Answer:
500 - 2a = 340
500 - 2a - 500 = 340 - 500
-2a = -160
-2a/-2 = -160/-2
a = 80
Step-by-step explanation:
34− 6 × 3+ 78 pemdas
Answer:
94
Step-by-step explanation:
PEDMAS
[tex]34 - 6 \times 3 + 78 \\ 34 - 18 + 78 \\ 34 + 60 \\ = 94[/tex]
Step 1 : Multiplication :
-6×3 =-18
Step 2: Addition: -18+78 = +60
Step 3: Addition : 35+60
= 94
Answer:
62
Step-by-step explanation:
Cause first is multiply 6x3 =18 so next you add 18+78 =96 then Subtract 96 -34 =62
Plzzz helppp!!
9-4x=17????
Answer:
[tex] \boxed{ \bold{ \boxed{ \sf{x = - 2}}}}[/tex]Step-by-step explanation:
[tex] \sf{9 - 4x = 17}[/tex]
Move 9 to right hand side and change it's sign
⇒[tex] \sf{ - 4x = 17 - 9}[/tex]
Subtract 9 from 17
⇒[tex] \sf{ - 4x = 8}[/tex]
Divide both sides of the equation by -4
⇒[tex] \sf{ \frac{ - 4x}{ - 4} = \frac{8}{ - 4}} [/tex]
Calculate
⇒[tex] \sf{x = - 2}[/tex]
Hope I helped!
Best regards!!
• (4xy^4)(– 2x^2y^5)
Answer:
This will be -8x^3y^9.
The weight of a full steel bead tire is approximately 800 grams, while a lighter wheel weighs only 700 grams. What is the weight of each tire in pounds? There are 453.592 grams in one pound. Round answers to 2 decimal places.
Answer:
1.54 and 1.7 I believe
Step-by-step explanation:
Answer:
The full steel tire is 1.76 pounds and the lighter wheel is 1.54 pounds
Step-by-step explanation:
To find how many pounds each tire is, divide the weight in grams by 453.592
Full steel tire:
800/453.592 = 1.76 pounds
Lighter wheel:
700/453.592 = 1.54 pounds
So, the full steel tire is 1.76 pounds and the lighter wheel is 1.54 pounds
Please solve ASAP, 3k+16=9+6x? and show ur work please?
Answer:
[tex]\Large \boxed{k=2x + \frac{-7}{3}} \\ \\ \\ \Large \boxed{x=\frac{1}{2} k+\frac{7}{6}}[/tex]
Step-by-step explanation:
Solving for k:
[tex]\sf 3k+16=9+6x[/tex]
Subtracting 16 from both sides.
[tex]\sf 3k=6x-7[/tex]
Dividing both sides by 3.
[tex]\displaystyle \sf k=2x + \frac{-7}{3}[/tex]
Solving for x:
Flipping the original equation.
[tex]\sf 6x+9=3k+16[/tex]
Subtracting 9 from both sides.
[tex]\sf 6x=3k+7[/tex]
Dividing both sides by 6.
[tex]\sf \displaystyle x=\frac{1}{2} k+\frac{7}{6}[/tex]
Translate the sentence into an equation.
The sum of 2 times a number and 3 equals 7.
Use the variable b for the unknown number.
=================================================
Work Shown:
b = unknown number
2b = 2 times a number
2b+3 = the sum of 2 times a number and 3
2b+3 = 7, since the expression above is set equal to 7
The equation represents the given algebric phrase is 2b + 3 = 7 and that number will be 2.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
As per the given phrase,
The sum of 2 times a number and 3 equals 7.
2 times b = 2b
The Sum of 2b with 3 equal to 7 will be 2b + 3 = 7
2b = 7 - 3
2b = 4
b = 4/2 = 2
Hence"The equation represents the given algebric phrase is 2b + 3 = 7 and that number will be 2".
For more about the equation,
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Select the correct answer from each drop-down menu. Simplify. the square root of 64. I don't understand square root so if anyone could tell me how to do square root that would help.
Hey there! I'm happy to help!
Squaring a number is when you multiply it by itself. You represent this with an exponent, which is a little number above the number that you multiply by itself. When you square a number, this exponent is two.
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
The square root is basically just doing this backwards. It is finding the number that can be multiplied by itself to equal that number. You represent this with the √ symbol.
√1=1
√4=2
√9=3
√16=4
√25=5
√36=6
√49=7
√64=8
√81=9
√100=10
We know that 8 multiplied by itself is equal to 64. This means that the square root of 64 is 8.
I hope that this helps you out! Have a wonderful day! :D
what is the missing length.
Answer:
[tex] KS = 12 [/tex]
Step-by-step explanation:
Given that ∆KLM ~ ∆RSK, [tex] \frac{KL}{KR} = \frac{KM}{KS} [/tex] (similarity theorem)
KL = 65
KR = 65 - 52 = 13
KM = 60
KS = ?
[tex] \frac{65}{13} = \frac{60}{KS} [/tex]
Cross multiply
[tex] 65*KS = 60*13 [/tex]
[tex] 65*KS = 780 [/tex]
[tex] \frac{65*KS}{65} = \frac{780}{65} [/tex]
[tex] KS = 12 [/tex]
A line segment has a length of approximately 10cm. If a compass is set to a width of 9cm, will it still be possibly to bisect the line segment?
Answer: Yes it is possible to bisect the given segment
The compass width (9) is over half of the segment length (10), so we can form the arcs needed to get the perpendicular bisector.
Make the following conversion. 0.00432 km = _____ mm 0.00000000432 0.0000000432 432 4,320
Answer:
0.00432 km = 4320 mm
Step-by-step explanation:
There are 1000000 millimeters in a kilometer. To convert kilometers to millimeters, multiply the kilometer value by 1000000.
Quick check 0.00432 * 1000000 = 4320 mm
Answer:
4320
Step-by-step explanation:
a pitcher can hold 8 times as much as a glass. the pitcher holds 64 ounces which model shows this comparison.
Answer:
A model that shows a pitcher holding 8 times the amount of a glass
Step-by-step explanation:
I would need a picture of the models, but I think I can still help.
Any model that shows a pitcher holding 8 times as much as a glass is the correct model. Be sure to read carefully so you pick the right model.
The equation y = 8x shows the relationship between the holding capacity of the pitcher and glass, and x = 64/8 shows the total amount held by the glass.
What is a linear equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
Let's suppose the pitcher can hold x ounces
And the glass can hold y ounces
From the given problem:
y = 8x
The above equation modeled the relationship between the holding capacity of the pitcher and glass.
If y = 64
Then x = 64/8 = 8 ounces
Thus, the equation y = 8x shows the relationship between the holding capacity of the pitcher and glass, and x = 64/8 shows the total amount held by the glass.
Learn more about the linear equation here:
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Jake's water bill is $24.60 per month plus $2.00 per ccf (hundred cubic feet) of water. What is the maximum number of ccf Jake can use if he wants his bill to be no more than $64.00?
Answer:
Jake can use 19.70 ccf to not exceed $ 64.00 in water bill.
Step-by-step explanation:
The cost function of water bill is:
[tex]C = C_{f}+C_{v}[/tex]
Where:
[tex]C_{f}[/tex] - Fix costs, measured in USD.
[tex]C_{v}[/tex] - Variable costs, measured in USD.
The fix and variable costs are, respectively:
[tex]C_{f} = 24.60[/tex]
[tex]C_{v} =2\cdot \left(\frac{Q}{100} \right)[/tex]
Where [tex]Q[/tex] is the water capacity consumed within a month, measured in cubic feet. Therefore, first formula is expanded:
[tex]C = 24.60+2\cdot \left(\frac{Q}{100} \right)[/tex]
If [tex]C = 64\,USD[/tex], the maximum water capacity is:
[tex]64 = 24.60+2\cdot \left(\frac{Q}{100} \right)[/tex]
[tex]39.40 = 2\cdot \left(\frac{Q}{100} \right)[/tex]
[tex]Q = 1970\,ft^{3}[/tex]
Which is equivalent to 19.70 ccf.
Rationalise the denominator and find a, b
Answer:
a = 49
b = - 20√2
Step-by-step explanation:
5 - 2√6 / 5 + 2√6
We can rationalise the denominator as follow:
5 - 2√6 / 5 + 2√6
Multiply the numerator and the denominator by the conjugate of
5 + 2√6. The conjugate of 5 + 2√6 is
5 - 2√6
(5 - 2√6 / 5 + 2√6) x (5 - 2√6 / 5 - 2√6)
(5 - 2√6) (5 - 2√6) /(5 + 2√6) (5 - 2√6)
Expand
(25 - 10√6 - 10√6 + 4×6) / (25 - 10√6 + 10√6 + 4×6)
25 - 20√6 + 24 / 25 - 24
25 + 24 - 20√6 / 1
49 - 20√6
Equating 49 - 20√6 with a + b√3, we can obtain the value of a and b as follow:
49 - 20√6 = a + b√3
From the above
a = 49
b√3 = - 20√6
Divide both side by √3
b = - 20√6/√3
Rationalise
b = - 20√6/√3 x √3/√3
b = - 20√(6×3)/ √3×√3
b = - 20√18 / 3
b = - 20√(9×2) / 3
b = - 20 × 3√2 / 3
b = - 20√2
Given info:- Rationalise the denominator and find out the value of "a" and "b"
Given expression: {(5-2√6)/(5+2√6)} = a+b√3
Explanation:-
{(5-2√6)/(5+2√6)} = a+b√3
We know that Rationalising factor of a+b√c is a-b√c.
Therefore, the rationalising factor of 5+2√6 is 5-2√6.
⇛{(5-2√6)/(5+2√6)} × {(5-2√6)/(5-2√6)} = a+b√3
⇛{(5-2√6)(5-2√6)}/{(5+2√6)/(5-2√6)} = a+b√3
⇛{(5-2√6)²}/{5+2√6)(5-2√6)} = a+b√3 [∵(a-b)(a-b)=(a-b)²]
⇛{(5-2√6)²}/{(5)²-(2√6)²} = a+b√3 [∵(a+b)(a-b)=a²-b²]
⇛{(5-2√6)²}/({5*5)-(2*2√6*6)} = a+b√3
⇛{(5-2√6)²}/(25 - 4√6) = a+b√3
⇛{(5-2√6)²}/(25-24) = a+b√3
⇛{(5-2√6)²}/1 = a+b√3
⇛(5-2√6)² = a+b√3
⇛(5)²-(2√6)²+2(5)(2√6) = a+b√3
⇛(5*5) - (2*2√6*6) - 10 - 2√6 = a+b√3
⇛25 - 10 - 4√6 - 2√6 = a+b√3
⇛15 - 4√6 - 2√6 = a+b√3
⇛15 + 6√6 = a+b√3
∴ 15 + 6√6 = a+b√3
On, comparing with both RHS we notice that:
The value of a = 15 and b = 6.
Hope this helps!!
If you have any doubt, then you can ask me in the comments.
How many square inches are in 60 square fee
Answer:8640 square inches
Step-by-step explanation:
Kim can mow the greens at the golf course twice as fast as I can. Working together, we can mow them in 4 hours. How long will it take me to mow the greens alone?
Answer:
12 hours
Step-by-step explanation:
Let x hours be the time it will take you to mow the greens at the golf course.
Since Kim can mow twice as fast, it will take Kim x / 2 hours to mow the greens.
In 1 hour, you will mow 1 / x of the greens
in 1 hour, Kim will mow 1 / (x / 2) of the greens= 2 / x of the greens
In 4 hours, you will mow 4 * 1 / x of the course = 4 / x of the greens
In 4 hours, Kim will mow 4 * 1 / (x / 2) of the course = 4 / (x / 2) = 8 / x of the greens.
Since we are dealing in fraction, the sum of the amount of greens that they would individually mow in 4 hours should be 1. i.e
(4 / x) + (8 / x) = 1
12 / x = 1
Solve for x;
x = 12
Therefore, it will take you 12 hours to mow the greens alone.
HELPPp me asap please I'm hopeless
The arithmetic progressions [tex]\{2, 5, 8, 11, \ldots\}[/tex] and[tex]3, 10, 17, 24, \ldots \}[/tex] have some common values. What is the largest value less than 500 that they have in common?
=================================================
Work Shown:
We have two sequences, which we'll call A and B
A = {2,5,8,11,14, 17 ,20,23,26,29,32,35, 38, 41,44,47,50,53,56, 59 ,62...}B = {3,10, 17 ,24,31, 38 ,45,52, 59 , 66...}Both sequences are arithmetic. The first sequence starts at 2, and increases by 3 each time. Sequence B starts at 3 and increases by 7 each time.
The terms in bold are what the two sequences have in common.
-----------
It turns out that the bold terms follow an arithmetic sequence of their own.
The sequence {17, 38, 59, ...} is arithmetic.
Call this sequence C. This sequence starts at 17 and increases by 21 each time. The nth term for sequence C is
C(n) = a+d(n-1)
C(n) = 17+21(n-1)
C(n) = 17+21n-21
C(n) = 21n-4
Plugging in n = 1 leads to C(n) = 17. Also, plug in n = 2 and you should get C(n) = 38. Plugging in n = 3 leads to C(n) = 59. And so on.
-----------
The question is now "what is the largest term in sequence C such that it is less than 500?".
In other words, we want to find the term C(n) where C(n) < 500 and C(n) is as large as possible.
Use a bit of algebra to get
C(n) < 500
21n - 4 < 500
21n < 500+4
21n < 504
n < 504/21
n < 24
So n must be smaller than 24 to get what we want.
Because n is a natural number (positive whole number), we drop to n = 23 to find that
C(n) = 21n-4
C(23) = 21(23)-4
C(23) = 479
The largest value, less than 500, the two original sequences have in common is 479.
If we didn't have the restriction "less than 500", then there would be no largest value as sequence C goes on forever.
Answer:
467
Step-by-step explanation:
We have two sequences, which we'll call A and B
A = {2,5,8,11,14, 17 ,20,23,26,29,32,35, 38, 41,44,47,50,53,56, 59 ,62...}
B = {3,10, 17 ,24,31, 38 ,45,52, 59 , 66...}
Both sequences are arithmetic. The first sequence starts at 2, and increases by 3 each time. Sequence B starts at 3 and increases by 7 each time.
The terms in bold are what the two sequences have in common.
-----------
It turns out that the bold terms follow an arithmetic sequence of their own.
The sequence {17, 38, 59, ...} is arithmetic.
Call this sequence C. This sequence starts at 17 and increases by 21 each time. The nth term for sequence C is
C(n) = a+d(n-1)
C(n) = 17+21(n-1)
C(n) = 17+21n-21
C(n) = 21n-4
Plugging in n = 1 leads to C(n) = 17. Also, plug in n = 2 and you should get C(n) = 38. Plugging in n = 3 leads to C(n) = 59. And so on.
-----------
The question is now "what is the largest term in sequence C such that it is less than 500?".
In other words, we want to find the term C(n) where C(n) < 500 and C(n) is as large as possible.
Use a bit of algebra to get
C(n) < 500
21n - 4 < 500
21n < 500+4
21n < 504
n < 504/21
n < 24
So n must be smaller than 24 to get what we want.
Because n is a natural number (positive whole number), we drop to n = 23 to find that
C(n) = 21n-4
C(23) = 21(23)-4
C(23) = 479
The largest value, less than 500, the two original sequences have in common is 479.
If we didn't have the restriction "less than 500", then there would be no largest value as sequence C goes on forever.We have two sequences, which we'll call A and B
A = {2,5,8,11,14, 17 ,20,23,26,29,32,35, 38, 41,44,47,50,53,56, 59 ,62...}
B = {3,10, 17 ,24,31, 38 ,45,52, 59 , 66...}
Both sequences are arithmetic. The first sequence starts at 2, and increases by 3 each time. Sequence B starts at 3 and increases by 7 each time.
The terms in bold are what the two sequences have in common.
-----------
It turns out that the bold terms follow an arithmetic sequence of their own.
The sequence {17, 38, 59, ...} is arithmetic.
Call this sequence C. This sequence starts at 17 and increases by 21 each time. The nth term for sequence C is
C(n) = a+d(n-1)
C(n) = 17+21(n-1)
C(n) = 17+21n-21
C(n) = 21n-4
Plugging in n = 1 leads to C(n) = 17. Also, plug in n = 2 and you should get C(n) = 38. Plugging in n = 3 leads to C(n) = 59. And so on.
-----------
The question is now "what is the largest term in sequence C such that it is less than 500?".
In other words, we want to find the term C(n) where C(n) < 500 and C(n) is as large as possible.
Use a bit of algebra to get
C(n) < 500
21n - 4 < 500
21n < 500+4
21n < 504
n < 504/21
n < 24
So n must be smaller than 24 to get what we want.
Because n is a natural number (positive whole number), we drop to n = 23 to find that
C(n) = 21n-4
C(23) = 21(23)-4
C(23) = 479
The largest value, less than 500, the two original sequences have in common is 479.
If we didn't have the restriction "less than 500", then there would be no largest value as sequence C goes on forever.
3.5+0.86 divided by 2
Answer:
2.18
Step-by-step explanation:
2. A woman travelled from Lagos to Ondo a distance of 350km. Her average speed on the outward journey was ykm. On the return journey, her average speed was 10km/hr faster and therefore she completed the return journey 37.5minutes earlier. Find A. The value of y B. Get average speed on the return journey in km/hr C. The total time taken for the whole journey in hrs. Good luck
Answer:
70 km/h
9 hr 22.5 min
Step-by-step explanation:
Given
Distance = 350 kmSpeed = yReturn speed = y + 10Time difference on return = 37.5 min = 37.5/60 hr = 5/8 hrDifference in time as equation:
350/y - 5/8 = 350/(y+10)(8*350 -5y)/8y = 350/(y+10)(y+10)(560 - y)= 8y*70560y - y² +5600 - 10y = 560yy² + 10y - 5600=0y = (-10 ± √(100 +4*5600))/2y = (-10 ±150)/2y= 70 y = -80 not considered as negative valueAverage speed was 70 km/h
Total time = 350/70 + 350/(70+10) = 5 + 4.375 = 9.375 hr = 9 hr 22.5 min
If ya varies directly with x , and y =-12 when x =6 , find x when y =-4
Answer:
x = 2
Step-by-step explanation:
Hello!
Since y varies directly with x what happens to y also happens to x
From y = -12 to y = -4 you divide by 3 so we do that to x
6 / 3 = 2
The answer is 2
Hope this helps!
Please please please please please help me I really need this
Answer:
10x² + -18
Step-by-step explanation:
g(f(x)) means you substitute 2x²-5 for every occurrance of x in g(x).
g(f(x)) = 5(2x²-5) + 7 = 10x² - 25 + 7 = 10x² - 18 = 10x² + -18
What would this be for EBA
Answer:
25°
Step-by-step explanation:
180-130=50
50÷2=25°
What would be the equation for "two times x subtracted by x squared"?
Answer:
[tex]\Huge \boxed{-x^2+2x}[/tex]
Step-by-step explanation:
2 times x subtracted by x².
[tex]\Rightarrow 2 \cdot x-x^2[/tex]
[tex]\Rightarrow 2x-x^2[/tex]
Rearranging the expression.
[tex]\Rightarrow -x^2+2x[/tex]
Answer:
2x -x^2
Step-by-step explanation:
[tex]2(x) - x^2\\= 2x-x^2[/tex]
Stephen is tracking how many words per minute (wpm) he reads for reading class. He is now at
112 wpm, and each week he hopes to increase
his speed by 8 words per minute.
Equation: w = 112 + 8t
t = time (weeks)
w = wpm
How many weeks will it take Stephen to reach
176 wpm?
Answer:8 weeks
Step-by-step explanation:
Answer:
Column 1 label:
✔ t
Column 2 label:
✔ 112 + 8t
Column 3 label:
✔ w
Column 4 label:
✔ (t, w)
Step-by-step explanation:
edge20
Stephen is tracking how many words per minute (wpm) he reads for reading class. He is now at 112 wpm, and each week he hopes to increase his speed by 8 words per minute.
Equation: w = 112 + 8t
t = time (weeks)
w = wpm
Label the columns for the table
Column 1 label:
✔ t
Column 2 label:
✔ 112 + 8t
Column 3 label:
✔ w
Column 4 label:
✔ (t, w)
which decimal number best describes a fraction 79/6
Answer:
13.2
Step-by-step explanation:
We just divide 79/6 which is equal to 13.1666667 which we can round to 13.2
Answer:
13.166667 best describes the fraction 79/6
Find the length of the side x in this right triangle.
A.5 tan 50.1
B.(tan 50.1)/5
C.tan^-1(5/50.1)
Answer:
x = 5.98
Step-by-step explanation:
Step 1: Use tangent to solve for x
tan50.1 = [tex]\frac{x}{5}[/tex]
x = 5tan50.1
x = 5.98
Therefore x is equal to 5.98
Jim takes great pride in decorating his float for the homecoming parade for his high school. With the $5000 he has to spend, Jim buys 5,000 carnations at $0.30 each, 4,000 tulips at $0.60 each, and 300 irises at $0.25 each. Write an inequality which describes how many roses, r, Jim can buy if roses cost $0.80 each.
Answer:
r = (5000 - [(5000 x 0.3) + (4000 x 0.6) + (300 x 0.25)])0.8
Simplified - r = 820
Step-by-step explanation:
I don't know how to explain it exactly, but I know you have to find out how much the carnations, tulips, and irises all cost,subtract that from how much money he has, and divide what left by the cost of the roses (by multiplying the 0.8 cents, because it's a decimal).
r = (5000 - [(5000 x 0.3) + (4000 x 0.6) + (300 x 0.25)])0.8
r = (5000 - [1500 + 2400 + 75])0.8
r = (5000 - 3975)0.8
r = 1025(0.8)
r = 820
Part of a line Has two endpoints and includes all of the
points in between
a) Point
b) Angle
c) Line segment
d) Line Segment
Answer:
C or D
Step-by-step explanation:
It is a line segment but C and D are the exact same in the question you provided.
The part of a line that has two endpoints and includes all of the line segment
What is a line segment?A line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints
You can draw a line by locating any two point in space and then connecting them together.
Based on the explanation we can conclude that part of a line that has two endpoints and includes all of the line segment
Learn more on line segment here: https://brainly.com/question/18315903
To solve -8p = 48, which of the following could you do to both sides of the equation? A. add -8 B. subtract -8 C. multiply by -8 D. divide by -8
Answer:
D. divide by -8
Step-by-step explanation:
Find the product of the following. i) –5a² bc, 6ab, 8abc² ii) –3x²y and (5y – xy) iii) x²y²z² and (xy – yz + zx) iv) (p + 6) and (q – 7) v) (2x + 7) and (x² – 5x + 6) vii) (x + y + 5) and (2x – 2y – 3)
Answer:
i)-240*a^4*b^3*c^2
ii)-15*x^2*y^2+3*x^3*y^2
iii)x^4*y^3*z^2-x^2*y^3*z^3+x^3*y^2*z^3
iv)p*q+6*q-7*p-42
v)2*x^3-3*x^2-23*x+42
vii)2*x^2-2*y^2+7*x-12*y-15
Step-by-step explanation:
Solve for y.
2y^2 - 10y+44 =(y-7)^2
If there is more than one solution, separate them with commas.
Answer:
y = -5, 1
Step-by-step explanation:
2y² - 10y + 44 = (y - 7)²
expand (y - 7)²
(y - 7)² = y² - 14y + 49
move it to the left
(2y² - 10y + 44) - (y² - 14y + 49) = 0
distribute the (-)
2y² - 10 y + 44 - y² + 14y - 49 = 0
combine like terms
y² - 4y -5
factor with factoring X
y² + 5y - y - 5 = 0
factor by grouping ↓
factor out a y from first half of equation
y(y + 5) - y - 5 = 0
factor out a (-) from second half of equation
y(y +5) - (y + 5) = 0
(y +5)(y - 1) = 0
y = -5, 1