A student adds 34.2 mL of water to 72.3 mL of a 7.50 M glucose solution. (i) Will this solution be concentrated or dilute

Answer:

c. 12

Explanation:

Oxygen has six valance electrons

Silicon has six valance electrons

There are a number of possible atomic numbers but all come from the VI A group of elements.

so i think that is your answer base on the statement given above hope that helps thanx

Answer:

fr

Explanation:

Answer:

natural selection

Explanation:

natural selection

The number of electrons is revealed by the atomic number. This indicates that an aluminum atom contains 13 electrons. Eight electrons make up shell 1, eight electrons make up shell 2, and three electrons make up shell 3. The correct option is C.

Each subsequent shell that surrounds the nucleus of an atom's electrons is placed farther away from the nucleus. Atomic orbitals make up one or more of the one or more subshells that make up an electron shell.

The first two electrons in aluminum fall into the 1s orbital, followed by the next two electrons into the 2s orbital. The following six electrons complete the second shell's 2p orbital. The 3s orbital is then filled by electrons 11 and 12. The 3p orbital is now occupied by the final electron.

Thus the correct option is C.

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Answer:

The alcohol is a primary alcohol.

Explanation:

Chromic acid oxidizes primary alcohols to carboxylic acids and secondary alcohols to ketones but does not react with tertiary alcohols under mild conditions. Therefore, from the Chromic acid test, the class of alcohol is either primary or secondary.

Lucas reagent (a solution of anhydrous ZnCl₂ in conc. HCl)

Primary alcohols do not react readily at room temperature with the Lucas reagent, secondary alcohols react after some minutes while tertiary alcohols react immediately.

Since the alcohol is oxidized by chromic acid and does not react with Lucas reagent, it is a primary alcohol.

A solution of anhydrous zinc chloride in hydrochloric acid is called the Lucas reagent. The alcohol that does not react with Lucas's reagent is a primary alcohol.

The primary alcohol is the compounds that have their hydroxy group (-OH) attached to the primary carbon atom. Its molecular formula is, [tex]\rm CH_{2}OH[/tex].

The hydroxyl carbon of the primary alcohol contains only one R group in its structure. Methanol and ethanol are examples of primary alcohol.

Primary alcohol does not react with Lucas's reagent and no turbidity is formed as carbocation of the primary alcohol is too unstable.

Therefore, primary alcohol does not react with Lucas reagent.

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Answer:

2KCl + F₂   →     2KF + Cl₂

Explanation:

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

2KCl + F₂   →     2KF + Cl₂

In this equation mass of reactant and product is equal. There are 2 potassium 2 chlorine and fluorine atoms on both side of equation it means mass remain conserved.

All other options are incorrect because mass is not conserved.

Explanation:

rain, snow, cloud, fog or dry deposition - Dry particles, or gas

Answer:

MgBr₂

Explanation:

The given ions are:

             Mg²⁺    and   Br⁻

To find the formula of the compound that will result, we use the combining power or valency approach.

The combining power is the number of electrons usually lost or gained or shared by atoms of elements during the chemical combination.

                                           Mg²⁺    and   Br⁻

combining  power                2                  1

exchange of valencies        1                    2

 Molecular formula is given as  MgBr₂

Answer:

SOCl2, Mg, CH3CHO, H3O^+

Explanation:

The reaction of the 2,2-dimethylpropan-1-ol  with SOCl2 converts the alcohol to an alkyl halide. This now reacts with Mg metal to yield a Grignard reagent.

The Grignard reagent reacts with CH3CHO and acid  to yield  4,4-dimethylpentan-2-ol as shown in the image attached to this answer.

Answer:

2.7724 g

Explanation:

Mass of pre- 1892 pennies = 3.1 g

Abundance = 45.4 %

Mass of post 1892 pennies = 2.5 g

Abundance = 100 - 45.4 = 54.6 %

The average mass is given as = ( 3.1 g   *  45.4 / 100)  +  (2.5g  *  54.6 / 100)

Average Mass = 3.1 * 0.454   +   2.5  *  0.546

Average Mass = 1.4074  + 1.365 = 2.7724 g

Answer:

The mass of ammonium nitrate that has the same number of nitrogen atoms is 5077.5 g.

Explanation:

To calculate the mass of ammonium nitrate we need to find the number of atoms in liquid nitrogen, as follows:

[tex]d_{N} = \frac{m_{N}}{V}[/tex]

Where:

[tex]d_{N}[/tex]: is the density of liquid nitrogen = 0.808 g/mL

[tex]m_{N}[/tex]: is the mass of liquid nitrogen

V: is the volume of liquid nitrogen = 2.2 L

By calculating the mass of liquid nitrogen we can find the number of atoms:

[tex]m_{N}=d_{N}*V = 0.808 g/mL*\frac{1000 mL}{1 L}*2.2 L=1777.6 g[/tex]

[tex]n = N_{A}*\eta_{N}[/tex]

[tex]n=N_{A}*\frac{m_{N}}{M_{N}}[/tex]

Where:                

[tex]N_{A}[/tex]: is the Avogadro's number = 6.022x10²³ atoms/mol

n: is the number of atoms of liquid nitrogen

[tex]\eta_{N}[/tex]: is the number of moles of liquid nitrogen  

[tex]M_{N}[/tex]: is the molar mass of liquid nitrogen = 28.014 g/mol

[tex]n = \frac{6.022 \cdot 10^{23} atoms}{1 mol}*\frac{1777.6 g}{28.014 g/mol} = 3.82 \cdot 10^{25} atoms[/tex]

Finally, the mass of ammonium nitrate is:

[tex]m_{NH_{4}NO_{3}} = \frac{n*M_{NH_{4}NO_{3}}}{N_{A}}[/tex]

Where:

[tex]M_{NH_{4}NO_{3}}[/tex]: is the molar mass of ammonium nitrate = 80.043 g/mol

[tex] m_{NH_{4}NO_{3}} = \frac{3.82 \cdot 10^{25} atoms*80.043 g/mol}{6.022 \cdot 10^{23} atoms/mol} = 5077.5 g [/tex]

Hence, the mass of ammonium nitrate that has the same number of nitrogen atoms is 5077.5 g.

I hope it helps you!                                                            

The question is incomplete, the complete question is;

Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane? product. A) The terminal alkyne is more stable than the internal alkyne and is naturally the favored B) The terminal alkyne is not favored in this reaction. C) The resonance favors the formation of the terminal rather than internal alkyne. D) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.

E) The positions of the Cl atoms induce the net formation of the terminal alkyne.

Answer:

E) The positions of the Cl atoms induce the net formation of the terminal alkyne.

Explanation:

In this reaction, sterric hindrance plays a very important role. We know that sodamide is a strong base, it tends to attack at the most accessible position.

The first deprotonation yields an alkene. The strong base attacks at the terminal position again and yields the terminal alkyne. Thus the structure of the dihalide makes the terminal hydrogen atoms most accessible to the base. Hence the answer.

Answer:

There is no graph

Explanation:

Answer:

70.2 grams

Explanation:

The formula for density is p = m/V.

Here, p (density) and V (volume) are already given.

So, modify the formula to: m = pV.

p is 7.8 g/cm³, and V is 9 cm³.

m = 39/5 * 9/1

m = 351/5

m = 70.2 grams

The mass of the object is 70.2 grams.

Answer:

15.24× 10²³ atoms

Explanation:

Given data:

Number of atoms of sodium = ?

Number of moles = 2.53 mol

Solution:

The given problem will solve by using Avogadro number.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.53 mol × 6.022 × 10²³ atoms / 1mol

15.24× 10²³ atoms

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

Answer:

If the material is opaque, light is reflected or absorbed. If the material is transparent, all light is transmitted. If the material is translucent, the light is scattered. The higher the frequency, the more energy the light waves have. The lower the frequency, the less energy the light waves have.

Explanation:

I'm literally learning about it right now and I got it right.

CO diffuses more rapidly as compared to CO₂.

Diffusion is the movement of a substance from an area of high concentration to an area of low concentration. The process of diffusion  happens more rapidly in gases and liquids as compared to solids because their particles can move randomly.

The gases spread in the entire space available to them and intermix together even against gravity.

The Graham's law of diffusion states that the rates of diffusion of the gases are inversely proportional to the square root of their molar masses under same temperature and pressure.

Therefore, CO diffuses more rapidly as compared to CO₂.

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Answer:

C = 107.97 mol/L

Explanation:

Given data:

Volume of solution = 1.38 mL (1.38 mL× 1 L /1000 mL = 0.00138 L)

Mass of ammonium sulfite = 17.36 g

Concentration of solution =?

Solution:

We will calculate the number of moles of ammonium sulfite.

Number of moles = mass/molar mass

Number of moles = 17.36 g / 116.15 g/mol

Number of moles = 0.149 mol

Concentration/molarity:

C = n/V

C = 0.149 mol / 0.00138 L

C = 107.97 mol/L

Answer:

The energy stored in the spring when the bike goes over a bump is [tex]6.6\times 10^{-3}[/tex] joules.

Explanation:

Let suppose that spring has a linear behavious, by means of Hooke's Law, definition of Work and Work-Energy Theorem we find that the potential energy stored in the spring ([tex]U_{g}[/tex]), measured in joules, is defined by:

[tex]U_{e} = \frac{1}{2}\cdot k\cdot x^{2}[/tex] (1)

Where:

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]x[/tex] - Deformation, measured in meters.

If we know that [tex]k = 33\,\frac{N}{m}[/tex] and [tex]x = 0.02\,m[/tex], the energy stored by the spring due to compression is:

[tex]U_{e} = \frac{1}{2}\cdot \left(33\,\frac{N}{m} \right) \cdot (0.02\,m)^{2}[/tex]

[tex]U_{e} = 6.6\times 10^{-3}\,J[/tex]

The energy stored in the spring when the bike goes over a bump is [tex]6.6\times 10^{-3}[/tex] joules.

Answer:

12

Explanation:

The answer is 12 because You are looking for hydrogen which is the big H. you look to the number below it and it is 12. So H stands for hydrogen and there are 12 Hydrogen getting you your answer of 12.

Answer:

[tex]\mathbf{C_4 H_{8}O_{4}}[/tex]

Explanation:

From the given information:

Assume the molecular formula to be: [tex]C_a H_{2a} O_{a}[/tex]

Then, the molecular mass will be = 12a + 2a + 16a = 30a  (since the C = 12, H = 2 & O = 16) respectively.

Thus;

30a = 120

a = 120/30

a = 4

Thus, the molecular formula:

[tex]=C_4 H_{2*4} O_{4}[/tex]

[tex]= \mathbf{C_4 H_{8}O_{4}}[/tex]

Answer:

2.48 g

Explanation:

From the question given above, the following data were obtained:

Number of atoms = 2.53×10³⁴ atoms

Mass of Ni =?

From Avogadro's hypothesis,

we understood that 1 mole of any substance contains 6.02×10²³ atoms.

Therefore, 1 mole of Ni contains 6.02×10²³ atoms.

Recall:

1 mole Ni = 59 g

Therefore, 59 g of Ni contains 6.02×10²³ atoms.

Finally, we shall determine the mass of 2.53×10³⁴ atoms of Ni. This can be obtained as follow:

6.02×10²³ atoms = 59 g

Therefore,

2.53×10³⁴ = 2.53×10³⁴ × 59 / 6.02×10²³

2.53×10³⁴ atoms = 2.48 g

Thus, the mass of 2.53×10³⁴ atoms of Ni is 2.48 g.

Answer:

sperm cell

Explanation:

The male portion of a zygote is called the sperm cell. The sperm cell are produced by the male organism and they fertilize the eggs.

Answer:

10 m/s

Explanation:

100 meters covered in 10 seconds, so:

100 m / 10 s = 10 m/s

Answer:

A. Protists

C. Animals

Explanation:

Eukarya are protists, plants, animals, and fungi. Hope it helped!

The correct answers are A and C.

Eukarya are one of the three domains in which current biological science divides life. Eukarya are all organisms in which each cell contains a nucleus.

Eukarya, in addition to many unicellular species, include all types of multicellular organisms. Multicellular organisms are made up of different, specific cell types that make up different tissues.  

The largest group of organisms within eukarya are the protists. These are all single-celled organisms with a eukaryotic cell structure. The protists show a great diversity of species and, except for having a cell nucleus, show little similarity or relationship with each other. In addition, all multicellular organisms such as plants, animals and fungi are eukaryotes.

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Answer:

unit cells; lattice

Explanation:

Answer:

0.0584 M

Explanation:

From the question given above, the following data were obtained:

Mass of CaCl₂ = 0.808 g

Volume of water = 250 mL

Concentration of chloride =?

Next, we shall determine the number of mole in 0.808 g of CaCl₂. This can be obtained as follow:

Mass of CaCl₂ = 0.808 g

Molar mass of CaCl₂ = 40 + (35.5 × 2)

= 40 + 71

= 111 g/mol

Mole of CaCl₂ =?

Mole = mass / Molar mass

Mole of CaCl₂ = 0.808 / 111

Mole of CaCl₂ = 0.0073 mole

Next, we shall convert 250 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

250 mL = 250 mL × 1 L / 1000 mL

250 mL = 0.25 L

Next, we shall determine the molarity of CaCl₂. This can be obtained as follow:

Mole of CaCl₂ = 0.0073 mole

Volume of water = 0.25 L

Molarity of CaCl₂ =?

Molarity = mole /Volume

Molarity of CaCl₂ = 0.0073 / 0.25

Molarity of CaCl₂ = 0.0292 M

Finally, we shall determine the concentration of the chloride as illustrated below:

CaCl₂ <=> Ca²⁺ + 2Cl¯

From the equation above,

1 mole of CaCl₂ produced 2 mole of Cl¯.

Therefore, 0.0292 M CaCl₂ will produce = 0.0292 × 2 = 0.0584 M Cl¯.

Thus, the concentration of the chloride ion (Cl¯) in the solution is 0.0584 M

Answer:

0.67 g

Explanation:

We know that 1 mole of an element is 6.02 x 10^(23) atoms

Now, arsenic has 5.49 × 10²¹ atoms

Thus;

Number of moles of arsenic = 5.49 × 10²¹ × 1/6.02 x 10^(23) = 9 × 10^(-3) moles

We are told that;

one mole of arsenic = 74.92 g.

Thus, 9 × 10^(-3) moles = 9 × 10^(-3) × 74.92/1 = 0.67428 g ≈ 0.67 g

Answer:

A

Explanation:

Sana makatulong tong answer ko

The total number of molecules in 34.0 g of ammonia is equal to 12.044×10[tex]^23[/tex] molecules according to the concept of Avogadro's number.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number.

In the given example,number of molecules is determined as follows,

17 g ammonia has 6.022×10²³ molecules

So,34 g ammonia has, 34×6.022×10²³/17=12.044×10²³ molecules.

Hence, the total number of molecules in 34 g of ammonia is 12.044×10²³ molecules.

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Your question is incomplete, but the most probable answer is 12.044×10²³ molecules.