Answer:
8 atm
Explanation:
Given data:
Partial pressure of Ar = 4867 mmHg
Partial pressure of He = 1085 mmHg
Total pressure = ?
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = P(Ar) + P(He)
P(total) = 4867 mmHg + 1085 mmHg
P(total) = 5952 mmHg
mmHg to atm;
5952 /760 = 7.83 atm
P(total) = 8 atm
Explain why the atomic radius decreases across a period and increases down a group ?
Answer:
In general, atomic radius decreases across a period and increases down a group. ... Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital. This results in a larger atomic radius.
Which of the following is not a type of energy?
A. Electricity in a power cord.
B. Heat from an oven.
C. Light from a lightbulb.
D. Smoke from a fire.
Answer:
B- heat from an oven
Explanation:
temperature isn’t energy
QUESTION 4
How many moles are in 3.2 x 1024 of CO2 molecules? (round answer to the correct number of sig figs)
Answer:
5.3 mol CO₂
General Formulas and Concepts:
Chemistry - Stoichiometry
Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:
Step 1: Define
3.2 × 10²⁴ molecules CO₂
Step 2: Convert
[tex]3.2 \cdot 10^{24} \ mc \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ mc \ CO_2} )[/tex] = 5.31385 mol CO₂
Step 3: Check
We are given 2 sig figs. Follow sig fig rules.
5.31385 mol CO₂ ≈ 5.3 mol CO₂
1.
How many kJ are required to completely vaporize a 250 gram sample of water at 100°C?
general formula
Answer:
565 kJ
Explanation:
[tex]H_v[/tex] = Heat of vaporization of water at 100°C = 2260 J/g
m = Mass of water = 250 g
Heat required is given by
[tex]Q=mH_v[/tex]
[tex]\Rightarrow Q=250\times 2260[/tex]
[tex]\Rightarrow Q=565000\ \text{J}[/tex]
[tex]\Rightarrow Q=565\times 10^3\ \text{J}[/tex]
[tex]\Rightarrow Q=565\ \text{kJ}[/tex]
The heat required to vaporize the water is 565 kJ.
Can a closed system gain particles
Aqueous solutions of ammonium sulfide and potassium hydroxide are mixed. Precipitate:
Chemical Equation:
Complete Ionic Equation:
Net ionic Equation:
Answer:
Chemical Equation: (NH4)2S(aq) + 2KOH(aq) -> K2S(aq) + 2NH4OH(s)
Complete Ionic Equation: 2NH4^+(aq) + S^2-(aq) + 2K^+(aq) 2OH^-(aq) -> 2K^+(aq) + S^2- (aq) + 2NH4OH(s) 2NH4^+(aq) + OH^-(aq) -> NH4OH(s)
Explanation:
Ammonium sulfate and potassium hydroxide interact in this process to produce aqueous potassium sulfate, gaseous ammonia, and liquid water as byproducts. In essence, an acid-base reaction is taking place here, with the ammonium ion contributing a hydrogen ion to the potassium hydroxide's hydroxide ion.
What is chemical equation ?Chemical formulae and symbols are used to express a chemical reaction in a chemical equation.
A chemical equation represents a chemical reaction using symbols and the chemical formulas of the reactants and products involved. In this process, ammonia and hydrochloric acid are reacting to generate ammonium chloride. For solids, the symbol is (s).
( NH₄ ) 2S ₍ aq ₎ + 2KOH ₍ aq ₎ ⇒ K₂S ₍ aq ₎ + 2NH₄
Thus, Aqueous solutions of ammonium sulfide and potassium hydroxide are mixed to formed potassium sulphide and ammonia.
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#SPJ3
Among the following options, a valid Lewis structure of __________ cannot be drawn without violating the octet rule.
a. NH3
b. SbCl3
c. PF3
d. IF3
Answer:
d. IF3
Explanation:
The Octet rule posits that atoms gain, atom lose, or share electrons in order to have a full valence shell of 8 electrons. This statement occurs when atoms also combine to form molecules until they attain or share eight valence electrons either by losing or gaining eletrons.
From the given options, a valid Lewis structure that cannot be drawn without violating the octet rule is IF3
CHEMWORK The preparation of NO2(g) from N2(g) and O2(g) is an endothermic reaction: N2(g) + O2(g) + NO2(g) (unbalanced) The enthalpy change of reaction for the balanced equation (with lowest whole-number coefficients) is AH = 67.7 kJ. If 304 ml N2 (9) at 100ºC and 3.32 atm and 410 ml 0,(9) at 100°C and 3.32 atm are mixed, what amount of heat is necessary to synthesize the maximum yield of NO2(g) ?
Heat required : 1.523 kJ
Further explanationReaction
N₂+2O₂⇒2NO₂ AH = 67.7 kJ
mol of N₂:(use Pv=nRT)
[tex]\tt n=\dfrac{3.32\times 0.304}{0.082\times 373}=0.033[/tex]
mol of O₂:
[tex]\tt n=\dfrac{3.32\times 0.41}{0.082\times 373}=0.045[/tex]
Limiting reactant :
N₂ : O₂
[tex]\tt \dfrac{0.033}{1}\div \dfrac{0.045}{2}=0.033:0.0225[/tex]
Limiting reactant : O₂(smaller ratio)
mol NO₂ = mol O₂ = 0.045
2 mol ⇒ 67.7 kJ, so for 0.045 mol, heat required :
[tex]\tt \dfrac{0.045}{2}\times 67.7=1.523~kJ[/tex]
The heat required to produce the maximum yield of NO2 is 1.52 kJ.
The balanced reaction equation is;
N2(g) + 2 O2(g) -> 2 NO2(g)
The number of moles of each gas is obtained from the ideal gas equation as follows;
For N2;
P = 3.32 atm
V = 304 ml or 0.304 L
T = 100ºC + 273 = 373 K
n = ?
R = 0.082 atmLK-1mol-1
From;
PV = nRT
n = PV/RT
n = 3.32 atm × 0.304 L/0.082 atmLK-1mol-1 × 373 K
n = 0.033 moles
For O2;
PV = nRT
n = PV/RT
V = 410 ml or 0.410 L
P = 3.32 atm
R = 0.082 atmLK-1mol-1
T = 100°C + 273 = 373 K
n = 3.32 atm × 0.410 L/0.082 atmLK-1mol-1 × 373 K
n = 0.045 moles
1 mole of N2 reacts with 2 moles of O2
0.033 moles of N2 reacts with 0.033 moles × 2 moles/1 mole
= 0.066 moles
2 moles of O2 yields 2 moles of NO2
0.045 moles O2 yields 0.045 moles × 2 moles/2 moles = 0.045 moles
If 2 mole of NO2 requires 67.7 kJ
0.045 moles of NO2 requires 0.045 moles × 67.7 kJ/2 mole
= 1.52 kJ
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Write the balanced reaction and solubility product expression (KSP) for dissolving silver chromate: Ag2CrO4(s). Include all charges, stoichiometric coefficients, and phase subscripts.
Answer:
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓
Ksp = [2s]² . [s] → 4s³
Explanation:
Ag₂CrO₄ → 2Ag⁺ + CrO₄⁻²
Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓ Ksp
That's the expression for the precipitation equilibrium.
To determine the solubility product expression, we work with the Ksp
Ag₂CrO₄ (s) ⇄ 2Ag⁺ (aq) + CrO₄⁻² (aq) Ksp
2 s s
Look the stoichiometry is 1:2, between the salt and the silver.
Ksp = [2s]² . [s] → 4s³
10. Determine the frequency of light that has a wavelength of 400nm. c=X*v. C=3.0x108
Answer:
7.5 x 10^14 Hz
Explanation:
PLZZ ANSWER QUICKLY: True or False: MOST organelles found in plant cells are DIFFERENT than organelles found in animal cells
Answer:
Organelles allow for various functions to occur in the cell at the same time. Despite their fundamental similarities, there are some striking differences between animal and plant cells (see Figure 1). Animal cells have centrosomes (or a pair of centrioles), and lysosomes, whereas plant cells do not.
Explanation:
Determine the differences In electronegativity ionic radius atomic radius and first ionization energy for oxygen and beryllium
Answer:
Electronegativity = 1.87.
Ionic radius = 109 pm.
Atomic radius = -39 pm
First ionization energy = 410 kJ/mol
Explanation:
Hello!
In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.
In such a way, the required comparison is written below:
Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.
Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.
Atomic radius = 73 pm (oxygen) - 112 pm (beryllium) = -39 pm
First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol
It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.
Best regards!
Oxygen and Beryllium are the elements that pertain to the same period and different groups 6A and 2A.
Ionic radius, atomic radius, electronegativity and first ionization energy are periodic qualities that have selective trends.
Differences in the trends are:
Ionic radius = 109 pmAtomic radius = -39 pmElectronegativity = 1.87First ionization energy = 410 kJ/molThis can be explained as:
Ionic radius:= 140 pm (oxygen)- 31 pm (beryllium)
= 109.
Atomic radius:= 73 pm (oxygen) - 112 pm (beryllium)
= -39 pm
Electronegativity:= 3.44 (oxygen) - 1.57 (beryllium)
= 1.87
First ionization energy:= 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium)
= 410 kJ/mol
Therefore, these data tell that ionic radius, electronegativity and first ionization energy increases from left to right in a period whereas, the atomic radius increases from right to left in a period.
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If 8.793 of heat are added to a 2.00g sample of metal and the temperature increases by 4.9°C. What is the specific heat?
The specific heat of metal = 0.897 J/g° C
Further explanationHeat absorbed can be calculated using the formula:
Q = mc∆TQ = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Q = 8.793 J
m = 2 g
∆t = 4.9 °C
[tex]\tt c=\dfrac{Q}{m.\Delta t}\\\\c=\dfrac{8.793}{2\times 4.9}\\\\c=0.897~J/g^oC[/tex]
What term describes the state of matter in which the attractive forces between particles are the greatest?
liquid
solid
gas
metal
Answer:
I think it would be b
Explanation:
How much energy is used to melt 44.33 g of solid oxygen?
Answer:
Q1 = C * m * dT
Q2 = Qm * m
Qtotal = Q1 + Q2
Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.
C - is calorific capacity of oxygen -- better look at tables, it is a constant value
m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.
dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)
Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)
Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions
If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0
I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.
Data from tables
Tm = 54.36 K
C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.
Qm = 0.444 kJ/mol
Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol
So you have 44.33/32 = 1.385 moles of oxygen
a) if oxygen is already at melting temperature: you only have to melt it
Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J
b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.
Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J
Q2 = Qm * m = 615 J
Qtotal = 177.442 + 615 = 792.44 J
Explanation:
Answer:
In this case, 1 mole of liquid oxygen requires 3.41 kJ of heat in order to perform that liquid → solid. your sample from grams to moles by using oxygen's molar mass.
Calculate the total Calories in one cup of watermelon containing 0.9 g protein, 0.2 g fat, and 11 g carbohydrat
Answer:
49.4 cal
Explanation:
Step 1: Given data
Composition of 1 cup of watermelon: 0.9 g protein, 0.2 g fat, and 11 g carbohydrate.
Step 2: Calculate the calories provided by 0.9 g of protein
1 g of protein yields 4 cal.
0.9 g × (4 cal/1 g) = 3.6 cal
Step 3: Calculate the calories provided by 0.2 g of fat
1 g of fat yields 9 cal.
0.2 g × (9 cal/1 g) = 1.8 cal
Step 4: Calculate the calories provided by 11 g of carbohydrate
1 g of carbohydrate yields 4 cal.
11 g × (4 cal/1 g) = 44 cal
Step 5: Calculate the total number of calories
3.6 cal + 1.8 cal + 44 cal = 49.4 cal
Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition reactions in the table. A 2-column table with 3 rows. The first column labeled reactants has entries 2 N a C l O subscript 3, 2 K C l O subscript 3, 2 L i C l O subscript 3. The second column labeled products has entries 2 N a C l + 3 O subscript 2, 3 O subscript 2 + 2 K C l, empty. What products should she record in the last row of the table? 2LiCl + 3O2 3LiCl + 2O2 2LiO + 3Cl2 3LiO+ 2Cl2
Answer:
2LiCl + 3O2
Explanation:
Answer:
(C) 2LiCl + 3O2
Explanation:
sub to pewds
I need help. Will mark Brainlist.
Answer:
you are correct, the answer is 2 g
PLS HELP
Which substance contains bonds that involve the transfer of electrons from one atom to another?
1. CO₂
2. HF
3. CH₄
4. K₂S
What is the acceleration of gravity on Saturn if your mass is 75 kg and your weight is 800n
Answer:
The answer is 10.67 m/s²Explanation:
The acceleration of gravity of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{800}{75} = \frac{32}{3} \\ = 10.666666...[/tex]
We have the final answer as
10.67 m/s²Hope this helps you
HELP 40 POINTS
The figures below show the Lewis structures for three nonmetals. Which of the formulas COULD NOT represent a molecule formed by two of these elements?
A) F2
B) SF
C) OF2
D) SO
Answer:
F2
Explanation:
F2 is the only element with only 1 element and eveything else is formed by 2 non-metals
Answer:d I believe
Explanation:
Complete and balance the equation for the single displacement reaction Cl2 + NaCl + Br2
Answer:
NaBr + Cl2 = NaCl + Br2 - Chemical Equation Balancer.
Explanation:
Globular proteins play a critical role in virtually all chemical processes.
True or false
Answer:
True
Explanation:
A gas with a volume of 525 mL at a temperature of -25°C is heated to 175°C.
What is the new volume, in milliliters, of the gas if pressure and number of moles
are held constant?
Answer:
Volume V2 = 948.13 ml
Explanation:
Given:
Volume V1 = 525 ml
Temperature T1 = -25°C + 273.15
Volume V2 = ?
Temperature T1 = 175°C + 273.15
Computation:
V1 / T1 = V2 / T2
525 / [-25°C + 273.15] = V2 / [175°C + 273.15]
Volume V2 = 948.13 ml
The new volume, in milliliters, of the gas is 948 L
From the question,
We are to determine the new volume of the gas.
From Charles' law which states that the volume of a fixed mass of gas is directly proportional to the temperature (in Kelvin) provided that the pressure remains constant.
That is,
V ∝ T
Then,
V = kT
Therefore, we can write that
[tex]\frac{V_{1} }{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Where [tex]V_{1}[/tex] is the initial volume
[tex]T_{1}[/tex] is the initial temperature
[tex]V_{2}[/tex] is the final volume
and [tex]T_{2}[/tex] is the final temperature
From the given information,
[tex]V_{1} = 525 \ mL[/tex]
[tex]T_{1} = -25 ^{\circ}C = -25 + 273.15 \ K = 248.15 \ K[/tex]
[tex]T_{2} = 175 ^{\circ} C = 175 +273.15 \ K =448.15 \ K[/tex]
Putting the values into the formula, we get
[tex]\frac{525}{248.15} = \frac{V_{2} }{448.15}[/tex]
∴ [tex]V_{2} = \frac{525 \times 448.15}{248.15}[/tex]
[tex]V_{2} = \frac{235278.75}{248.15}[/tex]
[tex]V_{2} = 948.13 \ L[/tex]
V₂ ≅ 948 L
Hence, the new volume, in milliliters, of the gas is 948 L
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2. How many orbitals are in the following sublevels?
a. ls
b. 5s
c. 4d
d. 4f
e. 7s
f. 3p
g. the entire 5th principle energy level
h. 6d
PLEASE HELP AND FAST
Explanation:
The number of orbitals in the sublevels are given below:
Sublevels Orbitals
s 1
p 3
d 5
f 7
a. ls - 1 orbital
b. 5s - 1 orbital
c. 4d - 5 orbitals
d. 4f - 7 orbitals
e. 7s - 1 orbital
f. 3p - 3 orbitals
g. Entire 5th principal energy level : for s, p , f
1 + 3 + 5 + 7 + 9 = 25
h. 6d - 5
Which physical property does the inventor need to consider when choosing a
material for the container?
A. Ductility
B. Thermal conductivity
C. Transparency
D. Electrical conductivity
Answer:
A.
............
Explanation:
Ductility
According to the ideal gas law, a 10.68 mol sample of methane gas in a 0.8295 L container at 501.9 K should exert a pressure of 530.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure
Answer:
The answer is "152.28%".
Explanation:
Formula for ideal gas:
PV=nRT
equation:
[tex]\to (P+\frac{an^2}{v^2})(v-nb)=nRT \\\\a=2.253 \frac{L^2 atm}{mol^2}\\\\b=4.278 \times 10^{-2} \frac{L}{mol}\\\\n=10.68 \ mol\\\\v= 0.8295 \ L\\\\\to (P+\frac{an^2}{v^2})= \frac{nRT}{(v-nb)}\\\\\to (P)= \frac{nRT}{(v-nb)} - \frac{an^2}{v^2} \\\\[/tex]
[tex]= \frac{10.68 \times 0.0082 \times 501.9}{0.8295 - (10.68 \times 4.278 \times 10^{-2})} - \frac{2.253 \times 10.68^2}{0.8295^2}\\\\=\frac{43.9543944}{0.4568904} - \frac{256.982587}{0.68807025}\\\\ = 96.2033661- 373.483067\\\\=-277.279701 \\\\ =-277.279701 \ atm[/tex]
The pressure of gas:
[tex]= (530.3 + 277.279701) \ atm\\\\= 807.579701 \ atm \\\\[/tex]
Calculating the pressure percentage:
[tex]=\frac{807.579701}{530.3} \times 100\\\\= 152.28 \%[/tex]
Jet streams generally flow toward the
a. north
b. south
c. east
d. west
please answer thank you
Answer:
The major jet streams on Earth are westerly winds that flow west to east.
100.0 g H2SO4 =
? mole H2SO4
Answer:
sulfuric acid ..............
Chlorine dioxide is used as a disinfectant and bleaching agent. In water, it reacts to form chloric acid (HClO3), according to the following balanced equation: 6 ClO2 + 3 H2O → 5 HClO3 + HCl If excess ClO2 is mixed with 18.0 mL of H2O (d = 0.998g/1ml ) how many grams of HClO3 are formed?
would be very helpful if the answer was explained with steps
Answer:
b
Explanation:
b