a sports car has a mass of 1300kg.Starting from the rest the car generates a force of 4400 N.The frictional force opposing this motion is 280 N.What is the car’s acceleration

Answer:

b

Explanation:

Answer:

The table shows the height y (in thousands of feet) of an unmanned aerial vehicle (UAV) x minutes after it begins its descent from cruising altitude. Minutes, x Height (thousands of feet), y 0,62 5,58 10,54 15,50

Answer:

they will move away from each other

Answer:

273.15

Explanation:

So that's three over two times 1.38 times ten to the minus twenty-three joules per Kelvin, times 5500 degrees Celsius, the surface of the sun converted into Kelvin by adding 273.15. This works out to 1.20 times ten to the minus nineteen joules. So that's the average kinetic energy of hydrogen atoms.

Answer:

The moon keeps the same face pointing towards the Earth because its rate of spin is tidally locked so that it is synchronized with its rate of revolution (the time needed to complete one orbit). In other words, the moon rotates exactly once every time it circles the Earth.

Answer:

      v’ =( [tex]\frac{1}{1+ \frac{M}{m} }[/tex]  )  v

we see that the greater the difference, the more the sled slows down.

friction force

Explanation:

When the man pushes the sled he does work and the sled acquires a speed and as long as it is supplied with an energy equal to the work of the chipping force with the snow, the speed is maintained.

When he jumps on the sled, a collision occurs and the initial moment

             p₀ = mv

is increased by the increase in mass

             m_f= (m + M_{man} ) v '

In this case there is no longer any external force applied and the only external force is friction, which causes the sled to stop, even when it is small, but the significant reduction in speed is due to the increase in masses.

            p₀ = p_f

            mv = (m + M_{man}) v '

            v ’=  [tex]\frac{m}{m+M}[/tex] v

            v’ =( [tex]\frac{1}{1+ \frac{M}{m} }[/tex]  )  v

Therefore, we see that the greater the difference, the more the sled slows down.

The only forces that act on the sled with the man are the friction that is responsible for the decrease in speed and weight with the normal

Answer:

100

Explanation:

since the two at the left side is pulling with a force of 70 and 60 which equals to 130 for the rope to be in equilibrium, those at the left must also pull with same force. Which makes it 130-30=100N

Answer:

Homeostasis is the ability of the body to maintain balance inside the cells, even as the surrounding environment changes

The correct option is (1)Homeostasis is the ability of the body to change to match the surrounding environment.

Homeostasis is the ability of an organism or system to maintain a stable internal environment, despite changes in external conditions. This is achieved through a variety of physiological and behavioral mechanisms that help regulate various bodily functions such as temperature, blood sugar levels, hydration, and oxygen levels.

The process of homeostasis involves the detection of changes in the internal or external environment, followed by a response that helps restore the optimal conditions. For example, if the body's temperature rises above normal levels, the brain triggers sweat production to cool down the body.

Homeostasis is essential for the proper functioning of cells, tissues, organs, and the entire organism. It helps maintain a balance between various bodily functions and ensures that cells have the necessary conditions to carry out their functions. Without homeostasis, cells would be unable to survive and carry out the functions required for life.

Hence the correct statement about homeostasis is, Homeostasis is the ability of the body to change to match the surrounding environment.

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Answer:

(a) T = 18309.63 N = 18.31 KN

(b) T = 16314.03 N = 16.314 KN

Explanation:

(a)

The tension in an elevator while moving upward with some acceleration is given by the following formula:

[tex]T = m(g+a)\\[/tex]

where,

T = Tension = ?

m = mass = 1663 kg

g = acceleration due to gravity = 9.81 m/s²

a = acceleration of elevator = 1.2 m/s²

Therefore,

[tex]T = (1663\ kg)(9.81\ m/s^2 + 1.2\ m/s^2)\\[/tex]

T = 18309.63 N = 18.31 KN

(b)

Constant velocity means no acceleration. So, in that case, the tension will be equal to the weight of the elevator:

[tex]T = mg\\T = (1663\ kg)(9.81\ m/s^2)\\[/tex]

T = 16314.03 N = 16.314 KN

Answer: 0.33 m/s^2

Explanation:

The acceleration of Odysseus' ship as it moves across the water from Troy to Ithaca is 0.33m/s²

Given the data in the question;

To determine the acceleration of the ship, We the equation from Newton's Second Law of Motion:

[tex]F = m\ *\ a[/tex]

Where F is the force, m is the mass and a is the acceleration

Lets make acceleration ''a'', the subject of the formula

[tex]a = \frac{F}{m}[/tex]

Now, we substitute our given values into the equation

[tex]a = \frac{300000N}{900000kg}[/tex]

We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]

[tex]a = \frac{300000 kg.m/s^2}{900000kg} \\\\a = 0.33m/s^2[/tex]

Therefore, the acceleration of Odysseus' ship as it moves across the water from Troy to Ithaca is 0.33m/s²

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Answer:

true

Explanation:

because I tride it

Answer:

A) Energy is dissipated into heat and sound energy due to Friction

B) The energy goes into heat and sound energy due to friction again, otherwise the cart would accelerate due to an unbalanced force. Therefore, we know there's friction, and the friction causes energy loss.

The speed of the hoop when it has rolled halfway up the side of the pipe is √(v₀² - gR).

The speed of the hoop when it has rolled halfway up the side of the pipe is calculated as follows;

K.E = P.E

- ¹/₂mv₀²  + ¹/₂Iω² = (mgh₀ - mghf)

- ¹/₂mv₀²  + ¹/₂Iω² = (0 - 0.5mgh)        (hf = 0.5h) (half way up)

¹/₂Iω² = ¹/₂mv₀² - 0.5mgh  

where;

¹/₂(mr²)(vf/r)² = ¹/₂mv₀²  - 0.5mgh

¹/₂vf²  = ¹/₂v₀² - ¹/₂gh  

vf²  = v₀² - gh

vf = √(v₀² - gh)

where;

vf = √(v₀² - gR)

[tex]v_f = \sqrt{v_0^2 - gR}[/tex]

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Answer:

A. 450 N

B. 3240 J

C. 0.77 KW

Explanation:

From the question given above, the following data were obtained:

Height of one step = 20 cm

Number of steps = 36

Mass of runner = 45 kg

Time taken = 4.2 s

Next, we shall convert 20 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m /100 cm

20 cm = 0.2 m

Next, we shall determine the total height. This can be obtained as follow:

Height of one step = 0.2 m

Number of steps = 36

Total height =?

Total height = 36 × 0.2

Total height = 7.2 m

A. Determination of the runner's weight.

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 45 × 10

W = 450 N

B. Determination of the increase in the potential energy.

At the ground level, the potential energy (PE₁) is 0 J.

Next, we shall determine the potential energy at 7.2 m. This can be obtained as follow:

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Total height (h) = 7.2 m

Potential energy at height 7.2 m (PE₂) = ?

PE₂ = mgh

PE₂ = 45 × 10 × 7.2

PE₂ = 3240 J

Final, we shall determine the increase in potential energy. This can be obtained as follow:

Potential energy at ground (PE₁) = 0 J

Potential energy at height 7.2 m (PE₂) = 3240 J

Increase in potential energy =?

Increase in potential energy = PE₂ – PE₁

Increase in potential energy = 3240 – 0

Increase in potential energy = 3240 J

C. Determination of the power.

Energy (E) = 3240 J

Time (t) = 4.2 s

Power (P) =?

P = E/t

P = 3240 / 4.2

P = 771.43 W

Finally, we shall convert 771.43 W to kilowatt (KW). This can be obtained as follow:

1000 W = 1 KW

Therefore,

771.43 W = 771.43 W × 1 KW / 1000 W

771.43 W = 0.77 KW

Therefore, her power is 0.77 KW

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

Answer:

magnitude of friction force- 54.3

friction force- -54.2

Explanation:

Answer:

(a) The car is going approximately 40.43 m/s at the bottom of the hill

(b) The thermal energy will increase by 607,268.76 J

Explanation:

In the question, we have;

The height of the roller coaster above ground = 83.4 m

The mass of the roller coaster, m = 743.0 kg

(a) By the conservation of energy principle, we have;

The potential energy at the top of the hill, P.E., is equal to the kinetic energy at the bottom of the hill, K.E.

∴ P.E. = K.E.

P.E. = m·g·h

Where;

m = The mass of the roller coaster = 743.0 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height of the roller coaster = 83.4 m

Therefore, we have;

P.E. = 743.0 kg × 9.8 m/s² × 83.4 m = 607,268.76 J

P.E. = 607,268.76 J

K.E. = 1/2·m·v²

∴ K.E. = 1/2 × 743.0 kg × v²

P.E. = K.E.

∴ P.E. = K.E. = 607,268.76 J

1/2 × 743.0 kg × v² = 607,268.76 J

v² = 607,268.76 J/(1/2 × 743.0 kg) = 1,634.64 m²/s²

v = √(1,634.64 m²/s²) ≈ 40.43 m/s

(b) Given that the material wheel moves along polystyrene track, the sound released will be minimal and almost all the kinetic energy will be converted to heat energy when the train stops, therefore, the thermal energy will increase by K.E. = 607,268.76 J

The thermal energy change of the system is 624,492 J.

We know that in the roller coaster, there is an energy transformation from gravitational potential energy to kinetic energy. As such we can write;

mgh = 1/2mv^2

Where we cancel out the mass from both sides, we are left with;

gh=0.5v^2

v= √gh/0.5

v = √10 × 83.4 m/0.5

v = 41 ms-1

Now the kinetic energy is converted also into heat energy hence;

Thermal energy change of the system = 1/2 mv^2 = 0.5 × 743.0 kg × ( 41 ms-1)^2 = 624,492 J

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Answer:

the answer is c) 25.1 feet/second

Explanation:

because the blood droplets can not increase speed past terminal velocity 100.

The terminal velocity of blood is 25.1 ft/s in air. So, option C is correct.

Terminal velocity is defined as the maximum velocity to which a freely falling drop can accelerate.

Here,

When a drop of blood is observed, it can be found that due to the effect of gravity, the velocity of the freely falling blood drop increases. So, it moves with increasing velocity, which is due to the influence of acceleration due to gravity. During the free fall of blood drop, there are resistive forces in air that opposes the motion or tries to reduce the velocity of the blood drop. The friction in air affects the freely falling blood drop and the blood drop tends to reduce its velocity and reaches a maximum of velocity after which it cannot accelerate, which is due to the frictional force in air. This maximum velocity is called terminal velocity. The terminal velocity of blood is 25.1 feet/second.

Hence,

The terminal velocity of blood is 25.1 ft/s in air.

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Answer:

W = 6.5 W

Explanation:

Work is defined by

         W = F . d

          W = f d cos tea

where the point represents the scaled product and the bold letters indicate vectors

they ask us the work of the friction force

we write the translational equilibrium equation

y Axis

                  N -W = 0

                  N = mg

x axis

                  F - fr = 0

                  F = fr

the formula for the friction force is

                  fr = μ N

we substitute

                  fr = μ m g

we substitute in the equation of work

           W = fr d cos θ

            W = μ m g d cos θ

let's calculate

            W = 0.500 1.10 9.8   Σ d_i  cos θ_i

            W = 5.39 d cos tea

we have two displacement

the first on one side of the box, suppose that side is on the y-axis, therefore the angle between the displacement and the friction force is 70º

and there is a second displacement in the x axis, in this case the angle between the friction force and the displacement is 30º

therefore the total workload is the sum of those work

            W = 5.39 (1 cos 70 + 1 cos 30)

             W = 5.39 (0.342 + 0.866)

             W = 6.5 W

Answer:

3.9 × 10^7 J

Explanation:

Given that a tank is is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r = 15 m and h = 5 m.) W = 1.59 J

Solution

Since the tank is half full, the height = 2.5m

Pressure = density × gravity × height

Pressure = 900 × 9.8 × 2.5

Pressure = 22050 Pascal

The cross sectional area of the pump will be area of a circle.

A = πr^2

A = π × 15^2

A = 706.858 m^2

Using the formula

Density = mass/volume

Mass = density × volume

Mass = 900 × 706.86 × 2.5

Mass = 1590.435

Energy = mgh

Energy = 1590.435 × 9.8 × 2.5

Energy = 38965657.8 J

Since the work done = energy

Therefore, the work done = 3.9 × 10^7 J

Answer:

Venus

Explanation:

Answer:

94.25 seconds

Explanation:

Solve for period (T) using: v=(2*pi*r)/T

rearrange: vT=2*pi*r

rearrange: T=(2*pi*r)/v

Plug in values.

T=(2*pi*150)/10

T=94.25 seconds

If a race car goes around a circular track of a radius of 150 m at speed of 10.0 m/s ,then the time taken to complete the one lap would be 94.25 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

As given in the problem a race car goes around a circular track of radius 150 m at speed of 10.0 m/s.

vT = 2 × π × r

T = (2 × π × r)/ v

T = (2 × π× 150)/10

T = 94.25 seconds

Thus, the time taken to complete the one lap would be 94.25 seconds.

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Answer:

a. The current is flowing from South to North. So, the current flows in the North direction

b. West

Explanation:

a. A compass needle placed above the wire points with its north pole toward the east. In What direction is the current flowing?

Using Maxwell's corkscrew rule, with the thumb of the right hand pointing in the direction of the current and the closed fingers pointing in the direction of the magnetic field.

Since the compass is placed above the wire and points east, the direction of the magnetic field at that point is east.

Since the magnetic field is tangential to the circular path around the wire, to produce an eastward magnetic field above the wire, the current must go from South to North. So, the current flows in the North direction.

b. If a compass is put underneath the wire, in which direction will the compass needle point?

If the compass is put underneath the wire, using Maxwell's corkscrew rule, since the current points northward, and the magnetic field is tangential to the circular path around the wire, the magnetic field below the wire points west.

So, the direction of the compass needle when the compass is put beneath the wire is west.

Answer: Option b.

Explanation:

We know:

Wavelength = 632.8 nm

Fluence = 4.5*10^20 photon/s

The energy of a single photon of wavelength λ is:

E = (h*c)/λ

where:

h = 6.6*10^(-34) J*s

c = 3*10^8 m/s

And we should rewrite the wave length in meters, so:

λ = 632.8 nm = 632.8*10^(-9) m

replacing these in the energy equation, we get:

E = (6.6*10^(-34)J*s)*(3*10^8 m/s)/(632.8*10^(-9) m) = 3.13*10^(-19) J

So each one of the  4.5x10^20 photon that flow each second have this energy, then the power is:

P = (3.13*10^(-19) J)*(4.5*10^20 /s) = 140.85 J/s

and 1 W = 140.85 J/S

Then the power is:

P = 140.85 W

Then the correct answer is the option b, where the units are a little bit different than mine because I used really simplified values for c and h.

Answer:

D

Explanation:

You are boiling more grams for more time because the more water the longer it takes which requires more calories to burn it.

Answer:

The mass will be 227kg.

Explanation:

Mass is a measure of how much "stuff" is in an object. It's a measure of the number and type of atoms in something, and is fixed. If you and I went to the moon right now, our bodies wouldn't change what they were made of. I would still be made up of all the same "stuff," as would you! So my mass would be the same and so would yours.

Weight would change on the moon, because weight is a measure of the local pull of gravity on an object's mass. Earth's gravitational force is about 10m/s2 and the moon's is about 1.6m/s2. So on the moon, I would have a weight of about 1/6 my weight on Earth... but I'd still wear the same size jeans!