The final velocity of the tugboat and barge after the rope has fully stretched is 11.2 km/h. We can start by using the conservation of momentum to find the final velocity of the tugboat and barge after the rope has fully stretched.
Assuming that the rope is the only force acting on the system, we have:
[tex](m_t+ m_b) * v_i[/tex]= [tex](m_t+ m_b)[/tex]) ×[tex]v_f[/tex]
where [tex]m_t[/tex] and [tex]m_b[/tex] are the masses of the tugboat and barge, respectively, [tex]v_i[/tex]is the initial velocity of the system, and[tex]v_f[/tex] is the final velocity of the system after the rope has fully stretched. Solving for [tex]v_f,[/tex] we get:
[tex]v_f = v_i[/tex] * [tex](m_t + m_b)/(m_t + m_b + k*x_m)[/tex]
where [tex]x_m[/tex]is the maximum stretch in the rope, and k is the stiffness of the rope.
Next, we can use the conservation of energy to find x_max. Initially, the system has kinetic energy:
[tex]KE_i = 1/2 * m_t* v_i^2 + 1/2 * m_b * v_i^2[/tex]
After the rope has fully stretched, the system has potential energy stored in the stretched rope:
[tex]PE_f = 1/2 * k * x_max^2[/tex]
Using the conservation of energy, we can equate the initial kinetic energy to the final potential energy:
[tex]KE_i = PE_f[/tex]
Substituting the expressions for [tex]KE_i and PE_f,[/tex] we get:
[tex]1/2 * m_t* v_i^2 + 1/2 * m_b * v_i^2 = 1/2 * k * x_max^2[/tex]
Solving for [tex]x_m[/tex] we get:
[tex]x_max = \sqrt{((m_t + m_b) } * v_i^2 / k)[/tex]
Substituting the given values, we get:
[tex]x_max = \sqrt{((19 Mg + 75 Mg) } * (15 km/h)^2 / (600 kN/m))[/tex]
[tex]x_m[/tex]= 0.460 m
Finally, we can substitute[tex]x_m[/tex] into the expression for[tex]v_f[/tex] to get:
[tex]v_f = (15 km/h) * (19 Mg + 75 Mg)/(19 Mg + 75 Mg + 600 kN/m * 0.460 m)[/tex]
[tex]v_f = 11.2 km/h[/tex]
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49. A car traveled during two third of the total time with a peed of 10 m /. The car' average peed during the total time i 15 m /. What i the peed of the car in the remaining one third of the time?
The speed of the car in the remaining one third of the time is 25 m/sec.
The speed of the car during two-third(2t/3) of the total time= 10 m/sec
Average speed of the car during the entire journey = 15 m/sec
Let the total time taken by the car during the entire journey = t sec.
Average speed of an object is defined as the ratio of the total distance and the total time taken by the object during the entire journey.
Average speed = total distance/total time
Total distance = Average speed of the object × total time taken by the object
Total distance = 15×t = 15t
Distance covered during the 2t/3 time = 10×2t/3 = 20t/3
Remaining distance = 15t - 20t/3
= 25t/3
Remaining time = t- 2t/3 = t/3
So the speed during the remaining journey = (25t/3)/(t/3)
= 25 m/sec.
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Consider a network of 8 nodes A-H as shown below. The delay vectors
received from the neighbors of node F are also shown. Use the Distance Vector Routing
algorithm to calculate the new estimated delays from node F and the lines for those estimates.
The delay vector for node F as follows:
F: [5, 2, ∞, ∞, ∞, 0, ∞, ∞]
This means that the estimated delay from node F to node A is 5, to node B is 2 and to node F itself is 0. And all other nodes are unreachable.
THE DISTANCE VECTOR ROUTING ALGORITHMThe Distance Vector Routing algorithm, also known as Bellman-Ford algorithm, is used to calculate the shortest path from a given source node to all other nodes in a network.
To calculate the new estimated delays from node F, we first initialize the delay vector for node F as follows:
F: [0, ∞, ∞, ∞, ∞, ∞, ∞, ∞]
Next, we update the delay vector for node F using the delay vectors received from its neighbors. For example, using the information provided in here, we can update the delay vector for node F as follows:
F: [5, 2, ∞, ∞, ∞, 0, ∞, ∞]
This means that the estimated delay from node F to node A is 5, to node B is 2 and to node F itself is 0. And all other nodes are unreachable.
We then repeat this process of updating the delay vector until the estimates converge and no further updates are required.
This is a simplified process and in real world scenario there will be more number of nodes and edges, and also the cost of each edge will be different.
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Which player is serving the ball? OA. The receiver OB. The opponent OC. The server OD. None of the above
The player serving the ball is the server.
option C is the correct answer.
Who is the sever in a game of ball?The right back player of the serving team shall be the first server of the game. In volleyball, the serving player will always be the player that is standing in position 1.
After the right back player of the serving team start the serving process of the game, afterwards the player rotating from the right forward to the right back position shall be the server (clockwise rotation). Rotation occurs after opponents side-out.
Thus, the player that serves the ball is known as the server.
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________ strongly influences the amount of energy generated from hydropower.
The volume of water released and the height of fall strongly influences the amount of energy generated from hydropower.
Hydropower definitionHydropower is an alternative energy for generating electrical power by utilizing water to power machines.
In simple terms, Hydropower or water power is energy produced from flowing water.
In fact, water will not decrease when it is used in the energy utilization process. The reason is, the water cycle is an infinite and continuous recharging system, hydropower is considered a renewable energy. Apart from being more go green, the use of water can support a better natural cycle but must be accompanied by supporting equipment.
How does it workSome hydroelectric power plants are powered by the kinetic energy of flowing water as it moves downstream. Turbines and generators convert energy into electricity, which is then fed to the electrical grid for use in homes, businesses, and industry.
The Positive Side of HydropowerWith the presence of hydropower energy, a country especially like Indonesia which is rich in natural resources is very effective in using this natural energy to make electricity.
In addition to abundant water that can be used for free, hydropower also produces clean energy without pollution and free from air pollution. This energy source is also always renewed automatically by nature when the rainy season arrives. Therefore, so that water is not wasted, the government must provide extra proper drainage facilities both for the needs of the hydropower cycle and for drainage to the sea.
The Negative Side of HydropowerIt doesn't always bear fruit, it turns out that the existence of Hydropower also has a negative side effect which needs to be an important note.
Viewed from the negative side, this water-dependent power source can damage marine life and natural resources. Migration patterns of fish will be disrupted which will eventually damage fish populations. Another consequence of hydropower is the decrease in oxygen levels in the water which endangers fish habitat. If there is no special review, the marine ecosystem will collapse so that people's lives can be disrupted.
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What is the instantaneous angular speed of a spinning amusement-park ride that accelerates from 0.50 rad/s at a con-stant angular acceleration of 0.20 rad/s² for 1.0 s?
The instantaneous angular speed of a spinning amusement park is 0.70rad/sec.
What do you mean by angular speed?The definition of angular speed is the rate at which angular displacement changes.
To find the instantaneous angular speed of the spinning ride, we can use the equation:
ωf = ωi + αt
where ωf is the final angular speed, ωi is the initial angular speed, α is the angular acceleration, and t is the time.
Given that:
ωi = 0.50 rad/s
α = 0.20 rad/s²
t = 1.0 s
so, we can substitute these values into the equation and solve for ωf:
ωf = 0.50 rad/s + (0.20 rad/s² * 1.0 s)
ωf = 0.50 rad/s + 0.20 rad/s
ωf = 0.70 rad/s
The instantaneous angular speed of the spinning ride is 0.70 rad/s after 1s of constant angular acceleration of 0.20 rad/s².
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A ball is attached to a string and spun in a circular path. The string snaps and the ball continues outward from that point in a straight line path. What Newtonian concept explains this?
The ball will continue according to the concept of Inertia and in a straight line according to Newton's first law of motion.
Newton's First Law of MotionIt states that, an object at rest or in a linear motion will continue to be at rest or in its linear motion except an external force act on it.
Given that a ball is attached to a string and spun in a circular path.
In a circular motion, the speed of the object is the same but the velocity is not because the object tend to move in a different straight line direction.
If the string snaps and the ball continues outward from that point in a straight line path, The Newtonian concept that explain this is the concept of Inertia that emanate from the First Newton's Law of Motion
Therefore, the correct answer is First Newton's Law of Motion
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A block with the mass of 14.26kg is sliding down a ramp with an incline of 41 degrees at 2.361 m/s^2. WHat is the coefficient of kinetic friction?
Answer:
To calculate the coefficient of kinetic friction between the block and the ramp, you would need to know the force of kinetic friction acting on the block as it slides down the ramp.
This force can be determined using the equation:
F_friction = friction_coefficient * F_norm
where F_friction is the force of kinetic friction, friction_coefficient is the coefficient of kinetic friction, and F_norm is the normal force acting on the block.
The normal force, F_norm, is equal to the weight of the block, which is the force of gravity acting on the block. This can be calculated using the equation:
F_norm = m * g * cos(theta)
where m is the mass of the block, g is the acceleration due to gravity (approximately 9.8 m/s^2), and theta is the angle of incline of the ramp.
In this case, we know the following values:
mass: 14.26 kg
angle of incline: 41 degrees
velocity: 2.361 m/s^2
By using the law of Kinetic Friction force = friction coefficient * Normal force,
friction_coefficient = F_friction / F_norm
You can then solve for the coefficient of kinetic friction by measuring the force of friction. or by measuring the acceleration of the block and using the equations of motion.
Uday Tahlan
Jakku has half the density of earth and 1/3 the radius. What is the ratio of the acceleration due on gravity on Jakku to that of Earth’s? (Hint: density= p= m/v)
The two masses of the Jakku and earth are of no use. The ratio of their acceleration due on gravity is 9 : 1
What is Gravitational Field Strength ?Gravitational Field strength can be defined as the ratio of gravitational force to unit mass.
Given that Jakku has half the density of earth and 1/3 the radius. What is the ratio of the acceleration due on gravity on Jakku to that of Earth’s?
The acceleration due on gravity is the same as gravitational Field strength. That is,
g = GM/r²
The gravitational Field strength of Jakku of radius r/3 will be
g = GM/(r/3)²
g = GM/(r²/9)
g = 9GM/r²
The gravitational Field strength of earth of radius r will be
g = GM/r²
The mass M is the mass of the sun. The ratio of the acceleration due to gravity on Jakku to that of Earth’s will be
9GM/r² ÷ GM/r²
9/1 or 9 : 1
Therefore, the ratio of the acceleration due to gravity on Jakku to that of Earth’s is 9 : 1
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∆V (Voltage)
I (current)
R (resistance)
4V
2A
2 Ω
12V
8A
4 Ω
6V
3A
3
Inspect your data and write an equation that relates the ∆V to the I and R values. Support your claim with evidence and reasoning.
The equation relating voltage, current and resistance is V = IR, this is because voltage in a circuit increases with increase in current and resistance and vice versa.
What is Ohm's law?
Ohm's law states that the current flowing in a conductor is directly proportional to the voltage across the conductor.
Mathematically, the formula for Ohm's law is given as;
V = IR
where;
V is the voltage in the circuitI is the current flowing in the circuitR is the resistance of the circuitThe given data
Voltage ( V ) Current ( I ) Resistance ( R)
4 2 2
12 8 4
6 3 3
From the equation given above, the voltage in the circuit increases with increase in the current and resistance and decreases with decrease in the current and resistance.
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describe a situation in which work is being done
A box being moved across the room by a mover. A pool chair is blown across the yard by wind. A barbell is raised off the ground by a weightlifter.
Do weightlifters have strength?
Flexibility is important. In addition to being exceptionally strong and powerful, weightlifters are also very flexible. In fact, they are some of the most flexible athletes. To perform this same lifts with the required ranges of motion, extreme levels of versatility are needed.
Is lifting weights a skill?
Lifting weights is a skill. Additionally, it is preferable to study, acquire, and hone talents when you are rested and alert. You'll have to have some gas left in the barrel if you desire to be able to study it again in only a few of days.
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Answer:when you lifting weights
Explanation:
When Jeff ran up a hill at 7.0 m/s, the horizontal component of his velocity vector was 5.1 m/s. What was the vertical component of Jeff's velocity?
When Jeff ran up a hill at 7.0 m/s, the vertical component of his velocity was 4.8 m/s and the horizontal component of his velocity vector was 5.1 m/s.
What is velocity?The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change. Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number. Simply put, velocity is the rate at which something travels in a certain direction. For example, the speed of a car driving north on a highway or the speed of a rocket after launch.
Here,
the vertical component of Jeff's velocity,
=√7²-5.1²
=4.8 m/s
The vertical component of Jeff's velocity is 4.8 m/s when Jeff ran up a hill at 7.0 m/s, the horizontal component of his velocity vector was 5.1 m/s.
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A football punter wants to kick the ball so that it is in the air for 3.6 s and lands 50 m from where it was kicked. Assume that the ball leaves 1.0 m above the ground.
At what angle should the ball be kicked?
With what initial speed should the ball be kicked?
Answer:
H = Vy t - 1/2 g t^2 height after time t
Vy t = H + 1/2 g t^2
Vy = H / t + 1/2 g t
Vy = -1 / 3.6 + 4.9 * 3.6 = 17.4 m/s initial vertical speed
Vx = 50 / 3.6 = 13.9 m/s
tan θ = 17.4 / 13.9 = 1.25 θ = 51.4 deg
Ball should be kicked at 51.4 deg
V = (17.4^2 + 13.9^2)^1/2 = 22.3 m/s initial speed
As a check use range formula
R = 22.3^2 sin 102.8 / 9.80 = 49.5 m
That is slightly less than 50m as it should be since its height would be zero after being given the initial speed
Which of the following statements about this experiment is FALSE?
You may assume the collision between the bob and the box is completely inelastic.
Before each trial one should reshape the bab into something like a ball.
The initial position for the box should be just touching the pendulum bob when it is hanging straight down.
To make the box move, the pendulum bob should hit close to the bottom of the box during the collision.
The statement "before each trial one should reshape the bob into something like a ball" is false regarding the experiment.
If we assume the collision between the bob and the box is completely inelastic, then shape of the bob does not play any role in the time period of the plumb bob or the collision impact of the bob on the box. However the second statement which says that the initial position for the box should be just touching the pendulum bob, is true. This is because then initial position of the bob will become the mean position and we know at the mean position the kinetic energy of the bob is maximum.
For the third statement, the pendulum bob should hit close to the bottom of the box during the collision to make the box move, is also true. This is because the bottom surface experiences the maximum friction force, which can be reduced at maximum amount if bob impact closer to the bottom.
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A wave generated on a slinky has a frequency of 5 Hz and a wavelength of 0,75 m. Calculate its speed
Answer:
The speed of a wave is given by the equation:
Speed = Frequency x Wavelength
Given that the frequency of the wave is 5 Hz and the wavelength is 0.75 m, we can substitute these values into the equation:
Speed = 5 Hz x 0.75 m
Speed = 3.75 m/s
Therefore, the speed of the wave generated on the slinky is 3.75 m/s.
It's important to note that the speed of a wave depends on the properties of the medium through which it travels and not on the properties of the source of the wave.
Answer:
The speed is 3.75
Explanation:
The relationship between wavelength and frequency is described by this simple equation:
λ = v/f
wave length (T) = 0.75m
frequency (f) = 5Hz
0.75 = v / 5
0.75*5 = v
v=3.75
if the above bowling ball rolls into a pillow and stops in 0.5s. calculate the average force exerted on the pillow
The average force exerted on the pillow -32 N.
Force is an external influence that can change the velocity or motion of an object.
It can also be defined as the product of mass and acceleration.Mathematically, force F = m*aThe momentum of an object is the product of its mass and velocity.
The formula for momentum is: momentum = mass x velocitySo, in the case of an 8-kg bowling ball rolling at 2 m/s, the momentum would be: momentum
= 8 kg x 2 m/s
= 16 kg m/s
To calculate the average force that the bowling ball exerts on the pillow, we can use the equation:
force = change in momentum / change in time
The change in momentum is equal to the final momentum minus the initial momentum.
Since the bowling ball is rolling at 2 m/s and stops in 0.5s,
we can assume that its final momentum is 0 (since it stops moving) and the initial momentum is 16 kg m/s.
change in momentum = final momentum - initial momentum
= 0 - 16 kg m/s
= -16 kg m/s
change in time = 0.5s
So,
force = -16 kg m/s / 0.5 s
= -32 N (Newton)
Therefore the average force exerted on the pillow is -32 N.
the question is incomplete, the complete question is "What is the momentum of an 8-kg bowling ball rolling at 2 m/s? If the bowling ball rolls into a pillow and stops in 0.5 s, calculate the average force it exerts on the pillow".
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A turntable rotates with a constant 2. 25 rad/s^2 angular acceleration. After 4. 00 s it has rotated through an angle of 60. 0 rad. What was the angular velocity of the wheel at the beginning of the 4. 00-s interval?.
The angular velocity of the wheel at the beginning of the 4 s interval is calculated as 3 rad/s.
Given that,
Angular speed of turntable = 2.25 rad/s²
Time of motion, t = 4.0 s
Angular displacement, θ = 60 rad
The wheel's angular velocity at the start of the 4 second period is computed as follows,
θ = ωi t + 1/2 α t²
where, ωi is initial angular velocity
30 = ωi (4) + 1/2 × 2.25 ×4²
4 ωi + 18 = 30
4 ωi = 12
ωi = 3 rad/s
Thus, the angular velocity of the wheel at the beginning of the 4 s time is 3 rad/s.
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A crane and box are both initially at rest. At time to the crane begins to drive forward at a constant speed of 5 m/s, while also lifting the box with an upward acceleration of 1 m/s. The box does not swing while being lifted by the crane the scenario described above. Represent each force by a distint arrow starting on, and pointing away from the dot.
Arrow starting from the dot, pointing away from the dot in the direction of the crane's motion. Force of the crane lifting the box: Arrow starting from the dot, pointing away from the dot in the upward direction.
What is the Crane?
The Crane is a machine used in construction and engineering to lift and move heavy objects. It is usually composed of a tall, rotating arm with a hoist at the end, operated by an operator in a cab. Cranes come in a variety of sizes, from small models that can lift a few hundred pounds to huge machines that can move thousands of tons at once. Most cranes are attached to a fixed structure, such as a building or pier. Cranes can also be mounted on vehicles, such as trucks, to move around a worksite. Cranes are essential tools in the construction industry, as they allow workers to move large objects with ease and speed. Cranes are also used in a variety of other industries, such as manufacturing, shipbuilding, and material handling.
This force is the result of the crane pushing the box forward at a constant speed of 5 m/s.
This force is the result of the crane lifting the box with an upward acceleration of 1 m/s.
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how do you describe the speed at which you can sew
We can describe the sew speed as, calculate the measured stitches per unit and divide by reduction ratio.
Sewing machines are invented during the first Industrial Revolution to decrease the amount of manual sewing work performed in clothing companies. The speed is an important issue for sewing. All machines are not same, all operators are not equal experienced in production, quality expectation, stitch type, etc.
Since the invention, the efficiency and productivity of the clothing industry has been greatly improved. Now various types of sewing machines are used for sewing depending on different stitches. Most of them are automatic and run by motor.
When stitch is formed, three things come into factor such as needle thread, fabric types and bobbin thread or looper thread (Webster et al., 1998). Seam strength completely depends on quality of fabric and sewing machine.
Sewing thread needs to choose according to the properties of fabric (Chowdhary et al., 2006). Since seam strength is dependent on the thread strength, a reduction in thread strength during sewing will lead to lower seam strength.
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particles q1=+18.1uC, q2=-11.2uC, and q3=+5.67uC are in a line. particles q1 and q2 are separated by 0.280m and particles q2 and q3 are separated 0.350m. what is the net force on particle q2?
The net electric force on particle q2 is 27.81 N.
What is the net force on the particle q2?The net force on the particle q2 is calculated by applying Coulomb's law of electrostatic force.
The force on particle q1 due to particle q2 is calculated as;
F ( 12 ) = kq₁q₂/r²
where;
q1 is the charge of particle 1q2 is the charge of particle 2r is the distance between particle 1 and 2k is Coulomb's constantF ( 12 ) = ( 9 x 10⁹ x 18 x 10⁻⁶ x 11.2 x 10⁻⁶ ) / ( 0.28² )
F ( 12 ) = 23.14 N
The force on particle q3 due to particle q2 is calculated as;
F (23) = kq₃q₂/r²
F (23) = (9 x 10⁹ x 5.67 x 10⁻⁶ x 11.2 x 10⁻⁶)/(0.35²)
F (23) = 4.67 N
The net electric force on particle q2 is calculated as follows;
F (net) = 23.14 N + 4.67 N
F (net) = 27.81 N
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Starts at rest at 3m to the right after 10s he is traveling 2m/s to the left where does he end up
According to the given statement He ends up 100m to the left of its starting point.
What is acceleration and give explanation for above questions?Acceleration is the rate of change of velocity over time, or the change in speed and direction of an object. It can be measured in meters per second squared (m/s²).
He starts at rest 3 meters to the right, and after 10 seconds it is traveling 2 meters per second to the left.
To find out where he ends up, we can use the equation for distance: distance = initial velocity x time + (1/2) x acceleration x time^2.
Since the he starts at rest, its initial velocity is 0 m/s. he is moving to the left, so its acceleration is -2 m/s^2 (negative because he is moving in the opposite direction).
Therefore, the distance he travels :
-distance = 0 x 10s + (1/2) x (-2 m/s^2) x (10s)^2
-distance = -100m
So he ends up 100m to the left of its starting point.
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1.An electric pencil sharpener is has a current of 0.05A.The voltage
is 6v. What is the resistance?
An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rev/min in 4. 00 s. How many more seconds are required for the fan to come to rest if the angular acceleration remains constant at the value calculated in part (a)?.
Time of 6.667 seconds is required for the fan to come to rest at constant angular acceleration.
What is angular velocity?Rotational velocity, sometimes referred to as angular frequency vector, is a pseudovector that depicts how quickly an object's angular position or orientation varies over time and is termed as angular velocity.
To find:
now we know that[tex]w= 0\frac{rev}{s}[/tex] ,[tex]w0\frac{25}{3 \ }\frac{rev}{s}[/tex] and α = [tex]\frac{5}{4}\frac{rev}{8^{2} }[/tex]
t= 0-25/3 whole upon -5/4
t= 6.667s
Hence, time of 6.667 seconds is required for the fan to come to rest at constant angular acceleration.
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The complete question is :
An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rev/min in 4.00 s.
(a) Find the angular acceleration in rev/s^2 and the number of revolutions made by the motor in the 4.00-s interval.
(b) How many more seconds are required for the fan to come to rest if the angular acceleration remains constant at the value calculated in part (a)?
Sara has a fire in the fireplace to warm her 20°C apartment. She realizes that she has left the iron poker in the fire. How hot is the fire if the 0.60 m poker lengthens 0.30 cm? (αiron = 12 x 10-6°C-1)
The variation of temperature 437°C ,if Sara fire in the fireplace to warm her 20°C apartment.
What temperature can I refuse to work in?
Although there's no legally defined maximum or minimum temperature for working, health and safety guidance is that a reasonable temperature should usually be at least 16°C. If much of the work involves a lot of physical effort, it's 13°C.
What temperature is too hot for humans?
People often point to a study published in 2010 that estimated that a wet-bulb temperature of 35 C – equal to 95 F at 100 percent humidity, or 115 F at 50 percent humidity – would be the upper limit of safety, beyond which the human body can no longer cool itself by evaporating sweat from the surface of the body
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A force of 2. 2x10^4 N needed to lift a 2270 kg tone block. Uing the equation work=force x ditance, determine how much work i required to lift uch a blocki of ditand of 2 m
The work required to lift the block with a force of 2.2 · 10⁴ N at the distance/displacement of 2 meters is equal to 44,000 joules.
Force, according to Newton's law of motion, is equal to mass times acceleration. Newton is the standard unit of force. For an object to accelerate, there must be a net force acting on it.
When a force acts on an object and makes it move, the object is said to transfer energy. This is called work in physics. Mathematically speaking, work W is equal to force F times distance x (W = F · x). Joule is the standard unit of work.
Suppose that F equals 2.2 · 10⁴ newtons and x equals 2 meters. The work done is calculated as follows:
W = F · x
W = 2.2 · 10⁴ · 2
W = 44,000 joules
We have confirmed that the work needed to lift the block is equal to 44,000 joules.
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Why energy management control system is required in HEV?
To reduce fuel consumption while maintaining vehicle performance, driver comfort, and component constraints energy management control system is required in HEV.
A supervisory algorithm, also known as an energy management strategy, is necessary for hybrid vehicles to control the different parts of the drivetrain. Usually, when designing an energy management strategy, we face two challenges.
First off, the nonconvex cost function produced by the components' nonlinear behavior makes the employment of optimization techniques more challenging. There are several methods mentioned for dealing with nonconvexity.
Second, it is unknown what the future power and velocity trajectories will be. Using historical or projected vehicle velocity and road grade trajectories to forecast future trajectories could aid in finding a solution that is close to ideal.
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Scenario
Two different boxes are pushed from rest on a frictionless surface for a time t, with differing forces. Using Representations
PART A: Identify the box system by circling the objects inside the system with a dotted circle.
PARTB: The dots below represent the two boxes. Draw free-body diagrams showing and labeling the forces (not components) exerted on each bex Draw the relative lengths of all vectors to reflect the relative magnitudes of all the forces. Identify the external forces.
ART C: Sketch a graph of the net external force vs. t for each box on the same axis by using two different
colors and providing a key.
Quantitative Analysis
PART D: Using the equation for the area of a rectangle, A= bh, write two equations, one with words and one
with units, for the area of the rectangle between the net external force vs. time line and the x-axis on the
graph created in Part C.
(Hint: Check units!)
PART E: Re-represent the data above by creating a momentum diagram for each box on the same set axes
by using two different colors and providing a key. (A momentum diagram represents the momentum
of an object or system by showing the mass of the object as the width of bar on the chart, and the
velocity of the object as the height of the bar
PART F: Is the impulse given to the first bex while speeding up greater than, less than, or the same as the
impulse given to the second box while speeding up? Justify your ranking
Representations of Each Part are:
PART A:The objects inside the system are the two boxes, they should be circled with a dotted circle.
PART B:Free-body diagrams showing and labeling the forces (not components) exerted on each box. Draw the relative lengths of all vectors to reflect the relative magnitudes of all the forces and identify the external forces.
PART C:Sketch a graph of the net external force vs. t for each box on the same axis will using two different colors and providing a key.
PART D:Using the equation for the area of a rectangle, A= bh, the area of the rectangle between the net external force vs. time line and the x-axis on the graph created in Part C can be written as:
With words: The area of the rectangle is equal to the base times the height.
With units: A = (Fnet)(t) N × s
PART E:Re-represent the data above by creating a momentum diagram for each box on the same set axes by using two different colors and providing a key. (A momentum diagram represents the momentum of an object or system by showing the mass of the object as the width of bar on the chart, and the velocity of the object as the height of the bar.
PART F:This part whether the impulse given to the first box while it is speeding up is greater than, less than, or the same as the impulse given to the second box while it is speeding up. Impulse is the product of force and time and it is the change in momentum.
THE RANKING OF FORCES AND IMPULSETo determine the ranking of the impulse given to the two boxes, we would need to know the specific forces applied to each box and the duration of time over which those forces were applied. The impulse experienced by an object is the product of the force applied and the time over which it was applied. Without this information, it is not possible to determine whether the impulse given to the first box was greater than, less than, or the same as the impulse given to the second box.
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The primary coil in a transformer has 160 turns and is opperating at 151 V. If the secondary coil has 4,529 turns what will be the voltage in the secondary
coil?
Where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of loops in the primary coil, and Ns is the number of loops in the secondary coil.
How do you find the voltage in a primary coil?The ratio of the primary and secondary voltages in a transformer is the same as the proportion of loops in the primary and secondary coils. Where Np is the number of loops in the primary coil, Vp is the primary voltage, Vs is the secondary voltage, and Vp and Ns are the number of loops in the secondary coil. We specifically know that the ratio of the potential difference V across these coils to the number of turns N in the input and output coils is the same. The equation is V input divided by V output, where V input is equivalent to N input divided by N output. You may calculate a ratio by taking the larger number of turns and dividing it by the lower number of turns.To learn more about primary coil refer to:
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2. A ball has a weight of 15 N. If a cannon can shoot with a force of 100 N, what will be the net force
on the ball?
Answer: 115 N
Explanation:
In this case, the ball has a weight of 15 N (force due to gravity) acting on it and the cannon is shooting it with a force of 100 N.
To find the net force on the ball, we add the forces acting on it.
Net force = force due to gravity + force due to the cannon
Net force = 15 N + 100 N
Net force = 115 N
So, the net force on the ball will be 115 N. ✅
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What types of cooling systems do EVs and HEVs have?
Electric Vehicles (EVs) and Hybrid Electric Vehicles (HEVs) use a range of different cooling systems to ensure that their batteries, motors, and other components are kept at optimal temperatures.
Generally, EVs and HEVs use air-cooling systems that draw air over the components to keep them from overheating. Some EVs and HEVs also have liquid-cooling systems, which use coolant to more efficiently dissipate heat away from the components.
Additionally, some EVs and HEVs use a combination of both air and liquid cooling systems for maximum efficiency.
Electric Vehicles (EVs) and Hybrid Electric Vehicles (HEVs) have different cooling systems to keep their batteries and motors running optimally.
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if the speed of an object increases from 0 to 40 meters per second in 20 seconds how much distance has it covered
According to the given statement the object has covered 400 meters distance has it covered.
What is object and image in physics?The point where light rays from an object meet, or appear to meet after reflection or refraction, is sometimes referred to as the image. In this concept, a "object" might be anything that light rays are emanating from.
To find the distance covered by an object as it increases its speed from 0 to 40 meters per second in 20 seconds, we can use the formula:
Distance = (Initial speed + Final speed) x Time / 2
In this instance, the time is 20 seconds, the beginning speed is 0 m/s, and the ultimate speed is 40 m/s. With these values entered into the formula, we obtain:
Distance = (0 + 40) x 20 / 2 = 800/2 = 400 meters
So the object has covered 400 meters.
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