A wagon wheel has mass M,radius R and moment of inertia about its center I.It is free to rotate about a vertical axle. It is set into rotation with an initial angular velocity wo at the time t = 0. A small,self-propelled object with mass ms starts at the axle and moves toward the rim along a spoke so that the distance from the axle is cit.Find the torque,about the axle,exerted by the object on the wheel Wo r~axle

Answers

Answer 1

The torque exerted by the object on the wheel is equal to (ms * wo * cit) / R.

The torque exerted by the self-propelled object on the wagon wheel is dependent on several variables including the mass of the object, its distance from the axle, the initial angular velocity of the wheel, and the radius of the wheel.

To calculate the torque, we can use the equation T = I * alpha, where T is the torque, I is the moment of inertia, and alpha is the angular acceleration.

Since the object is moving along a spoke, we need to find the component of its motion that is perpendicular to the radius of the wheel.

Using trigonometry, we can determine that the distance from the axle to the object is cit * sin(theta), where theta is the angle between the spoke and the radius.

Thus, the torque is equal to (ms * wo * cit * sin(theta)) / R, where ms is the mass of the object, wo is the initial angular velocity of the wheel, and R is the radius of the wheel.

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Related Questions

Plsss Help!!!!
Complete the following nuclear reaction
a) γ

b) α

c) β–

d) p

Answers

I think the answer is d
So the answer is c because what is happening is called “beta decay”. A, gamma doesn’t change the two numbers. B, alpha increases it with a hydrogen atom. and D would make the bottom number on the left of the equation 9.

A rocket takes off from Earth and starts flying to Mars. What happens to the force of gravity between the rocket and Earth as the rocket approaches Mars

Answers

The force of gravity between Earth and Mars will decrease.

The gravitational law is given as-

           F = G mM/r²

  here,  m= mass of rocket

             M = mass of earth

             r = distance between earth and rocket

So, as rocket takes off from earth and fly towards mars then the distance starts to increase between earth and rocket, and the gravitational pull between them starts to weaken. Then a point will reach when rocket will far from gravity of earth and could probably enter the gravity of Mars.

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A patient who is lactose intolerant will have a normal glucose curve after ingesting a dose of lactose.

Answers

False, A patient who is lactose intolerant will not  have a normal glucose curve after ingesting a dose of lactose.

What is lactose intolerant ?

Lactose, the sugar in milk, cannot be fully absorbed by those who have lactose intolerance. They have diarrhea, gas, and bloating as a result of consuming dairy products. Although the illness, which is also known as lactose malabsorption, is typically not harmful, some people may experience uncomfortable symptoms.

Types of lactose intolerance -

Primary lactose intolerance (normal result of aging) This is the most common type of lactose intolerance. Secondary lactose intolerance (due to illness or injury)Congenital or developmental lactose intolerance (being born with the condition)Developmental lactose intolerance.

The symptoms of lactose intolerance?

Symptoms of lactose intolerance include nausea, cramps, gas, bloating, or diarrhea within 30 minutes to 2 hours after consuming milk or dairy products.

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When making segmented bends, the bend radius is the distance from the center point of the circle or object to

Answers

When making segmented bends, the bend radius is the distance from the center point of the circle or object to the centerline of conduit.

What is centerline of conduit.

Segment bending is a technique for bending conduit in which numerous tiny bends are combined to form a single, bigger bend.  Measure from the elbow's center at the bend's CenterPoint to the intersection of the "degrees of bend" lines to determine your centerline radius (see image above). In fact, the CLR may be determined by obtaining this measurement from any point on the elbow. The distance between segments is calculated by dividing the developed length by the number of shots. When making segmented bends, the bend radius is the distance from the center point of the circle or object to the centerline of conduit. To calculate the degrees per shot, divide 90 degrees by the quantity of shots. Regardless of how many lanes a road or highway has, centerline miles are used to quantify their length. Centerline of conduit miles between the two sides of a divided highway might differ slightly due to divergences and curves. Compared to lane miles, centerline miles provide a more understandable indication of a road's overall length.

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Work is being done in "which of these situations? All motions
are at a constant velocity (including velocity = zero).
O Jessica pushes a 25 kilogram cart a distance of 10 meters.
O
A weightlifter holds a 100 k/fogram barbell over his head.
O Bane carries a 20 kilogram box a distance of 50 meters.
O Ali is trying to push a truck away from the parking lot.

Answers

Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

What is Work ?

Work is the product of force and distance in the direction of the force. And the S.I unit of work is Joule

Looking at the given options one by one;

O Jessica pushes a 25 kilogram cart a distance of 10 meters. Work is done by Jessica. The work done = 25 x 10 x 10 = 2500 Joules

O A weightlifter holds a 100 kilogram barbell over his head. The weightlifter does no work.

O Bane carries a 20 kilogram box a distance of 50 meters. Bane does work. The work done = 20 x 10 x 10 = 2000 Joules

O Ali is trying to push a truck away from the parking lot. Since there is no movement, there is no work done.

Therefore, Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

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help me and I will be your friend forever.

Answers

Answer:

1. iodine

2. convection

3. radiation

4. conduction

5. gases

6. expansion

7. freezing point

8. absorber

9. thermos flask

10. mercury

A colleague proposes using giant vacuum-like strainers to strain all the water in the great pacific garbage patch. do you think this would be an effective way to remove plastic?

Answers

No, the use of a giant vacuum-like strainers is not an effective way to remove plastic because the patch tend to be very big and deep that it would need a lot of human effort or strength to filter the trash and the act would lead to disrupt of life in the water column.

What is plastic?

Plastic is known to be a term that connote the  material that is made up of a key ingredient of an organic substance and it is made up of large molecular weight.

Note that It is also seen as polymers that belongs to long carbon chains. and there are a lot of waste disposal in the ocean which disrupt marine activities.

Hence, No, the use of a giant vacuum-like strainers is not an effective way to remove plastic because the patch tend to be very big and deep that it would need a lot of human effort or strength to filter the trash and the act would lead to disrupt of life in the water column.

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A driver comes to a red light and applies her brakes to decelerate her car to a complete stop. The car’s brakes turned its kinetic energy into __________.

Group of answer choices

a. elastic potential energy

b. gravitational potential energy

c. thermal energy

d. electrical energy

Answers

c . Thermal energy I think

A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?

Answers

The frontage measure is 45 feet.

Feet

The British imperial and American customary systems of measurement both use the feet (standard symbol: ft) as a unit of length. One foot has exactly 0.3048 meters since the International Yard and Pound Agreement of 1959. One yard equals three feet in both customary and imperial measurements. One foot equals 12 inches.

Throughout history, numerous regional systems of units, including the Greek, Roman, Chinese, French, and English systems, included the concept of "feet." Its length varied from one nation to another, from one city to another, and occasionally from one trade to another. Its length was often divided into 12 inches or 16 digits, however this was not always the case. Its typical length was between 250 mm and 335 mm.

A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?

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A geologist finds that a Moon rock whose mass is 8.94 kg has an apparent mass of 6.18 kg when submerged in water. What is the density of the rock

Answers

Density of rock = 3.23 Kg/m^3

Given:

mass of Moon rock = 8.94 kg

apparent mass of Moon rock = 6.18 kg

To Find:

density of the rock

Solution: It is a universal fact that mass of an object remains constant whether measured on earth or on moon.

Mass of rock on moon/earth = 8.94 kg

When the block is immersed in water then;

Loss in weight = weight of water displaced

Loss in weight = 8.94 - 6.18 = 2.76 kg

As we know that water has a density of 1g/cm^3 (1000kg/m^3)

Volume of water = volume of the rock = Mass/density = 2.76 kg

density of rock mass/volume = 8.94/2.76 = 3.23 Kg/m^3

Density of rock = 3.23 Kg/m^3

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A gas is enclosed in a container fitted with a piston of cross-sectional area 0.10 m2 . the pressure of the gas is maintained at 8000 nm-2 . when heat is slowly transferred, the piston is pushed up through a distance of 4 cm. if 42 j heat is transferred to the system during the expansion, what is the change in internal energy of the system?

Answers

The change in internal energy is 10 J.

Calculation:

Given,

Cross-sectional area, A = 0.10 m²

Pressure of gas, P = 8000 N/m²

Displacement, s = 4 cm = 0.04 m

Heat transferred, H = 42 J

To find,

Change in internal energy =?

We know that, as per Law of thermodynamics,

Change in internal energy = Heat - Work

Force = pressure × area

          = 8000 × 0.10

          = 800 N

Work = Force × Displacement

         = 800 × 0.04

         = 32 J

Change in internal energy = Heat - Work

                                            = 42 - 32

                                            = 10 J

Hence, the change in internal energy is 10 J.

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NEED HELP asap pls
How much thermal energy must be removed from 3.75 kg of
water to freeze it at its melting point? Use Q = mass x latent
heat of fusion.
Melting point
Boiling point
OA. 15.8 kJ
B. 1250 kJ
Cliquid
Latent heat of fusion.
Latent heat of vaporization
C. 3.75 kJ
Properties of water
Property
D. 8480 kJ
0°C
Value
100°C
4.18 kJ/(kg x °C)
333 kJ/kg
2260 kJ/kg

Answers

The heat that is required to freeze the water is 1250 kJ. Option B

What is the freezing point?

The freezing point of water is the temperature at which liquid water turns to solid. We know that heat is withdrawn from water when it is frozen. This heat is added when the water melts.

The latent heat of fusion = mL

m =  3.75 kg

L = 333kJ/Kg

Hence;

H =  3.75 kg * 333kJ/Kg

H = 1250 kJ

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April stands on a flat surface . If she has a mass of 72 what is the nirmal force acting on her

Answers

The normal force acting on April as she stands on a flat surface is 705.6 N.

Normal force of the girl

Fₙ = mg

where;

Fₙ is the normal force of the girlm is mass of the girlg is acceleration due to gravity

Fₙ = 72 x 9.8

Fₙ = 705.6 N

Thus, the normal force acting on April as she stands on a flat surface is 705.6 N.

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In the paralleling technique, the central ray of the x-ray beam must be _____ to the film sensor and the long axis of the tooth.

Answers

The film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

To find the answer, we need to know above the paralleling technique in the dental x-ray.

What is paralleling technique?The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion. The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion.The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.When preparing for an x-ray, it is imperative to keep in mind the root anatomy.The maxillary occlusal plane of the patient should also be parallel to the ground.

Thus, we can conclude that, the film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

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A 58.5 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 41.7 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.27 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?

Answers

The velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s

What is conservation of momentum:

It states the amount of momentum remains constant

Momentum of a moving body is the product of mass times velocity.

Formula for momentum:

P = m* v

When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

here,

mass of wood, m=58.5 kg

mass of boy, M=41.7 kg

velocity of the boy V=1.27 m/s

Thus,

The conservation of momentum,

m*v = M*V

substituting the value,

(58.5*v) = 1.27* 41.7

v = 52.95 / 58.5

v = 0.905 m/s

Thus, the velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s.

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a 6 amp light bulb dissipates 24j per seconds

calculat the amount of charge passing through the 6 amp light bulb per second

Answers

The  charge passing through the circuit in one second is 8 C.

What is charge?

Charge is property of matter that causes experience of force when kept in electric or magnetic field.

Electric charge exists as the physical property of matter that causes charged matter to experience a force when positioned in an electromagnetic field. Electric charges can be positive or negative. Like charges repulse each other and unlike charges attract each other.

Charge, also understood as electric charge, electrical charge, or electrostatic charge and symbolized by q, exists as a characteristic of a unit of matter that represents the extent to which it has more or fewer electrons than protons.

As we know

I =Q/t

where I is current and Q is charge ,t is time

so put the value in formula

8 = Q/

Q  =  8 coulomb.

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What type of energy is solar energy? and how is it used to fuel us and the machines we use every day?

Answers

According to the research, solar energy is a renewable energy used in generating electricity and obtaining thermal energy.

What is solar energy?

It is a type of energy derived from natural sources known as renewable energy that is obtained from solar radiation that reaches the Earth in the form of light, heat or ultraviolet rays.

Solar energy can be used to generate electricity, hot water supply and home heating.

Therefore, we can conclude that according to the research, solar energy is a renewable energy used in generating electricity and obtaining thermal energy.

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On your way to work about two hours after sunrise, you notice the moon setting. What phase is it in?

Answers

The moon setting on your way to work about two hours after sunrise means it is in the gibbous phase.

What is Gibbous phase?

This phase of the moon involves its side facing the Earth appearing more than half-lit by the Sun, but is less than fully lit.

This phase occurs few hours after sunrise usually in the early morning which is why it is the most appropriate choice.


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A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weighs 160 N. The coefficient of static friction between the foot of the ladder and the ground is 0.40. A man weighing 740 N climbs slowly up the ladder.

Answers

The only vertical forces acting on the wall are the weights of the man and the ladder as well as the normal force because the wall has no friction.

The maximal frictional forces are μsN2=(0.40)(900N)=360N, and N1=w1+wm=160N+740N=900N for the vertical forces to balance. At a height of 4.0 meters above the ground, the ladder makes contact with the wall. about the point of contact with the ground, balancing torques.

N2 = 174.0N because (4.0m)2 = (1.5m)(160N) + (1.0m)(35)(740N) =684N.m. It is necessary for the frictional force to counteract this horizontal force. Setting the frictional fore and n1 to a maximum of 360N and solving for the distance x along the ladder (0.4m)(360N)=(1.50m)(160N)+x(35)(740N) yields x=2.70m

Friction

When two sliding solid surfaces, fluid layers, or material components come into contact with one another, friction acts as a force to stop them from moving in the same direction. Friction comes in several forms:

The relative lateral motion of two solid surfaces in contact is opposed by dry friction. Between moving surfaces, there is kinetic friction, which is different from static friction. With the exception of atomic or molecule friction, asperities on the surface interact to produce dry friction.

When layers of a viscous fluid move in relation to one another, there is friction between them. This is known as fluid friction.

When a lubricant fluid separates two solid surfaces, it is called lubricated friction.

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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m.

Answers

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

[tex]v^{2} - u^{2} = 2as[/tex]

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

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The wavelength of an electromagnetic wave is 600 nm. what is its frequency? (c = 3.0 × 108 m/s)

Answers

Answer:

5.0×10^-9

Explanation:

velocity = frequency × wavelength

3.0×10^8=f600×10^-9

divide both sides by 600×10^-9

f=3.0×10^8/600×10-9

f=5.0×10^-9

The wavelength of an electromagnetic wave is 600 nm. The frequency of the electromagnetic wave is 5.0 × 10^14 Hz.

To find the frequency of an electromagnetic wave, we can use the equation:

Frequency (f) = Speed of light (c) / Wavelength (λ)

where:

c = speed of light in a vacuum = 3.0 × 10^8 m/s

λ = wavelength of the electromagnetic wave in meters

First, we need to convert the given wavelength from nanometers (nm) to meters (m). Since 1 nm = 1 × 10^-9 m, the wavelength is:

λ = 600 nm × (1 × 10^-9 m/nm) = 600 × 10^-9 m = 6.0 × 10^-7 m

Now, we can calculate the frequency using the equation:

f = c / λ

f = 3.0 × 10^8 m/s / (6.0 × 10^-7 m)

f = 5 × 10^14 Hz

So, the frequency of the electromagnetic wave is 5 × 10^14 Hz (hertz).

This means that the wave oscillates or completes 5 × 10^14 cycles per second. Higher frequencies correspond to shorter wavelengths and vice versa. Electromagnetic waves with higher frequencies are more energetic, such as X-rays and gamma rays, while waves with lower frequencies, like radio waves, have longer wavelengths and are less energetic.

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Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F

Answers

The prove of  Angle XYZ- Angle NYM is given below:

∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

What is the triangle about?

Note that from the image given;

NM // XZNY = transversal line∠YXZ ≡ ∠YNM

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, how fast was the car initially traveling? assume that any other unbalanced forces are negligible.

Answers

Answer: A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, then the car initially traveling with a velocity of 40.28m/s.

Explanation: To find the answer, we need to know more about the Perfectly inelastic collision.

What is perfectly inelastic collision?Collision is an interaction between two bodies due to which the individual momenta of the colliding bodies are changed, but the total momentum remains constant.If the colliding bodies stick together after collision, then it is called perfectly inelastic collision.here, the coefficient of restitution will be equal to 0.For, inelastic collision, the momentum is conserved, but the energy is not conserved.How to solve the problem?let's write the conservation equation of momentum as,

               [tex]m_1v_1+0=(m_1+m_2)v_2\\[/tex]

We have to find the value of initial velocity v1,

               [tex]mv_1=(m+m)28 sin46\\v_1=2*28*0.719=40.28 m/s[/tex]

Thus, we can conclude that, the initial velocity of the car will be 40.28m/s.

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A current of 2.0 A flows through a circuit containing a motor with a resistance of 12 ohm how much energy is converted if the motor runs for a minute

Answers

The energy converted is 48 Joules

How to determine the energy

We have the formula for energy in a circuit as

Energy = Power × time

Power = I^2 R

Current, I = 2.0 A

time = 1 minute

Resistance = 12 Ohm

Substitute into the formula

Power = 2 × 2 × 12

Power = 48 Watts

Energy = 48 × 1

Energy = 48 Joules

Thus, the energy converted is 48 Joules

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How much is the velocity of a body when it travels 600m in 5 minutes?​

Answers

answer

so unit of velocity is m/s

displacement=600m

5minutes should be converted to seconds

5×60=300 seconds

so,

velocity= displacement÷time

= 600m ÷300s

=2m/s or 2ms^-1

Answer:

2 m/s

Explanation:

we have given

distance traveled by body =600m

time taken = 5*60 =300 sec( si unit of time is second)

velocity =?

we know that

velocity =distance traveled/ time taken

=600/300

= 2 m/s

What should a driver do when he/she gets to a speed hump? a maintain current speed. b accelerate. c brake. d reduce speed to suggested limit.

Answers

It is usually best to reduce speed to suggested limit when  a driver gets to a speed hump and is denoted as option D.

What is Deceleration?

This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.

Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.

Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.

This therefore the reason why reducing speed to suggested limit is the most appropriate choice.

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Which meteorological parameter is expressed as the ratio between the air’s actual water vapor content and the amount of water vapor required for saturation at that temperature?

Answers

Which meteorological parameter is expressed as the ratio between the air’s actual water vapour content and the amount of water vapour required for saturation at that temperature: relative humidity.

Water vapour is the primary form of atmospheric moisture. Although its storage in the atmosphere is comparatively small, water vapour is extremely important in forming the moisture supply for dew, frost, fog, clouds, and precipitation.

Water vapour is also the most important greenhouse gas in the atmosphere. Water vapour can be produced from the evaporation or boiling of liquid water or from the sublimation of ice.

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Ple can someone help me to answer this question

Answers

The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

A sketch of the uniform stick and the mass

The sketch of the uniform stick and the mass will be two based on the given statement.

when the uniform stick balances on knife at 10 cm from one end;

-------------------------------------------------------  

↓      10cm           Δ       (L - 10 cm)         ↓

200g                                                      M

When the knife edge is moved 5 cm further

|---------------15 cm-----------------|

-----------------------------------------------------------------------

              ↓      8.75 cm           Δ       (L - 15 cm)         ↓

          200g                                                               M

From the first diagram, apply principle of moment;

200(10) = M(L - 10) ------- (1)

From the second diagram, apply principle of moment;

200(8.75) = M(L - 15)   ------- (2)

From equation (1); M = (2000) / (L - 10)

From equation (2); M = (1750) / (L - 15)

Solve (1) and (2);

(2000) / (L - 10) = (1750) / (L - 15)

1750(L - 10) = 2000(L - 15)

L - 10 = 2000/1750(L - 15)

L - 10 = 1.143(L - 15)

L - 10 = 1.143L - 17.14

17.14 - 10 = 1.143L - L

7.14 = 0.143L

L = 7.14/0.143

L = 50 cm

Mass of the uniform stick

M = (2000) / (50 - 10)

M = 50 g

Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

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The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed

Answers

The apparent weight of a 1.1 g drop of water is 4.24084 N.

What is Apparent Weight?According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.

Solution:

N = Speed of rotation = 1250 rpm

D = Diameter = 45 cm

r = Radius = 22.5 cm

M = Mass of drop = 1.1 g

Angular speed of the water = [tex]\omega = \frac{2\pi N}{60}[/tex]

[tex]\omega = \frac{2\pi \times 1250}{60}[/tex]

[tex]\omega = 130.89 rad/s[/tex]

Apparent weight is given by

[tex]W _a = M\omega^{2}R[/tex]

[tex]W_a = 1.1 \times 10^-^3\times (130.89)^2\times 0.225[/tex]

[tex]W_a[/tex] = 4.24084 N

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Question:

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?

The use of fiberglass insulation in the outer walls of a building is intended to minimize heat transfer through the wall by what process?
a) conduction
b) radiation
c) convection
d) vaporization

Answers

Answer:

A, conduction.

Explanation:

Thermal conduction, by definition, is "a phenomenon  that occurs through the interaction of neighboring atoms and molecules, transferring their energy/heat (partially) to their neighbors". Fiberglass insulation works mainly by preventing thermal conduction, as would a rubber handle of a pot on a hot stove.

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