A student works a problem and finds that a compound has 0.074 moles of carbon and 0.148 moles of oxygen. What is the empirical formula of the compound?​

The statement that is true about the carbon is the correct option is d) it can form both polar and nonpolar bonds.

The atomic number of the carbon is 6. The carbon can form the nonpolar covalent bonds when the carbon bonds to itself, like as in graphene and the diamond. The carbon forms the polar covalent bonds with the elements that have the  slightly more electronegativity. The example of the polar bon is the carbon and the oxygen bond is the polar covalent bond.

Thus, the carbon can form the polar bond as well it can form the non polar bond.

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2.55 moles of aluminum hydroxide in grams is 198.9grams.

The number of moles can be converted to mass using the following expression:

mass = number of moles × molar mass

According to this question, 2.55 moles are present in aluminium hydroxide. It can be converted to mass as follows:

Molar mass of aluminum hydroxide = 78g/mol

Mass = 78g/mol × 2.55 mol

mass = 198.9grams

Hence, 198.9grams is the mass present in 2.55 moles of aluminum hydroxide.

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Answer:

approx. 5.0 x10^24 atoms

Explanation:

The molar mass of water is 18.02g/mol

50 grams of water contains 50g x 1 mole/18.02g moles of water

2.775 moles H2O

1 mole of H2O contains 6.022 x 10^23 molecules of water

2.775 moles of H2O contains 2.775 x 6.022 x 10^23 molecules of H2O

= 1.6711 x 10^24 molecules of H2O

1 molecule of H2O contains 3 atoms

Therefore 1.6711 x 10^24 molecules contains 1.6711 x 10^24 x 3 atoms

= approx. 5.0 x10^24 atoms

Answer:

Explanation: When water temperatures rise, or fall, this can irritate, and stress the coral polyps, causing them to lose the algae that lives in the polyp's tissues.

Answer:

Coral reef species may be significantly impacted by a shift in water temperature. Coral bleaching is a condition when the coral expels their symbiotic algae, resulting in a loss of color and perhaps mortality. Sudden temperature fluctuations, especially rises, can induce coral bleaching. The prevalence of illnesses in corals and other reef species can also rise in response to an increase in water temperature. The distribution and behavior of fish and other species might change in response to temperature changes, possibly upsetting the delicate balance of the reef ecosystem. These effects may result in a reduction in the coral reef's biodiversity and general health.

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The formula of X is  Cu₂O and the formula of Y is CuO.

The masses of X and Y that can react with 0.5 g of oxygen are 4.0 g and 2.0 g of copper respectively.

The law that is illustrated by the result above​ is the law of multiple proportions.

The law of multiple proportions states that when two components combine to generate more than one compound, the combined weights of each element are in a ratio of tiny whole numbers.

The mole ratio of copper and oxygen in X and Y are:

X --> 1.365/64 : 0.17/16 = 0.02 : 0.01

mole ratio = 2 : 1

The formula of X is Cu₂O

Y ---> 1.16/64 : 0.29/16 = 0.02 : 0.02

mole ratio = 1 : 1

The formula of Y is CuO

The masses of X and Y that can react with 0.5 g of oxygen are calculated as follows:

Mass of copper to yield X = 0.5/16 * 2 * 64 = 4.0 g

Mass of copper to yield Y = 0.5/16 * 64 = 2.0 g

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A tire has a pressure of 325 kPa at 10°C, the new pressure of tire is 285 Pka by using formula P1T1 = P2T2

Initial pressure = 325 kPa

Initial temperature = 10°C

Final temperature = 50°C

As given that the volume is constant.

Now, P1T1 = P2T2

P2 = P1T1 / T2

P2 = 325 kPa x 10 + 273 K / 50 + 273 K

P2 = 285 Pka

Thus, a tire has a pressure of 325 kPa at 10°C, the new pressure of tire is 285 Pka.

What is pressure?

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The balanced chemical equation for the combustion of liquid hexane in oxygen gas is: C6H14(l) + 19O2(g) -> 6CO2(g) + 14H2O(g)

In this equation, hexane (C6H14) is a liquid reactant and oxygen gas (O2) is a gaseous reactant. The products, carbon dioxide (CO2) and water vapor (H2O), are both in the gaseous state. To balance the equation, the coefficient 19 was used for the oxygen gas to ensure that the number of oxygen atoms in the reactants and products is equal. Similarly, the coefficients 6 and 14 were used for the carbon dioxide and water vapor, respectively, to balance the number of carbon and hydrogen atoms in the equation.

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There will be no reaction between aniline and NaH as both are base. The Arrhenius definitions of acid and base is restricted to compounds capable of producing H+ and OH ions.

The bronsted definitions of acid and base is restricted to compounds capable of producing H+ and OH ions within aqueous solutions. Although this is beneficial since water is indeed a liquid substance, it doesn't explain why some chemicals are acidic or basic.

In 1923, chemist Johannes Brnsted and English scientist Thomas Lowry introduced new definitions of acids and bases that focused on proton transport separately. Any species that may give a protons (H+) to some other molecule is referred to as a Brnsted-acid. There will be no reaction between aniline and NaH as both are base.

Therefore, there will be no reaction between aniline and NaH as both are base.

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The percent yield for the reaction is 84.6%.

To calculate the percent yield for the reaction, we first need to determine the theoretical yield of CO₂ based on the balanced chemical equation for the reaction:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

From the equation, we can see that for every mole of C₃H₈ , 3 moles of CO₂ are produced. So, to determine the theoretical yield of CO2, we need to first convert the mass of C₃H₈ to moles and then multiply that by the stoichiometric ratio for CO₂.

The molar mass of C₃H₈ is 44.1 g/mol, so:

3.66 g C₃H₈ / 44.1 g/mol = 0.083 mol C₃H₈

Using the stoichiometry of the reaction, we can now calculate the theoretical yield of CO₂:

0.083 mol C₃H₈ × 3 mol CO₂ / 1 mol C₃H₈ = 0.25 mol CO₂

And the theoretical mass of CO₂:

0.25 mol CO₂ × 44.01 g/mol = 11.0025 g CO₂

Finally, the percent yield of the reaction can be calculated as:

9.31 g CO₂ / 11.0025 g CO₂ × 100% = 84.6%

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If a container weighs exactly 10 grams, this mass show up on an analytical balance in 10.0000 grams.

The accuracy of measurement done with an analytical balance is more trustworthy when based on significant figures.

A unique kind of weighing scale known as an analytical balance is known for being able to measure very small things' masses down to milligrams. It is made up of a scale and a clear glass case.

Using an analytical balance to calculate the weight will increase the precision of the calculation because it calculates the mass to more precise significant figures.

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High insulation resistance, high dielectric strength, low dielectric constant, low dielectric loss at all frequencies, strong resistance to cold flow, and exceptional abrasion resistance are only a few of the outstanding electrical qualities.

On telephone signal and control cables, high frequency electronic cables, high and low voltage power cables, line wire, neutral supported secondary, and service drop cable, polyethylene is frequently used as insulation.

In comparison to polyethylene resins, polypropylene is less dense. This polymer's chemical, electrical, and electrical characteristics are comparable to those of polyethylenes. Its fluid resistance is a little higher. It has a somewhat lower dielectric constant than LDPE.

Compared to polyethylene, polypropylene is significantly stiffer and tougher. Additionally, its elasticity at low temperatures is not great. If antioxidants are not present, heat and light can cause it to deteriorate.

Therefore, High insulation resistance, high dielectric strength, low dielectric constant, low dielectric loss at all frequencies, strong resistance to cold flow, and exceptional abrasion resistance are only a few of the outstanding electrical qualities.

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The mass of KOH needed to dissolve in 500 mL of water to produce a pH of 12.40 is 0.7 grams

We'll begin by obtaining the pOH of the solution. Details below:

pH + pOH = 14

12.40 + pOH = 14

Collect like terms

pOH = 14 - 12.40

pHO = 1.6

Next, we shall determine the hydroxide ion concentration [OH⁻] of the solution. Details below:

pOH = -Log [OH⁻]

1.6 = -Log [OH⁻]

Multiply through by -1

-1.6 = Log [OH⁻]

Take the anti-log of -1.6

[OH⁻] = Anti-log -1.6

[OH⁻] = 0.025 M

Next, we shall determine the molarity of KOH. details below:

KOH(aq) <=> K⁺(aq) + OH¯(aq)

From the balanced equation above,

1 mole of KOH contains 1 mole of OH¯

Therefore,

0.025 M Pb(CH₃COO)₂ will also contain 0.025 M OH¯

Next, we shall determine the mole of KOH in the solution. Details below:

Molarity = Mole / Volume

Cross multiply

Mole = molarity × volume

Mole of KOH = 0.025 × 0.5

Mole of KOH = 0.0125 mole

Finally, we shall determine the mass of KOH needed. Details below:

Mole = mass / molar mass

0.0125 = Mass of KOH / 56

Cross multiply

Mass of KOH = 0.0125 × 56

Mass of KOH = 0.7 grams

Therefore, the mass of KOH needed is 0.7 grams

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Answer:

Mass number

Explanation:

All atoms of the same element have the same number of protons, but some may have different numbers of neutrons, which would cause a different mass number

Answer:

The answer is mass number

To determine the numerical value of the reaction, for the reactions investigated in this experiment by the equation Hrxn = q r xn / n,

The numerical value of the theoretical heat of reaction (dhrxn) can be determined using the equation qrxn = mc∆T, where qrxn is the heat of reaction, m is the mass of the water, c is the specific heat capacity of the water, and ∆T is the change in temperature. In this experiment, the initial temperature of the water used in the calorimeter is 72 degree Celsius. Thus, to calculate the dhrxn, the mass of the water and the final temperature of the water after the reaction can be used. The change in temperature (∆T) is the difference between the initial temperature of the water and the final temperature of the water. To determine the final temperature of the water, the heat released by the reaction must be measured using a calorimeter. This can be done by recording the temperature of the water at different intervals until the reaction is complete. After the heat of reaction is determined, the dhrxn can be calculated using the equation qrxn = mc∆T.

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Answer:

3.82 g.

Explanation:

To calculate the mass of sulfuric acid produced from 1.25 g of sulfur, we'll have to balance the chemical equations and use stoichiometry.

Starting with the first reaction:

2S(s) + 3O2(g) → 2SO3(g)

Since 1.25 g of sulfur is reacted, the number of moles of sulfur can be calculated as:

moles = mass / molar mass = 1.25 g / 32 g/mol = 0.03906 mol

Next, using the mole ratio from the balanced chemical equation, we can find the number of moles of sulfur trioxide produced:

2 moles of sulfur produce 2 moles of sulfur trioxide, so:

moles of SO3 = moles of S x (moles of SO3 / moles of S) = 0.03906 mol x (2 mol / 2 mol) = 0.03906 mol

Finally, we move on to the second reaction, the dissolution of sulfur trioxide in water:

SO3(g) + H2O(l) → H2SO4(l)

Using the mole ratio from this balanced equation, we can find the number of moles of sulfuric acid produced:

1 mole of sulfur trioxide reacts with 1 mole of water to produce 1 mole of sulfuric acid, so:

moles of H2SO4 = moles of SO3 x (moles of H2SO4 / moles of SO3) = 0.03906 mol x (1 mol / 1 mol) = 0.03906 mol

The mass of sulfuric acid produced can be calculated using the moles and the molar mass of sulfuric acid:

mass = moles x molar mass = 0.03906 mol x 98 g/mol = 3.82 g

Therefore, if 1.25 g of sulfur is reacted, the mass of sulfuric acid produced is approximately 3.82 g.

Heating a cup of tea before adding a spoonful of sugar would increase solubility. Therefore, the correct option is option D.

Solubility in chemistry refers to a material's capacity to create a solution with that other substance, the solvent. The incapacity of the solute to produce such a solution is referred to as insolubility.

The concentration of a solute inside a saturated solution, where no more solute could be dissolved, is used to determine the extent of a substance's solubility in a certain solvent. The two compounds are considered to be in solubility equilibrium at this moment. Heating a cup of tea before adding a spoonful of sugar would increase solubility.

Therefore, the correct option is option D.

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The new pressure of the oxygen in the container is approximately 8.74 atm.

According to the Ideal gas Law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in kelvins. We can use this equation to solve for the new pressure, as long as we know the other variables.

First, we need to find the number of moles of oxygen in 300 cm³. We can use the ideal gas law to convert cm³ to liters and find the number of moles:

V = 300 cm³ = 0.3 L

R = 8.31 J/ mol·K

T = (273 + 20) K = 293 K (room temperature)

n = PV / RT = (10 × 0.3) / (8.31 × 293) = 0.001054 moles

Next, we need to find the new volume of the oxygen, given the container size. We can convert the 5.0 dm² container to cm² and find the volume:

V_container = 5.0 dm² × 10⁴cm²/dm² = 5.0 × 10⁴ cm³

V_new = V_container - V = 5.0 × 10⁴ - 0.3 = 49999.7 cm³

Finally, we can use the ideal gas law to find the new pressure:

P_new = (nRT) / V_new = (0.001054 × 8.31 × 293) / (49999.7 / 10³) = 8.74 atm

So, the new pressure of the oxygen in the container is approximately 8.74 atm.

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The number of moles in butane C4H10 in 151gm of butane is 2.605 moles.we can do this with the help of molecular weights of C,H.

To calculate the number of moles in 151 grams of butane (C4H10), we need to determine the molecular weight of butane. The molecular weight of butane can be calculated using the atomic masses of its elements:

1 mole of C = 12 g 1 mole of H = 1 g

So, the molecular weight of butane can be calculated as: 4 moles of C * 12 g/mole + 10 moles of H * 1 g/mole = 4 * 12 + 10 * 1 = 48 + 10 = 58 g/mole

Now that we know the molecular weight of butane, we can use it to calculate the number of moles in 151 grams of butane:

151 g of butane / 58 g/mole = 2.605 moles

Therefore, there are 2.605 moles of butane in 151 grams of butane.

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In the given chemical equation, oxidation takes place at anode  of the electrochemical cell .

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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The molecular formula is C4H8 of a hydrocarbon has a molar mass between 50 and 60 g/mol.

Mass of CO2 = 3.14 grams

Mass of H2O = 1.28 grams

Molar mass = 50 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles CO2

Moles = mass / molar mass

Moles CO2 = 9.603 grams / 44.01 g/mol

Moles CO2 = 0.218 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.218 moles CO2 we have 0.218 moles C

Step 4: Calculate mass C

Mass C = 0.218 moles * 12.01 g/mol

Mass C = 2.618 grams

Step 5: Calculate moles H2O

Moles H2O = 1.573 grams / 18.02 g/mol

Moles H2O = 0.0873 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.0873 moles H2O we have 2* 0.0873 = 0.1746 moles

Step 7: Calculate mass H

Mass H = 0.1746 moles * 1.01 g/mol

Mass H = 0.176 grams

Step 8: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.218 moles / 0.1746 moles = 1.25

H: 0.1746 moles / 0.1746 moles =  1

The molecular formula is C4H8.

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When all the atoms in a molecule have the same atomic number, the substance is an element. If their atomic numbers differ, it is a compound.

Elements are pure substances that contain only one type of atom. Compounds are substances formed by the chemical union of two or more different types of elements in fixed proportions. There are currently nearly 118 elements, of which nearly 94 occur naturally on Earth.

An element is a substance that cannot be broken down into chemically simpler components. Aluminum is a chemical element that is found in soda cans. A compound is a substance that can be broken down into chemically simpler components.

Thus,the chemist conclude whether the substance is an element or a compound

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A chemist can conclude whether the sample is an element or compound by some qualitative tests. If it is  compound it gives positive results for multiple elements.

Compounds are formed by the combination of atoms of different elements. It can be pure substance or mixture. There are different kinds of compounds such as ionic compound, covalent compound , coordination compounds etc.

Elements are pure substance which cannot be split to its constituents. Hence, we can test by some qualitative techniques to identify whether the substance is a mixture or pure substance.

If the tests are giving positive results for multiple elements it is a compound. If it is a mixture it can be separated using techniques such as distillation, chromatography etc.

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At 0.752 atm of H2S and 1073 K, [H2] = 4.94 x 10^-12 mol/L and [S2] = 4.24 x 10^-5 mol/L. At 0.20 atm of H2 and 0.40 atm of S2, [H2] = 1.67 x 10^-12 mol/L and [S2] = 4.68 x 10^-5 mol/L.

The reaction for the decomposition of hydrogen disulfide (HS) is:

2 H2S (g) <=> 2 H2 (g) + S2 (g)

The equilibrium constant (Kc) at 1073 K is 2.0 x 10^-23.

1) At the initial conditions of 0.752 atm of H2S and the temperature of 1073 K, the equilibrium concentrations can be calculated using the equation:

Kc = [H2]^2 / [S2].

Rearranging the equation to solve for [H2], we get:

[H2]^2 = Kc * [S2]

[H2] = sqrt(Kc * [S2])

Since the initial pressure of H2S is 0.752 atm, we can convert it to concentration using the ideal gas law:

P = nRT/V, where n = number of moles, R = gas constant (8.31 J/mol*K), T = temperature (1073 K), and V = volume.

Since n = PV/RT, [H2S] = P/RT.

[H2S] = 0.752 atm / (8.31 J/mol*K * 1073 K) = 8.48 x 10^-5 mol/L.

[S2] = [H2S] / 2 = 4.24 x 10^-5 mol/L.

[H2] = sqrt(2.0 x 10^-23 * 4.24 x 10^-5) = 4.94 x 10^-12 mol/L.

2) At the new initial conditions of 0.20 atm of H2 and 0.40 atm of S2, the new equilibrium concentrations can be calculated using the Kc expression:

Kc = [H2]^2 / [S2].

[H2] = sqrt(Kc * [S2]) = sqrt(2.0 x 10^-23 * (0.40 atm / (8.31 J/molK * 1073 K))) = 1.67 x 10^-12 mol/L.

[S2] = 0.40 atm / (8.31 J/molK * 1073 K) = 4.68 x 10^-5 mol/L.

These are the new equilibrium concentrations at the new initial pressures and temperatures.

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The complete Question is:

Consider the reaction for the decomposition of hydrogen disulfide:         2H2S W=23 H2 = S2t Ko-2. Ax10 at 1073 K. A reaction vessel initially contains 0.752 atm of H2S at 1073K. Find the equilibrium concentrations of H2 and S2. The reaction in question 2 is then carried out at the same temperature but the initial pressures were 0.20 atm for H2 and 0.40 atm for S2. Calculate the equilibrium concentrations.

92% percentage of the iceberg was under water.

The percentage of an iceberg that is under water can be calculated by finding the ratio of the submerged portion of the iceberg to its total volume, and converting this ratio to a percentage. To do this, we need to know the density of the ice and water and the densities of both materials.

If the density of water is 1.0 g/cm3 and the density of ice is 0.92 g/cm3, then the iceberg will float in water. The portion of the iceberg that is above water will have a volume equal to the difference in the volumes of the water displaced and the portion of the iceberg that is above water.

Let V be the volume of the iceberg, and Vw be the volume of water displaced. Then, the portion of the iceberg that is above water will have a volume of V - Vw. The portion of the iceberg that is below water will have a volume of Vw. The percentage of the iceberg that is under water is given by:

Density of water = 1g/cm^3

Density of Ice = 0.921g/cm^3

ρ(ice)V(ice) = ρ(water)V(water)

so, V(water) =(ρ(ice)V(water))/ ρ(water)

or, V(water) = 0.92V(water)/1.0

V(water) = 0.92V(ice)

So, 92% percentage of the iceberg was under water.

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The given relative mass formula is correct. The weight in grams of the number of atoms of an element contained in 12.00 g of carbon-12 is known as the relative atomic mass of the element.

The ratio of an element's average atomic mass to the unified atomic mass unit is the relative atomic mass, or Ar. The average mass of an element's isotopes is used to calculate the relative atomic mass.

Absolute mass is the total mass of all protons and neutrons, whereas relative mass is the average atomic mass of all the isotopes present in a given percentage. As an illustration, the average atomic mass of carbon, calculated using the proportions of the isotopes C-12, C-13, and C-14, is 12.01 while the absolute mass of carbon is 12.0 amu.

An element's mass number is determined by the sum of its proton and neutron counts: Protons and neutrons together make up mass.

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Answer:

Her speed is 6.8m/s.

Explanation:

K.E= 1/2mv²

or, 2543.2= 1/2×110×v²

or, 2543.2 = 55v²

or, 2543.2/55 = v²

or, 46.24 = v²

or, 6.8² = v²

v = 6.8 m/s

answer

6.8

explanation

k.e=1/2v^2

2543.2=55v^2

46.24=v^2

6.8^2=v^2

v=6.8

The NMR signal at 2.10 ppm is more deshielded, meaning it is more chemically shift shifted to a higher field compared to the signal at 1.15 ppm. That is due to protons that are closer to electronegative atoms.

In the 1H NMR spectrum of a product, the chemical shift of the signals provides information about the environments of the protons in the molecule. The signal at 2.10 ppm is more deshielded compared to the signal at 1.15 ppm, meaning that it is shifted to a higher field. This indicates that the protons responsible for the signal at 2.10 ppm are closer to electronegative atoms or are experiencing a strong inductive effect, leading to greater electron density around the nucleus and hence a more deshielded signal. On the other hand, the signal at 1.15 ppm is due to protons that are further away from electronegative atoms or experiencing weaker inductive effects, resulting in less electron density around the nucleus and a less deshielded signal. Understanding the chemical shifts in 1H NMR spectra requires knowledge of the molecular structure and the environments of the protons in the molecule.

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The flame test can be effectively used to identify a cation in a solution because when a cation is placed in a flame, it will emit a different color with

visibile light.

Ions are charged particles that form when atoms gain or lose electrons. When an atom gains electrons, it forms negatively charged ions called negative ions. On the other hand, positively charged ions, called cations, are formed when atoms lose electrons. These ions can be detected in solution using special tests. The flame test involves exposing a joint to a flame and identifying the joint by flame color. The color of the flame test is due to the fact that electrons in metal cations are excited and jump to higher energy levels.

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According to unit conversion, 11.9 mg of sodium should be consumed by an average adult according to the data.

Unit conversion is defined as a multi-step process which involves multiplication or a division operation by a numerical factor.The process of unit conversion requires selection of appropriate number of significant figures and the rounding off procedure.

It involves a conversion factor which is an expression for expressing the relationship between the two units.A conversion ratio always has value which equals to one which indicates that numerator and denominator have values which are expressed in different units.

7% of 170 that is 7/100×170=11.9 mg.Thus, 11.9 mg of sodium should be consumed by an average adult according to the data.

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Answer:

answer is one

Explanation:

valency is the amount of electrons on the last shell

Polar water molecules have partial positive and negative charges on their both the ends. Because of their diametrically opposed charges, water molecules are drawn to one another by ionic bonds.

The main interaction taking place in ionic compounds is ionic bonding, a form of chemical bonding that includes the electrostatic attraction between two atoms or ions with dramatically differing electronegativities.

An atom may establish bonds with other atoms in two main ways. They are covalent and ionic. The sharing of electrons between two or more atoms, they in turn properly form a covalent connection. When two or more ions join in contact, they can create ionic bonds that are kept together by charge differences.

A water molecule contains two poles.  It is a positive charge on the hydrogen pole along with a negative charge on the oxygen pole. This is due to the uneven sharing of electrons between the atoms and the asymmetrical form of the molecule.

Thus, water molecules are drawn to one another by ionic bonds.

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