A 10 gram ball is rolling at 3 m/s. The ball has __________ energy. Calculate it. A 10 gram ball is held 2 meters from the ground. It has __________ energy. Calculate it. You serve a volleyball with a mass of 2100 g. The ball leaves your hand with a velocity of 30 m/s. The ball has ____________ energy. Calculate it. A toy baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 200 grams . The carriage has ____________ energy. Calculate it. A toy car is traveling with a velocity of 4 m/s and has a mass of 1120 g. The car has ___________energy. Calculate it. A cinder block is sitting on a platform 20 m high. It has a mass of 790 grams. The block has _____________ energy. Calculate it. There is a bell at the top of a tower that is 5 m high. The bell has a mass of 190 grams. The bell has ____________ energy. Calculate it. A toy roller coaster is at the top of a 2 m hill and has a mass of 9660 grams. The coaster (at this moment) has ____________ energy. Calculate it.
Answer:
a) KINETIC ENERGY K = 0.045 J , b) POTENTIAL ENERGY U = 0.196 J ,
c) KINETIC ENERGY K = 9.45 10⁵ J, d) POTENTIAL ENERGY , U = 41.16 J ,
e) POTENTIAL ENERGY U = 154.84 J , f) ENERGY IS POTENTIAL U = 9.31 J
g) energy is POTENTIAL U = 189.336 J
Explanation:
a) The ball is moving with a speed, so it has KINETIC ENERGY
K = ½ m v²
K = ½ 10 10⁻³ 3²
K = 0.045 J
b) The ball is at a given height therefore it has POTENTIAL GRAVITATORY ENERGY
U = m g y
U = 10 10-3 9.8 2
U = 0.196 J
c) The ball has speed so it has KINETIC ENERGY
K = ½ m v²
K = ½ 2,100 30²
K = 9.45 10⁵ J
d) The baby carriage is at a height whereby the POTENTIAL ENERGY
U = mg h
U = 0.200 9.8 21
U = 41.16 J
e) the concrete block is at a height that has POTENTIAL ENERGY
U = m g h
U = 0.790 9.8 20
U = 154.84 J
f) the hood has height, the ENERGY IS POTENTIAL
U = 0.190 9.8 5
U = 9.31 J
g) The roller coaster has height and speed, therefore the mechanical energy has a scientific part and a potential part, in general the speed at the top of the mountain is very small, so we can consider that almost all the energy is POTENTIAL
The value they give allows calculating the potential energy
U = 9.660 9.8 2
U = 189.336 J
The answer to all the questions on potential energy and kinetic energy have been done below;
A) We are told that the ball is rolling. An object in motion has kinetic energy. Formula for kinetic energy is;
K = ½mv²
We have; m = 10 g = 0.01 kg and v = 3 m/s
K = ½ × 0.01 × 3²
K = 0.045 J
B) We are told that the ball is held at a height. This means it is at rest and any object at rest has Potential Energy. Formula for potential energy is;
PE = mgh
We have; m = 10g = 0.01 kg and h = 2 m
PE = 0.01 × 9.8 × 2
PE = 0.196 J
C) Like in A above, the ball is in motion. Thus, it has kinetic energy.
K = ½ × 2.1 × 30²
K = 945 J
D) The baby carriage is sitting at rest and therefore has potential energy.
PE = 0.2 × 9.8 × 21
PE = 41.16 J
E) The toy car is in motion and has kinetic energy. Thus;
K = ½ × 1.12 × 4²
K = 8.96 J
F) The cinder block is sitting at rest and has potential energy. Thus;
PE = 0.79 × 9.8 × 20
PE = 154.84 J
G) The bell is at the top of the tower and is at rest and thus has potential energy.
PE = 0.19 × 9.8 × 5
PE = 9.31 J
g) The rollercoaster is at the top at rest and so has potential energy.
PE = 9.66 × 9.8 × 2
PE = 189.336 J
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1. If the front of the red car is used as a reference point, how far away is the white van?
Answer:
-36 m
Explanation:
In the diagram, the front of the black car is used as reference point which is point 0. The distance from the black car to the front of the red car is 15 m while the distance from the black car to the white van is - 21 m. The negative sign means the white van is behind the black car.
If the red car is used as the reference (point 0), the distance from the black car to the red car would be -15 m and the distance from the black car to the white van would be -21 m. Hence:
Distance from red car to white van = distance from the black car to the red car + distance from the black car to the white van = -15 + (-21)
Distance from red car to white van = -15 - 21 = -36 m
Answer:
The answer is -36
Explanation:
An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification?
Answer:
[tex] \boxed{\sf Magnification \ (m) = 2} [/tex]
Given:
Object distance (u) = 25.0 cm
Image distance (v) = -50.0 cm
To Find:
Magnification (m)
Explanation:
[tex]\boxed{\bold{\sf Magnification \: (m) = - \frac{Image \: distance \: (v)}{Object \: distance \: (u)}}}[/tex]
Substituting values of Image distance(v) & Object distance (u) in the equation:
[tex] \sf \implies m = - \frac{( - 50)}{25} [/tex]
-(-50) = 50:
[tex]\sf \implies m = \frac{50}{25} [/tex]
[tex]\sf \implies m = \frac{2 \times \cancel{25}}{ \cancel{25}} [/tex]
[tex]\sf \implies m = 2[/tex]
Answer:
+2
Explanation:
m = -di/do
m = -(-50)/25 = 2
HELP ASAP!! WILL MARK BRAINLIEST!! WRITE IN YOUR OWN WORDS!! What is something that you would like to see a physicist develop in the future?
Answer:
Phones as sunglasses with a mic. I put on my glasses and I say what's the weather today, The sunglasses will tell me the weather and can be charged just like phones
Explanation:
In a double-slit interference experiment you are asked to use laser light of different wavelengths and determine the separation between adjacent maxima. You observe that this separation is greatest when you illuminate the double slit with
Answer:
y = m λ L / d
must use lasers of greater wavelength
Explanation:
The expression for the constructive interference of a double slit is
d sin θ = m λ
let's use trigonometry to find the angle
tan θ = y / L
in interference phenomena the angles are small
tan θ= sin θ/ cos θ = sin θ
sin θ = y / L
we subjugate
d y / L = m λ
y = m λ L / d
In this expression we see that the separation of the lines (and) increases linearly with the wavelength, therefore we must use lasers of greater wavelength
The scale is 1:30 and their are 10 boulders. How many boulders are their in the real pond
A:20
B:10
C:300
D:3
Answer:
the correct answer is C
Explanation:
When we express that the scale is 1:30 we mean that the objects of the realization are reduced by a factor of 30 in the graph, for example a distance of 30 cm in the graph is represented by a distance of 1 cm.
Therefore something that in the graph has n value to bring it to real size must be multiplied by the scale.
Applying this to our case if there is
10 boulder on the chart
in reality there are #_boulder = 10 30
#_boulder = 300 boulder
so the correct answer is C
Question 5 At 12:00 pm, a spaceship is at position ⎡⎣324⎤⎦ km ⎣ ⎢ ⎡ 3 2 4 ⎦ ⎥ ⎤ km away from the origin with respect to some 3 dimensional coordinate system. The ship is travelling with velocity ⎡⎣−12−3⎤⎦ km/h ⎣ ⎢ ⎡ −1 2 −3 ⎦ ⎥ ⎤ km/h What is the location of the spaceship after 2 hours have passed
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
The location of the spaceship after 2 hours have passed is [1, 6, -2]
Calculation of the location:Since
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Now
Location of the ship after two hours should have passed
So,
Distance moved by spaceship should be
= Velocity × time
= [-1 2 -3] × 2
= [-2 4 -6]
Now
Location of ship after two hours should be
= Initial position + distance moved
= [3 2 4] + [-2 4 -6]
= [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6]
= [1, 6, -2]
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A car is traveling at some speed when it accelerates at 6 m/s2 for 3 seconds. If the car travels 39 meters in this time, how fast was it going before it sped up?
Answer:
4 m/s
Explanation:
Given:
Δx = 39 m
a = 6 m/s²
t = 3 s
Find: v₀
Δx = v₀ t + ½ at²
39 m = v₀ (3 s) + ½ (6 m/s²) (3 s)²
v₀ = 4 m/s
An astronaut throws a rock in outer space away from gravitational / frictional influences. Will the rock gradually stop or continue in a straight line at a constant speed?
Explanation:
the rock will go in constant slow speed
Anyone please help ASAP Why must the volume of a stereo in a room with wall-to-wall carpet be tuned higher than in a room with a wooden floor?related to sound.
Explanation:
A carpet absorbs sound making the room quieter. A wooden floor reflects sound making it louder. ... The carpet surface absorbs some of the sound, making the room less “live.”
if a rock sample has a mass of 2.7 g and a volume of 1.1 cm³, what type of rock is it? (answer choices are Diamond, Common glass, ruby, and cubic zirconia)
Answer:
common glass
Explanation:
mike shoots a large marble (Marble A, mass:0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble A was initially lacking at a velocity of 0.6 m/s, but after the collision it has a velocity of -0.2 m/s what is the resulting velocity of marble B after the collision? be sure to show your work.
Explanation:
According to Conservation of Linear Momentum :
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times - 0.2 + 0.03 \times v_2[/tex]
[tex]0.04 = 0.03v_2[/tex]
Velocity of marble B after collision = 1.33 m/sec
A track and field athlete is running forward with a javelin at a
velocity of 4.2 m/s. If he throws the javelin at a velocity relative
to him of 10.3 m/s, what is the velocity of the javelin relative to the ground?
Please help
Explanation:
The relative velocity is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.
v = 4.2 m/s + 10.3 m/s
v = 14.5 m/s
The relative velocity of the javelin relative to the ground be 14.5 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
Velocity of the athlete: u = 4.2 m/s
Velocity of the javelin related to him: v = 10.3 m/s.
The relative velocity of the javelin relative to the ground is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.
So, The relative velocity of the javelin relative to the ground is:
V = 4.2 m/s+ 10.3 m/s
⇒ V= 14.5 m/s
Hence, the relative velocity of the javelin relative to the ground be 14.5 m/s.
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Why does weight change depending
on location?
Answer:
gravity
Explanation:
gravity pulls you down so for example you will weigh more on earth than on the moon because earths gravitational pull is greater.
On arrival at a vehicle collision, you observe a small fire in the engine compartment. A bystander is attempting to smother the fire with a jacket as you approach with an A-B-C extinguisher from your ambulance. Which of the following is the best method of extinguishing the fire?
a. Sweep the nozzle of the extinguisher left and right using short bursts until you are out of extinguishing agent.
b. Aim at the base of the fire and use short bursts until the fire is out.
c. Close the hood to contain the fire within the engine compartment.
d. Aim the nozzle to the side of the fire and, with a sweeping motion, push the fire at its base
Answer:
Aim at the base of the fire and use short bursts until the fire is out.
Explanation:
Fire extinguishers use CO2 (Carbondioxide) as the extinguishing agent. This is because CO2 is denser than air, and does not support combustion.
Aiming at the base of the fire causes the CO2 to fall on the base of the fire, where the source of the fire is, trapping it, and preventing it from further reacting with air in a combustion reaction. Also, the short burst creates a strong wind that forces the flame to blow out.
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the green train? A. 90 kgm/s B. 20 kgm/s C. 200 kgm/s D. 110 kgm/s
Explanation:
Momentum = mass × speed
p = (30 kg) (3 m/s)
p = 90 kg m/s
The weight of a body kept at a distance of 6400 km from the centre of the
earth is 10N. What will be the weight of another object kept at a distance of 12,800km ?
Answer:
2.5N
Explanation:
since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1
so the weight will be reduced to 1/4 of 10N
A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the weights is to double the rotational inertia of the system. As he is rotating, the man opens his hands and drops the two weights. They fall outside the turntable. Then:
Answer:
w = 2w₀ the angular velocity of man doubles
Explanation:
In this exercise, releasing the weights reduces the moment of inertia
I= I₀ / 2
Therefore, since the platform system plus man is isolated, the kinetic moment must be conserved
L₀ = L
I₀ w₀ = I w
I₀ w₀ = I₀ / 2 w
w = 2w₀
therefore the angular velocity of man doubles
What is most likely the author’s motive for writing this article?
A.to get you to buy sports products
B.to get you to support nuclear power plants
C.to get you to raise money for space programs
D.to get you to appreciate the benefits of atomic research
Answer:
D
Explanation:
Answer
Its D
Explanation:
What is a Joule, and what are the SI units for a Joule?
The joule is a derived unit of energy in the International System of Units. It is equal to the energy transferred to an object when a force of one newton acts on that object in the direction of the force's motion through a distance of one metre.
Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.
What is the kinetic energy of a 3 kg ball that is rolling at 3 m/s?
Answer:
[tex]\Huge \boxed{\mathrm{13.5 \ Joules}}[/tex]
Explanation:
[tex]\sf Kinetic \ energy \ (J)=\frac{1}{2} \cdot mass \ (kg) \cdot (velocity \ (m/s)) ^2[/tex]
[tex]\mathrm{KE=\frac{1}{2} mv^2}[/tex]
The mass of the ball is 3 kg.
The velocity of the ball rolling is 3 m/s.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 3^2}[/tex]
Evaluating and solving for kinetic energy.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 9}[/tex]
[tex]\mathrm{KE=\frac{1}{2} \cdot 27}[/tex]
[tex]\mathrm{KE} =13.5[/tex]
The kinetic energy of the ball is 13.5 Joules.
Answer:
Kinetic energy =1/2mv^2.
1/2×3×3^2.
1/2×27=13.5 or 13 whole number 1/2.
What is the SI unit of gravitational constant?
Explanation:
The force between two bodies is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
And this force is called the gravitational force
r is the distance between bodies
G is universal gravitational constant
[tex]G=\dfrac{Fr^2}{m_1m_2}[/tex]
SI unit of force is Newton or N
SI unit of r is meter or m
The SI unit of m₁ and m₂ is kg
[tex]G=\dfrac{\text{Nm}^2}{\text{kg}^2}\\\\G=Nm^2kg^{-2}[/tex]
Newton = kg m/s²
So,
[tex]G=\dfrac{kgm^3}{s^2kg^2}\\\\G=kg^{-1} m^3s^{-2}[/tex]
Hence, this is the required solution.
If the angle of reflection of a propagated ray is 35°. Calculate the a. Angle of incidence b. Angle of deviation c. Angle of glance
[tex] \LARGE{ \underline{ \blue{ \tt{Required \: answers}}}}[/tex]
First of all,
Angle of incidence = Angle between normal and incident ray.Angle of reflection = Angle between normal and reflected rayGlance angle of incidence = Angle between incident ray and the surface.Glance angle of reflection = Angle between reflected ray and the surface.We have,
➝ Angle of reflection = 35°
(a) According to law of reflection,
Angle of incidence = Angle of reflection
➝ Angle of incidence = 35°
(b) By using formula,
Angle of Deviation = 180° - 2(Angle of incidence)
From (a),
➝ Angle of Deviation = 180° - 2(35°)
➝ Angle of Deviation = 180° - 70°
➝ Angle of Deviation = 110°
(c) We know,
Angle of Incidence + Glance angle of incidence = 90°
Angle of reflection + Glance angle of reflection = 90°
So,
As angle of incidence = angle of reflection
Then, Angle of glance is also equal.
➝ Angle of glance = 90° - 35° = 55°
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Jupiter has a mass of 1,898,000,000,000,000,000,000,000,000 kg. How would
this number be expressed in scientific notation?
A. 1.898 x 1027 kg
B. 1.898^27 kg
C. 189.8 x 10^27 kg
D. 1.898 x 10^24 kg
PLEASE HELP SOON AS POSSIBLE
Answer: 1,898 • 10^27 kg
Explanation:
A pex
The mass of Jupiter can be expressed in scientific notation as 1.898 ×10²⁷ Kg. Therefore, option (A) is correct.
What is scientific notation?Scientific notation can be described as a form of representing very large numbers in a simpler form. As we know, whole numbers can be extended to infinity, but we cannot write such numbers on a piece of paper.
Scientific notation helps us to represent the numbers that are very huge in a form of multiplication of single-figure numbers and 10 raised to the power of the respective exponent.
To determine the exponent of 10, we should follow the rule such as the base must be always 10. The exponent should be a non-zero integer, which means it can be either positive or negative.
The absolute value of the coefficient should be greater than or equal to 1 but it must be less than 10.
Given the number is 1,898,000,000,000,000,000,000,000,000 Kg can be written as 1.898 ×10²⁷ Kg in scientific notation.
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The force of air particles over an area is_____?
(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity?
Answer:
The time taken is missing in the question. The time is 18 minutes.
The answer is 34.3 km/hr
Explanation:
Average velocity is the speed or the velocity which is required to cover a distance in a time interval.
The time taken is = 18 min
= 18/60 hours
The distance from the university to her home is = 10.3 km
Therefore, the average velocity is = displacement/time taken
= 10.3 / (18/60) km/hr
= 34.3 km/hr
Hence, the average velocity is 34.3 km/hr
A weight lifter lifts a set of 212 kg weights to a height of 1.75 m. How much
potential energy to the weights now have?
Answer:
Potential energy = 3635.8 Joules
Explanation:
Given that,
Weight lifted by a weight lifter is 12 kg
It lifts to a height of 1.75 m
We need to find the potential energy to the wights now have. The energy possessed by an object due to its position or height above ground is called potential energy. Its formula is given by :
P = mgh
g is the acceleration due to gravity
[tex]P=212\ kg\times 9.8\ m/s^2\times 1.75\ m\\\\P=3635.8\ J[/tex]
So, the potential energy is 3635.8 joules.
What is the sub-unit of capacitance in physics?
Answer:
farad
Explanation:
The farad (symbol: F) is the SI derived unit of electrical capacitance, the ability of a body to store an electrical charge. It is named after the English physicist Michael Faraday. hope this helps you :)
which of the following statements is true about the atoms of any element
Answer:
The number of protons in an atom of an element is unique to each element. A proton in an atom of one element is identical to a proton in an atom of another element. The number of protons in an atom of an element is the same for all elements.
State the best unit for measuring mass:
a. mass of a chips:
b. your mass:
Answer:
Mass of chips: Gram ( g )
Your mass: Kilogram ( kg )