A={2,4,6,…,18,20} then n(A)=

Both are supplementary

Answer:

B.The answer is incorrect; the plus sign should be a minus sign.

Step-by-step explanation:

[tex]x^2-18x+81\\\\=x^2-2\cdot 9x +9^2\\\\=(x-9)^2\\\\=(x-9)(x-9)[/tex]

[tex]y \propto \dfrac 1x\\\\\implies y = \dfrac kx \\\\\implies \dfrac 14 = \dfrac k{8}\\\\\implies k=2\\\\\text{When}~ x =-4\\\\y = \dfrac{k}{x} = \dfrac{2}{-4}= -\dfrac 12[/tex]

Answer:

F(n) = 6n

Step-by-step explanation:

An explicit sequence goes by the pattern: A0 + (n-1)d, where A0 is the starting term, n is the nth term in the sequence, and d is the common difference. The explicit formula for this sequence is F(n) = 6 + 6(n-1), or 6n

Answer:

B. NRS

Step-by-step explanation:

You have to put the letters left to right.

Answer:

4/6 > 4/8

Step-by-step explanation:

To see if the following is true:

We can cross multiply:

[tex]\frac{4}{6}\neq \frac{4}{8}[/tex]        {4* 8 = 32}      {4*6=24}

Thus,

[tex]\frac{4}{6}=32[/tex]

[tex]\frac{4}{8}=24[/tex]

Hence, [tex]\frac{4}{6} > \frac{4}{8}[/tex]

We can also turn them into decimal:

[tex]\frac{4}6=0.6667[/tex]

[tex]\frac{4}{8}=0.5[/tex]

0.5 is NOT greater than 0.6667 which also means that 4/8 is NOT greater than 4/6.

~lenvy~

Answer:

i think I'd be / the answer is 46

The computation of the equation illustrates that the number will be 46.4.

Let the number be represented as x.

Therefore, the the difference of 3 / 4 and 1 / 6 of a number is 7 will be computed as follows:

(1/6 × x) - 3/4 = 7

0.167x = 7 + 3/4

0.167x = 7.75

x = 7.75/0.167

x = 46.4

Therefore, the number is 46.4.

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Answer:

x = 60

Step-by-step explanation:

Since this triangle is an isosceles triangle, the angle next to the 60 degrees is 60 as well. The interior angles of a triangle adds up to 180 degrees, so:

60 + 60 + x = 180
120 + x = 180
x = 60
Hope this helps :)

A candidate received the majority of first-place votes but loses hows that A. The statement does not make sense.

It should be noted that plurality voting simply means when each voter is allowed to vote for only one candidate.

In this case, a candidate received the majority of first-place votes will win the election. Here, the majority of the first place votes using the plurality method is the winner.

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[tex]~~~\dfrac{d}{dx} f(x) \\ \\=\dfrac{d}{dx} \left(x^3 \cdot \log_6 x \right)\\\\=x^3\dfrac{d}{dx} \left(\log_6 x\right) + \log_6 (x)\dfrac d{dx} x^3 \\\\=x^3 \cdot \dfrac 1{x \ln 6} + \log _6 (x) \cdot 3x^2\\\\=\dfrac{x^2}{\ln 6} + \log_6(x) \cdot 3x^2\\\\\\=x^2 \left(\dfrac 1{\ln 6} + 3\log_6 x \right)[/tex]

[tex]\text{The derivative is now in a form of}~ x^A (B + C \log_D (x))[/tex]

Answer:

Cubed root

Step-by-step explanation:

Do the inverse of cubed, cubed root

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=10\\ h=18 \end{cases}\implies V=\cfrac{\pi (10)^2(18)}{3}\implies \stackrel{using~\pi =3.14}{V=1884}[/tex]

Answer:

Step-by-step explanation:

If order matters (much like forming... a 4 digit number-maybe for a safe?), you will be computing "permutations".  The  formula for "r" items chosen from  "n" items, where order matters is   Npermutations = nPr  =  n!/ (n-r)!

Npermutations = 10P6 =  10!/(10-6)= 10*9*8*7*6*5 = 151200

When order doesn't matter (such as in dealing a poker hand, its the cards you end up with that matter not the order in which they are dealt into your hand) you will be computing combinations.   The formula for the number of combinations of  "r "items from "n" choices is  Ncombinations =  nCr = n!/((n-r)!r!)

Ncombinations = 10C6 =  10!/((10-6)!6!) =  (10*9*8*7)/(4*3*2*1) = 210

Notice how there are far fewer combinations than permutations.  This makes sense because if you think about how 6 colors  {red, blue, green, white, black, yellow} can be arranged, there are 6!=720 ways to arrange these 6 colors if order matters.  If order doesn't matter, this set of 6 colors counts only once.
Same thing with numbers :)

Hope this helped, brainliest is always appreciated! :)

Have a nice day CX
~Mitsuna

Answer:

403π/9 or 140.67

Step-by-step explanation:

First, you have to find the circumference of the circle

Circle circumference equation:

Circumference = dπ (Circumference = diameter x pi)

You have a radius of 31 which is equal to 62 diameter (diameter is double the radius)

So:

C = 62π

Now, you need to know that a full circle is 360 degrees and we want only 200 degrees of that,

So in other words, you want 200/360 of the circle's circumference.

You can find the measure of the 200 degree arc by doing

62π x [tex]\frac{200}{360}[/tex] = [tex]\frac{403pi}{9}[/tex] or 140.67

Answer

Step-by-step explanation:

So she needs to give 25 pencils to each student.

1 box = 12

number of boxes = 25/12

                                  =2.08

round it to 3

An expression is defined as a set of numbers, variables, and mathematical operations. The value(s) for which the rational expression (10w−5)/(2w²+11w+5) is undefined is -1/2 and -5.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The value for which the function will not be defined is the value of w which will make the denominator of the rational function zero. This values can be found by factorizing the denominator of the function. Therefore,

2w² + 11w + 5 = 0

2w² + 10w + 1w + 5 = 0

2w(w+5) + 1(w+5) = 0

(2w+1)(w+5) = 0

w = -1/2 , -5

Hence, the value(s) for which the rational expression (10w−5)/(2w²+11w+5) is undefined is -1/2 and -5.

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#SPJ1

Answer:

Θ = (π/6) + πn

Θ = (5π/6) + πn

Step-by-step explanation:

4sin²Θ + 4 = 5

            -4    -4

4sin²Θ = 1

÷4         ÷4

sin²Θ = (1/4)

√sin²Θ = √(1/4)

sinΘ = (1/2), (-1/2)

-------------------------

Θ = arcsin (1/2)

Θ = (π/6)

to find the quadrant subtract π

Θ = π - (π/6)

Θ = (5π/6)

Find the period

2π / |b|

b = 1

2π/1 = 2π

The sin Θ function is 2π, so values will repeat 2π in both directions.

Θ = (π/6) + 2πn (n is the variable)

Θ = (5π/6) + 2πn

-------------------------------------------------------------------------------------------------------

sin Θ = (-1/2)

Θ = arcsin (-1/2)

Θ = (-π/6)

To find the second function add π

Θ = 2π + (π/6) + π

Θ = (7π/6)

Find the period

2π/|b|

2π/1

2π

(-π/6) + 2π

2π       6         π

----- ×  ----- -  -----

1           6        6

Θ = (11π/6) will repeat every 2π in both directions

-------------------------------------------------------------------------------------------------------

Θ = (π/6) + 2πn

Θ = (5π/6) + 2πn

Θ = (7π/6) + 2πn

Θ = (11π/6) + 2πn

(π/6) + π = (7π/6)

(5π/6) + π = (11π/6)

Θ = (π/6) + πn

Θ = (5π/6) + πn

----------------------------------------------------------------------------------------------------------

I hope this helps!

Answer:

72 orange marbles

Step-by-step explanation:

First, divide 45 by 5 to determine how many red units there are. Then, use that number (9) to multiply with 8 to get the number of orange marbles, which is 72.

Hopefully this helps- let me know if you have any questions!

The value of x in the equation, as a mixed number in simplest form is solved as: x = 2 2/9.

To solve for a variable, say x, in an equation, it means to find the value of x that will make the equation true. Do this by isolating x in the equation.

Given the equation:

x/−8 = −5/18

Cross multiply

18x = (-5)(-8)

18x = 40

Divide both sides by 18

x = 40/18

x = 2 2/9.

Therefore, the value of x in the equation, as a mixed number in simplest form is solved as: x = 2 2/9.

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Answer:

y=2x-1

Step-by-step explanation:

[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=24\\ \theta =135 \end{cases}\implies s=\cfrac{(135)\pi (24)}{180}\implies s=18\pi ~cm[/tex]

Answer:

B) 18π cm

Step-by-step explanation:

Step 1

Given:

   Central angle θ=135°

    Radius of circle r=24 cm

    Length of arc CD =θ360°(2πr)

Step 2

  l=135°360°×2π×24

    l=38×2×π×24

    l=3×2π×3

      l=18π cm

Therefore

  Length of arc CD =18π cm

Thus, option B is correct.

The answer to your question is =

Danny got 1/16 of the whole pie

Answer:

x is greater than -2 and less than or equal to 3

Step-by-step explanation:

so the 3x + 1 is greater than -5

so 3x is greater than -6

we divide both sides by 3

then we find out that x is greater than -2

we also know that 3x + 1 is less than or equal to 10

so 3x is less than or equal to 9

we divide both sides by 3

then we find out that x is less or equal to 3

so we can say that x is greater than -2 and less than or equal to 3

Answer:

44 represents months

x*y

$77

x

x*y

[tex]6 - \sqrt{5} \times \frac{6 + \sqrt{5} }{6 + \sqrt{5} } [/tex]

[tex] \frac{(6 - \sqrt[]{5})(6 + \sqrt{5} ) }{6 + \sqrt{5} } = \frac{36 - 5}{6 + \sqrt{5} } = \frac{31}{6 + \sqrt{5} } [/tex]

Using the Central Limit Theorem, it is found that the values of the population standard deviation [tex]\sigma[/tex] needed are given by:

a) [tex]\sigma = 32[/tex]

b) [tex]\sigma = 16[/tex]

c) [tex]\sigma = 4[/tex]

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, we have that n = 16.

Item a:

s = 8, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]8 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 32[/tex]

Item b:

s = 4, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]4 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 16[/tex]

Item c:

s = 1, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 4[/tex]

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Answer:

sorry cant help with that

Step-by-step explanation:

[tex]~~~~~~ \stackrel{\textit{\Large 4.8\% semiannually}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1000\\ r=rate\to 4.8\%\to \frac{4.8}{100}\dotfill &0.048\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &1 \end{cases}[/tex]

[tex]A=1000\left(1+\frac{0.048}{2}\right)^{2\cdot 1}\implies \boxed{A\approx 1048.58}~~\textit{\Large \checkmark} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \stackrel{\textit{\Large 4.7\% quarterly}}{\textit{Compound Interest Earned Amount}}[/tex]

[tex]A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1000\\ r=rate\to 4.7\%\to \frac{4.7}{100}\dotfill &0.047\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &1 \end{cases} \\\\\\ A=1000\left(1+\frac{0.047}{4}\right)^{4\cdot 1}\implies \boxed{A\approx 1047.83}[/tex]