Answer:
194.81 revolutions
Explanation:
Given that,
Initial angular velocity, [tex]\omega_i=3700\ rpm[/tex]
Final angular velocity, [tex]\omega_f=1800\ rpm[/tex]
Time, t = 4.25 seconds
We need to find the number of revolutions occur during this time.
3700 rpm = 387.46 rad/s
1800 rpm = 188.49 rad/s
Let [tex]\alpha[/tex] is angular acceleration. Using first equation to find it.
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{188.49 -387.463 }{4.25}\\\\\alpha =-46.81\ rad/s^2[/tex]
Now let us suppose that the number of revolutions are [tex]\theta[/tex].
[tex]\theta=\dfrac{\omega_f^2+\omega_i^2}{2\alpha}\\\\=\dfrac{188.49 ^2-387.463 ^2}{2\times -46.81}\\\\=1224.087\ rad[/tex]
or
[tex]\theta=\dfrac{1224.087}{2\pi}\\\\=194.81\ rev[/tex]
Hence, there are 194.81 revolutions.
A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volume of the block. Then, use that answer to determine the density of the block. *
Answer:
6g/cm³
Explanation:
Density is the mass per unit volume of any substance. To solve this problem:
Density = [tex]\frac{mass}{volume}[/tex]
Since mass = 600g
Let us find the volume;
Volume = length x width x height
Volume = 25cm x 2cm x 2cm = 100cm³
Therefore;
Density = [tex]\frac{600}{100}[/tex] = 6g/cm³
if an object is projected upward with an initial velocity of 80 ft per second, what is t at maximum height
Answer:
The time at maximum height is 2.49 s.
Explanation:
The time (t) at the maximum height can be found using the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Where:
[tex]v_{f}[/tex]: is the final velocity = 0 (at the maximum height)
[tex]v_{0}[/tex]: is the initial velocity = 80 ft/s
g: is the gravity = 9.81 m/s²
Hence, the time is:
[tex]t = \frac{v_{0}}{g} = \frac{80 \frac{ft}{s}*\frac{1 m}{3.281 ft}}{9.81 m/s^{2}} = 2.49 s[/tex]
Therefore, the time at maximum height is 2.49 s.
I hope it helps you!
2. Use the data table below to respond to the
question:
4 seconds
At seconds
Speed (meters per second Im/s]
At 1 second At 2 seconds At 3 seconds
2
+
6
At 4 seconds
8
Car A
0
B
2
Car B
2
2
2
2
4
Car C
3
2
1
0
0
Car D
5
5
5
5
5
5
ant
Which car had the greatest acceleration?
A. A
B. B
C. C С
D. D
Answer:
car d
Explanation:
5555555555555555555
Is this statement true or false?
Tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud.
Answer:
true true true true true
Psychophysic is the study of
Answer:
Psychophysics is the subfield of psychology devoted to the study of physical stimuli and their interaction with sensory systems.
Explanation:
Hope this helps <3
Help me with this, I'm being timed.
Answer:
I guess C
Explanation:
cause you can just try with hot water and ice cubes you know.
and we all know that ice will melt and the hot tea will get cold.
Answer:
D option
Explanation:
heat move from hot source to cold sink untill equilibrium reached
What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water
This question is incomplete, the complete question is;
Styrofoam has a density of 32kg/m³.
What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water
Answer: the required maximum mass is 63.3459 kg
Explanation:
Given that;
diameter d = 50 cm = 0.5 m
radius r = 0.5 / 2 = 0.25 m
Styrofoam density = 32kg/m³
Volume of sphere V = 4/3 πr³.
we substitute
V = 4/3 π(0.25)³
V = 0.06544 m³
Mass of sphere M = Volume × Density
we substitute
Mass of sphere M = 0.06544 m³ × 32kg/m³
Mass of Sphere M = 2.09408 kg
Mass of the water it displace will be;
volume × density
we know that density of water = 1000 kg/m³
so
Mass of the water it displace = 0.06544 m³ × 1000kg/m³
= 65.44 kg
Now the difference between mass of water and mass of the Styrofoam will be the amount of mass that the sphere can support
so
65.44 kg - 2.09408 kg = 63.3459 kg
Therefore, the required maximum mass is 63.3459 kg
A planet of mass M and radius R has no atmosphere. The escape velocity at its surface is ve. An object of mass m is at rest a distance r from the center of the planet, where r>>R. The particle falls to the surface of the planet. The total mechanical energy of the particle at the surface of the planet is closest to
The total mechanical energy of the particle of mass m at the surface of the planet of mass M when the distance is R (planet's radius) is [tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex].
When the particle is at rest at a distance "r" from the planet's center, it only has gravitational potential energy. As the particle falls to the planet's surface, some initial gravitational potential energy converts to kinetic energy.
The total mechanical energy of the particle at the planet's surface is equal to the sum of the gravitational potential energy and kinetic energy, so:
[tex] E = P + K [/tex]
[tex] E = maR + \frac{1}{2}mv_{e}^{2} [/tex] (1)
Where:
m: is the mass of the object
a: is the acceleration due to gravity on the surface of the planet
R: is the radius of the planet
[tex]v_{e}[/tex]: is the escape velocity
The acceleration due to gravity is given by:
[tex] a = \frac{GM}{R^{2}} [/tex] (2)
By entering equation (2) into (1), we have:
[tex] E =mR\frac{GM}{R^{2}} + \frac{1}{2}mv_{e}^{2} [/tex]
[tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex]
Therefore, the total mechanical energy of the particle is [tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex]
Learn more here:
https://brainly.com/question/9322440?referrer=searchResultshttps://brainly.com/question/14127859?referrer=searchResultsI hope it helps you!
If a 15kg mass weighs 372 N on Jupiter, what is Jupiter's gravitational acceleration?
Answer:
Jupiter's gravitational acceleration is 24.8 m/s^2
Explanation:
Recall that the weight under the influence of a gravitational acceleration G is defined as:
Weight = m * G
Then, in our case we have
372 N = 15 kg * G
G = 372/15 m/s^2
G = 24.8 m/s^2
A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of friction between the box and the floor is 0.795. Determine the mass of the box.
Answer:
the mass of the box is 51.98 kg.
Explanation:
Given;
applied horizontal force, F = 450 N
coefficient of friction, μ = 0.795
constant velocity, v = 1.2 m/s
At constant velocity, the acceleration of the object is zero and the net force will be zero.
[tex]F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg[/tex]
Therefore, the mass of the box is 51.98 kg.
Which title goes with this list: Amendments Articles Preamble?
A. Florida and County Government
B. Florida and U.S. Government
C. City and County Government
D. City and U.S. Government
How to intercept a slope
Answer:
The slope intercept form is probably the most frequently used way to express equation of a line. To be able to use slope intercept form, all that you need to be able to do is 1) find the slope of a line and 2) find the y-intercept of a line.
Explanation:
Answer:You plot the numbers and divide
Explanation:
what are three ways the electricity we use can be generated
A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of 0.060 m>s. After 1.5 minutes the finch tires of
Complete Question:
A finch rides on the back of a Galapagos tortoise, which walks
at the stately pace of 0.060 m/s. After 1.5 minutes the finch tires of
the tortoise’s slow pace, and takes flight in the same direction for
another 1.5 minutes at 11 m/s.
What was the average speed of the finch for this 3.0-minute interval?
Answer:
[tex]Speed = 5.53 m/s[/tex]
Explanation:
Distance is calculated as:
[tex]Distance = Speed * Time[/tex]
First, we calculate the distance for the first 1.5 minutes
For the first 1.5 minutes, we have:
[tex]Speed = 0.060m/s[/tex]
[tex]Time = 1.5\ mins[/tex]
[tex]D_2= 0.060m/s * 1.5\ mins[/tex]
Convert 1.5 mins to seconds
[tex]D_2= 0.060m/s * 1.5 * 60s[/tex]
[tex]D_2= 5.4m[/tex]
Next, we calculate the distance for the next 1.5 minutes
[tex]Speed = 11m/s[/tex]
[tex]Time = 1.5\ mins[/tex]
[tex]D_2= 11m/s * 1.5\ mins[/tex]
Convert 1.5 mins to seconds
[tex]D_2 = 11m/s * 1.5 * 60s[/tex]
[tex]D_2= 990m[/tex]
Total distance is:
[tex]Distance = 990m + 5.4m[/tex]
[tex]Distance = 995.4m[/tex]
The average speed for the 3.0 minute interval is:
[tex]Speed = \frac{Distance}{Time}[/tex]
[tex]Speed = \frac{995.4\ m}{3.0\ mins}[/tex]
Convert 3.0 minutes to seconds
[tex]Speed = \frac{995.4\ m}{3.0 * 60 secs}[/tex]
[tex]Speed = \frac{995.4\ m}{180 secs}[/tex]
[tex]Speed = 5.53 m/s[/tex]
PLEASE PLEASE HELP!!!!
A 200-kg car is moving at 50 mis. What is the kinetic energy of the car? show
Answer:
Ekin = 250000 [J]
Explanation:
The kinetic energy of a body or object can be calculated based on the mass and the speed with which it moves. This energy can be easily calculated by means of the following equation.
[tex]E_{kin}=\frac{1}{2} *m*v^{2}[/tex]
where:
m = mass = 200 [kg]
v = velocity = 50 [m/s]
Now replacing:
[tex]E_{kin}=\frac{1}{2} *200*(50)^{2}\\E_{kin}=250000[J][/tex]
Does Newton’s 1st Law of Motion apply to sports
Answer: Yes indeed it does.
Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.
What type of wavelength can we feel as heat and it is used to change the television channel with a remote?
microwaves
ultraviolet waves
X-rays
infrared waves
Answer:
d)infrared waves
Explanation:
A remote control uses light waves just beyond the visible spectrum of light—infrared light waves—to change channels on your TV. This region of the spectrum is divided into near-, mid-, and far-infrared.
The human nervous system can propagate nerve impulses at about 102 m>s. Estimate the time it takes for a nerve impulse to travel 2 m from your toes to your brain.
Answer:
t = 0.196 s
Explanation:
The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement
v = x / t
t = x / v
calculate
t = 2/102
t = 0.196 s
Brainliest brainliest help help help mememememememme
Answer:
????????????????????,
Explanation:
I need points sorry
Answer:
honestly this was so long ago can i get brainliest i need 2 more until i am at expert level
Explanation:
Gizmo Warm-up: Lifting a piano A pulley is a simple machine that is used to lift heavy objects. A pulley is a wheel with a groove for a rope. Pulling down on one end of the rope causes the other end to pull up. In the Object to lift menu choose Piano. What is the weight of the piano
Answer:
bruuuuuuuuh
Explanation:
id
explain how electrically neutral objects can become electrically charged even though charge cannot be created or destroyed
Answer:
The object gains or loses electrons to become charged. Both are a movement of electrons from the negative to the positive charge. A circuit has a continuous current provided by a voltage source.
Explanation:
Which has more volume a liter of a quart?
1. A quart
2. Both are the same
3. Neither describes volume
4. A liter
Curious George is whirling a 2.0 kg bunch of bananas on a smooth floor in a circular path having a radius of 0.50 m. What force must he apply to keep the motion constant so that the bananas complete one revolution every 4.0 seconds
Answer:
The force will be [tex]F_{c}=2.47 N[/tex]
Explanation:
Let's use the centripetal force equation.
[tex]F_{c}=m\omega ^{2}R[/tex]
Where:
m is the mass of the bunch of bananas
ω is the angular speed
R is the radius
Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.
[tex]\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}[/tex]
FInally, the force will be:
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.47 N[/tex]
I hope it helps you!
If a dog that has moved has a displacement of zero, it means that the dog's initial position and final position are the same. Is it T or F
Answer:
true
Explanation:
the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same
The period of a satellite circling planet Nutron is observed to be 84 s when it is in a circular orbit with a radius of 8.0 x 106 m. What is the mass of planet Nutron
Answer:
4.3 * 10^28 kg
Explanation:
Given:
Period, T = 84s
Radius of satellite orbit, r = 8*10^6
Using the relation :
M = 4π²r³ / GT²
Where G = Gravitational constant, 6.67 * 10^-11
M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2
M = (20218.191872 * 10^18) / 47063.52 * 10^-11
M = 0.4295937 * 10^18 - (-11)
M = 0.4295937 * 10^29
M = 4.295937 * 10^28 kg
M = 4.3 * 10^28 kg
Mass of planet Nutron = 4.3 * 10^28 kg
a student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the ground. the object takes 0.5 seconds to complete one rotation.
mass= 50 kg. length of the rope = 1.2 m
what is the objects speed of rotation?
what is the objects centripetal acceleration?
what tension force is required to maintain this motion?
The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.
Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2π (1.2 m) = 2.4π m ≈ 7.5 m, so that
2 rot/s = (2 rot/s) • (2.4π m/rot) = 4.8π m/s ≈ 15 m/s
thus giving it a centripetal acceleration of
a = (4.8π m/s)² / (1.2 m) ≈ 190 m/s².
Then the tension in the rope is
T = (50 kg) a ≈ 9500 N.
Which term is applied to an object through which light passes?
A. Absorbent
B. Opaque
C. Reflective
D. Transparent
Answer:
D
Explanation:
transparent_objects that allows light to pass through and can you see through them
What is the difference between a graph of linear motion and a graph of harmonic motion?
newtons first law 1 to 5.
What is each of the net force for all of the 5 questions?
Answer:
1. 65 N.
2. 160 N.
3. 0 N.
4. 210 N.
5. 90 N.
Explanation:
1. Determination of the net force.
Force applied to the right (Fᵣ) = 80 N
Force applied to the left (Fₗ) = 145 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 145 – 80
Fₙ = 65 N
Thus, the net force is 65 N
2. Determination of the net force.
Force 1 applied to the left (F₁) = 35 N
Force 2 applied to the left (F₂) = 125 N
Net force (Fₙ) =?
Fₙ = F₁ + F₂
Fₙ = 35 + 125
Fₙ = 160 N
Thus, the net force is 160 N.
3. Determination of the net force.
Force applied to the right (Fᵣ) = 75 N
Force applied to the left (Fₗ) = 75 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 75 – 75
Fₙ = 0
Thus, the net force is 0 N
4. Determination of the net force.
Force 1 applied to the right (F₁) = 150 N
Force 2 applied to the right (F₂) = 60 N
Net force (Fₙ) =?
Fₙ = F₁ + F₂
Fₙ = 150 + 60
Fₙ = 210 N
Thus, the net force is 210 N.
5. Determination of the net force.
Force applied to the right (Fᵣ) = 115 N
Force applied to the left (Fₗ) = 25 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 115 – 25
Fₙ = 90 N
Thus, the net force is 90 N