A survey of over 25,000 Americans aged between 18 and 24 years revealed the following: 88.1% of the 12,678 females and 84.9% of the 12,460 males had high school diplomas.
a) Do the data suggest that females are more likely to graduate from high school than males? Test at a significance level of 5%.
b) Set-up a 95% confidence interval for the difference in the graduation rates between females and males.
c) State the assumptions and conditions necessary for the above inferences to hold.

Answers

Answer 1

Answer:

(a) Yes, the data suggest that females are more likely to graduate from high school than males.

(b) A 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .

Step-by-step explanation:

We are given that a survey of over 25,000 Americans aged between 18 and 24 years revealed the following: 88.1% of the 12,678 females and 84.9% of the 12,460 males had high school diplomas.

Let [tex]p_1[/tex] = population proportion of females who had high school diplomas.

[tex]p_2[/tex] = population proportion of males who had high school diplomas.

(a) So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex]    {means that females are less or equally likely to graduate from high school than males}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1 > p_2[/tex]     {means that females are more likely to graduate from high school than males}

The test statistics that will be used here is Two-sample z-test statistics for proportions;

                        T.S.  =    ~  N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of females having high school diplomas = 88.1%

[tex]\hat p_2[/tex] = sample proportion of males having high school diplomas = 84.9%

[tex]n_1[/tex] = sample of females = 12,678

= sample of males = 12,460

So, the test statistics =  

                                    =  7.428  

The value of the standardized z-test statistic is 7.428.

Now, at a 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 7.428 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that females are more likely to graduate from high school than males.

(b) Firstly, the pivotal quantity for finding the confidence interval for the difference in population proportion is given by;

                        P.Q.  =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex]  ~  N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of females having high school diplomas = 88.1%

[tex]\hat p_2[/tex] = sample proportion of males having high school diplomas = 84.9%

[tex]n_1[/tex] = sample of females = 12,678

[tex]n_2[/tex] = sample of males = 12,460

Here for constructing a 95% confidence interval we have used a Two-sample z-test statistics for proportions.

So, 95% confidence interval for the difference in population proportions, ([tex]p_1-p_2[/tex]) is;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                      of significance are -1.96 & 1.96}    

P(-1.96 < [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < 1.96) = 0.95  

P( [tex]-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < [tex]{(\hat p_1-\hat p_2)-(p_1-p_2)}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95  

P( [tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < ([tex]p_1-p_2[/tex]) < [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95

95% confidence interval for ([tex]p_1-p_2[/tex]) = [[tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] , [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ]

= [ [tex](0.881-0.849)-1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }[/tex] , [tex](0.881-0.849)+1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }[/tex] ]

= [0.024, 0.404]

Therefore, a 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .

(c) The assumptions and conditions necessary for the above inferences to hold are;

The data must follow the normal distribution.The sample must be taken from the population data only or the sample represents the population data.

Related Questions

Geometry: Find the value of X

Answers

Answer:

[tex] x = \sqrt{30} [/tex]

Step-by-step explanation:

BD is the altitude of the right ∆ which divides the hypotenuse to create two line segments, CD, and AD.

According to the right triangle altitude theorem,

[tex] BD = \sqrt{CD*AD} [/tex]

CD = 3, AD = 7, therefore,

[tex] BD = \sqrt{3*7} [/tex]

[tex] BD = \sqrt{21} [/tex]

Find x using Pythagorean theorem

[tex] x^2 = BD^2 + CD^2 [/tex]

[tex] x^2 = (\sqrt{21})^2 + 3^2 [/tex]

[tex] x^2 = 21 + 9 [/tex]

[tex] x^2 = 30 [/tex]

[tex] x = \sqrt{30} [/tex]

Star Wars land encompasses an area of 14.0 acres. [1.00 acre = 4046.86m2]. If Star Wars land were made into a circle, what would be the radius of Star Wars land?

Answers

Answer:

The answer is 134.29 m

Step-by-step explanation:

First of all we need to convert 14.0 acres to m²

1.00 acre = 4046.86 m²

14.0 acres = 14 × 4046.86 = 56656.04 m²

Area of a circle = πr²

where

r is the radius

To find the radius substitute the value for the area into the above formula and solve for the radius

That's

[tex]56656.04 = \pi {r}^{2} [/tex]

Divide both sides by π

We have

[tex] {r}^{2} = \frac{56656.04}{\pi} [/tex]

Find the square root of both sides

[tex]r = \sqrt{ \frac{56656.04}{\pi} } [/tex]

r = 134.29139

r = 134.29 m to 2 decimal places

Hope this helps you

Answer:

we have no way of knowing

Step-by-step explanation:

it could be a jedi mind trick.

2) In the Tour de France, cyclists ride 3,653.6 km in 20 days. How many miles do they go per day?

Answers

Answer:

The answer is 182.68 km

Step-by-step explanation:

To solve this question we use ratio and proportion

If in 20 days they ride 3,653.6 km , then

in 1 day they will ride [tex] \frac{3653.6 \times 1}{20} [/tex]

We have the final answer as

182.68 km

Hope this helps you

Ms. Ironperson and Mr. Thoro are making Avenger posters to give children when they visit Avenger Academy. Ms. Ironperson has completed 12 posters and will complete 6 more per day. Mr. Thoro has not started yet but can make 12 per day. At some point Mr. Thoro will catch up and both will have finished the same number of posters. When this does happen, how many posters will each Avenger have completed? If x denotes the number of days and y denotes the number of posters, what are the equations needed to solve this problem? Group of answer choices

Answers

Answer:

The equations needed to solve this problem are:

y = 12 + 6x

y = 12x

The number of posters completed by each Avenger will be 24.

Step-by-step explanation:

The information provided are:

Ms. Ironperson has completed 12 posters and will complete 6 more per day.

Mr. Thoro has not started yet but can make 12 per day.

The variable x denotes the number of days and y denotes the number of posters.

So, after x day the number of poster completed by Ms. Ironperson will be:

y = 12 + 6x

And after x day the number of poster completed by Mr. Thoro will be:

y = 12x

Thus, the equations needed to solve this problem are:

y = 12 + 6x

y = 12x

Compute the value of x as follows:

12x = 12 + 6x

6x = 12

x = 2

The number of posters completed by each Avenger is:

y = 12x = 12 × 2 = 24

Thus, the number of posters completed by each Avenger will be 24.

. A normal population has a mean of 80.0 and a standard deviation of 14.0. a. Compute the probability of a value between 75.0 and 90.0. b. Compute the probability of a value of 75.0 or less. c. Compute the probability of a value between 55.0 and 70.0. 19. Suppose the Internal Revenue Service reported that the mean

Answers

Answer:

a. The probability of a value between 75.0 and 90.0 is 0.40173

b. The probability of a value of 75.0 or less is 0.35942

c. The probability of a value between 55.0 and 70.0 is 0.19712

Step-by-step explanation:

To solve for this we make use of the z score formula.

z = (x-μ)/σ,

where

x = raw score

μ = the population mean

σ = the population standard deviation.

a. Compute the probability of a value between 75.0 and 90.0.

When x = 75

μ =80.0 and σ = 14.0.

z = (x - μ)/σ

z = 75 - 80/ 14

z = -0.35714

z = -0.36 to 2 decimal places

Using the z score table to find the probability

P(x = 75) = P(z = -0.36)

= 0.35942

For x = 90

z = 90 - 80/14

z = 0.71429

z = 0.71 to 2 decimal place

Using the z score table to find the probability

P(x = 90) = P(z = 0.71)

= 0.76115

The probability of a value between 75.0 and 90.0 is:

75 < x < 90

= P( x = 90) - P(x = 75)

= 0.76115 - 0.35942

= 0.40173

Therefore, probability of a value between 75.0 and 90.0 is 0.40173

b. Compute the probability of a value of 75.0 or less.

For x = 75

From the question, we know that

mean of 80.0 and a standard deviation of 14.0.

z = (x - μ)/σ

z = 75 - 80/ 14

z = -0.35714

z = -0.36 approximately to 2 decimal places.

P-value from Z-Table:

P(x ≤ 75) = 0.35942

c. Compute the probability of a value between 55.0 and 70.0.

For x = 55

From the question, we know that

mean of 80.0 and a standard deviation of 14.0.

z = (x - μ)/σ

z = 55 - 80/ 14

z = -1.78571

z = -1.79 approximately to 2 decimal places

Using the z score table to find the probability

P(x = 55) = P(z = -1.79)

= 0.036727

For x = 70

z = 70 - 80/14

z = -0.71429

z = - 0.71 approximately to 2 decimal place.

Using the z score table to find the probability

P(x = 70) = P(z = -0.71)

= 0.23885

The probability of a value between 55.0 and 70.0 is:

55 < x < 70

= P( x = 70) - P(x = 55)

= P( z = -0.71) - P(z = -1.79)

= 0.23885 - 0.03673

= 0.19712

A quality control manager is concerned about variability of the net weight of his company’s individual yogurt cups. To check the consistency, he takes a random sample of sixteen 6-ounce yogurt cups and finds the mean of the sampled weights to be 5.85 ounces and the sample standard deviation to be 0.2 ounce. Test the hypotheses H0: µ ≥ 6 Ha: µ < 6 at the 5% level of significance. Assume the population of yogurt-cup net weights is approximately normally distributed. Based on the results of the test, will the manager be satisfied that the company is not under-filling its cups? State the decision rule, the test statistic, and the manager’s decision.

Answers

Answer:

Decision rule : The  p-value  <  [tex]\alpha[/tex] so  the  null hypothesis is rejected

The test statistics is  [tex]t = -2.8[/tex]

The  manger will not be manager be satisfied that the company is not under-filling since the company is under-filling its cups

Step-by-step explanation:

From the question we are told that

    The  sample size is  n  =  16

     The  sample  mean is  [tex]\= x = 5.85[/tex]

     The  standard deviation  is  [tex]\sigma = 0.2[/tex]

      The  null hypothesis is  [tex]H_o : \mu \ge 6[/tex]

       The alternative  hypothesis is  [tex]H_a : \mu < 6[/tex]

       The  level of significance is  [tex]\alpha = 0.05[/tex]

       

Generally the test statistics is mathematically represented as

        [tex]t = \frac{ \= x - \mu }{ \frac{\sigma }{ \sqrt{n} } }[/tex]

=>    [tex]t = \frac{ 5.86 - 6 }{ \frac{ 0.2}{ \sqrt{ 16} } }[/tex]

=>   [tex]t = -2.8[/tex]

The  p-value is obtained from the z-table  the value is  

       [tex]p-value = P(Z < -2.8 ) = 0.0025551[/tex]

     [tex]p-value = 0.0025551[/tex]

 Given that the [tex]p-value < \alpha[/tex] we reject the null hypothesis

Hence there is sufficient evidence to support the concern of the quality control manager. and the manger will not be satisfied that since the test proof that the company is under-filling its cups

Consider the linear equation, 2.5n + 5.2 = 35.2.

What property will be used to complete the first step in solving for n?

Answers

Answer:

Subtraction Property of Equality

Step-by-step explanation:

When solving an equation for a variable (in this case n), we want to move all of the n-terms to 1 side and the non-n terms to the other side. To do this, we can subtract 5.2 from both sides to leave 2.5n by itself. The property we used to do this is the Subtraction Property of Equality which states that if you subtract a quantity from one side of an equation, you must also subtract that same quantity from the other side of the equation.

Answer: A is the right one

Step-by-step explanation:

Consider the linear equation, 2.5n + 5.2 = 35.2.

What property will be used to complete the first step in solving for n?

subtraction property of equality

multiplication property of equality

division property of equality

distributive property

Find the product of the complex numbers (-5+ 8i) and (3 - 8i)

Answers

Answer: 49+64i

Step-by-step explanation:

Concept to know:

i=√-1

i²=-1

i³=-i

[tex]i^{4}[/tex]=1

-------------------------------------

 (-5+8i)(3-8i)

=-15+40i+24i-64i²

=-15+64i-64i²

=-15+64i+64  (remember, i²=-1)

=49+64i

Hope this helps!! :)

Please let me know if you have any question or need further explanation

All of the following expressions are equivalent except.___ 2+m m+2 m-(-2) -2-m

Answers

Answer:

[tex]\Huge \boxed{-2-m}[/tex]

Step-by-step explanation:

2 + m

Rewrite with variable first.

m + 2

m + 2

Can’t be simplified further.

m - (-2)

Distribute negative sign.

m + 2

-2-m

Rewrite with variable first.

-m - 2

The last expression is not equivalent to m+2.

NEED HELP ASAP!!! Angles of Elevation and Despression! Need to find y!

Answers

Answer:

Hey there!

We have cosine 61=y/500

cosine 61(500)=242.4 ft.

Let me know if this helps :)

what is the rate of change of the linear function that has a graph that passes through the points (2, 9) and (-1, 3)

Answers

Answer:

Slope= 2

Step-by-step explanation:

Rate of change can simply be called slope

So the rate of change or slope of the linear function that passes through the points (2, 9) and (-1, 3) is

Slope = (y2-y1)/(x2-x1)

Where y2= 3

Y1= 9

X2= -1

X1= 2

Slope = (y2-y1)/(x2-x1)

Slope= (3-9)/(-1-2)

Slope= -6/-3

Slope= 2

I need help, I'm completely lost

Answers

Answer:

alpha = 2

beta = -6

Step-by-step explanation:

let everything inside the ln be 'a'

use the chain rule to to differentiate ln a with respect to a

since the differentiation of lnx is 1/x , the differentiation of lna will be 1/a

after the differentiation, you will get: [tex]\frac{1}{a}[/tex] X [tex]\frac{d[(x+1)^{2}X (2x-1)^{2} ] }{dx}[/tex]

you need to use the product rule to differentiate the second part, then multiply 1/a by both the equations being added

replace a with its actual value

you will get [tex]\frac{2}{x + 1}[/tex] and [tex]\frac{-6}{2x -1}[/tex]

by comparing it to the given equation, we get α = 2  and  β = -6

Which ordered pairs are in the relation {(x, y) | x > y 1} on the set {1, 2, 3, 4}?

Answers

Answer:

R = { ( 3 , 1 ) , (4 , 1) , (4 , 2) }

Step-by-step explanation:

Which ordered pairs are in the relation {(x, y) | x > y + 1} on the set {1, 2, 3, 4}

Assuming that:

R should be the set of real numbers such that:

R = { (x,y) | x > y + 1}  on the set {1, 2, 3, 4}

Then:

The ordered pairs for the relation can be computed as:

R = { ( 3 , 1 ) , (4 , 1) , (4 , 2) }

AB= please help step by step

Answers

Answer:

8x−14

Step-by-step explanation:

3x - 4 + 5x - 10

=3x+−4+5x+−10

Combine Like Terms:

=3x+−4+5x+−10

=(3x+5x)+(−4+−10)

3-x=5x+21
A: The solution set is (_) Simplified
B: There is no solution
Pick one and if A then simplify the answer

Answers

Answer:

[tex] \boxed{ \sf{ \bold{- 3}}}[/tex]

Step-by-step explanation:

[tex] \sf{3 - x = 5x + 21}[/tex]

Move 5x to left hand side and change it's sign

⇒[tex] \sf{ - x - 5x + 3 = 21}[/tex]

Move 3 to right hand side and change it's sign

⇒[tex] \sf{ - x - 5x = 21 - 3}[/tex]

Collect like terms

⇒[tex] \sf{ - 6x = 21 - 3}[/tex]

Subtract 3 from 21

⇒[tex] \sf{ - 6x = 18}[/tex]

Divide both sides of the equation by -6

⇒[tex] \sf{ \frac{ - 6x}{ - 6} = \frac{18}{-6}} [/tex]

Calculate

⇒[tex] \sf{x = -3}[/tex]

Hope I helped!

Best regards!!

Answer:

x = - 3

Step-by-step explanation:

3 - x = 5x + 21

- x + 3 = 5x + 21

(- x + 3) + (- 3 - 5x) = (5x + 21) + (- 3 - 5x)

(- x + 3) + (- 5x - 3) = (5x + 21) + (- 5x - 3)

- x + 3 - 5x - 3 = 5x + 21 - 5x - 3

- x - 5x + 3 - 3 = 5x - 5x + 21 - 3

- 6x = 18

x = - 18/6

x = - 3

Convert the following point from spherical to rectangular coordinates: (6,5π4,3π4). (x,y,z)=______
Usage: To enter a point, for example (x,y,z), type "(x, y, z)".

Answers

Answer:

nxjhbfhbfwihsfnjkfdbjbshcxbdbjibebfhdhwhhdhdhffvnfnjehrhffbfgnfjrjhhfrj

Step-by-step explanation:

Convert the following to slope-intercept form.
4x + 3y = 24

Answers

Answer:

y = -4/3x +8

Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

4x+3y = 24

Subtract 4x from each side

3y = -4x+24

Divide each side by 3

y = -4/3x +24/3

y = -4/3x +8

Answer: y = -4/3x +8

Can someone show me how to get the answer of -8 - 12 / (-4) step by step?

Answers

Answer:

-5

Step-by-step explanation:

12 ÷ -4 = -3Plug -3 in: -8 - -3Simplify: -8 + 3-8 + 3 = -5

Four less than the
product of 2 and 5
Help pleasss!!!

Answers

Answer:

The answer is 6

Step-by-step explanation:

2 x 5 = 10

10 - 4 = 6

Hope this helps!

Answer:

6

Step-by-step explanation:

2 x 5 = 10

10 - 4 = 6

I hope this helps!

A force of 150N is applied at an angle of 60° to the horizontal to pull a box through a distance of 50m. Calculate the work done

Answers

Answer:

Work done = 3750 Joules

Step-by-step explanation:

The force acting in the body should be resolved to it's horizontal component before we can use ut to solve for the problem

Horizontal component= 150 * cos 60

Horizontal component= 150*0.5

Horizontal component= 75N

Work done= Force * distance

Work done= 75*50

Work done= 3750 Nm

Work done = 3750 Joules

which symbol will make |-8|?|-10|
>
<
=
which property is shown by 4+(5+6)=(4+5)+6?
commutative property of addition
distributive property
additive Indentity
associative property of addition​

Answers

Answer:

[tex]|-8|<|-10| \Longleftrightarrow 8 < 10[/tex]

[tex]\text{Which property is shown by } 4+(5+6)=(4+5)+6?[/tex]

[tex]\text{It is the associative property of addition}[/tex]

You can group the addends in any combination and it won't change the result.


Find the amount of $8000 for 3 years,compounded annually at 5% per annum. Also ,find the compound interest

Answers

Answer:

$9261

$1261

Step-by-step explanation:

Principal: $8000

Interest rate: 5% PA compounded annually

Time: 3 years

Sum = $8000*(1.05)³ = $9261Interest = $9261 - $8000 = $1261

In a parallelogram ABCD, AB is parallel to CD. Which two sides are opposite sides?

Answers

Answer:

According to the picture you have AD AND BC

Step-by-step explanation:

Lisa owns a "Random Candy" vending machine, which is a machine that picks a candy out of an assortment in a random fashion. Lisa controls the probability of picking each candy. The machine is running out of "Honey Bunny," so Lisa wants to program it so that the probability of getting a candy other than "Honey Bunny" twice in a row is greater than \dfrac{9}{4} 4 9 ​ start fraction, 9, divided by, 4, end fraction times the probability of getting "Honey Bunny" in one try. Write an inequality that models the situation. Use ppp to represent the probability of getting "Honey Bunny" in one try.

Answers

Answer:

[tex][P(X_{1})\times P (X_{2})]>[\frac{9}{4}\times P (H_{1})][/tex]

Step-by-step explanation:

Let the candy "Honey Bunny" be labelled as H and the other candies as X.

It is provided that the machine is running out of "Honey Bunny".

So, Lisa wants to program it so that the probability of getting a candy other than "Honey Bunny" twice in a row is greater than 9/4 times the probability of getting "Honey Bunny" in one try.

Probability of getting a candy other than "Honey Bunny" twice in a row,

        P (X₁) × P (X₂)

Probability of getting "Honey Bunny" in one try,

        P (H₁)

The inequality is as follows:

[tex][P(X_{1})\times P (X_{2})]>[\frac{9}{4}\times P (H_{1})][/tex]

Answer:

(1-p)^2>9/4p

Step-by-step explanation:

A customer wants to enlarge a photo to 2.75 it’s current height the photo current height is 3.25 inches what should its enlarged height be in inches

Answers

Answer:

8.9375

Step-by-step explanation:

2.75×3.25=8.9375

According to the question it said increase to and that is why I only multiplied but if the question said increase by then I would have to add my product (8.9375) to the original height of the photo.

(Math question incoming) Are the Polynomials in standard form(Yes or No?) Identify the name of each Polynomial. Identify the leading coefficient. Identify the degree.

Answers

Standard polynomial form means that the terms are arranged from highest to lowest degree.

The leading coefficient is the number before the highest degree.

The degree of the polynomial is the power of the variable attached to the leading coefficient.

1) This is not in standard polynomial form.

The leading coefficient is -1.

This is a second-degree polynomial.

2) This is in standard polynomial form.

The leading coefficient is 3.

This is a fourth-degree polynomial.

3) This is not in standard polynomial form.

The leading coefficient is 3.

This is a fifth-degree polynomial.

4) This is in standard polynomial form.

The leading coefficient is -4.

This is a fifth-degree polynomial.

5) This is not in standard polynomial form.

The leading coefficient is -5.

This is a third-degree polynomial.

6) This is not in standard polynomial form.

The leading coefficient is -1.

This is a sixth-degree polynomial.

7) This is in standard polynomial form.

The leading coefficient is 2.

This is a second-degree polynomial.

8) This is in standard polynomial form.

The leading coefficient is 1.

This is a second-degree polynomial.

9) This is in standard polynomial form.

The leading coefficient is 1.

This is a third-degree polynomial.

10) This is not in standard polynomial form.

The leading coefficient is 6.

This is a fourth-degree polynomial.

A piece of rope falls out of a hot air
balloon from a height of 5,184 ft. If the
equation for height as a function of time
is h(t) = -16t2 - initial height where t is
time in seconds and h(t) is height in feet,
how many seconds will it take for the
piece of rope to hit the ground?

Answers

Answer: 18 seconds

==========================================

Explanation:

The equation should be h(t) = -16t^2 + (initial height). If you subtract off the initial height, then you'll have a negative starting height, which is not correct. Try plugging t = 0 into h(t) = -16t^2 - (initial height) and you'll see what I mean.

The initial height is 5184. We want to find the t value when h(t) = 0. So we want to find the time value when the height is 0.

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h(t) = -16t^2 + (initial height)

h(t) = -16t^2 + 5184

0 = -16t^2 + 5184

16t^2 = 5184

t^2 = 5184/16

t^2 = 324

t = sqrt(324)

t = 18

It takes 18 seconds for the rope to hit the ground.

The ares of a rectangle is 46 square inches, if the length is 4 times the width , the find the dimensions of the rectangle.

Answers

Answer:

[tex]\sqrt{11.5} =w[/tex] (Width)

[tex]4\sqrt{11.5}= Length[/tex]

Step-by-step explanation:

Area of a rectangle: 46 = w(L)

L = 4w

Substitute

46 = 4[tex]w^{2}[/tex]

Divide both by 4

[tex]11.5=w^{2}[/tex]

[tex]\sqrt{11.5} =w[/tex] (Width)

[tex]4\sqrt{11.5}= Length[/tex]

Josie has a bag of ice that weighs 5 pounds. She left it in a sealed container and it melted. How much does the resulting water weigh

Answers

Answer:

  5 pounds

Step-by-step explanation:

The only thing added or removed from the container was heat, which has no weight. The water has the same weight regardless of its chemical phase (solid, liquid, gas, plasma).

  5 pounds

Each of the sides of a square $S_1$ with area $16$ is bisected, and a smaller square $S_2$ is constructed using the bisection points as vertices. The same process is carried out on S_2 to construct an even smaller square $S_3$. What is the area of $S_3$?

Answers

Answer:

4 sq. units

Step-by-step explanation:

Because the vertices of S₂ are the midpoints of S₁, the area of S₂ will be half of that of S₁ which is 16 / 2 = 8. Similarly, because the same process is carried out on S₂ to make S₃, the area of S₃ is 8 / 2 = 4 sq. units.

Answer:

hope this helps friend

Step-by-step explanation:

A = a^2

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