A triangle has area 100 square inches. It's dilated by a factor of k= 0.25.
Mai says, "The dilated triangle's area is 25 square inches."
Lin says, "The dilated triangle's area is 6.25 square inches."

1. For each student, decide whether you agree with their statement. If you
agree, explain why. If you disagree, explain what the student may have done to arrive at their answer.

2. Calculate the area of the image if the original triangle is dilated by each of these scale factors:
a. K = 9
b. K = 3/4

The slope in the equation b = 0.29h + 1.35 is the measure of the rate at which the bike frame size changes with the height of the rider.

The slope in the equation b = 0.29h + 1.35 refers to the coefficient of the variable h, which represents the height of the rider. The slope is the measure of the rate at which the bike frame size changes with the height of the rider.

In this equation, the slope is 0.29, which means that for every inch increase in the rider's height, the bike frame size increases by 0.29 inches. The slope is a crucial component of the equation as it determines the proportionality of the two variables.

Moreover, the slope is essential in analyzing the relationship between the rider's height and the bike frame size.

It plays a vital role in determining the appropriate size of the BMX bike frame and analyzing the relationship between the two variables.

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Complete Question:

Purchasing the correctly sized BMX bike is based on the height of the rider. In order to fit a customer, the salesman can use the equation b 0.29h +1.35 where b is the size of the BMX bike frame in inches and h is the height of the rider in inches.

Which sentence explains the slope in the equation?

The better understanding of the data, making it easier to draw conclusions and make decisions based on the data.

In statistics, the spread of the data is used to describe the variability or deviation of a set of data. The location of the data is used to determine the center of the data, and the shape of the data describes the distribution of the data. When it comes to the variable number of care types sp unable to get (acv nocarsum), the data should be analyzed using the appropriate graph(s) and descriptive statistics to determine its shape, location, and spread.
Descriptive statistics:
In descriptive statistics, measures such as mean, mode, median, standard deviation, variance, and range are used to analyze data. These statistics provide a summary of the data in the form of numerical values, making it easy to identify patterns, outliers, and other characteristics of the data.
Graphs:
Graphs are also used in statistical analysis to visually represent the data. There are different types of graphs that can be used, depending on the type of data being analyzed. Commonly used graphs in statistical analysis include histograms, scatterplots, boxplots, and line graphs.
To describe the shape, location, and spread of the data for the number of care types sp unable to get (acv nocarsum) variable, the following steps should be followed:

Step 1: Collect the data.
The first step is to collect the data on the number of care types sp unable to get (acv nocarsum) variable. This data can be obtained from various sources such as surveys, questionnaires, or observational studies.

Step 2: Determine the center of the data.
The center of the data can be determined using measures such as mean, mode, or median. The mean is the average of the data, while the median is the middle value of the data when arranged in order of magnitude. The mode is the value that appears most frequently in the data.

Step 3: Determine the variability of the data.
The variability of the data can be determined using measures such as variance or standard deviation. The variance is the average of the squared differences between each data point and the mean, while the standard deviation is the square root of the variance.

Step 4: Determine the shape of the data.
The shape of the data can be determined using graphs such as histograms, boxplots, or line graphs. Histograms show the distribution of the data, while boxplots show the quartiles and outliers of the data.

Step 5: Interpret the results.
Once the data has been analyzed using the appropriate graph(s) and descriptive statistics, the results should be interpreted to describe the shape, location, and spread of the data for the number of care types sp unable to get (acv nocarsum) variable. This will provide a better understanding of the data, making it easier to draw conclusions and make decisions based on the data.

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Answer:

15

Step-by-step explanation:

Answer can only be found through estimation.

This means you have to do:

[tex]\frac{50*3}{\sqrt{100} }[/tex]

This will get you 15.

Rs 5.25 can be expressed without decimals as Rs 525/100 or as 5 1/4 (or 5 ¼) using mixed numbers. Both methods allow us to represent the value of Rs 5.25 accurately without using decimal notation.

To express Rs 5.25 without using decimals, we need to convert it into a fraction with a numerator and a denominator. One way to do this is by multiplying both the numerator and the denominator by 100 to eliminate the decimal point.

So, Rs 5.25 can be written as Rs 525/100. This is also known as a fraction in its simplest form, as both the numerator and denominator have no common factors other than 1.

Another way to express Rs 5.25 without decimals is to use mixed numbers. A mixed number is a whole number combined with a fraction. To convert a decimal to a mixed number, we need to find the whole number part and the fraction part.

To find the whole number part, we can simply drop the decimal point and write the digits to the left of it. In this case, the whole number part is 5.

To find the fraction part, we need to subtract the whole number part from the original number and simplify the fraction. In this case, Rs 5.25 can be written as 5 and 1/4 (or 5 ¼), where the fraction part is 1/4.

In conclusion, Rs 5.25 can be expressed without decimals as Rs 525/100 or as 5 1/4 (or 5 ¼) using mixed numbers. Both methods allow us to represent the value of Rs 5.25 accurately without using decimal notation.

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The first 4 terms of the sequence represented by the expression 3n + 5

is 8, 11, 14 and 17.

Sequence:

In mathematics, an array is an enumerated collection of objects in which repetition is allowed and in case order. Like a collection, it contains members (also called elements or items). The number of elements (possibly infinite) is called the length of the array. Unlike sets, the same element can appear multiple times at different positions in the sequence, and unlike sets, order matters. Formally, a sequence can be defined in terms of the natural numbers (positions of elements in the sequence) and the elements at each position. The concept of series can be generalized as a family of indices, defined in terms of any set of indices.

According to the Question:

Given, aₙ = (3n+5).

First four terms can be obtained by putting n=1,2,3,4

a 1=(3×1+5) = 8

a 2 =(3×2+5) = 11

a 3 =(3×3+5) = 14

a 4 =(3×4+5) = 17

First 4 terms in the sequence are 8, 11, 14, 17.

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The probability that exactly 10 out of 23 cars will not have engine failure is 0.007638.

Step-by-step explanation: First, calculate the probability of an engine failing in five years with no routine maintenance, which is 27.5%. This can be written as a decimal, 0.275.Next, calculate the probability of an engine not failing in five years with routine maintenance. This probability is 100%-27.5% = 72.5%, written as a decimal 0.725.

Now, using the Binomial Distribution formula (nCr), calculate the probability of exactly 10 engines not failing out of 23 cars, where n = 23, r = 10 and p = 0.725. The equation would be [tex](23C10)*(0.725^{10})*(0.275^{13}) = 0.0076379904[/tex]

Finally, round the result to 6 decimal places, giving an answer of 0.007638.

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The function that satisfies the hypotheses of the Extreme Value Theorem on the given interval is given by

B. g(x)=6x^2+3 on 0≤x≤4

D. f(x) = (e^x)/x for 2 ≤ x ≤ 16.

Step 1: State the Extreme Value Theorem

The Extreme Value Theorem states that if a function is continuous on a closed interval [a,b], then the function must have a maximum and a minimum on the interval.

Step 2: Check for continuity and closed interval for each function

A. f(x) = 1/x on −10 ≤ x ≤ 10

The function f(x) = 1/x is continuous on the interval (-10, 0) and (0, 10).

However, since the interval given is [−10, 10], we see that the function is not continuous over the closed interval.

Hence the function does not satisfy the hypotheses of the Extreme Value Theorem.

B. g(x) = 6x^2+3 on 0 ≤ x ≤ 4

The function g(x) is continuous on the interval [0, 4].

Therefore, this function satisfies the hypotheses of the Extreme Value Theorem on the given interval.

C. k(x) = {3x^2+9 for 0 ≤ x < 2, 12x for 2 ≤ x ≤ 10} on 0 ≤ x ≤ 10

The function k(x) is continuous on the interval [0, 2) and (2, 10]. H

However, since the interval given is [0, 10], we see that the function is not continuous over the closed interval.

Hence the function does not satisfy the hypotheses of the Extreme Value Theorem.

D. h(x) = (e^x)/x for 2 ≤ x ≤ 16The function h(x) is continuous on the interval [2, 16].

Therefore, this function satisfies the hypotheses of the Extreme Value Theorem on the given interval.

E. m(x) = 6x^3+x+1 on −4 < x < 3

The function m(x) is continuous on the interval (-4, 3).

However, since the interval given is [-4, ∞), we see that the function is not continuous over the closed interval.

Hence the function does not satisfy the hypotheses of the Extreme Value Theorem.

Therefore, the only function that satisfies the hypotheses of the Extreme Value Theorem on the given interval is given by

B. g(x)=6x^2+3 on 0≤x≤4

D. f(x) = (e^x)/x for 2 ≤ x ≤ 16

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The set of all possible y-values for the function h constitutes its range. The range is therefore [-3, 0].

The collection of all feasible output values (dependent variable) of a function is known as the range in mathematics. It is the totality of all possible numbers that the function can accept as input (an independent variable) and output. On the number line, the range is frequently represented by an interval or group of intervals. For instance, the range can be written as [-3, 3] if the domain of a function f(x) is [-2, 2] and its output numbers fall within [-3, 3].

given

The collection of all x-values for which h(x) is specified is the domain of the function h.

The graph's [-2, 4] domain can be determined by looking at the graph, which shows that it begins at x=-2 and concludes at x=4.

The set of all possible y-values for the function h constitutes its range. Looking at the graph, we can see that it takes all values between y=-3 and y=0, and that it begins at y=-3.

The range is therefore [-3, 0].

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The complete question is :-  The entire graph of the function h is shown in the figure below. Write the domain and range of h as intervals or unions of intervals.

-2

-3-

4-

domain =

range =

a) Graph this system of inequalities, we can plot the lines x = 0, y = 0, x = 260, y = 320, and x + y = 380

b) The maximum profit of $5200 achieved.

Selling profit is the profit that a business makes on the sale of its products or services. It is the difference between the selling price and the cost of product.

a) Let x be the number of boards of mahogany sold and y be the number of boards of black walnut sold. Then, the constraints of the problem can be represented by the following system of inequalities:

x ≥ 0 (non-negative constraint)

y ≥ 0 (non-negative constraint)

x ≤ 260 (maximum number of mahogany boards available)

y ≤ 320 (maximum number of black walnut boards available)

x + y ≤ 380 (maximum number of boards that can be sold)

To graph this system of inequalities, we can plot the lines x = 0, y = 0, x = 260, y = 320, and x + y = 380 on a coordinate plane and shade the feasible region that satisfies all of the constraints. The feasible region is the area that is bounded by these lines and includes the origin (0, 0).

b) The profit function P(x, y) can be defined as follows:

P(x, y) = 20x + 6y

To maximize the profit, we need to find the values of x and y that satisfy all of the constraints and maximize the profit function P(x, y).

One way to do this is to use the corner-point method. We can evaluate the profit function at each of the corners of the feasible region and find the corner that gives the maximum profit.

The corners of the feasible region are (0, 0), (0, 320), (260, 0), and (120, 260).

P(0, 0) = 0

P(0, 320) = 6(320) = 1920

P(260, 0) = 20(260) = 5200

P(120, 260) = 20(120) + 6(260) = 4720

Therefore, the maximum profit of $5200 can be achieved by selling 260 boards of mahogany and 0 boards of black walnut.

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Answer:

  r ≈ 44.25 cm

Step-by-step explanation:

You want the hypotenuse of a right triangle in which the side adjacent to the angle of 57° is 24.1 cm.

The cosine relation is ...

  Cos = Adjacent/Hypotenuse

  cos(57°) = (24.1 cm)/r

Solving for r gives ...

  r = (24.1 cm)/cos(57°) ≈ 44.25 cm

The length r is about 44.25 cm.

__

Additional comment

The calculator shown in the attachment has its angle mode set to degrees.

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Answer:

Step-by-step explanation:

Regular price:$19

60 per cent of $19 is 11.4 dollars.

but if ypu are looking for how much did she pay then it is..

19-11.4=$7.6

Answer:

-10 or -4

Step-by-step explanation:

the absolute value of -10 + 7 is 3

the absolute value of -4 + 7 is 3

absolute value just removes the negative sign of what is inside of it.

The rounding of the number to 1 significant figure is-

216 × 876 = 180000

216 × 876

This number can be written in form of rounding to 1 significant figure as;

200 × 900 = 180000

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Answer:

The sequence is defined as follows:

a1 = 5

an = an-1 - 5, for n > 1

Using this definition, we can find the first four terms of the sequence as follows:

a1 = 5

a2 = a1 - 5 = 5 - 5 = 0

a3 = a2 - 5 = 0 - 5 = -5

a4 = a3 - 5 = -5 - 5 = -10

Therefore, the first four terms of the sequence are: 5, 0, -5, -10.

Step-by-step explanation:

(a) To find the lower bound for the length of the rectangle, we need to subtract half of the smallest unit of measurement from the given measurement.

The smallest unit of measurement given is 1 mm, so half of that is 0.5 mm.

Therefore, the lower bound for the length of the rectangle is:

64 mm - 0.5 mm = 63.5 mm

(b) The perimeter of a rectangle is calculated by adding up the length of all four sides.

The lower bounds for the length and width of the rectangle are 63.5 mm and 36.5 mm, respectively.

So, the lower bound for the perimeter is:

2(63.5 mm + 36.5 mm) = 2(100 mm) = 200 mm

Answer and explanation below. Credits to Chris, Mechanical engineering college, Master's degree

Answer:

7/10

59/100

11/20

Step-by-step explanation:

59/100=59/100

7/10=70/100

11/20=55/100

Therefore, the total number of ways to select 2 cooked and 3 uncooked eggs is 210 ways.

In mathematics, a combination is a way of selecting items from a collection, such that (unlike permutations) the order of selection does not matter. In other words, a combination is a selection of items from a larger set, without regard to the order in which they are chosen. The number of combinations of size r that can be chosen from a set of n elements is denoted by the symbol C(n, r), and is given by the formula:

C(n, r) = n! / (r! * (n-r)!)

where n! (pronounced "n factorial") is the product of all positive integers up to n, and r! is the product of all positive integers up to r.

Here,

a) To find the number of ways to select 2 cooked or 3 uncooked eggs, we need to use the combination formula, which is:

ⁿCₓ= n! / r!(n-r)!

where n is the total number of eggs, r is the number of eggs we want to select, and ! represents factorial.

For 2 cooked eggs, we can select them in:

⁷C₂ = 7! / 2!(7-2)! = 21 ways

For 3 uncooked eggs, we can select them in:

⁵C₃ = 5! / 3!(5-3)! = 10 ways

Therefore, the total number of ways to select 2 cooked or 3 uncooked eggs is:

21 + 10 = 31 ways

b) To find the number of ways to select 2 cooked and 3 uncooked eggs, we need to use the product rule of counting. That is, we need to multiply the number of ways to select 2 cooked eggs and 3 uncooked eggs.

The number of ways to select 2 cooked eggs is:

⁷C₂ = 21 ways

The number of ways to select 3 uncooked eggs is:⁵C₃ = 10 ways

Therefore, the total number of ways to select 2 cooked and 3 uncooked eggs is:

21 x 10 = 210 ways

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A theorem which these transformations reveal include the following: theorem of intersecting secants.

In Mathematics and Geometry, the theorem of intersecting secants states that when two lines intersect outside a given circle, the measure of the angle formed by these intersecting lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.

By applying the theorem of intersecting secants, the value of any of the angle subtended by the intersecting lines can be calculated by using the following mathematical equation:

m∠a = One-half(y – x).

m∠a = ½(y – x).

Where:

x and y represent the angles formed by the intersecting lines.

Therefore, the theorem of intersecting secants describe these set of transformations.

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Answer:

Cost price (CP) = Rs20

% Profit = 10%

Selling price (SP) = y

By formula:

% Profit = (Profit/CP) x 100%

But Profit= SP - CP

Therefore;

% Profit = [(SP-CP)/C.P)] x 100%

Substituting, we have:

10% = [(y-20)/20] x 100%

10/100 = (y-20)/20

1/10 = (y-20)/20

1 = (y-20)/2

Cross multiply

y - 20 = 2

y = 2 + 20

y = 22

Therefore, the Sale price is Rs 22

Answer: The median is 6

Step-by-step explanation: The median is the data value separating the upper half of a data set from the lower half.

Arrange data values from lowest to highest value

The median is the data value in the middle of the set

If there are 2 data values in the middle the median is the mean of those 2 values.

Answer:

I zont know i need points

Step-by-step explanation:

Yea im srry

The rate at which the amount of bacteria is changing after 12 hours is 21.698 units/hour.

The given formula for the amount of bacteria present in a medium after t hours is:

[tex]a(t) = 16e^ (0.32t)[/tex]

Now, we need to find out at what rate the amount of bacteria is changing after 12 hours.

This means we need to find out the derivative of a(t) with respect to t and then substitute t = 12 in the derivative formula to get the rate of change of bacteria after 12 hours.

Differentiating the given formula for a(t) with respect to t, we get:

a'(t) = [tex]16(0.32)e^(0.32t)[/tex]

On substituting, t = 12, we get

a'(12) = [tex]16(0.32)e^ (0.32X12)[/tex]

On solving this, we get a'(12) = 21.698.

Therefore, the rate at which the amount of bacteria is changing after 12 hours is 21.698 units/hour.

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The new coordinates of the two points after rotating the parallel lines 180 degrees clockwise are (2, -7) and (-8, 5).

What are parallel lines?

In geometry, parallel lines can be defined as two lines in the same plane that are at equal distance from each other and never meet.

If the set of parallel lines contains the points (-2, 7) and (8, -5), then the two lines are parallel to each other and have the same slope. We can find the slope of the line that passes through these two points using the slope formula:

slope = (y2 - y1) / (x2 - x1)

slope = (-5 - 7) / (8 - (-2))

slope = -12 / 10

slope = -6 / 5

So, the equations of the two parallel lines are:

y - 7 = (-6 / 5)(x + 2) --- equation 1

y + 5 = (-6 / 5)(x - 8) --- equation 2

To rotate the lines 180 degrees clockwise, we need to negate both the x and y coordinates of the points on the lines. That is, we need to replace each point (x, y) with the point (-x, -y).

So, after the rotation, the new coordinates of the two points will be:

(-(-2), -7) = (2, -7) --- for point (-2, 7)

(-(8), -(-5)) = (-8, 5) --- for point (8, -5)

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Answer:

6.9 or 7.0 .

Step-by-step explanation:

*Note that ^2 means raised to the power of two or squared

a^2 + b^2 = c^2

The hypotenuse is always the C, and the leg can be either a or b.

Fill in the blanks with the numbers that we have:

Hypotenuse: 7.7 | Leg: 3.4

3.4^2 + b^2 = 7.7^2

Square the numbers given

3.4 x 3.4 = 11.56

7.7 x 7.7 = 59.29, which leads us to:

11.56 + b^2 = 59.29

To find what b equals, we need to subtract 11.56 from 59.29

59.29 - 11.56 = 47.73

b^2 = 47.73

We need to take the square root of 47.73 to find b. b and b^2 are two different things.

The square root of 47.73 is about 6.90869017977. It asks for the answer to be rounded to the nearest tenth, giving us 6.9 or 7.0.

Use the line segment that connects (3, 42.5) and (5, 44) to estimate the vine length after 4 days.

Given the table of values

To do this, we make use of linear interpolation

Such that the points closest to day 4 are (3, 42.5) and (5, 44)

The slope of the line passing through the two points can be found using the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) = (3, 42.5) and (x2, y2) = (5, 44).

Thus, we have:

m = (44 - 42.5) / (5 - 3) = 0.75

So, we have

y = 0.75x + b

Using the point (3, 42.5), we get:

42.5 = 0.75(3) + b

Solving for b, we get:

b = 42.5 - 0.75(3)

b = 40.25

So, the equation is

y = 0.75x + 40.25

To estimate the vine length after 4 days, we substitute x = 4 into the equation and solve for y:

y = 0.75 * 4 + 40.25

y = 43.25

Therefore, the vine length after 4 days is estimated to be about 43.25 units.

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The equation that correctly represents this situation is c(t) = 45 + 45(t-2). This equation states that the total number of credits the student will have after t semesters is equal to 45 (the number of credits they had before beginning college) plus 45 times the number of semesters after two (t-2).

To explain this equation in more detail, we need to break it down. First, the student had some credits earned while in high school, so the equation starts off with c(t) = 45, which is the number of credits the student had before beginning college.

Next, 45(t-2) represents the number of credits earned in the additional semesters since college began. The t-2 part of the equation means that the total number of credits earned in the additional semesters starts at zero for t = 2. Then, for each additional semester, 45 credits are added. So, for example, when t = 5, 45 credits are added to the initial 45 credits the student had before beginning college, resulting in 90 credits.Therefore, the equation  c(t) = 45 + 45(t-2)  correctly represents this situation.

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The most distance Talia can go each day while staying within her budget is 320 miles.

In this case, our goal is to write an inequality before moving on to solve it.

We begin with the daily rental fee and the cost per mile.

This is stated as $30 per day and $0.20 per mile in the question.

She is required to spend a total of $94.

This means that the total cost of the rental automobile and the cost per mile must be $94 or less.

Let m be the maximum number of miles she can travel.

Hence, we may write the inequality as follows: 30 + 0.2 m 94.

This inequality is what we can now solve;

0.2m ≤ 94 - 30

0.2m ≤ 64

m ≤ 64/0.2

320 miles = m

The most distance Talia can go each day while staying within her budget is 320 miles.

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A unity feedback control system is characterized by an open-loop transfer function G(s)H(s)=k/s(s+10). The system gain k so that the system will have a damping ratio of 0.5 is 4. The corresponding rise time is 2.3s, settling time is 4.4s, and peak overshoot is 0.26.

To determine the system gain k so that the system will have a damping ratio of 0.5, we can use the equation  ζ=1/2ωn. Rearranging the equation yields k=2ωn2. Using the damping ratio of 0.5, this yields k=4.
For this value of k, the rise time, settling time, and peak overshoot can be determined using the following equations:
Rise Time: Tr=4.6/ωn
Settling Time: Ts=4.4/ζωn
Peak Overshoot: Mp=e^(-ζπ/√1-ζ^2)
Given that the damping ratio is 0.5 and the system is subjected to a step input of 1V, we can determine the rise time, settling time, and peak overshoot.
Rise Time: Tr=4.6/ωn=4.6/2=2.3s
Settling Time: Ts=4.4/0.5ωn=4.4/1=4.4s
Peak Overshoot: Mp=e^(-0.5π/√1-0.5^2)=0.26

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The value of x for each circle is calculated as follows:

1. x = 148°

3. x = 82°

4. x = 135°

5. x = 7

8. x = 6

9. x = 13

The Circle identities refer to a set of fundamental identities in trigonometry that relate the six trigonometric functions of an angle in a right-angled triangle.

1. Given, SR = ST

then, arcSR = arcST = x°

and arcRT = 64°

Sum of arc,

x + x +64 =360

x = 148°

3. Given, JK=LM

then, arcJK=arcLM

So, x=82°

4. Given, BA=AC =9

Then, arcBA = arcAC = x°

and arcBC = 90°

Sum of arc,

x + x +90 =360

x = 135°

5. Given, arc are equal then side also equal

2x+4=18

x=7

8. Given that, Circle M similar to circle P, and arc are equal so, side also equal

2x+24=6x

x=6

9. Given that, Circle V similar to circle W,

arcYZ + 198 =360

arcYZ = 162°

Now, arcTU=arcYZ

Then, 9x-78 = 3x

So, x=13

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The interest charge per month would be around $[tex]532.02[/tex], and the principal payment per month would be about $[tex]399.09[/tex].

Your hobbies are the things you find enjoyable to do and the things that you prefer to learn more about. A lack of intriguing conversation: Interesting things hold your attention and arouse your curiosity.

The cost of borrowing money is called interest, and it is typically stated as a percent, such as an annualized rate (APR). By utilizing the money, debtors may accrue interest to lenders, or lenders may pay the interest to borrowers.

We will use annuity formula, which is: [tex]P=C(\frac{1-(1+r)^{-n} }{r} )[/tex]

[tex]P[/tex] is [tex]105,000[/tex]

[tex]C[/tex] is what we need

[tex]r[/tex] is the [tex]0.045/12 = 0.00375[/tex]

[tex]n[/tex] is [tex]12*30 = 360[/tex]

[tex]P=C[\frac{1-(1+r)^{-n} }{r} ][/tex]

[tex]105,000=C[\frac{1-(1+0.00375)^{-360} }{0.00375} ][/tex]

[tex]1.5,000=C[197.3612][/tex]

[tex]C=532.02[/tex]

So monthly payment would be around [tex]532.02[/tex]

Now,

With each point purchase, the interest rate goes down by [tex]0.25[/tex]%, so for [tex]2[/tex] points it will be [tex]4.5[/tex]%[tex]- 2(0.25) = 4[/tex]%

Also, since [tex]20[/tex]% down payment, the loan amount would be [tex](0.8)(105,000) = 84,000[/tex].

Putting these values into the annuity formula we have:

[tex]84000=C[\frac{1-(1+.0..33)^{-360} }{0.0033} ][/tex]

[tex]84000=C(210.47)[/tex]

[tex]C=399.09[/tex]

The monthly payment would be around $[tex]399.09[/tex]

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