A young student drops a stone off the side of a cliff that is 41 meters high. How long does it take the stone to hit the ground below?


A)
2.89 s

B)
8.36 s

C)
3.20 s

D)
2.04 s

Answer:

The other component is 17.32m/s.

For more information

lemme so you how to solve it!

given velocity v = 20 m/s

let the given rectangular component is

cos somponent, so 10 = v cos x

so, other component will be sin component

i.e., v sin x

or, 10 = 20 cos x

or, cos x = 1/2 

and as sin^2 x + cos^2 x = 1

or, 1 - cos^2 x = sin^2 x

or, 1 - (1/2)^2 = sin^2 x

so, sin x = sqrt( 1 - 1/4)

or, sin x = sqrt(3/4)

so, rectangular component is 

20 sin x = 20 sqrt(3/4)

= 10 sqrt3

= 17.32 m/s

Explanation:

hope to help you (:

Answer:

The statements that best compares radiation and conduction are the following: both transfer thermal energy from warm objects to cooler objects and both can transfer energy through matter. The difference is that conduction is through direct heat transfer; whereas, radiation transfers heat through waves.

Answer:

4.71m/s

Explanation:

Average speed = Total distance travelled ÷ Total time taken.

80/17=4.71

4.71m/s

Answer:

In this question,

                                                = 80m.

                                     = 17s

So, Average speed would be 80 ÷ 17

= [tex]\frac{80}{17}[/tex]

 = 4.71 m/s. or 4.71 meter per second.

Answer:

a

Explanation:

Answer:

Explanation:

Formula

Force = G * m1 * m2 / r^2

Givens

Solution

1.67 * 10^-9 = 6.67 * 10^-11 * 110 * m2/(11)^2        Divide both sides by 10^-9

1.67 * 10^-9/10^-9 = 6.67*10^-11/(10^-9 *110*m2/121

1.67 = 6.67 * 110 * 10^-2 * m2 / 121                      Multiply both sides by 121

1.67 * 121  = 6.67 * 10 ^-2 * 110 * m2 * 121/121      Combine

202.07 = 7.337 * m2                                           Divide both sides by 7.337

202.07/7.337  =  m2

m2 = 27.54 kg

Answer:

A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are and respectively.

As masses are equal, so .

Similarly, let the radii of the planets A and B are and respectively.

As radii are equal, so .

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A,

my weight of planet B,

By using equations (i) and (ii),

.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (A) is correct.

Explanation:

let's assume that:

v1= 600ml=0,6l

T1=27°C= 300K

p1=700mmHG=93326Pa

T2=-20°C=253K

p2=500mmHg=66661

V2=?

p1V1/T1=p2V2/T2 => V2=p1V1T2/p2

V2= 93326*0,6*253/66661

V2=212,52l

Answer:

yes

Explanation:

masses attract each other

with a teeny-tiny force

Answer:

69

Explanation:

just because

Answer:

you have gay

Explanation:

699999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999ooooooooooooooooooooooooooo

Answer:

Answer: C. -12 newtons

Explanation: Since, the block is in static equilibrium,

the net force on the block is zero i.e. balance forces are acting on the block.

In the horizontal direction,

force applied+force due to friction = 0

20 N + (-20N) = 0

In the vertical direction as well, net force is zero:

Force due to gravity + force exerted by the ground = 0

12 N + force exerted by the ground = 0

⇒force exerted by the ground = 0 -12 N = -12 N

Thus, the correct option is C. -12 N where negative sign means that the direction of the force due to ground is opposite to the force of gravity.

Answer:

Initial velocity (u) = 40 m/s

Distance travel in last 5 seconds = 100 m

Explanation:

Given:

Acceleration (a) = 8 m/s²

Final velocity (v) = 0 m/s

Find;

1] Initial velocity before 5 sec

2] Distance travel in last 5 seconds

Computation:

1] Initial velocity before 5 sec

v = u + at

0 = u + (-8)(5)

u - 40 = 0

Initial velocity (u) = 40 m/s

2] Distance travel in last 5 seconds

s = ut + (1/2)(a)(t²)

s = (40)(5) + (1/2)(-8)(5²)

s = 200 - 100

Distance travel in last 5 seconds = 100 m

Answer:

Explanation:

The equation for frequency is

[tex]f=\frac{v}{\lambda}[/tex] where

f = frequency, v is velocity, and lambda is wavelength. Filling in:

[tex]262=\frac{343}{\lambda}[/tex] and

[tex]\lambda=\frac{343}{262}[/tex] so

[tex]\lambda=1.31m[/tex]

The wavelength of the note played on the piano is 1.31m.

Given the data in the question;

Wavelength of the note; [tex]\lambda = \ ?[/tex]

Wavelength is simply referred to as the spatial period of a periodic wave i.e when the shapes of waves are repeated, the distance over which they are repeated is called wavelength. It is expressed as;

[tex]\lambda = \frac{v}{f}[/tex]

Where v is velocity and f is frequency

We substitute our given values into the expression above;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{343m/s}{262s^{-1}} \\\\\lambda = 1.309m\\\\\lambda = 1.31m[/tex]

Therefore, the wavelength of the note played on the piano is 1.31m.

Learn more about wavelength: https://brainly.com/question/16776907

Answer:

There is a lot of instruments used for measurement, may I ask which one are you referring to?

Answer:

<7

Explanation:

This is a reaction between a steong acid and a weak base which produces a acidic salt at equvalence point. Hence pH is less than 7

Answer:

D bcz the slope rose the fastest

Explanation:

I DON'T WANNA BE QUESTIONED, THIS IS BECAUSE y POSITION ROSE FASTER THAN x POSITION

Answer:

(a) 12 m/s

(b) At t = 0, x'(t) = 0

At t = 5.0 s, x'(t) = 15 m/s

At t = 10.0 s, x'(t) = 12 m/s

(c) i. The initial velocity = 2.0 cm/s

The initial position = 50 cm

The initial acceleration = 0.125 cm/s²

ii. 16 seconds

2. (a) Approximately 0.85 m/s

(b) 2.094 J

(c) i. Approximately 49.74 m/s

ii. Approximately 86.38°

3. (i) 4·i + 5·j

(ii) -2·i - j - 2·k

(iii) 5·i + 4·j - 3·z

(iv) 8

(v) (a) The magnitude is 2.8 cm, the direction is East

(b) The magnitude is ((14·√3)/5) cm, the direction is North

(c)  The magnitude is ((14·√3)/5), the direction is South

Explanation:

x(t) is given as follows;

x(t) = b·t² - c·t³

Where;

b = 2.4 m/s(²) (we note that the unit of b for the term to be distance in m/s²)

c = 0.120 m/s³

(a) At t = 0, we have;

x(0) = b × 0² - c × 0³ = 0

At t = 10.0 s, we have;

x(10.0) = 2.4 m/s² × (10.0 s)² - 0.120 m/s³ × (10.0 s)³ = 120 m

The average velocity = (Total distance)/(Total time)

∴ The average velocity of the car for the time interval t = 0 to t = 10.0 s, [tex]v_{ave}[/tex], is given as follows;

[tex]v_{ave}[/tex] = (120 m - 0 m)/(10.0 s - 0 s) = 12 m/s

The average velocity of the car for the time interval t = 0 to t = 10.0 s, [tex]v_{ave}[/tex]  = 12 m/s

(b) The instantaneous velocity, [tex]v_{inst}[/tex], is given as follows;

[tex]v_{inst} = \lim \limits_{t \to 0} \left( v_{ave}\right) = \lim \limits_{t \to 0} \left( \dfrac{\Delta x}{\Delta t} \right) = \dfrac{dx}{dt} = x'(t)[/tex]

[tex]x'(t) = \dfrac{d\left (b \cdot t^2 - c \cdot t^3\right)}{dt}[/tex]

x'(t) = 2·b·t - 3·c·t²

At t = 0, x'(t) = 2 × b × 0 - 3 × c × 0² = 0

At t = 5.0 s, x'(t) = 2 × 2.4 m/s² × 5.0 s - 3 × 0.120 m/s³ × (5.0 s)² = 15 m/s

At t = 10.0 s, x'(t) = 2 × 2.4 m/s² × 10.0 s - 3 × 0.120 m/s³ × (10.0 s)² = 12 m/s

(c) x(t) = 50 cm + (2.0 cm/s)·t - (0.0625 cm/s²)·t²

i. The initial velocity is the instantaneous velocity, x'(t), at time, t = 0

x'(t) = 2.0 cm/s - 2 × 0.0625 cm/s² × t

At t = 0, x'(0) = 2.0 cm/s - 2 × 0.0625 cm/s² × 0 = 2.0 cm/s

The initial velocity, x'(0) = 2.0 cm/s

The initial position = The position at time t = 0 = x(0)

x(0) = 50 cm + (2.0 cm/s) × 0 - (0.0625 cm/s²) × 0² = 50 cm

The initial position, x(0) = 50 cm

The initial acceleration, x''(0) = 2 × 0.0625 cm/s² = 0.125 cm/s²

ii. x'(t) = 2.0 cm/s - 2 × 0.0625 cm/s² × t

When the velocity of the turtle, x'(t) = 0 we have;

0 = 2.0 cm/s - 2 × 0.0625 cm/s² × t

∴ t = (2.0 cm/s)/(2 × 0.0625 cm/s²) = 16 seconds

The velocity of the turtle is zero after 16 seconds

2. The mass of the large fish, m₁ = 15.0-kg

The speed of the large fish, v₁ = 1.1 m/s

The mass of the smaller fish, m₂ = 4.50 kg

The speed of the small (stationary) fish, v₂ = 0

The initial momentum = 15.0 kg × 1.1 m/s + 4.50 kg × 0 = 16.5 kg·m/s

The initial momentum = 16.5 kg·m/s

The final momentum = (15.0 kg + 4.50 kg) × v₃ = 19.50 kg × v₃

The final momentum = 19.50 kg × v₃

Where;

The total initial momentum = The total final momentum

We get;

16.5 kg·m/s = 19.50 kg × v₃

∴ v₃ = (16.5 kg·m/s)/(19.50 kg)

v₃ = (16.5/19.50) m/s = (11/13) m/s ≈ 0.85 m/s

∴ The speed of the large fish just after it eats the small, v₃ ≈ 0.85 m/s

(b) The initial kinetic energy, K.E.₁ = (1/2) × 15 kg × (1.1 m/s)² = 9.075 J

The final kinetic energy, K.E.₂ = (1/2) × 19.5 kg × (11/13 m/s)² = 363/52 J

The mechanical energy dissipated, ΔE = K.E.₁ - K.E.₂

ΔE = (9.075 - 363/42) J = 1089/520 J ≈ 2.094 J

The mechanical energy dissipated, ΔE = 2.094 J

(c) i. We have the total momentum = 110 × 8.8· j + 85 × 7.2· i = 9.680·i + 612·i

The velocity after collision, v = (9.680·i + 612·i)/(110 + 85) = 49.64·j + 3.14·i

The magnitude of the velocity, v = √(49.64² + 3.14²) ≈ 49.74 m/s

ii. The direction, θ = arctan(49.64/3.14) ≈ 86.38°

3. (i) [tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = (i + 2·j - k) + 3·i + 3·j + k = 4·i + 5·j

(ii) [tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = (i + 2·j - k) - (3·i + 3·j + k) = -2·i - j - 2·k

(iii) [tex]\underset{A}{\rightarrow} \times \underset{B}{\rightarrow}[/tex] = (2 + 3)·i - (1 + 3)·j + (3 - 6)·z = 5·i + 4·j - 3·z

(iv) [tex]\underset{A}{\rightarrow} \cdot \underset{B}{\rightarrow}[/tex] = 1×3 + 2 × 3 + (-1)×1 = 8

(v) (a) [tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = 2.8·cos(60°)·i + 2.8·sin(60°)·j + (2.8·cos(60°)·i - 2.8·sin(60°)·j

[tex]\underset{A}{\rightarrow} + \underset{B}{\rightarrow}[/tex] = 5.6·cos 60°·i = 2.8·i

The magnitude = 2.8, the direction is east

(b) [tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = 2.8·cos(60°)·i + 2.8·sin(60°)·j - (2.8·cos(60°)·i - 2.8·sin(60°)·j

[tex]\underset{A}{\rightarrow} - \underset{B}{\rightarrow}[/tex] = 5.6·sin(60°)·j= ((14·√3)/5)·j

The magnitude = ((14·√3)/5), the direction is North

(c)  [tex]\underset{B}{\rightarrow} - \underset{A}{\rightarrow}[/tex] = (2.8·cos(60°)·i - 2.8·sin(60°)·j - (2.8·cos(60°)·i + 2.8·sin(60°)·j)

[tex]\underset{B}{\rightarrow} - \underset{A}{\rightarrow}[/tex] = -5.6·sin(60°)·j= (-(14·√3)/5)·j

The magnitude = ((14·√3)/5), the direction is South

Answer:

Explanation:

We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.

F = +50.0,

f = -30.0,

m = 7.60 kg. Therefore:

50.0 - 30.0 = 7.60a and

20.0 = 7.60a and

a = 20.0/7.60 so

a = 2.63 m/s/s to the right

Explanation:

sana po nakatulong

pa brainliest po thanks❤

Answer

Explanation:

Simple arithmetic cannot be used if two or more vectors are not along the same direction. Vectors can be added when two vectors are in the same direction but for the subtraction of vectors, if the vectors are not in the same direction you then subtract.

Answer:

1. Torque → F. Study of forces

2. C.O.G → D. Point of action of weight.

3. Plumb line → A. Line of C.O.G

Answer:

c.

Explanation:

Answer:

Centripetal force is the force acting towards the center of circular motion or path.

[tex]{ \tt{formular : \: F = \frac{m {v}^{2} }{r} }} \\ { \tt{F : \: is \: centripetal \: force}} \\ { \tt{m : \: is \: mass}} \\ { \tt{v : \: is \: velocity}} \\ { \tt{r : \: is \: radius}}[/tex]

Explanation:

Its opposite is centrifugal force which acts away from the center of circular path.

Answer:

Theres 2 meanings first is:

the action or process of registering or of being registered.

The other one is:

a combination of stops used when playing the organ.

The meaning of registration is the action of process of registering to some applications or websites which includes some terms and conditions also.

Registration is the process or action of registering into a website or application or to any institute through online or offline mode. By registering we are giving some personal and professional details as per the requirements of the source which need us to be registered.

For example, if we are applying for a central examination, we have to register our name and details in the official website of the examination board.

The registration process bring us some terms and conditions which we can apply or accept to continue the registration process. After successful registration we can have an acknowledgement for the action.

Find more on registration process:

https://brainly.com/question/29602320

#SPJ2

Answer:

Explanation:

Virtual images are always right side up while real images are always upside down. Therefore, the is a virtual image that is smaller than the original.

Answer:

A. Looking at stick shadows on the equinox.

Explanation:

He measures the circumference by placing a pole when the sun is overhead on the days of solstice. He determined the circumference by measuring the difference between  Alexandria to Syene and the angle of the pole's shadow.

The equation used for the calculation of circumference is as follow

[tex]\frac{360 degrew}{7.2 degree} = \frac{Circumference of earth}{Distance from Alexandria to Syene}[/tex]

Please refer to the following link for more details

https://www.khanacademy.org/humanities/big-history-project/solar-system-and-earth/knowing-solar-system-earth/a/eratosthenes-of-cyrene

Answer:

Cause you are their family and they need you. Do you wanna be someone who abandoned them or be the one they look to and dont dislike into adulthood. Also you signed onto this job no one said it was going to be easy but you making your life easier but harder for someone who is just a kid who still needs you.

Answer:

everything except smell,hate,love,cold

Answer:

chair, air, almonds, cold-drink, smell of perfume

Explanation:

Anything that occupies space and has mass is called matter. Matter can exist in three physical states which are the:

Solid state

Liquid state

Gaseous state

therefore:

Solids: chair and almonds

Liquids: cold-drink

Gas: air and smell of perfume

•Love, smell, hate, thought, and cold are not in the category of matter/are not considered matter

•The sense of smell is not considered a form of matter. However, the smell or odour of a substance is classified as matter.

-The smell of any substance (say, perfume) is the gaseous form of that substance our olfactory system can detect (even at deficient concentrations).

Hence, the smell of some substances is considered matter.

Explanation:

Momentum conservation

V=3.38

Delta kinetic energy =1/2m(vi^2-v^2)

Answer:

Since the mass does not change as the acceleration increases, we can say that force is equal to acceleration. Therefore, if you double the force you double the acceleration. If you increase the mass at a given force the rate of acceleration slows. Therefore, mass is inversely proportional to acceleration.

Answer:

where is the question? I can only see the diagram

d) is an atom of Sodium and an atom of Chlorine.

e) is a molecule of water.