Answer:
The expansion of the steel bridge is 0.0605 cm
Explanation:
The given length of the steel bridge, L = 5.5 m
The linear expansivity of the steel bridge, [tex]\alpha_ L[/tex] = 0.000011/°C
The rise (change) in the temperature, ΔT = 10°C
Let, ΔL, represent the expansion of the steel bridge
Given that the linear expansivity, [tex]\alpha_ L[/tex], of a material is the change in the length of a material per unit length of the material per unit change in the temperature, we have;
[tex]\alpha_ L[/tex] = ΔL/(L × ΔT)
∴ ΔL = [tex]\alpha_ L[/tex] × L × ΔT = 0.000011 /°C × 5.5 m × 10 °C = 0.000605 meters
ΔL = 0.000605 meters
The expansion of the steel bridge, ΔL = 0.000605 meters = 0.000605 m × 100 cm/m = 0.0605 cm
Describe the 3 types of collisions. Then explain how they are alike and different.
Michael is biking on a trail and is accelerating at a rate of 1.2 m/s/s for 15 seconds. He began this part of his ride with a velocity of 1.62 m/s. Determine Michael's final velocity?
Answer:
Michael's final velocity is 19.62 m/s.
Explanation:
We can find the final velocity of Michael by using the following kinematic equation:
[tex] v_{f} = v_{0} + at [/tex] (1)
Where:
[tex]v_{f}[/tex]: is the final velocity =?
[tex]v_{0}[/tex]: is the initial velocity = 1.62 m/s
a: is the acceleration = 1.2 m/s²
t: is the time = 15 s
By entering the above values into equation (1) we have:
[tex] v_{f} = 1.62 m/s + 1.2 m/s^{2}*15 s [/tex]
[tex] v_{f} = 19.62 m/s [/tex]
Therefore, Michael's final velocity is 19.62 m/s.
I hope it helps you!
Suppose a candle is burned in a closed system where matter cannot enter or leave. Given this situation,
what is equal to the mass of the original candle?
Answer:
Mass of the melted wax
Explanation:
The mass of the original candle that has been burnt in the closed system is equal to the mass of the melted wax.
A closed system is a system where matter cannot be exchange with the surrounding. As the candle undergoes a phase change during the burning, it melts to liquid wax. Since there is no loss of mass, the amount of matter in the system is conserved. Therefore, the mass of the molten wax will be the same as the mass of the candle originally melted.An airplane flies at 40 m/s at an altitude of 50 meters. The pilot drops a heavy package which falls to the ground. Where, approximately, does the package land relative to the plane's new position
Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =?
Next, we shall determine the time taken for the package to get to the ground.
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9
t² = 50 / 4.9
t² = 10.2
Take the square root of both side
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =?
s = ut
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane
Fossils, plants, and animals are what make rocks different from minerals.
true of fales
Use the drop-down menus to determine which state of matter is described in each statement.
The atoms in a
are closely packed, but able to slide past each other.
The atoms in a
spread as far apart as possible.
A
has a definite shape and volume.
The shape of a
can change, but the volume is definite.
Answer:
Explanation:
There are three states of matter; solid, liquid and gaseous states.
The solid state of matter has it's particles tightly packed with very restricted or no movement within the molecule hence the reason for it's definite shape.
The liquid state of matter has it's particles with a free movement (better than solid but not as free as gases) within the molecule hence it's particles are loosely packed within the molecule. Hence, they (liquids) assume the shape of the container in which they are stored and they move freely when released from the container.
The gaseous state of matter has it's particles totally loosely packed as a result of it's particles moving freely and colliding against one another.
Thus, we can use the above descriptions to answer the statements from the question.
1) The atoms in a ----- are closely packed, but able to slide past each other. Answer: From the description above, it can be deduced that the atoms here are in a solid because the particles within a solid are closely packed.
2) The atoms in a -------- spread as far apart as possible.
Answer: The atoms here are in gaseous form because, as described earlier, they are loosely packed and can thus be as far apart as possible.
3) A ----- has a definite shape and volume.
Answer: As described earlier, a solid substance would have a definite shape and volume because it's particles are tightly packed.
4) The shape of a ----- can change, but the volume is definite.
Answer: The substance here is a liquid because the particles are free (but not as free as gases) and would have a definite volume but will assume the shape of the any container they are placed in (hence they have an irregular shape).
Answer:
The atoms in a
✔ liquid
are closely packed, but able to slide past each other.
The atoms in a
✔ gas
spread as far apart as possible.
A
✔ solid
has a definite shape and volume.
The shape of a
✔ liquid
can change, but the volume is definite.
Explanation:
A book weighing 2 Newtons is at rest on a table. The net force on the book is zero.
TRUE
FALSE
Answer: I think its True
A 750 g ball is raised 3 m off the ground and then thrown. What is the potential energy
of the ball before the throw?
Answer:
22.05 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass in kg
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question
750 g = 0.75 kg
We have
PE = 0.75 × 9.8 × 3
We have the final answer as
22.05 JHope this helps you
A star's brightness as if it were a standard distance from Earth (10 parsecs) is known as what? radiation apparent brightness lighting absolute brightness
Answer:
In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).
Explanation:
A clown in a circus act swings a 2.7-kg metal ball attached to a 72.0-cm nylon string in a horizontal circle above her head, making one revolution in 0.98 s. What is the tension force, Ft, exerted on the string by the ball?
Answer:
Tension, Ft = 79.91 N
Explanation:
The tension in the string is the resultant force that exists in the string due to the centripetal effect of the swinging ball.
From conservation laws, the tension in the string will be equals to the centripetal force acting on the string.
The tension in a string can be obtained using the formula:
[tex]T=mv^2/R[/tex]
where v = linear velocity of the metal ball which equals to the angular velocity of the ball X the radius of the ball.
The radius of the ball is given as 72 cm = 0.72m and the angular velocity = 1.02 rad/second.
Therefore, linear velocity, [tex]v = 2\pi \times 1.02\times 0.72 =4.616m/s[/tex]
The tension in the string will now be equals to [tex]2.7 \times 4.616^2 /0.72 =79.91N[/tex]
What is the random walk?
Answer:
In mathematics, a random walk is a mathematical object, known as a stochastic or random process, that describes a path that consists of a succession of random steps on some mathematical space such as the integers.
Explanation:
Example of first, second and third law of motion.
Examples of Newton's three law of motion.
First law of motion: A rocket being launched up in the atmosphere.
Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.
Third law of motion:when we jump off from the boat,the boat moves backward.
Hope,it will helpyouu!
[tex]x3n + 5x2n + 12xn + 18 \div xn + 3[/tex]
Answer:
sorry its impossible
Explanation:
your stopped at a red light. You've checked the intersection to see that it is clear of vehicles and pedestrians, unless a tells you not, you may then?
Answer:
Unless you are at a red light you may not proceedYou pose a threat to other drivers who are following the instructions and ethics.You have to travel 5000 meters. You only have two minutes (120 seconds) to get there. How fast must you travel to get there in time in meters per second?
Answer:
416.667 m/s
Explanation:
divide the distance by the time
A bullet of mass 4.0g is fired from a rifle of mass 2.0kg with muzzle velocity of 380m/s. What is the initial recoil velocity of the rifle?
Answer:
v = 0.76 [m/s]
Explanation:
The linear momentum generated by the shot must be calculated. This can be calculated using the following expression.
[tex]P=m*v\\[/tex]
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
[tex]P=0.004*380\\P=1.52[kg*m/s][/tex]
Now we can calculate the recoil velocity, because the momentum is equal for the rifle.
[tex]P=m*v\\v = P/m\\v = 1.52/2\\v = 0.76[m/s][/tex]
What is the velocity of a wave with a frequency of 930 Hz and a wavelength of 0.50 m?
Answer:
Hi, thank you for posting your question here at Brainly.
To find the velocity of light or any electromagnetic wave, we use the equation: v = wavelength * frequency. Substituting,
v = 0.5 m * 930 1/s
v = 465 m/s
Brainiest please
Explanation:
a truck of mass 200kg rests on an inclined plane hindered from rolling down the surface by a storing sprint whose force constant is 10^6N/M.neglecting friction,how much work does the truck do on the spring?
Answer:
1.92 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 200 Kg
Spring constant (K) = 10⁶ N/m
Workdone =?
Next, we shall determine the force exerted on the spring. This can be obtained as follow:
Mass (m) = 200 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = m × g
F = 200 × 9.8
F = 1960 N
Next we shall determine the extent to which the spring stretches. This can be obtained as follow:
Spring constant (K) = 10⁶ N/m
Force (F) = 1960 N
Extention (e) =?
F = Ke
1960 = 10⁶ × e
Divide both side by 10⁶
e = 1960 / 10⁶
e = 0.00196 m
Finally, we shall determine energy (Workdone) on the spring as follow:
Spring constant (K) = 10⁶ N/m
Extention (e) = 0.00196 m
Energy (E) =?
E = ½Ke²
E = ½ × 10⁶ × (0.00196)²
E = 1.92 J
Therefore, the Workdone on the spring is 1.92 J
An object located near the surface of Earth has a weight of a 245 N
object?
• What is the mass of the object?
• What is the weight of the object on Mars where the gravity is
3.72 m/s?
Answer:
The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.
Explanation:
Weight of the object on the surface of Earth, W = 245 N
On the surface of Earth, acceleration due to gravity, g = 10 m/s²
Weight of an object is given by :
W = mg
m is mass
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg[/tex]
So, the mass of the object is 24.5 kg
Acceleration due to gravity on Mars, g' = 3.72 m/s²
Weight of the object on Mars,
W' =mg'
W' = 24.5 kg × 3.72 m/s²
= 91.14 N
So, the weight of the object on Mars is 91.14 N.
Given the data in the question;
Weight of object; [tex]W = 245N[/tex]
What is the mass of the object.Weight the measure of the force of gravity pulling down on a particle or object.
It is expressed as:
[tex]W = m* g[/tex]
Where m is mass of the object and g is acceleration due to gravity { Acceleration due gravity of Earth [tex]g_{earth} = 9.8m/s^2[/tex] }
We substitute our values into the equation
[tex]245N = m * 9.8m/s^2\\\\245kg.m/s^2 = m * 9.8m/s^2\\\\m = \frac{245kg.m/s^2}{9.8m/s^2} \\\\m = 25kg[/tex]
Therefore, mass of the object located near the Earth surface is 25kg
Weight of the object on Mars where the gravity [tex]3.72m/s^2[/tex]
So on planet Mars; [tex]g = 3.72m/s^2[/tex], we know that mass of the object is [tex]25kg[/tex]
We substitute into our equation
[tex]W = m* g[/tex]
[tex]W = 25kg * 3.72m/s^2\\\\W = 93kg.m/s^2\\\\W = 93N[/tex]
Therefore, the weight of the object on Mars with the given gravity is 93 Newtons.
Learn more: https://brainly.com/question/23245710
An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 320 mV/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. The magnetic field amplitude of the signal at that point, in nT, is closest to:
Answer:
1.07 nT
Explanation:
We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.
So, B = E/c
Substituting E and c into B, we have
B = E/c
= 0.32 V/m ÷ 3 × 10⁸ m/s
= 0.1067 × 10⁻⁸ T
= 1.067 × 10⁻⁹ T
= 1.067 nT
≅ 1.07 nT
A container is filled with liquid the depth of the liquid is 60 CM if exertingc in pressure is 2000pa. calculator the density of a liquid
Answer:
The density of the liquid is 340.136 kg/m³
Explanation:
Given;
depth of liquid in the container, h = 60 cm = 0.6 m
pressure of the liquid, P = 2000 Pa = 2000 N/m²
The pressure of the liquid is calculated as ;
P = ρgh
where;
ρ is density of the liquid
g is acceleration due to gravity = 9.8 m/s²
h is depth of the liquid
Make the density (ρ) the subject of the formula;
[tex]\rho = \frac{P}{gh} \\\\\rho = \frac{2000}{9.8 \times 0.6}\\\\\rho = 340.136 \ kg/m^3[/tex]
Therefore, the density of the liquid is 340.136 kg/m³
help please 10 pts and quick!
can someone write me a short response
Answer:
Explanation:
Pecan 1 and 4 seem the best answer
state Newton second law of motion
Newton 2ns law state that external forces that exert on an object is proportional to the mass and the acceleration of an object
Formula : ΣF = ma
ask me if you're confused with my answer
A race car moves along a circular track at a speed of 0.512 m/s. If the car's centripetal acceleration is 15.4 m/s2, what is the distance between the car and the center of the track?
Answer:
The radius is [tex]r = 0.0170 \ m[/tex]
Explanation:
From the question we are told that
The speed at which the race car moves is [tex]v = 0.512 \ m/s[/tex]
The centripetal acceleration is [tex]a _r = 15.4 \ m/s[/tex]
Generally the centripetal acceleration is mathematically represented as
[tex]a_r = \frac{v^2 }{r}[/tex]
=> [tex]15.4 = \frac{0.512^2 }{ r}[/tex]
=> [tex]r = 0.0170 \ m[/tex]
A horizontal disc of radius 45 cm rotates about a vertical axis through its centre. The disc makes one full
revolution in 1.40 s. A particle of mass 0.054 kg is placed at a distance of 22 cm from the centre of the disc.
The particle does not move relative to the disc.
a On a copy of the diagram draw arrows to represent the velocity and acceleration of the particle. [2]
b Calculate the angular speed and the linear speed of the particle. [2]
c The coe cient of static friction between the disc and the particle is 0.82. Determine the largest distance
from the centre of the disc where the particle can be placed and still not move relative to the disc. [3]
d The particle is to remain at its original distance of 22cm from the centre of the disc.
i Determine the maximum angular speed of the disc so that the particle does not move relative to
the disc. [2]
ii The disc now begins to rotate at an angular speed that is greater than the answer in d i. Describe
qualitatively what happens to the particle. [2]
Answer:
a. Please find attached the diagram of the disc, having arrows that represent the velocity and the acceleration of the particle placed on it
b. The angular speed is approximately 4.488 rad/s
The linear speed is approximately 0.987 m/s
c. The largest distance from the center of the disc where the particle can be placed and still not move is approximately 0.399 m from the center of the disc
d. i The maximum angular speed of the disk so that the particle does not move relative to the disk is approximately 6.044 rad/sec
ii When the angular speed with which the disc rotates is more than the the answer of question d i above, the particle slips on the disc, and the disc begins to rotate faster than the particle, while the particle is swung in an outward radial direction off the disc due to the centrifugal forces
Explanation:
The given parameters are;
The radius of the horizontal disc, r = 45 cm = 0.45 m
The time the disc makes one full revolution, T = 1.40 s
The mass of the particle placed on the disc = 0.054 kg
The location on the disc the particle is placed = 22 cm from the disc's center
a. Please find attached the diagram of the disc created with Microsoft Visio, with arrows representing the velocity and the acceleration of the particle placed on the disk
b. The angular speed, ω = 2·π/T = 2 × π/1.4 ≈ 4.488 rad/s
The linear speed, v = ω × r = 4.488 rad/s × 0.22 m ≈ 0.987 m/s
The linear speed, v ≈ 0.987 m/s
c. The given coefficient of static friction = 0.82
Therefore;
The frictional force that prevents motion = Weight of the particle × The coefficient of static friction
The frictional force that prevents motion is [tex]F_f[/tex] = 0.054 × 9.8 × 0.82 ≈ 0.434 N
[tex]F_f[/tex] ≈ 0.434 N
Therefore, for the largest distance from the center of the disc where the particle can be placed and still not move, r, is given by the formula for the centripetal force, [tex]F_c[/tex], acting on the particle as follows;
For static equilibrium, no movement of the particle relative to the disc, we have;
[tex]F_f[/tex] = [tex]F_c[/tex]
Where;
[tex]F_c = \dfrac{m \times v^2}{r} = m \times \omega ^2 \times r[/tex]
Which gives;
[tex]F_c = {0.054 \ kg \times (4.488 \ rad/s)^2} \times r = F_f = 0.434 \ N[/tex]
r = 0.434 N/(0.054 kg × (4.488 rad/s)²) ≈ 0.399 m
The largest distance from the center of the disc where the particle can be placed and still not move, r = 0.399 m from the center of the disc
d. i From the static equilibrium equation where r = 0.22 m, we have;
[tex]F_c = {0.054 \ kg \times \omega ^2} \times 0.22 \ m = F_f = 0.434 \ N[/tex]
ω = √(0.434 N/(0.054 kg × (0.22 m))) ≈ 6.044 rad/sec
The maximum angular speed of the disk so that the particle does not move relative to the disk, ω ≈ 6.044 rad/sec
ii When the angular speed with which the disc rotates is more than the the answer of question d i above, we have
The particle begins to slip on the disc such that the disc rotates faster than the particle and the particle tends to rotate slower than the speed pf the disc and is swung off the disc by centripetal force acting on the particle due to the rotational motion of the disc.
I got a new kitten and I dont know how to train them to use a leash. Can anyone help?
Give a paragraph on how to become a better leader
Answer:
Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line
Explanation:
:)
2 What can you Infer about this source of electricity?
A It is a source of alternating current
B It Is a source of direct current
С It is a source of static electricity
D It is a source of electromagnetic radiatlon
Answer:i think it's d
Explanation:
Potassium chloride forms a solid made up of a highly organized set of
positive and negative particles. Which term describes this solid?
A. An ion
B. A crystal
C. An atom
D. A molecule
Answer: It is b. a crystal
Explanation:
Answer:
B. A crystal
Explanation:
10 cm^3 of iron have a smaller
mass then 115 cm^3 of wood.
(density of iron 7.9 g/cm^3)
(density of wood 0.7 g/cm^3)
true or false
Explanation:
Mass of iron = (7.9)(10) = 79g
Mass of wood = (115)(0.7) = 80.5g
Therefore iron has a smaller mass than the wood, which is true.