The total distance covered by the subway train is 1796.5 m. The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. The equations apply in horizontal dimension are
v₁ = v₀ + at
v₁² = v₀² + 2ax
x = v₀t + ½ at²
Where
v₀ = initial velocityv₁ = final velocitya = accelerationt = timex = distanceA subway train starts from rest at a station.
It accelerates at a rate of 1.60 m/s² for 14.0 s. It runs at constant speed for 70.0 s.It slows down at a rate of 3.50 m/s² until it stops at the next station.Find the total distance covered!
When it accelerates, the distance is
x₁ = v₀t + ½ a₁t₁²
x₁ = 0 + ½ (1.60)(14.0)²
x₁ = 0 + 0.8(196)
x₁ = 156.8 m
The final speed after 14 s is
v₁ = v₀ + at
v₁ = 0 + (1.6)(14.0)
v₁ = 22.4 m/s
The speed later will be constant for t₂ = 70.0 s.
When it moves with a constant speed (22.4 m/s), the distance is
x₂ = v₁t₂
x₂ = 22.4(70)
x₂ = 1568 m
When it slows down until it stops (v₂ = 0), the distance is
v₂² = v₁² - 2a₂x₃
0 = 22.4² - 2(3.5)x₃
22.4² = 2(3.5)x₃
501.76 = 7x₃
x₃ = 71.68 m
The total distance covered will be
x = x₁ + x₂ + x₃
x = 156.8 m + 1568 m + 71.68 m
x = 1796.48
x = 1796.5 m
Hence, the subway train traveled for a total distance of 1796.5 m.
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If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1 thru A7)?
Answer:
A1 = 10 V
A2 = 10 V
A3 = 10 V
A4 = 0 V
A5 = 10 V
A6 = 10 V
A7 = 10 V
Explanation:
The voltage across each ammeter should be the same for each ammeter connected in parallel. Since each ammeter is connected in parallel with the power supply, the reading across each ammeter should be 100 V. Since the actual voltage inputted from the voltage source is 100 V, each ammeter should read 10 V. The only exception is the ammeter connected in series with the other ammeters (A4). Since no circuit or component is connected in series with this ammeter, the reading should be 0 V.
A 238.8 g sample of water at 17.5°C is heated to steam at 118.9°C. How much heat was absorbed?
Answer:
535.3 kJ heat was absorbed.
Explanation:
The heat absorbed by the water can be calculated using the equation:
Q = mLf
where Q is the heat absorbed, m is the mass of the water, Lf is the heat of vaporization, and Lf is the amount of heat required to vaporize a substance at a constant temperature.
The heat of vaporization of water at 100°C is 40.7 kJ/mol. Since 1 mol of water has a mass of 18.02 g, the heat of vaporization per gram of water is 40.7 kJ/mol / 18.02 g/mol = 2.257 kJ/g.
So the heat absorbed by the 238.8 g of water can be calculated as:
Q = 238.8 g * 2.257 kJ/g = 535.3 kJ.
This is the amount of heat energy absorbed by the water to convert from a liquid at 17.5°C to a gas at 118.9°C.
The closed tank was completely filled with carbon tetrachloride when the valve at B was opened, slowly letting the carbon tetrachloride level drop as shown. The valve is then closed and the space within A is a vacuum. Density of carbon tetrachloride is 3.09 slug/ft3. The atmospheric pressure is 14.7 psi.
A) Determine the gage pressure (psi) in the liquid near valve B when h = 33ft
B) Determine at what level h (ft) the absolute pressure in the liquid near valve B will be equal to the atmospheric pressure.
A) The gage pressure (psi) in the liquid near valve B when h = 33ft is: 472.7ps. B) The level h (ft) where the absolute pressure in the liquid near valve B will be equal to the atmospheric pressure is: -14.9ft.
What is gage pressure?
Gage pressure is the pressure of a gas, liquid, or solid measured relative to the atmospheric pressure. It is measured by a device known as a gage, which is typically a tube with a movable spring-loaded diaphragm that is connected to a display or recording device. Gage pressure is typically expressed in units of pounds per square inch (psi) or kilopascals (kPa).
A) The gage pressure (psi) in the liquid near valve B when h = 33ft is:
Pgage = Patm + ρgh
Pgage = 14.7psi + (3.09slug/ft3)(32.2ft/s2)(33ft)
Pgage = 472.7ps
B) The level h (ft) where the absolute pressure in the liquid near valve B will be equal to the atmospheric pressure is:
Pabs = Patm
Pabs = ρgh + Pgage
0 = (3.09slug/ft3)(32.2ft/s2)h + 472.7psi
h = -14.9ft
Since h cannot be negative, the absolute pressure in the liquid near valve B will never equal the atmospheric pressure.
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A man pushes a lawn mower on a level lawn with a force of 211 N. If 50% of this force is directed forward, how much work is done by the man in pushing the mower 5.7 m?
Answer:
I have same doubt
Explanation:
somebody help
Can someone pls answer this question ?
20 Pascal is the correct answer
What is Pressure ?
Pressure is a physical quantity that describes the force per unit area applied to an object defined as the force (F) applied on a surface divided by the area (A) of that surface:
P = F/A Pressure is a fundamental concept in physics and is encountered in many areas of science and engineering, including mechanics, thermodynamics, and fluid mechanics. It is a measure of the average force exerted by a fluid or gas on a surface, and it is often expressed in units of Pascals (Pa) or pounds per square inch (psi). In physics, pressure is an important concept in understanding a wide range of phenomena, including the behavior of gases, liquids, and solids, as well as the transfer of energy through fluids and gases. It is also used in many practical applications, such as in the design of containers and piping systems to safely contain and transport pressurized fluids and gases.
Pressure= rho x g x h=10x2 =20 Pascal
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The stair stepper is a novel exercise machine that attempts to reproduce the work done against gravity by walking up stairs. With each step, Brad (of mass 80 kg) simulates stepping up a vertical distance of 0.15 m with this machine. If Brad exercises for 18 min per day with a stair stepper at a frequency of 50 steps per minute, what total work he does he do each day? The acceleration of gravity is 9.8 m/s^2 . Answer in units of J.
Answer:
Brad does about 105840 Joules (J) of work each day with the stair stepper.
Explanation:
To calculate the work done by Brad, we need to find the force he exerts and the distance he moves against gravity with each step, and then multiply by the number of steps per day.
The force Brad exerts is equal to his weight, which is:
F = mg = (80 kg) x (9.8 m/s^2) = 784 N
The distance Brad moves against gravity with each step is 0.15 m.
The total number of steps Brad takes each day is:
steps = (18 min/day) x (50 steps/min) = 900 steps/day
Now we can calculate the work done by Brad each day as follows:
work = force x distance x number of steps
= (784 N) x (0.15 m) x (900 steps)
= 105840 J
Therefore, Brad does about 105840 Joules (J) of work each day with the stair stepper.
which of these would increase if a second traffic light were attached to the first? assume the cables do not change their lengths.(select all that apply)
a.the tension T1
b.The angle of the cable with tension T2
c. The angle of the cable with tension T1
d.tension t2
Out of the following statement, a.the tension T1 and d.tension t2 would increase if a second traffic light were attached to the first.
The addition of a second traffic light increases the tension in both cables, when two traffic lights are connected, the cable connected to the first light T1 will increase in tension due to the added weight of the second light. The additional weight creates a greater force that must be resisted and so the tension in the cable will increase, similarly the cable connected to the second light, T2 will also increase in tension due to the added weight of the first light.
The angle of the cable with tension T2 will also increase due to the additional force created by the tension in T1. This increase is due to the additional force created by tension inT1, this increase in tension and angle can be seen in the physical world as the cables connected to the two traffic lights stretch and bend to accommodate the additional weight, the increase in tension and angle helps to ensure that the two lights stay secure and remain in the proper position.
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Find parametric equations of the line that passes through the point (1, −4) and is perpendicular to the line with vector equation r(t)= −3 + 2t, 2 + 3t. (Enter your answer as a comma-separated list of equations where x and y are in terms of the parameter t.)
This vector equation in terms of the parameters x and y, resulting in the following parametric equations: x = 1 + 2s, y = -4 - 3s.
What is vector?Vector is a mathematical object that has both a magnitude and a direction. It is typically represented by an arrow and the length of the arrow represents the magnitude and the direction of the arrow represents the direction. Vectors are commonly used to represent physical quantities such as velocity, force, and momentum.
A vector equation for a line is of the form r(t)= (x0, y0) + t(a, b). To find a line that is perpendicular to this line, we need to find another line with a vector equation of the form r(s) = (x0, y0) + s(b, -a).
Since the given point is (1, -4), we can set (x0, y0) = (1, -4). Also, from the given vector equation, we know that (a, b) = (-3, 2). Thus, the vector equation of the line that passes through (1, -4) and is perpendicular to the given line is:
r(s) = (1, -4) + s(2, -3)
We can then rewrite this vector equation in terms of the parameters x and y, resulting in the following parametric equations:
x = 1 + 2s, y = -4 - 3s
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What are the nature and focal length of a lens that will form a real image having one-third the dimensions of an object located 9cm from the lens
A lens that forms a real image one-third the dimensions of an object located 9 cm from the lens is a diverging lens with a negative focal length.
What are the nature and focal length?The nature and focal length of a lens that will form a real image having one-third the dimensions of an object located 9cm from the lens is determined as follows;
The formula for the magnification (m) of an image formed by a lens is given by m = -h' / h,
where;
h is the height of the objecth' is the height of the image.Given that m = 1/3,
we have h' / h = -1/3
Solving for the focal length (f) using the lens formula;
1/f = 1/u + 1/v,
where;
u is the object distancev is the image distance,f = -3u = -27 cm.
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A man pushes a lawn mower on a level lawn with a force of 211 N. If 50% of this force is directed forward, how much work is done by the man in pushing the mower 5.7 m?
Answer:
W = 211 N * 0.5 * 5.7 m = 597.7 Nm.
Explanation:
The work done by the man in pushing the mower is given by the equation, W = F * d, where F is the force applied and d is the displacement.
In this case, the force applied is 211 N, and the displacement is 5.7 m. Since only 50% of the force is directed forward, we can calculate the amount of work done by multiplying the force by 0.5.
Therefore, the work done by the man in pushing the mower is:
W = 211 N * 0.5 * 5.7 m = 597.7 Nm.
5. (3 points) Recall that the Stefan-Boltzmann Law relates the temperature of a blackbody
(T) and the power radiated at its surface (E), according to:
B = GT4
(Note that we have assumed the emissivity is 1, and therefore leave it out of this equation for simplicity).
If a star's surface temperature is 30,000 K, how much power does a square meter of its
surface radiate? Give your answer in scientific notation with units of W/m². Use the
Stefan-Boltzman constant, o= 5.67 x 10^-8 W/m^2(K^4)
The power radiated by a square meter of the star's surface is 5.67 x 10^17 W/m².
What do you mean by Stefan-Boltzmann Law?
The Stefan-Boltzmann Law states that the total energy radiated per unit surface area of a black body in thermodynamic equilibrium is directly proportional to the fourth power of its absolute temperature. This law is a fundamental law of thermodynamics and was first derived by Austrian physicist Josef Stefan in 1879, and later extended by German physicist Ludwig Boltzmann in 1884.
This is calculated by plugging the temperature into the Stefan-Boltzmann Law, as follows:
E = oT^4 = (5.67 x 10^-8)(30,000)^4 = 5.67 x 10^17 W/m².
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An object on a rough horizontal surface has a maximum possible static friction of 3 N and kinetic friction of 2 N. If the object is given a 4-N horizontal push, what is the magnitude of the net frictional force (static plus kinetic frictional forces) acting on the object?
The net frictional force acting on the object on a rough horizontal surface is 5 N.
This is because the maximum static frictional force is 3 N and the kinetic frictional force is 2 N. Therefore, the total of the two forces is 5 N.
The frictional force is always a resistive force between two surfaces in contact that opposes their relative motion. It is a non-conservative force, meaning it does not obey the laws of conservation of energy. The magnitude of the frictional force is dependent on a number of factors, including the nature of the two surfaces in contact, the normal force between them, the speed of the relative motion, and the coefficient of friction between them.
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a researcher wants to measure internal consistency in a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings. which of the following would be the best method to use in measuring internal consistency?
If the researcher wants to measure internal consistency in a test , then the best method to use in measuring the internal consistency is Split Half Reliability .
The Split Half Reliability is defined as a method which is used to measure the internal consistency of a test by splitting the test into two halves and then calculate the correlation between the scores on the two halves of the test .
In this case, the researcher wants to measure the internal consistency of a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings.
Since the test measures two different constructs, the split half reliability may not be able to provide an accurate estimate of internal consistency, because the correlation between the scores on the two halves may be influenced by the different constructs being measured.
The given question is incomplete , the complete question is
A researcher wants to measure internal consistency in a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings. What would be the best method to use in measuring internal consistency ?
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O FIND THE MOMENT OF INERTIA IF MASS is 20kg and radius 2m
The moment of inertia (I) of the given object is 40 kg m².
The moment of inertia of the given body having the mass of 20 kg and radius 2 m can be calculated using the formula:
I = (1/2)× m × r²
where 'm' is the mass of the body and 'r' is the radius.
Putting the values in the above equation :
I = (1/2) × 20 kg × 2m × 2m
I = (1/2) × 20 kg × 4 m²
I = 40 kg m²
So, the moment of inertia of the object given is 40 kg m².
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The Sun radiates a total power of about 4×1026 watts into space. The Sun's radius is about 7×108 meters.
Calculate the average power radiated by each square meter of the Sun's surface. (Hint: The formula for the surface area of a sphere is A=4πr2.)
a. ≈2×108Wm2
b. ≈2×1045Wm2
c. ≈5×1016Wm2
d. ≈6×107Wm2
The average power radiated by each square meter of the Sun's surface is 6 × 10⁷ W/m². therefore option D is correct.
What is radius?Radius is a term used in geometry to describe the length of a line extending from the center of a circle to the edge of the circle. This line is also referred to as the radius of the circle. The radius is half the distance of the diameter, which is the line that goes from one side of the circle to the other. The radius is also used in other shapes such as ellipses, rectangles, and polygons.
This is because the electric field lines radiate outward from the circumference of the ring, and as a result, the electric potential is lower near the circumference and higher further away from the circumference. As one moves closer to the center of the ring, the electric potential decreases.
Given power = 4×10²⁶ watts
Area = 4πr²
= 4π(7×10⁸)²
Area = 6.15752 × 10¹⁸
Average Power = Power/Area
= 4 × 10²⁶/6.157 × 10¹⁸
= 6.496 × 10⁷ W/m²
≈ 6 × 10⁷ W/m²
Thus, the average power radiated by each square meter of the Sun's surface is 6 × 10⁷ W/m². therefore option D is correct.
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Which of these statements is true of how a medium absorbs a wave’s energy?
A. The amount of energy absorbed by a medium only depends on a wave’s direction.
B. The amount of energy absorbed by a medium only depends on a wave’s frequency.
C. The amount of energy absorbed by a medium can depend on a wave’s properties.
D. The amount of energy absorbed by a medium only depends on how long a wave has been traveling.
Answer:
C. The amount of energy absorbed by a medium can depend on a wave's properties.
Explanation:
The statement that is true of how a medium absorbs a wave's energy is:
C. The amount of energy absorbed by a medium can depend on a wave's properties.
When a wave travels through a medium, the medium can absorb some of the wave's energy, which can cause the wave to weaken or decrease in amplitude. The amount of energy that is absorbed by the medium can depend on various factors, such as the properties of the medium, the frequency and wavelength of the wave, and the intensity of the wave. For example, certain materials may be more effective at absorbing certain wavelengths of light, while others may be more effective at absorbing sound waves of specific frequencies. Therefore, the amount of energy absorbed by a medium can depend on the properties of the wave as well as the medium it is traveling through.
A geologist finds that a moon rock whose mass is 8.88 kg has an apparent mass of 5.97 kg when submerged in water. What is the density of rock?
The Density of rock=(6315 kg/m^3)
It is a universal fact that the mass of an object remains constant whether measured on earth or on the moon.
Mass of rock on moon/earth = 7.2
Loss in weight =7.02 - five.88 = 1.14 kg = 1140g
As we know that water has a density of 1g/cm^3 (1000kg/m^3)
The volume of water = volume of the rock
= Mass/density;
=1140 cm^3
density of rock = mass/extent = 7200/1140 = 6.315 g/cm^3
Density of rock=(6315 kg/m^3)
Density (volumetric mass density or particular mass) is the substance's mass in line with a unit of extent. The symbol most usually used for density is ρ (the decreased case Greek letter rho), despite the fact that the Latin letter D also can be used. Mathematically, density is described as mass divided with the aid of volume.
The density of fabric varies with temperature and stress. this variation is usually small for solids and drinks but a whole lot greater for gases. increasing the strain on an object decreases the quantity of the object and therefore will increase its density. increasing the temperature of a substance (with some exceptions) decreases its density via increasing its quantity. In most materials, heating the bottom of fluid outcomes in convection of the warmth from the bottom to the pinnacle, due to the lower density of the heated fluid, which motivates it to rise relative to denser unheated material.
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Complete question:
A geologist finds that a moon rock whose mass is 7.2 kg has an apprant mass 5.88kg when submerged in water what is the density of rock.
A cannon is fired horizontally with a velocity of 125 m/s from a castle wall that is 250 m tall. a) How far from the wall does the cannon ball land?
b) With what velocity (v f and θ) does the cannon ball hit the ground?
c) What is the acceleration of the cannon ball just before it hits the ground?
(a) The horizontal distance traveled is 1940 m.
(b) The final velocity and the angle with which the cannon hits the ground are of the cannon is 180.07 m/s and 63.4⁰ respectively.
(c) The acceleration of the cannon ball just before it hits the ground is 29.44 m/s².
What is the time of flight of the cannon?The time of flight or time of motion of the cannon is calculated as follows;
t = √ ( 2h / g )
where;
h is the height g is acceleration due to gravityt = √(2 x 250 / 9.8 )
t = 15.6 s
The horizontal distance traveled can be found using the velocity and time of flight,
Horizontal distance (d) = vt
d = 125 m/s x 15.6 s
d = 1940 m
The final velocity of the cannon is calculated as ;
Vertical velocity (v fy ) = gt
v = 9.8 x 15.6 s
v = 153.68 m/s
v f = √(Vx² + Vy²)
vf = √ (125² + 153.68²)
vf = 180.07 m/s
θ = arc tan ( Vy / Vx )
θ = arc tan (153.68 m/s / 125 m/s)
θ = 63.43°
The acceleration of the cannon ball just before it hits the ground can be calculated using the final velocity and the time of flight,
a = (v f² - v i²) / (2t)
a = (180.07² - 0²) / (2 x 15.6 s)
a = 29.44 m/s²
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Ventilation removes steam, smoke, grease, and heat from food-preparation areas and equipment, helps maintain indoor
air quality, and reduces the possibility of fires from accumulated grease.
True
False
True, Ventilation removes steam, smoke, grease, and heat from food-preparation areas and equipment, helps maintain indoor air quality, and reduces the possibility of fires from accumulated grease.
What should ventilation in locations where food is prepared get rid of?
An efficient ventilation system is made to eliminate smoke, fumes, and airborne oil from the kitchen while minimizing cooking odors. When constructing the ventilation system, an establishment's various cuisines, cooking styles, and equipment must be taken into account.
There are many ventilation requirements in the food processing industry, including heating and cooling to maintain room temperatures for both workers and the product, ventilation of produce to prevent premature aging, odor control, freezer recirculation air, caustic gas removal, or air turnover during wash-down cycles.
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Consider a circular ring of radius r,uniformly charged with linear charge density λ. Find the electric potential at a point on the axis at a distance x from the centre of the ring. Using this expression for the potential, find the electric field at this point.
The electric potential at a point on the axis at a distance x from the centre of the ring = k (q/r). And
The electric field at a circular ring of radius r, uniformly charged with linear charge density λ = (1/ 2€⁰) (rλ /r² + x² ) ⅔
Resolution of the electric field into its vertical and horizontal components. Vertical components cancel out while horizontal components add because the ring is symmetric.
From the figure, we can determine the circumference of the ring:
L = 2πr
Hence, electric field at P:
(1/ 2€⁰) (rλ /r² + x² ) ⅔
Where,
k = 9 x 10⁹
r = radius of the ring
λ = charge density
x = distance of the point
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If we double the root-mean-square speed (thermal speed) of the molecules of a gas, then A) its temperature must increase by a factor of 4. B) its temperature must increase by a factor of 2. C) its temperature must increase by a factor of . D) its pressure must increase by a factor of 2.
Radiotherapy techniques, when changing the dose rate, people see ?
a. Threshold dose to biological effect increases if dose efficiency decreases
b. Threshold dose to biological effect increases if dose efficiency increases
Radiotherapy techniques, when changing the dose rate, people see threshold dose to biological effect increases if dose efficiency decreases.
What is Radiotherapy?High doses of radiation are used in radiation therapy, also known as radiotherapy, as a cancer treatment to eradicate cancer cells and reduce tumour size. As with x-rays of your teeth or shattered bones, radiation is utilised at low doses in x-rays to see inside your body.
Radiation therapy damages cancer cells' DNA, which either kills them or limits their growth at high dosages. Cancer cells that have DNA damage that cannot be repaired either cease proliferating or die.
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1+0.5+1+2-4.5 What is gravitation? What is the value of acceleration due to gravity 'g' at polar region? The weight of a body is 600 N on the earth's surface. If the mass and radius of the earth are 6x10kg and 6.4x10 km respectively, calculate the mass of the body. के तो?
Answer:
The result of 1 + 0.5 + 1 + 2 - 4.5 is 0.
Gravitation is the force of attraction between two masses. It is the force that causes objects to fall to the ground and keeps planets in orbit around the sun.
The value of acceleration due to gravity 'g' at the polar region is approximately 9.8 m/s^2.
The weight of a body is directly proportional to its mass. Hence, to calculate the mass of a body with a weight of 600 N on the surface of the Earth, you can use the formula: mass = weight / g, where g is the acceleration due to gravity (approximately 9.8 m/s^2 at the Earth's surface). The mass of the body would be approximately 61.2 kg.
A man pushes a lawn mower on a level lawn with a force of 186 N. If 26% of the force is directed horizontally, how much work is done by the man in pushing the mower 6.5 m?
Answer:
W = 48.36 x 6.5 = 314.34 J.
Explanation:
The work done by the man in pushing the mower is the force multiplied by the displacement. Since 26% of the force is directed horizontally, we can calculate the amount of force that is directed horizontally as 0.26 x 186 N = 48.36 N. The work done is then calculated as W = F x s, where F is the horizontal force and s is the displacement. Therefore, the work done by the man in pushing the mower 6.5 m is W = 48.36 x 6.5 = 314.34 J.
Answer:
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Explanation:
the volume and pressure of a gas are 7.80 m3 and 2.10 atm, respectively. (a) if this gas expands to one and one-half its initial volume while the pressure is constant, determine the work done on the gas. j (b) on the other hand, if this gas is compressed to two-fifths its initial volume while the pressure is constant, determine the work done on the gas.
(a) The work done on the gas when it expands to one and one-half its initial volume while the pressure is constant is 2.92 x [tex]10^5[/tex] J.
(b) The work done on the gas when it is compressed to two-fifths its initial volume while the pressure is constant is 3.74 x [tex]10^5[/tex] J.
Work done on a gas can be calculated using the equation:
W = -PΔV
where P is the pressure, ΔV is the change in volume, and W is the work done.
In this case, the pressure is constant at 2.10 atm, which is equivalent to 2.10 x [tex]10^5[/tex]Pa.
For (a), the initial volume is 7.80 m^3 and the final volume is 1.5 times the initial volume, which is 11.70 m^3. The change in volume is 11.70 - 7.80 = 3.90 [tex]m^3[/tex]. So, the work done on the gas is W = -PΔV = -(2.10 x [tex]10^5[/tex]) x (3.90) = 2.92 x [tex]10^5[/tex] J.
For (b), the final volume is two-fifths the initial volume, which is 3.12 m^3. The change in volume is 7.80 - 3.12 = 4.68 [tex]m^3[/tex]. So, the work done on the gas is W = -PΔV = -(2.10 x [tex]10^5[/tex]) x (4.68) = 3.74 x [tex]10^5[/tex] J.
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physics covers______
A man carries 20 tiles from the ground to the roof of a house. Each tile has a mass of 1.2 kg. The roof of the house is 15 m above the ground.How much work does the man do against gravity on the tiles in carrying them to the roof?
Answer:
3531.6 J
Explanation:
Work = Force x distance
the force is equal to the gravitational force, which is mg.
the distance equals the height h
W = mg x h = (1.2)(9.81)(15) = 176.58 J
but, this is only the work on 1 tile, so we multiply this by 20 to get 3531.6 J
which a car can travel along a curved road with a radius of curvaturer, in feet. To the nearest whole number, find The formula v= /2.5r can be used to estimate the maximum safe velocity v, in miles per hour, the radius of curvature if the maximum safe velocity is 35 miles per hour. a. 3063 ft b. 490 ft c. 196 ft d. 1225 ft
The radius of curvature when the maximum safe velocity is 35 miles per hour is 14 feet. The answer is c. 196 ft.
What is velocity?Velocity is a vector quantity that describes both the speed and direction of an object's motion. It is measured in units of distance per unit of time, such as meters per second or miles per hour.
The formula v = 2.5r can be used to estimate the maximum safe velocity v, in miles per hour, given a radius of curvature r, in feet.
To find the radius of curvature when the maximum safe velocity is 35 miles per hour, we can solve the equation for r:
r = v/2.5
Substituting 35 for v, the radius of curvature is:
r = 35/2.5
r = 14
Therefore, the radius of curvature when the maximum safe velocity is 35 miles per hour is 14 feet. The answer is c. 196 ft.
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determine the direction of the electric field at the given observation points (point p) inside insulators and conductors with charge distributions as shown.
In insulator electric field is zero and direction of electric field is away from the center.
In a insulator (dielectric) there are no (not very many) portable charge transporters thus the outer electric field mutilates the electron shells around the cores so the iota behaves like a dipole.
Every one of the electrons are as yet bound to cores yet the "middle" of the electron cloud is as of now not incidental with the place of the core.
The actuated dipoles are arranged and produce a prompted electric field contrary to the initiating electric field. The general permittivity of the medium is a proportion of how well the initiated field goes against the outer inciting field.
So the higher the permittivity the more modest is the electric field inside the protector.
Affected by an outer electric field the versatile charge transporters in a transmitter improve themselves (the portable charge transporters really move inside the grid) so the prompted electric field that they produce is equivalent in extent and inverse in heading to the outside initiating field with the outcome that there is no electric field inside the channel - relative permittivity is boundless.
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Which of the following is true for the wavelength of the photon emitted when an electron in a hydrogen atom jumps from the ni=70 state to the nf=2 State as compared to the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state?A. It is longerB. It is shorterC. They are equalD. The wavelength of the photon is not related to the change in state.
The true statement among the following for the wavelength of a photon emitted when an electron in a hydrogen atom jumps from ni=70 state to the nf=2 is option B. it is shorter.
A photon is a particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.
Using the below giving equation we can find out the wavelength of the photon emitted when an electron in a hydrogen atom jumps from a higher energy state to a lower energy state
λ = [tex]R_{H}[/tex] × (1/ni² - 1/nf²)
where [tex]R_{H}[/tex] is the Rydberg-constant and ni is the initial quantum number and nf is the final quantum number.
First case, the wavelength of the photon emitted when an electron jumps from the ni=70 state to the nf=2 means
λ(70 to 2) = [tex]R_{H}[/tex]* (1/70² - 1/2²)
And then the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state can be calculated as:
λ(4 to 2) = [tex]R_{H}[/tex] * (1/4² - 1/2²)
When we consider these two, we will get that the wavelength of the photon emitted when an electron jumps from the ni=70 state to the nf=2 state is longer than the wavelength of the photon emitted when the electron jumps from the ni=4 state to the nf=2 state.
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