1.5 + 3x

However, he only has 12 dollars. Hence,

1.5 + 3x ≤ 12

Subtract both sides by 1.5

3x ≤ 12 - 1.5

3x ≤ 10.5

Divide both sides by 3

x  ≤ 10.5/3

x ≤ 3.5

Hence, the maximum price of a popcorn is $3.5

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Marcus's father would require 189 if he wanted to completely redo the tent's cover, including the bottom.

He needs 55 to completely cover the tent's one rectangular side with the rip. 55

Marcus's father would require 189 if he wanted to completely redo the tent's cover, including the bottom.

3 rectangular sides = 165

2 triangular sides = 24

165 + 24 = 189

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a) k/6 = 1 → k=6 is the distribution of the median of Y1,Y2,··· ,Yn when n is an odd integer

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

a) if distribution

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

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formula for the tangent line is y=x-1 and differentiation of ln(x) is 1/x

A straight line without crossing the curve , it touches the curve at one single point is called tangent . Finding the derivative of a function or a variable in mathematics is called differentiation.

The ratio of the vertical to the horizontal distance between any two points on it  is called slope of ray or line or line segment in analytical geometry.

y-y1 = m(x-x1)

If the function passes through (1,0)  and the slope equals to 1 is:

y-0 = 1(x-1)

y=x-1

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Tangents are straight lines that only touch curves at a single spot rather than crossing them. Differentiation in mathematics refers to the process of determining a function's or variable's derivative.

The slope of a ray, line, or line segment in analytical geometry is the ratio of the vertical to the horizontal distance between any two locations on it.

y-y1 = m(x-x1) (x-x1)

If a function goes through the point (1, 0) and its slope is 1, then:

y-0 = 1(x-1) (x-1)

y=x-1

Answer: She can buy 2 sweatshirts and 3 T-Shirts or 1 sweatshirt and 4 T-Shirts

Step-by-step explanation:

The names for the radius of the circle with center F are FA, FC, EF, BF, DF

The radius is defined as a line segment joining the center of the circle or a sphere to its circumference or boundary.

Given that, circle with center at point F. Points A, B, C, D and E are on the circle. Line segments FA, FC, AFC, EF, BF, EFB, DF and AB are drawn.

Since, the radius is the distance from center to a point on the circumference,

Therefore, FA, FC, EF, BF, DF are showing the distance from center to a point on the circumference,

Hence, the names for the radius of the circle with center F are FA, FC, EF, BF, DF

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The measure of angle BCA in the given circle O is 32°.

The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Given that, A, B, C and D lie on the circumference of the circle.

A and C lie on a straight line segment.

B and D lie on a straight line segment.

Here, ∠ADB=∠BCA=32° (Angles in same segment are equal)

Therefore, the measure of angle BCA in the given circle O is 32°.

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(a) The probability that an assembly will have exactly one defect is 0.2.

This can be calculated using the Poisson distribution formula, which states that the probability of a given number of events (in this case, defects) occurring in a given interval is equal to the mean number of events (in this case, defects) multiplied by the exponential of the mean number of events (in this case, defects).

And multiplied by the exponential of the mean number of events (in this case, defects) multiplied by the exponential of the mean number of events (in this case, defects) divided by the factorial of the given number of events (in this case, defects). Thus, the probability of an assembly having exactly one defect is 0.2.

(b) The probability of an assembly having one or more defects is 1 - 0.2 = 0.8. This can be calculated using the same formula as in (a).

(c) By reducing the occurrence rate of defects to λ = 0.1, the probability of an assembly having one or more defects is reduced to 1 - 0.1 = 0.9. This can be calculated using the same formula as in (a).

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Correct question:

A mechatronic assembly is subjected to a final functional test. Suppose that a defect occurs at random in the assemblies, and that defect occurs according to a Poisson distribution with parameter λ= 0. 2. (a) What i the probability that an assembly will have exactly one defect? (b) What i the probability that an assembly will have one or more defects? (c) Suppose that you improve the process o that the occurrence rate of defects i cut in half to λ=0. 1. What effect doe this have on the probability that an assembly will have one or more defects? \