A standard six-sided die is rolled $6$ times. You are told that among the rolls, there was one $1,$ two $2$'s, and three $3$'s. How many possible sequences of rolls could there have been? (For example, $3,2,3,1,3,2$ is one possible sequence.)

Answer:

since y is across from 60 so

y=60

and on the bottom it is 15 so

x+3=15

x=12

Hope This Helps!!!

Answer:

(x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Step-by-step explanation:

x² - 5 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - 5

= x² - ([tex]\sqrt{5}[/tex] )²

= (x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

[tex]{ \bf{ \underbrace{Given}}}[/tex]:

Diameter of the circle "[tex]d[/tex]" = [tex]36[/tex]

Value of [tex]π[/tex] = [tex]3[/tex]

[tex]{ \bf{ \underbrace{To\:find}}}[/tex]:

The circumference "[tex]C[/tex]" of the circle.

[tex]{ \bf{ \underbrace{Solution }}}[/tex]:

[tex]\sf\pink{The\:circumference \:"C"\:of\:the\:circle\:is\:108.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:πd }[/tex]

[tex] = 3 \times 36[/tex]

[tex] = 108[/tex]

Therefore, the circumference of the circle is [tex]108[/tex].

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer:

[tex]\Longrightarrow: \boxed{\sf{108}}[/tex]

Step-by-step explanation:

Apply the formula for the circle's circumference.

[tex]\text{Circumference circle formula:}[/tex]

[tex]\Longrightarrow: \sf{C=\pi d}[/tex]

[tex]\Longrightarrow:\sf{C=?}\\\\\Longrightarrow:\sf{\pi =3}\\\\\Longrightarrow:\sf{d=36}[/tex]

Multiply.

[tex]\sf{3*36=\boxed{\sf{108}}[/tex]

I hope this helps! Let me know if you have any questions.

hello,

" a turning point is defined as the point where a graph changes from either  increasing to decreasing, or  decreasing to increasing"

a)

[tex]y=x^3+x^2-6x\\\\y'=3x^2+2x-6=0\\x=\dfrac{-2-\sqrt{76} }{6} \approx{-1.786299647...}\\or\\x=\dfrac{-2+\sqrt{76} }{6} \approx{1.1196329...}\\[/tex]

b)

Zeros are -3,0,2.

Sol={-3,0,2}

The solution of the graph function y=x³+x²-6x are -3 , 0 and 2

The link between lines and points is described by a graph, which is a mathematical description of a network. A graph is made up of certain points and the connecting lines. It doesn't matter how long the lines are or where the points are located. A node is the name for each element in a graph.

We have the function

y=x³+x²-6x

now, equating it to 0

x³+x²-6x = 0

x² + x - 6= 0

x² - 3x + 2x -6 =0

x(x -3) + 2(x -3)

x= 3 and -2

Now, ew can see from the that the equation is touching the x-axis at three points and it will represent three zeroes of the equation.

So, the solution of the graph are -3 , 0 and 2

Learn more about graph here:

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Answer:

both choices with 2x+y = -3

Step-by-step explanation:

to have the solution (-4, 5), that point must be on both equations/functions, meaning it must be on either one.

in other words, if the point is not on at least one of the functions, it cannot be a solution for that system.

the given function

2x + y = -3

looks like for the point (-4, 5)

2×-4 + 5 = -3

-8 + 5 = -3

-3 = -3

correct.

but

-2x + y = -3

looks like for (-4, 5)

-2×-4 + 5 = -3

8 + 5 = -3

13 = -3

wrong. the point is not on this function.

as we can therefore rule out 2 of the answer options, the other 2 most be correct.

The two equations which when written as a system has a solution of (-4, 5) is; 2x + y = -3 and 2x + y = -3

The correct equations must have same output with the given one when we place -4 and 5 for x and y respectively.

Now, for 2x + y = -3

At x = -4, and y = 5 we have;

2(-4) + 5 = -3

Same with the right hand side.

For -2x + y = -3;

At x = -4, and y = 5 we have;

-2(-4) + 5 = 13

Not the same with the right hand side.

Thus, the two equations with 2x + y = -3 are correct

Read more about Inequalities at; https://brainly.com/question/24372553

Answer:

Answer: for polynomials in two or more variables, the degree of a term is the sum of the exponents of the variables in the term; the degree (sometimes called the total degree) of the polynomial is again the maximum of the degrees of all terms in the polynomial

Proportional Linear Relationships can be expressed in the following ways:

From a graphical point of view, a relationship is proportional and linear if the line representing the equation goes via the origin. It is to be noted that a relationship must be linear for it to be proportional and vice versa.

Thus, it is correct to state that Proportional Linear Relationships can be expressed in the following ways:

An example of an equation that is proportional and linear is:
y = 6x + 8. Note that this linear equation is proportional because it has a constant component.

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The arc length is 10 Pi

(I don't know for sure, but its what I got)

Answer:

9. The area of rectangle S is four times bigger than rectangle R

10. (1, 3)

Step-by-step explanation:

To find the solution of the two linear equations:

y=x+2

y=-2x+5

x+2=y=-2x+5

3x=3

x=1

y=1+2

y=3

(1,3)

Slope intercept form of a line is, y = mx + c where m is the slope and c is constant.

Judging the given equation y = 2x + 5

Slope (m) of the line is 2,

y-intercept of the line,

y = 2x + 5

y = 2×0 + 5

y = 5

Answered by GAUTHMATH

Answer:

m = 2

y intercept = 5

Step-by-step explanation:

The given equation of the line is ,

[tex]\implies y = 2x +5[/tex]

We know that the Standard equation of Slope Intercept Form of the line is,

[tex]\implies y = mx + c[/tex]

Where ,

On comparing to the Standard form of the line we get ,

[tex]\implies Slope = 2 [/tex]

[tex]\implies y - intercept= 5[/tex]

The percentage rate of change of the given functions is given by the

derivative of their natural logarithm.

Responses:

[tex]f(t) = 1.18^t[/tex]

[tex]g(t) = 2^{-2 \cdot t}[/tex]

[tex]h(t) = 1.19^{\frac{t}{10} }[/tex]

[tex]k(t) = 0.13^t[/tex]

The percentage rate of change can be presented as follows;

[tex]Percentage \ rate \ of \ change = \mathbf{100 \times \dfrac{d}{dt} ln \left(f(t)\right)}[/tex]

[tex]f(t) = \mathbf{ 1.18^t} \ gives;[/tex]

[tex]g(t) = \mathbf{2^{-2 \cdot t} }\ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(2^{-2 \cdot t}\right) \right) = \mathbf{ 100 \times -2 \times ln(2)} \approx \underline{ -138.6 \%}[/tex] , exponential decay

[tex]h(t) = \mathbf{1.19^{\frac{t}{10} } }\ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(1.19^{\frac{t}{10} }\right) \right) = \mathbf{ 100 \times \dfrac{10 \cdot ln(1.19)}{100}} \approx 1.7 \%[/tex], exponential growth

[tex]k(t) = \mathbf{ 0.13^t} \ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(0.13^t }\right) \right) = \mathbf{100 \times ln(0.13)}\approx -204 \%[/tex], exponential decay

Learn more about exponential functions here:

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Step-by-step explanation:

the graph should look something like this

Answer:

EXPLAINED ON THE ATTACHED

Answer: [tex]9240\ ft^3[/tex]

Step-by-step explanation:

Given

Dimension of the bathroom is [tex]12'\times 16'[/tex]

Dimension of the bedroom is [tex]14'\times 18[/tex]

Dimension of the great room is [tex]20'\times 30'[/tex]

Height of the ceiling is [tex]h=10'[/tex]

Total area of the cabin

[tex]\Rightarrow A=12\times6+14\times 18+20\times 30\\\Rightarrow A=72+252+600\\\Rightarrow A=924\ ft^2[/tex]

Volume of the cabin is [tex]V=A\times h[/tex]

[tex]\Rightarrow V=924\times 10\\\Rightarrow V=9240\ ft^3[/tex]

Step-by-step explanation:

= 1.414×2.236

= ±3.162

hope it is helpful to you ☺️

Answer:

Step-by-step explanation:

This is a right triangle because angle V is 90. Draw out a right triangle and put V at the 90 degree angle. It doesn't matter where you put U or T; you get the same cos value for T regardless of how you place your other 2 angles. The things you need to know are that UT is the hypotenuse of the triangle, side VU is across from angle T, and side TV is across from angle U.

The cos ratio is side adjacent to the reference angle over the hypotenuse.

Our reference angle is T, so we are looking for the side next to T that is NOT the hypotenuse. This side measures 33; the hypotenuse measures 65, so the tangent ratio of T is

[tex]tanT=\frac{33}{65}[/tex]

Answer:

If you go to a website that has a red (or orange) triangle with an exclamation mark next to the link, it's an untrusted site. The things you list (your phone is being attacked and then said something with 26..) are likely to be scam ads (probably viruses). Therefore,  I do not recommend you to click the ads or enter that site again.

Step-by-step explanation:

triangle BCA=BAL bcoz Angle BCA= Angle BAL

Answer:

2nd option

Step-by-step explanation:

Given

[tex]\frac{x}{5}[/tex] = 5 ( multiply both sides by 5, the reciprocal of [tex]\frac{1}{5}[/tex] to clear the fraction )

x = 25

Answer:

5m/s²

Step-by-step explanation:

Given :-

To Find :-

Solution :-

We know that the rate of change of velocity is called acceleration. Therefore ,

[tex]\sf\implies a = v - u / t \\ [/tex]

[tex]\sf\implies a = 60m/s - 40m/s/ 4 \\ [/tex]

[tex]\sf\implies a = 20m/s \div 4 \\[/tex]

[tex]\bf\implies a = 5m/s^2[/tex]

Answer:

use average seep hours

top = 77/12 = 6.4 (most)

middle = 6 (middle)

bottom = 50/9 = 5.5 (least)

Step-by-step explanation:

Answer:

1000

Step-by-step explanation:

Given data

we have the sequence

25, 10, -5, ...

we want to find the 66th term, let us apply the formula

an = a + (n – 1)d

a= 25

n= 66

d= 15

substitute

a66= 25+(66-1)15

a66= 25+(65)*15

a66= 25+975

a66= 1000

Hence the 66th term is 1000

Answer:

do you have a pic of the problem

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

the answer is the sqare rute of 25 which is 5

Answer:

5x+8x+17-9+2y

13x+8+2y

Answer:

13x+8+2y

Step-by-step explanation:

5x+8x=13x

17–9=8

2y=2y

Answer:

x=0..............................

Answer:

-8x - 1

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

-10x - 10 + 2x + 9

Step 2: Simplify

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{-10x - 10 + 2x + 9}[/tex]

[tex]\huge\textsf{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{-10x + 2x - 10 + 9}[/tex]

[tex]\large\textsf{-10x + 2x}\\\\\large\textsf{ = \bf -8x}[/tex]

[tex]\large\textsf{-10 + 9}\\\\\large\textsf{ = \bf -1}[/tex]

[tex]\boxed{= \large\textsf{\bf -8x - 1}}\large\checkmark[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf -8x - 1 }}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

2^4×3^2 = 144

___________

Answer:

144 would be the answer.

Step-by-step explanation:

Question:- [tex]2^{4}[/tex] · [tex]3^{2}[/tex]

[tex]2^{4}[/tex] = 2 x 2 x 2 x 2

   = 4 x 2 x 2

   = 8 x 2

   = 16

[tex]3^{2}[/tex] = 3 x 3

   = 9

So, [tex]2^{4}[/tex] · [tex]3^{2}[/tex] = 16 x 19

              = 144