For example, 0.123 would be a legitimate entry. Lower limit (first blank) = 0.285, Upper limit (second blank) = 0.562.
The confidence interval for proportions is
p±z *√p(1-p)/n.
In this case, p = 36/85 = .4235, and z* = 2.575 (the value of the standard normal distribution corresponding to 99%).
so,
0.4235 ± 2.576 * √0.4235*0.5765/85
0.4235 ± 0.13804
= (0.285, 0.562)
Therefore, Lower limit is 0.285 and Upper limit 0562.
A confidence interval is the mean of your estimate plus and minus the variation in that estimate. This is the range of values you anticipate your estimate to fall between if you redo your test, within a certain position of confidence.
Confidence, in statistics, is another way to describe probability. For illustration, if you construct a confidence interval with a 95 confidence position, you're confident that 95 out of 100 times the estimate will fall between the upper and lower values specified by the confidence interval.
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The well ordering property can be used to show that there is a unique greatest common divisor of two positive integers. Let a and b be positive integers, and let S be the set of positive integers of the form as + bt, where s and t are integers.
a) Show that S is nonempty
b) Use the well ordering property to show that S has a smallest element c.
c) Show that if d is a common divisor of a and b, then d is a divisor of c.
d) Show that c | a and c | b [Hint: First, assume that c does not divide a. Then a = qc + r, where 0 < r < c. Show that r E S, contradicting the choice of c.]
e) Conclude from (c ) and (d) that the greatest common divisor of a and b exists. Finish the proof by showing that this greatest common divisor is unique.
The well ordering property states that every non-empty set of positive integers contains a least element. This property can be used to show the existence and uniqueness of the greatest common divisor (GCD) of two positive integers.
a) To show that S is non-empty, we note that the element 0 is a member of S, since 0 = 0 + 0*b.
b) The well ordering property guarantees that S has a least element, which we denote as c.
c) Suppose d is a common divisor of a and b. We know that a = dq and b = dr for some integers q and r. Then c = a + bt = dq + drt = d(q + rt). Thus, d must be a divisor of c since it divides the terms on the right side of the equation.
d) Assume that c does not divide a. Then a = qc + r where 0 < r < c. This means r is also a member of S, contradicting the choice of c as the least element of S.
e) From (c) and (d) we can conclude that the GCD of a and b exists. To show that it is unique, we note that if a and b have two GCDs, d and e, then d and e must both divide c. Since c is the least possible value, this implies that d and e must actually be the same number, thus showing the GCD of a and b is unique.
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please help quick!
photo attatched!
The missing values in the ratio table on pages and minutes is :
Pages 1 / 4 3 / 4 1 ¹ / ₂ 5
Minutes 1 / 2 1 ¹ / ₂ 3 10
How to fill the ratio table ?To fill the ratio table, find the relationship between Minutes and Pages :
= 1 / 2 ÷ 1 / 4
= 2 mins per page
This means that every page is read in 2 minutes.
3 / 4 pages would be read in :
= 3 / 4 x 2
= 1 ¹ / ₂ minutes
3 minutes would allow for the reading of :
= 3 / 2
= 1 ¹ / ₂ pages
5 pages would be read in:
= 5 x 2
= 10 mins
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i have $8$ pieces of strawberry candy (all identical) and $7$ pieces of rhubarb candy (all identical). find the number of ways i can distribute this candy to $5$ children, if it's ok to not give a child any candy.
Answer:
2 pieces of sc and 1 piece of rc
Step-by-step explanation:
For each example, state whether the one-sample, two-independent-sample, or related-samples t test is most appropriate. If it is a related-samples t test, indicate whether the test is a repeated-measures design or a matched-pairs design. A professor tests whether students sitting in the front row score higher on an exam than students sitting in the back row. A graduate student selects a sample of 25 participants to test whether the average time students attend to a task is greater than 30 minutes. A researcher matches right-handed and left-handed siblings to test whether right-handed siblings express greater emotional intelligence than left-handed siblings. A principal at a local school wants to know how much students gain from being in an honors class. He gives students in an honors English class a test prior to the school year and again at the end of the school year to measure how much students learned during the year.
All the sample tests are stated below :
1) A two-independent-sample t test.
2) A one-sample t test.
3) A related-samples t test.
4) A related-samples t test.
What is Sample Test ?It is a subgroup of people with traits from a wider population. When population sizes are too big for the test to include all potential participants or observations, samples are utilized in statistical testing. A sample must be representative of the entire population and must not be biased toward any one trait.
A professor runs an experiment to see if front-row students perform better on an exam than back-row pupils.
This is a two-independent-sample t test, as there are two distinct groups (students in the front row and students in the back row) and the professor is interested in comparing the mean exam scores between them.
To determine whether students spend more than 30 minutes on an activity on average, a graduate student chooses a sample of 25 participants.
This is a one-sample t test, as there is only one group of participants and the graduate student is interested in comparing the mean time students attend to a task to a specific value (30 minutes).
To determine whether right-handed siblings exhibit higher emotional intelligence than left-handed siblings, a researcher pairs up right- and left-handed siblings.
This is a related-samples t test using a matched-pairs design, as the researcher is interested in comparing emotional intelligence scores of right-handed and left-handed siblings who are matched based on certain criteria (in this case, being siblings).
A local school's principal is curious to discover how much an honors class benefits the children there. He administers tests to honors English students before the start of the school year and again at the conclusion of the year to gauge their progress.
This is a related-samples t test using a repeated-measures design, as the principal is interested in comparing the test scores of the same group of students before and after taking the honors English class to measure how much they learned during the year.
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What is the approximate area of the geometric figure?
Responses
A 10 square units10 square units
B 8 square units8 square units
C 5 square units5 square units
D 2 square units2 square units
E 3 square units
Area of figure in the graph is 5 square unit.
Correct option is C.
What is area?Area is defined as the total space taken up by a flat surface or shape of an object. The space enclosed by the boundary of a plane figure is called its area. The area of a figure is the number of unit squares that cover the surface of a closed figure. Area is measured in square units like cm² and m².
Given, By the graph
Figure consists of one triangle and one rectangule
height of the triangle = 2 unit
length of base of triangle = 3 unit
Area of triangle
= (1/2) × height × base
= (1/2) × 2 × 3
= 3 unit²
Length of rectangle = 2 unit
Width of rectangle = 1 unit
Area of the rectangle
= length × width
= 2 × 1
= 2 unit²
Total area of the figure
= area of triangle + area of rectangle
= 3 + 2
= 5 unit²
Hence, 5 square unit is area of the figure in the graph.
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suppose that a and b are diagonalizable matrices of the same size, i.e.\ there exist invertible matrices u and v such that uau^{-1} and vbv^{-1} are diagonal. show that ab =
ab is diagonalizable and can be written as a product of invertible matrices.
Since a and b are both diagonalizable, there exist invertible matrices u and v such that [tex]uau^{-1} and vbv^{-1}[/tex] are both diagonal matrices. Thus, we can rewrite ab as [tex]uau^{-1}vbv^{-1}[/tex]. Since matrix multiplication is associative, the order of multiplication does not matter and thus [tex]ab = u(au^{-1}vb)v^{-1}[/tex]. Since the [tex]au^{-1}vb[/tex] is also diagonalizable, it can be written as c, where c is a diagonal matrix. Thus, [tex]ab = ucv^{-1}[/tex], which is also a diagonal matrix. Therefore, ab is diagonalizable and can be written as a product of invertible matrices.
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Complete questiom:
Suppose that A and B are diagonalizable matrices of the same size, i.e.\ there exist invertible matrices U and V such that [tex]UAU^{-1} and VBV^{-1}[/tex]are diagonal. Show that AB = UDEV, where UDEV is also a diagonal matrix.
If it takes 4/5 of an hour to paint 2/5 of a room how long to paint 1 room
Answer: 2 hrs
Step-by-step explanation:
4/5 + 4/5 = 1 3/5 + 2/5 (half of 4/5) = 2
↑
(4/5 of a room)
LPQR is a right angle. Find m/PQS and mZSQR. Enter deg after any value that
is in degrees.
The required measures of the angles ∠PQS and ∠SQR are given as 51 and 49.
What is complementary angles?Complementary angles are two angles whose measures add up to 90 degrees. In other words, if angle A and angle B are complementary, then A + B = 90 degrees.
Here,
∠PQR is a right angle,
So ∠PQS and ∠SQR are supplementary angles, from the figure.
∠PQR = ∠PQS + ∠SQR
90 = 8x + 131 + 10x + 139
90 = 18x + 270
18x = -180
x = -10
Now,
∠PQS = 8x + 131 = -80 + 131 = 51°
Similarly,
∠SQR = 49°
Thus, the required measure of the angles ∠PQS and ∠SQR are given as 51 and 49.
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Here is a graph of F and G.
Answer: please look at the image for the answer
Step-by-step explanation:
suppose that cars cross the point a in a highway following a poisson process with rate 4 cars per minute. suppose bob runs across the point a blindly, which takes him t seconds. please calculate the probability that he will be hit by a car with
Therefore, the probability that Bob will be hit by a car while crossing the point A is 1 [tex]-e^{-4t}[/tex] , where t is the time it takes him to cross the point A in seconds.
If the cars follow a Poisson process with rate 4 cars per minute, then the time between successive cars follows an exponential distribution with parameter λ = 4. Therefore, the probability density function of the time between cars is given by:
f(t) = λe^(-λt)
Since Bob takes t seconds to cross the point A, the probability that he will be hit by a car during this time is the probability that a car arrives within t seconds of his crossing, which is given by the cumulative distribution function:
F(t) = P(X ≤ t) = ∫[0, t] f(x)dx = ∫[0, t] 4e⁽⁻⁴ˣ⁾dx
Evaluating this integral, we get:
F(t) = [tex]-e^{-4t}[/tex]
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Consider the following two statements: 1. p: It is Friday 2. q: I don't go to class Express the following in words: a). p → q
b). -q → -p c). p A q
d) p V -q
Referring to the given statements,
a) p → q: "If it is Friday, then I don't go to class."
b) -q → -p: "If I don't go to class, then it is not Friday."
c) p ∧ q : "It is both Friday and I don't go to class."
d) p V -q: "Either it is Friday, or I don't go to class (or both)."
Some main logical operatorsConjunction (∧): The conjunction operator is used to connect two propositions and create a compound statement that is true only if both the propositions are true. Disjunction (V): The disjunction operator is used to connect two propositions and create a compound statement that is true if at least one of the propositions is true. Negation (-): The negation operator is used to negate a proposition and create a new proposition that is the opposite of the original one.Implication ( → ): is used to connect two propositions and create a compound statement that is true unless the first proposition is true and the second proposition is false. The implication "p → q" can be read as "if p, then q" or "p implies q."
In this problem, the propositions are:
p : It is Friday
q : I don't go to class
Hence,
a) p → q is an implication and read as: "If it is Friday, then I don't go to class."
b). -q → -p
-q is negation of q and read as: I go to class
-p is negation of p and read as: It is not Friday
Therefore, -q → -p means "If I don't go to class, then it is not Friday."
c) p ∧ q is a conjunction. p ∧ q can be read as: "It is both Friday and I don't go to class."
d) p V -q is a disjunction. p V -q can be read as: "Either it is Friday, or I don't go to class (or both)."
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Factor each expression
1. x² + 3x + 2
2. x² +10x+16
3. X²-10x+24
The expressions are factorized to;
1.(x + 1)(x + 2)
2.(x + 2) (x + 8)
3. (x -4) (x -6)
How to factorize the expression
Using the factorization method of solving quadratic equations, we have;
1. x² + 3x + 2
Find the pair factors of 2 that adds up to 3 and substitute the values, we get
x² + 2x + x + 2
Factorize in pairs
x(x + 2) + 1( x+ 2)
(x + 1)(x + 2)
2. x² +10x+16
Find the pair factors
x² + 8x + 2x + 16
Factorize in pairs
x(x + 8) + 2( x+ 8)
(x + 2) (x + 8)
3. X²-10x+24
Find the pair factors
x² - 6x - 4x + 24
Factor in pairs
x(x -6) - 4(x -6)
(x -4) (x -6)
Hence, use the factorization method in the expressions
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To rent a certain meeting room, a college charges a reservation fee of 37 and an additional fee of 7.90 per hour. The chemistry club wants to spend at most 92.30 on renting the meeting room.
Answer:
t ≤ 8
Step-by-step explanation:
Equation Total
1 hour 32 + 9.4 41.4
2 hours 32 + 2(9.4) 50.8
3 hours 32 + 3(9.4.) 60.2
4 hours 32 + 4(9.4.) 69.6
5 hours 32 + 5(9.4.) 79.0
6 hours 32 + 6(9.4.) 88.4
7 hours 32 + 7(9.4.) 97.8
8 hours 32 + 8(9.4.) 107.2
So we know the maximum amount of time is 8 hours. So now let's express this as an inequality:
32 + 9.4t ≤ 107.2 Now let's solve for t
9.4t ≤ 75.2
t ≤ 8
Un estudiante diseñó una investigación para probar el efecto del color de la luz en el crecimiento de las plantas. 1. ¿Cuál fue la variable independiente en la investigación? A. Color de la bombilla B. Altura de la planta C. Horas de luz D. Tamaño de la olla Plant Growth Investigation Blue Light Yellow Light Red Light State to
La intensidad de la luz afecta la tasa de fotosíntesis, cuanto mayor es la intensidad de la luz, mayor es la tasa de fotosíntesis y viceversa. ver explicacion.
What is plant growth?Important structures in plant development are buds, shoots, roots, leaves, and flowers; plants produce these tissues and structures throughout their life from meristems located at the tips of organs, or between mature tissues. Thus, a living plant always has embryonic tissues.
La fotosíntesis es el proceso mediante el cual las plantas verdes fabrican su propio alimento en presencia de luz solar, clorofila, dióxido de carbono y agua.
La intensidad de la luz afecta la tasa de fotosíntesis, cuanto mayor es la intensidad de la luz, mayor es la tasa de fotosíntesis y viceversa. Cuando hay una mayor intensidad de luz, hay más luz disponible para impulsar las reacciones de la fotosíntesis.
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Esmerelda is conducting a clinical drug trial. She has data from an Experiment Group and a Control Group. She wants to see which group feels less pain after having been given a new painkilling drug called Floximin. The pain scale is 1 = no pain, 5 = moderate pain and 10 unbearable pain (with values in between of course). Here are data for each:Experimental Group "Floximin" (M-3.14, SD 132) Control Group, "placebo (M-7.22, SD = 2.40) Using the mean and standard deviation for the Experimental Grour, about what is the pain range for most people in this group? (From where to where on the 1 - 10 pain scale) O 4.82 - 9.62 O 5.00 - 10.00 O 1.82 - 4.46 O 2.00 - 5.00
The mean of the Experimental Group is -3.14 and the standard deviation is 132.
We can use this data to calculate the range of pain for most people in this group.
Using the formula for standard deviation, we can find the lower and upper bounds of the range. The lower bound is the mean minus one standard deviation, or[tex]-3.14 - 132 = -135.14[/tex]. The upper bound is the mean plus one standard deviation, or [tex]-3.14 + 132 = 128.86[/tex].
When converted to the 1 - 10 pain scale, the lower bound is 1.82 and the upper bound is 4.46. Therefore, we can conclude that the range of pain for most people in the Experimental Group is 1.82 - 4.46.
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3x^2-18x=-15 by complete the square
The solutions to the equation 3x²-18x=-15 by completing the square are x = 1 and x = 5.
How to solve quadratic equation by completing the square?In order to make an equation a perfect square, something must be added. This is known as "completing the square." This makes a number of equations simple to solve. In fact, by solving the square, all quadratic problems can be resolved.
According to question:To complete the square for the equation 3x²-18x=-15, we can follow these steps:
Move the constant term to the right side of the equation:
3x² - 18x + 15 = 0
Divide both sides by the coefficient of x^2 to make the coefficient 1:
x² - 6x + 5 = 0
To complete the square, we need to add and subtract the square of half of the coefficient of x:
x² - 6x + 9 - 4 = 0
(x - 3)² = 4
Take the square root of both sides to solve for x:
x - 3 = ±2
x = 3 ± 2
x = 1 or x = 5
Therefore, the solutions to the equation 3x²-18x=-15 by completing the square are x = 1 and x = 5.
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National Hurricane Center estimates that the Gulf of Mexico averages 3 major Hurricanes (Category 3 or higher) in a season.
a) What is the Mean number of major hurricanes gulf can expect in a season?
b) What is the probability that the Gulf will have no major hurricanes in 2022?
c) What is the probability that the Gulf will have at least one major hurricane in 2022?
d) What is the probability that the Gulf will have three major hurricanes in 2022?
The Mean number of major hurricanes gulf can expect in a season is 3.
What is probability?
A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1, and they can also be expressed as percentages ranging from 0% to 100%.
What is mean?
The mean (aka the arithmetic mean, different from the geometric mean) of a dataset is the sum of all values divided by the total number of values. It's the most commonly used measure of central tendency and is often referred to as the “average.”
Given:
Gulf of Mexico averages 3 major Hurricanes
Since, It is stated that the Gulf experiences 3 major hurricanes on an average in a season. Since the average is the expected no. of observations the mean no. of major hurricanes Gulf expect is 3.
Hence, the Mean number of major hurricanes gulf can expect in a season is 3.
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PRACTICE IT Use the worked example above to help you solve this problem. parallel-plate capacitor has an area A = 2.50 X 10 m2 and plate separation d 1.40 * 10- m. (a) Find its capacitance_ 1.58e-12 (b) How much charge is on the positive plate if the capacitor Is connected to 3.00 battery? 12000 Your response differs significantly from the correct answer: Rework vour solution from the beginning and check each step carefully: € (c) Calculate the charge density on the positive plate, assuming the density is uniform: Clm (d) Calculate the magnitude of the electric field between the plates. 3.92 Your response differs significantly from the correct answer: Rework vour solution from the beginning and check each step carefully: Vlm
The capacitance is [tex]1.58*10^{-12} F[/tex], the charge is 12000 e, the charge density is [tex]4.80*10^{7} C/m^{2}[/tex], and the electric field is [tex]3.92*10^{6} N/C[/tex].
Here's how you can solve the above problems:
(a) To find the capacitance of a parallel-plate capacitor, we use the formula:
C = ε0A/d
where ε0 is the vacuum permittivity constant [tex](8.85*10^{-12}F/m )[/tex], A is the area of the plates, and d is the distance between the plates. Substituting the given values, we get:
C =[tex](8.85 * 10^{-12} F/m) (2.50* 10^{-4}m^{2} )/(1.40*10^{-7}m )[/tex]
= [tex]1.58*10^{-12} F[/tex]
(b) To find the amount of charge on the positive plate of the capacitor, we use the formula:
Q = CV
where Q is the charge, C is the capacitance, and V is the voltage across the capacitor. Substituting the values from (a) and the given voltage, we get:
Q = [tex](1.58*10^{-12}F )(3.00 V)[/tex]
= [tex]4.74*10^{-11} C[/tex]
= 12000 e
(c) To find the charge density on the positive plate, assuming the density is uniform, we divide the charge on the plate by the area of the plate:
ρ = Q/A = [tex](12000e)/(2.50*10^{-4}m^{2} )[/tex]
= [tex]4.80*10^{7} C/m^{2}[/tex]
(d) To find the magnitude of the electric field between the plates, we use the formula:
E = V/d
where E is the electric field, V is the voltage across the capacitor, and d is the distance between the plates. Substituting the given values, we get:
E = [tex](3.00 V)/(1.40*10^{-7}m )[/tex]
= [tex]2.14*10^{-7} V/m[/tex]
= [tex]3.92*10^{6} N/C[/tex]
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I will give brainliest and ratings if you get this correct
determine whether the following function have limit or not?
CAN SOMEONE HELP WITH THIS QUESTION?
The rate at which the water level is rising when the water level is 3 cm,
⇒ 0.65 cm / sec
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Let us assume it is a regular pyramid. The (altitude) height "h" of apex from base square, slanting height and the side "a" of the base square rise uniformly and proportionally when we move from the apex point to the base.
Now, If height (altitude) h becomes x times, then side "a" of the base square becomes x times, the slanting height also becomes x times. Thus, the area b of the base square rises x² times.
Δh / h = Δa / a
Δb / b = 2 Δa / a = 2 Δh / h
Or, h₁/h₂ = a₁/a₂
Since, We know that;
⇒ V = 1/3 b h = 1/3 a² h
⇒ d V / dt = 1/3 a² dh/dt + 1/3 h a da/dt
= 1/3 a² dh /dt + 2/3 h a (a/h) (dh/dt)
= 1/3 a² dh / dt + 2/3 a² dh/dt
Hence, We get;
dV/dt = a² dh/dt
dh/dt = (1/a²) dV/dt
We have;
h₀ = 5 cm and a₀ = 3 cm
At the base;
When h = 5cm,
Hence, h / h₀ = a/a₀ ;
⇒ a = a₀ h / h₀ = 5×5/3 = 8.3 cm
And, dh/dt = 1/8.3² × 45 = 45/68.89 cm/sec = 0.65 cm / sec
Thus, The rate at which the water level is rising when the water level is 3 cm,
⇒ 0.65 cm / sec
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Mrs.Nunes has 7 yards of string and needs to split it into 4 equal sections to make bows. How long will each section of string be?
Answer: 1.75 yards
Step-by-step explanation:
You need to divide 7 by 4 to get 4 equal sections.
7/4 = 1.75
Therefore, 1.75 is your answer
determine if the specified linear transformation is (a) one-to-one and (b) onto. justify each answer
To determine if a linear transformation is onto, we need to check if every vector in the range has at least one pre-image in the domain.
Let T be a linear transformation from R^3 to R^2 given by:
T (x, y, z) = (2x - y, x + 3y - 4z)
(a) To check if T is one-to-one, we need to check if for any two distinct vectors (x1, y1, z1) and (x2, y2, z2) in R^3, we have T (x1, y1, z1) ≠ T (x2, y2, z2). Equivalently, we can check if T (x1, y1, z1) - T (x2, y2, z2) ≠ 0 for any two distinct vectors (x1, y1, z1) and (x2, y2, z2) in R^3.
So, let (x1, y1, z1) and (x2, y2, z2) be two distinct vectors in R^3. Then:
T (x1, y1, z1) - T (x2, y2, z2) = (2x1 - y1, x1 + 3y1 - 4z1) - (2x2 - y2, x2 + 3y2 - 4z2)
= (2x1 - y1 - 2x2 + y2, x1 + 3y1 - 4z1 - x2 - 3y2 + 4z2)
= (2(x1 - x2) - (y1 - y2), x1 - x2 + 3(y1 - y2) - 4(z1 - z2))
For T to be one-to-one, the only solution to T (x1, y1, z1) - T (x2, y2, z2) = 0 must be (x1, y1, z1) = (x2, y2, z2). So, we need to solve the equation above and check if the only solution is (x1, y1, z1) = (x2, y2, z2).
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An element with a mass of 820 grams decays by 24% per minute. To the nearest
minute, how long will it be until there are 120 grams of the element remaining?
7 minutes will it be until there are 120 grams of the element remaining.
What is Percentage?To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. With the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.
We have,
An element with a mass of 820 grams decays by 24% per minute. To the nearest minute.
Now, 100 - 24 = 76% of the element remains after each minute.
So, 820 x (0.76[tex])^t[/tex] = 120 where t is number of minutes.
(0.76[tex])^t[/tex] = 0.146
Taking log both side we get
t log 0.76 = log 0.146
t = 7.00724
t = 7 minutes
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Use the Exterior Angle Theorem to find the measure of each angle.
mangleC =
mangleD =
mangleDEC =
Answer:
∠C = 35°
∠D = 76°
∠DEC = 69°
Step-by-step explanation:
Exterior angle theorem:Exterior angle equals the sum of opposite interior angles (remote angles).
∠C + ∠D = ∠DEF
3y + 5 + 7y + 6 = 111°
3y + 7y + 5 + 6 = 111
Combine like terms,
10y + 11 = 111
Subtract 11 from both sides,
10y = 111 - 11
10y = 100
Divide both sides by 10
y = 100 ÷ 10
[tex]\boxed{y = 10}[/tex]
∠C = 3y + 5
= 3*10 + 5
= 30 + 5
[tex]\boxed{\bf \angle C = 35^\circ}[/tex]
∠D = 7y + 5
= 7*10 + 6
= 70 + 6
[tex]\boxed{\bf \angle D = 76^\circ}[/tex]
∠C + ∠D + ∠DEC = 180° {Angle sum property of triangle}
35 + 76 + ∠DEC = 180
111 + ∠DEC = 180
∠DEC = 180 - 111
[tex]\boxed{\bf \angle DEC = 69^\circ}[/tex]
can you please solve?
Answer: (0,0)
Step-by-step explanation: 3+5=8-4=4-4=0
Determine the ratio of the volume of a paraboloid (the solid generated by rotating a parabola about the y-axis) to the volume of a cylinder with the same height and base radius. You may assume that the volume of the cylinder is V_cyl = pi r^2 h, but you must derive the volume of the paraboloid by treating it as a solid of revolution. Determine the ratio of the volume of a sphere to the volume of a cylinder with the same radius, and the height the same as the diameter of the sphere. You may assume that the volume of the cylinder is V_cyl = pi r^2 h, but you must derive the volume of the sphere by treating it as a solid revolution. (Archimedes was particularly proud of this last result and requested to have it inscribed on his grave. The Roman philosopher Cicero later discovered the tomb and had found it overgrown with vegetation. I was in Syracuse this last Summer and visited the tomb and can confirm that no such inscription exists today.)
The volume of a paraboloid with height h and base radius r can be found by treating it as a solid of revolution, rotating the parabolic cross-section about the y-axis.
The equation for the parabola is y = x^2 / (4h), so the equation for the cross-section is x = 2sqrt(hy). The volume can be found by integrating the area of the cross-section from y = 0 to y = h, and then multiplying by 2pi:
V_parab = 2pi * ∫[0,h] (2sqrt(hy))^2 dy, = 2pi * ∫[0,h] 4hy dy= 2pi * 2hy^2]_[0,h] = 4/3 * pi * h^3
The volume of a cylinder with the same height and base radius r is V_cyl = pi * r^2 * h. The ratio of the volume of the paraboloid to the volume of the cylinder is: V_parab / V_cyl = (4/3 * pi * h^3) / (pi * r^2 * h)
= (4/3 * h^2 * r)
For the second part, the volume of a sphere with radius r can be found by treating it as a solid of revolution, rotating a semicircle about its diameter.
The equation for a semicircle with radius r is y = sqrt(r^2 - x^2), so the equation for the cross-section is x = sqrt(r^2 - y^2). The volume can be found by integrating the area of the cross-section from y = -r to y = r, and then multiplying by 2pi: V_sphere = 2pi * ∫[-r,r] (sqrt(r^2 - y^2))^2 dy
= 2pi * ∫[-r,r] (r^2 - y^2) dy = 4/3 * pi * r^3
The volume of a cylinder with the same radius and height (which is equal to the diameter of the sphere) is V_cyl = pi * r^2 * 2r = 2pi * r^3. The ratio of the volume of the sphere to the volume of the cylinder is: V_sphere / V_cyl = (4/3 * pi * r^3) / (2pi * r^3) = 2/3
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Suppose a fair die is tossed three times. Let X be the number of different faces that appear (so X = 1, 2, or 3). Find px(k) and show all work
Let X be the number of different faces that appear (so X = 1, 2, or 3). The probability mass function of X is px(1) = 1/36, px(2) = 15/36, px(3) = 60/216 = 5/18.
To find the probability mass function px(k), where k is the number of different faces that appear, we can use the combinatorial approach:
When k = 1, there is only one possible combination of outcomes: all three tosses must have the same face, and there are 6 ways to choose which face it is. Therefore, the probability of k = 1 is:
px(1) = (6/6) * (1/6) * (1/6) = 1/36
When k = 2, there are three possible combinations of outcomes: the first two tosses can have the same face and the third a different face, the first and third tosses can have the same face and the second a different face, or the second and third tosses can have the same face and the first a different face.
There are 6 ways to choose which face appears twice and 5 ways to choose which face appears once. Therefore, the probability of k = 2 is:
px(2) = 3 * [(6/6) * (1/6) * (5/6)] = 15/36
When k = 3, there are 3! = 6 possible combinations of outcomes: each of the three tosses can have a different face. There are 6 ways to choose the face for the first toss, 5 ways to choose the face for the second toss, and 4 ways to choose the face for the third toss.
Therefore, the probability of k = 3 is:
px(3) = 6 * (6/6) * (5/6) * (4/6) = 60/216
Note that the probabilities add up to 1:
px(1) + px(2) + px(3) = 1/36 + 15/36 + 60/216 = 1
Therefore, the probability mass function of X is:
px(1) = 1/36
px(2) = 15/36
px(3) = 60/216 = 5/18
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An instructor grades on a curve (normal distribution) and your grade for each test is determined by the following where S = your score. A-grade: Su + 20 B-grade: u + OSS< + 20 C-grade: u-OSS<+ D-grade: -20 SS-O F-grade: S
The formula for a curve grade is based on a normal distribution with the average score being 0.
The formula for each grade is as follows:
A-grade: S + 20
B-grade: S + 10S< + 20
C-grade: S - 10S< + 20
D-grade: S - 20
F-grade: S < 0
The formula is based on a normal distribution with the average score being 0.
For example, if the average score is 50 and your score is 55, then you would receive an A-grade because your score is 5 points above the average. This can be calculated by adding 20 points to your score of 55 resulting in a grade of[tex]75 (55 + 20 = 75)[/tex]. Similarly, if your score is 40, then you would receive a C-grade because your score is 10 points below the average. This can be calculated by subtracting 10 points from your score of 40 resulting in a grade of 30 (40 - 10 = 30).
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determine which side would be greater given 2 triangles with 2 congruent lengths and the measure of the angle inbetween
The SAS congruence criteria, option (c), is the appropriate response. The acronym SAS stands for "side-angle-side," and it denotes that two sides and the included angle of one triangle must be congruent to two sides and the incorporated angle of another triangle for the triangles to be considered congruent.
"Right-angle-hypotenuse-side" (or option a) refers to a particular instance of the SAS criteria that only applies to right triangles.
The acronym ASA (option b) stands for "angle-side-angle," and it denotes that two angles and the included side of one triangle must be congruent with two angles and the included side of some other triangle for the triangles to be considered congruent.
Side-side-side, or SSS (option d), refers to the situation in which all three sides of one triangle are congruent with all three sides of another triangle.
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The question is -
Two triangles are congruent if two angles and the side included between them in one triangle are equal to the two angles and the side included between them in the other triangle. This is known as:
a. RHS congruence criterion
b. ASA congruence criterion
c. SAS congruence criterion
d. SSS congruence criterion
Let A be a 3x4 matrix with reduced row echelon form given by
U= 1021
0112
0000
a1= 2
3
1
a2 = -2
3
-3
In a 3×4 matrix with reduced row echelon form given by U=[1,0,5,1;0,1,1,1;0,0,0,0], where a1=[−1,3,−2], and a2=[2,-3,-1] is given and the value of a3 = [-5, -1, 1, 0], a4 = [-1, -1, 0, 1] .
Since the reduced row echelon form of A has only two pivot columns, the matrix A can have at most two linearly independent columns. We already know that a1 and a2 are linearly independent (neither is a scalar multiple of the other), so we can use them as a basis for the column space of A.
To find a3 and a4, we need to find two vectors that are linearly independent of a1 and a2 and that span the null space of A (i.e., are solutions to the homogeneous equation Ax=0).
To find a basis for the null space of A, we can set the non-pivot columns of A equal to free variables, and then solve for the corresponding pivot variables in terms of the free variables. In this case, the non-pivot columns are columns 3 and 4, so we set x3=t and x4=s for some scalars t and s, and solve for x1 and x2:
x1 = -5t - s
x2 = -t - s
Thus, the general solution to Ax=0 can be written as a linear combination of the vectors [-5, -1, 1, 0] and [-1, -1, 0, 1]. We can check that these two vectors are linearly independent, so they form a basis for the null space of A. We can use them as a3 and a4:
a3 = [-5, -1, 1, 0]
a4 = [-1, -1, 0, 1]
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____The given question is incorrect, the correct question is given below:
Let A be a 3×4 matrix with reduced row echelon form given by U=[1,0,5,1;0,1,1,1;0,0,0,0]. If a1=[−1,3,−2], and a2=[2,-3,-1] Find a3 and a4