Answer:
$325.50, mentioned methods below.
Step-by-step explanation:
55% means it increases by 55%. an increase of 50% is basically taking half of the original amount . So a 50% increase of 4 would be 4 + .5*4 = 4+2 = 6
So for 210 that's 210 + .55*210 = 325.50
You could also factor to make it a little simpler.
210 + .55*210 = 325.50
210(1 + .55) = 325.50
210*1.55 = 325.50
.55 = 55/100 = 11/20
1.What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of AC and AB .
2.Use the distance formula to find BC. Show your work.
Answer/Step-by-step explanation:
1.
✔️Coordinates of vertices ABC:
A(2, 2)
B(6, 2)
C(2, -1)
✔️AC = |2 - (-1)| = 3 units
AB = |2 - 6| = 4 units
2. Distance formula => [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Distance between B(6, 2) and C(2, -1):
[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Where,
[tex] B(6, 2) = (x_1, y_1) [/tex]
[tex] C(2, -1) = (x_2, y_2) [/tex]
[tex] BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2} [/tex]
[tex] BC = \sqrt{(-4)^2 + (-3)^2} [/tex]
[tex] BC = \sqrt{16 + 9} = \sqrt{25} [/tex]
[tex] BC = 5 units [/tex]
Answer:
The person above me has the correct answer and solves it in the correct way.
Step-by-step explanation:
This is what I used as my answer though.
Distance Formula: d = √(x2-x1)^2 + (y2-y1)^2
BC = √(x2-x1)^2 + (y2-y1)^2
B = (6,2)
C = (2,-1)
BC = √(2-6)^2 + (-1-2)^2
BC = √(-4)^2 + (-3)^2
BC = √16+9
BC = √25
BC = 5
I don’t understand how to do this.
Answer:
46degrees
Step-by-step explanation:
From the question, we are told that both triangles are similar, hence;
<E = <S
<D = <R
<F = <T
From triangle DEF
<D + <F + <E = 180
Since <D = <F = 67
67 + 67 + <E = 180
134 + <E = 180
<E = 180 - 134
<E = 46degrees
Since <E = <S, hence the measure of <S is 46degrees
Which expression is equivalent to 4p^-4 10q -3? Assume
Step-by-step explanation:
Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is

Note that the equivalent width is practically insensitive to the number density of absorbing material.
Help me pls this is hard
Answer:
I guess it is the Answer C
Answer:
C
The distance around the edge of the circle
Một hộp đựng 10 phong bì bốc thư trúng thưởng trong đó 3 phong bì đựng 500 nghìn 7 phong bì đựng 100 nghìn. Bốc ngẫu nhiên liên tiếp hai phong bì. Nếu biết phong bì thứ hai có 500 nghìn, tìm xác xuất để phong bì đầu tiên cũng có 500 nghìn?
I can't understand tell me in english
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
Answer:
27.5 miles per gallon
1 full tank = 15.45 gallons
27.5 x 15.45 = 424.875 miles
rounded to the nearest 100th: 424.88 miles
nearest 10th: 424.9 miles
nearest whole #: 425 miles
Bryan is sitting on a bench in the mall. He noticed that 18 out of the last 60 men who walked by had a beard . Considering this data how many of the next 90 men who walk by should Bryan expect to have a beard?
Answer:
27
Step-by-step explanation:
every 30 men = 9 men with beards
you have 30 3 times in 90 so you get 27
60÷2=30
18÷2=9
30 men normal = 9 men with beards
90÷30=3
3×9=27
please helpppppppppp
Answer:
Step-by-step explanation:
b = sqrt(2 * L) Given
L = 4.5 Given
b = sqrt(2 * 4.5)
b = sqrt(9)
b = 3
Answer:
b = 9
Step-by-step explanation:
Given :-
[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]
[tex] \small \: l = 4.5[/tex]
Solution :-
[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]
plug the values of l in the equation
[tex] \small \sf \leadsto \: b = \sqrt{2 × 4.5} [/tex]
[tex] \small \sf \leadsto \: b = \sqrt{9} [/tex]
[tex] \small \sf \leadsto \: b = 9 [/tex]
Let V be the set of all 3x3 matrices with Real number entries, with the usual definitions of scalar multiplication and vector addition. Consider whether V is a vector space over C. Mark all true statements (there may be more than one).
a. The scalar closure axiom is satisfied
b. The additive inverse axiom is not satisfied
c The additive inverse axiom is satisfied
d. The additive closure axiom is not satisfied
e. The scalar closure axiom is not satisfied
f. The additive closure axiom is satsified
g. V is not a vector space over C
h. V is a vector space over C
i. The zero axiom is satisfied
j. The zero axiom is not satisfied
Answer:
the Scalar Closure axiom is not satisfiedV is not a Vector Space of CThe Additive Closure axiom is satisfied.Step-by-step explanation:
According to the Question,
Given That, Let V be the set of all 3x3 matrices with Real number entries, with the usual definitions of scalar multiplication and vector addition. Consider whether V is a vector space over C.For V is a vector space over C and V is Set of 3x3 Matrices with Real entries.Then, For any u,w ∈ V ⇒ u+w ∈ V
And u∈V and z∈C ⇒ z u ∈ V
So, If we take any z= i ∈ C
and V be any 3x3 matrices with Real entrices.then, z,v ∉ V ∴z,v Has Complex entries
So, the Scalar Closure axiom is not satisfied
Hence, V is not a Vector Space of C
Any u,w ∈ W ⇒ u+w ∈ V
So, The Additive Closure axiom is satisfied.
Are the triangles congruent? Why or why not?
Answer:
Yes, because they are identical to eachother
Step-by-step explanation:
I need to match them but I don't know how
Given:
The system of equations is:
[tex]x+3y=5[/tex]
[tex]x-3y=-1[/tex]
The given matrices are [tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex], [tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex], [tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex].
To find:
The correct names for the given matrices.
Solution:
We have,
[tex]x+3y=5[/tex]
[tex]x-3y=-1[/tex]
Here, coefficients of x are 1 and 1 respectively, the coefficients of y are 3 and -3 respectively and constant terms are 5 and -1 respectively.
In the x-determinant, the coefficients of x are in the first column and the constant terms are in the second column. So, the x-determinant is:
[tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex]
In the y-determinant, the constant terms are in the first column and the coefficients of y are in the second column. So, the y-determinant is:
[tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex]
In the system determinant, the coefficients of x are in the first column and the coefficients of y are in the second column. So, the system determinant is:
[tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex]
Therefore, the first matrix is y-determinant, second matrix is x-determinant and the third matrix is the system determinant.
ok and again i just dont understand well so this is why i am asking so many times and u guys and girls are getting alot of points
Answer:
The answer is A
Step-by-step explanation:
Can someone help I forgot what formal to use?
Answer:
1) V = 336mm
2) V = 64.33ft
Step-by-step explanation:
1) V = lwh + lwh
V = 4(6)(5) + 9(6)(4)
V = 120 + 216
V = 336mm
2) V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h +
Cone = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h
Cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex](1.5)^{2}[/tex](3) +
V = [tex]\pi[/tex][tex](1.5)^{2}[/tex] +
V = 7.07 + 57.26
V = 64.33ft
Find the zeros of the quadratic function: y = 6x2 + x – 35.
The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
How to determine the zeros?The function is given as:
y = 6x^2 + x - 35
Expand the function
y = 6x^2 + 15x - 14x - 35
Factorize the function
y = (2x + 5) * (3x - 7)
Set the function to 0
(2x + 5) * (3x - 7) = 0
Split
2x + 5 = 0 or 3x - 7 = 0
Solve for x
x = -2.5 or x = 7/3
Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
Read more about quadratic functions at:
https://brainly.com/question/1214333
#SPJ1
What’s the domain of the function?
Answer:
domain of function refers to the various values that can be passed through to the function.
Step-by-step explanation:
Consider a student loan of 15,000 at a fixed APR of 9% for 25 years. A) Calculate the monthly payment B) Determine the tiaras amount paid over the term of the loan C) Of the total amount paid, what percentage is paid toward the principal and what percentage is paid for interest.
Answer:
The monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.
Step-by-step explanation:
Since there is a student loan of 15,000 at a fixed APR of 9% for 25 years, to calculate the monthly payment, determine the tiaras amount paid over the term of the loan, and determine, of the total amount paid, what percentage is paid toward the principal and what percentage is paid for interest, the following calculations must be performed:
((15,000 x 0.09) x 25) + 15,000 = X
33,750 + 15,000 = X
48,750 = X
48,750 / (25x12) = X
48,750 / 300 = X
162.5 = X
48,750 = 100
33,750 = X
33,750 x 100 / 48,750 = X
69.23 = X
Therefore, the monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.
Orla weighed 3.77kg when she was born.
On Orla's second birthday she weighed 12.8kg.
Calculate the percentage increase in her weight.
Answer :
70.5% weight increase
solve marked question only !
plz
Answer:
hello ok I will share u the link where u can find step by step answers
Answer:
The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.
A Let tower be AB
Let point be C
Distance of point C from foot of tower = 30m Hence,
BC = 30m
Angle of elevation = 30°
So < ACB = 30°
Since tower is vertical,
< ABC = 90°
See the image for the question
Answer:
The value of equipment after 2 years is $58,800
Step-by-step explanation:
f(n) = 67,500(14/15)ⁿ
where f(n) is the value after n years.
1 – 1 / 15 = 14 / 15.
What is the value of h(2)?
-2
-1
0
3
Help me pleassseeeee
Answer:
8x+(-20x)
Step-by-step explanation:
Given f(x) = x2 + 24 - 12, find f(3)
Answer:
f(3) = 12
Step-by-step explanation:
f(3) = (3 x 2) + 24 - 12
= 6 + 24 - 12
f(3) = 12
If this helps you, please give brainliest!
Answer:
Step-by-step explanation:
f(x) = [tex]x^{2}[/tex] + 24 - 12
substitute 3 inplace of x
f(3) = [tex]3^{2}[/tex] + 24 - 12
=9 + 24 - 12
21
If the question is f(x) = x2 + 24 - 12 {x*2 + 24 - 12}
now substitute 3 in place of x
f(3) = 3*2 + 24 - 12
=6 + 24 - 12
18
The sum of two numbers is 56. Seven times the smaller number is 12 more than three times the larger number. Find the numbers.
Answer:
x = 18
y = 38
Step-by-step explanation:
Let the smaller number be = x
Let the larger number be = y
Sum of the number, x + y = 56 --------- ( 1 )
Seven times smaller number = 7x
Three times larger number = 3y
Seven times smaller = 12 more than 3times larger , 7x = 12 + 3y ----- ( 2 )
Solve ( 1 ) and ( 2 )
x + y = 56 => x = 56 - y
Substitute x in ( 2 )
7x - 3y = 12
7(56 - y) - 3y = 12
392 - 7y - 3y = 12
-10y = 12 - 392
-10y = - 380
y = 38
Substitute y in ( 1 )
x + y = 56
x + 38 = 56
x = 56 - 38
x = 18
Why should people conserve energy? (Please don’t get the answer form the internet)
You work for a company in the marketing department. Your manager has tasked you with forecasting sales by month for the next year. You notice that over the past 12 months sales have consistently gone up in a linear fashion, so you decide to find a regression equation for the company's sales history. You find that the regression equation for the data is (sales) = 25.614*(time) + 5.499. Interpret the slope.
a. When sales increases by 1 unit, time increases by 5.499 months.
b. We are not given the dataset, so we cannot make an interpretation.
c. When sales increases by 1 unit, time increases by 25.614 months.
d. When time increases by 1 month, sales increases by 5.499 units.
e. When time increases by 1 month, sales increases by 25.614 units.
2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method.
2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method.
Solution:-[tex]\sf{Set\:y = 0. Thus, }[/tex]
[tex]\sf\rightarrow{0 = x2 – 3x + 2} [/tex]
[tex]\sf\rightarrow{0 = ( x – 2) ( x – 1)}[/tex]
[tex]\sf\rightarrow{x – 2 = 0 or x – 1 = 0} [/tex]
[tex]\sf{Then\:x = 2\:and\:x = 1}[/tex]
Answer:-The zeros of y = x² – 3x + 2 are 2 and 1.=====================#CarryOnLearning
(ノ^_^)ノ
Out of 90 civil servants, 65 were working in the office, 50 were working in the field and 35 were working in both the premises (sites). How many civil servants were absent? How many civil servants were working in the field only? Represent the above information in the Venn diagram. 1
Answers:
10 people absent15 people working in the field onlySee the below image for the venn diagram=======================================================
Explanation:
35 people are working in both places. 50 work in the field or both, so 50-35 = 15 people work solely in the field. 65 work in the office or both, so 65-35 = 30 people work solely in the officeSo far that accounts for 15+30+35 = 80 people who work in the field, the office, or both.
The remaining 90-80 = 10 people are absent.
The venn diagram is below.
What is the least common denominator of rational expressions with the given denominators? 4a^2, 6a, and 10b
( please do not respond to this if you are going to spam my question)
can we say ((-16)÷4) ÷ (-2) is the same as (-16)÷ (4÷(-2)?
Answer:
no we can't
Step-by-step explanation:
(-4)÷(-2). (-16÷(-2)
2. 8
[tex]\longrightarrow{\blue{[( - 16)\div 4) \div ( - 2)] \:is\:not\:equal\:to\:( - 16) \div [4 \div( - 2) ] }}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex][( - 16 )\div 4) \div ( - 2)] = ( - 16) \div [4 \div( - 2) ][/tex]
Let us first solve for L. H. S.
[tex] = [( - 16 )\div 4) \div ( - 2)][/tex]
[tex] = [ (\frac{ - 16}{4} )\div ( - 2)][/tex]
[tex] = \frac{( - 4)}{( - 2)} [/tex]
[tex] = 2[/tex]
Now, R. H S.
[tex]( - 16) \div [4 \div ( - 2)][/tex]
[tex] = \frac{ - 16}{ - 2} [/tex]
[tex] = 8[/tex]
[tex]\sf\purple{L. H. S.\: ≠ \:R. H. S. }[/tex]
Hence, [tex][( - 16) \div 4) \div( - 2)] ≠(-16)\div [4 \div( - 2) ][/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
For which value of m does the graph of y = 18x2 + mx + 2 have exactly one x-intercept?
Answer:
m = +/- 12
Step-by-step explanation:
A quadratic function has only one x-intercept when the discriminant is equal to 0. The discriminant is b^2 - 4(a)(c).
When we plug in what we know, we have:
m^2 - 4(18)(2) = 0.
Then using algebraic properties, solve for m.
m^2 - 144 = 0
m^2 = 144
m = +/- 12
When you plug in positive or negative 12, and then factor you will see that it comes out to a difference of squares, proving that there is only one x-intercept.
Answer: C
Step-by-step explanation:
EDGE 2023