a three tiered birthday cake rests on a table. From the bottom to the top, the cake tiers weigh 15 N, 8N, and 6N, respectively. What is the magnitude and direction of the normal force acting on the base of the seconf tier

Answers

Answer 1

The normal force on the second tier of the cake is 14N. It is the sum of the weight of the last and the second tier of the cake.

What is Normal force?

The normal force is the force which the surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two objects or surfaces are not in contact, they cannot exert a normal force on each other.

Fₙ = mg

Fₙ = Normal force

Fₙ on the second tier is the sum of the first and second tier of the cake is:

Fₙ = 8N + 6N

Fₙ = 14N

The normal force on the second tier is 14N.

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Related Questions

Hi, can anyone help me with this question I have?

Assume a tornado is in the vicinity of your neighborhood. Which would
be the most useful information to determine your safety - speed or
velocity? Explain your answer.

Answers

Answer:

speed

Explanation:

you need to move fast so the tornado can't reach you

H
Question 12 of 15:
Select the best answer for the question.
12. A 150-lb block of ice has a temperature of 22 F. How much heat will the ice absorb before it begins to melt?
O A. 1500.0 Btu
O B. 1663.2 Btu
C. 756.0 Btu
OD. 2419.2 Btu

Answers

Answer:

I think it is A

Explanation:

It is A because if you calculate the weight minus the F, then you have to divide that by the amount of absorbation (the lb) before timsing it by 1000.

What will be the change in temperature if 600 g of water absorbs 5200 J of heat?

Answers

The change in temperature of the 600 g of water, given that the water aborbs 5200 J of heat energy is 2.07 °C

How do I determine the change in temperature of the water?

First, we shall list out the given parameters from the question. This is given below:

Mass of water (M) = 600 gHeat absorbed (Q) = 5200 JChange in temperature (ΔT) = ?

Calorimetry suggest the following formula:

Q = MCΔT

Where

Q is the heat transferred M is the mass C is the specific heat capacity ΔT is the change in temperature

Using the above formula, the change in temperature of the water can be obtained as follow:

Note: Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

5200 = 600 × 4.184 × ΔT

5200 = 2510.4 × ΔT

Divide both sides by 2510.4

ΔT = 5200 / 2510.4

ΔT = 2.07 °C

Thus, we can conclude from the above calculation, that the change in temperature of the water is 2.07 °C

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